Find three positive consecutive intregers such that the product of the first and third intreger is 17 more than 3 times the second intreger

The speed of the first runner is 5 miles per hour, and the speed of the second runner is 1 mile per hour.

Let's assume the speed of the second runner is "x" (in some unit, let's say miles per hour).

According to the given information, the speed of the first runner is 5 times the speed of the second runner. Therefore, the speed of the first runner can be represented as 5x.

After 30 minutes, the first runner would have covered a distance of 5x ×(30/60) = 2.5x miles.

In the same duration, the second runner would have covered a distance of x × (30/60) = 0.5x miles.

Since the runners are 2 miles apart, we can set up the following equation:

2.5x - 0.5x = 2

Simplifying the equation:

2x = 2

Dividing both sides by 2:

x = 1

Therefore, the speed of the second runner is 1 mile per hour.

Using this information, we can determine the speed of the first runner:

Speed of the first runner = 5 × speed of the second runner

= 5 × 1

= 5 miles per hour

So, the speed of the first runner is 5 miles per hour, and the speed of the second runner is 1 mile per hour.

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To solve the exponential equation e^(2x) - 6 = (58^x) / 10, follow these steps:

Step 1: Add 6 to both sides of the equation.
e^(2x) = (58^x) / 10 + 6

Step 2: Rewrite the right side of the equation as a common base (e).
e^(2x) = e^(x * ln(58/10)) + 6

Step 3: Set the exponents equal to each other, as the bases are equal.
2x = x * ln(58/10)

Step 4: Solve for x.
x = 2x / ln(58/10)

Step 5: Calculate the decimal approximation of x rounded to two decimal places.
x ≈ 2.07

So, the exact expression for the solution of the exponential equation is x = 2x / ln(58/10), and the decimal approximation is x ≈ 2.07.

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The objective function in this scenario would be to maximize the exposure of Diamond Jeweler's while staying within their weekly advertising budget of $10,000.

The correct answer is (c) Maximize 7000T + 8500N + 3000R

Maximize 7000T + 8500N + 3000R where T represents the number of TV ads, N represents the number of newspaper ads, and R represents the number of radio ads. By maximizing the audience reached through each medium, Diamond Jeweler's can ensure that they are getting the most out of their advertising budget and reaching as many potential customers as possible.

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The transformation t applied to vector a rotates it by 90 degrees around the y-axis and then scales it by a factor of 2 along the x-axis.

The given vector a can be represented in 3D space as (0,0,0,0,1,0,0,0,1)^T, where T denotes the transpose.

To apply the rotation, we first represent the rotation matrix R about the y-axis by an angle of 90 degrees as:

R = [0 0 1 0 1 0 -1 0 0;

0 1 0 0 0 0 0 0 1;

-1 0 0 1 0 0 0 0 0]

Multiplying R with a, we get:

Ra = [0 0 1 0 1 0 -1 0 0]^T

This means that a is rotated by 90 degrees around the y-axis.

Next, we apply the scaling along the x-axis. We represent the scaling matrix S as:

S = [2 0 0;

0 1 0;

0 0 1]

Multiplying S with Ra, we get:

SRa = [0 0 2 0 1 0 -2 0 0]^T

This means that Ra is scaled by a factor of 2 along the x-axis.

Thus, the transformation t applied to vector a rotates it by 90 degrees around the y-axis and then scales it by a factor of 2 along the x-axis. Geometrically, this can be visualized as taking the original vector a and rotating it clockwise by 90 degrees about the y-axis, and then stretching it horizontally along the x-axis.

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So, the inequality which represents the situation is 7.5h + 30 ≥ 300, where h ≥ 36. Hence, the answer is B.

Given: Chris works at a bookstore and earns $7. 50 per hour plus a $2 bonus for each book she sells. Chris sold 15 books. The total earning of Chris,E(h) = 7.5h + 2 × 15 = 7.5h + 30 dollars where h is the number of hours worked by Chris .In order to find out the minimum hours she has to work to earn at least $300, we have to solve the inequality:7.5h + 30 ≥ 300 ⇒ 7.5h ≥ 270 ⇒ h ≥ 36.

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Working together, Aubrey and Maxwell can finish washing all the windows of the retail store in approximately 3.6 hours.

Aubrey's rate of work is 1 window per 6 hours, while Maxwell's rate of work is 1 window per 9 hours. To determine how long it would take for them to finish the work together, we need to calculate their combined rate of work.
Let's assume the total number of windows in the retail store is W. Since Aubrey can wash all the windows in 6 hours, their combined rate of work is W/6 windows per hour. Similarly, Maxwell's rate of work is W/9 windows per hour.
When working together, their rates of work are additive. Therefore, their combined rate of work is (W/6 + W/9) windows per hour.
To find the time it takes to complete the work, we divide the total number of windows by the combined rate of work. This can be expressed as:
Time = Total number of windows / Combined rate of work.
Time = W / (W/6 + W/9)
Simplifying the expression, we get:
Time = 1 / (1/6 + 1/9)
Time = 1 / (3/18 + 2/18) hourshours/18) hours.
Time = 1 / (5/18) hours.
Time ≈ 3.6 hours
Therefore, working together, Aubrey and Maxwell can finish washing all the windows of the retail store in approximately 3.6 hours.

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The derivative of y with respect to x is y' = x - 1.

We can find the derivative of y using the power rule and the product rule as follows:

y = 1/2 x^2 - x

y' = (1/2)(2x) - 1

y' = x - 1

The derivative of y with respect to x, y'(x), is the slope of the tangent line to the graph of y at the point (x, y).

To find y', we need to differentiate y with respect to x using the power rule and the constant multiple rule of differentiation.

y = 1/2x^2 - x

y' = d/dx [1/2x^2] - d/dx [x]

y' = (1/2)(2x) - 1

y' = x - 1

Therefore, the derivative of y with respect to x is y' = x - 1.

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The 9th term of the sequence 128, 32, 8, 2, 1/2 is 0.003.

To find the 9th term of the sequence, we need to determine the pattern followed by the sequence. We can see that each term is one-fourth of the previous term. Using this pattern, we can write the general formula for the nth term of the sequence as: a_n = 128*(1/4)^(n-1)

Now we can substitute n = 9 in the formula and simplify to get the 9th term as: a_9 = 128*(1/4)^8 ≈ 0.003

A geometric progression, sometimes referred to as a geometric sequence in mathematics, is a series of non-zero numbers where each term following the first is obtained by multiplying the preceding one by a constant, non-zero value known as the common ratio. For instance, the geometric progression 2, 6, 18, 54, etc. has a common ratio of 3. Similar to that, the geometric series 10, 5, 2.5, 1.25,... has a common ratio of 1/2.

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There are 1,680 different ways to select the officers for your club.

To determine the number of ways you can select officers for your club, you'll need to use the concept of permutations.

In this case, there are 8 members and you need to choose 4 positions (president, vice president, secretary, and treasurer).

The number of ways to arrange 8 items into 4 positions is given by the formula:

P(n, r) = n! / (n-r)!

where P(n, r) represents the number of permutations, n is the total number of items, r is the number of positions, and ! denotes a factorial.

For your situation:

P(8, 4) = 8! / (8-4)! = 8! / 4! = (8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) / (4 × 3 × 2 × 1) = (8 × 7 × 6 × 5) = 1,680

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Two vectors are orthogonal if their dot product is zero. So, we need to find the dot product of (3, x, -5) and (2, x, x) and set it equal to zero:

(3, x, -5) ⋅ (2, x, x) = (3)(2) + (x)(x) + (-5)(x) = 6 + x^2 - 5x

Setting 6 + x^2 - 5x = 0 and solving for x gives:

x^2 - 5x + 6 = 0

Factoring the quadratic equation, we get:

(x - 2)(x - 3) = 0

So, the solutions are x = 2 and x = 3.

Therefore, the values of x such that (3, x, −5) and (2, x, x) are orthogonal are x = 2 and x = 3.

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The cost of the furniture without VAT can be found by subtracting the VAT amount from the total cost. In this case, the cost of the furniture without VAT is Rs. 3000.

The total cost of the furniture, including VAT, is given as Rs. 3390. To find the cost of the furniture without VAT, we need to subtract the VAT amount.

The VAT is calculated as a percentage of the total cost. In this case, the VAT rate is 13%. To calculate the VAT amount, we multiply the total cost by the VAT rate:

VAT amount = 13% of Rs. 3390 = 0.13 * Rs. 3390 = Rs. 440.70

To find the cost of the furniture without VAT, we subtract the VAT amount from the total cost:

Cost without VAT = Total cost - VAT amount = Rs. 3390 - Rs. 440.70 = Rs. 3000

Therefore, the cost of the furniture without VAT is Rs. 3000.

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Let's first calculate the new average speed when John Short travels at 50mph speed.Let's use the formula:average speed = distance / time, which is 50mph.

We know that distance remains the same (36 miles) at different speeds, but time will change as speed changes.

Therefore, the new time can be calculated as:time = distance / average speedNew time for 50 mph is:time = 36 / 50 = 0.72 hours

Now, let's calculate the new distance that can be traveled on 1 gallon of fuel.

We know that the new average speed is 50mph. Therefore, the new fuel economy can be calculated as:fuel economy = distance / fuel used

We also know that fuel used will decrease by 25% when speed increases from 40 mph to 50 mph. Therefore, the new fuel used can be calculated as:fuel used = 0.75 * fuel used at 40 mphUsing the above formula and the given values, we can calculate the new fuel used:fuel used = 0.75 * 1 = 0.75 gallonsNow, we can calculate the new distance that can be traveled on 1 gallon of fuel as:fuel economy = distance / fuel used36 = distance / 0.75distance = 36 * 0.75 = 27Therefore, John Short can expect to travel 27 miles per gallon at an average speed of 50mph.

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The magnitude Bode plot starts at 100 dB and decreases with a slope of -20 dB/decade, the phase plot starts at 0 degrees and decreases with a slope of -90 degrees.

To sketch the Bode plot and phase plot of the b H(f) = 100 / (1+j(f/1000)), we first need to express it in standard form:

H(jω) = 100 / (1 + j(ω/1000))

Hence, we have:

Magnitude:

|H(jω)| = 100 / √[1 + (ω/1000)²]

Phase:

∠H(jω) = -arctan(ω/1000)

Now, we can sketch the approximate asymptotic magnitude Bode plot and approximate phase plot as follows:

Magnitude Bode Plot:

Phase Plot:

Overall, the Bode plot of the magnitude starts at 100 decibels and decreases with a rate of 20 decibels per decade, while the phase plot starts at 0 degrees and decreases with a rate of 90 degrees per decade.

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The three distinct real eigenvalues of the matrix B are -4, 4, and 6.

To find the eigenvalues of a matrix, we need to solve the characteristic equation, which is obtained by setting the determinant of the matrix subtracted by λ (the eigenvalue) times the identity matrix equal to zero.

Let's calculate the determinant of the matrix B - λI, where B is the given matrix and I is the identity matrix:

B - λI = [8 - 7 - 3

0 4 2

0 0 -4] - [λ 0 0

0 λ 0

0 0 λ]

B - λI = [8 - 7 - 3 - λ 0 0

0 4 - λ 2 0

0 0 -4 - λ]

The determinant of B - λI is calculated as follows:

det(B - λI) = (8 - 7 - 3 - λ) * (4 - λ) * (-4 - λ)

Now, we set det(B - λI) = 0 and solve for λ to find the eigenvalues:

(8 - 7 - 3 - λ) * (4 - λ) * (-4 - λ) = 0

Expanding this equation:

(-4 - λ) * (4 - λ) * (8 - 7 - 3 - λ) = 0

Simplifying further:

(λ + 4) * (λ - 4) * (λ - 6) = 0

So, the eigenvalues are λ = -4, λ = 4, and λ = 6.

Therefore, the three distinct real eigenvalues of the matrix B are -4, 4, and 6.

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To evaluate the expression 12x⁻³y⁻¹ for x = -1 and y = 5, we substitute these values into the expression.

12x⁻³y⁻¹ = 12(-1)⁻³(5)⁻¹

Here, -1 is raised to an odd power, so it is negative.

-1³ = -1 × -1 × -1

= -1

So, (-1)³ = -1

Thus, we have:

12x⁻³y⁻¹ = 12(-1)⁻³(5)⁻¹

= 12(-1/1)(1/5)

= -12/5

Therefore, the value of 12x⁻³y⁻¹ for x = -1 and y = 5 is -12/5.

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There are 1,088,080 different ways to arrange the letters in the word "occasionally" while keeping all the letters together.

The number of different ways that the letters of "occasionally" can be arranged is 1,088,080.The number of ways to arrange n distinct objects is given by n! (n factorial). In this case, there are 11 distinct letters in the word "occasionally". Therefore, the number of ways to arrange those letters is 11! = 39,916,800.

However, the letter 'o' appears 2 times, 'c' appears 2 times, 'a' appears 2 times, and 'l' appears 2 times.Therefore, we need to divide the result by 2! for each letter that appears more than once.

Therefore, the number of ways to arrange the letters of "occasionally" is:11! / (2! × 2! × 2! × 2!) = 1,088,080

We can use the formula n!/(n1!n2!...nk!), where n is the total number of objects, and ni is the number of indistinguishable objects in the group.

Therefore, the total number of ways to arrange the letters of "occasionally" is 11! / (2! × 2! × 2! × 2!), which is equal to 1,088,080.

In conclusion, there are 1,088,080 different ways to arrange the letters in the word "occasionally" while keeping all the letters together.

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The Laplace transform F(s) = L{f(t)} of the function f(t) = e^4t-8 h(t - 2), where h(t - 2) is the Heaviside step function, defined on the interval t ≥ 0 can be found using the Laplace transform definition. The Laplace transform of e^at is 1/(s-a) and the Laplace transform of h(t-a)f(t-a) is e^(-as)F(s), where F(s) is the Laplace transform of f(t). Therefore, F(s) = 1/(s-4) * e^(-2s) as h(t-2) shifts the function to the right by 2 units. Thus, the Laplace transform of the given function is F(s) = 1/(s-4) * e^(-2s).

The Laplace transform is a mathematical technique that converts a function of time into a function of a complex variables. It is widely used in engineering and physics to solve differential equations and study the behavior of systems. The Laplace transform of a function f(t) is defined as F(s) = L{f(t)} = ∫[0,∞] e^(-st) f(t) dt, where s is a complex variable. The Laplace transform has several properties, such as linearity, time-shifting, and differentiation, that make it a powerful tool for solving differential equations.

In conclusion, the Laplace transform F(s) = L{f(t)} of the function f(t) = e^4t-8 h(t - 2), where h(t - 2) is the Heaviside step function, defined on the interval t ≥ 0 can be found using the Laplace transform definition. The Laplace transform of e^at is 1/(s-a) and the Laplace transform of h(t-a)f(t-a) is e^(-as)F(s), where F(s) is the Laplace transform of f(t). Therefore, F(s) = 1/(s-4) * e^(-2s) as h(t-2) shifts the function to the right by 2 units. The Laplace transform is a powerful mathematical tool that is widely used in engineering and physics to solve differential equations and study the behavior of systems.

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the standard normal distribution (also called the z-distribution) is a normal distribution with a mean of zero and a standard deviation of one.

a) We know that the t-distribution is symmetric, so P(t > 2.17) = P(t < -2.17). Therefore, we can use the complement rule to find P(-2.17 =< T =< 2.17):

P(-2.17 =< T =<2.17) = 1 - P(T < -2.17) - P(T > 2.17)

= 1 - 0.04 - 0.04

= 0.92

Therefore, P(-2.17 =<T =<2.17) is 0.92.

b) We know that the standard normal distribution is symmetric, so P(Z > 1.18) = P(Z < -1.18). Let's call this common probability value p:

P(Z > 1.18) = P(Z < -1.18) = p

We also know that P(-1.18 =< Z =< 1.18) = 0.76. We can use the complement rule to find p:

p = 1 - P(-1.18 =< Z =< 1.18)

= 1 - 0.76

= 0.24

Therefore, P(Z > 1.18) is also 0.24.

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Given that Jake's net pay is 160.65 after deductions of 68.85 and he makes 8.50 per hour. We need to find how much hours did he work. Let the hours he worked be h.

From the problem statement we can write an equation based on the above given information as:8.50h - 68.85 = 160.65Simplifying the equation,8.50h = 160.65 + 68.85= 229.50Now, dividing both sides by 8.5, we get,h = 229.50/8.5h ≈ 27Therefore, Jake worked for 27 hours .Let's verify this result: Total earning = 8.50hNet pay = Total earnings - Deductions=> 8.50 × 27 - 68.85 = 229.50 - 68.85 = 160.65Thus, the solution is Jake worked for 27 hours.

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To calculate the test statistic you would use to test your hypothesis, you can use the formula given below;

[tex]t = \frac{\bar{X}-\mu}{\frac{s}{\sqrt{n}}}[/tex]

Here, [tex]\bar{X}[/tex] = Sample Mean, [tex]\mu[/tex] = Population Mean, s = Sample Standard Deviation, and n = Sample Size

Given,The sample size n = 16Sample Variance = 4 years

So, Sample Standard Deviation (s) = [tex]\sqrt{4}[/tex] = 2 yearsPopulation Mean [tex]\mu[/tex] = 24 yearsSample Mean [tex]\bar{X}[/tex] = 25 years

Now, let's substitute the values in the formula and

calculate the t-value;[tex]t = \frac{\bar{X}-\mu}{\frac{s}{\sqrt{n}}}[/tex][tex]\Rightarrow t = \frac{25 - 24}{\frac{2}{\sqrt{16}}}}[/tex][tex]\Rightarrow t = 4[/tex]

Hence, the test statistic you would use to test your hypothesis (two decimals) is 4.

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The sum of the series is (6 - 3ln(6))/6.

To get the sum of the series, we need to add up all the terms. The series starts with 1 and then subtracts terms involving ln(6).
So the sum of the series is:
1 - ln(6) + (ln(6))^2/2 - (ln(6))^3/3!
We can simplify this by first finding (ln(6))^2 and (ln(6))^3:
(ln(6))^2 = ln(6) * ln(6) = ln(6^2) = ln(36)
(ln(6))^3 = ln(6) * ln(6) * ln(6) = ln(6^3) = ln(216)
Now we can substitute these values into the sum of the series:
1 - ln(6) + ln(36)/2 - ln(216)/6
To simplify further, we can find a common denominator:
1 = 6/6
ln(6) = 6ln(6)/6
ln(36)/2 = 3ln(6)/6
ln(216)/6 = ln(6^3)/6 = 3ln(6)/6
So the sum of the series is:
6/6 - 6ln(6)/6 + 3ln(6)/6 - 3ln(6)/6 =
(6 - 6ln(6) + 3ln(6) - 3ln(6))/6 =
(6 - 3ln(6))/6
Therefore, the sum of the series is (6 - 3ln(6))/6.

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The first four terms of the Maclaurin series of f(x) are -6 + 6x + (13/2)x^2 + 2x^3.

The Maclaurin series expansion of a function f(x) is given by:

f(x) = f(0) + f'(0)x + (f''(0)/2!)x^2 + (f'''(0)/3!)x^3 + ...

In this case, we are given that f(0) = -6, f'(0) = 6, f''(0) = 13, and f'''(0) = 12. Therefore, the first four terms of the Maclaurin series of f(x) are:

f(x) = -6 + 6x + (13/2)x^2 + (12/6)x^3 + ...

Simplifying the third and fourth terms, we get:

f(x) = -6 + 6x + (13/2)x^2 + 2x^3 + ...

Therefore, the first four terms of the Maclaurin series of f(x) are -6 + 6x + (13/2)x^2 + 2x^3.

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The value of vector A is approximately 17.08.

To find the magnitude of a vector with components = 4.43 and = -16.5, you can use the Pythagorean theorem.

The formula for the magnitude of a vector (|A|) is:

|A| = √(x² + y²)

In this case, x = 4.43 and y = -16.5.

Plugging these values into the formula, you get:

|A| = √((4.43)² + (-16.5)²)

|A| = √(19.5849 + 272.25)

|A| = √(291.835)

Calculating the square root, you find that the magnitude of vector A is approximately 17.08.

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We need to find the probability of a randomly selected bolt having thread length (a) within 1.9 SDs of its mean value, (b) farther than 2.4 SDs from its mean value, and (c) between 1 and 2 SDs from its mean value.

(a) To find the probability that the thread length of a randomly selected bolt is within 1.9 SDs of its mean value, we can use the empirical rule or the 68-95-99.7 rule. According to this rule, approximately 68% of the values fall within 1 SD of the mean, 95% within 2 SDs, and 99.7% within 3 SDs. Therefore, the probability of the thread length being within 1.9 SDs of the mean is approximately (0.5 + 0.45) = 0.95 or 95%.

(b) The probability of a bolt's thread length being farther than 2.4 SDs from its mean value is the same as the probability of a value being beyond 2 SDs plus the probability of a value being beyond 3 SDs. The probability of a value being beyond 2 SDs is approximately 0.05, and the probability of a value being beyond 3 SDs is approximately 0.003. Therefore, the total probability is (0.05 + 0.003) = 0.053 or 5.3%.

(c) To find the probability of the thread length being between 1 and 2 SDs from the mean, we can subtract the probability of values beyond 2 SDs from the probability of values beyond 1 SD. Using the empirical rule, we know that the probability of a value being beyond 1 SD is approximately 0.32, and the probability of a value being beyond 2 SDs is approximately 0.05. Therefore, the probability of the thread length being between 1 and 2 SDs from the mean is approximately (0.5 - 0.32 - 0.05) = 0.13 or 13%.

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The magnitude of vector a is 6√2.

To calculate the projection of vector a onto vector v, we can use the formula:

proj_v(a) = (a · v) / ||v||² × v

where · represents the dot product and ||v|| represents the magnitude of vector v.

Given:

a = [4, 8, 8]

v = [1, 1, 0]

First, let's calculate the dot product (a · v):

(a · v) = 41 + 81 + 8×0 = 4 + 8 + 0 = 12

Next, let's calculate the magnitude of vector v:

||v|| = √(1² + 1² + 0²) = √(2)

Now, we can calculate the projection of vector a onto v:

=  12 / ((√2)² ×  [1, 1, 0]

= 12 / 2 x [1, 1, 0]

= 6  [1, 1, 0]

= [6, 6, 0]

The projection of vector a onto v is [6, 6, 0].

To find the magnitude of vector a, we can use the formula:

||a|| = √a1² + a2² + a3²

||a|| = √ 6² + 6² + 0²

= √ 36+36

= √72

= 6√2

Thus, The magnitude of vector a is 6√2.

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The given options can be represented in the following general form:

Circle with center (h, k) and radius r is expressed in the form

(x - h)^2 + (y - k)^2 = r^2.

Therefore, the option with the equation (x + 2)^2 + (y - 5)^2 = 25 has center (-2, 5) and radius of 5.

Let us plug in the point (-1, 1) in the equation:

(-1 + 2)^2 + (1 - 5)^2 = 25(1)^2 + (-4)^2 = 25.

Thus, the point (-1, 1) does not lie on the circle

(x + 2)^2 + (y - 5)^2 = 25.

In conclusion, the point (-1, 1) does not lie on the circle

(x + 2)^2 + (y - 5)^2 = 25.

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Let x be the number of student tickets and y be the number of adult tickets. There are 12 tickets total. Therefore: `x + y = 12`The cost of student tickets is $9 and the cost of adult tickets is $12.

We know that the cost of all 12 tickets is $120. Therefore: `9x + 12y = 120`We can solve this system of equations by substitution or elimination.

Let's use substitution: Solve the first equation for `x`: `x = 12 - y`Substitute that into the second equation: `9(12 - y) + 12y = 120`Simplify and solve for `y`: `108 - 9y + 12y = 120` `3y = 12` `y = 4`Now we know that 4 adult tickets were bought. We can substitute that back into the first equation to find the number of student tickets: `x + 4 = 12` `x = 8`Therefore, 8 student tickets were bought.

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Based on the given information, we can set up inequalities to determine the possible combinations of levels that Kiran could have completed to earn 80 or more stars, with the total number of levels being greater than 20.

Let's analyze the given information. Kiran earns 3 stars for each easy level completed and 5 stars for each difficult level completed. The total number of levels completed can be represented as `x + y`. The total number of stars earned can be calculated as 3x + 5y. According to the given conditions, the total number of levels completed is greater than 20, so we have the inequality x + y > 20. Additionally, the total number of stars earned is 80 or more, leading to the inequality 3x + 5y ≥ 80.

By setting up these inequalities, we can explore different combinations of `x` and `y` that satisfy the conditions. For example, if Kiran completes 10 easy levels (x = 10), he would need to complete at least 11 difficult levels (y ≥ 11) to meet the requirements. Similarly, other combinations can be explored to find valid solutions. The goal is to find the combinations of `x` and `y` that satisfy both inequalities and result in a total number of stars earned equal to or greater than 80.

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(a) The probability of drawing only odd numbered balls is 1/8 or 0.125.

(b) The probability of the smallest drawn number being equal to k for k = 1,...,10 is (4 choose 1)/ (10 choose 4) or 0.341.

(a) To calculate the probability of only drawing odd numbered balls, we first need to find the total number of ways to draw four balls from the urn, which is (10 choose 4) = 210. Then, we need to find the number of ways to draw only odd numbered balls, which is (5 choose 4) = 5. Thus, the probability of only drawing odd numbered balls is 5/210 or 1/8.

(b) To calculate the probability that the smallest drawn number is equal to k for k = 1,...,10, we first need to find the total number of ways to draw four balls from the urn, which is (10 choose 4) = 210. Then, we need to find the number of ways to draw four balls such that the smallest drawn number is k. We can do this by choosing one ball from the k available balls (since we need to include that ball in our draw to ensure the smallest drawn number is k) and then choosing three balls from the remaining 10-k balls. Thus, the number of ways to draw four balls such that the smallest drawn number is k is (10-k choose 3). Therefore, the probability that the smallest drawn number is equal to k is [(10-k choose 3)/(10 choose 4)] for k = 1,...,10, which simplifies to (4 choose 1)/(10 choose 4) = 0.341.

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The major that is LEAST likely to be Tom's college major is a. Engineering.

Tom's interest in reading about the history of ancient civilizations and discussing the themes of the books he reads with others suggests that he is most likely interested in pursuing a major in the humanities or social sciences. Therefore, the major that is LEAST likely to be Tom's college major is a. Engineering. Engineering is a major that is typically focused on technical skills and problem-solving in areas such as mathematics and physics, which may not align with Tom's interests and strengths. The other options, East Asian Studies, Political Science, History, and Psychology, are all majors that would allow Tom to explore his interests in history and civilization in more depth.

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