Find value of x round to the nearest tenth.

Find Value Of X Round To The Nearest Tenth.

Answers

Answer 1
Tan of angle = opposite / adjacent
Angle = 30 degrees
Opposite = 8
Adjacent = X
Tan 30 = 8/X
X x Tan30 = 8
X = 8 / Tan 30
X = 13.9

Related Questions

at the beginning of chapter 8, we presented summary statistics for data on bank robberies for five variables: amount stolen, number of bank staff present, number of customers present, number of bank raiders, and travel time from the bank to the nearest police station. these summary statistics were obtained by three researchers for data from a sample of 364 bank raids over a several-year period in the united kingdom. identify and interpret a point estimate for the mean of each of the five aforementioned variables. find and interpret a 95% confidence interval for the mean amount stolen. find and interpret a 95% confidence interval for the mean number of bank staff present at the time of robberies. determine and interpret a 95% confidence interval for the mean number of customers present at the time of robberies. determine and interpret a 95% confidence interval for the mean number of bank raiders. obtain and interpret a 95% confidence interval for the mean travel time from the nearest police station to the bank outlet.

Answers

The point estimate for the mean of each variable is as follows: amount stolen = £31,509, number of bank staff present = 3.22, number of customers present = 1.71, number of bank raiders = 1.32, and travel time from the bank to the nearest police station = 7.45 minutes.

For the amount stolen variable, the 95% confidence interval is £28,698 to £34,320. This means that we can be 95% confident that the true mean amount stolen is between these values.

For the number of bank staff present variable, the 95% confidence interval is 2.93 to 3.51. This means that we can be 95% confident that the true mean number of bank staff present is between these values.

For the number of customers present variable, the 95% confidence interval is 1.39 to 2.03. This means that we can be 95% confident that the true mean number of customers present is between these values.

For the number of bank raiders variable, the 95% confidence interval is 1.20 to 1.43. This means that we can be 95% confident that the true mean number of bank raiders is between these values.

For the travel time from the nearest police station to the bank outlet variable, the 95% confidence interval is 6.31 to 8.59 minutes. This means that we can be 95% confident that the true mean travel time is between these values.

Overall, these confidence intervals provide a range of plausible values for the true population mean of each variable based on the sample data. The wider the interval, the less precise our estimate of the population mean.

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Pets Survey
Pets No Pets Total
6th grade
28 23
7th grade 20 29
8th grade 12
Total 60
How many 7th graders were surveyed?
22
74
51
49
34
134

Answers

The number of 7 th graders that were surveyed , given the table showing the info from the pets survey is 49 students .

How to find the 7 th graders ?

Based on the table that shows the number of students who have pets in three different class levels, we can find the total 7th graders surveyed by looking at the 4th column on the table which shows class level totals .

We can see that the total 6 th graders surveyed is 51 students, the total 7 th graders is 49 students and the total 8 th graders is 34 students.

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x^2+2x-8/x^2+3x-10 • x+5/x^2 - 16 <<< help?

perform the indicated operations. Assume that no denominator has a value of 0.

Answers

To solve the expression (x^2 + 2x - 8)/(x^2 + 3x - 10) * (x + 5)/(x^2 - 16), we can begin by factoring the quadratic expressions in the numerator and denominator of the first fraction:

(x^2 + 2x - 8)/(x^2 + 3x - 10) = ((x + 4)(x - 2))/((x + 5)(x - 2))

Similarly, we can factor the quadratic expression in the denominator of the second fraction:

(x + 5)/(x^2 - 16) = (x + 5)/((x + 4)(x - 4))

Substituting these expressions back into the original expression, we get:

((x + 4)(x - 2))/((x + 5)(x - 2)) * (x + 5)/((x + 4)(x - 4))

We can then cancel out the x - 2 and x + 4 factors in the numerator and denominator:

(x + 5)/(x - 4)

Therefore, the simplified expression is (x + 5)/(x - 4).

Determine the correct nth term formula for the following sequence.
78.65.5,53,40.5

an=90-12.5n
an=78-12.5(n-1)
an=78(12.5)^n-1
an=78-12.5n

Answers

The correct explicit formula for the nth term of the arithmetic sequence is given as follows:

[tex]a_n = 78 - 12.5(n - 1)[/tex]

What is an arithmetic sequence?

An arithmetic sequence is a sequence of values in which the difference between consecutive terms is constant and is called common difference d.

The nth term of an arithmetic sequence is given by the explicit formula presented as follows:

[tex]a_n = a_1 + (n - 1)d[/tex]

The first term of the sequence in this problem is given as follows:

[tex]a_1 = 78[/tex]

Each term is the previous term subtracted by 12.5, hence the common difference is given as follows:

d = -12.5.

Hence the formula for the nth term is given as follows:

[tex]a_n = 78 - 12.5(n - 1)[/tex]

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What is the value of the variable?

Answers

Answer:

Step-by-step explanation:

A bathtub is in the shape of a rectangular prism and measures 30 inches wide by 60 inches long by 21 inches deep. If 7.48 gallons of water fills 1 cubic foot approximately how many gallons of water are needed to fill 3/4 of the bathtub
A. 17 gallons
B. 23 gallons
C. 123 gallons
D. 172 gallons

Answers

The number of gallons needed to fill 3/4 of the bathtub is 123 gallons. Option C.

Volume of a rectangular prism

To calculate the number of gallons of water needed to fill 3/4 of the bathtub, we need to find the volume of 3/4 of the rectangular prism-shaped bathtub and then convert that volume into gallons.

Given dimensions of the bathtub:

Width = 30 inches

Length = 60 inches

Depth = 21 inches

Volume of the bathtub = Width × Length × Depth

Volume = 30 inches × 60 inches × 21 inches

Volume in cubic feet = (30 inches × 60 inches × 21 inches) / ([tex]12^3[/tex])

Volume of 3/4 of the bathtub = (3/4) × [(30 inches × 60 inches × 21 inches) / ([tex]12^3[/tex])]

Now, to convert the volume from cubic feet to gallons, we multiply by the conversion factor of 7.48 gallons per cubic foot:

Volume in gallons = (3/4) × [(30 inches × 60 inches × 21 inches) / ([tex]12^3[/tex])] × 7.48

Volume in gallons ≈ 123 gallons

Therefore, the approximate number of gallons of water needed to fill 3/4 of the bathtub is 123 gallons.

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Suppose that f(x,y) = x^2−xy+y^2−5x+5y with D={(x,y)∣0 ≤ y ≤ x ≤ 5}The critical point of f(x,y) restricted to the boundary of D, not at a corner point, is at (a,b). Then a=____and b=___Absolute minimum of f(x,y) is ___and absolute maximum is ___

Answers

The critical point of f(x, y) restricted to the boundary of D, not at a corner point, is at (a, b). Then a= 5/2 and b = 0 Absolute minimum of f(x, y) is -25/4 and absolute maximum is 25 .

The critical point of f(x, y) is restricted to the boundary of D

f(x,y) = x² − xy + y² − 5x + 5y

The partial derivatives of f(x, y) are

∂f/∂x = 2x - y - 5

∂f/∂y = -x + 2y + 5

Now, let's examine the boundary of D. The given conditions state that 0 ≤ y ≤ x ≤ 5.

When y = 0: In this case, the boundary is the line segment where y = 0 and 0 ≤ x ≤ 5. We can restrict our analysis to this line segment.

Substituting y = 0 into the partial derivatives

∂f/∂x = 2x - 0 - 5 = 2x - 5

∂f/∂y = -x + 2(0) + 5 = -x + 5

Setting both partial derivatives to zero

2x - 5 = 0

=> x = 5/2

Therefore, at (x, y) = (5/2, 0), we have a critical point on the boundary.

When y = x

Substituting y = x into the partial derivatives

∂f/∂x = 2x - x - 5 = x - 5

∂f/∂y = -x + 2x + 5 = x + 5

Setting both partial derivatives to zero

x - 5 = 0

=> x = 5

Therefore, at (x, y) = (5, 5), we have a critical point on the boundary.

When x = 5

Substituting x = 5 into the partial derivatives

∂f/∂x = 2(5) - y - 5 = 10 - y - 5 = 5 - y

∂f/∂y = -5 + 2y + 5 = 2y

Setting both partial derivatives to zero

5 - y = 0

=> y = 5

Therefore, at (x, y) = (5, 5), we have a critical point on the boundary.

Two critical points on the boundary: (5/2, 0) and (5, 5).

Now, let's evaluate the function f(x, y) at these points to determine the absolute minimum and maximum.

For (5/2, 0)

f(5/2, 0) = (5/2)² - (5/2)(0) + 0² - 5(5/2) + 5(0)

f(5/2, 0) = 25/4 - 25/2

f(5/2, 0) = -25/4

For (5, 5)

f(5, 5) = 5² - 5(5) + 5² - 5(5) + 5(5)

f(5, 5) = 25 - 25 + 25

f(5, 5) = 25

Therefore, the absolute minimum of f(x, y) is -25/4, which occurs at (5/2, 0), and the absolute maximum is 25, which occurs at (5, 5).

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i need help with this chemistry homework

Answers

1. Nuclear chemistry studies about radioactive isotopes

2. Isotopes are elements with the same atomic number but different mass numbers.

Nuclear chemistry

The study of the chemical and physical characteristics of elements and their radioactive isotopes, including nuclear reactions, radioactive decay, and nuclear processes, is known as nuclear chemistry.

It entails the investigation of atomic nuclei's behavior, including interactions and transformations.  The isotopes have same atomic number but different mass numbers.

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what is the coefficient of x^13 y^7 in 〖(3x – 2y)〗^20?

Answers

The coefficient of x^13 y^7 in 〖(3x – 2y)〗^20 is -1164240.The coefficient of x^13 y^7 represents the number of ways we can choose x^13 and y^7 terms from the expansion of 〖(3x – 2y)〗^20.

To find the coefficient of x^13 y^7 in 〖(3x – 2y)〗^20, we use the binomial theorem, which states that the coefficient of x^m y^n in 〖(a+b)〗^n is given by the binomial coefficient (n choose k) times a^(n-k) times b^k, where k = n - m.

Therefore, we can write the coefficient of x^13 y^7 in 〖(3x – 2y)〗^20 as (20 choose 7) times (3x)^(20-7) times (-2y)^7. Simplifying this expression gives us (-1164240)x^13 y^7, which is the answer.

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Please help I don't get this at all

Answers

Answer:

(5,6) and (8,3)

Step-by-step explanation:

A and C are two of the corners of the square.

Imagine the top LEFT corner. If you drew a line straight UP from A and to the LEFT of C, it would meet at (5,6).

Now picture the bottom RIGHT corner. If you drew a line from A to the RIGHT and then another line from C DOWN, those lines would meet at (8,3).

I drew a pic showing the square you are trying to create! See attached.

The annual revenue for a clothing retailer is shown in the graph, where x is the number of years since 2000 and y is the revenue in tens of thousands of dollars. The revenue in 2001 was $24,000, and the revenue in 2019 was $96,000. Using these two data points, write the equation for a line of fit for the data. Revenue ($10,000s) 8642986 18 16 14 12 10 2 y (1, 2.4) O ● O O C (19, 9.6) O 2 4 6 8 10 12 14 16 18 * Years Since 2000​

Answers

Answer:The revenue in 2001 was $24,000, and the revenue in 2019 was $96,000. Using these two data points, write the equation for a line of fit for the data.

Step-by-step explanation:

Find the standard deviation of a sample n = 200 if p = 7. O a. 0.0160 O b.0.0324 O c.0.2640 O d. 0.0016

Answers

The standard deviation of the sample is approximately 0.0180.

To find the standard deviation of a sample with a sample size (n) and proportion (p), we can use the formula:

Standard deviation (σ) = √(p(1-p)/n)

Given that n = 200 and p = 0.07, we can substitute these values into the formula:

σ = √(0.07(1-0.07)/200)

σ = √(0.07(0.93)/200)

σ = √(0.0651/200)

σ ≈ √0.0003255

σ ≈ 0.01803

Rounding to four decimal places, the standard deviation of the sample is approximately 0.0180.

Comparing this result with the given options, none of them match exactly. However, the option closest to the calculated standard deviation is b. 0.0324. It is important to note that this option is not an exact match and may be considered an error or an approximation. The actual standard deviation based on the given values is approximately 0.0180.

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find the area of the infinite region in the first quadrant between the curve y=e^-x and teh x-axis

Answers

Thus,  the area of infinite region in the first quadrant between the curve y=e^-x and the x-axis is 1 square unit.

To find the area of the infinite region in the first quadrant between the curve y=e^-x and the x-axis, we need to integrate the function y=e^-x from x=0 to x=∞.

First, let's find the indefinite integral of e^-x:
∫e^-x dx = -e^-x + C

Next, we can use this indefinite integral to find the definite integral from x=0 to x=∞:
∫[0,∞]e^-x dx = lim┬(t→∞)∫[0,t]e^-x dx
= lim┬(t→∞)[-e^-t + e^0]
= lim┬(t→∞)[-e^-t + 1]
= 1

Therefore, the area of the infinite region in the first quadrant between the curve y=e^-x and the x-axis is 1 square unit.

It is important to note that this region is infinite because the curve y=e^-x approaches the x-axis but never actually touches it.

As we integrate from x=0 to x=∞, we are essentially adding up an infinite number of infinitely small rectangles, resulting in an infinitely large area.

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Find the standard form of the complex number, then represent the complex number graphically: 5(cos(135°) + i sin(135°))

Answers

To find the standard form of the complex number, we can use Euler's formula which states that e^(ix) = cos(x) + i sin(x). Using this formula, we can rewrite 5(cos(135°) + i sin(135°)) as 5(e^(i * 135°))

We can then use the fact that e^(ix) = cos(x) + i sin(x) to simplify this expression:
5(cos(135°) + i sin(135°)) = 5(e^(i * 135°)) = 5(cos(135°) + i sin(135°))
So the standard form of the complex number is:
5(cos(135°) + i sin(135°))
To represent this complex number graphically, we can plot the point (5 cos(135°), 5 sin(135°)) in the complex plane. This point has a magnitude of 5 and an angle of 135° (measured counterclockwise from the positive real axis). So the graphical representation of the complex number is a point in the second quadrant of the complex plane, 5 units away from the origin, and making an angle of 135° with the positive real axis.

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a man has 32 coins in his pocket, all of which are dimes and quarters. if the total value of his change is 620 cents, how many dimes and how many quarters does he have? your answer is

Answers

If the total value of his change is 620 cents, the man has 12 dimes and 20 quarters in his pocket.

Let's assume that the man has x dimes and y quarters in his pocket. We know that he has 32 coins in total,

x + y = 32.

We also know that the total value of his change is 620 cents, which can be expressed as

10x + 25y = 620.

To solve for x and y, we can use either substitution or elimination. Let's use substitution. Solving the first equation for x, we get

x = 32 - y.

Substituting this into the second equation, we get

10(32 - y) + 25y = 620

Simplifying this equation, we get

320 - 10y + 25y = 620

which yields

15y = 300.

Therefore, y = 20, and x = 32 - 20 = 12.

So the man has 12 dimes and 20 quarters in his pocket. We can check that this is correct by verifying that

12(10) + 20(25)

= 120 + 500

= 620.

In summary, we can solve the problem by setting up a system of equations, either using substitution or elimination to solve for the variables, and then checking our answer to make sure it is correct.

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need help with this problem

Answers

The solution to the equation is x = 0.

Option D is the correct answer.

We have,

The equation is:

(1 - 3x)^{1/3} - 1 = x

Let's start by isolating the radical term by adding 1 to both sides:

(1 - 3x)^(1/3) = x + 1

Next, we'll cube both sides to eliminate the radical:

[(1 - 3x)^(1/3)]^3 = (x + 1)^3

1 - 3x = (x + 1)^3

1 - 3x = x^3 + 3x^2 + 3x + 1

0 = x^3 + 3x^2 + 6x

Now we have a cubic equation, which we can solve by factoring out an x:

x(x^2 + 3x + 6) = 0

The quadratic factor doesn't have any real roots (since its discriminant is negative),

So the only solution is x = 0.

i.e

(1 - 3x)^(1/3) - 1 = 1^(1/3) - 1 = 0.

Thus,

The solution to the equation is x = 0.

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noe is at an elevation of 453 feet after descending at a rate of 50 feet per minute she is at an elevation of 146 feet how long does the descent take

Answers

It takes 6.14 minutes for Noe to complete the descent.

To determine the time it takes for Noe to descend from an elevation of 453 feet to 146 feet at a rate of 50 feet per minute, we can use the formula:

Time = Distance / Rate

In this case, the distance is the difference in elevations

= 453 - 146 =

307 feet,

and the rate is 50 feet per minute.

Substituting these values into the formula:

Time = 307 feet / 50 feet per minute

Time ≈ 6.14 minutes

Therefore, it takes 6.14 minutes for Noe to complete the descent.

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Use a sum-to-product formula to show the following. Sin(55°) sin(5°) = sin(65°) use a sum-to-product formula for sine and simplify

Answers

sin(55°) + sin(5°) = sin(65°) using a sum-to-product formula for sine

We can use the sum-to-product formula for sine to show that sin(55°) + sin(5°) = sin(65°). The formula is:

sin A + sin B = 2 sin[(A + B)/2] cos[(A - B)/2]

Substituting A = 55° and B = 5°, we get:

sin(55°) + sin(5°) = 2 sin[(55° + 5°)/2] cos[(55° - 5°)/2]

Simplifying, we get:

sin(55°) + sin(5°) = 2 sin(30°) cos(25°)

We know that sin(30°) = 1/2 and cos(25°) = sin(90° - 25°), so we can substitute these into the expression:

sin(55°) + sin(5°) =  sin(90° - 25°)

We also know that sin(90° - 25°) = sin(65°), so we can substitute this into the expression:

sin(55°) + sin(5°) = sin(65°)

Therefore, sin(55°) + sin(5°) = sin(65°) using a sum-to-product formula for sine.

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Given question is incomplete, the complete question is below

Show that sin(55°) + sin(5°) = sin(65°)

use a sum-to-product formula for sine and simplify

Find the volume of the cylinder. Round your answer to the nearest hundredth.
26.8 cm
9.8 cm
The volume is about
cubic centimeters.

Answers

The volume of the given cylinder with a height of 9.8cm and a diameter of 26.8cm is approximately 5525.42 cm³.

Given diameter of the cylinder = 26.8cm

So, radius = diametre/2 = 26.8cm/2 = 13.4 cm

height of the cylinder = 9.8cm

the formula for finding the volume of the cylinder = [tex]\pi[/tex]r²h

[here r = radius, h = height and [tex]\pi[/tex]  ≅ 3.14]

So, the volume of the given cylinder = 3.14 x (13.4)² x (9.8) ≅ 5525.42 cm³.

From the above solution, we can conclude that the volume of the given cylinder which is having the height of 9.8cm and a radius of 13.4cm is approximately 5525.42 cm³.

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Show transcribed dataFind the general solution of the differential equation r ′(t)=(4−5t)i+10tj. (Use symbolic notation and fractions where needed. Give your answer in the form ⟨x(t),y(t),z(t)⟩.

Answers

The general solution of the differential equation is: r(t) = ⟨x(t),y(t),z(t)⟩ = ⟨(4t − (5/2)t^2), (5t^2), C⟩

The differential equation given is r ′(t)=(4−5t)i+10tj, where r(t) represents the position vector of a particle moving in a plane.

To find the general solution of this differential equation, we need to integrate both sides with respect to t.

Integrating the x-component of r ′(t), we get:
r(t) = ∫(4−5t) dt i + ∫10t dt j + C
r(t) = (4t − (5/2)t^2)i + (5t^2)j + C

where C is a constant of integration.

Therefore, the general solution of the differential equation is:
r(t) = ⟨x(t),y(t),z(t)⟩ = ⟨(4t − (5/2)t^2), (5t^2), C⟩

where C is an arbitrary constant.

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what's the answer I really need it ​

Answers

Answer:A

Step-by-step explanation:

using the raiload racks

FODORHER
What is the probability of winning a lion, then another lion?
What should we multiply together to get the answer?
J.C
1/9
::1/10 :: 2/8
# 2/9 # 2/10
3/9
:: 3/10
4/8
2
:: 4/9
:: 4/10

Answers

Answer: J.C

1/9

::1/10 :: 2/8

Step-by-step explanation: good day! hope i helped love helping. bye

What happens to the t distribution as degrees of freedom increase? question 6 options: it approaches the uniform disribution it approaches the normal disribution it approaches the exponential disribution it approaches the binomial disribution

Answers

As the degrees of freedom increase, the t distribution b. approaches the normal distribution, which is a key assumption in many statistical tests. Understanding this relationship is important for making accurate statistical inferences and drawing valid conclusions from data.

The t distribution is a probability distribution that is commonly used in hypothesis testing. It is similar to the normal distribution but with heavier tails. As the degrees of freedom increase, the t distribution approaches the normal distribution. This means that the shape of the t distribution becomes more and more like the normal distribution as the sample size increases.
The reason for this is that the t distribution is based on the sample mean, which becomes more normally distributed as the sample size increases due to the central limit theorem. As the sample size increases, the standard error of the mean decreases, and the t distribution becomes less spread out and more peaked. This is why we use the t distribution instead of the normal distribution when we have a small sample size.

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
Mr. Schwartz builds toy cars. He begins the week with a supply of 85 wheels, and uses 4 wheels for each car he builds. Mr. Schwartz plans to order more wheels once he has fewer than 40 wheels left.
The inequality that can be used to find the number of cars, x, Mr. Schwartz builds before he places an order for more wheels is − x < 40.
Mr.Schwartz will need to order more wheels after building cars.

Answers

Mr. Schwartz will need to order more wheels after building 12 cars.

The number of cars x Mr. Schwartz builds before he places an order for more wheels can use the following steps:

Determine how many wheels are used per car:

4 wheels/car

Determine the number of wheels available at the start of the week:

85 wheels

Determine the minimum number of wheels needed to be available before placing an order:

40 wheels

Set up an inequality to represent the situation using x to represent the number of cars built before an order is placed:

Number of wheels used = 4x

Number of wheels remaining = 85 - 4x

Order is placed when number of wheels remaining is less than 40:

85 - 4x < 40

Solve for x by isolating the variable:

85 - 4x < 40

-4x < -45

x > 11.25

Since x represents the number of cars built can't have a fractional value for x.

The nearest integer to get the minimum number of cars that need to be built before an order is placed:

x > 12

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The function f(x) is shown in the graph.

Graph in two parts. Part one is increasing from -infinity in quadrant 3 to pass through (-3, -2) and (-1, 2) and continues increasing upward in quadrant 2. Part 2 is increasing from -infinity in quadrant 4 and passes through (1, -2) and (3, 2), then continues increasing upward to the right in quadrant one.

Which type of function describes f(x)?

Exponential
Logarithmic
Rational
Polynomial

Answers

The function f(x) appears to be a polynomial function.

Based on the description of the graph, the function f(x) does not appear to be exponential, logarithmic, or rational.

Exponential functions typically exhibit a constant rate of change as x increases or decreases, resulting in a curve that either exponentially increases or decreases. The graph described does not match this pattern, as it increases in some areas and decreases in others.

Logarithmic functions have a characteristic shape with a vertical asymptote and a slow growth or decay. The given graph does not exhibit this behavior.

Rational functions are defined as the ratio of two polynomials, and their graphs often have vertical and horizontal asymptotes. However, the description does not mention any asymptotes, suggesting that the function is not rational.

The most suitable choice based on the given information is polynomial. Polynomial functions are characterized by having non-negative integer exponents and can exhibit various shapes, including increasing or decreasing trends. The description mentions that the graph is increasing in quadrant 3 and quadrant 4, indicating that the function could be a polynomial.

Without additional information or the specific equation of the function, it is challenging to determine the exact degree or form of the polynomial function.

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7 teams participated in a hip-hop dance competition the table shows the average number of hours each team for each week in the school did you received the competition which scatter plot represents the data in the table

Answers

Answer:

Step-by-step explanation:

The answer is D

The set of parametric equations represents a line. Without eliminating the parameter, find the slope of the line. x = 7 + 2t, y = 5 – 4t II dy/ dx =?

Answers

Answer:

[tex]\frac{dy}{dx}=-2[/tex]

Step-by-step explanation:

Given a set of parametric equations that represent a line. Find the slope of the line without eliminating the parameter.

[tex]x = 7 + 2t \\ y = 5 - 4t[/tex]

Differentiate each equation with respect to t.

[tex]x = 7 + 2t \\\\\Longrightarrow \boxed{ \frac{dx}{dt}=2}[/tex]

[tex]y = 5-4t \\\\\Longrightarrow \boxed{ \frac{dy}{dt}=-4}[/tex]

[tex]\boxed{\left\begin{array}{ccc}\text{\underline{Note:}}\\\\\Big{\frac{dy}{dx}=\frac{(\frac{dy}{dt} )}{(\frac{dx}{dt})}} \end{array}\right}[/tex]

[tex]\frac{dy}{dx}=\frac{(\frac{dy}{dt} )}{(\frac{dx}{dt})}} \\\\\Longrightarrow \frac{dy}{dx}=\frac{-4}{2} \\\\\therefore \boxed{\boxed{\frac{dy}{dx}==-2}}[/tex]

Thus, the problem is solved.

Which expression is equivalent to 12.8-3s+15.5+8s?
A. -2+5s
B. 5s +28.3
C. 33.3s
D. 27.3 +5s

Answers

The correct expression which is equivalent to 12.8 - 3s + 15.5 + 8s is,

⇒ 5s + 28.3

We have to given that;

Expression to solve is,

⇒ 12.8 - 3s + 15.5 + 8s

Now, WE can simplify as;

⇒ 12.8 - 3s + 15.5 + 8s

Combine like terms,

⇒ 12.8 + 15.5 - 3s + 8s

⇒ 28.3 + 5s

⇒ 5s + 28.3

Thus, The correct expression is,

⇒ 5s + 28.3

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if z = x2 − xy 6y2 and (x, y) changes from (2, −1) to (2.04, −0.95),

Answers

The problem asks to find the approximate change in the value of z when the variables x and y change from (2, -1) to (2.04, -0.95), given the function z = x^2 - xy/(6y^2). Therefore, the approximate change in z is about 0.1933.

To find the rate of change of z with respect to x and y, we first need to take the partial derivatives of z with respect to each variable:

∂z/∂x = 2x - y/6y^2

∂z/∂y = -x/(3y^3) + 1/(2y)

Then, at the point (2, -1), we can evaluate these partial derivatives to find:

∂z/∂x = 2(2) - (-1)/(6(-1)^2) = 4 + 1/6

∂z/∂y = -2/(3(-1)^3) + 1/(2(-1)) = 2/3 - 1/2

Using the formula for total differential, we can approximate the change in z as:

Δz ≈ ∂z/∂x Δx + ∂z/∂y Δy

where Δx and Δy are the changes in x and y, respectively. In this case, Δx = 2.04 - 2 = 0.04 and Δy = -0.95 - (-1) = 0.05. Substituting the partial derivatives and the values for Δx and Δy, we get:

Δz ≈ (4 + 1/6)(0.04) + (2/3 - 1/2)(0.05) = 0.1933...

Therefore, the approximate change in z is about 0.1933.

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A researcher is testing the effects of a new high-fiber diet on cholesterol. She selects 40 patients with high cholesterol and randomly selects half to follow the new diet. The remaining patients follow the original diet. The researcher measures the participants' cholesterol once per month. What are the treatments?

Answers

The treatments by the researcher are:

The new high-fiber diet and original diet

What are the treatments in a research?

A randomized block design is defined as an experimental design whereby the experimental units are in groups referred to as blocks. The treatments are usually randomly allocated to the experimental units inside each block. When all treatments appear at least once in each block, we will have a completely randomized block design.

Now, from the question, we see that the researcher is testing the effects of a new high-fiber diet on cholesterol.

We also see that half are being tested on the original diet.

Thus, we can easily infer that the treatment here is the new high-fiber diet and original diet because that is what we are using to find the get a research on the testing.

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