Which statement about rectangles is true?
1. Only some rectangles are parallelograms.
2. Parallelograms have exactly 1 pair of parallel sides.
3. So, only some rectangles have exactly 1 pair of parallel sides.
1. All rectangles are parallelograms.
2. Parallelograms have 2 pairs of parallel sides.
3. So, all rectangles have 2 pairs of parallel sides.
1. Only some rectangles are parallelograms.
2. Parallelograms have 2 pairs of parallel sides.
3. So, only some rectangles have 2 pairs of parallel sides.
1. All rectangles are parallelograms.
2. Parallelograms have exactly 1 pair of parallel sides.
3. So, all rectangles have exactly 1 pair of parallel sides.
The correct statement about rectangles is:
1. All rectangles are parallelograms.
2. Parallelograms have exactly 1 pair of parallel sides.
3. So, all rectangles have exactly 1 pair of parallel sides.
A rectangle is a type of parallelogram that has additional properties. By definition, a rectangle is a quadrilateral with four right angles. This means that opposite sides of a rectangle are parallel. Since all four sides of a rectangle are right angles, it follows that a rectangle has exactly 1 pair of parallel sides.
Option 1 states that only some rectangles are parallelograms, which is incorrect. All rectangles are parallelograms because they have opposite sides that are parallel.
Option 2 states that parallelograms have 2 pairs of parallel sides, which is also incorrect. Parallelograms have exactly 2 pairs of parallel sides, not 4. A rectangle is a special type of parallelogram that has additional properties such as all angles being right angles.
Option 3 states that only some rectangles have 2 pairs of parallel sides, which is incorrect. All rectangles have exactly 1 pair of parallel sides, not 2. Having 2 pairs of parallel sides would make a shape a parallelogram, not a rectangle.
Therefore, the correct statement is that all rectangles are parallelograms and have exactly 1 pair of parallel sides. 1,2,3 are correct.
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Sue rode her bike 12 miles every day in March, April and May and 13 miles each day in June and August how many miles did she cycle total?
Answer:
372 March
360 April
372 May
390 June
403 August
1897 miles
Step-by-step explanation:
Sue cycled a total of 1889 miles in the five months of March, April, May, June, and August.
Explanation:In this problem, Sue rides her bike different amounts in different months but it's a straightforward calculation. To find the total miles she cycled, we need to add up the totals for each month. In March, April and May, she cycled 12 miles per day. Each of these months has 30 or 31 days, so let's average that to 30.5 days per month. 12 miles/day * 30.5 days/month * 3 months = 1098 miles. In June and August, she cycled 13 miles per day. We'll use the same average of 30.5 days per month. 13 miles/day * 30.5 days/month * 2 months = 791 miles. Adding those up, 1098 miles + 791 miles, we get a total of 1889 miles.
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Find LU factorization of the matrix:
[-5 0 4
10 2 -5
10 10 16]
Please explain in detail how to get the lower triangle
The LU factorization of the matrix is:
[-5 0 4] [1 0 0] [ -5 0 4 ]
[10 2 -5] = [1 0 0] [ 0 2 3 ] [ 0 2 3 ]
[10 10 16] [-2 5/2 1] [ 0 0 9 ]
To compute the LU factorization of a matrix, we need to decompose it into an upper triangular matrix U and a lower triangular matrix L, where L is a unit lower triangular matrix (i.e., its diagonal entries are all 1).
We begin with the given matrix:
[-5 0 4]
[10 2 -5]
[10 10 16]
First, we use row operations to transform the matrix into an upper triangular matrix. Let's use Gaussian elimination to reduce the matrix to row echelon form.
Let's add 2 times the first row to the second row to eliminate the entry in the (2,1) position:
[-5 0 4]
[0 2 3]
[10 10 16]
Next, let's add 2 times the first row to the third row to eliminate the entry in the (3,1) position:
[-5 0 4]
[0 2 3]
[0 10 24]
subtract 5 times the second row from the third row to eliminate the entry in the (3,2) position:
[-5 0 4]
[0 2 3]
[0 0 9]
We now have an upper triangular matrix U. To find L, we need to keep track of the row operations performed to get to this matrix. Specifically, to get L, we take the inverse of the row operations applied to the identity matrix.
The row operations we performed were to add multiples of the first row to the other rows. So, to get L, we apply the inverse row operations and write the multipliers as entries in L below the diagonal:
[1 0 0]
[-2 1 0]
[-2 5/2 1]
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27. What is the reflection image of (5, –3) across the y-axis? (–5, 3) (–5, –3) (–3, 5) (5, 3)
The search results are unrelated to the question of finding the reflection image of (5, -3) across the y-axis. To find the reflection image of a point across the y-axis, we need to change the sign of the x-coordinate of the point. Therefore, the reflection image of (5, -3) across the y-axis is (-5, -3).
On Tuesday, you have two orders. You may send each order to a separate factory OR both to the same factory. If they are both sent to be fulfilled by a single factory, you must use the total of the two orders to find that factory's cost per unit for production on this day. Remember that the goal is to end the day with the lowest cost per unit to produce the company's products. Order B is 7,000 units, and Order C is 30,000 units. First consider giving the orders to separate factories. Use the values and the following formula to calculate the average weighted cost per unit. Second, consider sending both orders to a single factory that had the lowest cost per unit to produce 37,000 units.
Answer:
49,321
Step-by-step explanation:
there's no explanation just add them
You have just paid $1,135.90 for a bond, which has 10 years before it, matures. It pays interest every six months. If you require an 8 percent return from this bond, what is the coupon rate on this bond? Par value is $1000.
The coupon rate on the bond is 7.56 percent.
To find the coupon rate on the bond, we need to calculate the annual interest payment and then divide it by the par value of the bond.
1. Calculate the semi-annual interest payment:
The bond pays interest every six months, so there are a total of 20 six-month periods (10 years x 2 periods per year).
The total amount paid in interest over the bond's lifetime is the difference between the purchase price and the par value: $1,135.90 - $1,000 = $135.90.
Divide the total interest payment by the number of periods: $135.90 / 20 = $6.795.
2. Calculate the annual interest payment:
Since the bond pays interest every six months, we need to double the semi-annual interest payment: $6.795 x 2 = $13.59.
3. Calculate the coupon rate:
Divide the annual interest payment by the par value of the bond: $13.59 / $1,000 = 0.01359.
4. Convert the coupon rate to a percentage:
Multiply the coupon rate by 100 to express it as a percentage: 0.01359 x 100 = 1.359%.
Therefore, the coupon rate on the bond is 7.56 percent (rounded to two decimal places).
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You are graphing rectangle A B C D in the coordinate plane. The following are three of the vertices of the rectangle A (-7,-2), B(3,-2) and C(3,-5). What are the coordinates of point D?
Answer:
The coordinates of point D are (-7, -5).
Step-by-step explanation:
Since ABCD is a rectangle, opposite sides are parallel and have the same length. We are given points A(-7, -2), B(3, -2), and C(3, -5).
We can find the length and direction of the sides AB and BC:
AB = B - A = (3 - (-7), -2 - (-2)) = (10, 0)
BC = C - B = (3 - 3, -5 - (-2)) = (0, -3)
Now, we can find the coordinates of point D by moving along the direction of side BC from point A:
D = A + (direction of BC) = (-7, -2) + (0, -3) = (-7, -5)
So, the coordinates of point D are (-7, -5).
PLEASE HELP YR 9 MATHS URGENT
Among the given four countries the one which has the largest land area is Algeria, and the total land area in k[tex]m^2[/tex] of the four countries is 5017000 k[tex]m^2[/tex].
Given the land area of Ethiopia is 1.13×[tex]10^6[/tex] k[tex]m^2[/tex] = 1130000 k[tex]m^2[/tex].
The land area of Algeria is 2.38×[tex]10^6[/tex] k[tex]m^2[/tex] = 2380000k[tex]m^2[/tex].
The land area of Nigeria is 9.24×[tex]10^5[/tex] k[tex]m^2[/tex] =924000k[tex]m^2[/tex].
The land area of Kenya is 5.83×[tex]10^5[/tex] k[tex]m^2[/tex] =583000 k[tex]m^2[/tex].
Now obviously 2380000k[tex]m^2[/tex] > 1130000 k[tex]m^2[/tex] > 924000k[tex]m^2[/tex] > 583000 k[tex]m^2[/tex] .
Hence, Algeria has the largest land area.(a)
Total land area will be, (1130000+2380000+924000+583000 )k[tex]m^2[/tex] = 5017000 k[tex]m^2[/tex].
Hence, the total land area in k[tex]m^2[/tex] of the four countries is 5017000k[tex]m^2[/tex]. (b)
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Convert: 18 yards = _____ feet 52 feet 6 feet 54 feet 216 feet
Answer:
18 yards = 54 feet
Step-by-step explanation:
using the conversion
1 yard = 3 feet
then
18 yards = 18 × 3 = 54 feet
a radioactive substance used in nuclear weapons decays at the rate of 3.6% per year. Calculate the half life of the radioactive substance
The half-life of the radioactive substance is approximately 18.81 years. This means that it takes around 18.81 years for half of the substance to decay.
To calculate the half-life of a radioactive substance, we need to determine the time it takes for half of the substance to decay.
In this case, we know that the substance decays at a rate of 3.6% per year.
Let's assume we start with a certain amount of the substance.
After one year, 3.6% of the substance will decay, leaving us with 96.4% of the original amount.
If we continue this process, we can calculate the remaining amount of the substance after each year:
Year 1: 96.4% remains
Year 2: 96.4% of 96.4% remains = 96.4% [tex]\times[/tex] 96.4%
Year 3: 96.4% of 96.4% of 96.4% remains = 96.4% [tex]\times[/tex] 96.4% [tex]\times[/tex] 96.4%
...
Year n: [tex](96.4)^n[/tex]% remains
To find the half-life, we need to solve the equation [tex](96.4)^n[/tex]%
Let's solve this equation:
[tex](96.4)^n[/tex] = 50%
Taking the logarithm of both sides:
[tex]log((96.4)^n) = log(50)[/tex]
n [tex]\times[/tex] log(96.4%) = log(50%)
n = log(50%) / log(96.4%)
Using a calculator, we can evaluate the right-hand side of the equation:
n ≈ -0.301 / -0.016
Simplifying the division, we get:
n ≈ 18.81.
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the quotient of x and 2 increased by 7
Answer:
x/2 + 7
Step-by-step explanation:
x/2 + 7 represents the quotient of x and 2 increased by 7
The answer is:
[tex]\bf{\dfrac{x}{2} +7}[/tex]
Work/explanation:
First things first, the quotient of two numbers is what you get once you divide one number by another one.
So, the quotient of x and 2 is x ÷ 2.
Second things second, when you increase a number by an amount, you add that amount to that number.
So as a result, we have
[tex]\bf{\dfrac{x}{2}+7}[/tex]
Hence, this is the answer.Find a function whose graph is a parabola with vertex (3, -2) and that passes through the point (4, 3).
I don't understand can someone help please
Answer:
[tex]y=5(x-3)^2+2[/tex]
Step-by-step explanation:
[tex]y=a(x-h)^2+k\\y=a(x-3)^2-2\\\\3=a(4-3)^2-2\\3=a(1)^2-2\\3=a-2\\5=a\\\\y=5(x-3)^2+2[/tex]
By using the vertex form of a parabola, we were able to plug in the vertex (h,k)=(3,-2) and then eventually our point (x,y)=(4,3) to solve for "a" to get the final function.
Mr mbhalati deposited R1500 an amount from sale of goods that were sold at a value added tax (VAT) inclusive price .calculate the Vat on goods sold
The VAT on the goods sold is R195.65 when a VAT rate of 15% is applied. It's important to note that this calculation assumes a standard VAT rate of 15% and may not be accurate for all jurisdictions or specific goods.
To calculate the value-added tax (VAT) on goods sold, we need to know the applicable VAT rate. VAT rates can vary from country to country, and even within different categories of goods. However, assuming a standard VAT rate of 15%, we can calculate the VAT on the goods sold.
First, we need to determine the VAT-exclusive price. Since the amount deposited by Mr. Mbhalati is VAT-inclusive, we can calculate the VAT-exclusive price by dividing the deposit amount by 1 plus the VAT rate:
VAT-exclusive price = Deposit amount / (1 + VAT rate)
= R1500 / (1 + 0.15)
= R1500 / 1.15
= R1304.35 (rounded to two decimal places)
To find the VAT amount, we subtract the VAT-exclusive price from the VAT-inclusive price:
VAT amount = VAT-inclusive price - VAT-exclusive price
= R1500 - R1304.35
= R195.65 (rounded to two decimal places)
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Let R be the relation defined on Z by aRb if a + b is even. Show that R is an
equivalence relation.
R s an equivalence relation on the set of integers Z using the properties of reflexivity, symmetry, and transitivity.
To show that the relation R defined on the set of integers Z is an equivalence relation, we need to demonstrate that it satisfies three properties: reflexivity, symmetry, and transitivity.
Reflexivity: For any integer a, a + a = 2a, which is always even. Therefore, aRa holds true for all integers a, showing that R is reflexive.
Symmetry: If aRb holds, then a + b is even. However, the sum of two integers is unaffected by their order. So if a + b is even, b + a will also be even. Hence, if aRb, then bRa, establishing symmetry.
Transitivity: Suppose aRb and bRc, meaning a + b and b + c are both even. In this case, we can express a + c as (a + b) + (b + c) - 2b. Since the sum of two even numbers is even, and 2b is also even, it follows that a + c is even. Therefore, if aRb and bRc, then aRc, demonstrating transitivity.
In conclusion, the relation R satisfies the properties of reflexivity, symmetry, and transitivity, proving that it is an equivalence relation on the set of integers Z.
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A bag contains red marbles, blue marbles and green marbles only. The ratio of the number of each marble is Red:Green:Blue=12:5:2. There are 112 more red marbles than green marbles. Work out the number of blue marbles
Answer:
There are 14 blue marbles in the bag.
Step-by-step explanation:
Let's call the number of green marbles "x". Then we know that the number of red marbles is 112 more than x, or x+112. We can use the ratio to find the number of blue marbles.
First, we need to find the total number of parts in the ratio. That's 12+5+2=19.
Next, we can use the ratio to set up an equation. The number of blue marbles is 2/19 of the total number of marbles. We can write this as:
2/19 (x + x + 112 + blue) = blue
Simplifying this equation, we get:
2x + 224 = 17blue
Now we can solve for blue:
blue = (2x + 224)/17
We know that blue is a whole number, so we need to find a value of x that makes the numerator of this fraction divisible by 17. After some trial and error, we find that x=3 works:
blue = (2(3) + 224)/17 = 14
Therefore, there are 14 blue marbles in the bag.
Solve the inequality and graph the solution on the line provided. 6x-6<-30
The solution to the inequality 6x - 6 < -30 is x < -4, and it is graphically represented as a closed circle at -4 and shading to the left of -4 on the number line.
To solve the inequality 6x - 6 < -30, we can follow these steps:
Step 1: Add 6 to both sides of the inequality to isolate the variable:
6x - 6 + 6 < -30 + 6
6x < -24
Step 2: Divide both sides of the inequality by 6 to solve for x:
(6x)/6 < (-24)/6
x < -4
The solution to the inequality is x < -4. This means that any value of x less than -4 will satisfy the inequality.
To graph the solution on the number line, we represent -4 as a closed circle (since it is not included in the solution) and shade the region to the left of -4 to indicate all values less than -4.
On the number line, mark a point at -4 with a closed circle:
<--------●-----------------
Then, shade the region to the left of -4:
<--------●================
The shaded region represents the solution to the inequality x < -4.
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Use what you know about intersecting lines to label the missing and
picture below.
35°
X
type of angle pair:
zoom in
X =
OManeuvering the Middle LLC, 2016, 2022
Answer:
x = 145
Step-by-step explanation:
x and 35° lie on a straight line and are supplementary angles , sum to 180°
x + 35 = 180 ( subtract 35 from both sides )
x = 145
Haley pays a montlhy fee is 20$ for her cell phone and then pays 5 cents per minute used. The total cost of haleys monthly cell phone bill can be expressed by the function C(m)=0.05m+20, where m is the number of minutes used. What are domain and range of the function C(m)
The domain of the function C(m) is the set of all possible values for the number of minutes used, m. In this case, the number of minutes used cannot be negative because it represents the actual usage, so the domain of the function C(m) is m ≥ 0. In other words, the domain includes all non-negative real numbers or zero.
The range of the function C(m) is the set of all possible values for the total cost of Haley's monthly cell phone bill.
The cost is determined by the number of minutes used, and since the function C(m) is a linear equation with a positive coefficient for the m term, the cost increases as the number of minutes used increases.
Therefore, the range of the function C(m) includes all real numbers greater than or equal to the fixed monthly fee of $20. In interval notation, the range can be expressed as [20, ∞), indicating that the cost can be any value greater than or equal to 20.
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Given rhombus ABCD, find the
perimeter if AE = 9 and BE = 12
The perimeter of the Rhombus ABCD that is given above would be = 60.
How to calculate the perimeter of the given rhombus?To calculate the perimeter of the rhombus, the following steps needs to be taken as follows:
But;
AE = a = 9
BE = b = 12
AB = c = ?
Using the Pythagorean formula;
C² = a²+b²
C = 9²+12²
= 81+144
= 225
c = √225 = 15
The perimeter = 4× 15 = 60
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Apart from division or a fraction, what does '/' mean?
/ mean do or does when a 3rd person is present
Referring to the equation for earnings on a checking account (I = rB − sx − f), where, if r = 0.0095, B = $2,000.00, s = 0, x = 28, and f = $4.00, what are the customer’s earnings for the month if her minimum balance is $2,000.00?
$8.00
$21.00
$15.00
$7.00
Answer:
Based on the given equation for earnings on a checking account, we can substitute the given values to find the customer's earnings for the month if her minimum balance is $2,000.00:
I = rB - sx - f
I = 0.0095($2,000.00) - 0(28) - $4.00
I = $19.00 - $4.00
I = $15.00
Therefore, the customer's earnings for the month if her minimum balance is $2,000.00 is $15.00. Option C is the correct answer.
What is the equivalent to the product below when x>_0?
√5x² •√15x²
In a large restaurant, there are 9 times as many chairs as tables. The restaurant is famous for its very spicy chili. If the restaurant has 360 chairs, how many tables are in the restaurant?
Answer:
There are 40 tables.
Step-by-step explanation:
Since we know that there are 9 times as many chairs, then there are tables, all we have to do is divide the number of chairs by 9, and we get the answer 40.
3rd Grade Math Question
Answer:
∠ 1 = 110° , ∠ 2 = 70°
Step-by-step explanation:
∠ 1 and ∠ 2 lie on a straight line and sum to 180° , that is
6x + 20 + 4x + 10 = 180
10x + 30 = 180 ( subtract 30 from both sides )
10x = 150 ( divide both sides by 10 )
x = 15
Then
∠ 1 = 6x + 20 = 6(15) + 20 = 90 + 20 = 110°
∠ 2 = 4x + 10 = 4(15) + 10 = 60 + 10 = 70°
Graphing Linear Inequalities and Systems of Linear Inequalities in Real-World Situations - Item 50373Question 2 of 7
A coffee shop orders at most $ 3 , 500 worth of coffee and tea. The shop needs to make a profit of at least $ 1 , 900 on the order. The possible combinations of coffee and tea for this order are given by this system of inequalities, where c = pounds of coffee and t = pounds of tea:
6 c + 13 t ≤ 3 , 500
3 . 50 c + 4 t ≥ 1 , 900
Which graph's shaded region represents the possible combinations of coffee and tea for this order?
Material Cost per
Pound Profit per
Pound
Coffee $6.00 $3.50
Tea $13.00 $4.00
CLEAR CHECK
A graph with X-axis labeled c and points labeled 100 to 600, and Y-axis labeled t, with points labeled 100 to 600. 1 line starts just under 300 on the Y-axis and goes to the right of the X-axis. Another line starts at about 450 on the Y-axis and goes to just past the 500 on the X-axis. The space above both lines is shaded.
A graph with X-axis labeled c and points labeled 100 to 600, and Y-axis labeled t, with points labeled 100 to 600. 1 line starts just under 300 on the Y-axis and goes to the right of the X-axis. Another line starts at about 450 on the Y-axis and goes to just past the 500 on the X-axis. The space between the 2 lines after they cross near the 500 mark is shaded.
A graph with X-axis labeled c and points labeled 100 to 600, and Y-axis labeled t, with points labeled 100 to 600. 1 line starts just under 300 on the Y-axis and goes to the right of the X-axis. Another line starts at about 450 on the Y-axis and goes to just past the 500 on the X-axis. The space between the 2 lines between the Y-axis and where they cross near the 500 mark is shaded.
A graph with X-axis labeled c and points labeled 100 to 600, and Y-axis labeled t, with points labeled 100 to 600. 1 line starts just under 300 on the Y-axis and goes to the right of the X-axis. Another line starts at about 450 on the Y-axis and goes to just past the 500 on the X-axis. The space below both lines is shaded.
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Answer:
695,512
Step-by-step explanation:
no explanation just x
Find the exact value of sin (theta) if csc (theta)=13/9 and 0<(theta)<90
When csc([tex]\theta[/tex]) = 13/9 and 0 < theta < 90, the exact value of sin([tex]\theta[/tex]) is 9/13.
To find the exact value of sin([tex]\theta[/tex]) given that csc([tex]\theta[/tex]) = 13/9 and 0 < [tex]\theta[/tex] < 90 degrees, we can use the reciprocal relationship between csc([tex]\theta[/tex]) and sin([tex]\theta[/tex]).
The reciprocal of csc([tex]\theta[/tex]) is sin([tex]\theta[/tex]), so sin([tex]\theta[/tex]) = 1 / csc([tex]\theta[/tex]). Therefore, sin([tex]\theta[/tex]) = 1 / (13/9).
To simplify the expression, we can multiply the numerator and denominator of 1 / (13/9) by the reciprocal of 13/9, which is 9/13:
sin([tex]\theta[/tex]) = (1 / (13/9)) * (9/13)
Multiplying the fractions, we get:
sin([tex]\theta[/tex]) = 9 / 13
Hence, the exact value of sin([tex]\theta[/tex]) is 9/13.
Since the value of csc([tex]\theta[/tex]) is positive (13/9) and [tex]\theta[/tex] is in the first quadrant (0 < [tex]\theta[/tex] < 90), we know that sin([tex]\theta[/tex]) is also positive. This confirms that sin([tex]\theta[/tex]) = 9/13 is the correct value.
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ہے
x
-3
-2
0
2
3
1(x)
9
4
0
4
9
What is the domain of this function?
OA. (-3,9)
OB. (-3, -2, 0, 2, 3)
OC. {0, 4, 9)
OD. (0, 2, 3)
Answer:
introduction of a business invironment
Washington Junior High is holding a bake sale to raise money for new computers in their library. The principal has estimated that they will need 4 1/2 dozen cookies. If 9 parents have volunteered to bring cookies, how many cookies will each need to bring.
Answer: 6 cookies
Step-by-step explanation:
4.5 dozen is 54 cookie
Dividen 54 by the 9 parents is 6 cookie so each partner need to make at least 6 cookie
What is the M.A.D. (mean absolute deviation) of the following data set?
8 9 9 7 8 6 9 8
The mean absolute deviation is 0.75
How to determine the mean absolute deviationTo calculate the mean absolute deviation (M.A.D.), you need to find the average of the absolute differences between each data point and the mean of the data set
From the information given, we have that the data set is;
8 9 9 7 8 6 9 8
Let's calculate the mean, we get;
Mean = (8 + 9 + 9 + 7 + 8 + 6 + 9 + 8) / 8
Mean = 64 / 8
Divide the values
Mean = 8
Let's determine the absolute difference, we get;
Absolute differences=
|8 - 8| = 0
|9 - 8| = 1
|9 - 8| = 1
|7 - 8| = 1
|8 - 8| = 0
|6 - 8| = 2
|9 - 8| = 1
|8 - 8| = 0
Find the mean of the absolute differences:
Average of absolute differences = (0 + 1 + 1 + 1 + 0 + 2 + 1 + 0) / 8
Absolute difference = 6 / 8 = 0.75
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PLEASE ANSWER AND FILL IN THE BOX if needed
There is no solution in the system
How to determine the solution to the systemFrom the question, we have the following parameters that can be used in our computation:
The augmented matrix
In the augmented matrix, we have
Rows = 4
Columns = 6
This means that
There are 4 equations in the system and there are 5 variables
The general rule is that
The number of variables must be equal to or less than the number of equations
Hence, there is no solution in the system
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