First come first serve, solve it properly and get points.

The mass of the car will be same as m, and its weight will be 3w/4 on the planet which has three times the mass of the earth and twice the radius of the earth.

Mass is a constant quantity of an object which remains constant irrespective of the place, where the object is placed. So the mass will remains the same as m.

Acceleration due to gravity of earth is defined as, g = GM/R²

Where G is universal gravitational constant, M is the mass of the earth, and R is the radius of the earth.

Mass of the planet, = 3M  

Radius of the planet, = 2R

Acceleration due to gravity of the planet, g₁ = G(3M)/(2R)²

g₁ = 3GM/4R²

g₁ = 3g/4

We know

weight on a planet = mass × acceleration due to gravity of that planet

w = mg

w₁ = mg₁

w₁ = m(3g)/4

w₁ = 3mg/4

w₁ = 3w/4

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The pressure required to change the volume from 0.650 L to 0.250 L is 298 kPa. We can find out using Ideal Gas Law.

The ideal gas law states that the pressure, volume, and temperature of a gas are related by the equation:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in kelvins.

Since the temperature is constant, we can simplify the equation to:

P1V1 = P2V2

where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume. Rearranging the equation gives:

P2 = P1 * (V1 / V2)

Substituting in the known values, we find:

P2 = 101 kPa * (0.650 L / 0.250 L) = 298 kPa

Therefore, pressure is 298kPa.

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The ratio of surface area to mass when the density of an object decreases while the surface area and volume remain the same, increases. The correct option is A.

An object's surface area and volume don't change, but its density does. The formula for density

ρ = m ÷ V

V = m ÷ ρ

m = mass (kg)

V = volume (m³)

ρ = the density (kg/m³)

The density decreases

ρ₁ > ρ₂

The surface area remains the same

A₁ = A₂

The volume remains the same

V₁ = V₂

V₁ = V₂

m₁ ÷ ρ₁  = m₂ ÷ ρ₂

m₂ × ρ₁ = m₁ × ρ₂

m₂ = (m₁ × ρ₂) ÷ ρ₁

ρ₁ > ρ₂

m₂ < m₁

The density decreases, and the mass also decreases.

The quantity of surface area per unit mass of an object is known as the surface area to mass ratio.

S:M = A ÷ m

At initial (S:M)₁ = A₁ ÷ m₁

At final (S:M)₂ = A₂ ÷ m₂

A₁ = A₂

m₂ < m₁

(S:M)₂ > (S:M)₁

Thus, the surface area to mass ratio will increase.

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A) The velocity of the two freight car is 1.83 m/s, B) The impulse exerted on each freight train car is 22000 kg-m/s, C) The net force exerted on each freight train car is 31428.6 N.

Mass of the loaded freight car, m₁ = 10000 kg

Initial velocity of the loaded freight car, v₁ = 3 m/s

Mass of the empty freight car, m₂ = 2000 kg

Velocity of the empty freight car, v₂ = -4 m/s

Let the velocity of the coupled car after collision, = v

By the law of conservation of momentum,

m₁v₁ + m₂v₂ = (m₁+m₂)v

A) v = (10000×3 - 2000×4)/(10000+2000)

    v = 1.83 m/s

B) Impulse = change in momentum(Δp)

Δp = 10000×3 - 2000×4 = 22000 kg-m/s

C) Net force, F = Impulse/time = 22000/0.7

  F = 31428.6 N

D) The collision is inelastic as the final speed of both the car is less than their initial velocities.

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The Parthenon is a famous ancient Greek temple known for its classical architecture, which was built in Athens between 447 and 432 BC.

Many other structures have been inspired by the Parthenon and have similar characteristics, including:

These structures, like the Parthenon, showcase the beauty and elegance of ancient Greek architecture and its influence on other cultures and time periods.

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The time required to drop the pressure of one of the gases from 2.0 atm to 0.25 atm at 389 K is 288 hours, or Option (D).

For a first order reaction, the change in pressure of a gas is proportional to its initial concentration and to the rate constant of the reaction. The half-life of a first order reaction is defined as the time required for the concentration of a reactant to decrease to half its initial value.

The rate constant (k) of a first order reaction can be related to its half-life (t1/2) as follows:

k = 0.693 / t1/2

We can use this relationship to find the rate constant for our reaction:

k = 0.693 / 24 hours = 0.0289 h^-1

Next, we can use the rate constant to find the time required for the pressure of one of the gases to decrease from 2.0 atm to 0.25 atm:

P = P0 * e^(-kt)

ln(P/P0) = -kt

-t = ln(P/P0) / k

where P0 is the initial pressure, P is the final pressure, t is the time, and e is the base of natural logarithms.

Plugging in the values, we get:

-t = ln(0.25/2.0) / 0.0289 h^-1

t = 288 hours

Therefore, the time required to drop the pressure of one of the gases from 2.0 atm to 0.25 atm at 389 K is 288 hours, or Option D).

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Answer:

All 3 cards are completely different

Frequency is measured in hertz and it is described by the number of waves that pass a certain point within a certain time

The number of waves that pass a fixed point in a unit of time is known as frequency in physics.

It is also the number of cycles or vibrations that a body in periodic motion experiences in a unit of time.

When a body in periodic motion moves through a series of events or locations before returning to its initial state, it is said to have experienced one cycle or one vibration. A simple harmonic motion is also seen under angular velocity.

If one cycle or vibration takes half a second to complete, the frequency is two per second.

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"Ancient astronomers knew about precession of the celestial equator, which means that as time passes, it points at a different star." Correct option is D.

Right now, the north celestial pole is pointing just 1° from the star Polaris. Ancient astronomers also employed the celestial equator and the Earth's North Pole as points of reference for observing and measuring the stars.

The north celestial pole's direction progressively shifts over time as a result of the ecliptic's precession, which is a slow, ongoing change in the orientation of the Earth's axis of rotation. A combination of gravitational forces from the Sun, Moon, and other planets result in this phenomenon.

The two places in the sky where the axis of rotation of the Earth intersects the celestial sphere are known as the north and south celestial poles.

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Answer:

The momentum bar chart is a tool used to track the changes in momentum of objects in a system over time.

(a) With one cart as the system:

Initial Momentum: m1v1

Final Momentum: m1v1'

Change in Momentum: m1(v1' - v1)

(b) With both carts as the system:

Initial Momentum: m1v1 + m2v2

Final Momentum: m1v1' + m2v2'

Change in Momentum: (m1 + m2)(v1' + v2' - v1 - v2)

The above expressions represent the changes in momentum of the carts, where m1 and m2 are the masses of the carts, v1 and v2 are their initial velocities, and v1' and v2' are their final velocities. The expressions can be used to calculate the net force acting on the carts using Newton's second law, F = Δp/Δt, where Δp is the change in momentum and Δt is the change in time.

Physical quantities that can be calculated from this scenario include the initial and final momentum of the carts, the change in momentum, the net force acting on the carts, and the acceleration of the carts.

It will be like over 2.4353m

The vapor pressure of solvent A at 25 °C is approximately 2.93 atm, if this solvent has a normal boiling point of 80.1 °c. the ∆hvap for solvent a is 30.5 kj/mol.

The vapor pressure of a solvent can be estimated using the Clausius-Clapeyron equation, which relates the vapor pressure of a substance to its normal boiling point and enthalpy of vaporization. The equation is:

ln(P2/P1) = ΔHvap/R * (1/T1 - 1/T2)

Where P1 and P2 are the vapor pressures at two temperatures, T1 and T2, ΔHvap is the enthalpy of vaporization, and R is the gas constant. We can rearrange the equation to solve for the vapor pressure at a given temperature:

P = P1 * exp(ΔHvap/R * (1/T1 - 1/T2))

In this case, the normal boiling point of solvent A is 80.1 °C, so T1 can be taken as that temperature. The temperature we want to find the vapor pressure for is 25 °C, so T2 is 25 + 273.15 = 298.15 K. The enthalpy of vaporization of solvent A is given as ΔHvap = 30.5 kJ/mol.

Plugging in these values and using the ideal gas law to convert pressure units, we find:

P = 1 atm * exp(30.5 kJ/mol / (8.314 J/mol*K) * (1/371.15 K - 1/298.15 K))

P = 2.93 atm

So the vapor pressure of solvent A at 25 °C is approximately 2.93 atm.

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In an elliptical orbit, the kinetic energy of an object is smallest at the point in the orbit where the object is at its farthest distance from the planet, also known as the apogee.

At this point, the object is moving the slowest and has the least kinetic energy. The gravitational potential energy of the object is at a maximum at this point, since the object is farthest from the planet and the gravitational pull is weakest. The total energy of the object remains constant as it moves along its elliptical orbit, but the distribution of energy between kinetic and potential energy changes as the object moves from perigee (the point of closest approach to the planet) to apogee and back.

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No it does not take same amount of solid materials to saturate 50 milileter of water.

There are different amount of voids in different types of solids (for example: soil). When the volume of the voids with respect to the volume of the solid particles is called void ratio.

void ratio(N) = volume of voids(Vₙ)/volume of solids(Vₓ)

When the volume of void is completely filled with water and no air is present in the voids then this phenomena is know as saturation. But as we discussed earlier that different amount of solid contains different volume of voids, so it will take different amount of solids to be saturated by 50 ml of water.

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Using fin material that is too thin or weak for a rocket and its motor can result in fin failure, trajectory instability, motor damage, and loss of control.

Fin failure: Thin or weak fins may not be able to withstand the aerodynamic forces and stresses during launch, which can result in fin failure.

Trajectory instability: Weak or poorly designed fins can cause trajectory instability, making the rocket unpredictable and potentially dangerous.

Motor damage: In some cases, using weak or improperly designed fins can lead to excessive stress on the motor casing, causing damage and potentially leading to a motor failure.

Loss of control: If fins fail or the rocket becomes unstable, it may become uncontrollable and fall back to the ground, potentially causing damage or injury.

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To determine if the average mass of the object, based on the experimental trials, agrees with the mass measured with a digital scale, you will need to compare the two values.

If the difference between the two values is small, then the average mass of the object based on the experimental trials is in agreement with the mass measured with the digital scale.

If the difference between the two values is large, then the average mass of the object based on the experimental trials is not in agreement with the mass measured with the digital scale.

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Answer:

Explanation:

v=wavelengths *frequency

5.0/5.0

But I think is wrong the question

Because if they ask you wavelength you need to have frequency and speed

Contrary charges attract each other whereas like charges repel one another. Accordingly, two negative charges repel one another, but a positive charge pulls a negative charge toward it. Along the line between the two charges, attraction or repulsion occurs.

Example :

15N = 9 * (10)9 NM²(-5.0 *  (10) -5 C) (-5.0 * (10 )- 5 c) / c² (d)²

15N = 22.5 NM² / d²

d ² = 22.5 NM² / 15N

d² = 1.5m².

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3750N work has been done on the lawn mower, the work done is equal to 1 joule.

How are work hours determined?

250N * 15N = 3750N.

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The net force on charge of 1 nC is, [tex]F = 0\ \hat{i} + 1.02 \times 10^{-3}\ \hat{j}[/tex] Newtons.

Electric force on a charge q₁ due to charge q₂ is,

[tex]F = \dfrac{kq_1q_2}{r^2}[/tex],

where r is the distance between the charges and k is the permittivity of free space.

The other four charges are of magnitude 2 nC.

The diagonals of a square are equal. Hence the magnitude of forces due to all other four charges is same.

Now, talking about direction of forces, the force, for the positive 2 nC charge its towards the negative and for negatives too it's towards the negative charge.

Now, the y- component of forces cancel away.

The x-component in negative x-direction adds up.

[tex]F = 4 \times \dfrac{k(2)(1)}{\dfrac{1}{\sqrt2}^2} \times 10^{-9-9+4} \times sin(45^0)[/tex]

[tex]F = 1.02 \times 10^{-3}[/tex]

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The unit of the two quantities used in the Newton's third law is Newton, which is denoted by N.

Newton's third law states that there is equal and opposite reaction for every action, In other words, There is an equal reaction for every force, but in the direction opposite to direction of the force. These forces are the quantities which are used in this law. The SI unit of reaction and force is Newton, which is equal to kg-m/s². It is denoted by N. It is formulated as: Force = mass × Acceleration.

F = m × a

Hence the correct option is C.

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Using Ohm's law, the current flow across the resister is 5 Ampere, if the voltage across the resister is 10 volts, and the resistance is 2Ω.

Voltage across the resistor, V = 10 volts

Resistance of the resistor, R = 2Ω

Let the current flow in the resistor, = I

According to Ohm's law, current flow in a conductor is directly proportional to the voltage across it. The ratio of the voltage and current is a constant called "Resistance".

I ∝ V

R = V/I

I = V/R

I = 10/2

I = 5 A

So the current flow across the resister is 5A.

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Solid water becomes a liquid when the pressure increases isothermally. The entropy of the water   Increases

This is because the increase in pressure causes the water molecules to gain more thermal energy and become more disordered.

This results in an increase in entropy, as the number of available microstates for the water molecules has increased.

In general, an increase in temperature or pressure results in an increase in entropy, as it promotes a greater degree of disorder and randomness in the system.

Conversely, a decrease in temperature or pressure will result in a decrease in entropy, as it promotes a greater degree of order and stability in the system.

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10 kg object is moving in a straight line with an initial speed of 2 m/s.it will take  8 seconds for the speed of the object to increase to 10 m/s if its kinetic energy increases at a rate of 20 j/s.

In an isolated system, energy is conserved, meaning that the total energy of the system remains constant. In this case, the rate of energy increase is 20 J/s, meaning that 20 J of energy is added to the system each second. This energy is used to accelerate the object, increasing its kinetic energy and thus its speed.  

The equation t = (KE2 - KE1)/P can be used to calculate the amount of time it takes for an object to accelerate from one speed to another given a rate of energy increase. In this case, the object is accelerating from an initial speed of 2 m/s to a final speed of 10 m/s, and the rate of energy increase is 20 J/s. Therefore, it will take 8 seconds for the object to reach its final speed.

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When traveling twice as fast your kinetic energy is increased: by four times

It is the energy possessed by a body due to its relative motion. It is usually expressed in Joules (J).

The kinetic energy depends on velocity, so when the velocity increased twice the kinetic energy increase 2^2= 4

The kinetic energy formula is:

K.E. = 1/2 * m * v²

Where:

v = speed

m = mass

Joules = Kg m²*s²

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Answer:

The density of a material can be found by using the formula:

Density = Mass / Volume

The volume of the block can be found by multiplying its three dimensions:

Volume = 5.29 cm x 4.45 cm x 3.34 cm = 81.99 cm^3

So,

Density = 882.2 g / 81.99 cm^3

= 10.77 g/cm^3 (rounding to two significant figures)

The maximum speed at which the car can safely negotiate the curve without slipping is 450 m/s

The formula v = (Ff / m) x r, where

The maximum speed of the vehicle can be calculated using the friction force Ff, mass m, and curve radius r.

Calculating maximum speed is done as follows:

= (4500N/500kg) x 50m

= 450 m/s

The force produced when two sliding surfaces come into contact with one another is known as the frictional force.

The texture of the surface and the amount of force holding the two surfaces together both have a significant impact on this force.

For instance, the weight of the first thing will exert frictional force when it is placed on top of another object.

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It happens due to the elasticity of balloon.Also, the pressure inside the balloon of air is higher than outside, which creates a difference between the surrounding air pressure and the pressure inside the balloon.

why, when popped, does a fully inflated balloon make a louder noise than a partially inflated balloon?

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The required solution of the dimensional formula is calculated to be [M][L]/[T]. Correct option is B.

Dimensional analysis is the practice of checking relations between physical quantities by identifying the dimensions of the physical quantities.

If Q is the unit of a derived quantity represented by Q = M^a L^b T^c, then M^a L^b T^c is called the dimensional formula and the exponents a, b, and c are called the dimensions.

The given expression is the multiplication of dimensional formulae of two different physical quantities.

We know that,

Mass m = [M]

Length l = [L]

Time t = [T]

The given expression to solve is,

[M][L]²/[T]² . [T]/[L] = [M][L]/[T]

Thus, the required solution of the given expression is [M][L]/[T].

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An osmotic pressure of 7 atm in units of [tex]\frac{dyne}{cm^{2} }[/tex] is [tex]7\times10^{6}\frac{dyne}{cm^{2} }[/tex].

Osmotic pressure and various other colligative properties of solutions are closely connected. These are induced by solutes dissolving in a solution and include the freezing point depression, boiling point elevation, and vapour pressure depression. Instead than using direct measurements of osmotic pressure, the osmolarity is frequently calculated from vapour pressure depression or freezing point depression. The concentration required to witness these phenomena is called osmolarity.

Albumin and other macromolecules inside the intravascular compartment exert an osmotic force known as colloid osmotic pressure (COP), also known as oncotic pressure, which balances the hydrostatic forces of the capillaries and venules to determine the net fluid flux across the endothelium.

Now, 1 atm=1.03bar

and 1.03 bar=[tex]10^{6}\frac{dyne}{cm^{2} }[/tex]

So, 7 atm=[tex]7\times10^{6}\frac{dyne}{cm^{2} }[/tex]

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