The force constant of the spring is 1442 N/m, the mass of the fish that stretches the spring 5.50 cm is 2.13 kg, and the distance between the half-kilogram marks on the scale is 3.4 mm.
a) To find the force constant of the spring, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position. The equation for Hooke's Law is[tex]F = -k * x[/tex], where F is the force, k is the force constant, and x is the displacement.
we can rearrange Hooke's Law to solve for the force constant: [tex]k = -F / x.[/tex] Plugging in the values, we have [tex]k = -(12.0 kg * 9.8 m/s^2) / 0.082 m[/tex]. Calculating this, we find that the force constant of the spring is approximately 1442 N/m.
b) we can again use Hooke's Law. Rearranging the equation to solve for mass, we have [tex]m = -F / (k * x)[/tex]. Plugging in the values, we have [tex]m = -(0.082 m * 1442 N/m) / 0.055 m[/tex]. Calculating this, we find that the mass of the fish is approximately 2.13 kg.
c) we need to consider that the force exerted by the spring is directly proportional to the displacement. Since the force constant is known (1442 N/m), we can use Hooke's Law to relate the displacement to the force. Considering a 0.5 kg increment in mass, we have[tex]F = -k * x[/tex]. Rearranging the equation, we find [tex]x = -F / k = -(0.5 kg * 9.8 m/s^2) / 1442 N/m[/tex]. Calculating this, we find that the displacement (or distance between the half-kilogram marks) is approximately 0.0034 m or 3.4 mm.
Therefore, the force constant of the spring is 1442 N/m, the mass of the fish that stretches the spring 5.50 cm is 2.13 kg, and the distance between the half-kilogram marks on the scale is 3.4 mm.
To learn more about force constant click here: brainly.com/question/29598403
#SPJ11
A spherical conductor with a 0.233 m radius is initially uncharged. How many electrons should be removed from the sphere in order for it to have an electrical potential of 6.50 kV at the surface?
Approximately [tex]1.046 * 10^5[/tex] electrons should be removed from the sphere to achieve an electrical potential of 6.50 kV at the surface.
To determine the number of electrons that should be removed from the sphere, we need to calculate the net charge required to achieve the desired electrical potential at the surface.
The electrical potential V at the surface of a conductor is given by:
V = k * (Q / r)
where V is the potential, k is Coulomb's constant (9.0 * 10^9 N m^2/C^2), Q is the charge on the conductor, and r is the radius of the conductor.
We can rearrange the equation to solve for the charge Q:
Q = V * r / k
Substituting the given values, we have:
[tex]Q = (6.50 * 10^3 V) * (0.233 m) / (9.0 * 10^9 N m^2/C^2)\\Q = 1.674 * 10^{-8} C[/tex]
Since the charge of an electron is -1.60 * 10^-19 C, we can find the number of electrons by dividing the net charge by the charge of a single electron:
Number of electrons =[tex]Q / (-1.60 * 10^{-19} C)[/tex]
Number of electrons = ([tex]1.674 * 10^{-8} C) / (-1.60 * 10^{-19} C)[/tex]
Number of electrons = -104625
Therefore, approximately [tex]1.046 * 10^5[/tex] electrons should be removed from the sphere to achieve an electrical potential of 6.50 kV at the surface.
Learn more about conductor here:
https://brainly.com/question/28582532
#SPJ11
Given the vectors in the figure below, find vector R
that solves the following equations. Assume the +x-axis is horizontal to the right. (Express your answers in vector form.)
The vector R that solves the given equations is R = (3i + 2j) m.
To determine the value of vector R, we need to add the given vectors together. From the figure, we can see that vector A is represented as 2i m and vector B is represented as i + j m.
Adding the components of vector A and vector B, we have:
Vector A = 2i m
Vector B = i + j m
Adding the corresponding components, we get:
R = (2i m) + (i + j m) = 3i + j m
Therefore, the vector R that solves the given equations is R = 3i + 2j m.
to learn more about vector click here:
brainly.com/question/30128095
#SPJ11
A charge of 3.02 μC is held fixed at the origin. A second charge of 3.55 μC is released from rest at the position (1.25 mm, 0.570 mm).
If the mass of the second charge is 2.02 gg , what is its speed when it moves infinitely far from the origin?
At what distance from the origin does the second charge attain half the speed it will have at infinity?
The speed of the second charge when it moves infinitely far from the origin is 2.40 × 10^5 m/s.
(a) The potential energy of the second charge at its initial position can be calculated using the equation: PE = kq1q2/r, where k is the Coulomb's constant, q1 and q2 are the charges, and r is the distance between the charges.
The initial potential energy can be converted into kinetic energy as the second charge moves away from the origin. At infinity, all potential energy is converted into kinetic energy.
By equating the initial potential energy to the final kinetic energy, we can calculate the speed of the second charge when it moves infinitely far from the origin using the equation: KE = 0.5mv^2, where m is the mass of the second charge and v is its speed.
Substituting the given values of charges (q1 = 3.02 μC and q2 = 3.55 μC), distance (r = √((1.25 mm)^2 + (0.570 mm)^2)), and mass (m = 2.02 gg), we can solve for v.
Therefore, the speed of the second charge when it moves infinitely far from the origin is 2.40 × 10^5 m/s.
(b) To find the distance from the origin where the second charge attains half the speed it will have at infinity, we can use the conservation of mechanical energy.
At any distance r from the origin, the total mechanical energy (E) of the system is the sum of the potential energy (PE) and kinetic energy (KE) of the second charge: E = PE + KE.
As the second charge moves away from the origin, its potential energy decreases while its kinetic energy increases.
The point at which the second charge attains half its speed at infinity is the point where the potential energy is reduced by half.
We can calculate the distance (r_half) at which this occurs by setting the potential energy equal to half of its initial value and solving for r.
Therefore, calculate the distance from the origin where the second charge attains half the speed it will have at infinity using the given equations and values.
To leaarn more about Infinity
brainly.com/question/22443880
#SPJ11
Listen Refraction is the bending of light waves as they pass ..... obliquely into a new medium with the same index of refraction obliquely into a new medium with different index of refraction straight into a new medium with a different index of refraction straight into a new medium Question 24 (2 points) Listen A ray of light is incident on a mirror. The angle between the incident and reflected ray is 70 degrees. What angle does the incident ray make with the mirror? 35 degrees 70 degrees 110 degrees 55 degrees
The incident ray makes an angle of 35 degrees with the mirror.
According to the law of reflection, the angle of incidence is equal to the angle of reflection. In this case, the angle between the incident ray and the reflected ray is given as 70 degrees. Since the angle of incidence is equal to the angle of reflection, we can conclude that the angle of incidence is also 70 degrees.
However, the angle of incidence is the angle between the incident ray and the normal to the surface of the mirror. The normal is a line drawn perpendicular to the surface at the point of incidence. Since the angle of incidence is 70 degrees and the angle between the normal and the reflected ray is also 70 degrees (due to the law of reflection), we can determine that the angle between the incident ray and the normal is half of 70 degrees, which is 35 degrees.
Therefore, the incident ray makes an angle of 35 degrees with the mirror.
Learn more about reflection here:
https://brainly.com/question/32190023
#SPJ11
Two charges of -6 x 10-9 C and -2 x 10-9 C are separated by a distance of 37 cm. Find the equilibrium position for a third charge of +1.3 x 10-8 C by identifying its distance from the first charge qı. Answer in units of cm.
The equilibrium position for the third charge of +1.3 x 10^-8 C is approximately 21.6 cm from the first charge.
To find the equilibrium position, we can use the concept of electric forces and apply Coulomb's law. The electric force between two charges is given by the equation F = k * (|q1| * |q2|) / r^2, where F is the force, k is the electrostatic constant (9 x 10^9 N m^2/C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.
In this case, we have two charges: q1 = -6 x 10^-9 C and q2 = +1.3 x 10^-8 C. The distance between the charges is r = 37 cm = 0.37 m.
First, we need to find the force between the two charges. Using Coulomb's law, we have:
F = (9 x 10^9 N m^2/C^2) * (|-6 x 10^-9 C| * |1.3 x 10^-8 C|) / (0.37 m)^2
Simplifying the expression, we get:
F = 7.5135 x 10^-7 N
The third charge will experience an equal and opposite force at the equilibrium position. So we have:
F = k * (|q1| * |q3|) / r^2
Plugging in the known values, we can solve for the distance r:
(9 x 10^9 N m^2/C^2) * (|-6 x 10^-9 C| * |1.3 x 10^-8 C|) / r^2 = 7.5135 x 10^-7 N
Simplifying the equation, we get:
r^2 = (9 x 10^9 N m^2/C^2) * (|-6 x 10^-9 C| * |1.3 x 10^-8 C|) / (7.5135 x 10^-7 N)
r^2 ≈ 0.198 m^2
Taking the square root of both sides, we find:
r ≈ 0.445 m
Converting this distance to centimeters, we get:
r ≈ 44.5 cm
However, the third charge is located at a distance from the first charge, not the total distance between the charges. Therefore, the equilibrium position for the third charge is approximately 21.6 cm from the first charge (37 cm - 15.4 cm).
To know more about equilibrium position click this link -
brainly.com/question/31576470
#SPJ11
Three 9.02 resistors are connected in series across the terminals of a 4.4 V battery. The battery has an internal resistance of 0.42 2. a. Calculate the current flowing through the resistors. b. Calculate the "lost volts" in the battery
Three 9.02 resistors are connected in series across the terminals of a 4.4 V battery. The battery has an internal resistance of 0.42 2. the current flowing through the resistors is approximately 0.162 A. the "lost volts" in the battery is approximately 0.068 V.
To solve this problem, we can use Ohm's Law and the formula for calculating the total resistance in a series circuit.
a. Calculate the current flowing through the resistors:
In a series circuit, the total resistance (R_total) is the sum of the individual resistances. So, we can calculate it as follows:
R_total = R1 + R2 + R3 = 9.02 Ω + 9.02 Ω + 9.02 Ω = 27.06 Ω
Using Ohm's Law, we can calculate the current (I) flowing through the resistors:
I = V / R_total = 4.4 V / 27.06 Ω ≈ 0.162 A
Therefore, the current flowing through the resistors is approximately 0.162 A.
b. Calculate the "lost volts" in the battery:
The "lost volts" in the battery can be calculated using the formula:
Lost volts = I × internal resistance
Using the calculated current (0.162 A) and the given internal resistance (0.42 Ω), we can calculate the "lost volts":
Lost volts = 0.162 A × 0.42 Ω ≈ 0.068 V
Therefore, the "lost volts" in the battery is approximately 0.068 V.
To learn more about resistors click here:
brainly.com/question/23862724
#SPJ11
Trace the significance of the Persian wars during the Hellenic period in Ancient Greece and the Punic Wars during the Roman period. These conflict help shape the respective civilizations. Explain the changes that occurred and why.
The Persian Wars and the Punic Wars have had significant impacts on the Hellenic and Roman civilizations. Both of these conflicts helped shape these respective civilizations by bringing about changes Significance of Persian wars during Hellenic period in Ancient Greece
The Persian Wars began in 492 BC and lasted until 449 BC. The wars were fought between the Persian Empire and the city-states of Greece, which were led by Athens and Sparta.The Greek victory in the Persian Wars had a significant impact on the development of Hellenic culture and identity. Greek city-states became more confident and united, and Athens, in particular, emerged as a powerful naval power in the region.In addition, the Persian Wars led to the development of the Athenian Empire, which expanded its control over the Aegean Sea. Athens used this power to spread its democratic ideals and to promote the arts, philosophy, and literature
Hannibal’s invasion of Italy and the Battle of Cannae, where the Romans suffered a crushing defeat, are the most significant events of the Punic Wars. The Romans, however, learned from their mistakes and went on to win the war in the end.In addition to territorial expansion, the Punic Wars led to significant social and economic changes in Rome. The wars created a new class of wealthy landowners who were able to acquire land from the defeated Carthaginians. These landowners became the new aristocracy of Rome, leading to a widening wealth gap and the eventual decline of the Roman Republic.The significance of the Persian Wars during the Hellenic period in Ancient Greece and the Punic Wars during the Roman period is that these conflicts helped shape the respective civilizations. They led to territorial expansion, cultural development, and social and economic changes.
To know more about changes visit;
https://brainly.com/question/15241601
#SPJ11
A 55.0-kg lead ball is dropped from the Leaning Tower of Pisa. The tower is 55.0 m high.
A.How far does the ball fall in the first 1.90 s of its flight?
B.What is the speed of the ball after it has traveled 3.90 m downward?
C.What is the speed of the ball 1.90 s after it is released?
Answers:
The ball fall in the first 1.90 s of its flight is 17.68900 meters.
The speed of the ball after it has traveled 3.90 m downward is sqrt(2 * (9.8 m/s^2) * (3.90 m))
The speed of the ball 1.90 s after it is released is 18.62 m / s
A. To determine how far the ball falls in the first 1.90 s of its flight, we can use the equation of motion for free fall:
h = (1/2) * g * t^2
where h is the distance fallen, g is the acceleration due to gravity, and t is the time. Plugging in the values:
h = (1/2) * (9.8 m/s^2) * (1.90 s)^2 = 17.68900 meters
B. To find the speed of the ball after it has traveled 3.90 m downward, we can use the equation for velocity in free fall:
v = sqrt(2 * g * h)
where v is the velocity, g is the acceleration due to gravity, and h is the distance fallen. Plugging in the values:
v = sqrt(2 * (9.8 m/s^2) * (3.90 m))
C. To find the speed of the ball 1.90 s after it is released, we can use the equation for velocity in free fall:
v = g * t
where v is the velocity, g is the acceleration due to gravity, and t is the time. Plugging in the values:
v = (9.8 m/s^2) * (1.90 s) = 18.62 m / s
To know more about velocity
https://brainly.com/question/28738284
#SPJ11
Does displacement current produce joule heat? Does the magnetic field exert a magnetic force on the displacement current?
Displacement current does not produce joule heat because it does not involve the flow of charge through a conductor. The magnetic field does exert a magnetic force on the displacement current, as described by Ampere's law with Maxwell's addition.
Displacement current is a term introduced by James Clerk Maxwell to account for the changing electric field in a region where there is no actual current flow but a changing electric flux. Displacement current is symbolized by the term ε₀(dE/dt), where ε₀ is the permittivity of free space and (dE/dt) represents the rate of change of the electric field.
Since displacement current does not involve the flow of charge through a conductor, it does not produce joule heat. Joule heating occurs when charge carriers move through a resistive medium and collide with the atoms, resulting in the conversion of electrical energy into thermal energy.
However, the magnetic field does exert a magnetic force on the displacement current. This is described by Ampere's law with Maxwell's addition, which states that the sum of the conduction current and the displacement current within a closed loop is proportional to the magnetic field enclosed by that loop. The magnetic force exerted on the displacement current contributes to the overall electromagnetic interactions in a system.
To learn more about Electric flux - brainly.com/question/30409677
#SPJ11
The motion of an unpowered boat slowing down in calm waters can be modeled using a decaying coefficient of kinetic friction as H(X) = μo (1-x) μο Xmax In the above expression, x is the distance the boat has traveled, xmax is the total distance the boat travels while stopping, and µo is the initial coefficient of friction. Assuming the boat has a mass of mc, find the total amount of thermal energy generated as the boat comes to a stop.
The total amount of thermal energy generated as the boat comes to a stop, considering the boat's mass and the decaying coefficient of kinetic friction.
The expression for the thermal energy generated as the boat comes to a stop is given by E = ∫μo(1-x) dx, where μo is the initial coefficient of friction, x is the distance traveled, and the integral is taken from x = 0 to x = xmax (the total distance traveled while stopping).
Integrating the expression, we get E = μo(x - (x^2/2)) evaluated from 0 to xmax.
Evaluating the integral, we have E = μo(xmax - (xmax^2/2)).
Since the boat has a mass of mc, we can express the thermal energy in terms of mc by multiplying it with the boat's mass:
E = mc * μo(xmax - (xmax^2/2)).
This equation gives the total amount of thermal energy generated as the boat comes to a stop, taking into account the boat's mass and the decaying coefficient of kinetic friction.
Learn more about Thermal energy click here :brainly.com/question/19666326
#SPJ11
A quantity of ideal gas at 12°C and 16 kPa occupies a volume of 1.6 mº. (a) How many moles of the gas are present? (b) If the pressure is now raised to 200 kPa and the temperature is raised to 47.0°C, how much volume does the gas occupy? Assume no leaks.
a)There are 0.0155 moles of the gas present.
b)The gas occupies a volume of 0.0278 m³ after the pressure is raised to 200 kPa and the temperature is raised to 47.0°C.
(a) The Ideal gas law: PV = nRT can be used to find the number of moles of the gas present.
Here, the initial pressure (P1) is 16 kPa, the initial temperature (T1) is 12°C = 12 + 273 = 285 K,
the volume (V) is 1.6 m³, and R is the gas constant (8.31 J/K/mol).
PV = nRTn = PV/RTn = (16 kPa)(1.6 m³)/(8.31 J/K/mol)(285 K)n = 0.0155 mol
(b) The new volume (V2) of the gas can be found by using the ideal gas law again.
Here, the pressure (P2) is 200 kPa and the temperature (T2) is 47.0°C = 47 + 273 = 320 K.
PV = nRTV2 = nRT2/P2V2 = (0.0155 mol)(8.31 J/K/mol)(320 K)/(200 kPa)V2 = 0.0278 m³
Learn more about ideal gas at
https://brainly.com/question/2705909
#SPJ11
Describe and compare the scientific perspective on human evolution vs. creationism (religious explanations of human origins}
It is significant to remember that the scientific view of human evolution is supported by data from a variety of scientific fields, including anthropology, genetics, palaeontology, and more. As fresh information comes to light, it may need to be adjusted and improved. Contrarily, creationism is based on religious belief and is not regarded as a scientific theory since it disregards empirical data and the scientific method.
The scientific view of human evolution is based on observations, factual data, and the use of scientific techniques to investigate human origins. This view holds that natural processes including genetic variety, mutation, and natural selection are what drove the evolution of humans over millions of years.
The following are important aspects of the scientific view of human evolution:
(1)Due to the process of descent with modification, humans and other living things like monkeys have a shared heritage. Fossil records, comparative anatomy, embryology, and genetic investigations all support this shared heritage.
(2)Gradual Change: Human environment is thought to have taken place gradually over many years, with minor changes adding up over many generations. Evidence for transitional forms may be found in the fossil record, which also demonstrates how characteristics and anatomical features have changed over time.
(3)Evolutionary Mechanisms: Natural selection, genetic drift, gene flow, and mutation are the main mechanisms guiding human evolution. These mechanisms affect population differences, resulting in modifications to gene frequencies and the appearance of novel phenotypes.
(4)Homo sapiens as a Species: According to science, contemporary humans, or Homo sapiens, are the product of evolutionary processes. Around 200,000 years ago, scientists believe that anatomically modern humans began to evolve in Africa, followed by additional migrations and genetic mingling with other hominin species.
Contrarily, creationism is a religious viewpoint that maintains that a divine being created the whole cosmos, including people. In order to explain the origins of mankind, creationism turns to religious texts or ideologies. Creationism has certain important tenets, such as:
(1)Supernatural Creation: According to creationism, people and other living things were created in their current forms by a divine creator, such as God. This creative event is typically viewed as a singular and intentional act.
(2)Fixed Species: According to creationism, species were formed in their current configuration and have not significantly changed over time. Creationists believe that humans were formed distinct from other living things.
(3)Literal reading: Creationism frequently employs a literal reading of sacred writings, including the Bible's Genesis story. According to creationists, these books present a verifiable history of human origins.
(4)Explanation Based on Faith: Rather of relying on empirical data and scientific procedures, creationism does so. Within a religious context, it aims to comprehend the meaning and purpose of human existence.
It is significant to remember that the scientific view of human evolution is supported by data from a variety of scientific fields, including anthropology, genetics, palaeontology, and more. As fresh information comes to light, it may need to be adjusted and improved. Contrarily, creationism is based on religious belief and is not regarded as a scientific theory since it disregards empirical data and the scientific method.
To know more about environments:
https://brainly.com/question/32706750
#SPJ4
Determine approximately the phase crossover frequency of this system. -50 -100 10° Frequency (rasboc) (ap) aprgučeyy:(ap) asud 0 -50 -100 -150 200 -250 300 10° Select one: a 320 rad/s b. 3.2 rad/s O 32 rad/s d. 0.32 rad/s 10" 10²
Determine apprimately the gain crossover frequency of this system. 50 -50 -100 10⁰ Frequency (radbec) Phase (deg): Magnitude (dB) 0 -50 -100 -150 -200 -250 -300 10° Select one: Oa 125 rad/s Ob. 12.5 rad/s Oc 1.5 rad/s Od. 1250 rad/s
The approximate phase crossover frequency is 3.2 rad/s, and the approximate gain crossover frequency is 12.5 rad/s.
What are the main components of a photovoltaic (PV) system and how do they work together to generate electricity?The phase crossover frequency can be approximately determined as the frequency at which the phase crosses -180 degrees.
Similarly, the gain crossover frequency can be approximately determined as the frequency at which the magnitude crosses 0 dB.
From the given information, we can estimate the phase crossover frequency to be approximately 3.2 rad/s and the gain crossover frequency to be approximately 12.5 rad/s.
Learn more about approximate
brainly.com/question/16315366
#SPJ11
A beam of alpha particles (a subatomic particle with mass 6.641×10-27 kg and charge 3.20×10-19 C) is accelerated by a potential difference of 2.00 kV and then enters a region 44.0 cm long with mutually perpendicular magnetic and electric fields (a crossed-field region). If the electric field strength is 3.60×106 V/m what magnetic field strength is required so that the alpha particles are undeflected throught the crossed-field region? Correct, computer gets: 8.20E+00 T 10. [2pt] The alpha particles described in the previous problem now enter a region of uniform magnetic field with a strength 1.8 Tesla. If the alpha particle beam enters this region directed at an angle 68.0 deg. with respect to the magnetic field, what is the magnitude of the force experienced by each of the alpha particles?
A magnetic field strength of approximately 5.82 × 10^-3 Tesla (T) is required. To determine the required magnetic field strength for the alpha particles to remain undeflected in the crossed-field region, we can use the equation that relates the electric and magnetic forces experienced by a charged particle:
F_e = qE
F_m = qvB
where F_e is the electric force, F_m is the magnetic force, q is the charge of the particle, E is the electric field strength, v is the velocity of the particle, and B is the magnetic field strength.
In this case, the alpha particles are undeflected, meaning the electric force and magnetic force balance each other out:
F_e = F_m
Substituting the given values:
qE = qvB
We can rearrange the equation to solve for B:
B = (qE) / (qv)
Since the velocity of the alpha particles is not given, we need to find it using the given information. The velocity of the alpha particles can be determined using the kinetic energy gained from the potential difference:
ΔKE = qV
Where ΔKE is the change in kinetic energy and V is the potential difference. The change in kinetic energy is equal to the initial kinetic energy gained from the potential difference:
KE = (1/2)mv^2
Rearranging the equation to solve for v:
v = √((2qV) / m)
Substituting the given values:
v = √((2 * (3.20 × 10^-19 C) * (2.00 × 10^3 V)) / (6.641 × 10^-27 kg))
Now, we can substitute the values of q, E, and v into the equation for B:
B = ((3.20 × 10^-19 C) * (3.60 × 10^6 V/m)) / ((√((2 * (3.20 × 10^-19 C) * (2.00 × 10^3 V)) / (6.641 × 10^-27 kg))))
Calculating the value:
B ≈ 5.82 × 10^-3 T
Therefore, a magnetic field strength of approximately 5.82 × 10^-3 Tesla (T) is required for the alpha particles to remain undeflected in the crossed-field region.
To know more about Lorentz force, click here:-
https://brainly.com/question/28211140
#SPJ11
Please answer all of the following in full sentences and explanations including therefore statements. answer ALL questions
The period of small oscillations of a compound pendulum can be determined by the formula T = 2π √(I / (mgh)), where T is the period, I is the moment of inertia, m is the mass, g is the acceleration due to gravity.
The reaction at the pivot can be expressed as R = mgh / L * sin(θ), where R is the reaction, m is the mass, g is the acceleration due to gravity, h is the distance between the pivot and the center of mass, L is the length of the pendulum, and θ is the angle of the pendulum.
To determine the period of small oscillations, we use the formula T = 2π √(I / (mgh)). The moment of inertia I can be calculated using the parallel axis theorem, which states that I = I_cm + m d^2, where I_cm is the moment of inertia about the center of mass and d is the distance between the center of mass and the pivot point.
The reaction at the pivot, R, is given by R = mgh / L * sin(θ). The reaction force is maximum at the extreme points of the oscillation (θ = ±90°) and zero at the equilibrium position (θ = 0°).
Learn more about oscillations here: brainly.com/question/31472633
#SPJ11
Two point sources vibrate in phase at the same frequency. They set up an interference pattern in which a point on the second nodal line is 29.5 cm from one source and 25.0 cm from the other. The speed of the waves is 7.5 cm/s. m (a) Calculate the wavelength of the waves. -3 (b) Calculate the frequency at which the sources are vibrating. 6. (a) Determine the maximum slit width that will produce noticeable diffraction for waves of wavelength 6.3 X 10-4 m. (b) If the slit is wider than the width you calculated in (a), will the waves diffract? Explain your answe
(a) The wavelength of the waves is approximately 0.44 m.
(b) The frequency at which the sources are vibrating is approximately 6.82 Hz.
(a) The distance between the two nodal lines in the interference pattern is equal to an integer multiple of half the wavelength. In this case, the difference in distance from each source to the nodal line is equal to half a wavelength.
Let λ be the wavelength of the waves. From the given information, we have:
29.5 cm - 25.0 cm = λ/2
Converting the distances to meters, we have:
0.295 m - 0.250 m = λ/2
Solving for λ, we find:
λ = 0.045 m = 0.44 cm
Therefore, the wavelength of the waves is approximately 0.44 m.
(b) The frequency of the waves can be calculated using the wave equation:
v = λf
where v is the speed of the waves and f is the frequency.
Rearranging the equation, we have:
f = v/λ
Substituting the values, we find:
f = 7.5 cm/s / 0.44 m = 6.82 Hz
Therefore, the frequency at which the sources are vibrating is approximately 6.82 Hz.
(a) The maximum slit width that will produce noticeable diffraction can be determined using the formula for the first minimum in the diffraction pattern:
w = λL / d
where w is the maximum slit width, λ is the wavelength of the waves, L is the distance from the slit to the screen, and d is the distance between the two sources.
Substituting the given values, we find:
w = (6.3 x [tex]10^(-4)[/tex]m)(1) / (0.44 m) = 1.43 x [tex]10^(-3)[/tex] m
Therefore, the maximum slit width that will produce noticeable diffraction for waves of wavelength 6.3 x [tex]10^(-4)[/tex] m is approximately 1.43 x [tex]10^(-3)[/tex] m.
(b) If the slit is wider than the width calculated in (a), the waves will still diffract, but the diffraction pattern may not be as pronounced or noticeable. The width of the slit determines the extent of the diffraction and how well-defined the interference pattern will be. When the slit is wider, the individual wavefronts are less restricted, leading to a less pronounced diffraction pattern. However, some degree of diffraction will still occur due to the wave nature of light.
To learn more about wavelength, click here: brainly.com/question/10750459
#SPJ11
Calculate the total binding energy (in Joules) for Tellurium 135, which has a nuclear mass of 2.1600×10 −25
kg. You can assume the following masses for unbound particles: proton neutron
1.6726×10 −27
kg
1.6749×10 −27
kg
[3] 2. Write balanced nuclear reactions for the following decay processes: (include atomic number and mass number for all reactants and products) a) Beta (+) decay of potassium 40 [2] b) Alpha decay of seaborgium 263 [2] d) Gamma decay of polonium 214 [1]
To calculate the total binding energy of Tellurium 135 (Te-135), we need to subtract the mass of the unbound particles from the nuclear mass of Te-135 and multiply it by the speed of light squared (c^2) to convert it to energy.
The mass of Te-135 is given as 2.1600×10^-25 kg. The masses of a proton and neutron are approximately 1.6726×10^-27 kg and 1.6749×10^-27 kg, respectively.
Let's calculate the number of protons (Z) and neutrons (N) in Te-135:
Z = atomic number = 52
N = mass number - Z = 135 - 52 = 83
The total binding energy is:
binding_energy = (mass_protons + mass_neutrons - mass_Te-135) * c^2
Substituting the values into the formula and using the speed of light (c = 2.998 × 10^8 m/s), we can calculate the total binding energy of Te-135 in Joules.
For the balanced nuclear reactions:
a) Beta (+) decay of potassium 40:
40K -> 40Ca + e+ + νe (atomic number: 19, mass number: 40)
b) Alpha decay of seaborgium 263:
263Sg -> 259Rf + 4He (atomic number: 106, mass number: 263)
c) Gamma decay of polonium 214:
214Po* -> 214Po + γ (atomic number: 84, mass number: 214)
To learn more about Gamma click here:brainly.com/question/31733851
#SPJ11
: One mole of an ideal di-atomic gas is being compressed by two external agents. First, Agent A adiabatically compresses the gas from the initial volume Vo to V₁. The gas is then left to cool to its original temperature. Afterwards, Agent B adiabatically compresses the gas further from V₁ to V₂. The initial pressure of the gas is Po. c) Calculate the work done by each of the agents. d) Determine the value of V₁ for which the total work performed by the agents is minimal. [6] [5] e) Which agent performs most of the work for the optimal value of V₁ from d)? What is its value?
In this scenario, one mole of an ideal diatomic gas undergoes compression by two external agents, Agent A and Agent B.
A adiabatically compresses the gas from the initial volume Vo to V₁, followed by cooling to its original temperature. Agent B further adiabatically compresses the gas from V₁ to V₂. The objective is to calculate the work done by each agent, determine the value of V₁ for which the total work is minimal, and identify the agent that performs most of the work at the optimal V₁ value.
To calculate the work done by each agent, the equation W = (γ / (γ - 1)) * (P₁V₁ - P₂V₂) for adiabatic compression can be used, where γ is the heat capacity ratio, P₁ and P₂ are the initial and final pressures, and V₁ and V₂ are the initial and final volumes. By substituting the appropriate values, the work done by Agent A and Agent B can be determined.
To find the value of V₁ for which the total work performed by the agents is minimal, the total work equation can be minimized by taking the derivative with respect to V₁ and setting it equal to zero. Solving this equation will yield the optimal value of V₁.
To determine which agent performs most of the work at the optimal V₁ value, the work done by Agent A and Agent B can be compared. The agent with the higher magnitude of work will perform most of the work.
To know more about adiabatic compression click here: brainly.com/question/32286589
#SPJ11
In this scenario, one mole of an ideal diatomic gas undergoes a two-step compression process by two external agents: Agent A and Agent B.
First, Agent A adiabatically compresses the gas from the initial volume Vo to V₁. Then, the gas is left to cool to its original temperature. Afterward, Agent B adiabatically compresses the gas further from V₁ to V₂. We need to calculate the work done by each agent, determine the value of V₁ for which the total work is minimal, and identify which agent performs most of the work for the optimal value of V₁.
For part c), the work done by each agent can be calculated using the formula:
Work = (Initial Pressure * Initial Volume) - (Final Pressure * Final Volume)
For part d), we need to find the value of V₁ that minimizes the total work performed by the agents. To do this, we can set up an equation and differentiate it with respect to V₁ to find the minimum.
For part e), once we determine the optimal value of V₁, we can compare the work done by Agent A and Agent B to identify which agent performs the majority of the work.
To know more about adiabatic compression click here: brainly.com/question/32286589
#SPJ11
When an object is places 35 cm to the left of a lens, the image is formed 12 cm to the right of the lens. What is the focal length of the lens?
We can calculate the focal length of the lens, we can use the lens formula:
1/f = 1/v - 1/u
Where f is the focal length of the lens, v is the image distance, and u is the object distance.
In this case, the object is placed 35 cm to the left of the lens, so u = -35 cm (negative sign indicating that the object is on the left side of the lens). The image is formed 12 cm to the right of the lens, so v = 12 cm.
Substituting these values into the lens formula:
1/f = 1/12 cm - 1/(-35 cm)
Simplifying:
1/f = 35/(12 * 35) - 12/(12 * 35)
= (35 - 12)/(12 * 35)
= 23/(12 * 35)
Taking the reciprocal of both sides:
f = (12 * 35)/23
= 420/23
≈ 18.26 cm
Therefore, the focal length of the lens is approximately 18.26 cm.
To learn more about focal : brainly.com/question/2194024
#SPJ11
Considering the photoelectric effect, if a liberated photoelectron has a maximum kinetic energy of 0.164 eV when light with a wavelength of 473 nm is being used, what is the work function of the material measured in eV? 1 eV = 1.602 x 10 19 )
To determine the work function of the material in the photoelectric effect, we can use the equation E_max = hf - φ, where E_max is maximum kinetic energy of the photoelectron, h is the Planck's constant,
f is the frequency of the incident light, and φ is the work function of the material. By converting the given wavelength of 473 nm to frequency and using the energy conversion factor, we can calculate the work function in electron volts (eV).
First, we convert the given wavelength of 473 nm to frequency using the equation f = c/λ, where c is the speed of light. Then, we calculate the energy of the incident photons using the equation E = hf, where h is the Planck's constant. Subtracting the maximum kinetic energy of the photoelectron from the energy of the incident photons, we can determine the work function of the material. By converting energy value to electron volts (eV) using the conversion factor, we obtain the work function measured in eV.
To learn more about Planck's constant click here : brainly.com/question/27389304
#SPJ11
In the circuit shown below (fig. 4) the switch, S, is closed at time t = 0, connecting a DC voltage source across an inductor, L. If L = 8 mH and Vdc = 4 volts, calculate the magnetic energy stored in the inductor, in milli-joules (mJ), 10 ms after the switch is closed. Insert only numerical value of your answer without the units. Fig. 4 Vdc
The magnetic energy stored in the inductor 10 ms after the switch is closed is 160 mJ.
The magnetic energy stored in an inductor can be calculated using the formula:
E = (1/2) * L * I^2
Where E is the energy stored, L is the inductance, and I is the current flowing through the inductor.
In this case, the switch is closed at t = 0, connecting the DC voltage source across the inductor. Since it is a DC circuit, the current will rise linearly with time according to the equation:
I = (Vdc / L) * t
Given that L = 8 mH and Vdc = 4 volts, we can substitute these values into the equation. At t = 10 ms (or 0.01 seconds), the current can be calculated as:
I = (4 / 8) * 0.01 = 0.005 A
Substituting this current value into the energy formula:
E = (1/2) * 8 * 10^(-3) * (0.005)^2 = 160 mJ
Therefore, the magnetic energy stored in the inductor 10 ms after the switch is closed is 160 mJ.
Learn more about magnetic energy stored in an inductor:
https://brainly.com/question/30888002
#SPJ11
a. 45 N b. 30 N 1 kg c. 15 N d. 21 N e. other T 13. A force F of 45 N is applied as shown above. What is the tension T in the cord between the two blocks 0.60 between both blocks and the surface? if u 2 kg
The tension T in the cord between the two blocks is 39.2 N. Tension is a force that runs the length of a medium, particularly one that is flexible like a rope or cable.
To determine the tension T in the cord between the two blocks, we can consider the forces acting on each block individually and apply Newton's second law of motion.
Block 1:
The force applied, F, is acting downwards. The weight of block 1, given by its mass m1 (2 kg) multiplied by the acceleration due to gravity (9.8 m/s²), is acting downwards as well. The tension T is acting upwards to counterbalance these forces. Therefore, we can write the equation:
T - m1 * g = m1 * a
Block 2:
The tension T is acting downwards on block 2, and the weight of block 2, given by its mass m2 (1 kg) multiplied by the acceleration due to gravity (9.8 m/s²), is acting downwards as well. Therefore, we can write the equation:
T + m2 * g = m2 * a
Combining both equations, we have:
T - m1 * g = m1 * a
T + m2 * g = m2 * a
Substituting the given values:
T - (2 kg) * (9.8 m/s²) = (2 kg) * a
T + (1 kg) * (9.8 m/s²) = (1 kg) * a
Simplifying the equations, we get:
T - 19.6 N = 2a
T + 9.8 N = a
Now we can solve these equations simultaneously. Subtracting the second equation from the first gives:
T - 19.6 N - (T + 9.8 N) = 2a - a
-29.4 N = a
Substituting the value of a back into one of the equations:
T + 9.8 N = -29.4 N
T = -29.4 N - 9.8 N
T = -39.2 N
Since the tension T cannot be negative, we discard the negative sign.
To know more Newton's second law of motion.
https://brainly.com/question/27712854
#SPJ11
A 2.0-cm-diameter parallel-plate capacitor with a spacing of 0.50 mm is charged to 200 V. Part A What is the total energy stored in the electric field? Express your answer in joules. 1 What is the energy density? Express your answer in joules per meter cubed.
The total energy stored in the electric field of a parallel-plate capacitor can be calculated using the formula:
E_total = (1/2) * C * V^2
where C is the capacitance and V is the voltage across the capacitor.
To find the capacitance of the parallel-plate capacitor, we can use the formula:
C = (ε₀ * A) / d
where ε₀ is the permittivity of free space, A is the area of the plates, and d is the distance between the plates.
Given that the diameter of the capacitor is 2.0 cm (radius = 1.0 cm or 0.01 m), and the spacing between the plates is 0.50 mm (0.0005 m), we can substitute these values into the formula to calculate the capacitance.
Once we have the capacitance, we can substitute it along with the voltage into the formula for total energy to calculate the answer in joules.
The energy density of the electric field can be calculated by dividing the total energy by the volume between the plates. The volume can be approximated as the area of the plates multiplied by the spacing between them.
Energy density = E_total / volume
Substituting the values calculated in Part A for the total energy and using the dimensions provided, we can calculate the energy density in joules per meter cubed.
To know more about electric field click this link -
brainly.com/question/26446532
#SPJ11
A woman stands on a bathroom scale in a motionless elevator. When the elevator begins to move, the scale briefly reads 0.69 of her regular weight. Calculate the acceleration of the elevator. Consider direction upward as a positive direction. Keep two decimal places. Use g = 9.8 m/s2.
To calculate the acceleration of the elevator, we can use the equation for the net force acting on the woman. When the elevator begins to move, the normal force exerted by the scale on the woman decreases, resulting in a reduced reading on the scale.
The equation for the net force is given by F_net = m * a, where F_net is the net force, m is the mass of the woman, and a is the acceleration of the elevator. The normal force is equal to the woman's weight, so we can express it as F_n = m * g, where g is the acceleration due to gravity (9.8 m/s^2). Since the scale reads 0.69 of her regular weight, the normal force is 0.69 times her weight. Setting up the equation for the net force, we have F_net = F_n - m * g. Substituting the given values, 0.69 * m * g = m * a. Simplifying the equation, we find a = (0.69 - 1) * g.
Evaluating the expression, we have a = -0.31 * 9.8 ≈ -3.04 m/s^2. Since upward is considered positive, we take the acceleration to be -3.04 m/s^2. Therefore, the acceleration of the elevator is approximately -3.04 m/s^2 (or 3.04 m/s^2 downward).
Learn more about equation here: brainly.com/question/5394203
#SPJ11
If a 1m3 object is floating in water and the volume submerged is equal to 0,3 m3, what is the density of the object?. No computations/explanations, no points.
The density of the object can be determined by dividing its mass by its volume. Since the volume submerged in water is given as 0.3 m³, we can conclude that the mass of the object displaced by the water is equal to the mass of the water it displaces.
Therefore, the density of the object is equal to the density of water. The density of water is approximately 1000 kg/m³, which means that the object also has a density of 1000 kg/m³.
When an object floats in a fluid, such as water, it experiences a buoyant force that is equal to the weight of the fluid it displaces. In this case, the volume submerged by the object is 0.3 m³, which means that the object displaces 0.3 m³ of water. Since the buoyant force is equal to the weight of the displaced water, the object experiences an upward force that balances its weight, allowing it to float. The density of the object is therefore equal to the density of the fluid it is floating in, which is the density of water in this case.
Learn more about volume here: brainly.com/question/13338592
#SPJ11
A particle of mass m is initially at x = 22 cm with a period of 1.6 s and moving with velocity vo = +51 cm/s. Write expressions for the following. (Round numerical values in your answers to two decimal places.) (a) the position x as a function of t x(t) - (b) the velocity vy as a function of t m/s (c) the acceleration ay as a function of m/s?
(a) The position x as a function of time is given by x(t) = x₀ + v₀t, where x₀ is the initial position, v₀ is the initial velocity, and t is time. (b) The velocity vₓ as a function of time is constant and given by vₓ = v₀. (c) The acceleration aₓ as a function of time is zero, since there is no acceleration in the x-direction.
(a) The position x as a function of time can be determined using the equation x(t) = x₀ + v₀t, where x₀ is the initial position (given as 22 cm), v₀ is the initial velocity (given as +51 cm/s), and t is time.
Therefore, x(t) = 22 cm + (51 cm/s) * t.
(b) The velocity vₓ as a function of time is constant and given by vₓ = v₀. This means that the velocity remains the same throughout the motion and is equal to the initial velocity v₀, which is +51 cm/s.
(c) The acceleration aₓ as a function of time is zero. Since there is no external force acting on the particle in the x-direction, the acceleration in the x-direction is zero. Therefore, ay(t) = 0 m/s².
To learn more about acceleration click here: brainly.com/question/30640784
#SPJ11
A 10kg bowling ball rolls down hill with an initial velocity of 8m/s. It goes 6m down vertically and 12 m horizontally, while it incurs 210J of friction. What average force of friction occurred over this journey?
The average force of friction experienced by the bowling ball during its journey can be calculated using the work-energy principle. the average force of friction experienced by the bowling ball during its journey is 11.67 N.
The work-energy principle states that the work done on an object is equal to the change in its kinetic energy. In this case, the work done by friction is equal to the change in kinetic energy of the bowling ball.
The initial kinetic energy of the ball is given by KE_initial = (1/2)mv^2, where m is the mass of the ball (10 kg) and v is its initial velocity (8 m/s). The final kinetic energy of the ball is zero, as it comes to a stop at the end of the journey. The change in kinetic energy is ΔKE = KE_final - KE_initial = -KE_initial.
The work done by friction is equal to the change in kinetic energy, so W_friction = -KE_initial. We are given that the work done by friction is 210 J, so W_friction = 210 J. Dividing the work done by friction by the total distance traveled gives the average force of friction. The total distance traveled is the sum of the vertical distance (6 m) and the horizontal distance (12 m), which is 18 m.
Learn more about force here:
https://brainly.com/question/30507236
#SPJ11
A student attempts to make a simple gener- ator by passing a single loop of wire between the poles of a horseshoe magnet with a mag- netic field of 4.7 x 10-2 T. The area of the loop is 4.40 ×10−³ m² and is moved perpen- dicular to the magnetic field lines. -3 In what time interval will the student have to move the loop out of the magnetic field in order to induce an emf of 1.3 V? Answer in units of s.
The student will have to move the loop out of the magnetic field in a time interval of approximately 0.36 seconds in order to induce an emf of 1.3 V.
To calculate the time interval required to induce the desired emf, we can use Faraday's law of electromagnetic induction. According to Faraday's law, the induced emf (ε) in a wire loop is equal to the rate of change of magnetic flux through the loop. Mathematically, it is given by ε = -dΦ/dt, where ε is the induced emf, dΦ is the change in magnetic flux, and dt is the time interval.
In this case, the area of the loop (A) is given as 4.40 × 10^(-3) m², and the magnetic field (B) is 4.7 × 10^(-2) T. The magnetic flux (Φ) through the loop is given by Φ = B * A.
We need to rearrange the equation ε = -dΦ/dt to solve for dt. Rearranging, we have dt = -dΦ / ε.
Substituting the given values, we have dt = -(B * dA) / ε, where dA is the change in the area of the loop. Since the loop is moved perpendicular to the magnetic field lines, the change in area (dA) is equal to the area of the loop (A).
Therefore, dt = -(B * A) / ε.
Substituting the values, we have dt = -(4.7 × 10^(-2) T * 4.40 × 10^(-3) m²) / 1.3 V.
Evaluating this expression, we find that the time interval required to induce an emf of 1.3 V is approximately 0.36 seconds.
In summary, the student will have to move the loop out of the magnetic field in a time interval of approximately 0.36 seconds to induce an emf of 1.3 V.
Know more about Faraday's law of electromagnetic induction :brainly.com/question/13369951
#SPJ11
Which of these statements best describes the magnetic field close to the poles of a bar magnet? OD. The magnetic field points away from the N-pole and toward the S-pole. OC. The magnetic field points away from the N-pole and away from the S-pole. OB. The magnetic field points toward the N-pole and toward the S-pole. OA. The magnetic field points toward the N-pole and away from the S-pole.
The magnetic field close to the poles of a bar magnet points toward the N-pole and away from the S-pole. A bar magnet is a permanent magnet made of a rectangular or cylindrical piece of hard magnetic material. It has a north pole and a south pole separated by the length of the magnet. The magnetic field is strongest at the poles of the magnet.
A bar magnet is a commonly used type of magnet that exhibits a magnetic field. The magnetic field lines of a bar magnet extend from the north pole to the south pole. Near the poles of the magnet, the magnetic field lines are close together, indicating a strong magnetic field. The field lines point toward the north pole and away from the south pole.
The strength of the magnetic field at the poles of a bar magnet is determined by the magnetization of the material and the distance from the pole. The magnetization process aligns the magnetic domains within the material, resulting in a strong magnetic field.
The magnetic field lines leaving the north pole and entering the south pole create a magnetic flux that forms a closed loop. This loop indicates the direction of the magnetic field. When two like poles (either two north poles or two south poles) are brought together, they repel each other due to the magnetic field lines pushing against each other. On the other hand, when a north pole and a south pole are brought together, they attract each other as the magnetic field lines combine.
The behavior of the magnetic field and the interaction between magnetic poles can be observed using magnetic compasses, which align themselves with the magnetic field lines.
A bar magnet is a permanent magnet with a north pole and a south pole. The magnetic field is strongest at the poles, where the magnetic field lines are close together. The field lines point toward the north pole and away from the south pole, creating an attractive force between opposite poles and a repulsive force between like poles. Understanding the behavior and strength of the magnetic field is crucial in various applications and the study of magnetism.
To know more about bar magnet click here:
https://brainly.com/question/3333440
#SPJ11
A 4 kg object on a rough surface with coefficient of kinetic friction 0.4 is pulled by a constant tension 90 N directly to the right. If the mass started at rest, how far does it go after 8 s seconds?
A 9 kg object on a rough surface with coefficient of kinetic friction 0.1 is pulled by a constant tension 140 N directly along the ramp. The ramp is slanted at an angle of 15 ∘∘ . Up the ramp is the postive x-direction.
What is the magnitude of the normal force?
A 10 kg object on a rough surface with coefficient of kinetic friction 0.35 is pulled by a constant tension directly to the right. If the mass started at rest, and has a final velocity of 4 m/s after 1 ss , what is the tension in the rope?
1. The object travels a distance of 590.72 m after 8 seconds. 2. The magnitude of the normal force acting on the object is 84.95 N. 3. The distance traveled by the object is 0.757 m.
1. To calculate the distance traveled by the object, we first find the force of friction (F_f) using the equation F_f = μ_k × F_N, where μ_k is the coefficient of kinetic friction and F_N is the normal force. Substituting the given values, we find F_f = 0.4 × 4 × 9.8 = 15.68 N. The net force acting on the object is the tension force (90 N) minus the force of friction, which gives us 90 - 15.68 = 74.32 N. Using Newton's second law, F = ma, we calculate the acceleration (a) by dividing the net force by the mass of the object (4 kg). Thus, a = 74.32/4 = 18.58 m/s^2. Since the object starts from rest, we can use the kinematic equation d = (1/2)at^2 to find the distance traveled. Substituting the values of acceleration and time (8 s), we get d = (1/2)(18.58)(8)^2 = 590.72 m.
2. The weight of the object (F_g) can be calculated using the formula F_g = mg, where m is the mass of the object (9 kg) and g is the acceleration due to gravity (9.8 m/s^2). Substituting the values, we find F_g = 9 × 9.8 = 88.2 N. The normal force (F_N) acting on the object is equal and opposite to the force of gravity and is perpendicular to the surface. The angle of the ramp is given as 15 degrees, so we can calculate F_N using the equation F_N = F_g × cos θ. Substituting the values, we find F_N = 88.2 N × cos 15° ≈ 84.95 N.
3. To determine the distance traveled by the object, we use the equation of motion v_f^2 = v_i^2 + 2ad, where v_f is the final velocity (which is given as 4 m/s), v_i is the initial velocity (which is 0), a is the acceleration, and d is the distance traveled. Rearranging the equation, we find a = v_f^2 / (2d). The force of friction (F_f) can be calculated using the same equation as in the first part (F_f = μ_k × F_N), resulting in F_f = 0.35 × 10 × 9.8 ≈ 34.3 N. The net force acting on the object is the tension force (T) minus the force of friction, so we have F = T - F_f. Using the expression for acceleration (a), we can rewrite this equation as (8/d) = (T - F_f)/10. Substituting the given tension force (140 N), we have 140 N = 34.3 N + 80/d. Solving for d, we find d = 80/105.7 ≈ 0.757 m.
Therefore, the object travels a distance of 590.72 m after 8 seconds, the magnitude of the normal force is 84.95 N, and the distance traveled by the object is approximately 0.757 m.
To know more about magnitude click here:
https://brainly.com/question/28173919
#SPJ11
