For 17-20, Find the value of each variable.

45 kilograms of meat is required to feed 2 pet dragons each day.

Amara needs 45 kilograms of meat to feed 2 pet dragons each day.

Unitary method is a mathematical way of deriving a single unit then obtaining the required units by multiplying it with the single unit.

According to the given question Amara needs 90 kilograms of meat to feed her 4 pet dragons each day.

Also given that each pet dragon eats the same amount of meat.

∴ 1 pet dragon eat 90/4 kilograms of meat which is

= 22.5 kilograms of meat.

So, Amara need (22.5×2) = 45 kilograms of meat to feet 2 pet dragons.

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The mass of the regular hippo at birth to that of the pygmy hippo is 49/11

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

An independent variable is a variable that does not depend on any other variable for its value while a dependent variable is a variable that depends on other variable.

The pygmy hippo had a mass of 5 1/2 kg at birth = 5.5 kg.

The regular hippo had a mass of 24 1/2 kg at birth = 24.5 kg

Hence:

Ratio of regular hippo to pygmy hippo = 24.5 / 5.5 = 49/11

The mass of the regular hippo at birth to that of the pygmy hippo is 49/11

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Answer:

49/11 or 4 5/11

Step-by-step explanation:

just did it on khan Academy.

Answer:

(0, - 3 )

Step-by-step explanation:

- 5x - 3y - 9 = 0 → (1)

4x - 18y - 54 = 0 → (2)

multiplying (1) by - 6 and adding to (2) will eliminate y

30x + 18y + 54 = 0 → (3)

add (2) and (3) term by term to eliminate y

34x + 0 + 0 = 0

34x = 0 ⇒ x = 0

substitute x = 0 into either of the 2 equations and solve for y

substituting into (2)

4(0) - 18y - 54 = 0

- 18y - 54 = 0 ( add 54 to both sides )

- 18y = 54 ( divide both sides by - 18 )

y = - 3

solution is (0, - 3 )

Answer:

(0, -3)

Step-by-step explanation:

This system of equations consists of two equations. There are 3 main ways to solve a system of equations:

First, start by having the variables on one side.

[tex]-5x-3y-9=0 \Rightarrow \text{Add 9 to both sides} \Rightarrow -5x-3y=9\\4x-18y-54=0 \Rightarrow \text{Add 54 to both sides} \Rightarrow 4x-18y=54 \Rightarrow \text{Simplify} \Rightarrow 2x-9y=27[/tex]

This method is the easiest to use in this situation.

In this method, we increase equations by a certain factor in order to eliminate one variable.

We can see that 3y in the first equation can be multiplied by 6 in order to obtain the 18y in the second equation. Therefore, we can multiply the whole first equation by 6:

[tex]-30x-18y=54\\4x-18y=54[/tex]

Now, subtract the two equations to eliminate y.

[tex]-34x=0\\x=0[/tex]

Plug in 0 to x in either of the equations to solve for y:

[tex]-5(0)-3y=9\\0-3y=9\\-3y=9\\ \text{Divide both sides by -3}\\y=-3[/tex]

OR

[tex]4(0)-18y=54\\0-18y=54\\-18y=54\\\text{Divide both sides by -18}\\y=-3[/tex]

Therefore:

(x, y) = (0, -3)

Answer:

(A∩B)' = A'∪B'

Step-by-step explanation:

U is the universal set

A and B are two subsets of U

let A' be the complement subset of A

and  B' be the complement subset of B

U = {-10,-9,…,-1,0,1,…,9,10}

A = {-1,0,1}

B = {1,2,…,9,10}

Then

A∩B = {1}

Then

the complement of A∩B :

(A∩B)' = {-10,-9,…,-1,0,2,…,9,10}

(notice the absence of 1)

On the other hand,

A' = {-10,…,-2}∪{2,…,10}

B' = {-10,…,0}

Then

A'∪B' = {-10,-9,…,-1,0}∪{2,…,10}

         =  {-10,-9,…,-1,0,2,…,9,10}

Conclusion:

(A∩B)' = A'∪B'

I've done it on the attached pages.

I hope this helps you...

Considering the given inequality, the solution is given by graph D.

The inequality is given by:

-36 ≤ 2x + 4(x-3)

Applying the operations:

-36 ≤ 2x + 4x - 12

-24 ≤ 6x

6x >= -24

x >= -24/6

x >= -4.

Hence option D is correct.

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Answer:

figure A = 3 units

figure B = 9 x 3 = 27 units

scale factor =

[tex] \frac{3}{27 } = \frac{1}{9} [/tex]

so the scale factor = 9

Answer:

Rajani needs 7.8 (39/5) cups of yogurt to make 13 smoothies.

Step-by-step explanation:

3/5 = 0.6

The amount of cups of yogurt needed to make 13 smoothies = 13 x 0.6

This equals to 7.8 cups or 39/5 cups of yogurt to make 13 smoothies.

Hope this helps!

Answer:

16

Step-by-step explanation:

6/3 = 2 postcards per day

2x8 = 16 postcards

Based on the stock price and its growth rate, the function that models the situation is 48 (1 + 8%) ^ n. The price of the stock 6 years from now is $76.17.

The value of a stock in future can be calculated using several types of formulas that take into account the various characteristics of the stock.

For this stock, the value of the stock at any given year is:

= Current price of stock x ( 1 + growth rate) ^ number of years from now

Assuming the number of years is n, the function becomes:

= 48 x ( 1 + 8%) ^n

In 6 years, the price will be:

= 48 x ( 1 + 8%) ⁶

= $76.17

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The simplified product of (√6x² +4√8x³)(√9x-x√5x^5) is 3x√6x  + 24x^2√2 - x^4√30x - 8x^5√10

The product expression is given as:

(√6x² +4√8x³)(√9x-x√5x^5)

Evaluate the exponents

(√6x² +4√8x³)(√9x-x√5x^5) = (x√6 +8x√2x)(3√x - x^3√5x)

Expand the brackets

(√6x² +4√8x³)(√9x-x√5x^5) = x√6 * 3√x + 8x√2x * 3√x - x√6 * x^3√5x - 8x√2x * x^3√5x

This gives

(√6x² +4√8x³)(√9x-x√5x^5) = 3x√6x  + 24x^2√2 - x^4√30x - 8x^5√10

Hence, the simplified product of (√6x² +4√8x³)(√9x-x√5x^5) is 3x√6x  + 24x^2√2 - x^4√30x - 8x^5√10

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75  is  the least positive integers which , when subtracted 7300 would make a result a perfect square

So normally the least positive integer of all the numbers is the number 1 but when you talk about least positive integer, often times you are talking about the special function called the ceiling function

The smallest of the numbers in the set {1, 2, 3, …} is 1.

So, the number 1 is the smallest positive integer.

7300

If we Take Square root of 7300 we have to subtract 75 from 7300 to get a perfect square.

7300-75=7225

(85)^2=7225

75 to be subtracted

√7300 ≥ 85

Perfect Square = 85² =  7225     or (7300-7225 = 75)

75  is  the least positive integers which , when subtracted 7300 would make a result a perfect square

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D. 16

Cross multiply, to cancel the denominator; so if you multiple by 6 on one side, to cancel the division of 6 - you must also multiply the other side by 6 & vice versa.

You get:

8(x-4) = 6x

Expand bracket to get:

8x - 32

Now solve for x :

8x - 32 = 6x

- 8x

- 32. = - 2x

÷ - 2

16 = x

Or

8x - 32 = 6x

+ 32

8x. = 6x + 32

- 6x

2x. = 32

÷2

x =16

Check:

16 - 4 = 12, then ÷ 6 is 2

16/8 = 2

Hope this helps!

Answer: D

Step-by-step explanation:

The first term is 3 and the common difference is 2.

Substituting into the explicit formula for an arithmetic sequence gives D as the correct answer.

The first five terms of the given arithmetic sequence are:

1/5, 2/5, 3/5, 4/5, 1 (Fourth option)

The arithmetic sequence is given as follows,

f(n) = f(n-1) + 1/5 ............ (1)

Now, for finding the first five term of this arithmetic sequence, we will substitute n as 1, 2, 3, 4, and 5 one by one. Using the above formula for the arithmetic sequence, we can deduce the first five terms.

It is already given that f(1) = 1/5 ......... (2)

f(1) is the first term of the sequence.

Now, putting n=2 in equation (1), we get,

f(2) = f(2-1) + 1/5

f(2) = f(1) + 1/5

Substitute f(1) = 1/5 from equation (2)

⇒ f(2) = 1/5 + 1/5

f(2) = 2/5

To find the third term of the arithmetic sequence, put n = 3 in equation (1)

f(3) = f(3-1) + 1/5

f(3) = f(2) + 1/5

⇒ f(3) = 2/5 + 1/5

f(3) = 3/5

Similarly, we can find the fourth and fifth terms of the arithmetic sequence by substituting n = 4 and n = 5 respectively.

∴ f(4) = f(3) + 1/5

⇒ f(4) = 3/5 + 1/5

f(4) = 4/5

Likewise, f(5) = f(4) + 1/5

⇒f(5) = 4/5 + 1/5

f(5) = 1

Thus, using the recursive formula, the first five terms of the arithmetic sequence come out to be:

1/5, 2/5, 3/5, 4/5, 1

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Answer:

[tex]tan(2\theta) = -\frac{4}{3}\\[/tex]

Step-by-step explanation:

So cos is defined as: [tex]cos(\theta) = \frac{adjacent}{hypotenuse}[/tex], meaning we can tell that the adjacent side is 1, and the hypotenuse is 5, from the fraction you gave.

Using this we can solve for the opposite side.

[tex]1^2 + b^2 = \sqrt{5}^2\\1+b^2 = 5\\b^2=4\\b=2[/tex]

Now it's important to note, that b can be a negative number, so we have to use the information that sin(x) > 0, to determine the length of this side.

The sin is defined as: [tex]sin(\theta) = \frac{opposite}{hypotenuse}[/tex], and since we we're solving for the opposite side, this means that the value +\- 2, is in the top, and since the hypotenuse is positive, this means that the opposite side is also positive.

This also tells us one more thing, since both cos(x) and sin(x) are positive, we are dealing with a angle in the first quadrant.

So we can now define sin(x), using the opposite (2) and the hypotenuse (sqrt(5))

[tex]sin(\theta) = \frac{2}{\sqrt{5}}[/tex]

And we can rationalize the denominator for both the cosine and sine, by multiplying by the square root in the denominator so that

[tex]sin(\theta) = \frac{2\sqrt{5}}{5}\\\\cos(\theta) = \frac{\sqrt{5}}{5}[/tex]

Now we can define the value of tan(2 theta) using the double angle-identities such that:

[tex]tan(2\theta) = \frac{2\ tan(\theta)}{1-tan^2{\theta}}[/tex]

And we can also define tan(theta) using the definition that:

[tex]tan(\theta) = \frac{sin(\theta)}{cos(\theta)}[/tex]

So plugging in the values sin(theta) and cos(theta) we get the following:

[tex]tan(\theta) = \frac{\frac{2\sqrt{5}}{5}}{\frac{\sqrt{5}}{5}}\\\\tan(\theta) = \frac{2\sqrt{5}}{5} * \frac{5}{\sqrt{5}}\\\\tan(\theta) = 2[/tex]

Btw in the last step, I just canceled out the 5 and sqrt(5) since they were both in the denominator and numerator

So now let's plug this value, 2 as tan(theta) into the equation

[tex]tan(2\theta) = \frac{2\ *2}{1-2^2}\\\\tan(2\theta) = \frac{4}{-3}\\tan(2\theta) = -\frac{4}{3}\\[/tex]

The given equation x-1/x-2+x+3/x-4=2/(x-2).(4-x) is correct. the answer is proved.

According to the statement

we have given that the equation and we have to prove that the given answer is a correct answer for those equivalent equation.

So, The given expression are:

[tex]\frac{x-1}{x-2} +\frac{x+3}{x-4} = \frac{2}{(x-2).(4-x)}[/tex]

And we have to prove the answer.

So, For this

[tex]\frac{x-1}{x-2} +\frac{x+3}{x-4}[/tex]

[tex]\frac{({x-1}) ({x-4}) +({x+3})({x-2})} {(x-2) (x-4)}[/tex]

Then the equation become

[tex]\frac{x^{2} -4x -x +4 + x^{2} -2x + 3x -6 }{(x-2) (x-4)}[/tex]

Now solve it then

[tex]2x^{2} - 4x -2 / (x-2) (x-4)[/tex]

Now take 2 common from answer then equation become

[tex]\frac{x-1}{x-2} +\frac{x+3}{x-4} = \frac{2}{(x-2).(4-x)}[/tex]

Hence proved.

So, The given equation x-1/x-2+x+3/x-4=2/(x-2).(4-x) is correct. the answer is proved.

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Answer:

The answer is (3,11) or x = 3, y = 11

Step-by-step explanation:

:)

Answer:

(3, 11 )

Step-by-step explanation:

y = x + 8 → (1)

y = 3x + 2 → (2)

substitute y = 3x + 2 into (1)

3x + 2 = x + 8 ( subtract x from both sides )

2x + 2 = 8 ( subtract 2 from both sides )

2x = 6 ( divide both sides by 2 )

x = 3

substitute x = 3 into either of the 2 equations and solve for y

substituting into (1)

y = 3 + 8 = 11

solution is (3, 11 )

Answer:

Step-by-step explanation:

(14 - 7x)/7 =

[7(2-x)]/7 =

2-x

Answer:

11/15 km

Step-by-step explanation:

Simply sum the areas:

2/5 + 1/3 = (6 + 5)/15 = 11/15

The equation that could represent a linear combination of the system 2/3x + 5/2y = 15 and 4x + 15y = 12 is 0 = 26

Linear equations are equations that have constant average rates of change, slope or gradient

A system of linear equations is a collection of at least two linear equations.

In this case, the system of equations is given as

2/3x + 5/2y = 15

4x + 15y = 12

Multiply the first equation by 6, to eliminate the fractions.

6 * (2/3x + 5/2y = 15)

This gives

4x + 15y = 90

Subtract the equation 4x + 15y = 90 from 4x + 15y = 12

4x - 4x + 15y - 15y = 12 - 90

Evaluate the difference

0 + 0 = -78

Evaluate the sum

0 = -78

The above equation is the same equation as option (b) 0 = 26

This is so because they both represent that the system of equations have no solution

Hence, the equation that could represent a linear combination of the system is 0 = 26

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Answer:

y=-\frac{2}{5}x+\frac{19}{5}y=−52x+519

Further explanation:

We have to find the equation of the line first to graph the line.

The general form of slope-intercept form of equation of line is:

y=mx+by=mx+b

Given

m=-\frac{2}{5}m=−52

Putting the value of slope in the equation

y=-\frac{2}{5}x+by=−52x+b

To find the value of b, putting the point (-3,5) in equation

\begin{gathered}5=-\frac{2}{5}(-3)+b\\5=\frac{6}{5}+b\\5-\frac{6}{5}+b\\b=\frac{25-6}{5}\\b=\frac{19}{5}\end{gathered}5=−52(−3)+b5=56+b5−56+bb=525−6b=519

Putting the values of b and m

y=-\frac{2}{5}x+\frac{19}{5}y=−52x+519

Answer:  108 square feet

===============================================

Work Shown:

L = 4 = length

W = 3 = width

H = 6 = height

SA = surface area of the box

SA = 2*(LW + LH + WH)

SA = 2*(4*3 + 4*6 + 3*6)

SA = 108

The area of the adjoining trapezium is 276 [tex]cm^{2}[/tex].

Given the sides of trapezium be 16 cm, 15 cm, 30 cm, 13 cm.

We are required to find the area of adjoining trapezium.

Draw two perpendiculars on AD and the points will be E and F.

From triangles ABE and CFD.

let the length of AE=x, FD=30-16-x=14-x.

BE=[tex]\sqrt{169-x^{2} }[/tex], CF=[tex]\sqrt{225-(14-x)^{2} }[/tex]

BE=CF

[tex]\sqrt{169-x^{2} }[/tex]=[tex]\sqrt{225-(14-x)^{2} }[/tex]

Squaring both sides.

169-[tex]x^{2}[/tex]=225-196-[tex]x^{2}[/tex]+28x

140=28x

x=5 cm.

Put in BE=[tex]\sqrt{169-x^{2} }[/tex]

BE=[tex]\sqrt{169-25}[/tex]

=[tex]\sqrt{144}[/tex]

=12 cm.

Area of trapezium=1/2 (sum of parallel sides)*height

=1/2 (30+16)*12

=23*12

=276 [tex]cm^{2}[/tex]

Hence if the sides of trapezium are 16 cm, 15 cm, 30 cm, 13 cm then the area of the adjoining trapezium is 276 [tex]cm^{2}[/tex].

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[tex]\frac{6xyz}{2xy-y}.\frac{2x^{2}-7x+3 }{3xz - 9z} = 2x[/tex]

The expression can be simplified as follows:

[tex]\frac{6xyz}{2xy-y}.\frac{2x^{2}-7x+3 }{3xz - 9z}[/tex]

Hence,

[tex]\frac{6xyz}{y(2x-1)}.\frac{(x-3)(2x-1)}{3z(x-3)}[/tex]

Therefore.

[tex]\frac{6xyz}{y(2x-1)}.\frac{(2x-1)}{3z}[/tex]

Hence,

[tex]\frac{2xy}{y(2x-1)}.\frac{(2x-1)}1=2x[/tex]

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Based on the given function, the equivalent function that best shows the x-intercepts on the graph is f(x) = (6x - 1)(6x + 1)

Equivalent functions are different functions that have equal values when evaluated and compared

The function is given as:

f(x) = 36x^2 - 1

Express 1 as 1^2

f(x) = 36x^2 - 1^2

Express 36x^2 as (6x)^2

f(x) = (6x)^2 - 1^2

Apply the difference of two squares.

This is represented as:

(a + b)(a - b) = a^2 - b^2

So, we have the following equation

f(x) = (6x - 1)(6x + 1)

Based on the given function, the equivalent function that best shows the x-intercepts on the graph is f(x) = (6x - 1)(6x + 1)

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generally, tanA=opposite/adjacent

answer:tanC=36/15=12/5

Answer:

[tex]Tan \space\ \theta =\frac{\boxed{12}}{\boxed5}}[/tex]

Step-by-step explanation:

The tangent (Tan) of an angle is the ratio of the opposite side and the adjacent side, so that:

[tex]\boxed{Tan\space\ \theta = \frac{opposite}{adjacent}}[/tex].

In this case, with respect to angle C:

• opposite = AB =  36 units

• adjacent = CB = 15 units.

Substituting the values into the equation:

[tex]Tan \space\ C = \frac{36}{15}[/tex]

           = [tex]\bf \frac{12}{5}[/tex]   (simplified)

The given expression is a (A) linear expression.

Therefore, the given expression is a (A) linear expression.

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The correct question is given below:

Classify the expression: 5x 2.

(A) linear expression

(B) quadratic expression

(C) cubic expression

(D0 quartic expression

Using the arrangements formula, the number of orders is given as follows:

The number of possible arrangements of n elements is given by the factorial of n, that is:

[tex]A_n = n![/tex]

When there are no restrictions, the number of ways is:

[tex]A_{11} = 11! = 39,916,800[/tex]

When they must be lined alternatively, the 6 dogs can be arranged in 6! ways, and the 5 cats in 5! ways, hence the number of orders is:

[tex]A_6A_5 = 6! \times 5! = 86,400[/tex]

When the first and last are cats, we have that:

Hence:

20 x 9! = 7,257,600.

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