for a binomial probability distribution with 8 trials and probability of success equal 0.95. what is probability of exactly six successes? (use the binomial tables)

The value of side AC is AC = 3.

What is right triangle?

A right triangle, also known as a right-angled triangle, an orthogonal triangle, or historically a rectangled triangle, is a triangle with one right angle, meaning that its two sides are perpendicular. Trigonometry's foundation is the relationship between the right triangle's sides and other angles.

The given triangle  ΔABC is a right angled triangle.

So, to find the side AC we can use the cosine ratio,

[tex]cosB = \frac{Adjacent side}{Hypotenuse}\\ cos65 = \frac{AC}{AB} \\cos65 = \frac{AC}{7} \\AC = 7(c0s(65)\\AC = 7(0.4226)\\AC = 2.9583[/tex]

AC ≈ 3.

Hence, the length of side AC is 3.

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Answer:

93.33%

Step-by-step explanation:

56/60 as a percentage:

56/60 = 0.93333

0.93333 as a percent:

0.93333 * 100 = 93.33%

The value of solution for a number 56/60 into a percentage is,

⇒ 93.33%

We have to given that,

To change a number 56/60 into a percentage.

Since, A number or ratio that can be expressed as a fraction of 100 or a relative value indicating hundredth part of any quantity is called percentage.

Hence, We can write as,

⇒ 56/60 × 100%

⇒ 5600/60

⇒ 93.33%

Therefore, The value of solution for a number 56/60 into a percentage is,

⇒ 93.33%

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Answer:

yes, you did it right!

Step-by-step explanation:

You firsth calculate how much 15% of £600 are.
You did it exactly right. It's £90.
And to work out rhe value of the shares one week later, you add the £90 to the £600.

The slope-Intercept form of the given line is y=x-1.

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of line is given by,

y =mx + c

where,

x is the coordinate of the x-axis,

y is the coordinate of the y-axis,

m is the slope of the line, and

c is y-intercept.

The given line passes through (0,-1) and (1,0). Therefore, the slope of the given line can be written as,

Slope of the line, m = [0 - (-1)]/(1 - 0)

                                 = 1 / 1

                                 = 1

Now, the equation of the line passing through (0,-1) can be written as,

y = mx + c

(-1) = 1(0) + C

-1 = 0 + C

C = -1

Substitute all the value in the equation of the line,

y = m(x) + c

y = 1(x) + -1

y = x - 1

Hence, the equation of the given line is y=x-1.

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The equation of the line from the given graph can be written as  y = x + 1.

A straight line can be written in the form of equation as, y = mx + c.

Two straight lines intersect each other only at one point.

When two straight lines are parallel to each other the angle between them is zero.

From the given graph the points on the straight line can be determined as (1, 0) and (2, 1).

The slope of the line passing through points (x₁, y₁) and (x₂, y₂) is given as slope = (y₂ - y₁) / (x₂ - x₁).

Then, the slope of the line is (2 - 1) / (1 - 0) = 1

Now, the equation of the line can be written as,

(y - 1) / (x - 0) = 1

⇒ y - 1 = x

⇒ y = x + 1

Hence, the equation of the line in slope-intercept form is given as y = x + 1.

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The time taken to label 750 books if Clare labels books at 15 books per minute is 50 minutes.

In this situation, Clare volunteers at a library during the summer and has to label 750 books and she labels books at 15 books per minute and she takes no breaks.

Let the time taken to label the 750 books be represented by x.

This will be illustrated as:

1/x = 15/750

Cross multiply

(15 × x) = (750 × 1)

15x = 750

Divide

x = 750 / 15

x = 50

The time is 50 minutes.

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Complete question

Clare volunteers at a library during the summer and has to label 750 books. Clare labels books at 15 books per minute and she takes no breaks, then it would take her minutes to finish labeling all the books.

Answer:

56cm²

Step-by-step explanation:

Because this is an irregular shape, you have to split it into two shapes and find the area of each one. Then you can add those two areas together to find the total area of the figure. There are many ways you can split it but the way I did it left me with the equation (12·3)+(4·5). Then all you have to do is multiply and add which will give you a total of 56cm².

Thus, the number of ways in which  to choose 4 letters, without replacement, from 17 distinct letters is 57,120.

Total distinct letters are 17.

There are 17 alternatives for the initial letter if there are 17 letters.

There are just 16 alternatives left once you remove the letter.

Each time you remove a letter, the bag contains one fewer letter.

Number of ways = 17 x 16 x 15 x 14

Number of ways =  57,120

Thus, if the sequence of the alternatives is irrelevant, there are 57,120 options.

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Answer:

Here,

2x+3x=20x

or,5x=20x

or,5x-20x=0

or,15x=0(divide both sides by -15)

hence,x=0

The probability that of 10 randomly chosen bags of flour at least 2 are overweight be 0.68.

Given, that the weight of bags of all purpose flour is normally distributed with expected value 10 pounds and standard deviation 0.2 pounds.

As, we know that

P(X) = (1/s√2π)exp(-1/2((X-m)/s)^2)

where, m is the expected value

and s is the standard deviation.

Now, we have Expected value 10 pounds

and Standard Deviation 0.2 pounds

So,  the probability that of 10 randomly chosen bags of flour at least 2 are overweight be

P(X=0) + P(X=1) = (1/0.2√2π)exp(-1/2((0-10)/0.2)^2) + (1/0.2√2π)exp(-1/2((1-10)/0.2)^2)

P(X=0) + P(X=1) = 0.32

So, Required Probability be 0.68.

Now,  the probability that of 10 randomly chosen bags of flour at least 2 are overweight be 0.68

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The total amount of milk needed for the recipes, considering the line plot, is of:

5.25 cups.

The total amount of milk needed for the recipes is obtained adding all the measures of the line plots.

The measures of the line plot given by the image at the end of the answer are given as follows:

The total amount is given by the sum of all these measures, hence:

2 x 0.25 + 1.25 + 1.5 + 2 = 5.25 cups.

The line plot is given by the image at the end of the answer.

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There are 200 dogs Roscoe groom if he worked for 40 hours.

What is working time?

A person's working time is the time they are engaged in paid work. Personal housework, childcare, and pet care are examples of unpaid work that is not included in the definition of the working week.

In most cases, when someone inquires about your working hours, you should first provide the start time before providing the time you leave for home.

From the given graph we can see that for each three hours the number of dogs are increased by 15.

So, for each one hour the number of dogs increased by 5.

For 18 hours the the number of dogs are 90.

After 18 hours to complete 40 hours we need 22 hours.

So, for 22 hours the number of dogs are

22 x 5 = 110.

Therefore, the total number of dogs worked for 40 hours are,

90 + 110 = 220.

Hence, there are 200 dogs Roscoe groom if he worked for 40 hours.

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Answer:

Step-by-step explanation:

3p. = 2m - 5q

-2m. = -3p - 5q

Divide through by -2

m. = (3p + 5q) \2

The equation can be rearranged and expressed in terms of p and q is m = (3p+5q)/2.

Given equation 3p = 2m - 5q

3p + 5q = 2m

(3p + 5q) / 2 =m

Hence, m = (3p+5q) / 2  

To express the equation in terms of p and q we need to put all the p and q terms to one side of the equation and m terms to another side of the equation. It can be easily seen that 3p is already on one side and we just need to bring a q term to this side which can be done by shifting 5q from the right-hand side to left-hand side. The equation is now 3p+5q. Now to get the equation in terms of m we need to divide the whole equation by 2 which will give m = (3p+5q) / 2.

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Answer:2

Step-by-step explanation:

1+1 es 2

The unit rate for the given situation is 29 students per classroom.

What is the unit rate?

A unit rate is described as a ratio comparing the first quantity to one unit of the second quantity.

Given situation is 87 students in 3 classrooms.

So, the unit rate  [tex]= \frac{87}{3}[/tex]  students/classroom

                            [tex]= 29[/tex] students per classroom

Hence, the unit rate for the given situation is 29 students per classroom.

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Index contours are usually drawn darker than the other contours.

Index Contours are darker and wider than the other regular contour lines for ease of identification. They are labeled with elevation and also have their altitude value mentioned on the dark lines and these values represent the altitudes of the particular contours. Index contours appears after every fifth contours. If the number with contours will increase then its elevation will also increase and similarly if the number associated with contours starts to decrease then its elevation also decreases.

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The 10th term of an arithmetic sequence is found as the 49.

As per the stated values in question.

Fifth term a5 = 24

8th term a8 = 39.

Let the first term be 'a' and the common difference be 'd'.

Then,

a5 = a + 4d

24 = a + 4d .....eq 1

a8 = a + 7d

39 = a + 7d .....eq 2

Solving eq 1 and 2.

3d = 15

d = 5

a = 4

Now,

a10 = a + 9d

a10 = 4 + (9 x 5)

a10 = 4 + 45

a10 = 49

Thus, the 10th term of an arithmetic sequence is found as the 49.

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1) Simple interest is $41600, 2) compound interest is $ 43264, 3) Amount at the end of Simple interest is $301600, 4) Amount at the end of Compound interest is $303264, 5) Difference in the amount of simple and compound interest is $ 1664.

Here it is given:

Principle (P) =$ 260000

Time(t) = 2 years

Rate (R) = 8%

1) We have to find the simple interest:

Simple interest(SI) = P× t × R/ 100

                               = 260000× 2× 8/ 100

                               = $41600

2) We have to find Compound Interest

Compound interest(CI) =P( 1 + R/100[tex])^{t}[/tex]- P

                                     = 260000( 1 + 8/100[tex])^{2}[/tex]- 260000

                                     = 260000( 27/25[tex])^{2}[/tex] - 260000

                                     = 303264 - 260000

                                     = $43264

3) Amount at the end of simple interest

Amount = P + SI

             = 260000 + 41600

             =$301600

4) Amount at the end of compound interest

Amount = P + CI

             = 260000+ 43264

             = $303264

5) Difference between the amount at simple interest and compound interest

Difference = 303264 - 301600

                  = $1664

Therefore the simple interest is $41600, the compound interest is $43264, the Amount at the end of simple interest is $ 301600, the amount at the end of the compound interest is $303264, and the difference in the amount of simple interest and compound interest is $1664.

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The values of x, y and z are 4, 1 and - 6 respectively.

The general equation of a straight line is -

[y] = [m]x + [c]

where -

[m] is slope of line which tells the unit rate of change of [y] with respect to [x].

[c] is the y - intercept i.e. the point where the graph cuts the [y] axis.

A system of equations is a set of one or more equations involving a number of variables. The solutions to systems of equations are the variable mappings such that all component equations are satisfied

We have the following equations -

8x + y + 4z = 9

4x - 3y + z = 7

8x - 4y + 5z = - 2

We have -

4x - 3y + z = 7

z = 7 - 4x + 3y

We can write -

8x + y + 4z = 9

as -

8x + y + 4(7 - 4x + 3y) = 9

8x + y + 28 - 16x + 12y = 9               ...Eq[1]

and we can write -

8x - 4y + 5z = - 2

8x - 4y + 5(7 - 4x + 3y) = -2

8x - 4y + 35 - 20x + 15y = - 2         ...Eq[2]

Plot the graph of equation [1] and [2]. We will will get -

x = 4

y = 1

Now -

z = 7 - 4x + 3y

z = 7 - 16 + 3

z = - 6

Therefore, the values of x, y and z are 4, 1 and - 6 respectively.

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1. Translation; y= f(x) + 2

2. Reflection; y= -f(x)

3. Stretch; y= 2f(x)

4. Shrink; y= 1/2 f(x)

Each point in a figure is moved the same distance in the same direction using a type of transformation known as translation.

A reflection is the shape's mirror image. A line, called the line of reflection, will allow an image to reflect through it. Every point in a figure is said to reflect the other figure when they are all equally spaced apart from one another.

Given:

When f(x) shifts 2 units up, we have

y= f(x) + 2; Translation

When the graph of f(x) to a symmetric position on the opposite side of the x-axis

y= -f(x); Reflection

When it stretches f(x) by a factor of 2

y= 2f(x); Stretch

When it reduces f(x) by a factor of 1/2

y=  1/2f(x); Shrink

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Call the number of hours of labor x.

A flat rate of $500 -> just $500.
$50 for each hour of labor -> 50x (for x hours)

Therefore, we can represent the amount needed for x hours of labor as the function : 500 + 50x.

We substitute :
20 hours of labor = 500 + 50 x 20 = $1500
50 hours of labor = 500 + 50 x 50 = $3000

The mean and standard deviation of this sampling distribution is 1 cm and 0.033 cm, respectively.

The sample mean is the arithmetic mean of all the samples of processor chips. The mean of the sample group is known as the sample mean.

Let X denote the multiple random samples of 35 processor chips and each of which represents the size of the processor chips.

Let 'x' be the sample mean of all the random samples X which represents the size of the processor chips.

The mean of the size of processor chips= μ =1 cm

The mean of the sampling distribution x of sample means is equal to the mean of the sizes of the processor chips μ

Mean of sampling distribution x  = mean of the size of the processor chips μ

⇒ x = μ

   x = 1 cm

The mean of this sampling distribution is 1 cm.

The standard deviation is the amount of variation among the set of values. It is the measure of the dispersion of values in the data set.

The size of the processor chips has a standard deviation of 0.2 cm so σ = 0.2 cm

Let 'x' be the standard deviation of random samples X of the size of processor chips.

Number of random multiple samples of processor chips, n =35

The standard deviation of this sampling distribution can be calculated by using the below formula;

x = σ/[tex]\sqrt{n}[/tex]

Substituting the value of \sigma as "0.2" cm and the value of "n" as 35 in the above formula, we get;

x = 0.2/√35

x = 0.033 cm

The standard deviation of this sampling distribution is 0.033 cm.

The mean of this sampling distribution is 1cm and the standard deviation of this sampling distribution is 0.033 cm.

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Step-by-step explanation:

In a candy box, there are 3 times as many candies with nuts as candies without nuts. There are 12 candies in the box. How many candies with nuts are in the box?

let:

without nuts = x

with nuts = 3x

so:

x + 3x = 12

4x = 12

x = 3, so there are 3 candies without nuts.

Because there are three times more candies with nuts than without:

3 * 3 = 9 candies with nuts

Answer:

9 candies with nuts

Step-by-step explanation:

Suppose the number of candies is x

there three times as many candies with nuts as candies without nuts, so 3x

there are 12 candies in total

3x+x=12

4x=12

x=3

3x=9

We're given :
Patricia originally has $3425.82 in her account.

After that, she deposits $9120.75, meaning her amount in her account goes up by $9120.75

Lastly, she withdraws $185.90, meaning her amount in her account goes down by $185.90.

Therefore, after the transactions, she has a total of : 3425.82 + 9120.75 - 185.90 = $12360.67

The value of function is positive so the function have maximum value at x=3.

In the given question we have to find the maximum or the minimum value of a function.

The given function is

f(x) = -3x^2+18x+3

To find the maximum or minimum value we firstly find the value of f'(x).

f'(x) = -6x+18

Now put f'(x)=0

-6x+18=0

Subtract 18 on both side we get

-6x=-18

Divide by -6 on both side we get

x = 3

Now finding the value of function at x=3

f(3)= -3*(3)^2+18*3+3

f(3)= -3*9+54+3

f(3)= -27+54+3

f(3)= 30

Since the value of function is positive so the function have maximum value at x=3.

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the solution for the  given equation is  x= 1/2

an equation could be a formula that communicates the balance of two expressions, by interfacing them with the equals sign. Understanding an equation containing factors comprises deciding which values of the factors make the equality true. The factors for which the equation must be fathomed are moreover called unknowns, and the values of the unknowns that fulfill the balance are called solutions of the condition. There are two sorts of equations such as conditional and identities equations. An identity is genuine for all values of the factors. A conditional equation is as it were genuine for specific values of the factors

since the  given expression is :

`(2-4)=2(-5+1)x²

so solving for the simple  arithmetic expression on both sides  :

=>-2 =2(-4)x²

=> -2 = -8x²

=>2/8=x²

=>1/4= x²

=>x= 1/2

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Using the compound amount formula, the amount after 40 years is 2000(107/100)^40.

In the given question,

Esther got a summer job and decided to set aside $2000 to prepare for retirement without making monthly contribution.

She invests in the US stock market through as index fund that averages a 7% return compounded annually over this 40 year period.

We have to find the total balance in the account after 40 years.

We have to find total balance compounded annually.

The formula of the compound amount is

A = P(1+r/100)^n

where A = Amount

P = Principal Amount

r = interest rate

n = time

From the question we know that

P = $2000, r = 7%, n = 40

Now putting the value in formula

A = 2000(1+7/100)^40

Simplifying

A = 2000(1×100/100+7/100)^40

A = 2000(100/100+7/100)^40

A = 2000((100+7)/100)^40

A = 2000(107/100)^40

You can find the amount after simplifying the amount.

Hence, the amount after 40 years is 2000(107/100)^40.

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The number problems solved by the little Monsters  of Beast Academy in March's meet is 15.

The problem is a simultaneous equation of two unknowns with two equations.

The equations are formed as follows

let the number of questions solved by little Monsters  of Beast Academy in

In November's Math Meet, the Little Monsters of Beast Academy solved $\frac{1}{5}$ of the problems = y/5

In March's Math Meet, they solved $\frac23$ of the problems = 2x/3

Hence:

y/5 + 2x/3 = 12

x + y = 30

solving the equation gives

x = y = 15

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The annual percentage rate of depreciation of the number of rhinos represented by the statistics is approximately 6.41 %

The rate of depreciation is the rate at which the number or value of an item reduces within each specified period.

The initial number of black rhinos in 1970 = 60,500

The number of black rhinos remaining in 2011 = 4,000

The annual rate of depreciation can be found using the formula;

Where;

FV = The future value = 4,000

PV = The present value = 60,500

r = The annual depreciation rate

n = The number of years

[tex]4,000 = 60,500 \times \left(1+\dfrac{r}{100} \right)^{(2011-1970)}=60,500 \times \left(1+\dfrac{r}{100} \right)^{41}[/tex]

[tex]\left(1+\dfrac{r}{100} \right)^{41} = \dfrac{4000}{60500} = \dfrac{8}{121}[/tex]

[tex]r = 100\times \left(\sqrt[41]{ \dfrac{8}{121}} - 1\right) \approx -6.41[/tex]

The annual rate of depreciation is approximately 6.41%

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