For a population with = 100 and = 20, what is the x value corresponding to z = 1. 50?

Answer:

N = 2.1

M = 4.5

Step-by-step explanation:

<p is 25 degrees.  I know this because the exterior angle of p corresponds with 155.  Since this is a straight angle, angle p must be 25 (180-155).  Now I can use the cos and the sin of 25 to find M and N

sin 25 = N/5  multiply both sides by 5 to get

5 sin 25 = N  Use your calculator put in 5 sin 25

2.1 rounded to the nearest tenth.

cos 25 = M/5  Multiply both sides by

5 cos 25 = M Use your calculator

4.5

Option C. The mean is less than the median in the distribution of the scores.

The median is given as 79 + 78 / 2

= 78.5

The mode is 79 this is the number that has the highest frequency in the data.

The median is 78.5  this is the middle number in the set of scores of these students.

Hence the mean is less than the mode and the median given that it was  it was brought down by the few scores of 49.

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The first series uses a linear function with - 1 as first element and 1 as common difference, then the rule corresponding to the series is y = |- 1 + x|.

The second series uses a linear function with - 3 as second element as 2 as common difference, then the rule corresponding to the series is y = |- 3 + 2 · x|.

In this problem we have two cases of arithmetic series, which are sets of elements generated by a condition in the form of linear function and inside absolute power. Linear functions used in these series are of the form:

y = a + r · x      (1)

Where:

The first series uses a linear function with - 1 as first element and 1 as common difference, then the rule corresponding to the series is y = |- 1 + x|.

The second series uses a linear function with - 3 as second element as 2 as common difference, then the rule corresponding to the series is y = |- 3 + 2 · x|.

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[tex]let \: the \: number \: be \: denoted \: by \: p \\ five \: times \: a \: number = 5p \\ square\: of \: a \: number = p {}^{2} [/tex]

[tex] \gamma - p {}^{2} = 5p - p {}^{2} [/tex]

[tex]\textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ V=562\\ r=5 \end{cases}\implies 562=\cfrac{\pi (5)^2 h}{3}\implies 1686=25\pi h \\\\\\ \cfrac{1686}{25\pi }=h\implies 21.47\approx h[/tex]

Answer:$96.98

Step-by-step explanation: all you just do is to add it all up to the total amount.

Answer: $105.47

I hope you get the job!!!!!

Answer:

1. BD bisects <CBE, AE || BD (Given)

2. <EBD ~= <CBD (Definition of < Bisectors)

3. <AEB ~= <EBD (Alternate Interior Angles Theorem)

4. <CAE ~= <CBD (Corresponding Angles Postulate)

5. <CAE ~= <AEB (Transitive Property of Congruence)

6. AB ~= BE (Converse of Isosceles Triangles Theorem)

Answer:

Step-by-step explanation:

177.8 centimeters.

The shortest distance between the tip of the cone and its rim:

cos θ= base/Hypotenuse

cos 77°=[tex]\frac{40}{H}[/tex]

[tex]0.22495=\frac{40}{H}[/tex]

[tex]H=177.8[/tex]

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The shortest distance between the tip of the cone and its rim exits 51.11cm.

If you draw a line along the middle of the cone, you'd finish up with two right triangles and the line even bisects the angle between the sloping sides. The shortest distance between the tip of the cone and its rim exists in the hypotenuse of a right triangle with one angle calculating 38.5°. So, utilizing trigonometry and allowing x as the measurement of the shortest distance between the tip of the cone and its rim.

Cos 38.5 = 40 / x

Solving the value of x, we get

Multiply both sides by x

[tex]$\cos \left(38.5^{\circ}\right) x=\frac{40}{x} x[/tex]

[tex]$\cos \left(38.5^{\circ}\right) x=40[/tex]

Divide both sides by [tex]$\cos \left(38.5^{\circ}\right)$[/tex]

[tex]$\frac{\cos \left(38.5^{\circ}\right) x}{\cos \left(38.5^{\circ}\right)}=\frac{40}{\cos \left(38.5^{\circ}\right)}[/tex]

simplifying the above equation, we get

[tex]$x=\frac{40}{\cos \left(38.5^{\circ}\right)}[/tex]

x = 51.11cm

The shortest distance between the tip of the cone and its rim exits 51.11cm.

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Answer: Total = $200

Step-by-step explanation:

Given information

Money spent on shoes = $20.00

Percent of Money spent on shoes = 10%

Given formula

The total amount of money spent × Percent = Money spent on shoes

                                                      ⇵    

The total amount of money spent = Money spent on shoes / Percent

Substitute values into the given formula

The total amount of money spent = Money spent on shoes / Percent

Total = (20.00) / (10%)

Convert percentage into decimal

Total = 20.00 / 0.1

Simplify the fraction

[tex]\Large\boxed{Total~=~200~Dollars}[/tex]

Hope this helps!!  :)

Please let me know if you have any questions

The radius of cylinder = 6 meter

The height of cylinder = 11 meter

According to the question,

Surface area of the cylinder = 640.56 m²

Let the height of the cylinder = x meters

Let the radius of the cylinder = (x-5)meters

Formula for surface area of cylinder = 2πrh ( where 'r' is the radius of the cylinder and 'h' height of the cylinder)

640.56 = 2 (3.14) (x-5) (x)

640.56/(6.28) = x² - 5x

x² - 5x =102

x² - 5x - 102 =0

using quadratic equation, [-b±√(b² - 4ac)]/2a.

b = -5; a=1; c=102

x =[-(-5) ±√(-5)² - 4(1)(102)]/2

= [5 ± √433]/2

x = 11 and -7

since x=-7 neglect negative value, we get x=11.

The height of the cylinder is 11 meters

The radius of the cylinder is (11 - 5) = 6 meters.

Hence, The radius of cylinder = 6 meter.

The height of cylinder = 11 meter.

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Answer:

Step-by-step explanation:

The radius of cylinder = 6 meter

The height of cylinder = 11 meter

According to the question,

Surface area of the cylinder = 640.56 m²

Let the height of the cylinder = x meters

Let the radius of the cylinder = (x-5)meters

Formula for surface area of cylinder = 2πrh ( where 'r' is the radius of the cylinder and 'h' height of the cylinder)

640.56 = 2 (3.14) (x-5) (x)

640.56/(6.28) = x² - 5x

x² - 5x =102

x² - 5x - 102 =0

using quadratic equation, [-b±√(b² - 4ac)]/2a.

b = -5; a=1; c=102

x =[-(-5) ±√(-5)² - 4(1)(102)]/2

= [5 ± √433]/2

x = 11 and -7

since x=-7 neglect negative value, we get x=11.

The height of the cylinder is 11 meters

The radius of the cylinder is (11 - 5) = 6 meters.

Hence, The radius of cylinder = 6 meter.

The height of cylinder = 11 meter.

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The surface area of all 27 blocks compared to the surface area of the box is 3 times the surface area of the box.

To find the total surface area of the 27 blocks:

A cube's surface area

Given that the box's side length is 15 inches:

Surface Area of 3-inch side length blocks:

Surface Area of 4-inch side length blocks:

Surface Area of 5-inch side length blocks:

Therefore, from the given answer options for the total surface area of the 27 blocks, the side length of the blocks must be 5 inches.

To calculate how many times the total surface area of the 27 blocks is to the surface area of the box:

So,

The side length of the blocks is 5 inches.

The total surface area of the 27 blocks is 4050 square inches.

This is 3 times the surface area of the box.

Therefore, the surface area of all 27 blocks compared to the surface area of the box is 3 times the surface area of the box.

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Answer:

16 square units

Step-by-step explanation:

You find the area by multiplying the base times the height.  The base or horizonal length is 4.  You get this from the ordered point x (4,0).  The x coordinate 4, tells us that the point x is 4 spaces to the right of zero, so the length or base is 4.

The height is also 4.  You get this from the point S (2,4)  The y coordinate of 4 tells you how high up the point is.

4 x 4 = 16

Answer:

The rope is worth 13.

The shoe is worth 5.

The clock is worth 3.

Step-by-step explanation:

We know that the weights are 8 so we will use 8 for the weights.

Let s = show

Let r = rope

Let c = clock

We have three unknowns so we need three equations.

8 + s = r                      c + s = 8                                 s= c +2

There are a number of ways that we can approach this.  Let's substitute

c + 2 for s in the first 2 equations.

8 + s = r

8 + c + 2 = r

10 + c = r

c + s = 8

c + c + 2 = 8

2c + 2 = 8  

2c = 6

c = 3  we found the value of the clock.

Now, let's substitute 3 in for 3 in the bold equation above.

10 + c = r

10 + 3 = r

13 = r we found the value of the rope.

We can use any of the equations to find the shoe.

s= c + 2

s = 3 + 2

s = 5

This is tricky.  It takes a lot of practice.  Don't give up!

Shoe= 5

Rope= 13

Clock= 3

We can start by giving each item a variable. Shoe= s, rope= r, clock= c. The weight is 8, so we don't need to give it a variable. Our equations are now:

8+s= r

c+s= 8

s= c+2

Now, we can isolate a variable to solve for it using the substitution method. Let's start with s.

c+s=8

-c    -c

s= 8-c

Now, we'll take another equation and plug s in.

8-c=c+2

 +c +c

8= 2c+2

-2      -2

6=2c

c=3

Now we know that the clock is 3. Put 3 into the last equation, and add 3+2 to get 5 for the shoe. 5 in the first equation for the shoe plus 8 as the weight means the rope is 13.

hope this helped!

Juan's ball would travel the greatest distance while Barry's ball would travel the shortest.

Juan

Juan's equation is given as:

h = -0.001d^2 + 0.5d + 2.5

h =

Set d to multiples of 50 from 0 to 400.

So, the table of values of Juan's function is:

d (ft)                   h(ft)

0                          2.5

50                        25

100                      42.5

150                        55

200                      62.5

250                        65

300                      62.5

350                        65

400                      42.5

See attachment for the graph of Juan's function

Mark

A quadratic function is represented as:

h = ad^2 + bd + c

Using the values on the table of values, we have:

c = 3 -- the constant value

So, the equation becomes

h = ad^2 + bd + 3

Using the two other values on the table of values, we have:

23 = a(50)^2 + b(50) + 3

38 = a(100)^2 + b(100) + 3

Using a graphing tool, we have:

a = -0.001

b = 0.45

So, Mark's equation is h(d) = -0.001d^2 + 0.45d + 3

See attachment for Mark's graph.

Barry

From the graph, we have the table of values of Barry's function to be:

d (ft)                   h(ft)

0                          2.5

50                        21

100                      35

150                       44

200                      48

250                       46

300                      41

350                       30

400                      14

450                      0

Using a graphing tool, we have the quadratic function to be:

y = -0.001x^2 +0.4x +2.5

From the graphs, equations and tables, the distance travelled by the balls are:

Juan = 505 feet

Mark = 457 feet

Barry = 450 feet

This means that Juan's ball would travel the greatest distance while Barry's ball would travel the shortest.

To do this, we set d = 350

From the graphs, equations and tables, the height at 350 ft by the balls are:

Juan = 65 feet

Mark = 38 feet

Barry = 30 feet

The above represents the height the balls hit the fence

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Step-by-step explanation:

Since you haven't provided any functions, I can answer this question generally as to what the function would look like.

So when a polynomial has an even degree, then the two end behaviors will go in the same direction, and when it has an odd degree, then the two end behaviors will be in opposite directions. When a polynomial has a positive leading coefficient the right side will go towards infinity, and if a polynomial has a negative leading coefficient the right side will go towards negative infinity.

So let's look at the information:

As x approaches negative infinity, y approaches positive infinity.

Just given this we can't really say anything about the polynomial since we have to relate this to the right end behavior, or as x approaches infinity, so let's look at that.

As x approaches positive infinity, y approaches negative infinity.

This means that as x increases, y decreases, so that means the leading coefficient is negative. Since we know both end behaviors, and they're opposite (one y-value goes to negative infinity, and the other positive infinity), that means the polynomial is an odd degree.

So this means the polynomial will look something like this:

[tex]ax^n+bx^{n-1}+cx^{n-2}...[/tex]

where the leading coefficient "a" is negative and the degree of the polynomial (degree of leading coefficient) will be odd.

Answer:A

Step-by-step explanation:

edge 2023

The required radius of the cylinder that can be covered by the paint exists at 3.8 feet.

Franco has enough paint to protect an area of about 226 square feet. He must paint a cylinder that exists 5 feet, and the maximum possible radius of the cylinder that can be covered by the paint exists to be determined.

The cylinder exists described as a 3D solid that holds two identical bases joined by a curved surface, at a particular distance.

Here, Franco keeps sufficiently paint to cover an area of about 226 square feet.

Area of the cylinder = 226

Area of the cylinder = πr²h = 226

h = 5 feet and π = 3.14

3.14 [tex]*[/tex] 5 [tex]*[/tex] r² = 226

r² = 226/15.70

[tex]$r = \sqrt{14.70}[/tex]

r = 3.80

Therefore, the required radius of the cylinder that can be covered by the paint exists at 3.8 feet.

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Answer: 4

Step-by-step explanation: I got the answer 4 right on the test

Answer:

Find out how much each makes per hour and then compare.

Step-by-step explanation:

Phil: 112.70/14 = 8.05  Phil makes $8.05 per hour

Eva: 113.82/1 =8.13  Eva makes $8.13 per hour

Eva makes $0.08 more an hour.

[tex]\textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{lllllllll} \log_{\underline{10}}(10)=1&\implies &\underline{10}^1=10 ~~ \checkmark\\\\ \log_{10}(100)=2&\implies &10^2=100~~ \checkmark\\\\ \log_{10}(55)=1.5&\implies &10^{1.5}=55\implies 10^{\frac{3}{2}}=55\implies \sqrt[2]{10^3}=55\\\\ &&\sqrt{1000}\ne 55 ~~ \bigotimes \end{array}[/tex]

increments over the exponent, are not directly proportional to increments on the resulting values, namely the half-way from 10² and 10⁴ is not 10³, because 10⁴ is 100 times 10², and 10³ is simply 10 times 10².

The satellite makes 8 revolutions around the earth, it passes 177272 kilometers.

The orbital velocity of the satellite exists independent of its mass. The radius of the orbit exists as the only variable. If the satellite orbits near the planet at such a low height, its orbital speed must be extremely fast. If the orbital speed exists less than the required value, the satellite will be drawn to the earth's surface by gravity.

The satellite rotates around the earth to form a circle,

diameter of circle = Diameter of earth + 2(Height)

d = 6714 + 2(343)

d = 6714+ 686

d = 7057

Perimeter = πd

Perimeter = 3.14 (7057)

Perimeter = 22158.98

Total Revolution exists 8

Therefore, 8πd = 8(22158.98)

= 177272 kilometers.

Therefore, the satellite makes 8 revolutions around the earth, it passes 177272 kilometers.

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[tex](x-5)(x+5)-(x+1)^2\\=x^2 -25-(x^2+2x +1)\\=x^2 -25-x^2-2x -1\\=-2x-26[/tex]

ANSWER: -2x -26

Ok done. Thank to me :3

See attached images for the graph.

The solution for the given equation is -5/8. By using simple algebraic operations, the equation is solved.

A linear equation is represented by ax + b = 0. The solution for this equation is

ax + b = 0

⇒ ax = -b

⇒ x = -b/a

The given equation is

7/8 + x = 1/4

On simplifying,

x = 1/4 - 7/8

⇒ x = -5/8

Therefore, the solution of the given equation is -5/8.

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The constant in the expression represents that the company earned  85 billion dollars in 2008.

The expression given in the question is known as a quadratic function. A quadratic function is a function that usually has a single variable and it is raised to the power of 2. The graph of a quadratic function is a curve called a parabola. Parabolas may curve upward or downward

An example of a quadratic function is ax² + bx + c

Where: a,b, c are real numbers not equal to zero

c = constant.

The constant in this question is 85. It is the amount earned in 2008

Here are the options:

The company earned  85 billion dollars from 2008 to 2018

The company earned  85 billion dollars in 2008

The company earned 14  billion dollars from 2008 to 2018.

The company earned  14 billion dollars in 2008.

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Answer:

5/222

Step-by-step explanation:

you need to add all the cards together first

13 + 10 + 8 + 6 = 37

then you take out 1 card to find the first probability of the blue card (there are 6 blue cards out of 37)

so 6/37

that will be your first probability

then for the 2nd probability, you will have 1 less card grom the deck making it only 36 cards (after taking out the first one, there will be only 5 blue cards left)

making it 5/36

that will be the 2nd probability

then you multiply both these probabilities to find the answer

6/37 × 5/36 = 5/222

I'll go for the third option. It seems sensible to having a balance in estimating provided data, even though that may not always be the case.

Hope this helps!

The zeros represent the number of monthly memberships where no profit is made; x = 6, x = 44.

The function we have is: [tex]f(x) = -x^{2} +50x-264[/tex]

That models the profit in dollars, where [tex]x[/tex] is the number of memberships sold.

In order to get the zeros we'll use the quadratic formula:

[tex]x_{1,2} =\frac{-b+-(b^{2}-4ac) }{2a} \\[/tex]

For,

[tex]a=-1,b=50,c=-264: x^{1,2} =\frac{-50+-\sqrt[]{50^{2} -4(-1)(-264)} }{2(-1)} \\x_{1} =\frac{-50+\sqrt[]{50^{2} -4(-1)(-264)} }{2(-1)} =\frac{-50+\sqrt[]{50^{2} -4*1*264} }{2(-1)}=\frac{-50+\sqrt[]{1444} }{-2} =6\\x_{2} =\frac{-50+\sqrt[]{50^{2} -4(-1)(-264)} }{2(-1)} =\frac{-50-\sqrt[]{50^{2} -4*1*264} }{2(-1)}=\frac{-50-\sqrt[]{1444} }{-2} =44\\[/tex]

So, the zeroes are [tex]x=6, x=44[/tex].

Therefore, the zeros represent the number of monthly memberships where no profit is made; x = 6, x = 44.

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The complete question is given below:

A yoga studio sells monthly memberships. The function f(x) = −x2 + 50x − 264 models the profit in dollars, where x is the number of memberships sold.

Determine the zeros, and explain what these values mean in the context of the problem.

x = 6, x = 44; The zeros represent the number of monthly memberships that produce a maximum profit.

x = 6, x = 44; The zeros represent the number of monthly memberships where no profit is made.

x = 25, x = 361; The zeros represent the number of monthly memberships where no profit is made.

x = 25, x = 361; The zeros represent the number of monthly memberships that produce a maximum profit.

Answer:

The answer is: x = 6, x = 44; The zeros represent the number of monthly memberships when no profit is made.

The average density of the rod is  0.704 kg/m.

For given question,

We have been given the linear density in a rod 5 m long is 10 / x + 4 kg/m, where x is measured in meters from one end of the rod.

We need to find the

The length of rod is, L = 5 m.

The linear density of rod is, ρ = 10/( x + 4) kg/m

To find the average density we need to integrate the linear density from x₁ = 0 to x₂ = 5,  

The expression for the average density is given as,

⇒ ρ'

[tex]=\int\limits^5_0 {\rho} \, dx\\\\=\int\limits^5_0 {\frac{m}{L} } \, dx\\\\=\int\limits^5_0 {\frac{10}{5(x+4)} }\, dx\\\\=\int\limits^5_0 {\frac{2}{x+4} }\, dx[/tex]                        ......................(1)

Using u = x + 4  

du = dx

u₁ = x₁ + 4

u₁ = 0 + 4

u₁ = 4

and

u₂ = x₂ + 4

u₂ = 5 + 4

u₂ = 9

By entering the values above into (1), we have:

⇒ ρ'

[tex]=2\int\limits^9_4 {\frac{1}{u} } \, du\\\\ = 2[(log~u)]_4^{9}\\\\=2[(log~9-log~4)]\\\\=2\times[0.352][/tex]

= 0.704

Thus, we can conclude that the average density of the rod is  0.704 kg/m.

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[tex] \sqrt{112x {}^{6}y {}^{3} {z}^{5} } \\ \sqrt{(2 {}^{4} \times 7 )x {}^{6}y {}^{2}yz {}^{4} z } \\ 2 {}^{2}x {}^{3} yz {}^{2} \sqrt{7yz} [/tex]