For each value of w determine whether it is a solution to 53=9w-1

-10
9
6
-1

Answer: 3 rose bushes

Step-by-step explanation:

1. First we must identify the unknown. We do not know how many rose bushes he can get, we will use "x" to represent this number.

2. We must set up an equation with the given information. We know the delivery fee will remain constant.

3. 15+18.75(x)=80

4. Subtract 15 from both sides and it leaves you with 18.75x=65

5. Then you must divide both sides by 18.75, which leaves you with x=3.46

6. We cannot buy .46 of a plant so we must round down to 3

7. Jim can buy 3 rose bushes

Answer:

Yes.

Step-by-step explanation:

They will be either side of the 2 circles.

Answer: 80g

Step-by-step explanation:

we can write an equation for the weight of chocolate; 360-(2/5)x=248

when we solve that equation, we get x=280

since the total weight is 360, we can minus 280 from it to get the weight of the box

360-280=80

Answer:

Step-by-step explanation:

let the common ratio be x.

boy 1 share= 6x

boy 2 share= 7x

boy 3 share= 8x

-------------------------------

                    21x= 10500.00

              => x= 10500/21

                   x= 500

6 x 500= $3000

7x 500= $3500

8 x 500= $28000

therefore,  boy 3 has the largest share of $28000.

25 Degres it is a obtuse angle using the dewy decimal system

Answer:

The person above me is correct

25

Step-by-step explanation:

In the given simultaneous linear equation, the value for x is 3 and the value for y is 2.

A system of simultaneous linear equations is any set of two or more linear equations that share the same variables involved. Obtaining values for the unknown variables that simultaneously satisfy all of the equations is required to solve such a system.

In the given question,

x + y = 5.......(i)

x2 - 2y2 = 1.......(ii)

x = 5 - y.........(iii)

Substituting x in equation(ii) = (5 - y)2 - 2y2 = 1

25- 10y + y2 - 2y2 = 1

25 - 1 = y2 + 10y

y2 + 10y2 - 24 = 0

(y + 12)(y - 2) = 0

Then Either y + 12 = 0 or y - 2 = 0

= (-12, 2)

Thus, y = 2

Now, substituting the value of y in equation (i),

x + y = 5

x + 2 = 5

x = 5 - 2

x = 3

Therefore x = 3 and y = 2.

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Let's call the length of the bottom side of the triangular banner "b". When Alice reaches her arm up above the ground, the height of the banner changes from its original height of "h" to a new height of "h'". The area of the banner can be calculated using the formula:

A = (b * h') / 2

The new height "h'", can be calculated using the Pythagorean theorem, which states that in a right triangle, the sum of the squares of the two shorter sides is equal to the square of the longest side (the hypotenuse).

In this case, the two shorter sides are the original height "h" and the difference between the length of Alice's arm and the original height, which we will call "d". The longest side is the distance between the two anchors, which we will call "a".

So:

h^2 + d^2 = a^2

We can solve for "d" using this equation:

d = sqrt(a^2 - h^2)

And then we can find "h'" using:

h' = h + d

So the area of the banner can be calculated as:

A = (b * (h + sqrt(a^2 - h^2))) / 2

The solution assumes that the banner is a right triangle, with one vertex at the top, one vertex at the bottom, and a straight side along the ground connecting the two bottom vertices.

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[tex]~~~~~~ \stackrel{\textit{\LARGE Quarterly}}{\textit{Compound Interest Earned Amount}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$7000\\ r=rate\to 9\%\to \frac{9}{100}\dotfill &0.09\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years\dotfill &12 \end{cases}[/tex]

[tex]A = 7000\left(1+\frac{0.09}{4}\right)^{4\cdot 12} \implies A=7000(1.0225)^{48}\implies \boxed{A \approx 20367.48} \\\\[-0.35em] ~\dotfill[/tex]

[tex]~~~~~~ \stackrel{\textit{\LARGE Annually}}{\textit{Compound Interest Earned Amount}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$7000\\ r=rate\to 9\%\to \frac{9}{100}\dotfill &0.09\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &12 \end{cases}[/tex]

[tex]A = 7000\left(1+\frac{0.09}{1}\right)^{1\cdot 12}\implies A=7000(1.09)^{12} \implies \boxed{A \approx 19688.65} \\\\[-0.35em] ~\dotfill\\\\ 20367.48~~ - ~~19688.65 ~~ \approx ~~ \text{\LARGE 678.83}[/tex]

The new coordinates of the point (-7, -6) are (-6, 7).

From the question, we have the following parameters that can be used in our computation:

(x, y) = (-7, -6)

The rule is given as

A rotation of 90° clockwise around the origin.

Mathematically, this can be represented as

(x, y) = (y, -x)

So, we have

Image = (-6, 7)

Hence, the image is (-6, 7)

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The amount of money that Adrian will pay if he goes on the given amount of ride would be =$71

An amusement park is defined as the park where different recreational activities are being carried out.

The price of admission in the park = $35

The amount he pays for each ride at the amusement park= $3.

The amount for 12 rides= 3×12 = $36

Therefore the total amount of money that Adrian will pay if he goes to the amusement park for 12 rides would be = $36 + $35 =$71

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In a repeated measures design with 20 subjects, each subjected to 2 measurements (before and after stimulus presentation), the degrees of freedom in the test would be 19.

The problem is about an experiment in which a measurement is taken before and after a stimulus is presented to 20 subjects. The aim is to determine the number of degrees of freedom in the data analysis of the experiment.

Degrees of freedom (df) are a measure of the amount of variability in a set of data that is free to vary in the calculation of a statistical test. In a repeated measures design, the degrees of freedom are calculated as the number of subjects minus 1. In this case, with 20 subjects, the degrees of freedom would be 19.

The concept of degrees of freedom is used in both mathematics and physics, but the specific context of a t-test for dependent samples is commonly used in statistical analysis, particularly in the social sciences, psychology, and education research. So, it is more related to mathematics.

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This indicates that there is an about 0.1587 chance that a particular student will like Eminem tracks between 5.5 and 8.5.

The quantity of possible outcomes is known as probability. all events that could possibly occur. For instance, there is a 1 in 2 chance of receiving a head when flipping a coin, and there are 2 possible outcomes overall (a head or tail). P(heads) = 12 is the formula.

There are four primary categories of probability: axiomatic, axiomatic, classical, and empirical. Probability is the area of mathematics that deals with the possibility of a random event.

How likely something is to occur is known as its probability. We can discuss the probabilities of various outcomes—how likely they are—when we aren't sure how a particular event will turn out. Statistics describes the examination of events subject to probability.

To find:

P(X < 5.5)

Z = -1.0

However;

P(X< 5.5) = P(Z < -1.0)

P(X< 5.5) = 0.1587

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An expansion within a population that happens at the same pace across time is represented by the function of exponential growth.

Examples :

The analyst can determine the possible returns after three, five, and ten years if the customer deposits an initial starting capital of $5,000 into their compound savings account. The analyst decides: Using a 5% interest rate

Upon completion of three years: ($5,000)(1 + 0.05)(3) = $5,788

Upon completion of five years: ($5,000)(1 + 0.05)(5) = $6,381

A decade later, ($5,000)(1 + 0.05)(10) = $8,144

The Complete Question is exponential growth.

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The correct description is that moon is waxing.

The theory used in this question is the lunar cycle, which is the process by which the moon changes its shape and illumination over the course of a month.

The waxing phase of the lunar cycle is when the moon is gradually getting bigger and more illuminated.

The waning phase is when the moon is gradually getting smaller and less illuminated.

The moon is waxing:

This is an accurate description because when the moon changes from a new moon to a full moon, it is said to be waxing.

This means that the moon is gradually getting bigger, and its illuminated side is increasing.

This process is called the waxing phase of the moon's cycle.

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To calculate the probability a) P = (4C4 x 3C3)/(12C12) = 1/12. (b) P = (4C1 x 3C3 x 5C5)/(12C12) = 1/12. (c) P= (4C1 x 3C3 x 4C3 x 5C4)/(12C12) = 1/9. (d) P= (4C2 x 3C3 x 5C5)/(12C12) = 1/36.

(a) To calculate the probability that all hip surgeries are completed before another type of surgery, we first determine the total number of possible combinations of surgeries (12C12). We then calculate the number of combinations with four hip surgeries and three knee surgeries (4C4 x 3C3). We divide the number of combinations with the desired schedule by the total number of combinations to get the probability (1/12). (b) To calculate the probability that the schedule begins with a hip surgery, we first determine the total number of possible combinations of surgeries (12C12). We then calculate the number of combinations with one hip surgery, three knee surgeries, and five shoulder surgeries (4C1 x 3C3 x 5C5). We divide the number of combinations with the desired schedule by the total number of combinations to get the probability (1/12). (c) To calculate the probability that the first and last surgeries are hip surgeries, we first determine the total number of possible combinations of surgeries (12C12). We then calculate the number of combinations with one hip surgery at the start, three knee surgeries, three hip surgeries, and four shoulder surgeries (4C1 x 3C3 x 4C3 x 5C4). We divide the number of combinations with the desired schedule by the total number of combinations to get the probability (1/9). (d) To calculate the probability that the first two surgeries are hip surgeries, we first determine the total number of possible combinations of surgeries (12C12). We then calculate the number of combinations with two hip surgeries, three knee surgeries, and five shoulder surgeries (4C2 x 3C3 x 5C5). We divide the number of combinations with the desired schedule by the total number of combinations to get the probability (1/36).

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The acceleration of an object is interpreted as the rate of change at which its speed varies with time. When the motion is vertical, the object has an acceleration when its speed varies, while when the speed is constant, the acceleration is equal to zero. The acceleration of the box is 0.614 m/s.

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One significant mathematical function that has the form is the exponential function, f(x) = [tex]$$a^x[/tex].

If f(x) = [tex]$$a^x[/tex], where x is the input variable and is expressed as an exponent, is the formula for an exponential function. In addition to being dependent on the exponential function, the exponential curve also depends on the value of x. One significant mathematical function that has the form is the exponential function. f(x) = [tex]$$a^x[/tex].

The four fundamental characteristics of exponential functions are their y-intercept, horizontal asymptote, domain (the range of x values at which the function occurs), and constant growth factor, b.

Calculating the exponential growth or decay of a set of given data is done using an exponential function. According to the power to the power rule, "If the base increased to a power is being raised to another power, then the two powers are multiplied and the base remains the same."

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Answer:

See below

Step-by-step explanation:

The graph is of f(x) is shifted 1 unit to the LEFT to get g(x)

          so  4^x     is now  4^(x+1)

                                   then    4^(x+1) = 4^(x-h)

                                         would mean h = - 1

The required area of the parallelogram and pentagon is 91 unit² and 75 unit².

The surface area of any shape is the area of the shape that is faced or the Surface area is the amount of area covering the exterior of a 3D shape.

A parallelogram in is shown in figure 1 with the dimensions height = 7 and base = 13,
Area of the parallelogram  = 13 × 7 = 91 unit²

Now,
A pentagon is shown in figure 2,
Area of the pentagon = 5 [1/2 × height × side]
                                 = 5 [1/2 × 5 × 6]

                                 = 75 suqare units.

Thus, the required area of the parallelogram and pentagon is 91 unit² and 75 unit².

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The equation of sphere is (x + 4)² + (y - 2)² + (z - 6)² = 49 and the intersection is a circle of radius √33 on yz - plane.

A sphere, like a ball, is defined as a perfectly spherical geometrical entity in three dimensions.

the general equation of a sphere is (x – a)² + (y – b)² + (z – c)² = r² where (a, b, c) is the centre of the sphere and r is the radius of the sphere.

Given, the centre of the sphere C(−4, 2, 6) and radius of sphere 7 units

Equation of sphere: (x - (-4))² + (y - 2)² + (z - 6)² = 7²

                                   (x + 4)² + (y - 2)² + (z - 6)² = 49

It is given that the sphere is intersecting with yz - plane which means x = 0

so, (0 + 4)² + (y - 2)² + (z - 6)² = 49

                     (y - 2)² + (z - 6)² = 33

The intersection is a circle of radius √33 on yz - plane.

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The only one carton of pear is not enough because the sum of both Jo and Max requirement is max than the one.

There is only one carton of pear.

Jo want to buy 3/4 of it, and Max to buy 1/3 of it.

To check whether one carton of pear is enough for both Jo and Max we firstly add the part of Jo and Max to find the total pear they want. Then we check the one pear is enough y subtracting.

Now finding the total pear that Jo and Max want:

Total Pear they want = Jo want + Max want

Total Pear they want = 3/4 + 1/3

To add we equal the denominator.

Multiply and divide by 12 on both number

Total Pear they want = 3/4 × 12/12 + 1/3 × 12/12

Total Pear they want = 9/12 + 4/12

Total Pear they want = (9 + 4)/12

Total Pear they want = 13/12

Total Pear they want = 1 1/12

As we can see that the sum of both Jo and Max requirement is max than the one pear. So the only one carton of pear is not enough.

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DeAndre should select the shape that satisfy the equation -

r(2h + r) = (190/π).

Given is that DeAndre has 190 square inches of plastic to make a cylindrical bird feeder.

He should choose the design whose total surface area is equivalent to 190 square inches. We can write the total surface area as -

2πrh + πr² = 190

πr(2h + r) = 190

r(2h + r) = (190/π)

Therefore, DeAndre should select the shape that satisfy the equation -

r(2h + r) = (190/π).

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Answer:If at the end of any year a car is worth 5% less than what it was worth at the beginning of the year, we can say that the car's value decreases by a factor of 0.95 (1 - 0.05) every year.

To find the car's value in December 2009, we can use the formula:

Car value at end of year = Car value at beginning of year * (1 - 0.05)^(number of years)

Plugging in the given values, we get:

Car value in December 2009 = 10,000 * (1 - 0.05)^1 = 9,500

So the car's value in December 2009 is 9,500 dollars.

Step-by-step explanation:

Answer:

9500

Step-by-step explanation:

If you didn't understand that one (which I personally found a little complicated) the answer can be found like this.

1. You firstly find the decrease which is 5/100 × 10000 (5/100 can also be written as 5%) and the answer will be 500

2. Then you take the original value and you minus the loss in worth of the car —> 10000-500 = 9500

The required multiplicative rate in the given function is 3 / 4.

Option B is correct.

The function which is in format f(x) =a^x  where a is constant and x is variable,  the domain of this exponential function lies   (-∞, ∞).

Here,

From the table of the exponential functions,

The multiplicative factor is given as,

K = y₂/y₁

K =  [9 / 8] / [3/2]

K = 3 / 4

Thus, the required multiplicative rate in the given function is 3 / 4. Option B is correct.

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The translation needed to obtain the graph of g(x) = [tex]9^{x}-4[/tex] from the graph of f(x) = [tex]9^{x}[/tex] is a shift down 4 units.

Graph is a type of data structure that is used to store and organize data in a visual representation. It consists of nodes, which store the data, and edges that connect the nodes. Graphs can be used to represent networks, relationships between different entities, or even mathematical equations. Graphs are versatile and can be used in many different applications, from engineering to data science. Graphs are also used to represent complex data structures and are often used to simplify and organize data for easier analysis.

This is because subtracting 4 from  [tex]9^{x}[/tex] is the same as shifting the graph of f(x) down 4 units on the y-axis, resulting in the graph of g(x).

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By using the box plots, each statistical value should be completed as follows;

Mean: cannot be determined.

Median: equal for data sets X and Y.

Range: greater for data set X.

Interquartile range: greater for data set Y.

Mathematically, the range of a data set can be calculated by using this formula;

Range of X = Highest number - Lowest number

Range of X = 65 - 20

Range of X = 45.

Range of Y = Highest number - Lowest number

Range of Y = 55 - 20

Range of Y = 35.

Mathematically, interquartile range (IQR) of a data set and it is typically calculated as the difference between the first quartile (Q₁) and third quartile (Q₃):

Interquartile range (IQR) of X = Q₃ - Q₁

Interquartile range (IQR) of X = 55 - 35

Interquartile range (IQR) of X = 20.

Interquartile range (IQR) of Y = Q₃ - Q₁

Interquartile range (IQR) of Y = 50 - 25

Interquartile range (IQR) of Y = 25.

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[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{ASSUMING:}[/tex]

[tex]\mathsf{\dfrac{3}{2}(4x + 6)}[/tex]

[tex]\huge\textbf{If so, distribute \boxed{\rm{\bf \dfrac{3}{2}}} within the}\\\\\huge\textbf{parentheses}[/tex]

[tex]\mathsf{\dfrac{3}{2}(4x + 6)}[/tex]

[tex]\mathsf{= \dfrac{3}{2}(4x) + \dfrac{3}{2}(6)}[/tex]

[tex]\mathsf{= \dfrac{3}{2}\times \dfrac{4}{1}x + \dfrac{3}{2} \times \dfrac{6}{1}}[/tex]

[tex]\mathsf{= \dfrac{3\times4}{2\times1}x +\dfrac{3\times6}{2\times1}}[/tex]

[tex]\mathsf{= \dfrac{12}{2}x +\dfrac{18}{2}}[/tex]

[tex]\mathsf{= 6x + 9}[/tex]

[tex]\huge\textbf{Therefore your answer should be:}[/tex]

[tex]\huge\boxed{\mathsf{6x + 9}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

Answer:

Step-by-step explanation:

219y+608=−121156 219y+608=−121156 219y+608=−121156 v 219y+608=−121156v219y+608=−121156vvv219y+608=−121156=  365

Answer:

d = 114t

Step-by-step explanation:

distance = rate * time

therefore, rate = distance/time

684 ft in 6 sec = 114 ft per sec (this is the 'rate')

so the distance can be calculated by multiplying time in seconds to get distance in feet

d = 114t

The smallest sample standard deviation

Confidence Level: 95%; Confidence Interval: 42 to 48.

Assume that x  ±   y represents the confidence interval at P% for the values of some parameter.

In other words, the parameter's projected value is P% likely to fall within the range.

[x - y, x + y]

Data on how quickly a brand-new iron skillet rusts were gathered by four research teams using various techniques.

Assume that everyone is in agreement with the sample size and sample mean (in days).

Choose the team with the smallest sample standard deviation using the (confidence level; confidence interval) pairs below.

Then we have

= 48 - 42 = 6

Then we have

= 6/2

=3, which is smallest

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The question you have uploaded is seems to be incomplete, the complete question is

A. Confidence Level: 99.7%; Confidence Interval: 40 to 40

B. Confidence Level: 95%; Confidence Interval: 40 to 50

C. Confidence Level: 68%; Confidence Interval: 43 to 47

D. Confidence Level: 95%; Confidence Interval: 42 to 48