for f(x)=2x-3x^2, evaluate f(-3)

Answer:

answer down below <3

Step-by-step explanation:

[tex]Hello[/tex] [tex]There![/tex]

There is simple no way, for me to answer this.

Because, this answers doesn't exist. :)

[tex]AnimeVines[/tex]

[tex]\large \mathfrak{Solution : }[/tex]

Answer:

35% of 150=52.5

20% of 50=10

10% of 20=2

45% of 200=90

Answer:

Step-by-step explanation:

1) What will you get if you add a number to 3?

2) Cost of a pen is $2. What is the cost of x pens?

3) y less than 5

4) What is quotient of n and 4?

5) What is the sum of 10 and t ?

6) Product of 3 and s

1*a sum of number and three

2*the product of two and a number

3*the difference of a number and five

4*the ratio of number and four

5*a sum of number and ten

6*the product of a number and three

O Hope it helps*

Answer:

-11

Step-by-step explanation:

If you know how to play golf, you'll know that when you see a negative sign infront of a number, thats good.

So starting off with -6 and -5. That makes -11

Take -11 and +1, thats -10

Take -10 and -3 thats -13

Take -13 and +2 thats -11

Step-by-step explanation:

don't know man I don't know it

Answer:

385.3369[tex]\pi[/tex]

Step-by-step explanation:

385.3369[tex]\pi[/tex]

9514 1404 393

Answer:

  x = 1

Step-by-step explanation:

The x-intercept of any log function is x=1.

Answer:

your answer is (B) 2 2/9

I hope it's helps you

When we multiply two negative numbers, one always gets a positive number.

(-)×(-)= +

Hope it helps

[tex]\displaystyle \lim_{x\to 0}\left(\frac{2x\ln \left(1+3x\right)+\sin \left(x\right)\tan \left(3x\right)-2x^3}{1-\cos \left(3x\right)}\right)[/tex]

Both the numerator and denominator approach 0, so this is a candidate for applying L'Hopital's rule. Doing so gives

[tex]\displaystyle \lim_{x\to 0}\left(2\ln(1+3x)+\dfrac{6x}{1+3x}+\cos(x)\tan(3x)+3\sin(x)\sec^2(x)-6x^2}{3\sin(3x)}\right)[/tex]

This again gives an indeterminate form 0/0, but no need to use L'Hopital's rule again just yet. Split up the limit as

[tex]\displaystyle \lim_{x\to0}\frac{2\ln(1+3x)}{3\sin(3x)} + \lim_{x\to0}\frac{6x}{3(1+3x)\sin(3x)} \\\\ + \lim_{x\to0}\frac{\cos(x)\tan(3x)}{3\sin(3x)} + \lim_{x\to0}\frac{3\sin(x)\sec^2(x)}{3\sin(3x)} \\\\ - \lim_{x\to0}\frac{6x^2}{3\sin(3x)}[/tex]

Now recall two well-known limits:

[tex]\displaystyle \lim_{x\to0}\frac{\sin(ax)}{ax}=1\text{ if }a\neq0 \\\\ \lim_{x\to0}\frac{\ln(1+ax)}{ax}=1\text{ if }a\neq0[/tex]

Compute each remaining limit:

[tex]\displaystyle \lim_{x\to0}\frac{2\ln(1+3x)}{3\sin(3x)} = \frac23 \times \lim_{x\to0}\frac{\ln(1+3x)}{3x} \times \lim_{x\to0}\frac{3x}{\sin(3x)} = \frac23[/tex]

[tex]\displaystyle \lim_{x\to0}\frac{6x}{3(1+3x)\sin(3x)} = \frac23 \times \lim_{x\to0}\frac{3x}{\sin(3x)} \times \lim_{x\to0}\frac{1}{1+3x} = \frac23[/tex]

[tex]\displaystyle \lim_{x\to0}\frac{\cos(x)\tan(3x)}{3\sin(3x)} = \frac13 \times \lim_{x\to0}\frac{\cos(x)}{\cos(3x)} = \frac13[/tex]

[tex]\displaystyle \lim_{x\to0}\frac{3\sin(x)\sec^2(x)}{3\sin(3x)} = \frac13 \times \lim_{x\to0}\frac{\sin(x)}x \times \lim_{x\to0}\frac{3x}{\sin(3x)} \times \lim_{x\to0}\sec^2(x) = \frac13[/tex]

[tex]\displaystyle \lim_{x\to0}\frac{6x^2}{3\sin(3x)} = \frac23 \times \lim_{x\to0}x \times \lim_{x\to0}\frac{3x}{\sin(3x)} \times \lim_{x\to0}x = 0[/tex]

So, the original limit has a value of

2/3 + 2/3 + 1/3 + 1/3 - 0 = 2

Answer:

The greatest common factor of 64 and 72 is 8.

Step-by-step explanation:

Q1 . (f+g)(x) = f(x) + g(x)

=4x-4 +2x^2 -3x

= 2x^2 + x -4

Q2. (f-g)(x) = f(x) - g(x)

= 2x^2−2 - (4x+1)

= 2x^2 -2 -4x -1

= 2x^2 - 4x -3

Q3. h(x)=3x−3 and g(x)=x^2+3

(h.g)(x) = h(x) × g(x)

= (3x-3) × (x^2 + 3)

=3x^3 -3x^2 + 9x -9

Q4.f(x)=x+4 and g(x)=x+6

(f/g)(x) = f(x) ÷ g(x)

= x+4 / x+6

the domain restriction is x>-6

x<-6

x doesn't equal (-6)

If the two function f(x) and g(x) are to be combined, use basic arithmetic rules,

(f + g)(x) = f(x) + g(x)

(f - g)(x) = f(x) - g(x)

[tex](\frac{f}{g})(x)=\frac{f(x)}{g(x)}[/tex]

(f . g)(x) = f(x) × g(x)

Question 1

f(x) = 4x - 4 and g(x) = 2x² - 3x

[tex](f+g)(x)=f(x)+g(x)[/tex]

Therefore, [tex](f+g)(x)=(4x-4)+(2x^2-3x)[/tex]

                                   [tex]=2x^2+x-4[/tex]

Question 2

f(x) = 2x² - 2 and g(x) = 4x + 1

Since, (f - g)(x) = f(x) - g(x)

Therefore, (f - g)(x) = (2x² - 2) - (4x + 1)

                               = 2x² - 2 - 4x - 1

                               = 2x² - 4x - 3

Question 3

h(x) = 3x - 3 and g(x) = x² + 3

Since, (h - g)(x) = h(x) - g(x)

Therefore, (h - g)(x) = (3x - 3) - (x² + 3)

                                = 3x - 3 - x² - 3

                                = -x² + 3x - 6

Question 4

F(x) = x + 4 and g(x) = x + 6

Since, [tex](\frac{f}{g})(x)=\frac{f(x)}{g(x)}[/tex]

Therefore, [tex](\frac{f}{g})(x)=\frac{x+4}{x+6}[/tex]

Learn more,

https://brainly.com/question/7447002

Y = -9 *10/3 = -30

Minus of thirty (-30) is right answer

[tex]2 = \frac{ - 3}{10y} - 7 \\ \\ 2 + 7 = \frac{ - 3}{10y} \\ \\ 9 = \frac{ - 3}{10y} \\ \\ \frac{9 \times 10}{ - 3} = y \\ \\ \frac{ - 90}{3} =y \\ \\ - 30= y \\ \\ y = - 30[/tex]

Answer:

-3

Step-by-step explanation:

Bring -2 to the other side and A to the other side

-2 Become 2 because of flipping

And A becomes -A because of flipping

2-2+3=-A

Flip the whole equation to avoid confusion

-A=2-2+3

-A=+3

Bring the minus sign to the other side,

A=-3

-3 -2 +3 = - 2

Which make the statement correct.

I hope this explanation helps, dont hesitate to ask for any question.Mark me as brainliest is appreciated.Tq!!

Answer: A = -3

Step-by-step explanation:

A - 2 + 3 = -2

...............+2..............

..... A + 3 = 0

................-3..............

............ A = -3

Answer:

-5

Step-by-step explanation:

put the 10 on the other side of the = wich will change it to -10 then do -10/2 and x2/2 to get x=-5

Answer: 1,4

Step-by-step explanation:

2(5x) = 14

10x = 14

x = 14/10

x = 1.4

Answer:

the value of x in 2 (5 ^ x) = 14 is:

c. 1.21

Step-by-step explanation:

Answer:

4190 m

Step-by-step explanation:

3500-560=2940

2940+1250=4190

Answers:

===========================================================

Explanation:

Straight angles are always 180 degrees in measure.

The two smaller angles shown add up to 180

(angle RQS) + (angle SQT) = angle RQT

(9x+7) + (6x+8) = 180

(9x+6x) + (7+8) = 180

15x+15 = 180

15x = 180-15

15x = 165

x = 165/15

x = 11

From here, we then know that,

Note how the two results add to 106+74 = 180 to help confirm the answers.

is 4.23 less than 4.135

its not its larger

Answer:-10

Step-by-step explanation:

Formula for mid point is :

Mid point = ( (x1+x2)÷2 , (y1+y2)÷2) )

So, X1 = 4

X2 = X

Y1 = -2

Y2 = y

Now, use the formula

(-3,1) = ( (4 + x)÷2 , (-2+y)÷2) )

Now divide the sides for yourself to solve for midpoint for X and y separately

-3 = (4+x) ÷ 2 and 1 = (-2+y) ÷ 2

This is because 3 is the x coordinate of the mid point of A and B , so we equate it to (4+x) ÷ 2 because this expression basically gives us the x coordinate of mid point of A and B. So we already have the x coordinate of midpoint which is -3 so we can use this to find X coordinate of point B

So then we solve it by multiplying the 2 with -3 which gives -6

-6 = 4+X

Shift 4 on the other side and it will become negative 4

-6-4 = X

X = -10

Answer:

B (-10,4)

Step-by-step explanation:

Given A (4,-2) and midpoint M (-3,1) we can find equation of the line

y = mx +b

slope m = raise / run

m = (y1 - y2) / (x1 - x2)

m = (-2 - 1) / (4 - -3)

m = -3 / 7 = -3/7

given the midpoint M, then point B (x,y) must have the same length and slope as AM. So point B must have twice the rise and twice the run.

Slope was -3/7 so segment AB must be 2(slope) = -6/14, so from point A, point B will be from A (4,-2)

raise = y1 - y2 = -6

-2 - y2 = -6

-y2 = -6 + 2

y2 = 4

run = x1 - x2 = 14 = 4 - x2

14 - 4 = -x2

x2 = -10

Answer:

If you have a calculator with a "Y^X" function, you can raise 27 to the (1/3) power to get the cube root. Or, take the logarithm of 27, divide it by 3, and then find the anti log. That is, find the base 10 log of 27, divide it by three, and then compute 10 ^ that number. (Or of course you can use the base e log and raise e to the number.)

If you are willing to get into complex numbers, you can find that there are actually three cube roots of 27. One of them is 3. To find the other two, use de Moivre's formula (from Wikipedia):

If z is a complex number, written in polar form as

then the n nth roots of z are given by

where k varies over the integer values from 0 to n − 1.

This formula is also sometimes known as de Moivre's formula.

This leads to the two complex roots,

3 x ( (cos 120 degrees) + i x sin(120 degrees) ) and

3 x ( (cos 240 degrees) + i x sin(240 degrees) ).

These work out to be approximately:

3 x (-0.5 + i x 0.866) and

3 x (-0.5 - i x 0.866).

Step-by-step explanation:

Answer:

5).

According to the question,

CD+DE=CE

2+13=2x-3

15=2x-3

15+3=2x

18=2x

18/2=x

8=x

6).

According to the question,

AB+BC=AC

5x-16+3x-6=2x+20

8x-22=2x+20

8x-2x=20+22

6x=44

x=44/6

x=7.33

Step-by-step explanation:

......

Step-by-step explanation:

DE = 13

2 + 2x - 3 = 13

2x - 1 = 13

2x = 12

x = 12/2

x = 6

0.054227406110177... is an irrational number.

There are only two types of number in which all the other subsets of numbers resides they are real numbers and imaginary numbers.

According to the statement given we have to determine whether  0.054227406110177... is rational or irrational.

We know rational numbers are of two types one which has a repeating pattern after the decimal so after that 1 repeating cycle we terminate the digits after it and write.

Next type of rational number which has a recurring pattern means a single digits repeats so we terminate every digit except one after the decimal place and write.

0.054227406110177... here we neither see repeating pattern nor do we see terminating pattern so this is an irrational number.

learn more about irrational number here :

https://brainly.com/question/4031928

#SPJ2

Answer:

the top one is 30 the second one is 60.22 the third one is 66.7 the forth one is 59.8