For parts of the free-response question that require calculations, clearly show the method used and the steps involved in arriving at your answers. You must show your wo
your answer. Examples and equations may be included in your answers where appropriate.
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H:O:H
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Answer the following questions about CH, and CC14. The Lewis electron-dot diagrams for molecules of the compounds are shown above.
(a) Which compound has the higher boiling point? Justify your answer. The type(s) of intermolecular force(s) in both substances should be included in your answer.

The mathematical representation of Charles's Law is V1/T1 = V2/T2.

What do you mean by Charles's Law?

Charles's Law, also known as the Law of Volume-Temperature, states that the volume of a gas is directly proportional to its temperature when pressure is held constant. In other words, as the temperature of a gas increases, its volume will also increase. It was first established by physicist Jacques Charles in 1787.

The mathematical representation of Charles's Law states that the ratio of the initial volume (V1) to the initial temperature (T1) is equal to the ratio of the final volume (V2) to the final temperature (T2). This means that, as the temperature of a gas increases, its volume will increase proportionally.

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The mass of trifluoroacetic acid that contains 83.3 g of oxygen is approximately 482.6 g.

First we need to use the molar mass and stoichiometry of the compound.

The molar mass of trifluoroacetic acid is:

(2 x 12.01 g/mol) + (1 x 19.00 g/mol) + (3 x 19.00 g/mol) + (2 x 16.00 g/mol) = 114.02 g/mol

The molar mass of oxygen is 16.00 g/mol.

From the chemical formula of trifluoroacetic acid (C2HF3O2),

we can see that each mole of the compound contains 2 moles of carbon, 1 mole of hydrogen, 3 moles of fluorine, and 2 moles of oxygen.

Using this information, we can set up a proportion to find the mass of trifluoroacetic acid that contains 83.3 g of oxygen:

(83.3 g O2) x (1 mol O2/16.00 g O2) x (1 mol C2HF3O2/2 mol O2) x (114.02 g C2HF3O2/1 mol C2HF3O2) = 482.6 g

Therefore, the mass of trifluoroacetic acid that contains 83.3 g of oxygen is approximately 482.6 g.

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Molecular formula S₂F₁₀ for the compound with the empirical formula SF₅ and formula weight 254.1 a.m.u.

Molecular formula for a compound with the empirical formula CH₂O and formula weight 180.156 a.m.u: C₆H₁₂O₆.

Molecular Formula:

Molecular formulas use subscripts that give the actual number of atoms of each type in the molecule of a compound. The molecular formula is related to the molecular weight in grams, which is a simple integer multiple of the mass of the corresponding empirical formula.

Empirical Formula:

The empirical formula of a compound is the formula for a substance written in terms of the smallest integer exponent. The empirical formula provides information about the atomic number ratio of a compound. The percent composition of a compound leads directly to the empirical formula.

Now,

The molecular formula of a compound with a given empirical formula can be calculated as:

molecular formula = (empirical formula)n

The molecular formula for this compound is: n = 254.1

⇒ 127n = 254.1

⇒ n = 2

Formula = (SF5)₂ = S2F10

⇒ (CH2O)n = 180.156amu 44 {41 24424} = 180. 156

⇒ (30)n = 180.156

⇒ n = 6

Molecular formula = (CH2O)₆ = C6H12O₆

Molecular formula of a compound with empirical formula CH2O and formula weight 180.156 amu: C₆H₁₂O₆.

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Answer:

The molecular formula of the compound with the empirical formula SF5 and a formula mass of 254.1 amu is S2F10. This can be determined by dividing the formula mass by the empirical formula mass (254.1/48.3 = 5.26) and then multiplying the elements of the empirical formula by this value (S x 5.26 = S2, F x 5.26 = F10).

Answer:  i answerd 34cu i got coreect hopefully you get it corecct!!!!!!!

Explanation:

Ml without changing the temperature,The pressure of the gas is [tex]16.8atm[/tex]

The pressure of a gas is related to its volume and temperature by the ideal gas law:

PV = nRT

n is the number of moles of gas, P is the pressure, V is the volume, R is the ideal gas constant, and T is the temperature.

Since we know the initial pressure, volume, and temperature, we can rearrange the equation to solve for n:

[tex]n =\frac{ PV}{RT}[/tex]

Now that we know the amount of gas, we can use the same equation to calculate the pressure when the gas is compressed to 10. Ml without changing the temperature:

[tex]P = \frac{nRT}{V}\\\\P = (\frac{PV}{RT}) * (\frac{RT}{V})\\\\P = (2.0 atm * 200. Ml) / (0.08206 L atm K ^{-1} mol^{-1} * 298.15 K) \\\\P = 16.8 atm[/tex]

Therefore the pressure of the gas is [tex]16.8atm[/tex]

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Answer:

C.

Explanation:

in CO there are 2 capital letters,but in Co there is 1 capital letter because its an element.

Answer: c. Co is an element and CO is not

Explanation:

Co and CO are two different chemical substances. Co is the metal element named cobalt whereas CO is the inorganic compound i.e. carbon monoxide.

Co is a chemical element with atomic no. 27 and CO is an inorganic compound consisting of atoms of carbon and oxygen.

co is a metal whereas CO is a gas.

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When water is carefully dropped onto the surface of a penny, it can form a dome before spilling over the small lip around the penny's perimeter. Rubbing alcohol can also accumulate, but it will spill before forming a well-rounded dome.

Cohesive forces are powerful, but not invincible. The force of gravity on the water molecules will eventually overcome the cohesive forces as a water drop builds up and out, usually bulging over the sides of the penny. The "skin" will rupture, allowing all the water to escape.

When the drops of water you add to the penny reach the penny's edge, the cohesion and surface tension of water become apparent.

Thus, When the water reaches the edge, a bubble or dome of water begins to form on top of the penny.

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The F-F bond energy is 293 kJ/mol.

Bond Energy also known as  simply bond enthalpy, is described as a quantity that offers insight into the strength of a chemical bond.

ΔH = ∑(bond energies of bonds broken) - ∑(bond energies of bonds formed)

In this reaction above one H-H bond and one F-F bond are broken, and two H-F bonds are formed. Thus, the enthalpy change can be shown  as:

ΔH = (1 × H-H bond energy) + (1 × F-F bond energy) - (2 × H-F bond energy)

Which gives us :

-269 kJ/mol = (1 × 432 kJ/mol) + (1 × F-F bond energy) - (2 × 565 kJ/mol)

Therefore, the F-F bond energy = [1 × (432 kJ/mol) + 2 × (565 kJ/mol)] - 269 kJ/mol = 293 kJ/mol

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Answer:

no answer

Explanation:

I wish I could help you

In the electromagnetic spectrum,  the energy of a photon of wavelength X₂ = 0.152 nm is 3.021×10[tex]^-35[/tex] m.

The electromagnetic  radiation are composed of electromagnetic waves which are synchronized oscillations of electric and magnetic fields . They are created due to change which is periodic in electric as well as magnetic fields.

In vacuum ,all  electromagnetic waves travel at  same speed that is with the speed of air.The position of an electromagnetic wave in an electromagnetic spectrum is characterized by it's frequency or wavelength.These are emitted by electrically charged particles which undergo acceleration and subsequently interact with other charged particles.

Where energy is given by equation  as ,E= hc/λ= 6.626×10[tex]^-34[/tex]×3×10⁸/0.152×10[tex]^-9[/tex]=130.77×10[tex]^-17[/tex] J.

Thus, the energy of a photon of wavelength X₂ = 0.152 nm is 3.021×10[tex]^-35[/tex] m.

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The formula of the original hydrate is CuSO4 · 5H2O, and its name is copper (II) sulfate pentahydrate.

First we need to use the mass information provided in the problem and the molar masses of the relevant compounds.

First, we can calculate the mass of water that was present in the original hydrate:

Mass of water = Mass of hydrate - Mass of anhydrous salt

Mass of water = 2.50 g - 1.59 g

Mass of water = 0.91 g

Next, we can calculate the number of moles of anhydrous copper (II) sulfate that remained after heating:

Number of moles of anhydrous salt = Mass of anhydrous salt / Molar mass of anhydrous salt

Molar mass of anhydrous copper (II) sulfate = (1 x 63.55 g/mol) + (1 x 32.06 g/mol) + (4 x 16.00 g/mol) = 159.61 g/mol

Number of moles of anhydrous salt = 1.59 g / 159.61 g/mol

Number of moles of anhydrous salt = 0.00997 mol

We can then calculate the number of moles of copper (II) sulfate that were present in the original hydrate:

Number of moles of copper (II) sulfate = Number of moles of anhydrous salt

Number of moles of copper (II) sulfate = 0.00997 mol

Finally, we can use the mass of copper (II) sulfate and the number of moles of copper (II) sulfate to determine the formula and name of the original hydrate. The formula of the hydrate will be in the form of CuSO4 · xH2O, where x is the number of water molecules per formula unit.

The molar mass of CuSO4 is (1 x 63.55 g/mol) + (1 x 32.06 g/mol) + (4 x 16.00 g/mol) = 159.61 g/mol.

The mass of CuSO4 in the original hydrate is 2.50 g - 0.91 g = 1.59 g.

The number of moles of CuSO4 in the original hydrate is therefore 1.59 g / 159.61 g/mol = 0.00997 mol.

The ratio of moles of water to moles of CuSO4 in the original hydrate is:

x = (moles of water) / (moles of CuSO4)

x = (0.91 g / 18.02 g/mol) / 0.00997 mol

x = 5.06

Therefore, the formula of the original hydrate is CuSO4 · 5H2O, and its name is copper (II) sulfate pentahydrate.

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Answer: c – Reactant 1

Explanation:

Since HNO3, (Nitric Acid), is an acid, that leaves Mg(OH)2 to be the Base in the reaction.

Hence the answer is Reactant 1

Answer:

it's c

Explanation:

maybe...I don't know how I works it out but it is c

The wavelength of radio waves with a frequency of 93.5 MHz is equal to 3.2 meters

Wavelength is a measure of the distance between two consecutive points in a wave. It is determined by the speed of the wave and its frequency, which is the number of waves that pass a point in a given period of time. Wavelength is usually measured in meters, and is sometimes expressed as the number of waves that pass a point in one second. Wavelengths can range from fractions of a nanometer to many kilometers.

The wavelength of radio waves is calculated using the following formula: wavelength (λ) = velocity (c) / frequency (f).

The velocity of radio waves in air is approximately 300,000,000 m/s.

Therefore, the wavelength of radio waves with a frequency of 93.5 MHz is equal to:

λ = 300,000,000 / 93,500,000 = 3.2 meters

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The half life is 2.9 * 10^-3 s

A first-order reaction is a chemical reaction in which the rate of reaction is directly proportional to the concentration of one of the reactants. This means that the rate of reaction increases as the concentration of the reactant increases.

The mathematical expression for a first-order reaction is:

Rate = k[A]

where Rate is the rate of the reaction, k is the rate constant, and [A] is the concentration of the reactant that the reaction rate depends on. This equation is also known as the rate law for a first-order reaction.

Half life of a first order reaction;

0.693/k

k = Decay constant

Half life = 0.693/2.35×10^2

= 2.9 * 10^-3 s

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When the grain size is reduced to 0.160 pm, the strength of mild steel is 1851 MPa.There are a number of variables that can affect mild steel's strength, including the grain size, which is controllable.

We may use the above information to determine the constants in the Hall-Petch equation: The strength of mild steel at grain size d1 = 17.43 pm is 1 = 232.9 MPa. Mild steel has a strength of 2 = 874.2 MPa when the grain size is d2 = 0.80 um (or 800 nm). This is the formula for the Hall-Petch equation: = o + Kd(-1/2). We can use the following equation to determine K: K = (σ2 - σ1)(d2^(1/2) - d1^(1/2))^(-1) (-1) When the values are plugged in, we get the following result: K = (874.2 - 232.9)(800(1/2) - 17.43(1/2))(-1) = 276.3 MPa um(1/2) We can use the following equation to determine o: σo = σ1 - Kd1^(-1/2) Plugging in the numbers yields the following result: o = 232.9 - 276.3(17.43(-1/2)) = 62.28 MPa. The Hall-Petch equation's constants are K = 276.3 MPa um(1/2) and o = 62.28 MPa. Hence, the power of the  yield strength of mild steel at 0.160 pm grain size is 1851 MPa.

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The boys could cover the end of the test tube with a balloon to capture the escaping gas. Therefore, the correct option is option C.

A chemical reaction is the chemical change from one set of chemical components into another. Chemical reactions are changes that solely affect the locations of electrons inside the formation as well as breakdown of chemical bonds that link atoms, and without any modification to the nuclei, and therefore are frequently represented using a chemical equation.

Nuclear chemistry is the branch of chemistry that studies the chemical interactions of unstable especially radioactive materials, which can result in both electronic plus nuclear alterations. The boys could cover the end of the test tube with a balloon to capture the escaping gas.

Therefore, the correct option is option C.

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Answer:

The energy released as the mercury vapor cools from 356°C to 25°C can not be determined from the information provided. The amount of energy released depends on various factors such as the heat capacity of the substance, the mass of the substance, and the specific conditions in which it is cooling.

Explanation:

Answer:

807 cal

Explanation:

To determine the energy released as the mercury vapor cools from 356°C to 25°C, we need to determine the change in its internal energy. The internal energy of a substance is given by the equation ΔU = q + w, where ΔU is the change in internal energy, q is the heat absorbed or released by the substance, and w is the work done by the substance.

In this case, the heat absorbed by the mercury as it is heated from 25°C to 356°C is 110 cal, and the heat absorbed to vaporize the mercury is 697 cal, so the total heat absorbed is 110 + 697 = 807 cal. As the mercury vapor cools from 356°C to 25°C, it releases heat, so the heat released can be calculated as q = -807 cal.

Since no work is done in this process (the substance is not expanding or contracting against an external pressure), the work term can be ignored. Therefore, the change in internal energy of the mercury vapor as it cools from 356°C to 25°C is ΔU = q = -807 cal.

So, the mercury releases 807 cal of energy as it cools from 356°C to 25°C.


Tell me if you still confuse

ALLEN

In A option1 is correct

What is Acid ?

In chemistry, an "acid" is a substance that donates hydrogen ions (H+) to another substance, or accepts electrons from another substance. Acids are typically characterized by a sour taste, the ability to dissolve some metals, and a pH value of less than 7 in aqueous solutions. They are often used as reagents in chemical reactions, and are important in many biological processes. Common examples of acids include hydrochloric acid (HCl), sulfuric acid (H2SO4), and acetic acid (CH3COOH). Acids can be classified as either strong or weak, depending on the extent to which they dissociate in water, and can react with bases to form salts and water in a process called neutralization.

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A key advantage of PDF is that it has excellent tools for creating and editing images. It is true.

What is a PDF?

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According to the recipe, to make 4 moles of lemonade, you use 2 moles of water, one mole of sugar and one mole of lemon juice, expressed in grams:

2 water  + sugar + lemon juice = 4 lemonade

2*(236.59) + 225g + 257.83g  = 4*(719.42)g

   473.18g + 225g + 257.83g = 2877.68g

So for every 2877.68g of lemonade made, they use 473.18g of water, 225g of sugar, and 257.83g of lemon juice.

You know that they made a batch of 2050.25g, so to detect the limiting reactant, first, you have to calculate, in theory, how much of each ingredient you need to make the given amount of lemonade:

Use cross multiplication

Water:

2877.68g lemonade → 473.18g water

2050.25g lemonade → X= (2050.25*473.18)/2877.68= 337.12g water

Following the recipe, to elaborate 2050.25g of lemonade, you need to use 337.12g of water.

Sugar:

2877.68g lemonade → 225g sugar

2050.25g lemonade → X= (2050.25*225)/2877.68= 160.30g sugar.

To elaborate 2050.25f of lemonade you need to use 160.30g of sugar.

Lemon juice:

2877.68g lemonade → 257.83g lemon juice

2050.25g lemonade → X= (2050.25*257.83)/2877.68= 183.69g lemon juice.

To elaborate 2050.25f of lemonade you need to use 183.69g lemon juice.

Available ingredients vs. theoretical yields for 2050.25g of lemonade:

Water 946.36 g → 337.12g

Sugar 196.86 g → 160.30g

Lemon Juice 193.37 g → 183.69g

The lemon juice will be the first ingredient to be used up, there will be a surplus of water and sugar.

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Answer:

27 moles of sulfuric acid are produced.

Explanation:

The equation for the reaction between nitric acid (HNO3) and sulfuric acid (H2SO4) to form nitration sulfate (HNO3) and water (H2O) is:

2 HNO3 + H2SO4 → H2SO4 + 2 H2O

For every 2 moles of nitric acid that react, 1 mole of sulfuric acid is produced. So, when 54 moles of nitric acid are consumed, 54/2 = 27 moles of sulfuric acid are produced.

Add together all the atomic masses of the individual atoms to determine the molarity of the a compound with numerous atoms. Ca(NO3)2 has a molar mass of 164.1 g/mol.

The density in grams with one molar (6.02 x 1023 molecules) of a metal is its molar mass. Therefore, in the majority of circumstances, all you need to do is look at an element's atomic mass (atoms) on the periodical table to determine its molar mass. Keep in mind that it is the number that is listed beneath the element's name and symbol.

The mass in kilograms of one mole of an substance is its molar mass. As this video demonstrates the computed molar mass can then be used to translate between mass and the quantity of moles in the substance.

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If you use 0.600 mol of gas, the gas will have a new volume of 13.2 L.

The amount of space a three-dimensional item takes up is measured by its volume. Usually, it is expressed in terms of liters (L), cubic meters (m3), or cubic feet (ft3).

The volume of the gas is directly proportional to the amount of gas (measured in moles) present, presuming constant temperature and pressure. Avogadro's Law describes this connection.

This law allows us to establish a proportion:

Amount1 / Volume1 = Volume2 / Amount2

If Volume2 is the new volume we wish to find, Volume1 is the initial volume, Amount1 is the initial amount of gas (in moles), and Volume2 is the new volume (in moles).

By entering the specified values, we obtain:

Volume2 / 0.600 mol = 1.1 L / 0.05 mol

For Volume 2, we solve as follows:

Volume2 = 1.1 liters / 0.05 mol / 0.600 mol = 13.2 liters

Therefore, if you use 0.600 mol of gas, the new volume of the gas will be 13.2 L.

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Answer: 1 L

Explanation: M1V1 = M2V2

Given :

M1 =15  M

V1=0.2 L

M2=3  M

V 2= ?

15 × 0.2 = 3V2

​Thus, V 2=1  L

The mass of the HgO is 434 g.

Stoichiometry allows us to calculate the amount of each reactant and product involved in a reaction based on its chemical formula. This is done by using the balanced chemical equation for the reaction, which shows the ratio of moles of each reactant and product involved in the reaction.

The reaction equation is; 2HgO(s)→Hg(l)+O2(g).

The number of moles of the oxygen is; 32.1g/ 32 g/mol

= 1 mole

We have to know form the reaction equation that;

2 moles of the HgO produces 1 mole of oxygen

x moles of HgO would produce 1 moles of oxygen

x = 2 moles

Mass of the compound = 2 moles * 217 g/mol

= 434 g

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The compound with half life of 17 minute have the rate constant of 0.040 minutes⁻¹ will take  to reach  to 12.5%  of  the initial amount .

Half life of a sample is the time required to consume half of its initial amount in a reaction.

For a first order reaction,

the rate constant k  = 1/t ln W0/Wt

where t is the time of consumption, W0 be the initial amount and Wt be the amount after time t.

The half life of the compound =  17 minutes

rate constant = k = 0.693/17 = 0.040 minutes⁻¹

The time taken to reach the concentration of 12.5 % of its original amount is calculated as follows:

t = 1/k  ln Wo/(Wt )

= ln( 100/12.5)/ 0.040 minutes⁻¹

= 52.49 minutes

Therefore, taken to reach the concentration  12.5%  of  the initial amount is 52.49 minutes.

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Answer:

No

Explanation:

Vitamins cannot be a direct source of energy for muscle work. Vitamins play important roles in various metabolic processes, but they do not provide energy directly. Energy is primarily provided by the breakdown of carbohydrates, fats, and proteins. Vitamins are essential for the proper functioning of these metabolic processes and for the release of energy from these macronutrients.

Answer:

Vitamins are not a reliable source of immediate energy for working muscles. Vitamins are necessary for optimum health and for supplying energy for many metabolic processes, however they do not directly provide energy to muscles. The breakdown of glucose or glycogen, which is stored in muscle cells, is the main source of energy for muscle action. Although they are not an energy source in themselves, vitamins are essential for supporting the metabolic processes that turn glucose and glycogen into energy. Vitamin consumption must remain adequate to sustain healthy energy metabolism and overall health, but vitamins cannot take the place of the need for carbohydrates and other meals high in energy to power physical activity.

Explanation:

For Sn;

Protons = 50,  Electrons = 50

For Mg^2+

Protons 12, Electrons = 10

The number of protons in an atom is called the atomic number and determines the chemical identity of the element. Each element has a unique atomic number, which is equal to the number of protons in the nucleus of one of its atoms.

To determine the number of protons in an atom, you can look up the atomic number of the element in the periodic table. The periodic table is a chart that organizes elements based on their atomic number and other properties. The atomic number is listed for each element and indicates the number of protons in its nucleus.

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The two reaction products as they appear in an acidic solution. Hydrogens on oxygen and nitrogen is drawn below:

Higher than that of pure water, an acidic solution has a high concentration of hydrogen ions (H +start superscript, plus, end superscript). A basic solution has a lower concentration of H +start superscript, plus, end superscript than pure water. Ammonia and water are just two examples of the simple molecules that hydrogen bonds can affect, but other simple molecules can also be affected. Moreover, the oxygen and nitrogen hydrogen bonds serve crucial functions in biochemistry, with DNA structure being the most well-known example.

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