Chemistry College

For the following reaction:

2 N2O5 → 4 NO2 + O2

The rate of formation of oxygen is 0.200 mol/L. The rate of formation of NO2 will be

Group of answer choices

0.0500 mol/L

0.200 mol/L

0.500 mol/L

0.800 mol/L

Answers

Answer 1

The rate of the formation of nitrogen dioxide can be obtained as 0.800 mol/L. Option D

What is rate of reaction?

The rate of reaction depends on various factors, including the nature of the reactants, the concentrations of the reactants, the temperature, the presence of catalysts, and the surface area of the reactants. It is determined by the collision of particles and their energy, orientation, and the effectiveness of the collision in breaking and forming chemical bonds.

We have that;

1/4d[[tex]O_{2}[/tex]]/dt = d[[tex]NO_{2}[/tex]]/dt

Thus;

Rate of formation of the nitrogen dioxide = 2 * 0.200 mol/L

= 0.800 mol/L

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Related Questions

3. A Wilkinson’s catalyst is widely used in the hydrogenation of alkenes. Show a catalytic cycle, including: i. chemical structure of the catalyst, with complete stereochemistry ii. molecular geometry of catalyst iii. type of reactions involved iv. the appropriate starting material, reagent and solvent v. major and minor end-products vi. all intermediates, for each reaction stated in (iii)

Answers

We can see here that the catalytic cycle for the hydrogenation of alkenes using Wilkinson's catalyst involves several steps.

What are the steps involved?

Here's an overview of the catalytic cycle, including the necessary details:

i. Chemical structure of the catalyst:

Wilkinson's catalyst, also known as chloridotris(triphenylphosphine)rhodium(I), has the following chemical structure: [RhCl(PPh3)3]

ii. Molecular geometry of the catalyst:

The Wilkinson's catalyst has a trigonal bipyramidal geometry around the rhodium center. The three triphenylphosphine (PPh3) ligands occupy equatorial positions, while the chloride (Cl) ligand occupies an axial position.

iii. Type of reactions involved:

The catalytic cycle involves several reactions, including:

Oxidative addition: The rhodium center undergoes oxidative addition, reacting with molecular hydrogen (H2) to form a dihydride intermediate.Alkene coordination: The alkene substrate coordinates to the rhodium center, forming a π-complex.Hydrogenation: The coordinated alkene undergoes hydrogenation, resulting in the addition of hydrogen atoms to the double bond and formation of a metal-alkyl intermediate.Reoxidation: The metal-alkyl intermediate reacts with a hydrogen molecule to regenerate the rhodium dihydride species.

iv. Starting material, reagent, and solvent:

The starting material is an alkene, and the reagent is Wilkinson's catalyst ([RhCl(PPh3)3]). The reaction is typically carried out in a suitable solvent, such as dichloromethane (CH2Cl2) or tetrahydrofuran (THF).

v. Major and minor end-products:

The major end-product of the hydrogenation reaction is the fully saturated alkane, resulting from the addition of hydrogen across the double bond. The minor end-product may include cis- or trans-configured alkanes if the original alkene substrate possesses geometric isomers.

vi. Intermediates:

The intermediates in the catalytic cycle include:

Rhodium dihydride complex: [RhH2(PPh3)3]Alkene-Rhodium π-complex: [Rh(η2-alkene)(PPh3)3]Metal-alkyl intermediate: [Rh(alkyl)(PPh3)3]

These intermediates play a crucial role in facilitating the hydrogenation reaction and enabling the catalytic cycle to proceed.

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What is the molar mass
MgCrO4

Answers

The molar mass of MgCrO4 is approximately 140.30 g/mol.

To determine the molar mass of MgCrO4 (magnesium chromate), we need to calculate the sum of the atomic masses of each individual element in the compound.

The chemical formula MgCrO4 indicates that the compound consists of one magnesium atom (Mg), one chromium atom (Cr), and four oxygen atoms (O).

The atomic masses of the elements can be found on the periodic table:

Magnesium (Mg) has an atomic mass of approximately 24.31 g/mol.

Chromium (Cr) has an atomic mass of around 51.99 g/mol.

Oxygen (O) has an atomic mass of about 16.00 g/mol.

Now, we can calculate the molar mass of MgCrO4 by summing up the atomic masses of each element, considering the respective subscripts:

Molar mass = (Atomic mass of Mg) + (Atomic mass of Cr) + 4 × (Atomic mass of O)

Molar mass = (24.31 g/mol) + (51.99 g/mol) + 4 × (16.00 g/mol)

Molar mass = 24.31 g/mol + 51.99 g/mol + 64.00 g/mol

Molar mass ≈ 140.30 g/mol

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PLEASE ANSWER QUICKLY!!!!

2KI (aq) + Cl₂(g) → 2KCl(aq) + 1₂(g)
What volume of 12 gas forms when
21 L Cl2 react at STP?
[?] L 12

Answers

The volume of 12 gas forms when 21 L Cl2 react at STP is 21 L.

To determine the volume of 12 gas (I assume you mean I2 gas) formed when 21 L of Cl2 reacts at STP (standard temperature and pressure), we need to use the ideal gas law equation.

The ideal gas law equation is given by:

PV = nRT

Where:

P = pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

At STP, the pressure is 1 atm, and the temperature is 273.15 K.

From the balanced equation, we can see that the molar ratio between Cl2 and I2 is 1:1. So, if 21 L of Cl2 reacts, it will produce an equal volume of I2 gas.

Given that the volume of Cl2 is 21 L, we can assume the volume of I2 gas formed will also be 21 L.

Therefore, the volume of I2 gas formed is 21 L.

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