For which pair of functions f(x) and g(x) below will the limit as x goes to infinity of the quotient of f of x and g of x equals 0 ?
f(x) = ex; g(x) = x2
f(x) = ex; g(x) = ln(x)
f(x) = ln(x); g(x) = ex
f(x) = x; g(x) = ln(x)

Answers

Answer 1

The pair of functions f(x) and g(x) below that equals 0 as the limit as x goes to infinity of the quotient of f of x and g of x will be C. f(x) = ln(x); g(x) = ex

How to explain the information

For the limit of the quotient of f(x) and g(x) to equal 0 as x approaches infinity, it is necessary for f(x) to grow more slowly than g(x).

Out of the options given, the only pair of functions where this is true is f(x) = ln(x) and g(x) = ex. As x approaches infinity, ex grows much faster than ln(x), so the limit of the quotient of these two functions as x approaches infinity is 0.

In conclusion, the correct option is C.

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Related Questions

a basketball player makes 80% of her free throws. what is the standard deviation of the successes from 100 free throws?

Answers

Since 80 out of 100 free throws were successful, the standard deviation of the success rate would be 8, and the standard deviation of a binomial distribution is the square root of (p*q)/n, where p is the probability of success, q is the probability of failure (1-p), and n is the total number of trials.

Standard deviation is calculated as follows:

p*q/n = 0.8*0.2/100 = 0.0016 = 0.04 = 8

Since 80% of 100 equals 80 successful free throws, the standard deviation of the successes from 100 free throws would be 8. The dispersion in a set of data is measured by standard deviation. A binomial distribution's standard deviation is equal to the square root of (p*q)/n, where p is the success probability, q is the failure probability (1-p), and n is the number of trials. Since the success rate in this instance is 80%, p = 0.8, q = 0.2, and n = 100. The standard deviation is then equal to the square root of (p*q/n): (0.8*0.2/100) = (0.0016) = (0.04), which equals 8. Therefore, the standard deviation of the successes from 100 free throws for a basketball player who makes 80% of them would be 8.

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PLEASE HELP 20 POINTS

unit 9: transformations homework 1: translations

Answers

The translation of a function and coordinates are given below..

What is translation?

It is the movement of the shape in the left, right, up, and down directions.

The translated shape will have the same shape and shape.

There is a positive value when translated to the right and up.

There is a negative value when translated to the left and down.


We have,

The following functions:

y = x²

y = 2x

The transformation is:

Translate two units to the left.

So,

y = (x - 2)²

y = 2(x - 2)

Translation 5 units up.

y = x² + 5

y = 2x + 5

The following coordinates:

Translate 2 units to the right.

(1, 4) = (1 + 2, 4) = (3, 4)

(5, 8) = (5 + 2, 8) = (7, 8)

Translation 5 units down.

(1, 4) = (1, 4 - 5) = (1, -1)

(5, 8) = (5, 8 - 5) = (5, 3)

Thus,

The translation of a function and coordinates are given above.

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Howard's pencil is 75 cm long. How many millimeters long is Howard's pencil?

Answers

Answer:

Howard's pencil is 750 millimeters

Step-by-step explanation:

[tex]\begin{array}{|l}\underline{km~}\\~~~~~\underline{|hm~}\\~~~~~~~~~~~\underline{|dam}~~~~~~~~\nwarrow~\div10\\~~~~~~~~~~~~~~~~~\underline{|m~~}\\~~~~~~~~~~\searrow~~~~~~~\underline{|dm~}\\~~~\times10~~~~~~~~~~~~~~~~~~\underline{|cm~}\\\underline{~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~|mm~}\end{array}\\~~~~~~~~~~~\rm Converting ~Length ~ Unit[/tex][tex]~[/tex]

Step-by-step:

75 cm = 75 × 10 mm

75 cm = 750 mm

you want to compute a 90% confidence interval for the mean of a population with unknown population standard deviation. the sample size is 30. the value of t* you would use for this interval is

Answers

The value of t* would use for this interval is 1.699 to compute a 90% confidence interval.

It is given that the confidence = 90% or 0.9

also, the sample size (n) = 30

The degrees of freedom is the sample size decreased by 1:

df = n - 1

df   = 30 - 1

df = 29

The critical value t* can then be found in the row with df = 29 and in the column with c = 90% (or upper tail probability p = 0.05) using table B.

t* = 1.699

The image attached is t* table

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Find the sum of (8a + 2b -4) and (3b-5)

Answers

The sum of expression is 8a + 5b - 9.

What is expression?

A mathematical operation such as subtraction, addition, multiplication, or division is used to combine terms into an expression. In a mathematical expression, the following terms are used:

An absolute numerical number is referred to as a constant.Variable: A symbol without a set value is referred to as a variable.Term: A term can be made up of a single constant, a single variable, or a mix of variables and constants multiplied or divided.Coefficient: In an expression, a coefficient is a number that is multiplied by a variable.

Given:

(8a + 2b -4) and (3b-5)

Now, adding the above expression we get

(8a + 2b -4) + (3b-5)

= 8a + 2b - 4 + 3b - 5

= 8a + 2b + 3b -4 - 5

= 8a + b(2+ 3) - 9

= 8a + b(5) -9

= 8a + 5b - 9

Hence, the simplified expression is 8a + 5b - 9.

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Select all the equations that have 9 as a solution. j + 8 = 72 m × 3 = 27 b + 4 = 13 p – 5 = 4 q ÷ 3 = 27

Answers

The equation with solution 9 is
m × 3 = 27,
b + 4 = 13
and p – 5 = 4.




Given:
1. j + 8 = 72
j= 72- 8
j= 64
2. m × 3 = 27
m= 37/3
m=9
3. b + 4 = 13
b= 13- 4
b = 9
4. p – 5 = 4
p= 9
6.q ÷ 3 = 27
q= 27 x 3
q= 81
Hence, the equation with solution 9 is m × 3 = 27, b + 4 = 13 and p – 5 = 4.

Are both correct? EXPLAIN your reasoning.

Answers

We can draw the conclusion that Sadio and Amir's methods for solving the equation are both valid.

What are equations?

A mathematical statement that has a "equal to" symbol between two expressions with equal values is called an equation.

As in 3x + 5 Equals 15, for instance.

Equations come in a variety of forms, including linear, quadratic, cubic, and others.

Equation: A declaration that two expressions with variables or integers are equal.

In essence, equations are questions and attempts to systematically identify the solutions to these questions have been the driving forces behind the creation of mathematics.

So, as we have the equation:

12x + 3 = 3(5x + 9)

Now, as we can see, Sadio took out 3 as common from LHS and RHS and solved the equation.

Which gave her the value of x as -8.

Amir, on the other hand, did not take out anything as common and directly multiply 3 with other terms in the brackets to solve the equation.

He also got -8 as the value of x.

Hence, we can conclude that yes both the ways of solving the equation is correct which is done by Sadio and Amir.


Therefore, we can draw the conclusion that Sadio and Amir's methods for solving the equation are both valid.

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Olivia has 1/8 pound of butter. She needs to divide the butter equally amoungn4 batches of muffins she is baking. How much butter is used in each batch of muffins

Answers

The correct weight of butter is 1/32 pounds. Olivia will use 1/32 pound of butter in each batch of muffins.

Olivia has 1/8 pound of butter that she needs to divide equally among 4 batches of muffins. To find out how much butter is used each batch of muffins, we can divide the total amount of butter by the number of batches. So, the amount of butter in each batch of muffins is: 1/8 ÷ 4 batches = 1/32 pound. So, Olivia will use 1/32 pound of butter in each batch of muffins. A pound (lb) is a unit of weight or mass commonly used in the United States and other countries that follow the customary system of measurement.

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How do you find the leading coefficients of a parabola graph?

Answers

well, if we use the vertex form of a parabola, we can pretty much see the parabolas all pretty much have a vertext at the origin, (0,0), now, let's take a look of a point they go by, Check the picture below.

[tex]~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{a~is~negative}{op ens~\cap}\qquad \stackrel{a~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} h=0\\ k=0\\ \end{cases}\implies y=a(~~x-0~~)^2 + 0\hspace{4em}\textit{we also know that} \begin{cases} x=4\\ y=4 \end{cases} \\\\\\ 4=a(4-0)^2 + 0\implies 4=16a\implies \cfrac{4}{16}=a\implies \cfrac{1}{4}=a~\hfill \boxed{y=\cfrac{1}{4}x^2}[/tex]

now let's do D

[tex]\begin{cases} h=0\\ k=0\\ \end{cases}\implies y=a(~~x-0~~)^2 + 0\hspace{4em}\textit{we also know that} \begin{cases} x=-1\\ y=-3 \end{cases} \\\\\\ -3=a(-1-0)^2+0\implies -3=a\hspace{5em}\boxed{y=-3x^2}[/tex]

SOMEONE HELP URGENT PLS

20 POINTS AND BRAINLEST

Answers

A graph which represents the solution to this system of inequalities include the following: graph D.

How to graph the solution to this system of inequalities?

In order to to graph the solution to the given system of inequalities on a coordinate plane, we would use an online graphing calculator to plot the given system of inequalities and then take note of the point of intersection;

y ≤ 3x - 4     .....equation 1.

4x + 2y < 6    .....equation 2.

Based on the graph (see attachment), we can logically deduce that the solution to the given system of inequalities is the shaded region below the solid and dashed line, and the point of intersection of the lines on the graph representing each, which is given by the ordered pair (1.4, 0.2).

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4,400 is placed in an account with an annual interest rate of 8. 25%. How much will be in the account after 22 years to the nearest cent

Answers

If $4400 is placed in account at 8.25% for 22 years , then the final amount received after 22 years will be $26480.08  .  

We use the formula for compound interest to find the final amount  :

that is ⇒  A = P(1 + r)ˣ  ;

where:  A = the amount of money in the account after "x years"  ;

P(initial amount) = $4400 ;   r (interest rate) = 0.0825  ;

⇒ x(time) = 22 years

we get ;

⇒ A = 4400×(1 + 0.0825)²²  ;

⇒ A =  4400×(1.0825)²²  ;

⇒ A =  4400×6.018028  ;

⇒ A = 26480.08  ;

Therefore , the amount in the account after 22 years is $26480.08  .

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equation of the blue line?

Answers

Answer:

Step-by-step explanation:

y=kx+b

b=3

(1,5)

1*k+3=5

k=2

so, 2x+3=y

how many times does 4 go in 5

Answers

Answer:

Step-by-step explanation:

9 times

6,7,8,9 (4 times starting at 5)

Answer: 1.25

Step-by-step explanation:

you divide/combine 5 and 4 to get Ur anwser 1.25.  Yet it's the same thing as asking ,"How much is 5 divided by 4?" just think of it to yourself as how many times you can fit 4 into 5. One tip you can use is 4(x) = 5 and x will equal 1.25.

A builder is constructing an office building with n floors that will have an antenna 13.5 feet tall on its roof. Each floor of the building will be 6.8 feet high. Which function can be used to find the total height, h, of the building in feet, including the antenna?

Answers

The function that can be used to find the total height, h, of the building in feet, including the antenna is h = 6.8n + 13.5.

How to use function to find the total height?

A builder is constructing an office building with n floors that will have an antenna 13.5 feet tall on its roof. Each floor of the building will be 6.8 feet high.

Therefore, the function that can be used to find the total height of the building in feet including the antenna can be calculated as follows:

Therefore,

n = numbers of floors in the building.

h = total height of the building

Hence, the function is as follows

h = 6.8n + 13.5

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A factory has two smokestacks. The rate of particle pollution produced is 12 kg / h
for the first smokestack and 32 kg / h
for the second. The manufacturing process requires that the first smokestack operates 2
hours longer than 1. 5
times as long as the second. A local pollution control board has ordered that the factory produce no more than 374 kg
of particle pollution per day. What is the maximum number of hours per day that each smokestack can operate?

Answers

Maximum number of hours per day that first smokestack can operate 12.5 hours and for second smokestack is 7 hours.

According to the question a  factory has two smokestacks:

Let first smokestack take x  number of hours per day

and second smokestack take y number of hours per day

The rate of particle pollution produced is 12 kg/h for the first smokestack

and rate of particle pollution produced is 32 kg/h for the second.

A local pollution control board has ordered that the factory produce no more than 374 kg of particle pollution per day.

so, equation becomes 12x + 32y = 374

also the first smokestack operates 2 hours longer than 1. 5 times as long as the second.

so, x = 2 + 1.5y

putting value of x in other equation

12(2 + 1.5y) + 32y = 374

24 + 18y + 32y = 374

50y = 350

y = 7 hours

x = 2 + 1.5(7) = 12.5 hours

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Lucy thinks of a number.
10 x the number = 10 ÷ the number
Give a possible value of the number.​

Answers

Answer: 1

Step-by-step explanation: Knowing the division and multiplication rules, any number times one equals itself and any number divided by one equals itself. Make sure not to put 0 as an answer because any number divided by 0 is undefined.

gwen has £7 a litre of cola costs £1.25 gwen buys as much as literes as she can. how much money does she have left?

Answers

Gwen has £0.75 money left over, as per linear equation if a litre of cola costs £1.25.

"A linear equation is an equation in which the highest power of the variable is always 1. It is also known as a one-degree equation."

It is given that Gwen has a £5 note and a £2 coin.

Therefore, she has a total of £(5 + 2) = £7

A liter of cola costs £1.25.

Therefore, (7 ÷ 1.25) = 5.6

Therefore, Gwen can buy a total of 5 liters of cola.

Now, Gwen has left money of £[7 - (5 × 1.25)] = £0.75

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Complete question is:

Gwen has a £5 note and a £2 coin

a litre of cola cost £1.25

gwen buys as many liter bottles of cola as she can

how much money will she have left over

HELP PLEASE




Which best represents the transformation for the coordinates of the vertices of the given pairs of triangles?

(1, 6), (−1, 3), (5, −2) and

(−1, 6), (−3, 3), (3, −2)

Answers

Step-by-step explanation:

what is the difference between the x- values ?

and what is the difference between the y- values ?

a transformation means a simple shift. so, addition of subtraction. no multiplication or such.

1 to -1 ? -2

-1 to -3 ? -2

5 to 3 ? -2

6 to 6 ? 0

3 to 3 ? 0

-2 to -2 ? 0

so, the transformation is (-2, 0)

a tank contains 1120 l of pure water. solution that contains 0.08 kg of sugar per liter enters the tank at the rate 4 l/min, and is thoroughly mixed into it. the new solution drains out of the tank at the same rate. (a) how much sugar is in the tank at the begining?

Answers

a) 0 kg of sugar is in the tank at the beginning., b) ds/dt = 0.08-(S/1120)*4, c) 0.32 kg of sugar is in the tank after 1 minute., d) 2.59 kg of sugar is in the tank after 84 minutes.

a) At the beginning, there is no sugar in the tank since it contains only pure water.

b) Let S(t) be the amount of sugar in the tank at time t (in minutes). The rate of change of S is given by the rate at which sugar enters the tank minus the rate at which it leaves. Since the solution enters at a rate of 4 L/min, and contains 0.08 kg of sugar per liter, the rate at which sugar enters is 0.08 kg/L * 4 L/min = 0.32 kg/min. Since the solution leaves at the same rate, the differential equation that models the situation is:

dS/dt = 0.32 - (S/1120) * 4

c) To find the amount of sugar after 1 minute, we need to solve the differential equation from part (b) with the initial condition S(0) = 0 (since the tank initially contains only water). One possible way to solve the differential equation is to use separation of variables:

dS/dt + (4/1120) S = 0.32

Multiplying both sides by dt and dividing by (0.32 - (4/1120) S), we get:

(1/S) dS = (4/0.32 - (1120/4)) dt

Integrating both sides from t = 0 to t = 1 and from S = 0 to S = S(1), we get:

ln(S(1)) - ln(0) = (1.25 - 280) * 1

S(1) = [tex]e^{0.25} * 1120[/tex] ≈ 300.92 kg

Therefore, after 1 minute, there is approximately 300.92 kg of sugar in the tank.

d) To find the amount of sugar after 84 minutes, we can solve the differential equation from part (b) numerically using an appropriate method such as Euler's method, or we can use an integrating factor to solve it analytically. One possible way to use an integrating factor is to multiply both sides of the differential equation by exp(4t/1120):

exp(4t/1120) dS/dt + (S/280) exp(4t/1120) = 0.32 exp(4t/1120)

This can be written as:

d/dt [S exp(4t/1120)] = 0.32 exp(4t/1120)

Integrating both sides from t = 0 to t = 84, we get:

[S(84) exp(4/1120 * 84)] - [S(0) exp(4/1120 * 0)] = ∫(0 to 84) 0.32 exp(4t/1120) dt

Since S(0) = 0 and exp(4/1120 * 84) is a constant, we can simplify this to:

S(84) = (1/exp(4/1120 * 84)) ∫(0 to 84) 0.32 exp(4t/1120) dt

Using integration by substitution with u = 4t/1120, we get:

S(84) = (1/exp(4/1120 * 84)) * (1120/4) * (0.32/4) * [exp(4/1120 * 84) - 1]

S(84) ≈ 301.53 kg

Therefore, after 84 minutes, there is approximately 301.53 kg of sugar in the tank.

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The complete question is:

A tank contains 1120 L of pure water. At a rate of 4 L/min, a solution that contains 0.08 kilogramme of sugar per litre enters the tank. At the same rate that it drains from the tank, the solution is mixed.

a) How much sugar is in the tank when it first starts?

b) With S representing the amount of sugar (in kg) at time t, write a differential equation which models the situation.

c) After 1 minute, calculate the sugar content (in kilogramme).

d) After 84 minutes, calculate the sugar content (in kg).

12. (A.10.B) A sidewalk was built around a rectangular garden. Find the area of the sidewalk in terms of x
x
3x
2x-1
X+2

Answers

The area of the sidewalk in terms of x would be 3 x ² + x + 2

How to find the area of the sidewalk ?

The area of the sidewalk would be :

= Area of rectangular area - Area of rectangular garden

Area of rectangular area = 2 x ( 2x + 1 )

Area of rectangular garden = x ( x + 1 )

The area of the sidewalk in terms of x is therefore :

= ( 2 x ( 2x + 1 ) ) - ( x ( x + 1 ) )

= ( 4 x ² + 2 ) - ( x ² + x )

= 4 x ² + 2 -  x ² + x

= 4 x ² - x ² + x + 2

= 3 x ² + x + 2

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Determine the occupant load of a one room daycare that is 20' by 30' !

Answers

The occupant load of a one room daycare that is 20' by 30' is 17 people.

The occupant load of the daycare room can be determined by using the formula:

Occupant load = Area of room / Occupant load factor

From the case, we know that the area of the room is 20' x 30', then:

Room area = 600 square feet.

The occupant load factor for a daycare is typically 35 square feet per person. This means that each person in the daycare should have at least 35 square feet of space.

Using the formula, the occupant load of the one room daycare is:

Occupant load = 600 square feet / 35 square feet per person = 17.14 people

Therefore, the occupant load of the one room daycare is 17 people. This means that the daycare can safely accommodate 17 people at one time.

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which equations for the measures of the unknown angles x and y are correct? check all that apply.(a) x=cos−1(a/c)x=cos−1(a/c)(b) x=sin−1(c/b)x=sin−1(c/b)(c) x=tan−1(c/a)x=tan−1(c/a)(d) y=sin−1(a/c)y=sin−1(a/c)(e)y=cos−1(c/b)y=cos−1(c/b)

Answers

The equations for the measures of the unknown angles x and y that are correct are (b), (c) and (e).

The six trigonometric ratios are sine (sin), cosine (cos), tangent (tan), cotangent (cot), cosecant (cosec), and secant (sec).

Sin θ = Opposite Side to θ/Hypotenuse

Cos θ = Adjacent Side to θ/Hypotenuse

Tan θ = Opposite Side/Adjacent Side

Cot θ = Adjacent Side/Opposite Side

Sec θ = Hypotenuse/Adjacent Side

Cosec θ = Hypotenuse/Opposite Side

where, Hypotenuse (the longest side), Perpendicular (opposite side to the angle), Base (Adjacent side to the angle)

The inverse ratios start with the ratio and then find the angle that produces this ratio.

(a) x=cos−1(a/c)

(b) x=sin−1(c/b)

(c) x=tan−1(c/a)

(d) y=sin−1(a/c)

(e)y=cos−1(c/b)

The equations for the measures of the unknown angles x and y that are correct are (b), (c) and (e).

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the letter grades (a, b, c, d, f) of business analysis students are recorded by a professor. this variable's classification . a. is time series data b. is categorical data c. is quantitative data d. cannot be determined

Answers

The letter grades (A, B, C, D, F) for business analysis students are categories that represent different levels of achievement, so the variable's classification is (b) Categorical Data.

The Categorical data are defined as the variables that represent characteristics or attributes, and they are often expressed as labels or categories.

The Quantitative data, on the other hand, are  the numerical values which  represent measurements or quantities.

Since the letter grades are not numerical values and do not represent a measurement or quantity, they cannot be classified as quantitative data.

Therefore , the letter grades represents a Categorical Variables .

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The given question is incomplete , the complete question is

The letter grades (A, B, C, D, F) of business analysis students are recorded by a professor. this variable's classification .

(a) is time series data

(b) is categorical data

(c) is quantitative data

(d) cannot be determined

What is the kinetic energy of a 3 kg ball that is rolling at 2 m/s

Answers

The kinetic energy of the 3 kg ball rolling at 2 m/s is 6 joules. The kinetic energy of an object is the energy it possesses due to its motion.

The kinetic energy of an object is the energy it possesses due to its motion. The formula for kinetic energy is given by:

Kinetic Energy = (1/2) * mass * velocity^2

In this case, the mass of the ball is 3 kg and its velocity is 2 m/s, so we can plug these values into the formula:

Kinetic Energy = [tex](1/2) * 3 kg * (2 m/s)^2[/tex]

Kinetic Energy = [tex](1/2) * 3 kg * 4 m^2/s^2[/tex]

Kinetic Energy = 6 J

So the kinetic energy of the 3 kg ball rolling at 2 m/s is 6 joules.

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Need some helppp on this question will give 20 points

Answers

[tex]\cfrac{\sqrt[3]{27xy^3}}{5x^{\frac{4}{3}}y^2}\implies \cfrac{\sqrt[3]{3^3 xy^3}}{5x^{\frac{4}{3}}y^2}\implies \cfrac{(3^3 xy^3)^{\frac{1}{3}}}{5x^{\frac{4}{3}}y^2}\implies \cfrac{3^{3\cdot \frac{1}{3}}x^{\frac{1}{3}}y^{3\cdot \frac{1}{3}}}{5x^{\frac{4}{3}}y^2}\implies \cfrac{3x^{\frac{1}{3}}y}{5x^{\frac{4}{3}}y^2}[/tex]

[tex]\cfrac{3}{5}\cdot \cfrac{x^{\frac{1}{3}}y}{x^{\frac{4}{3}}y^2}\implies \cfrac{3}{5}\cdot x^{\frac{1}{3}}yx^{-\frac{4}{3}}y^{-2}\implies \cfrac{3}{5}\cdot x^{\frac{1}{3}}x^{-\frac{4}{3}}yy^{-2}\implies \cfrac{3}{5}\cdot x^{\frac{1}{3}-\frac{4}{3}} y^{1-2} \\\\\\ ~\hfill {\Large \begin{array}{llll} \stackrel{a ~~~~ b ~~ ~~ c}{0.6 x^{-1}y^{-1}} \end{array}}~\hfill[/tex]

Please help me!
A spinner and a fair number cube are used in a game. The spinner has an equal chance of landing on 1 of 6 colors: red, purple, blue, green, white, or orange. The faces of the cube are labeled 1 through 6. What is the probability of a player spinning the color green and then rolling an even number?

Answers

The probability of spinning green and then rolling an even number is 1/36

What is Probability?

Probability is an area of mathematics that deals with numerical descriptions of how probable an event is to occur or how likely a statement is to be true. The probability of an event is a number between 0 and 1, where 0 denotes the event's impossibility and 1 represents certainty.

The probability of spinning green is 1/6 because there are 6 equally likely outcomes and 1 of them is green.

The probability of rolling an even number is 3/6 because there are 6 equally likely outcomes and 3 of them are even numbers (2, 4, and 6).

The probability of spinning green and then rolling an even number is the product of the probabilities of each event. To find this, we multiply the probability of spinning green (1/6) by the probability of rolling an even number (3/6):

(1/6) * (3/6) = 1/36

So, the probability of spinning green and then rolling an even number is 1/36.

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Can someone explain and help me through this?

a. Set up an equation to represent the distance the cheetah covered in terms of t minutes running at maximum speed. Remember, units of distance and time must agree. Use the conversion information from the warm-up to write a rate in miles per minute.



b. Let t = 10 and solve for the distance the cheetah covered in 10 minutes.


Information from the Warm Up:

According to the Travel Almanac, the world’s fastest land animal is the cheetah. It can travel at up to 70 mph. Think of this scenario: A cheetah sitting under a tree sprints toward its prey at 70 mph. It runs back to its initial spot by the tree at a modest 40 mph. The cheetah has embarked on a round-trip. Going from point A to point B, the cheetah traveled at an average rate of 70 mph. Returning to point A, the cheetah traveled at an average rate of 40 mph.

Can we say that this cheetah’s average rate was 55 mph?

That’s one of the things you’ll determine as you work to complete this task. Make a conjecture. What do you think the answer will be?

Answers

well, let's get the info first.

so going forth the Cheetah goes 70mph and going back it modestly does 40mph.

can we say that on average it did 55mph?

well, what's that?  on average means, that in total if we sum all units up and divide them evenly by relevant intervals, that's our average value.

well, let's see both intervals, on is forth and another is back 2 intervals, and the speed values are 70 and 40, so the average will really be (70 + 40) ÷ 2 = 55, that is an average of 55mph, so yes, we can say that.

A)

since an hour is 60 minutes, the Cheetah is really doing 70 miles per 60 minutes, or we can say

[tex]70\cdot \cfrac{miles}{~~\begin{matrix} hour \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }\cdot \cfrac{~~\begin{matrix} hour \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{60~minutes}\implies \cfrac{70}{60}\cdot \cfrac{miles}{minutes} \implies 1.1\overline{66}\frac{miles}{minutes}[/tex]

[tex]{\Large \begin{array}{llll} \stackrel{\textit{miles covered}}{m(t)}~~ = ~~1.1\overline{66}t \end{array}}[/tex]

B)

[tex]\stackrel{\textit{miles covered}}{m(t)}~~ = ~~1.1\overline{66}t\implies \stackrel{t=10}{m(10)=1.1\overline{66}(10)}\implies \stackrel{\textit{miles in 10 minutes}}{m(10)=11.\overline{66}}[/tex]

Macy wants to join a Rock-Climbing gym. Avery's gym has an initial cost of $50 with a $10 per session charge. Gabe's gym has no initial cost, but has a $12 per session charge. How many sessions will she have to take to make both gym's cost the same?​

Answers

Answer: 25 sessions

Step-by-step explanation:

Set up an equation.

50+10x=12x

50=2x

x=25

She will have to take 25 sessions for both gym costs to be the same.

You can check this too. 50 plus 10*25 is $300, and 12*25 is $300.

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Hope this helps.

MM4343

Answer: We can start by setting the cost of the two gyms equal to each other and then solving for the number of sessions. Let's call the number of sessions Macy takes x. The cost of Avery's gym is 50 + 10x, and the cost of Gabe's gym is 12x. Setting these two equal to each other, we have:

50 + 10x = 12x

Subtracting 12x from both sides:

50 = -2x + 10x

Simplifying:

50 = 8x

Dividing both sides by 8:

x = 6.25

So, Macy would need to take 6.25 sessions for the cost of both gyms to be the same. However, since she can only take whole number of sessions, she would need to take 7 sessions to make both gyms cost the same.

Step-by-step explanation:

The apothem is the perpendicular distance from the _____ of a regular polygon to any one of its sides. center.

Answers

The apothem is perpendicular distance from the center of a regular polygon to any one of it sides.

The Apothem is defined as a term that used in geometry to describe a characteristic feature of a regular polygon.

A Regular Polygon is a polygon that has all sides of equal length and all angles of equal measure.

The Apothem of a regular polygon is defined as the perpendicular distance from the center of the polygon to any one of its sides.

The Center of circle is also the center of polygon. So , apothem is the distance from the center of the circle to the midpoint of any side of the polygon .

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The given question is incomplete , the complete question is

The apothem is the perpendicular distance from the _____ of a regular polygon to any one of its sides.

Let f(x) = 3x + 5 and g(x) = 4x - 1. Find (f + g)(x), then evaluate when x = 2.

Answers

The resulting sum function if x is equivalent to 2 is 18

Solving composite functions

Composite functions are known as function of a function

Given the following functions

f(x) = 3x + 5 and;

g(x) = 4x - 1.

(f+g)(x) = f(x) + g(x)

(f+g)(x) = 3x + 5 + 4x - 1

(f+g)(x) = 7x + 4

Substitute x = 2 into the result

(f+g)(2) = 7(2) + 4

(f+g)(2) = 18

Hence the value of the sum of the function when x = 2 is 18

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