Force is needed to...?

Answer:

#10

Explanation:

21% of 477 = 100.17 N   in an area of  pi ( .006m)^2      (.6cm = .006 m)

Pa is in units of N/m^2

                           100.17 N / ( pi (.006)^2) = 8.857 x 10^5 Pa

The shorter the distance between the balls, the greater the electric force between them.

option C

The electric force between charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

F = kq²/r²

where;

Therefore, if the charges on the pith balls are fixed, the closer they are, the stronger the electric force between them will be. So option C is the correct answer.

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The two gaseous giants that Renaissance scientists such as Galileo knew about were Jupiter and Saturn.

Galileo Galilei (1564-1642) was an Italian astronomer, physicist, and mathematician who is considered one of the most important figures in the Scientific Revolution of the 16th and 17th centuries. Galileo is known for his contributions to the fields of astronomy, physics, and mathematics, and for his pioneering use of the telescope to observe and study the heavens.

Galileo's observations of the moons of Jupiter, the phases of Venus, and the craters and mountains on the Moon provided evidence for the heliocentric model of the solar system proposed by Copernicus, which stated that the planets revolve around the sun, and not the Earth. This was a major challenge to the prevailing geocentric model, which placed the Earth at the center of the universe.

Galileo also made important contributions to the study of motion, developing the law of falling bodies and the concept of inertia. He was an outspoken advocate for the use of empirical evidence and observation in scientific inquiry, and his work laid the foundation for modern experimental physics.

However, Galileo's ideas and discoveries were controversial and led to conflict with the Catholic Church, which saw them as a challenge to Church doctrine. In 1633, Galileo was put on trial by the Inquisition and forced to renounce his ideas, spending the rest of his life under house arrest. Despite this, his work had a profound impact on the development of modern science and astronomy.

In 1610, Galileo observed these two planets with his telescope and discovered four of Jupiter's largest moons, now known as the Galilean moons, and the strange shapes that appear to surround Saturn. At the time, it was not known that Jupiter and Saturn were gas giants, as the concept of planets being composed mainly of gas had not yet been developed.

Hence, Jupiter and Saturn were the two gaseous giants known to Renaissance scientists such as Galileo.

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Both situations involve the application of force to an object and can be connected to Newton's three laws of motion in the following ways:

What are Newton's three laws of motion?

Newton's First Law of Motion: An object at rest will remain at rest, and an object in motion will continue to move at a constant velocity unless acted on by a net external force.

Newton's Second Law of Motion: The acceleration of a body is inversely related to its mass and directly related to the net force acting on it. F = ma, where F is the net force, m is the object's mass, and an is its acceleration, is a mathematical formula that can be used to represent this.

 Third Law of Motion of Newton: There is an equal and opposite reaction to every action.

a) According to Newton's First Law of Motion, sometimes referred to as the Law of Inertia, an object at rest will stay at rest, and until moved upon by an outside force, an object in motion will keep traveling at a constant speed.. The more significant mass of the croquet ball means that it will have more inertia and require greater power to be accelerated than the tennis ball, which has a smaller group. This is true when applying the same amount of force to both balls. This implies that it will be harder to get the croquet ball going from a stationary position and more complicated to stop it once it moves.

b) According to Newton's Second Law of Motion, which is commonly referred to as the Law of Acceleration, an object's acceleration is directly proportional to the force acting on it and inversely proportional to its mass. As a result, applying the same force to a mass that is smaller than it is will cause it to accelerate more quickly. This means that when the same force is applied to a 56 g tennis ball and a 500 g croquet ball, the tennis ball will accelerate more quickly than the croquet ball.

c) According to Newton's Third Law of Motion, sometimes referred to as the Law of Action and Reaction, there is an equal and opposite reaction to every action. When a ball is struck with a mallet, the ball responds by exerting an equal and opposite force on the mallet. As a result of the croquet ball's greater mass compared to the tennis ball, hitting the croquet ball will cause a greater force to be applied back to the mallet.

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Answer:

The image formed by a thin convex lens with a focal length of 9.00 cm when an object is placed at a distance of 27.0 cm away from the lens is located 18 cm away from the lens. The image formed is an upright, virtual image.

can you give me the brilliant mark?

Steps to formulate a logical, reasonable perspective to any situation are: gather information, identify problem, analyze the situation, consider assumptions, generate solutions, evaluate options, consider your values, make decision and monitor and adjust

Here are the six questions that you can apply to formulating a logical, reasonable perspective to any situation:

What are the issues that should be addressed?

What are the relevant facts and data related to this problem or issue?

What assumptions am I making about the problem or issue?

What are the possible solutions or outcomes, and what are the pros and cons of each?

What are my values and priorities related to this problem or issue?

What additional information do I need to make an informed decision or come to a reasonable conclusion?

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The radius of the electron beam when the accelerating voltage is 150 V and the coil current is 1.3 A is 0.0054 meters.

An electron beam is known as a stream of electrons that an electric field has rapidly accelerated. It is commonly produced by an electron cannon, which releases electrons from a heated cathode and accelerates and concentrates the electron beam using a series of electrodes.

The following equation can be used to determine an electron beam's radius: r = (m x v / (B x q)

r is the radius of the beam

m is the mass of the electron

v is the velocity of the electron

B is the magnetic field strength

q is the charge of the electron

Finding the electron's velocity is necessary to solve for the electron beam's radius. The rate of an electron can be determined using the following equation:

v = (2 x e x V / m)²

e is the electron's basic charge.

V is the accelerating voltage

m is the mass of the electron

v =  [tex]\sqrt{2 * 1.602 * 10 ^{-19} * 150 / 9.109 * \ 10^{-31}[/tex]

= 3.23 x  m/s

The radius can now be obtained by substituting this value into the first equation together with the other supplied values:

r = (9.109 x 10⁻³¹ kg × 3.23 x 10⁶ m/s) / (0.2 T × 1.602 x 10⁻¹⁹ C)

= 0.0054 m

As a result, the electron beam's calculated radius is around 0.0054 meters.

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Answer:

The Correct answer is D

molecules of liquid are stationary

A meter stick has mass of 0.18 kg and balances at its center, then mass of the chain is 0.221 kg.

The principle of moments states that the sum of clockwise moments about any point must be equal to the sum of counterclockwise moments about the same point in order for a body to be in rotational equilibrium.

As the meter stick is in equilibrium, the sum of clockwise moments about the balance point must be equal to the sum of the counterclockwise moments. Clockwise moment due to the weight of the meter stick is: 0.18 kg × 9.81 m/s² × (0.5 × 100 cm) = 8.8416 Nm

Counterclockwise moment due to the weight of the chain is: m_chain × 9.81 m/s² × (100 cm - 30 cm - x) = (m_chain × 9.81 m/s²) × (70 cm - x)

8.8416 Nm = (m_chain × 9.81 m/s²) × (70 cm - x)

m_chain = 8.8416 Nm / (9.81 m/s² × (70 cm - x))

m_chain = 0.221 kg

Therefore, mass of the chain is 0.221 kg.

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The magnitude of resulting acceleration of the block on frictionless surface is found to be 3.99 m/s².

The force applied at an angle can be resolved into its components along the x and y directions,

Fx = Fcos(30°)

Fx = (23N)cos(30°)

Fx = 19.95 N

Fy = Fsin(30°)

Fy= (23N)sin(30°)

Fy = 11.5 N

Since the horizontal surface is frictionless, the only force acting on the block is the component of the applied force in the x direction. Therefore, the net force acting on the block is Fnet = Fx.

Fx = 19.95 N

Using Newton's second law of motion, we can find the acceleration of the block Fnet = Ma, mass of the block is M and resulting acceleration is a. Solving for a, we get,

a = Fnet / M

a = 19.95 N/5.0 kg ≈ 3.99 m/²

Therefore, the magnitude of the resulting acceleration of the block is approximately 3.99 m/s².

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The dome will have approximately 0.1176% more interior space in the summer than it does in the winter.
The dome will have approximately 88.6 m³ more interior space in the summer than it does in the winter.

The dome will have more interior space in the summer due to thermal expansion of the aluminum framework. To calculate the change in volume, we can use the coefficient of thermal expansion for aluminum, which is approximately 2.4 x 10⁻⁵ /°C.

The temperature change from -15°C to 34°C is a difference of 49°C. So, the fractional change in volume is:

ΔV/V = αΔT

ΔV/V = (2.4 x 10⁻⁵/°C) x 49°C

ΔV/V = 0.001176

As a result, the dome will have 0.1176% more internal area in the summer than it does in the winter.

To find the actual change in volume, we can use the formula for the volume of a hemisphere:

V = (2/3)πr³

The diameter of the dome is 58.0 m, so the radius is 29.0 m. Therefore, the volume of the dome is:

V = (2/3)π(29.0 m)³

V = 75344 m³

Increasing the volume by 0.1176% gives us:

ΔV = 0.001176 x 75344 m³

ΔV = 88.6 m³

As a result, the dome will have 88.6 m³ more internal room in the summer than it does in the winter.

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The force acting on the object is the weight of the object, which is given by:

F = m * g

where m = 3.0 kg is the mass of the object and g = 9.81 m/s^2 is the acceleration due to gravity.

F = 3.0 kg * 9.81 m/s^2 = 29.43 N

The net force acting on the object when the lift goes down is the difference between the weight of the object and the force required to accelerate it downward:

Fnet = F - m * a

where a = 0.1 m/s^2 is the acceleration of the lift.

Fnet = 29.43 N - 3.0 kg * 0.1 m/s^2 = 29.13 N

The reading on the spring balance is equal to the net force acting on the object, which is 29.13 N.

In the Roman soldier model for refraction, the first soldier who hits the muddy stream would slow down and turn slightly. Option B is correct.

The Roman soldier model is a simplified model used to explain the behavior of light when it passes from one medium to another. In this model, a group of Roman soldiers is marching across a field towards a muddy stream. The soldiers represent light rays, and the muddy stream represents the boundary between two media with different refractive indices.

When the first soldier hits the muddy stream, they slow down because the speed of light decreases when it passes from a medium with a lower refractive index to a medium with a higher refractive index. Additionally, the soldier turns slightly because the direction of the light ray changes as it passes through the boundary between the two media. This change in direction is called refraction, and it occurs because the speed of light changes when it passes through a medium with a different refractive index.

The amount of refraction that occurs depends on the angle at which the light ray hits the boundary between the two media and the difference in refractive indices between the two media. The Roman soldier model is a useful tool for understanding the basics of refraction, but it has limitations and cannot fully explain all aspects of the phenomenon. Option B is correct.

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The metal bowl must displace 0.196 liters of castor oil in order to float.

Archimedes' principle states that when an object is placed in a fluid, the buoyant force on the object is equal to the weight of the fluid displaced by the object. In other words, the amount of fluid displaced by the object is directly proportional to the weight of the object.

We can use the weight density of castor oil, which is 9.42 N/L, to find the volume of oil displaced by the bowl.

Volume of oil displaced = Weight of bowl / Weight density of oil

Volume of oil displaced = 1.85 N / 9.42 N/L = 0.196 L

As a result, in order to float, the metal bowl must displace 0.196 liters of castor oil.

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The mass of the remaining ice in the jar will be 33.6 g.

To solve this problem, we need to use the principle of conservation of energy. The energy gained by the tea as it warms up is equal to the energy lost by the ice as it melts and cools down. We can use the following equation to calculate the mass of the remaining ice:

mice = (Qlost) / (L + CteaΔT)

where mice is the mass of the remaining ice, Qlost is the heat lost by the ice, L is the latent heat of fusion of water (334 J/g), Ctea is the specific heat capacity of the tea (4186 J/kg·°C), and ΔT is the temperature difference between the initial temperature of the ice (0°C) and the final temperature of the tea (24.6°C).

First, we need to calculate the heat lost by the ice:

Qlost = mice × L + mice × Cice × ΔT

where Cice is the specific heat capacity of ice (2108 J/kg·°C). Since the ice is initially at 0°C, ΔT is simply 24.6°C. Substituting the given values, we get:

Qlost = (130 g) × (334 J/g) + (130 g) × (2108 J/kg·°C) × (24.6°C)

= 1.108 × 10⁵ J

Now, we can substitute this value into the first equation to find the mass of the remaining ice:

mice = (Qlost) / (L + CteaΔT)

= (1.108 × 10⁵ J) / [(334 J/g) + (4186 J/kg·°C) × (24.6°C)]

= 33.6 g

Therefore, the mass of the remaining ice in the jar is 33.6 g.

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The transformation of energy from one form to another is the process where energy is converted from one form to another while the total amount of energy remains constant. This means that energy cannot be created or destroyed; it can only be transformed from one form to another.

One example of energy transformation is a light bulb. When a light bulb is switched on, electrical energy is transformed into light energy and heat energy. The electrical energy is transformed into light energy by the light bulb's filament, which heats up and emits light. At the same time, some of the electrical energy is transformed into heat energy, which is dissipated into the surrounding air. The total amount of energy is conserved, but it is transformed from electrical energy to light energy and heat energy.

Another example of energy transformation is a roller coaster ride. When a roller coaster is released from its starting point, its potential energy is transformed into kinetic energy as it moves downhill. As the roller coaster moves uphill, its kinetic energy is transformed back into potential energy. At the bottom of the hill, the kinetic energy is at its maximum, and the potential energy is at its minimum. At the top of the hill, the potential energy is at its maximum, and the kinetic energy is at its minimum. Again, the total amount of energy is conserved, but it is transformed from potential energy to kinetic energy and back again.

The work done is 259.8 J

The net work done is 140.625 J

Fx = F * cos(θ)

Fx = 60 N * cos(30°)

Fx ≈ 51.96 N

Fy = F * sin(θ)

Fy = 60 N * sin(30°)

Fy = 30 N

W = Fx * d

where d is the distance (5 m) the block moves.

work done = 51.96 N * 5 m

work done ≈ 259.8 J

Force norm = 10 kg * 9.81 m/s² - 30 N

Force  norm ≈ 68.1 N

Force  friction = 0.35 * 68.1 N

Force  friction ≈ 23.835 N

Workdone friction = 23.835 N * 5 m

Workdone friction ≈ 119.175 J

Workdone net = W_Force - W_friction

Workdone net = 259.8 J - 119.175 J

Workdone net ≈ 140.625 J

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Answer:

Time to get to top = 5 m/s / 10 m/s^2 = .5 sec

H at top = v0 t - 1/2 g t^2 =  5 * .5 - 1/2 * 10 * .5^2 = 1.25 m

Time to fall 1.25 + 20 = 21.25 m

S = 1/2 g t^2     since it starts out ar zero speed

t = (2 * 21.25 / 10)^1/2 = 2.06 sec

Total time = .5 + 2.06 = 2.56 sec

Calculations using equations of motion reveal that the total time for the ball to hit the ground, when thrown upward from a 20m high cliff with an initial speed of 5m/s and subjected to a gravitational pull of 10m/s², is about 3 seconds.

The time it takes for the ball to hit the ground is calculated using the equation of motion, t = sqrt((2h)/g), where 'h' is the height of the cliff and 'g' is the acceleration due to gravity. Since the ball is thrown upwards first, we also need to consider the time it takes for the ball to reach its maximum height and start falling down. This can be calculated using the equation t = v/g, where 'v' is the initial speed of the ball.

So, the total time would be the time it takes for the ball to reach the maximum height and fall down back to the ground, which is calculated using the following equation: t_total = t_up + t_down. Given that 'h' is 20m, 'v' is 5m/s, and 'g' is 10m/s², the total time it would take for the ball to hit the ground at the base of the cliff comes out to be approximately 3 seconds.

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Scientific question can be resolved by experimentation, observation, or other data collection methods.

A scientific investigation is an effort to use the scientific method to resolve a topic.

Since, they must be testable and objective, scientific questions vary from other types of questions. This implies that a scientific theory must be able to be frequently verified as true.

By examining quantifiable data and supporting evidence, it can be resolved by experimentation, observation, or other data collection methods.

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Answer:

Scalar quantity Vector quantity

Pressure Force

Energy Momentum

Speed Weight

Explanation:

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The statement true about sound waves is " Sound moves faster in the ocean than in the air."  The correct option is C.

Sound waves travel much faster in water (such as the ocean) compared to air. The speed of sound in air is around 343 meters per second at room temperature, while in water, it is about 1,500 meters per second. The denser medium of water allows sound waves to propagate more quickly.

A. Sound would move faster in a pool of water than in a pool of Jello: This statement is not true. Sound actually moves faster in water compared to Jello. The speed of sound depends on the medium it travels through, and in general, sound travels faster in denser materials. Water is denser than Jello, so sound waves would move faster in water.

B. Sound would move faster in a pool of rubber than in a pool of diamonds: This statement is not true. Sound waves do not travel faster in rubber compared to diamonds. In fact, the speed of sound in a material depends on its elasticity and density. Diamonds are much denser and have a higher elasticity compared to rubber, so sound waves would move faster in diamonds than in rubber.

D. Sound moves faster in a lake than in the ocean: This statement is not true. Sound waves do not travel faster in a lake compared to the ocean. The speed of sound in water depends on several factors, including temperature, salinity, and pressure. In general, the speed of sound is higher in the ocean compared to lakes due to the higher salinity and pressure in the ocean.

Therefore, C. Sound moves faster in the ocean than in the air: This statement is true.

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The force that is to be put on the brake of the bicycle is calculated as being equal to 12.36 N.

In order to know the force put on the brake, we are required to use the formula for rotational kinetic energy, which is presented by:

KE = (1/2) x I x ω²

(Here KE is defined as rotational kinetic energy, I is equal to the moment of inertia of the wheel, and ω is stated as the angular velocity of the wheel)

The moment of inertia of a solid disc can be calculated using the formula:

I = (1/2) x m x r²

(Here m is the mass of the wheel and r is radius of the wheel)

Putting in the given values, we get:

I = (1/2) x 2.5 kg x (0.5 m)²

I = 0.3125 kg m²

ω = 2π x f

Here f is the frequency of rotation. Given that the wheel is rotating at 1 revolution per second, we have:

f = 1 Hz, ω = 2π x 1 Hz and ω = 6.28 rad/s

The initial kinetic energy of the wheel is stated and defined as :

KEi = (1/2) x I x ω²

KEi = (1/2) x 0.3125 kg m² x (6.28 rad/s)²

KEi = 6.18 J

To bring the wheel to rest in 1 second, the work done by the brakes must be equal to the initial kinetic energy of the wheel. The work done by a force is presented by the equation below :

W = F x d

(Here F is the force exerted, and d is the distance over which the force is put. In this mentioned case, the force is put over the radius of the wheel, which is as equal to as 0.5 m. So, we are having :

W = F x 0.5 m

On calculating out this to the initial kinetic energy of the wheel, we will be getting,

F x 0.5 m = 6.18 J

In order to get F, we get:

F = 2 x 6.18 J / 1 s

F = 12.36 N

Therefore, the force that is to be put on the brake is calculated out being 12.36 N.

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The Kinetic energy possessed by the cycle with a mass of 100 kg and velocity 40 m/s is 80 kJ.

Kinetic energy is the energy of an object when the object is in motion. It is obtained by the product of the mass of the object and the velocity of the object. The unit of kinetic energy is the joule (J).

From the given,

mass of the motorcycle (m) = 100 kg

velocity (v) = 40 m/s

K.E =?

K.E = (mv²) / 2

     = (100×40×40) / 2

    = 160,000 / 2

   = 80,000 J

Thus, the kinetic energy of the motorcycle is 80kJ.

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The normal force acting on the block is approximately 16.0 N.

According to the question, the inclined surface is frictionless, therefore  the force of gravity is the only force acting on the block and the force applied by the horizontal force F.

The force of gravity acting on the block is given by:

F(gravity) = m * g

where m is the mass of the block, and g is the acceleration due to gravity (9.8 m/[tex]s^{2}[/tex] ).

So, F(gravity) = 2.0 kg * 9.8 m/[tex]s^{2}[/tex]

                      = 19.6 N

The force F is acting at an angle of 37° from the horizontal. By resolving the force into its components along the x and y axes, the normal force can be calculated

The component of the force F along the y-axis is equal to:

F(y axis)= F * sin(37°)

             = 6 N * sin(37°)

             ≈ 3.6 N

Since the surface is frictionless, the block is not moving in the vertical direction, and so the net force acting on it in the y-direction must be zero.

Therefore, the normal force acting on the block is equal in magnitude to the force of gravity, and is given by:

F(normal) = F(gravity) - F(y axis)

F(normal) = 19.6 N - 3.6 N

                ≈ 16.0 N

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Answer:

We can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration, to solve this problem.

The force on the tackle dummy can be calculated as follows:

F = m * a

F = 75.0 kg * 3.00 m/s^2

F = 225 N

According to Newton's third law of motion, for every action, there is an equal and opposite reaction. Therefore, the force on the football player is also 225 N, but in the opposite direction to the force on the tackle dummy.

So the force on the football player is 225 N, directed opposite to the direction of the tackle dummy's acceleration.

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The force on the football player is 150.0N.

To calculate the force on the football player, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration. In this case, the mass of the football player is 50.0kg and the acceleration is 3.00 m/s2. Therefore, the force on the football player is:

Force = mass x acceleration

Force = 50.0kg x 3.00 m/s2

Force = 150.0 N

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The lamp exhibits a constant obstruction, which is a quality of a conductor that abides by Ohm's law.

The relationship amongst the three variables in a circuit with electricity can be calculated using Ohm's Law. Ohm's Law (E = IR) is as crucial to electronics students as Einstein's Physics equation (E = mc2) is to physicists in terms of its fundamental importance. E = I x R.

The law is named after German mathematician Georg Ohm, who in an 1827 dissertation documented measurements pf applied current as well as voltage over straightforward electrical circuits with a range of wire lengths.

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Answer:

The Correct answer is D

molecules of liquid are stationary

The initial horizontal velocity of the stone is 29 m/s.

The initial vertical velocity of the stone is 0 m/s.

The time of motion of the stone is calculated as follows;

h = V₀yt + ¹/₂gt²

where;

Since the stone is projected horizontally, the initial vertical velocity = 0

h = ¹/₂gt²

t = √(2h/g)

t = √(2 x 31/9.8)

t = 2.52 s

The initial horizontal velocity of the stone is calculated as follows;

d = V₀ₓt

V₀ₓ = d/t

V₀ₓ = 73 m / 2.52 s

V₀ₓ = 29 m/s

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