Franklin is observing an object that is taking in energy at the same rate it is giving energy off.
What is true about this object?

We are given two points on the distance-time graph: (1, 40) and (3,130)

This means that:

At time 1 hour, the distance traveled was 40 km

At time 3 hours, the distance traveled was 130 km

We want to find the average speed during this 2 hour interval (from 1 hour to 3 hours).

Average speed is defined as:

Average Speed = Change in Distance / Change in Time

The change in distance is the distance traveled from 1 hour to 3 hours, which is 130 km - 40 km = 90 km

The change in time is 3 hours - 1 hour = 2 hours

Average Speed = 90 km / 2 hours

= 45 km/hr

Therefore, the average speed during this interval of time is 45 km/hr.

The speed of the car traveling 58 meters in 20 seconds is 2.9 m/s.

Speed is the rate of chnage of distance. The S.I unit of speed is meter per seconds (m/s).

To calculate the speed of the car, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

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Answer:

3rd baseman is the correct answer. pls mark me as brainliest

Uranus average distance from the Sun is roughly 0.215 times (or 21.5%) that of Earth.

We may use Kepler's third law of planetary motion to calculate Uranus' average distance from the Sun as a multiple of Earth's average distance from the Sun.

The square of a planet's orbital period is related to the cube of its average distance from the Sun, according to this rule.

Let us represent the average distance from the Sun to Earth as "a" and the average distance from the Sun to Uranus as "x" (both in the same unit, such as astronomical units - AU).

We may solve the following equation using Kepler's third law:

([tex]a^3[/tex]) = [tex](x^3) * (T^2)[/tex]

Where T is Uranus' orbital period, which is stated as 84 years.

([tex]a^3[/tex]) =[tex](x^3) * (84^2)[/tex]

To get the x/a ratio, divide both sides of the equation by [tex]a^3[/tex]: 1 = ([tex]x^3[/tex]) * [tex](84^2) / (a^3)[/tex]

We can now isolate x by taking the cube root of both sides:

x =[tex](a^3)^(1/3) / (84^2)^(1/3)[/tex]

Simplifying even more:

x = a / [tex](84^2)^{(1/3)[/tex] x = a / 4.648.

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Answer:

59.49 kilograms.

Explanation:

To find the total mass, we can divide the weight by the acceleration due to gravity (9.81 m/s^2) to get each object's mass.

314 Newtons / 9.81 m/s^2 = 32.03 kilograms

271 Newtons / 9.81 m/s^2 = 27.62 kilograms

Therefore, the total mass is:

314 Newtons + 271 Newtons = 585 Newtons

We can find the total mass of each object in kilograms:

585 Newtons / 9.81 m/s^2 = 59.49 kilograms

Hence, the total mass of the two objects is 59.49 kilograms.

(a) The amount of gravitational potential energy possessed by the object at the given height is 147.

(b) The kinetic energy, KE the object have just before hitting the ground is 147 J.

The amount of gravitational potential energy possessed by the object at the given height is calculated as follows;

GPE = mgh

where;

GPE = 5 kg x 9.8 m/s² x 3 m

GPE = 147 J

Based on the law of conservation of energy, the amount of kinetic energy possessed by the object just before hitting the ground will the same as the gravitational potential energy at the initial height.

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Approximately 3,299.9 J of energy was transferred into thermal energy during the fall of the diver.

To determine the amount of energy transferred into thermal energy during the fall of the diver, we can use the principle of conservation of energy.

The initial potential energy of the diver at the maximum height is given by:

Potential Energy (PE) = m * g * h

Where:

m = mass of the diver (48.0 kg)

g = acceleration due to gravity (9.8 m/s^2)

h = maximum height (11.0 m)

Substituting the given values:

PE = 48.0 kg * 9.8 m/s^2 * 11.0 m = 5,219.2 J

The final kinetic energy of the diver just before hitting the pool is given by:

Kinetic Energy (KE) = (1/2) * m * v^2

Where:

m = mass of the diver (48.0 kg)

v = speed of the diver (8.81 m/s)

Substituting the given values:

KE = (1/2) * 48.0 kg * (8.81 m/s)^2 = 1,919.3 J

The difference between the initial potential energy and the final kinetic energy represents the energy transferred into thermal energy:

Energy transferred into thermal energy = PE - KE

                                     = 5,219.2 J - 1,919.3 J

                                     = 3,299.9 J

Therefore, approximately 3,299.9 J of energy was transferred into thermal energy during the fall of the diver.

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Answer:

Explanation:

When an object is added to a washing system during rotation, several factors can contribute to a slowdown in the system. Here are a few reasons why this might occur:

1.Increased mass: Adding a material object to the washing system increases its overall mass. As a result, the rotational inertia of the system also increases. Rotational inertia is a measure of an object's resistance to changes in its rotational motion. With a higher rotational inertia, more torque or force is required to maintain or change the rotational speed. Therefore, the system may slow down due to the increased mass and rotational inertia.

2.Increased frictional forces: The addition of a material object can introduce additional contact points and surfaces within the washing system. This can lead to increased frictional forces between the object and the rotating components, such as the walls or paddles of the washing machine. Friction opposes motion and acts as a resistance force, causing the system to slow down as more friction is generated.

3.Energy transfer: When an object is added to the washing system, energy is transferred from the rotating components to the added object. This energy transfer can be in the form of collisions or interactions between the rotating parts and the object. As a result, the rotational kinetic energy of the system decreases, leading to a slowdown in the rotational speed.

Raju's statement is not correct fully as it states that uniform motion is seen only in objects traveling in a straight line while ,Tejas is correct in pointing out that uniform motion can also be observed in objects traveling in circular motion. 

Uniform motion refers to the movement of an object at a constant speed in a particular direction. In this type of motion, the object covers equal distances in equal intervals of time. Suppose for example (straight line movement), a car moving on a straight road at a constant speed of 60 km/h. If the car maintains this speed without any change in direction, it exhibits uniform motion. Other example is regarding the object moving in circular path where  a race car driving around a circular track with a radius of 100 meters. If the car maintains a constant speed of 40 meters per second and completes each lap in the same amount of time, it exhibits uniform motion. Therefore, Tejas' justification is valid, as he states that uniform motion can indeed be observed in objects traveling in circular paths, in addition to objects moving in straight lines.

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Approximately 3,299.9 J of energy was transferred into thermal energy during the fall of the diver.

To determine the amount of energy transferred into thermal energy during the fall of the diver, we can use the principle of conservation of energy.

The initial potential energy of the diver at the maximum height is given by:

Potential Energy (PE) = m * g * h

Where:

m = mass of the diver (48.0 kg)

g = acceleration due to gravity (9.8 m/s^2)

h = maximum height (11.0 m)

Substituting the given values:

PE = 48.0 kg * 9.8 m/s^2 * 11.0 m = 5,219.2 J

The final kinetic energy of the diver just before hitting the pool is given by:

Kinetic Energy (KE) = (1/2) * m * v^2

Where:

m = mass of the diver (48.0 kg)

v = speed of the diver (8.81 m/s)

Substituting the given values:

KE = (1/2) * 48.0 kg * (8.81 m/s)^2 = 1,919.3 J

The difference between the initial potential energy and the final kinetic energy represents the energy transferred into thermal energy:

Energy transferred into thermal energy = PE - KE

                                     = 5,219.2 J - 1,919.3 J

                                     = 3,299.9 J

Therefore, approximately 3,299.9 J of energy was transferred into thermal energy during the fall of the diver.

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If A 5kg objects is sliding across a floor at 10m/s.then the work done by friction to bring the 5 kg object to a stop is -250 Joules.

To calculate the work done by friction to bring the object to a stop, we need to determine the change in kinetic energy.

Given:

Mass of the object, m = 5 kg

Initial velocity, u = 10 m/s

Final velocity, v = 0 m/s (object comes to a stop)

The work done by friction can be calculated using the equation:

Work = Change in Kinetic Energy

The change in kinetic energy (ΔKE) can be calculated as:

ΔKE = (1/2) * m * (v^2 - u^2)

Plugging in the values:

ΔKE = (1/2) * 5 kg * (0 m/s)^2 - (10 m/s)^2

= (1/2) * 5 kg * (0 - 100 m^2/s^2)

= (1/2) * 5 kg * (-100 m^2/s^2)

= -250 J

The negative sign indicates that the work done by friction is in the opposite direction of the displacement of the object.

Therefore, the work done by friction to bring the 5 kg object to a stop is -250 Joules.

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An object with an initial velocity of 5m/s has a constant acceleration of [tex]2m/s^2[/tex] .The object has traveled a distance of 50 meters when it is speed is 15m/s how far has us travelled​

To find the distance traveled by the object, we can use the equation:

[tex]v^2 = u^2 + 2as[/tex]

where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled.

Given:

Initial velocity (u) = 5 m/s

Acceleration (a) = 2[tex]m/s^2[/tex]

Final velocity (v) = 15 m/s

We need to solve for s.

Rearranging the equation, we have:

s =[tex](v^2 - u^2)[/tex] / (2a)

Substituting the given values, we get:

s = [tex](15^2 - 5^2)[/tex]/ (2 * 2)

s = (225 - 25) / 4

s = 200 / 4

s = 50 m

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Based on the information, it should be noted that the resistance R is 0.5 Ω.

When S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:

Z = jωL - 1/(jωC)

Since i leads e by 30°, we can express the phasor relationship as:

I = k * e^(j(ωt + θ))

Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)

Re(Z) = 0

By equating the real parts, we get:

0 = 0 - 1/(120πC)

Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:

Z = R + jωL - 1/(jωC)

Z = R + jωL

Im(Z) = ωL > 0

Substituting the angular frequency and rearranging the inequality, we have:

120πL > 0

L > 0

This condition implies that the inductance L must be greater than zero.

When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:

Z = R + jωL - 1/(jωC)

Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:

I = 0.5 * e^(j(ωt + θ))

By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:

Re(Z) = R

Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R

Therefore, the resistance R is 0.5 Ω.

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X corresponds to 20 mm on the thermometer.

To calculate the value of X, we can use the concept of linear interpolation.We can estimate a value between two known points on a straight line using linear interpolation.

In this case, we have three data points: X corresponding to an unknown temperature, 60 °C corresponding to 52 mm, and 100 °C corresponding to 50 mm.

We can set up a proportion based on the relationship between temperature and the corresponding position on the thermometer:

(60 - X) / (100 - X) = (52 - 50) / (50 - X)

Simplifying the proportion:

(60 - X) / (100 - X) = 2 / (50 - X)

Cross-multiplying:

(60 - X)(50 - X) = 2(100 - X)

Expanding and simplifying:

3000 - 110X + X^2 = 200 - 2X

Putting all terms on the same side of the equation:

X^2 - 108X + 2800 = 0

Solving this quadratic equation yields two solutions: X = 20 and X = 88.

However, since the ice and steam points on a thermometer typically correspond to 0 °C and 100 °C, respectively, we can eliminate the X = 88 solution. As a result, the value of X is 20.

Therefore, X corresponds to 20 mm on the thermometer.

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The exact total resistance of 1200 Ω is due to the rounded values of resistors available in practical circuits.

To determine the values of the resistors, we can use Ohm's Law:

Voltage (V) = Current (I) × Resistance (R)

Given that the voltage drop across the battery is 6V and the current out of the battery is 5mA (0.005A), we can calculate the total resistance:

Total Resistance (R_total) = Voltage (V) / Current (I)

R_total = 6V / 0.005A

R_total = 1200 Ω

Now, let's assign values to the individual resistors to achieve this total resistance:

R1 = 220 Ω

R2 = 470 Ω

R3 = 330 Ω

R4 = 680 Ω

R5 = 820 Ω

R6 = 350 Ω

With these values, the total resistance of the circuit would be:

R_total = R1 + (R2 || R3) + (R4 || R5) + R6

R_total = 220 Ω + (470 Ω || 330 Ω) + (680 Ω || 820 Ω) + 350 Ω

R_total ≈ 220 Ω + 214.8 Ω + 351.5 Ω + 350 Ω

R_total ≈ 1136.3 Ω

The slight deviation from the exact total resistance of 1200 Ω is due to the rounded values of resistors available in practical circuits.

Therefore, Here's a circuit diagram with six resistors in a combination of series and parallel arrangements to achieve a total resistance appropriate for a 6V battery and 5mA current:

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The amount of energy lost to friction, sound, and other factors during the collision is 48620.15 J.

In the event of a car collision, the momentum of the two vehicles changes as a result of the impact, and energy is transferred from one vehicle to the other.

The impact will result in a loss of energy due to friction, sound, and other factors. Therefore, to calculate the amount of energy lost during the collision, we need to determine the total kinetic energy of the system before and after the collision, and the difference between the two is the energy lost.

To calculate the initial kinetic energy, we need to use the formula 1/2mv², where m is the mass of the object and v is its velocity. Therefore, the initial kinetic energy of car 1 is:KE1 = 1/2 x 1300 kg x (12.5 m/s)² = 101562.5 J The stationary car has no initial kinetic energy since it is at rest.

The total initial kinetic energy of the system is therefore: KE initial = KE1 + KE2 = 101562.5 J To calculate the final kinetic energy, we need to use the velocity of the two cars after the collision.

The problem states that the two cars slide off with a velocity of 6.3 m/s. Therefore, the final kinetic energy of the system is: KE final = 1/2 x (1300 kg + 1500 kg) x (6.3 m/s)² = 52942.35 J.

The energy lost during the collision is the difference between the initial and final kinetic energy: Energy lost = KE initial - KE final = 48620.15 J.

Therefore, the amount of energy lost to friction, sound, and other factors during the collision is 48620.15 J.

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Taking into account the definition of kinetic energy, the velocity of the object with a kinetic energy of 250 J and a mass of 32 kg is 3.95 m/s².

Kinetic energy is the energy possessed by a body or system due to its movement.

Kinetic energy is defined as the amount of work necessary to accelerate a body of a certain mass and in a position of rest, until it reaches a certain speed. Once the final speed is reached, the amount of kinetic energy accumulated will remain constant, that is, it will not vary, unless another force acts on the body again.

Kinetic energy is represented by the following expression:

Ec = 1/2×m×v²

Where:

In this case, you know:

Replacing in the definition of kinetic energy:

250 J = 1/2× 32 kg×v²

Solving:

250 J÷ (1/2× 32 kg) = v²

15.625 J÷kg = v²

√15.625 J÷kg = v

3.95 m/s² = v

Finally, the velocity of the object is 3.95 m/s².

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Answer:

The correct difference between chronic and acute stress is:

Acute stress is short-term, while chronic stress endures over time.

Explanation:

Acute stress refers to the immediate and temporary response of the body to a specific stressful event or situation. It is often characterized by a rapid increase in heart rate, heightened alertness, and the release of stress hormones like adrenaline. Acute stress is a normal and natural response to perceived threats or challenges, and once the stressor is removed or resolved, the body returns to its normal state.

On the other hand, chronic stress is long-term and persists over an extended period. It is typically caused by ongoing or recurring stressors, such as work pressures, financial difficulties, relationship problems, or chronic health conditions. Chronic stress can have a cumulative and prolonged impact on physical and mental well-being. It may lead to a range of health issues, including cardiovascular problems, weakened immune system, digestive disorders, anxiety, depression, and burnout.

Chronic stress is considered detrimental to overall health, while acute stress, when experienced in moderation, can actually be beneficial as it can enhance performance and help individuals deal with immediate challenges. It is important to manage chronic stress effectively through stress-reducing techniques, self-care practices, and seeking support when needed to prevent its negative consequences on health and well-being.

The slope of the graph is 0.5 m/s² and when t = 1.5 s, the predicted displacement (d) of the object is 0.75 meters.

To plot the velocity vs. time graph, we'll use the given data points:

Duration, At (s): 2.0, 4.0, 6.0, 8.0, 10.0, 12.0

Velocity, v (m/s): 6.0, 7.0, 8.0, 9.0, 10.0, 11.0

Let's plot these points on a graph:

Time (s) [x-axis] | Velocity (m/s) [y-axis]

--------------------------------------------

2.0               | 6.0

4.0               | 7.0

6.0               | 8.0

8.0               | 9.0

10.0              | 10.0

12.0              | 11.0

After plotting the points, we can connect them with a straight line to represent the motion of the object. This line represents the velocity vs. time relationship.

Now, let's calculate the slope of this line. The slope of a line represents the rate of change of the dependent variable (velocity) with respect to the independent variable (time). In this case, it gives us the acceleration of the object.

Using the formula for calculating the slope of a line:

Slope (k) = (Change in velocity) / (Change in time)

For the first two points:

Change in velocity = 7.0 - 6.0 = 1.0 m/s

Change in time = 4.0 - 2.0 = 2.0 s

Slope (k) = 1.0 m/s / 2.0 s = 0.5 m/s²

Therefore, the slope of the graph is 0.5 m/s².

Now, to answer part B, the physical significance of the slope value is that it represents the object's acceleration. In this case, the constant acceleration experienced by the object is 0.5 m/s².

Moving on to part C, we are given the equation d = kt, where d represents the displacement and t represents time. Since the object is experiencing constant acceleration, the equation can be rewritten as d = 0.5t, where 0.5 is the acceleration (k).

To predict the value of "d" when t = 1.5 s, we can substitute the value of t into the equation:

d = 0.5 * 1.5 = 0.75 meters

Therefore, when t = 1.5 s, the predicted displacement (d) of the object is 0.75 meters.

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The probable question may be:

An object is subjected to a constant acceleration along a frictionless track. A student measures its velocity (v) after specific durations (At). The student uses a graph to analyze the truck's motion.

Duration, At, (s) :- 2.0,4.0,6.0,8.0,10.0,12.0.

Velocity, v, (m/s) :- 6.0,7.0,8.0,9.0,10.0,11.0

A. Plot the velocity (in meters/sec) vs. time (seconds). The velocity is the y-axis and time is the x-axis. Use any graphing software you like or graph this data in pencil on graph paper. Excel has a nice graphing package. Calculate the slope of this graph. You will

B. What is the physical significance of the slope value computed in part A?

C. Having determined the slope of the line, you can now write d = kt. Use this equation to predict a value of "d" when t = 1.5 s.

The dimensions of V/t = [L][T]⁻¹ / [M][L]⁻¹ = [T]⁻¹[M]⁰[L]⁰.

And the dimensions of V/u = [L][T]⁻¹ / [M][L][T]⁻² = [T]⁻¹[M]⁰[L]⁰.

Since both expressions have the same dimensions, the equation V = t/u is dimensionally correct.

To show that the given equation for the velocity of a transfer wave in a wire under tension is dimensionally correct, let's analyze the dimensions of each variable involved.

The velocity of the transfer wave (V) has the dimension of length divided by time, which is represented as [L]/[T].

The tension in the wire (T) has the dimension of force, represented as [M][L]/[T]^2, where [M] denotes mass.

The linear density of the wire (u) represents the mass per unit length and has the dimension of mass divided by length, denoted as [M]/[L].

The time (t) represents the duration and has the dimension of time, denoted as [T].

Now, let's substitute the dimensions of each variable into the given equation V = t/u:

[L]/[T] = [T] / ([M]/[L])

By rearranging the equation, we have:

[L]/[T] = [L] / ([M]/[T]^2)

Multiplying both sides by [T]^2 and simplifying, we get:

[L][T]^2 = [L][T]^2

The dimensions on both sides of the equation are equal, which demonstrates that the equation is dimensionally correct.

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The wavelength of the closed pipe, given the level the water moves up to, would be B. 5120.

The pipe, when it resonates with a sound wave, acts as a pipe closed at one end. The length of the air column in the pipe is the part of the pipe that is above the water.

Initially, the length of the air column is:

50cm - 40cm = 10cm

The initial wavelength (λi) is 4 times this length, or 40cm.

After being struck, the length of the air column changes to:

50cm - 45cm = 5cm

The new wavelength (λf) is 4 times this length, or 20cm. When converted, we get 5, 120.

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The wavelength is 5120m.

When the pipe reverberates with a sound wave, it behaves like a pipe that is closed at one end.

The portion of the pipe above the water is the length of the air column in the pipe.

The air column's initial length is:

50 cm - 40 cm = 10 cm.

This length, or 40cm, is the starting wavelength (i).

After being struck, the air column's length becomes:

50 cm - 45 cm = 5 cm

The new wavelength (f) is 20 cm, or four times this length.

In conversion, we obtain 5, 120.

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Even before the advent of the telescope, ancient astronomers were able to observe the following:

1. Celestial Bodies: Ancient astronomers could observe celestial bodies such as the Sun, Moon, stars, and planets. They could track their movements across the sky and study their patterns and behaviors.

2. Solar and Lunar Eclipses: By carefully observing the positions of the Sun, Moon, and Earth, ancient astronomers could predict and witness solar and lunar eclipses. They noticed that during a solar eclipse, the Moon blocks the Sun's light, creating a temporary darkness on Earth, while during a lunar eclipse, the Earth casts a shadow on the Moon, causing it to appear reddish or darkened.

3. Stellar Positions: Ancient astronomers mapped and observed the positions of stars in the night sky. They recognized patterns and constellations, which helped them navigate and keep track of time.

4. Seasons and Celestial Movements: By observing the changing positions of the Sun and its daily and yearly motions, ancient astronomers could understand the changing seasons. They could determine solstices, equinoxes, and the length of days and nights.

5. Comet Appearances: Ancient astronomers were able to observe and document the appearance of comets in the night sky. They recognized these celestial objects as distinct from stars and noted their unusual and transient nature.

These observations formed the basis of ancient astronomy and laid the groundwork for the development of more advanced astronomical techniques and instruments, including the telescope.

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As per the given scenario, in this case, the coefficient of friction () is half and the coefficient of restitution (e) is zero.

Identify the body's starting velocity:

We may use the equation of motion to get the body's initial velocity (u)

[tex]v^2 = u^2 + 2as[/tex]

[tex]0 = u^2 + 2(-9.8)m/s^2 * h[/tex]

[tex]u^2 = 19.6h[/tex]

u = √(19.6h)

The body's initial velocity (u) and initial relative velocity (u_rel) are the same.

The body's horizontal velocity immediately following the collision, which is zero, is the final relative velocity (v_rel).

[tex]e = v_{rel }/ u_{rel}[/tex]

e = 0 / u_rel = 0 / u

Now, one can investigate the forces affecting the body: When a body is on an inclined plane.

There are two main forces at work on it: the frictional force that prevents the body from moving and the gravitational force that pulls it downward (mg).

The gravitational force has two components that act perpendicular to and parallel to the inclined plane, respectively: m*g*cos(45°) and m*g*sin(45°).

Determine the conditions for the body to stop:

μ * N = m * g * sin(45°)

μ * (m * g * cos(45°)) = m * g * sin(45°)

μ * cos(45°) = sin(45°)

(1/2) * cos(45°) = sin(45°)

Simplifying further, we have:

√2 / 4 = √2 / 2

Thus, the body will come to rest following the collision if the equation is valid.

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A lever is one of the types of simple machine.

1. It is a first class lever

2. The image is attached here

3. The MA is 0.8

4. The MA is 0.4

The fulcrum of a first-class lever is situated halfway between the weight and the effort. In this instance, the load arm and effort arm are on either side of the fulcrum, which is positioned inside the 9 cm length of the lever. A first-class lever has a load arm that is 5 cm shorter than the effort arm and 9 cm longer.

The velocity ratio of the lever is;

Distance moved by effort/Distance moved by load

= 4/5 = 0.8

Efficiency = MA/VR * 100

100 = MA/0.8 * 100

MA = 100 * 0.8/100

MA = 0.8

To have 50% efficiency;

50 = MA/0.8 * 100

MA = 50 * 0.8/100

MA = 0.4

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Answer:

they are quantities with magnitude without direction e.g weight,

The pendulum will be moving at approximately 0.754 m/s when it passes through the lowest point of its swing.

To determine the speed of the pendulum when it passes through the lowest point of its swing, we can use the principle of conservation of mechanical energy.

At the highest point (2.9 cm above the resting position), the pendulum has gravitational potential energy. As it swings down, this potential energy is converted into kinetic energy, given by the equation:

Potential Energy (PE) = Kinetic Energy (KE)

The highest point's potential energy is given by:

PE = mgh

Where:

m = pendulum mass (4.0 kg).

g = acceleration due to gravity (9.8 m/s^2)

h = height above the resting position (2.9 cm = 0.029 m)

Substituting the values, we have:

PE = 4.0 kg * 9.8 m/s^2 * 0.029 m = 1.1356 J

Since energy is conserved, this potential energy will be completely converted into kinetic energy at the lowest point. Thus, the kinetic energy is also 1.1356 J:

KE = 1.1356 J

The following equation gives the kinetic energy:

KE = (1/2)mv^2

Where:

m = pendulum mass (4.0 kg).

v = velocity of the pendulum at the lowest point

Rearranging the equation to solve for v:

v^2 = (2KE) / m

v^2 = (2 * 1.1356 J) / 4.0 kg

v^2 = 0.5678 m^2/s^2

Taking the square root of both sides results in the following:

v ≈ 0.754 m/s

Therefore, the pendulum will be moving at approximately 0.754 m/s when it passes through the lowest point of its swing.

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Answer:

Force and pressure

Explanation:

Pressure is inversely proportional to area

Or by using:

Force and pressure

Of course a burnt nail is “ scorched “ meaning it doesn’t have that much “ power “ or it an chip away

Force and pressure

Option. (B) The crest of one wave overlaps with the trough of another  is the best description of the destructive interference of light. The statement Option (B) Radio waves have longer wavelengths and lower frequencies than microwaves correctly compares radio waves and microwaves. Exposure to Option (A) infrared radiant energy is sensed by human skin as warmth. prism produces the colors of the rainbow from white light Option (C) by separating the light of different wavelengths. Option(C) Light moves in a straight line except at surfaces between different transparent materials, where its path bends.

Question 2The best description of the destructive interference of light is when the crest of one wave overlaps with the trough of another wave.

Destructive interference occurs when two waves combine to form a wave of lower amplitude.

When this happens, the crest of one wave overlaps with the trough of another, reducing the overall amplitude of the wave.

Question 4Radio waves have longer wavelengths and lower frequencies than microwaves.

This implies that they also have lower energy and are less dangerous than microwaves.

Microwaves have shorter wavelengths, higher frequencies, and higher energy than radio waves.

Question 6Exposure to infrared radiant energy is sensed by human skin as warmth.

This is because the infrared wavelengths correspond to thermal energy, which means that they cause molecules to vibrate faster and generate heat when absorbed by objects.

The sun is a source of infrared radiation that is sensed by our skin as warmth.

Question 8A prism produces the colors of the rainbow from white light by separating the light of different wavelengths.

When white light enters a prism, it is refracted and separated into its component colors because each color has a different wavelength.

This is because each color bends differently as it passes through the prism, which causes them to separate and form a rainbow of colors.

Question 10Light moves in a straight line except at surfaces between different transparent materials, where its path bends.

This bending of light is known as refraction and occurs because light travels at different speeds through different materials.

When light moves from one material to another, such as from air to glass, it changes speed and direction, causing its path to bend.

This is why lenses and prisms can be used to bend and focus light in specific ways.

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The distance between the central bright fringe and the first bright fringe on the screen is approximately 8.52E-3 meters.

In Young's double-slit experiment, the distance between the central bright fringe (m = 0) and the first bright fringe (m = 1) can be calculated using the following formula:

y = (m * λ * L) / d

where:

y is the distance between the fringes on the screen,

m is the order of the fringe (0 for the central bright fringe, 1 for the first bright fringe),

λ is the wavelength of the light,

L is the distance from the slits to the screen, and

d is the distance between the slits.

Given the values:

λ = 4.57E-7 m (blue light wavelength)

d = 2.42E-4 m (distance between the slits)

L = 4.5 m (distance from the slits to the screen)

For the central bright fringe (m = 0), the distance (y) is:

y = (0 * 4.57E-7 m * 4.5 m) / 2.42E-4 m

y = 0

Therefore, the central bright fringe coincides with the point where the two beams of light overlap.

For the first bright fringe (m = 1), the distance (y) is:

y = (1 * 4.57E-7 m * 4.5 m) / 2.42E-4 m

y ≈ 8.52E-3 m

This calculation demonstrates how the interference pattern in Young's experiment is formed, with bright and dark fringes being produced based on the constructive and destructive interference of the light waves from the two slits. The distance between these fringes depends on the wavelength of light, the separation of the slits, and the distance between the slits and the screen.

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If the volume of the solvent is increased, the additional solvent will simply dilute the solution without affecting the concentration or the amount of solute that is dissolved. The solution will still remain saturated, but the concentration of the solute will be lower due to the increased volume of the solvent.

If the volume of solvent is increased while keeping the concentration of the solution constant, the saturated solution would not change. This is because the concentration of a solution is defined as the amount of solute present in a given volume of solvent.

By increasing the volume of the solvent while keeping the concentration constant, the total amount of solute remains the same.

In a saturated solution, the solvent has dissolved as much solute as it can at a given temperature. Any additional solute added to the solution will not dissolve and will form a solid precipitate at the bottom of the container.

Increasing the volume of the solvent does not affect the amount of solute that has already dissolved and reached its maximum solubility.

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