Geometry question need help finding the answer.

Geometry Question Need Help Finding The Answer.

Answers

Answer 1

Answer: 1208.96

Step-by-step explanation:

The volume of the cylinder is [tex](\pi)(4^2)(4)=64\pi[/tex]

The volume of the prism is [tex](6)(12)(14)=1008[/tex]

So, the total volume is [tex]1008+64\pi=\boxed{1208.96}[/tex]


Related Questions

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Your Turn:
Simplify the following expressions by combining like term
1) 4x + 7 + 2x
2) -4x+3y-3x+8+2y

Answers

Answer:

[tex]\Large\boxed{1)~6x+7}[/tex]

[tex]\Large\boxed{2)~-7x+5y+8}[/tex]

Step-by-step explanation:

Question 1: 4x + 7 + 2x

Given expression

4x + 7 + 2x

Move like terms together

= 4x + 2x + 7

= (4x + 2x) + 7

Combine like terms

[tex]\Large\boxed{=6x+7}[/tex]

Question 2: -4x+3y-3x+8+2y

Given expression

-4x + 3y - 3x + 8 + 2y

Move like terms together

= -4x - 3x + 3y + 2y + 8

= (-4x - 3x) + (3y + 2y) + 8

Combine like terms

[tex]\Large\boxed{=-7x+5y+8}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

For each of the following, determine the interest rate per compounding period. 1) 12% per year, compounded weekly b) 8% per year, compounded bi-weekly c) 6% per year, compounded monthly

Answers

Using compound interest, the rates per compounding period are given as follows:

a) 0.1273 = 12.73%.

b) 0.0833 = 8.33%

c) 0.0617 = 6.17%

What is compound interest?

The amount of money earned, in compound interest, after t years, is given by:

[tex]A(t) = P\left(1 + \frac{r}{n}\right)^{nt}[/tex]

In which:

A(t) is the amount of money after t years. P is the principal(the initial sum of money). r is the interest rate(as a decimal value). n is the number of times that interest is compounded per year.

The interest rate per compounding period is given as follows:

[tex]\left(1 + \frac{r}{n}\right)^n - 1[/tex]

For item a, the parameters are:

r = 0.12, n = 52.

Hence:

[tex]\left(1 + \frac{0.12}{52}\right)^{52} - 1 = 0.1273[/tex]

For item b, the parameters are:

r = 0.08, n = 104.

Hence:

[tex]\left(1 + \frac{0.08}{104}\right)^{104} - 1 = 0.0833[/tex]

For item c, the parameters are:

r = 0.06, n = 12.

Hence:

[tex]\left(1 + \frac{0.06}{12}\right)^{12} - 1 = 0.0617[/tex]

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Micah drew a map of his neighborhood. the actual distance from his house to the school is 5.75 miles. what is the actual distance from the library to the park?

Answers

The scale factor is 2.875 miles per inch. Then the actual distance from the library to the park will be 2.875 miles.

What is dilation?

Dilation is the process of increasing the size of an item without affecting its form. Depending on the scale factor, the object's size can be raised or lowered. There is no effect of dilation on the angle.

Micah drew a map of his neighborhood. The actual distance from his house to the school is 5.75 miles. Then the scale factor is given as,

Scale factor = 5.75 / 2

Scale factor = 2.875 miles per inch

Then the actual distance from the library to the park is given as,

D = 1 x 2.875

D = 2.875 miles

The scale factor is 2.875 miles per inch. Then the actual distance from the library to the park will be 2.875 miles.

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The missing diagram is given below.

Answer:

2.875 miles per inch

Step-by-step explanation:

What are the values of a such that the average value of f(x) = 1 2x − x 2 on [0, a] is equal to 1?

Answers

The average value of the given function is [tex]f_{avg} = \frac{-2a^{2} + 6a + 6 }{6}[/tex].

According to the statement

we have given that the function f(x) and we have to find the average value of that function.

So, For this purpose, we know that the

The given function f(x) is

[tex]f(x) = -x^{2} + 2x +1[/tex]

And now integrate this function with the limit 0 to a then

[tex]f_{avg} = \frac{1}{b - a} \int\limits^a_0 {f(x)} \, dx = -x^{2} + 2x +1[/tex]

Now integrate this then

[tex]f_{avg} = \frac{1}{a} \int\limits^a_0 {-x^{2} + 2x +1} \, dx[/tex]

Then the value becomes according to the integration rules is:

[tex]f_{avg} = \frac{1}{a} \int\limits^a_0 {-\frac{x^{3} }{3} + \frac{2x^{2} }{2} +x} \,[/tex]

Now put the limits then answer will become as output is:

[tex]f_{avg} = \frac{1}{a} [ {-\frac{a^{3} }{3} + \frac{2a^{2} }{2} +a} \,][/tex]

Now solve this equation then

[tex]f_{avg} = [ {-\frac{a^{2} }{3} + \frac{2a }{2} +1} \,][/tex]

Now

[tex]f_{avg} = \frac{-2a^{2} + 6a + 6 }{6}[/tex]

This is the value which represent the average of the given function in the statement.

So, The average value of the given function is [tex]f_{avg} = \frac{-2a^{2} + 6a + 6 }{6}[/tex].

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What is the primary purpose of data democratization?
a) make data accessible to all users
b) make data inaccessible to all users

Answers

The main goal of data democratization is to make data accessible to all users. Option (a) is correct.

Given the primary goal of data democratization.

Data democratization is the ability to make information in a digital format accessible to the average end user. The goal of data democratization is to allow non-professionals to collect and analyze data without the need for outside help. This requires us to support access with an easy way for people to understand data, so they can use it to accelerate decision-making and uncover opportunities for a business. The goal is for everyone to be able to use the data at any time to make decisions without barriers of access or understanding.

Therefore, the main goal of data democratization is to make data accessible to all users.

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QPS=
Help me please! Thankss

Answers

Answer:

44°

Step-by-step explanation:

[tex]\frac{134-46}{2}=44[/tex]

.

Assume thst y varies directly with x then solve if y=4 when x=12 find y when x=-24

Answers

Answer:

-8

Step-by-step explanation:

y=(1/3)x

4 = (1/3)12

y=(1/3)(-24)

y= -8

Select the statement that describes this expression: 10 + fraction 1 over 4x (5 + 3) − 3.


A) 10 more than fraction 1 over 4 of the sum of 5 and 3, then subtract 3

B) fraction 1 over 4 of 10 times the sum of 5 and 3, minus 3

C) 3 more than 3 plus 5 multiplied by fraction 1 over 4, then add 10

D) 10 times fraction 1 over 4 plus 3 and 5, minus 3

Answers

Answer:

B

Step-by-step explanation:

because i said so

Evaluate the following integral (Calculus 2) Please show step by step explanation!

Answers

Answer:

[tex]\displaystyle \int \dfrac{x^2-4}{x^3-2x^2+x}\:\:\text{d}x=-4 \ln |x|+5 \ln|x-1|+\dfrac{3}{x-1}+\text{C}[/tex]

Step-by-step explanation:

Fundamental Theorem of Calculus

[tex]\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))[/tex]

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given integral:

[tex]\displaystyle \int \dfrac{x^2-4}{x^3-2x^2+x}\:\:\text{d}x[/tex]

Factor the denominator:

[tex]\begin{aligned}\implies x^3-2x^2+x & = x(x^2-2x+1)\\& = x(x^2-x-x+1)\\& = x(x(x-1)-1(x-1))\\ & = x((x-1)(x-1))\\& = x(x-1)^2\end{aligned}[/tex]

[tex]\implies \displaystyle \int \dfrac{x^2-4}{x^3-2x^2+x}\:\:\text{d}x=\displaystyle \int \dfrac{x^2-4}{x(x-1)^2}\:\:\text{d}x[/tex]

Take partial fractions of the given fraction by writing out the fraction as an identity:

[tex]\begin{aligned}\dfrac{x^2-4}{x(x-1)^2} & \equiv \dfrac{A}{x}+\dfrac{B}{(x-1)}+\dfrac{C}{(x-1)^2}\\\\ \implies \dfrac{x^2-4}{x(x-1)^2} & \equiv \dfrac{A(x-1)^2}{x(x-1)^2}+\dfrac{Bx(x-1)}{x(x-1)^2}+\dfrac{Cx}{x(x-1)^2}\\\\ \implies x^2-4 & \equiv A(x-1)^2+Bx(x-1)+Cx \end{aligned}[/tex]

Calculate the values of A and C using substitution:

[tex]\textsf{when }x=0 \implies -4=A(1)+B(0)+C(0) \implies A=-4[/tex]

[tex]\textsf{when }x=1 \implies -3=A(0)+B(0)+C(1) \implies C=-3[/tex]

Therefore:

[tex]\begin{aligned}\implies x^2-4 & \equiv -4(x-1)^2+Bx(x-1)-3x\\& \equiv -4(x^2-2x+1)+B(x^2-x)-3x\\& \equiv -4x^2+8x-4+Bx^2-Bx-3x\\& \equiv (B-4)x^2+(5-B)x-4\\\end{aligned}[/tex]

Compare constants to find B:

[tex]\implies 1=B-4 \implies B=5[/tex]

Substitute the found values of A, B and C:

[tex]\implies \displaystyle \int \dfrac{x^2-4}{x^3-2x^2+x}\:\:\text{d}x=\displaystyle \int -\dfrac{4}{x}+\dfrac{5}{(x-1)}-\dfrac{3}{(x-1)^2}\:\:\text{d}x[/tex]

[tex]\textsf{Apply exponent rule} \quad \dfrac{1}{a^n}=a^{-n}[/tex]

[tex]\implies \displaystyle \int \dfrac{x^2-4}{x^3-2x^2+x}\:\:\text{d}x=\displaystyle \int -\dfrac{4}{x}+\dfrac{5}{(x-1)}-3(x-1)^{-2}}\:\:\text{d}x[/tex]

[tex]\boxed{\begin{minipage}{5 cm}\underline{Terms multiplied by constants}\\\\$\displaystyle \int ax^n\:\text{d}x=a \int x^n \:\text{d}x$\end{minipage}}[/tex]

[tex]\boxed{\begin{minipage}{4 cm}\underline{Integrating} $\dfrac{1}{x}$\\\\$\displaystyle \int \dfrac{1}{x}\:\text{d}x=\ln |x|+\text{C}$\end{minipage}}[/tex]

[tex]\boxed{\begin{minipage}{4 cm}\underline{Integrating $ax^n$}\\\\$\displaystyle \int ax^n\:\text{d}x=\dfrac{ax^{n+1}}{n+1}+\text{C}$\end{minipage}}[/tex]

[tex]\begin{aligned}\implies \displaystyle \int \dfrac{x^2-4}{x^3-2x^2+x}\:\:\text{d}x & =\displaystyle \int -\dfrac{4}{x}+\dfrac{5}{(x-1)}-3(x-1)^{-2}}\:\:\text{d}x\\\\& = \displaystyle -4\int \dfrac{1}{x}\:\:\text{d}x+5\int \dfrac{1}{(x-1)}\:\:\text{d}x-3 \int (x-1)^{-2}}\:\:\text{d}x\\\\& = \displaystyle -4 \ln |x|+5 \ln|x-1|-3 \int (x-1)^{-2}}\:\:\text{d}x\end{aligned}[/tex]

Use Integration by Substitution:

[tex]\textsf{Let }u=(x-1) \implies \dfrac{\text{d}u}{\text{d}x}=1 \implies \text{d}x=\text{d}u}[/tex]

Therefore:

[tex]\implies \displaystyle -4 \ln |x|+5 \ln|x-1|-3 \int (x-1)^{-2}}\:\:\text{d}x[/tex]

[tex]\implies \displaystyle -4 \ln |x|+5 \ln|x-1|-3 \int u^{-2}}\:\:\text{d}u[/tex]

[tex]\implies -4 \ln |x|+5 \ln|x-1|-\dfrac{3}{-1}u^{-2+1}+\text{C}[/tex]

[tex]\implies -4 \ln |x|+5 \ln|x-1|+3u^{-1}+\text{C}[/tex]

[tex]\implies -4 \ln |x|+5 \ln|x-1|+\dfrac{3}{u}+\text{C}[/tex]

Substitute back in u = (x - 1):

[tex]\implies -4 \ln |x|+5 \ln|x-1|+\dfrac{3}{x-1}+\text{C}[/tex]

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Two trains leave the station at the same time, one heading west and the other east. The westbound train travels at miles per hour. The eastbound train travels at miles per hour. How long will it take for the two trains to be miles apart

Answers

Answer:

one hour

Step-by-step explanation:

if they are going the same speed going differnet directions they will be 2 miles apart after one hour

In a charity triathlon, Mark ran half the distance and swag a quarter of the distance. When he took a quick break to get a drink of Gatorade, he was just starting to bike the remaining 17 miles. What was the total distance of the race?

Answers

Answer:

  68 miles

Step-by-step explanation:

The total distance can be determined from the fractions.

Solution

Let d represent the total distance of the race.

The distance running is 1/2d. The distance swimming is 1/4d. The remaining distance is 17 miles.

  Remaining = total distance - distance running - distance swimming

  17 mi = d -1/2d -1/4d = 1/4d . . . . . . . . use known fractions

  68 mi = d . . . . . . . multiply by 4

The total distance of the race is 68 miles.

__

Additional comment

This would be a very difficult race. A typical "iron man" race has a swimming distance under 2.5 miles, less than 1/10 of the distance running. The biking distance is typically about 4 times the running distance of "only" 26 miles. An iron man race can take about 17 hours to complete.

This race has a 17-mile swimming segment, which would take a fast swimmer on the order of 8 hours, by itself. (This is 2.7 times the length of a "marathon" swim.) Here, the running distance is 34 miles, about 30% longer than a marathon.

Quick algebra 1 question for 10 points!

Only answer if you know the answer, quick shout-out to tariqareesha2 and MrBrainly, tysm for the help!

Answers

[tex]denote \: by \: s \: the \: cost \: of \: a \: sweatshirt \\ denote \: by \: t \: the \: cost \: of \: a \: t \: shirt[/tex]

[tex]3t + 7s = 240.5 \\ 6t + 5s = 220[/tex]

[tex] - 6t - 14s = - 481 \\ 6t + 5s = 220[/tex]

[tex] - 9s = - 261 \\ s = \frac{ - 261}{ - 9} = 29 \: dollars[/tex]

[tex]3t + 7(29) = 240.5 \\ [/tex]

3t + 203 = 240.5

3t = 37.5

t = 12.5 dollars

PLEASE HELP!!
Find the value of the following expression:
(2^8 ⋅ 5^−5 ⋅ 19^0)^−2 ⋅ (5^-2/2^3)^4 ⋅ 2^28

Write your answer in simplified form. Show all your steps.

Answers

Answer:

25

Step-by-step explanation:

Cancel out 19^0, then exponentiate and simplify by multiplying exponents. Then simplify the terms. This leaves you with 2^-16*5^10*5^-8*2^16 which equals 5^2 which is 25

If the sum of the interior angles of a regular polygon is 1620°, what is the measure of one exterior angle. Round to the nearest tenth.

Answers

[tex]\textit{sum of all interior angles in a polygon}\\\\ S =180(n-2) \begin{cases} n=\stackrel{number~of}{sides}\\[-0.5em] \hrulefill\\ S =1620 \end{cases}\implies 1620=180(n-2) \\\\\\ \cfrac{1620}{180}=n-2\implies 9=n-2\implies \underline{11=n} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\textit{sum of all exterior angles in a regular polygon}\\\\ n\theta = 360 \begin{cases} n=\stackrel{number~of}{sides}\\ \theta =\stackrel{angle~in}{degrees}\\[-0.5em] \hrulefill\\ \underline{n=11} \end{cases}\implies 11\theta =360\implies \theta =\cfrac{360}{11}\implies \theta \approx 32.7^o[/tex]

Interior angles of a regular polygon

A regular polygon is a figure in which all the sides have the same length that is, they are equal and all the interior angles are of the same measure.

The formula to calculate the interior angles of any regular polygon is:( n - 2 ) 180°

This regular polygon is a hendecagon.

A hendecagon is a polygon that has 9 equal sides.

If the sum of the interior angles is 1620°, then

( n - 2 ) 180° = 1620

As a second step, we divide by 180:

( n-2 ) = 1620 ➗ 180

We divide

n - 2 = 9

We change the direction, as the sign is negative, in the change of direction it starts to add.

n = 9 + 2

We add both numbers.

n = 11

Answer: the measure of the exterior angle of the regular polygon (hendecagon) is 11. ✅

Does anyone know the answer to this question? I’ve been staring at this for a solid 20mins but can’t figure it out.

Answers

[tex]\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}[/tex]

A linear function is an equation of the form:

[tex]\sf{y=mx+b}[/tex]

[tex]\sf{m= \: slope}[/tex]

[tex] \sf{b= \: y-intercept}[/tex]

First, pick any two pairs of points from the table.

[tex]\small\longrightarrow \sf{(x_1,y_1)(-1.13)}[/tex]

[tex]\small\longrightarrow \sf{(x_2,y_2)=(0,10)}[/tex]

Using these points, find the slope.

[tex]\small\longrightarrow \sf{m= \dfrac{y _{2 } - y_1}{x_2-y_1} }[/tex]

When x=0, y=10, therefore, the y-intercept, b=10.

[tex]\leadsto[/tex] Substitute m=-3 and b=10 into the slope-intercept form given above:

[tex]\small\longrightarrow \sf{m=m = \dfrac{10 - 13 }{0 -( - 1) } = - \dfrac{3}{1} = - 3}[/tex]

[tex]\small\longrightarrow \sf{y= -3x+10}[/tex]

[tex]\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}[/tex]

[tex]\large\boxed{\bm{y= -3x+10}}[/tex]

Calculate the amount of heat (in kJ) released when 3.5 mol CH4 react. 4() + 22() → 2() + 22() + 890

Answers

The amount of heat (in KJ) released when 3.5 moles of CH₄ react is 3115 KJ

Balanced equation

CH₄ + 2O₂ -> CO₂ + 2H₂O ΔH = 890 KJ

From the balanced equation above,

1 mole of CH₄ reacted to release 890 KJ of heat energy.

How to determine the heat energy released by 3.5 moles of CH₄

From the balanced equation above,

1 mole of CH₄ reacted to release 890 KJ of heat energy

Therefore,

3.5 moles of CH₄ will react ro release = 3.5 × 890 = 3115 KJ of heat energy

Thus, 3115 KJ of heat energy were released from the reaction

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the x and y intercept

Answers

Answer:

Step-by-step explanation:

X-INTERCEPT

Plug y=0 into the equation and solve the resulting equation −6x=−7 for x.

The x-intercept:

[tex]\left(\frac{7}{6},0\right)\approx \left(1.16666666666667,0\right)[/tex]

Y-INTERCEPT

Plug x=0 into the equation and solve the resulting equation 3y=−7 for y.

The y-intercept:

[tex]\left(0, - \frac{7}{3}\right)\approx \left(0,-2.33333333333333\right)[/tex]

Answer:

[tex]x[/tex]-intercept = ([tex]-\frac{7}{6}[/tex]  , 0)

[tex]y[/tex]-intercept = (0 , [tex]-\frac{7}{3}[/tex])

Step-by-step explanation:

[tex]6x + 3y = -7[/tex]

• The x-intercept is the point at which the line crosses the x-axis, that is, where y = 0.

∴ [tex]6x + 3(0) = -7[/tex]

⇒ [tex]6x = -7[/tex]

⇒ [tex]x = \bf -\frac{7}{6}[/tex]

∴ The x-intercept is at the point ([tex]-\frac{7}{6}[/tex] , 0).

• Similarly, the y-intercept is the point at which the line crosses the y-axis, that is, where x = 0.

∴ [tex]6(0) + 3y = -7[/tex]

⇒ [tex]3y = -7[/tex]

⇒ [tex]y = \bf - \frac{7}{3}[/tex]

∴ The y-intercept is at the point (0 , [tex]-\frac{7}{3}[/tex]).

Complementary angles have measures (4x)° and (5x−27)°. find the measure of the larger angle.

Answers

Answer:

4x=90

X=90÷4

X=22.5

5x-27=90

5x=90+27

5x=117

X=117÷5

X=23.4

So 23.4 is a larger angle

A point P lies on the line with equation y= 4-3X. The point P is a distance √34 from the origin. Find the two possible positions Of point P

Answers

The two possible positions of point P are:

(3, -5) and (0.6, 5.8)

How to find the two possible positions of point P?

We know that point P lies on the line:

y = 4 - 3*x

And that the distance between P and the origin is √34, then if the coordinates of point P are (x, y), we have that:

[tex]\sqrt{34} = \sqrt{x^2 + y^2}[/tex]

Now, we can replace "y" in the distance equation by the linear equation, and also remove the square roots:

[tex]34 = x^2 + (4 - 3x)^2[/tex]

Now we can solve the quadratic equation for x:

[tex]34 = x^2 + 9x^2 + 16 - 24x\\\\10x^2 - 24x - 18 = 0\\\\[/tex]

The solutions are:

[tex]x = \frac{24 \pm \sqrt{(-24)^2 - 4*10*(-18)} }{2*10} \\\\x = \frac{24 \pm36}{20}[/tex]

So the two solutions are:

x = (24 + 36)/20 = 3

x = (24 - 36)/20 = -0.6

To get the points, we need to evaluate y on these values:

y = 4 - 3*3 = -5   So we have P = (3, -5)

y = 4 - 3*(-0.6) = 2.2 So we have the point (0.6, 5.8)

There are the two possible positions of point P.

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what is 155x60cm into square inches

Answers

Answer:

1441.503 square inches

Step-by-step explanation:

155×60cm=9300square centimeter

9300 divide 6.452 to change to square inches.

Ans=1441.503

Answer:

64.58 sq.in

Step-by-step explanation:

Using a sample to make generalizations about an aspect of a population is called?

Answers

It is known as Statistical Inference.

Statistical Inference

Without sampling and statistical estimation of the value, some population parameters cannot ever be known. Take customer preference samples, for instance. Since asking everyone would be impractical, choose a sample to identify the parameter.A population's mean can be estimated quite well using the confidence interval. It offers a spectrum of values that most likely includes the population mean. The interval gets smaller as sample size increases.The method of ordinary least squares is used in a regression equation to develop an equation that best fits the data of an independent variable and dependent variable.

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help help help help help help help help help help help

Answers

Solving the quadratic equation we conclude that:

The maximum height is 45ft.The rocket is 18 seconds in the air.

How to get the maximum height of the rocket?

The height of the rocket is defined by the quadratic equation:

[tex]d = 90t - 5t^2[/tex]

The maximum height is what we get in the vertex of the quadratic equation, such that for this quadratic equation, the vertex is at:

[tex]t = -90/(2*-5) = 9[/tex]

So the maximum height is what we get when we evaluate in t = 9:

[tex]d = 90*9 - 5*9^2 = 45[/tex]

The maximum height is 45ft.

How to get the time in the air?

Now we need to solve the equation for the largest value of t:

[tex]d = 90*t - 5t^2 = 0[/tex]

Rewriting it, we get:

[tex]0 = 90*t - 5*t^2\\\\0 = t*(90 - t*5)[/tex]

The maximum solution is what we get when:

0 = 90 - t*5

t = 90/5 = 18

The rocket is 18 seconds in the air.

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Please help me. i dont get it

Answers

Step-by-step explanation:

let's say one integer is X ....

so , Another one is (X -4).....

so , X × (X - 4) = 45

x² - 4x - 45 = 0

x² - 9x + 5x - 45 = 0

x(x - 9) +5(x - 9) = 0

(x-9) × (X+5) = 0

x-9 = 0 OR x+5 = 0

X= 9 X= -5

X is not a negative integer ......

so , X = 9

X-4 = 5 .......

Given the following coordinates complete the reflection transformation.

A(1,−5)

B(2,−2)

C(5,−2)

Transformation: Complete the double reflection over the lines y=−1 followed by y=1.

Answers

The double reflection generates the following three points: A''(x, y) = (1, - 1), B''(x, y) = (2, 2) and C''(x, y) = (5, 2).

How to generate a set of point by rigid transformations

In this problem we must apply two rigid transformations to find three points. The formula for reflection over an axis parallel to the y-axis is defined below:

P'(x, y) = (x', k) - [P(x, y) - (x', k)]     (1)

Where:

x' - x-coordinate of the point P(x, y).P(x, y) - Original pointP'(x, y) - Resulting point

If we know that A(x, y) = (1, - 5), k = - 1 and k' =  1, then the resulting points are:

Point A

A'(x, y) = (1, - 1) - [(1, - 5) - (1, - 1)]

A'(x, y) = (1, - 1) - (0, - 4)

A'(x, y) = (1, 3)

A''(x, y) = (1, 1) - [(1, 3) - (1, 1)]

A''(x, y) = (1, 1) - (0, 2)

A''(x, y) = (1, - 1)

Point B

B'(x, y) = (2, - 1) - [(2, - 2) - (2, - 1)]

B'(x, y) = (2, - 1) - (0, - 1)

B'(x, y) = (2, 0)

B''(x, y) = (2, 1) - [(2, 0) - (2, 1)]

B''(x, y) = (2, 1) - (0, - 1)

B''(x, y) = (2, 2)

Point C

C'(x, y) = (5, - 1) - [(5, - 2) - (5, - 1)]

C'(x, y) = (5, - 1) - (0, - 1)

C'(x, y) = (5, 0)

C''(x, y) = (5, 1) - [(5, 0) - (5, 1)]

C''(x, y) = (5, 1) - (0, - 1)

C''(x, y) = (5, 2)

The double reflection generates the following three points: A''(x, y) = (1, - 1), B''(x, y) = (2, 2) and C''(x, y) = (5, 2).

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Three students want to estimate the mean word length of the same book. To do this, each student randomly chose 4 words from the book and recorded their lengths. The samples are shown in the table. (a)Fill in the sample means in the table. Do not round your answers. (number of letters) Sample mean 3, 3, 4, 7 - 8, 2, 3, 6 - 8, 5, 2, 4 (b)Use the table to calculate the range of the sample means. Range of sample means: (c)The students are going to use the sample means to estimate the mean word length in the book. Select all the true statements below. The mean of the sample means will tend to be a worse estimate than a single sample mean. A single sample mean will tend to be a worse estimate than the mean of the sample means. The closer the range of the sample means is to 0, the more confident they can be in their estimate. The farther the range of the sample means is from 0, the more confident they can be in their estimate.

Answers

The solutions to the questions are given below

a)

sample(n) word length sample mean

1                    5,4,4,2    3.75

2                    3,2,3,6     3.5

3                         5,6,3,3    4.25


b)R =0.75

c)

The mean of the sample means will tend to be a better estimate than a single sample mean.The closer the range of the sample means is to 0, the more confident they can be in their estimate.

What is the students are going to use the sample means to estimate the mean word length in the book.?

The table below shows sample means in the table.

sample(n) word length sample mean

1                    5,4,4,2    3.75

2                    3,2,3,6     3.5

3                         5,6,3,3    4.25

b)

Generally, the equation for is  mathematically given as

variation in the sample means

R =maximum -minimum

R=4.25-3.5

R =0.75

c)

In conclusion, In most cases, the mean of many samples will provide a more accurate estimate than the mean of a single sample.

They may have a higher level of confidence in their estimate if the range of the sample means is closer to 0 than it is now.

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find the missing numbers in the following equal ratios:
[tex]\frac{?}{3} = \frac{?}{6} = \frac{8}{?} = \frac{16}{24}[/tex]

Answers

First blank: Dividing the numerator and denominator of 16/24 by 8 gives the unknown to be 2.

Second blank: Dividing the numerator and denominator of 16/24 by 4 gives the unknown to be 4.

Third blank: Dividing the numerator and denominator of 16/24 by 2 gives the unknown to be 12.

someone please help i will give brainliest

Answers

From the two functions function 2 has the highest maximum value.

Given two functions,one is y=-[tex]x^{2} -2x-2[/tex] and f(-2)=1,f(-1)=6,f(0)=9,f(1)=10,f(2)=9,f(3)=6.

We ae required to choose a function which is having highest maximum possible value.

Function is like a relationship between two or more variables expressed in equal to form. Each value of x of a function has some value of y.

The highest value in the second function is 10 which is at x=1. Put the value of x=1 in y=-[tex]x^{2} -2x-2[/tex].

y=-1-2-2

y=-5

So it might not be highest value of this function.So the second function has highest maximum value of 10 at x=1.

Hence the second function has highest value.

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Using a calculator, circle the best price for a single doughnut using the prices given at five different bakeries.

a. $.42 each
b. 3 for $1.38
c. 9 for $3.60
d. 1 dozen for $6.00
e. 1/2 dozen for $2.70

Answers

Answer:   C

Step-by-step explanation: We see that e is 6 for $2.70 and d is 12 for $6.00.  Half of 6 is 3 and 2.70 is less than 3 so the cheapest price can't be d. Then, we have 9 for 3.60. 3.60 divided by 9 is 0.40 per which is cheaper than a (0.42 per) so a and d can't be the cheapest. 3 for 1.38 means 0.46 per which is more expensive than a so it also cannot be b. Now we only have c and e left. We divide 2.70 by 6 and find out that the answer is 0.45 which is also more expensive than a. So, the answer is c.

I really need help with this!! I’ll give brainliest to who ever answers!!

Answers

Answer:

a. triangle DEF's lines are all 3 times more than triangle ABC

b. triangle DEF's lines are all 3 times more than triangle ABC

c. 2.5 times 2 = 5

I hope u can elaborate a bit more :)

In a mixed school, the number of girls is 375. if the boys to girls is 4:5.how many boys are in the school

Answers

Answer:

300

Step-by-step explanation:

375 divided by 5=75

Each “1”=75

4x75=300

There are 300 boys.

Hope this makes sense

Answer:

300 boys

Step-by-step explanation:

Let the number of boys = x

Girls: 375

boys : girls = 4 : 5

total in the ratio is 9

girls are 5/9 of total, and are 375

boys are 4/9 of total

5/9 x = 375

x = 375 × 9/5

x = 675

Boys are 4/9 of total.

4/9 × 675 = 300

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