Gina was working in the laboratory on an experiment involving the population of bacteria. If her initial starting amount in a petri dish was 125 bacteria, how many would be in the petri dish after 24 hours?

Answers

Answer 1

Answer:

It would be a lot of bavgeria

Answer 2

Answer:

450000

Step-by-step explanation:

125×(60×60)

=125×3600

=450000


Related Questions

A department store sells a pair of shoes with an 87% markup if the store sells the shoes for 193.21 then what is their non-markup price

Answers

Answer:

103.32

Step-by-step explanation:

p = non-markup price of shoes

0.87p = amount of markup

selling price = p + 0.87p = 193.21

                        1.87p = 193.21

                        p = 103.32

check:  p + 0.87p = 193.21?

            103.32 + 89.89 = 193.21? YES

Let and y be whole-number variables such that y is the greatest whole number less than or equal to the table below lists some valuesfor and y.xy79411 513 6Which of the following statements is true?A. y changes by a constant amount when r changes by 2.OB. z changes by a constant amount when y changes by 1.C. y changes by a constant amount when changes by 1.D. 2 changes by a constant amount when y changes by 2.

Answers

we have

Verify each statement

A -------> For (7,3) and (9,4) -----> x changes by 2 and y change by 1

(9,4) and (11,5) -------> x changes by 2 and y change by 1

(11,5) and (13,6) -----> x changes by 2 and y change by 1

option A is true

B ----> option B is true

C -----> is not true

D ----> (7,3) and (11,5) ------> y changes by 2 and x changes by 4

(9,4) and (13,6) ----> y changes by 2 and x changes by 4

option D is true

step 2

Verify A, B and D

For x=14 ------> y=7

For x=16 -------> y=8

For x=18 ------> y=9

the answer must be option A

Write the expression with a single rational exponent 1/x to the -1 power

Answers

Given:

[tex]\frac{1}{x}[/tex]

To Determine: The simplified fraction to its rational exponent to the power of -1

Solution

Apply the exponent rule below

[tex]\frac{1}{a^n}=a^{-n}[/tex]

Apply the exponent rule above to the given fraction

[tex]\frac{1}{x}=x^{-1}[/tex]

Hence, 1/x = x ⁻¹

Calculating number of periods?How long will an initial bank deposit of $10,000 grow to $23,750 at 5% annual compound interest?

Answers

For an initial amount P with an annually compounded interest rate r, after t years the total amount A is is given by:

[tex]A=P(1+r)^t[/tex]

Then we have:

[tex]\begin{gathered} \frac{A}{P}=(1+r)^t \\ \ln\frac{A}{P}=t\ln(1+r) \\ t=\frac{\ln\frac{A}{P}}{ln(1+r)} \end{gathered}[/tex]

For P = $10,000, A = $23,750 and r = 0.05, we have:

[tex]t=\frac{\ln\frac{23750}{10000}}{\ln(1+0.05)}\approx17.73\text{ years}[/tex]

the missing angle men

Answers

Answer:

x = 16.

Explanation:

The angels x and 164 are supplementary, meaning they add up to 180; therefore, we can say

[tex]x+164^o=180^o[/tex]

Subtracting 164 from both sides gives

[tex]x+164^o-164^o=180^o-164^o[/tex][tex]x=16^o\text{.}[/tex]

Hence, the value of x is 16 degrees.

The vertex of this parabola is at (-2,5). Which of the following could be its equation? (-2,5) -5 O A. y = 3(x-2)2-5 O B. y = 3(x-2)2 + 5 O C. y= 3(x+ 2)2-5 BE E EIE O D. y=3(x + 2)2 + 5 anter

Answers

The base equation of a parabola is F(X) = X^2 + C

if we make F(X+2) it means the chart will move 2 units to the left

on the other hand, if the make F(X) + 5, it means the chart will displace 5 units upwards

As a result, from the given chart, our equation would be: y = 3(x+2)^2 + 5

What is the common ratio of the sequence 18,24,32…

Answers

Answer:

4/3

Explanation:

The given sequence is 18, 24, 32, ...

Then, the common ratio can be calculated as

24/18 = 4/3

32/24 = 4/3

Because 24 and 18 are consecutive numbers and 32 and 24 are consecutive numbers.

Therefore, the common ratio is 4/3

Given the following probabilities, algebraically determine if Events A and B are:• mutually exclusive or non-mutually exclusive• independent or dependent.P(A) =P(B) 0.75P(A U B)'U0.15

Answers

We know that:

[tex]\begin{gathered} P(A\cup B)^{\prime}=1-P(A\cup B) \\ P(A\cup B)^{\prime}=1-P(A)+P(B)-P(A\cap B) \end{gathered}[/tex]

Plugging the values given we have that:

[tex]\begin{gathered} 0.15=1-0.8+0.75-P(A\cap B) \\ P(A\cap B)=1-0.8+0.75-0.15 \\ P(A\cap B)=0.8 \end{gathered}[/tex]

Now, since the probability of the intersection is not zero this means that the events are non-mutually exclusive.

What is the solution to the system of equationsy = 3x - 2 and y = g(x) where g(x) is defined bythe function below?y=g(x)

Answers

we need to write the equation of the graph

it is a parable then the general form is

[tex]y=(x+a)^2+b[/tex]

where a move the parable horizontally from the origin (a=negative move to right and a=positive move to left)

and b move the parable vertically from the origin (b=negative move to down and b=positive move to up)

this parable was moving from the origin to the right 2 units and any vertically

then a is -2 and b 0

[tex]y=(x-2)^2[/tex]

now we have the system of equations

[tex]\begin{gathered} y=3x-2 \\ y=(x-2)^2 \end{gathered}[/tex]

we can replace the y of the first equation on the second and give us

[tex]3x-2=(x-2)^2[/tex]

simplify

[tex]3x-2=x^2-4x+4[/tex]

we need to solve x but we have terms sith x and x^2 then we can equal to 0 to factor

[tex]\begin{gathered} 3x-2-x^2+4x-4=0 \\ -x^2+7x-6=0 \end{gathered}[/tex]

multiply on both sides to remove the negative sign on x^2

[tex]x^2-7x+6=0[/tex]

now we use the quadratic formula

[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]

where a is 1, b is -7 and c is 6

[tex]\begin{gathered} x=\frac{-(-7)\pm\sqrt[]{(-7)^2-4(1)(6)}}{2(1)} \\ \\ x=\frac{7\pm\sqrt[]{49-24}}{2} \\ \\ x=\frac{7\pm\sqrt[]{25}}{2} \\ \\ x=\frac{7\pm5}{2} \end{gathered}[/tex]

we have two solutions for x

[tex]\begin{gathered} x_1=\frac{7+5}{2}=6 \\ \\ x_2=\frac{7-5}{2}=1 \end{gathered}[/tex]

now we replace the values of x on the first equation to find the corresponding values of y

[tex]y=3x-2[/tex]

x=6

[tex]\begin{gathered} y=3(6)-2 \\ y=16 \end{gathered}[/tex]

x=1

[tex]\begin{gathered} y=3(1)-2 \\ y=1 \end{gathered}[/tex]

Then we have to pairs of solutions

[tex]\begin{gathered} (6,16) \\ (1,1) \end{gathered}[/tex]

where green line is y=3x-2

and red points are the solutions (1,1)and(6,16)

f(x)=3x+12 find f(15)

Answers

Answer:

f(15) = 57

Explanation:

Given that

f(x) = 3x + 12

To find f(15), perform the following:

Step 1: Replace x by 15 in the given function

f(15) = 3(15) + 12

Step 2: Evaluate the expression

f(15) = 45 + 12

= 57

At what value of w does the graph have a vertical asymptote? Explain how you know and what this asymptote means in the situation.

Answers

Vertical asymptote are vertical lines which corresponds to the zeros of the denominator of our rational function. Then, the zeros of T(w) ocurr when

[tex]530-w=0[/tex]

which gives

[tex]w=530[/tex]

Therefore, the vertical asymptote is w = 530.

The asymptote is a line that the graph function approaches but never touches. In our case, this means that the speed of the wind is very close to 530 mph but never touches this value.

Simplify. Final answer should be in standard form NUMBER 18

Answers

4(2 - 3w)(w^2 - 2w + 10) =

(8 - 12w)(w^2 - 2w + 10) =

8w^2 - 16w + 80 - 12w^3 + 24w^2 - 120w =

- 12w^3 + 32w^2 - 123w + 80

1. Find the domain and range of f(x) = sqrt(x)2. Find the domain and range of f(x) = 3x + 2

Answers

We have the function:

[tex]f(x)=\sqrt[]{x}[/tex]

The domain is the set of values of x for which f(x) is defined. In this case, f(x) is defined only for non-negative values of x, so the domain is D:{x≥0}.

The range is the set of values that f(x) can take for the domain in which it is defined. In this case, f(x) will only take non-negative values, so the range can be defined as R: {y≥0}.

For the linear function f(x) = 3x+2, we don't have restrictions for the domain and the the range: both x and y can take any real value, so the domain and range are D: {x: all real numbers} and R: {y: all real numbers}.

Answer:

For the function f(x) = √x, the domain is D:{x≥0} and the range is R: {y≥0}.

For the function f(x) 3x+2, the domain is D: {x: all real numbers} and the range is R: {y: all real numbers}.

You earn $8.00 for every lawn that you mow. You went out to lunch andspent $25.75. At the end of the day, you had $94.25. Write and solve anequation to figure out howmany lawnsyou mowed.

Answers

Let individual move x lawns.

The equation for the number of lawns is,

[tex]8x-25.75=94.25[/tex]

Solve the equation to obtai the value of x.

This table represents the relationship between x and y described by the equation.y=-x1012141618SY6789Which list represents the dependent values in the table?5,6,7,8,95, 6, 7, 8, 9, 10, 12, 14, 16, 1810, 12, 14, 16, 181,2,3,4,5

Answers

ANSWER :

A. 5, 6, 7, 8, 9

EXPLANATION :

From the problem, we have the function :

[tex]y=\frac{1}{2}x[/tex]

y is the dependent variable and

x is the independent variable.

So the dependent values are the y values.

That will be 5, 6, 7, 8, 9

3. Determine - f(a) for f(x) =2x/x-1 and simplify.

Answers

Substitute a for x

[tex]-f\text{ (x ) = - f (a) = - }\frac{2a}{a-1}[/tex]

Determine - f(a) for f(x) =2x/x-1 and simplify.​

Thus, the solution becomes:

[tex]-\frac{2a}{a-1}\text{ or }\frac{2a}{1-a}[/tex]

Kennedy goes to a store an buys an item that costs xx dollars. She has a coupon for 35% off, and then a 7% tax is added to the discounted price. Write an expression in terms of xx that represents the total amount that Kennedy paid at the register.

Answers

We are given that an item has a cost xx.

First, we will calculate the 35% discount on the total price. To do that we will subtract 35% of the initial cost from the initial cost

To calculate the 35% we multiply the price by 35/100, like this:

[tex]xx\times\frac{35}{100}[/tex]

Now we subtract this from the initial price, which was "xx". Subtracting we get:

[tex]P_d=xx-xx\times\frac{35}{100}[/tex]

This is the cost with the discount. Now, we will add to this the tax of 7%. First, we calculate the 7% of the price with the discount by multiplying it by 7/100, like this:

[tex](xx-xx\times\frac{35}{100})\times\frac{7}{100}[/tex]

Now, we add this to the price with the discount, like this:

[tex]T=(xx-xx\times\frac{35}{100})+(xx-xx\times\frac{35}{100})\times\frac{7}{100}[/tex]

Now, we can simplify. We start by using the distributive property on the second parenthesis:

[tex]T=xx-xx\times\frac{35}{100}+xx\times\frac{7}{100}-xx\times\frac{35}{100}\times\frac{7}{100}[/tex]

Now we solve the product of 35/100 by 7/100, we get:

[tex]T=T=xx-xx\times\frac{35}{100}+xx\times\frac{7}{100}-xx\times\frac{49}{2000}[/tex]

Now we take xx as a co

tameka built 1/2 of a shed on monday and 2/5 of the tuesday

Answers

Answer:
1/10

Step-by-step explanation:
Given,
The part of shed built on Monday = 1/2
The part built on Tuesday = 2/5
Let x be the part built on Wednesday,
If the shed is finished on Wednesday,
Total part of work = 1= -9/10 = 10-9/10 = 1/10




Hence, she built shed on Wednesday.

Find the missing length of the triangle. 14 cm 8.4 cm b The missing length is centimeters.

Answers

Answer:

11.2cm

Explanation:

To be able to determine the missing length, we have to apply the Pythagorean Theorem which states that, in a right-angled triangle, the square of the hypotenuse(the longest side) is equal to the sum of squares of the other two sides.

Let's go ahead and find b as follows;

[tex]\begin{gathered} 14^2=8.4^2+b^2 \\ 196=70.56+b^2 \\ 196-70.56=b^2 \\ 125.44=b^2 \\ b=\sqrt[]{125.44}=11.2\operatorname{cm} \end{gathered}[/tex]

Maggie had a number of identical flowers for sale. She sold 70 of them with a 50% loss and sold the rest with a 80% profit. On the whole, Maggie still made a 10% profit. How many flowers did Maggie have at the beginning?

Answers

ANSWER:

130 flowers

STEP-BY-STEP EXPLANATION:

Let x be the total number of flowers, we can establish the following equation:

[tex]70\left(-50\%\right)+\left(x-70\right)\left(80\%\right)=x\left(10\%\right)[/tex]

We solve for x:

[tex]\begin{gathered} 70\left(-0.5\right)+\left(x-70\right)\left(0.8\right)=x\left(0.1\right) \\ \\ -35+0.8x-56=0.1x \\ \\ 0.8x-0.1x=56+35 \\ \\ 0.7x=91 \\ \\ x=\frac{91}{0.7} \\ \\ x=130 \end{gathered}[/tex]

The total number of flowers, that is, the ones it had at the beginning was 130

Hello I’ve been trying to solve this but have no luck :(

Answers

1. Domain, x ∈ [-9 , 8]

2. Range,   y ∈ [-10 , 10]

3. f(x) is not an increasing function, its a decreasing function.

4. f(x) is decreasing for interval,  x ∈ [-9,2] ∪ [7,8]

5. f(x) is constant function for the interval,   x ∈ [2,7]

                                   

Domain:- The value of x for which function f(x) is defined

Range : the value of y or f(x)

Increasing function: while increasing the value of x,  f(x)  is increasing and vice versa, called increasing function.

Decreasing function:  while increasing the value of x,  f(x)  is decreasing and vice versa, called increasing function.                              

From graph,

                     It seems very clear that,

1. Domain :-

                      x ∈ [-9 , 8]

                                       or      -9 ≤ x ≤ 8

2. Range :-

                       y ∈ [-10 , 10]

                                             or  -10 ≤ x ≤ 10

                     

3. Interval for which f(x) is increasing :-

                       f(x) is not an increasing function, its a decreasing function.

 

4. Interval for which f(x) is decreasing:-

                       f(x) is decreasing for interval,

                                 x ∈ [-9,2] ∪ [7,8]

5. Interval for which f(x) is constant function

                      f(x) is constant function for the interval,

                                     x ∈ [2,7]

                 

To learn more about Domain visit:https://brainly.com/question/28135761

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use the first derivative test to classify the relative extrema. Write all relative extrema as ordered pairs

Answers

The given function is

[tex]f(x)=-10x^2-120x-5[/tex]

First, find the first derivative of the function f(x). Use the power rule.

[tex]\begin{gathered} f^{\prime}(x)=-10\cdot2x^{2-1}-120x^{1-1}+0 \\ f^{\prime}(x)=-20x-120 \end{gathered}[/tex]

Then, make it equal to zero.

[tex]-20x-120=0[/tex]

Solve for x.

[tex]\begin{gathered} -20x=120 \\ x=\frac{120}{-20} \\ x=-6 \end{gathered}[/tex]

This means the function has one critical value that creates two intervals.

We have to evaluate the function using two values for each interval.

Let's evaluate first for x = -7, which is inside the first interval.

[tex]f^{\prime}(-7)=-20(-7)-120=140-120=20\to+[/tex]

Now evaluate for x = -5, which is inside the second interval.

[tex]f^{\prime}(7)=-20(-5)-120=100-120=-20\to-[/tex]

As you can observe, the function is increasing in the first interval but decreases in the second interval. This means when x = -6, there's a maximum point.

At last, evaluate the function when x = -6 to find the y-coordinate and form the point.

[tex]\begin{gathered} f(-6)=-10(-6)^2-120(-6)-5=-10(36)+720-6 \\ f(-6)=-360+720-5=355 \end{gathered}[/tex]

Therefore, we have a relative maximum point at (-6, 355).

Find the probability of X successes, using Table B in Appendix A of the textbook or some other method.n = 10, p = 0.3, X = 7

Answers

SOLUTION

The probability is a binomial probability

The probability is given as

[tex]\text{nCxp}^xq^{n-x}[/tex]

Where p= proability of succes=0.3

q=probability of failure=1-p=1-0.3=0.7

n=10, x=7

Then, substitute the parameters into the formula

[tex]10C_7(0.3)^7(0.7)^3[/tex][tex]\begin{gathered} 10C_7=120 \\ 120\times2.187\times10^{-4}\times0.343 \end{gathered}[/tex]

Then we have

[tex]\begin{gathered} 9.0017\times10^{-3} \\ 0.0090017 \end{gathered}[/tex]

The probability of x-success is 0.009

tem = 462-5 h 1995. Central High School had a student population of 2250 students. By 2005, the student population was only 1.800 students. What is the percent of decrease in the student population? A 2002 B. 25% C. 75% D. 80% tem = 119766

Answers

Central High School had a student population of 2250 students.

By 2005, the student population was only 1.800 students.

What is the percent of decrease in the student population?

A 2002

B. 25%

C. 75%

D. 80%

Percentage of decrease = 100 - 100 * (1800/2250) = 100 - 100 * 0.8 = 100 - 80 = 20%

In some states, the amount of sales tax on an item is found by multiplying the cost of the item by 0.07. Find the sales tax of a DVD that costs $23.99. O $1.67 $1.68 $16.79 O $0.17

Answers

DVD = $23.99

Sales tax = (23.99 x 0.07)

= 1,679 = $1.68

Determine the signs of given trigonometric function of an angle in standard position with given measure.cos (-302°) and sin (-302°)

Answers

Explanation

Exercise: Calculate the sign of cos(-302°) and sin(-302°).

We can know the sign of the trigonometric value of an angle depending on which quadrant the angle is located. In the case of cosine and sine, we have the following rules:

Let's calculate the sign of cos(-302°) first. Note that the angle within the cosine is negative; this means that it must be measured from the x-axis clockwise. Now, every quadrant has a total measure of 90°; then, dividing 302 by 90 we obtain

[tex]\frac{302}{90}\approx3.4,[/tex]

which means that -302° goes through two complete quadrants and a partial part of a third one. Since we must measure the angle clockwise, -302 lies in the first quadrant.

By the diagram above, the sign of -302° is +.

On the other hand, looking at the sine diagram, we see that the sign of sine(-302°) is + as well.

Answer

The signs of cos(-302°) and sin(-302°) are both +.

Use this graph of y = 2x2 - 12x + 19 to find the vertex. Decide whether thevertex is a maximum or a minimum point.A. Vertex is a minimum point at (3, 1)B. Vertex is a maximum point at (1,7)C. Vertex is a minimum point at (1,3)D. Vertex is a maximum point at (3,1)

Answers

Hello there. To slve this question, we'll have to remembrer some properties about maximum and minimum in a quadratic function.

Given a quadratic function f as follows:

[tex]f(x)=ax^2+bx+c[/tex]

We can determine whether or not the vertex is a maximum or minimum by the signal of the leading coefficient a.

If a < 0, the concavity ofthe parabolai is facing down, hence it admits a maximum value at its vertex.

If a > 0, the concavity of the parabola is facing up, hence it admits a minimum value at its vertex.

As a cannot be equal to zero (otherwise we wouldn't have a quadratic equation), we use the coefficients to determine an expression for the coordinates of the vertex.

The vertex is, more generally, located in between the roots of the function.

t is easy to prove, y comlpleting hthe square, that the solutions of the equation

[tex]ax^2+bx+c=0[/tex]

are given as

[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

Taking the arithmetic mean of these values, we get the x-coordinate of the vertex:

[tex]x_V=\dfrac{\dfrac{-b+\sqrt{b^2-4ac}}{2a}+\dfrac{-b-\sqrt{b^2-4ac}}{2a}}{2}=\dfrac{-\dfrac{2b}{2a}}{2}=-\dfrac{b}{2a}[/tex]

By evaluating the function at this point, we'll obtain the y-coordinate of the vertex:

[tex]f(x_V)=-\dfrac{b^2-4ac}{4a}[/tex]

With this, we can solve this question.

Given the function:

[tex]y=2x^2-12x+19[/tex]

First, notice the leadin coefficient is a = 2 , that is positive.

Hence it has a minimum point at its vertex.

To determine these coordinates, we use the other coefficients b = -12 and c = 19.

Plugging the values, we'll get

[tex]x_V=-\dfrac{-12}{2\cdot2}=\dfrac{12}{4}=3[/tex]

Plugging ths value in the function, ewe'll get

[tex]y_V=f(x_V)=2\cdot3^2-12\cdot3+19=2\cdot9-36+19=1[/tex]

Hence we say that the final answer is

Vertex is a minimum point at (3, 1)

As you can see in the gaph.

What is the spread of the data? 17 18 19 20 21 22 23 24 25 26 Age of female U.S. Olympic swimmers (years) O A. 21 to 25 years B. 15 to 30 years C. 18 to 25 years O D. 18 to 21 years

Answers

The spread of data is the difference between the maximum value and the minimum value.

Minimum value = 18

Maximum value = 25

Correct option: C . 18 to 25 years

Ingrid deposits $10,000 in an IRA. What will be the value of her investment in 6 years if the investment is earning 3.2% per year and is compounded continuously? Round to the nearest cent.

Answers

We have a initial deposit of $10,000 (PV=10,000).

The investment last 6 years (t=6).

The annual interest rate is 3.2% (r=0.032) and is compounded continously.

The equation to calculate the future value FV of the inverstment for this conditions is:

[tex]\begin{gathered} FV=PV\cdot e^{rt} \\ FV=10,000\cdot e^{0.032\cdot6} \\ FV=10,000\cdot e^{0.192}. \\ FV\approx10,000\cdot1.2116705 \\ FV\approx12,116.71 \end{gathered}[/tex]

The value of her investment will be $12,116.71.

Celine is playing a game at the school carnival. There is a box of marbles, and each box has a white, a green, a blue, and an orange marble. There is also a fair 12-sided die labeled with the numbers 1 through 12. How many outcomes are in the sample space for pulling a marble out of the box and rolling the die?4832168

Answers

Multiply the number of possible outcomes of pulling a marble out times the number of possible outcomes o rolling the die to find the total amount of outcomes in the sample space.

There are 4 different possibilities of pulling a marble out of a box: white, green, blue and orange. Since the die has 12 outcomes, then the total amount of outcomes in the sample space is:

[tex]4\times12=48[/tex]

Other Questions
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