808.2J heat energy needed to raise the temperature of a 30g Fe cube from 40°C to 100°C .
Given,
Fe (iron) has a specific heat capacity
= c = 0.4490 J/g°C
mass of iron = m = 30g
initial temperature = T1 = 40°C
final temperature = T2 = 100°C
thus, temperature change = ∆T = (100-40 )°C= 60°C
According to the formula of heat energy(Q) ,
Q = mc∆T
Q = 30g × 0.449J/g°C × 60°C = 808.2 J
Hence, 808.2J heat energy needed to raise the temperature of a 30g Fe cube from 40°C to 100°C .
What is Specific heat capacity ?The amount of energy needed to raise a material's heat content by precisely 1°C per gramme is known as specific heat, or Csp.
mathematically,
c = Q /m×∆T
Where
Q = quantity of heat absorbed by a body
m = mass of the body
∆t = Rise in temperature
C = Specific heat capacity of a substance depends on the nature of the material of the substance.
S.I unit of specific heat is J kg-1 K-1
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Which of the following cycles involve molecules from the atmosphere being broken and rearranged into new molecules in living things? (Choose all that apply!)
Choose all that apply:
Rock cycle.
Carbon Cycle
Carbon cycle.
Nitrogen cycle.
Solar cycle.
The cycles that involve molecules from the atmosphere being broken and rearranged into new molecules in living things are Carbon cycle and Nitrogen cycle.
The carbon cycle :
The carbon cycle is studied as two sub-cycles: One sub-cycle deals with rapid carbon exchange between the living organisms and the other deals with long-term carbon cycling by the various geologic processes. Carbon is present in the air as carbon dioxide. It gets dissolved in water and reacts with water molecules which produces bicarbonates. By land plants, bacteria, and algae, photosynthesis converts carbon dioxide into the organic molecules. These are made by photosynthesizers which are passed through the food chains. The cellular respiration forms carbon dioxide gas by converting the organic carbon.
When organic carbon gets stored for a longer term, it happens when matter from living organisms is deep in the ground or gets sink to the ocean bottom. It results in formation of sedimentary rock. Activities of volcano, and burning of fossil fuels brings the stored carbon in the carbon cycle.
The nitrogen cycle
The nitrogen cycle is a cycle of processes which repeats. During this cycle, nitrogen moves by the living and non-living things such as soil, water, plants, animals and bacteria. Microscopic living organisms which contains one cell. To move through the separate parts of the cycle, nitrogen change its forms. Nitrogen exists as a gas N₂ in the atmosphere, but in soil it is present as nitrogen oxide NO, and nitrogen dioxide NO₂. It is used as a fertilizer and found in other forms too like ammonia NH₃. It can be processed further in a fertilizer NH₄NO₃.
The five stages in the nitrogen cycle are nitrogen fixation, mineralisation, nitrification, immobilization, and denitrification. Microbes in the soil turns the nitrogen gas N₂ in volatile ammonia NH₃. Therefore, the fixation process is called nitrogen fixation. When a chemical like NO₃ moves away from the soil or other material and gets leaked into nearby areas, it dissolves in the water and dips out the soil which pollutes the waterways.
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The Federal Reserve Bank of the United States is also known as the
people’s bank.
central bank.
world bank.
retail bank.
Answer:
The Federal Reserve System (sometimes refered to as "The Fed") is the central bank of the United States. It is the name given to a country's primary monetary authority.
Explanation:
Answer:
central bank
Explanation:
2023
Liquid hexane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water . If 6.36 g of water is produced from the reaction of 7.76 g of hexane and 41.9 of oxygen gas, calculate the percent yield of water.
Percent yield of water when 7.76g liquid hexane and 41.9 of oxygen reacts to form 6.36g of water is 84 %
Balanced equation for the reaction is
2 C₂H₁₄ + 19 O₂ ---> 12 CO₂ + 14 H₂O
1 mole of hexane = Given weight / molecular weight = 7.76 g x 1 mole / 130 g = 0.06 moles [Molecular mass of hexane = 130]
1 mole O₂ = 41.9 g x 1 mole / 32 g = 1.3 moles
Hydrogen is the limiting reactant in the reaction
Moles of H₂O = 0.06 moles H₂ x 14 H₂O / 2 CO₂ = 0.42 moles H₂O
Mass H₂O = 0.42 moles x 18 gm/mole = 7.56 g
Percent yield = (Actual yield / Theoretical yield) * 100 = (6.36 / 7.56) * 100 = 84 %
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1. Consider the titration of 0.250 M of 50.0 mL nitric acid (HNO) by 0.350 M NH,. Kb for NH, is 1.8 x 10°. Calculate the pH of the resulting solution after the following volumes of NH, have been added. a. 0.0 mL b. 50.0 mL c. Half-way equivalence point d. At equivalence point e. 150.0 mL
Answer:I got pH = 4.98
Explanation:. This agrees with the fact that strong acid + weak base = acidic pH.
If you notice, the volume and concentration of both
NH
3
and
HNO
3
are identical, and
HNO
3
only has one
H
+
. Therefore, you should convince yourself that these neutralize each other exactly because the number of mols of each are equal.
This leaves the same number of mols of
NH
+
4
as
NH
3
, in TWICE the volume (i.e. don't forget to account for dilution!):
how to find number of moles of hydrogen gas collected for trial one?
We can consider the hydrogen gas of the first trial like an ideal gas and use the ideal gas law.
P * V = n * R * T
Where P is the pressure of the gas, V is the volume, n is the number of moles, R is the ideal gas constant and T is the temperature. We already have those values.
P = 753.8 mmHg (Pressure of Dry Hydrogen Gas)
760 mmHg = 1 atm
P = 753.8 mmHg * 1 atm/(760 mmHg)
P = 0.9918 atm
V = 40.3 mL (Volume of Hydrogen Gas Collected)
1000 mL = 1 L
V = 40.3 mL * 1 L/(1000 mL)
V = 0.0403 L
R = 0.082 atm*L/(mol*K) (ideal gas constant)
T = 295.6 K (Temperature in K)
Finally we can replace these values into the formula and solve it for n.
P * V = n * R * T
n = P * V /(R * T)
n = (0.9918 atm * 0.0403 L)/(0.082 atm*L/(mol*K) * 295.6 K)
n = 0.00165 moles
Answer: the number of moles of Hydrogen gas collected in trial 1 is 0.00165 mol.
If we use R = 62.358 L-torr/mol-K we need:
T = 295.6 K
V = 0.0403 L
P = 753.8 mmHg = 753.8 torr
n = P * V /(R * T)
n = (753.8 torr * 0.0403 L)/(62.358 torr*L/(mol*K) * 295.6 K)
n = 0.00165 moles
Using your understanding of the specific heat capacity, how many degress in °C will 100g of water (specific heat capacity =4.2J/g•°C) increase if 750J are added to it?
Answer
1.8 °C
Explanation
Given data:
Mass of water, m = 100 g
Specific heat capacity of water, c = 4.2 J/g•°C
Quantity of heat added, Q = 750 J
What to find:
The degree increase in °C, ΔT
Step-by-step solution:
The formula relating specific heat and heat is given by:
[tex]Q=mc\Delta T[/tex]To find ΔT, substitute, m = 100 g, c = 4.2 J/g•°C and Q = 750 J into the formula:
[tex]\begin{gathered} 750\text{ J }=100\text{ g }\times4.2\text{ }J\text{ /g}•\degree C\times\Delta T \\ 750\text{ J }=420\text{ J/}\degree C\times\Delta T \\ \text{Divide both side by 420 J/}\degree C \\ \frac{750\text{ J}}{420\text{ J /}\degree C}=\frac{420\text{ J/}\degree C\times\Delta T}{420\text{ J/}\degree C} \\ \Delta T=1.7857\degree C \\ \Delta T\approx1.8\degree C \end{gathered}[/tex]The degree in °C that 100 g of water increase, if 750 J are added to it, is 1.8 °C
Write one paragraph explaining if the plant will make enough oxygen for a human tosurvive on Mars. Explain how you figured it out.
To know if the plant will make enough oxygen for a human to survive on Mars, we need to calculate how much oxygen it produces using the photosynthesis equation ratio:
1 mole of Glucose --- 6 mol of oxygen
0.09 moles of Glucose --- x mol of oxygen
x = 0.54 moles of oxygen.
According to the data, a human needs 25 moles of oxygen per day to live and the plant produces just 0.54 moles of oxygen. One plant is not enough for a human to survive on Mars. We would need:
0.54 moles of oxygen ---- 1 plant
25 moles of oxygen ---- x plants
0.54x = 25
x = 46.3 plants
We would need 46.3 plants to produce enough oxygen for a human.
How many grams of C4H10 are needed to form 85 grams of carbon dioxide?
Answer
The mass of C4H10 needed = 28 grams
Explanation
Given:
The mass of carbon dioxide formed = 85 grams
What to find:
The mass of C4H10 needed to form 85 grams of CO2.
Step-by-step solution:
Step 1: Write the balanced equation for the reaction.
[tex]2C_4H_{10}+13O_2\rightarrow8CO_2+10H_2O[/tex]Step 2: Convert 85 grams of CO2 formed into moles.
Using the atomic masses of C and O from the periodic table; the molar mass of CO2 = 44.01 g/mol.
So, the moles of CO2 in 85 grams CO2 can be calculated using the mole formula
[tex]\begin{gathered} Moles=\frac{Mass}{Molar\text{ }mass} \\ \\ Moles\text{ }of\text{ }CO_2=\frac{85\text{ }g}{44.01\text{ }g\text{/}mol}=1.931379232\text{ }mol \end{gathered}[/tex]Step 3: Determine the moles of C4H10 needed.
Using the mole ratio of C4H10 to CO2 in step 1 and the moles of CO2 formed in step 2; the moles of C4H10 needed is calculated as shown below.
[tex]\begin{gathered} 2mol\text{ }C_4H_{10}=8mol\text{ }CO_2 \\ \\ x=1.931379232mol\text{ }CO_2 \\ \\ Cross\text{ }multiply\text{ }and\text{ }divide\text{ }both\text{ }sides\text{ }by\text{ }8mol\text{ }CO_2 \\ \\ x=\frac{1.931379232mol\text{ }CO_2}{8mol\text{ }CO_2}\times2mol\text{ }C_4H_{10} \\ \\ x=0.482844808\text{ }mol \end{gathered}[/tex]Step 4: Convert the moles of C4H10 in step 3 above to grams.
From the periodic table, the molar mass of C4H10 can be determined to be = 58.12 g/mol.
Using the same mole formula used in step 2, the mass of C4H10 is
[tex]\begin{gathered} Mass=0.482844808mol\times58.12g\text{/}mol \\ \\ Mass\text{ }of\text{ }C_4H_{10}=28.06294024\text{ }grams \\ \\ Mass\text{ }of\text{ }C_4H_{10}\approx28\text{ }grams \end{gathered}[/tex]Therefore, the mass of C4H10 needed to form 85 grams of carbon dioxide is 28 grams
A stack of newspapers is burned completely to ash in a laboratory. How does the resulting mass relate to the initial mass of the stack of newspapers?
Responses
The mass of the gases and the ash should be one-fourth the mass of the initial stack of newspapers.
The mass of the gases and the ash should be one-fourth the mass of the initial stack of newspapers.
The mass of the gases and the ash should be double the mass of the initial stack of newspapers.
The mass of the gases and the ash should be double the mass of the initial stack of newspapers.
The mass of the gases and the ash should equal the mass of the initial stack of newspapers.
The mass of the gases and the ash should equal the mass of the initial stack of newspapers.
The mass of the gases and the ash should be one-half the mass of the initial stack of newspapers.
If 88.0 g of CO2 is produced from the complete decomposition of calcium carbonate in 250 g of impure sample, what is the purity in terms of the carbonate content?
Now purity is the effective percentage of pure reactant in the total mass.
The rest is inert impurities.
They ask you to calculate the purity of the carbonate, so you have to focus on CaCO3
Let's calculate with the reaction:
CaCO3 (s) -----------------> CaO (s) + CO2 (g)
x 88.0 g
100 g CaCO3 ------- 44 g CO2
x ------- 88 g CO2
x = 200.16 g
Sample has 250 g of impurities. So:
Purity % = (200.16 g / 250 g impure) x 100 = 80.0 % of purity
Fill in the blanks
Interphase
Mitosis is now over
__________ is unwound.
Here the cell _________________its chromosomes in preparation for another round of cell division.
One complete ____________ is from one cell division to the next.
chromatin , grows , cell cycle .
What stage of the cell cycle do chromosomes copy in order to prepare for division?interphase
The cell then replicates its chromosomes during a crucial interphase stage known as the S phase and makes sure that its systems are prepared for cell division. The cell is now prepared to enter the first stage of mitosis, assuming all circumstances are ideal.
Mitosis is now over chromatin is unwound.
Here the cell grows its chromosomes in preparation for another round of cell division.
One complete cell cycle is from one cell division to the next.
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Use the heat equation to calculate the energy, in joules, required to heat 10.0 g of silver (Ag) from
112 °C to 275 °C. (SH of silver=0.235 J/g C
Answer:
383 joules
Explanation:
Energy = mass * delta T * c
c=0.235
delta t = 275 - 112 = 163
mass = 10
10 * 163 * 0.235 = 383.05 joules = 383 joules.
I didn't include units because i'm too lazy to and the units cancel out to joules anyways but you should probably include units in your answer
The following data was collected when a reaction was performed experimentally in the laboratory. What is the maximum amount of NaNO3?And how did you find the amount?
Explanation:
We are given: moles of Al(NO3)3 = 4 mol
: moles of NaCl = 9 mol
We know: molar mass of Al(NO3)3 = 212.996 g/mol
: molar mass of NaCl = 58.44 g/mol
: molar mass of NaNO3 = 84.9947 g/mol
The balanced chemical equation is given as:
[tex]Al\left(NO_3\right)_3+3NaCl\rightarrow3NaNO_3+AlCl_3[/tex]Number of moles of NaNO3 from Al(NO3)3:
[tex]\begin{gathered} n(NaNO_3)\text{ = n\lparen Al\lparen NO}_3)_3)\times\frac{n(NaNO_3)}{n(\text{Al\lparen NO}_3)_3)} \\ \\ \text{ = 4}\times\frac{3}{1} \\ \\ \text{ = 12 mol} \end{gathered}[/tex]Number of moles of NaNO3 from NaCl:
[tex]\begin{gathered} n(NaNO_3)=\text{ n\lparen NaCl\rparen}\times\frac{n(NaNO_3)}{n(NaCl)} \\ \\ \text{ = 9}\times\frac{3}{3} \\ \\ \text{ = 9 mol} \end{gathered}[/tex]Therefore, NaCl is a limiting reagent.
Answer:
The maximum amount of NaNO3 is 9 mol.
By balancing the chemical equation of the given reactants and products. And then use molar ratios and the number of moles to find the limiting reagent.
In a soccer game, the player with a momentum of 100 kg m/s kicks a ball that is motionless on the ground. After the kick, the player has a momentum of 94 kg m/s, and the ball has a momentum of 6 kg m/s. Was momentum conserved?
Since the momentum after collision is equal to the momentum before collision, the momentum was conserved.
What is the conservation of linear momentum?Let us recall that the principle of the conservation of linear momentum states that the momentum before collision is equal to the momentum after collision.
This implies that the total momentum of the system is constant. The momentum of the object does not change.
The total momentum before collision = 100 kg m/s + 0 kg m/s = 100 kg m/s
Total momentum after collision = 94 kg m/s + 6 kg m/s = 100 kg m/s
Hence the momentum of the system is conserved.
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Given the following equation:2 C4H10 + 13 O2 = 8 CO2 + 10 H2O ; what is the mole to mole ratio of C4H10 to O2? Mole to mole ratio of O2 to CO2?
2mol C4H10 : 13mol O2
13mol O2 : 8mol CO2
Explanations;Given the combustion of butane reaction expressed as:
[tex]2C_4H_{10}+13O_2\rightarrow8CO_2+10H_2O[/tex]In order to get the mole ratio, we will use the coefficient of the compound in the equation.
For the mole to mole ratio of C4H10 to O2
Coefficient of C4H10 in the equation is 2 while the coefficient of O2 in the equation is 13. Hence the mole ratio of C4H10 to O2 is 2mol C4H10 : 13mol O2
For the mole to mole ratio of O2 to CO2
Coefficient of CO2 in the equation is 8 while the coefficient of O2 in the equation is 13. Hence the mole ratio of O2 to CO2 is 13mol O2 : 8mol CO2
Can someone kindly help me!
Gibbs energy of a reaction can be calculated from the Helmholtz equation as follows: ΔG = ΔH - TΔS. The ΔG for the given reaction is 333214.2 J.
What is Gibbs free energy?Gibbs energy G is the energy stored in a system which is balanced from the energy for work done. The equation to find Gibbs energy change is as follows: ΔG = ΔH - TΔS.
The enthalpy change or ΔH is the difference of total enthalpy of products from the total enthalpy of reactants. In calculation, the standard enthalpy of each species in the reaction must be multiplied with their coefficients.
From the given standard values, ΔH is calculated as follows:
ΔH = ΔH (products) - ΔH (reactants).
= [(2× -733.8) + (3 × -393.5)] - [(-824.5) + (13 × -110.5)]
= - 2035.8 KJ/mol
The entropy change ΔS can be calculated in a similar way from the given values as follows:
ΔS = [(2× 445.2) + (3 × 213.6)] - [(87.4) + (13 × 197.6)]
= -1125 J/(mol K)
The temperature is 298 K thus ΔG can be calculated as follows:
ΔG = ΔH - TΔS
= - 2035.8 KJ/mol -(-1125 J/(mol K) × 298 K)
= 333214.2 J
Therefore, the Gibbs energy change ΔG for the given reaction is 333214.2 J.
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I’m struggling with determining the results of some of these problems.
Chemistry => Measurements => Dimensional Analysis
In order to do a division, the units must be congruent.
We can divide units of different properties, that is, units of mass by units of volume, but we cannot divide or multiply units of the same property that are on different scales, that is, we cannot divide nor multiply milligrams by grams, there must be a conversion before division. Therefore we will have to:
[tex](3.0mg^2)\cdot(0.023g)\text{ = No}[/tex][tex](4.0g)\cdot(1.0cm^3)=Yes=4.0g.cm^3[/tex][tex]\frac{20.mg^2}{0.010g}=No[/tex]A solution of an unknown compound has a concentration of 36.2% by mass. How many moles are present in 3.644 kg of solution if the solute has a molar mass pf 89.6 g/mol?
First part)
36.2% by mass means:
36.2 g of solute ------- 100 g of solution
Second part)
We want to know how many moles are present in 3.644 kg of solutions.
3.644 kg = 3644 g of solution
Now,
36.2 g of solute -------- 100 g of solution
x --------- 3644 g of solution
x = 1319 g of solute = 1320 g (3 significant figures)
Therefore 1320 g are diluted in 3644 g
Third part)
Number of moles = mass /molar mass
Number of moles = 1320 g of solute/ 89.6 g/mol of solute= 14.7 moles
Answer: 14.7 moles of solute
A 60.5 mL sample of a 0.116 M potassium sulfate solution is mixed with 40.0 mL of a 0.102 M lead (II) acetate solution and the following precipitation reaction occurs: K2SO4(aq)+Pb(C2H3O2)2(aq)→2KC2H3O2(aq)+PbSO4(s) The solid PbSO4 is collected, dried, and found to have a mass of 1.00 g . Determine the limiting reactant, the theoretical yield, and the percent yield.
The limiting reactant is lead acetate as in absence of it reaction will not occur. Theoretical and percent yield are 2.1092 g and 49.52% respectively.
What is percent yield?Percent yield is defined as the ratio of actual yield to the theoretical yield multiplied by 100. If the actual and theoretical yield are same then the percent yield is 100%.If actual yield is less than the theoretical yield then the percent yield is less than 100%.Reason of this condition arising is the incompletion of reaction or loss of sample during recovery process.
In cases where percent yield is over 100% it indicates that more sample is recovered than the predicted amount.This condition arises when there are other simultaneous reactions taking place leading to the formation of product. It can also arise if there is incomplete removal of impurities from the sample .
To calculate percent yield, it is necessary to know theoretical yield which for the given reaction is found out as, mass of potassium sulfate is found from molarity which is 1.212 g .If,174.259 g potassium sulfate produces 303.26 lead sulfate then 1.212 g potassium sulfate will produce 1.212×303.26/174.259=2.1092 g of lead sulfate which is the theoretical yield.
The percent yield is calculated as follows, 1/2.1092×100=49.52%.
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Which of the following are needed to calculate the percent yield? Select all that apply.Excess yieldLimiting yieldActual yieldTheoretical yield
Explanation:
Percent yield can be calculated as follows:
[tex]\text{ \%yield = }\frac{Actual\text{ yield}}{Theoretical\text{ yield}}x100[/tex]So,
Answer:
Actual yield
Theoretical yield
What is the name of a substance that contains a useful element which can be extracted from it?
The name of a substance that contains a useful element which can be extracted from it is ore.
ore can be defined as the mineral from which useful substance can be extracted and it contains more valuable substances. ore is deposited of one or more precious mineral in earth crust. examples of ore is iron ore : hematite , magnetite , copper ore : pyrite , borntite, zinc ore : sphalerite, zinc blende, calamite.
The Four types of ore are given as follows :
Ore oxideOre halidesOre carbonatessulphide oreThus, The name of a substance that contains a useful element which can be extracted from it is ore.
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Which equation is balanced?
Responses
2Mg+O2→2MgO
Na+F2→2NaF
2Al+3O2→Al2O3
Al+3F2→AlF3
PLEASE ANSWER i am begging
How many milliliters of a stock solution of 7.00 M HNO3 would you have to use to prepare 0.120 L of 0.480 M HNO3 ? If you dilute 20.0 mL of the stock solution to a final volume of 0.270 L , what will be the concentration of the diluted solution?
1. The volume of the stock solution needed is 0.008 L
2. The concentration of the diluted solution is 0.52 M
1. How to determine the volume of the stock solution
We can obtain the volume of the stock solution as follow:
Molarity of stock solution (M₁) = 7Volume of diluted solution (V₂) = 0.120 L Molarity of diluted solution (M₂) = 0.480 M Volume of stock solution (V₁) =?M₁V₁ = M₂V₂
7 × V₁ = 0.480 × 0.120
5 × V₁ = 0.0576
Divide both side by 7
V₁ = 0.0576 / 7
V₁ = 0.008 L
Thus, the volume needed is 0.008 L
2. How to determine the concentration of the diluted solution
We can obtain the concentration of the diluted solution as follow:
Volume of stock solution (V₁) = 20 mLConcentration of stock solution (C₁) = 7 MVolume of diluted solution (V₂) = 0.270 L = 0.270 × 1000 = 270 mL Concentration of diluted solution (C₂) =?C₁V₁ = C₂V₂
7 × 20 = M₂ × 270
140 = M₂ × 270
Divide both side by 270
C₂ = 140 / 270
C₂ = 0.52 M
Thus, the concentration is 0.52 M
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balance the equation for redox reaction in basic solution: HS^- (AQ.) + CLO3^- (AQ.) = S8 (S) +CL^- (AQ.)
The balancing of the given reaction can be: [tex]8HS^-_{(aq)}+4ClO^{3-}_{(aq)}---- > S_8+4Cl^-+4H_2O[/tex]
What is balancing equation?A balanced chemical equation is one that has the same number of atoms of each type in the reaction on both the reactant and product sides. In a balanced chemical equation, both the mass and the change are equal.
When using constants, a balanced equation is critical because the coefficients become the powers of the concentrations of products and reactants. The constant is incorrect if the equation is not balanced.
To balance a chemical equation, add coefficients to the symbols or formulas as needed so that the same number of each type of atom occurs in both reactants and products.
To balance the given reaction, it can be written as:
[tex]8HS^-_{(aq)}+4ClO^{3-}_{(aq)}---- > S_8+4Cl^-+4H_2O[/tex]
Thus, the above mentioned is the balanced equation.
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What is the concentration (M) of a KCl solution prepared by dissolving 82.4 g of KCl in sufficient water to give 450 mL of solution?
The molarity of KCl is 0.5 Molar when it is dissolved in 450 mL of water.
What is molarity?
The amount of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a solute per liter of a solution is known as molarity. The molar concentration of a solution is its other name.
Given,
Weight of KCl (w) = 82.4 g
Volume of water (v)= 450 mL
We know that,
Molecular mass of KCl (W)= 74.5
Molarity = w/W × v/1000
= 82.4/74.5 × 450/1000
= 1.1 × 0.45
= 0.5 M
Therefore, the molarity of 82.4 g of KCl in 450 mL water is 0.5 M.
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what is the molarity of h3po4 solution if 0.05 M ba(oh)2 is needed to neutralize 20.00 ml of h3po4
The molarity of h3po4 solution if 0.05 M ba(oh)2 is needed to neutralize 20.00 ml of h3po4 is 0.25 M.
Given,
M₁ =?
valance factor H₃PO₄ (n)₁ = 3
M₂ = 0.05 M
V1 = V2 = 20 m or 0.02 L
valance factor Ba(OH)₂(n)₂ = 2
M₁n₁V₁ = M₂n₂V₂
M₁ = (M₂n₂V₂) / n₁V₁
= 0.05 × 2 × 3
= 0.25 M
Molarity is the number of moles of a substance in keeping with the liter of answer. solutions labeled with the molar awareness are denoted with a capital M; a 1. zero M answer incorporates 1 mole of solute according to the liter of answer. Molality is the variety of moles of solute in step with a kilogram of solvent.
Molarity (M) is the amount of a substance in a positive volume of solution. Molarity is described because the moles of a solute in step with liters of an answer. Molarity is also known as the molar attention of an answer.
Molarity is very crucial in chemistry for one big purpose. it's far the measurement of concentration in any mixture. The molarity of any solution is a way to know the unique factors or compounds which are found in any solution.
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Enter your answer in the provided box.
Calculate the following quantity: volume of 1.96 M calcium chloride that must be diluted with water to
prepare 761 mL of a 2.79 x 102 M chloride ion solution.
mL
The volume of a 1.96 M calcium chloride that must be diluted with water to prepare 761 mL of a 2.79 x 102 M chloride ion solution is 108,326.02mL.
How to calculate volume?The volume of a solution can be calculated using the following formula:
C₁V₁ = C₂V₂
Where;
C₁ = initial concentrationV₁ = initial volumeC₂ = final concentrationV₂ = final volumeAccording to this question, 1.96 M calcium chloride must be diluted with water to prepare 761 mL of a 2.79 x 10² M chloride ion solution. The initial volume can be calculated as follows:
1.96 × V = 279 × 761
1.96V = 212,319
V = 108,326.02mL
Therefore, 108,326.02mL is the volume of the solution.
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a student pipettes 5 ml of vinegar into a erleyenmayeer flask adds indictator and 25 ml of distilled water and titrates it with 0.1098M naoh. calcualte the concentraion of acetic acid in the vinegar if the intitial volume reading on the burrette was 1.35 ml and the final reading is 37.83ml
The concentration of the solution is obtained as 0.134 M.
What is the concentration of the acetic acid?We know that titration is a method of analysis that depends on the volume of the solutions in order to determine the concertation.
We know that;
Total volume of the vinegar = 5 ml + 25 mL = 30 mL
Concentration of the sodium hydroxide = 0.1098M
Volume of the sodium hydroxide used = 37.83ml - 1.35 ml = 36.48 mL
Using the formula;
CAVA/CVB = NA/VB
CAVANB = CBVBNA
CA= CBVBNA/VANB
CA = 0.1098 * 36.48 * 1/30 * 1
CA = 0.134 M
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Balance this redox reaction by using the half reaction method. Show your work:
Al + Ni2+ --> Al3+ + Ni
In redox reaction the oxidation state of reactant changes by gain and loss of electron. Which element will take the electron depends on the reduction potential of the element. The balanced redox reaction is
[tex]2Al+3Ni^{+2} \rightarrow2Al^{+3} +3Ni[/tex]
What is redox reaction?Redox reaction is the one in which the one element oxidizes by the loss of electron while the element reduces by taking that lost electron.
The Half reaction for [tex]Al[/tex] is
[tex]Al\rightarrow Al^{+3} +3e^{-}[/tex]
the half reaction for [tex]Ni[/tex] is
[tex]Ni^{+2}+2e^{-} \rightarrow Ni[/tex]
Now to balance the number of electron multiply first reaction by 2 and second reaction by 3 and add these reactions, we will get the balanced equation as
[tex]2Al+3Ni^{+2} \rightarrow2Al^{+3} +3Ni[/tex]
Thus the balanced redox reaction is [tex]2Al+3Ni^{+2} \rightarrow2Al^{+3} +3Ni[/tex]
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:What is the name of the organic compound whose structural formula is shown here?A) EthaneB) EtheneC)PropeneD) Propane
We see that we have two carbon atoms. The nomenclature for two carbon atoms is Eth.
We also have a single bond between the two carbon atoms accompanied by hydrogens, so it is an alkane, so the name will be ethane.
The answer will be A) Ethane
