Answer:
A machine can help decrease the input force and increase the output force.
This is achieved by using a simple machine, such as a ramp, to increase the distance over which the input force is applied. By increasing the distance over which the input force is applied, the amount of force required to move an object is reduced. This is known as mechanical advantage, and it allows a smaller input force to produce a larger output force, making the work easier to do.
For example, if a person needs to lift a heavy object straight up, they would need to apply a large amount of force to lift it. However, if they use a ramp to move the object up a slope, the distance over which the force is applied is increased, making it easier to move the object with less force.
Determine the tension developed in cable ab for equilibrium of the 440- lb crate. (figure 1) express your answer to two significant figures and include the appropriate units
The tension developed in cable AB for the equilibrium of the 440-lb crate is approximately 1606 lb (to two significant figures). The units are pounds (lb).
To determine the tension developed in cable AB for the equilibrium of the 440-lb crate, we need to use the principle of equilibrium, which states that the net force acting on an object is zero.
Vertical component:
W = 440 lb
Tsin30 = (T/2) lb (since sin30 = 1/2)
Horizontal component:
Tcos30 = (0.866T) lb (since cos30 = √3/2 ≈ 0.866)
Since the crate is in equilibrium, the net force in the vertical direction must be zero. Therefore,
Tsin30 = W
(T/2) = 440 lb
T = 2 × 440 lb / sin30
T ≈ 1606 lb
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an effort of 10n applied to a simple machine moves a load of 40n through a distance of 100mm,the efficiency at this load being 80%.calculate the velocity ratio
If an 80% efficiency machine lifts a load of 40n by applying a 10N effort then the velocity ratio (VR) will be 5.
What is the efficiency of a machine?The efficiency of a machine can be calculated by the ratio of mechanical advantage(MA) and the velocity ratio(VR).
Mathematically,
Efficiency= η= [tex]\frac{MA}{VR}[/tex]
where MA= mechanical advantage = load(W)/ Effort(P)
VR=velocity ratio=[tex]\frac{distance moved by effort }{distance moved by load}[/tex]
Here in the given question
Load(w)=40N
Effort(P)= 10N
MA=40/10=4
Efficiency(η)=80% =0.8
we Know η=MA/VR
VR=MA/η
VR=4/0.8=5
VR=5
Hence the velocity ratio of the machine is 5.
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0.025 kg of water is fired from a water pistol with a speed of 230 m/s.
If the water pistol has a mass of 0.9 kg, what is the recoil speed of the
water pistol?
Show Your Work
The recoil speed of the water pistol, given that the mass of the water pistol is 0.9 Kg is -6.39 m/s
How do i determine the recoil speed of the water pistol?The following data were obtained from the question:
Mass of water (m₁) = 0.025 KgSpeed of water (v₁) = 230 m/sMass of water pistol (m₂) = 0.9 KgRecoil speed of water pistol (v₂) = ?The recoil speed of the water pistol can be obtained as illustrated below:
m₁v₁ = -m₂v₂
(0.025 × 230) = -(0.9 × v₂)
5.75 = -0.9v₂
Divide both sides by -0.9
v₂ = 5.75 / -0.9
v₂ = -6.39 m/s
Thus, we can conclude that the recoil speed is -6.39 m/s
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I need help with this one.
The correctly written chemical equation that demonstrates the conservation of mass is:
[tex]H_{2} + O_{2} - > H_{2}O[/tex]
What is conservation of mass?The law of conservation of mass is a fundamental principle in chemistry and physics that states that mass cannot be created or destroyed in a chemical reaction or a physical process. In other words, the total mass of the reactants must be equal to the total mass of the products in any chemical reaction. This means that the number of atoms of each element present in the reactants must be equal to the number of atoms of the same elements in the products.
[tex]H_{2} + O_{2} - > H_{2}O[/tex]
This equation shows the reaction between hydrogen gas and oxygen gas to produce water vapor. The equation is balanced, which means that the number of atoms of each element on both sides of the equation is equal, and therefore, the law of conservation of mass is upheld.
The law of conservation of mass is important in chemistry because it allows chemists to predict the outcome of a reaction and to calculate the amount of reactants needed to produce a certain amount of product. It also ensures that the total amount of matter in the universe remains constant, which is a fundamental concept in modern physics.
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When something moves, there is more than one __________________ involved
Answer:
Explanation:
force
One mole of an ideal gas expands isothermally at 270 K from 1 litreto 3. 5 litres. The
temperature is then increased to 300 K at constant volume. Next the gas is compressed
isothermally at 300 K to its initial volume. The gas is then returned to its initial state. Calculate the net work done during this process
The net work done during this process is -992 J. The negative sign indicates that work was done on the system, i.e. the gas lost energy to the surroundings.
W1 = (1 mol)(8.314 J/mol·K)(270 K) ln(3.5 L / 1 L) ≈ 5978 J
Next, the temperature is increased at constant volume, so no work is done:
W2 = 0
Then, the gas is compressed isothermally at 300 K to its initial volume, so we can use the same equation as before to calculate the work done:
W3 = (1 mol)(8.314 J/mol·K)(300 K) ln(1 L / 3.5 L) ≈ -6969 J
Finally, the gas is returned to its initial state, so the work done is:
W4 = 0
Therefore, the net work done is:
Wnet = W1 + W2 + W3 + W4 = 5978 J + 0 J - 6969 J + 0 J = -992 J
work done is defined as the product of force and displacement, where force is the amount of energy required to move an object and displacement is the distance over which the object is moved. Mathematically, work done is expressed as W = F x d, where W is the work done, F is the force applied and d is the displacement.
Work done can be positive, negative, or zero depending on the direction of force and displacement. When the force is in the same direction as displacement, work done is positive, when the force is in the opposite direction to displacement, work done is negative, and when the force and displacement are perpendicular, work done is zero.
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A capacitor of unknown charged capacitance c is charged to 100v and the connected across an intially uncharged 60micro f capacitor. If the final potenial diffrence across the 60micro-f capacitor is 40v ,determine c
If the final potential difference across the 69micro -f then capacitor is 40Mf
We cannot expect simple energy conservation to hold because energy is presumably dissipated as heat in the connection wires or as radio waves while the charge oscillates during the system "settling down" to its final state (40V across the parallel pair of capacitors C and 60 F).
We anticipate that charge will be conserved. Thus, if Q is the initial charge stored on C and q 1 and q2 are the charges on the parallel pair after "settling down," then -
Q= q1+ q2
C(100V) = C(40V) + 60mf(40V)
C= 40Mf
An electrical component that stores electrical energy in an electric field is known as a capacitor. It is made up of two conductive plates separated by a nonconductive material known as a dielectric.
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Imagine two like charges in close contact. If one of the charges becomes oppositely charged, what happens to the electrostatic force?
The force becomes attractive
The force becomes repulsive
The force increase
The force decreases
The electrostatic force between the two charges will decrease in magnitude and become attractive.
What is Electrostatic Force?
Electrostatic force, also known as Coulombic force or Coulomb's law, is the force that exists between electrically charged particles, such as protons and electrons. The force is exerted by one charged particle on another and can be attractive or repulsive, depending on the types of charges involved.
The magnitude of the electrostatic force is directly proportional to the product of the charges on the particles and inversely proportional to the square of the distance between them. Mathematically, this can be expressed as F = k(q1q2)/r^2, where F is the electrostatic force, q1 and q2 are the charges on the particles, r is the distance between them, and k is the Coulomb constant.
If one of the like charges becomes oppositely charged, the electrostatic force between them will become attractive. .
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When not part of a circuit, what happens in a battery’s negative terminal? A The negative charge is attracted to the opposite charge in the positive terminal but cannot get there. B The negative charge travels directly across the battery to the opposite charge where it remains. C The negative terminal has no electrical charge. D The negative terminal has a positive charge.
Question:
When not part of a circuit, what happens in a battery’s negative terminal?
Answer
A. The negative charge is attracted to the opposite charge in the positive terminal but cannot get there.
The correct statement is "The negative charge is attracted to the opposite charge in the positive terminal but cannot get there."The correct option is A.
What is electric potential?Electric potential is a fundamental concept in the study of electricity and magnetism that refers to the electric potential energy per unit charge at a given point in space. It is often represented by the symbol "V" and is measured in volts (V).
At its core, electric potential is a measure of the amount of work that would be required to move a unit positive charge from a reference point to a given point in space against an electric field. The reference point is often chosen to be at infinity, where the electric potential is defined to be zero.
Electric potential is influenced by the presence of charges and electric fields in the surrounding space. For example, if a positive charge is placed in the vicinity of a negatively charged object, the positive charge will experience a force that will cause it to move towards the negatively charged object. The electric potential at the point where the positive charge is located will be lower than the potential at a point farther away, because less work will be required to move the positive charge closer to the negatively charged object.
Mathematically, electric potential can be calculated using the equation:
V = W/q
where V is the electric potential, W is the work done in moving a unit charge from a reference point to the given point, and q is the magnitude of the charge.
Here in the Question,
When a battery is not part of a circuit, there is no flow of current. The chemical reactions inside the battery create a difference in electric potential between the positive and negative terminals of the battery, but this potential difference is not balanced until a complete circuit is formed.
In the absence of a circuit, the negative terminal of the battery has an excess of electrons, which are negatively charged particles. These electrons are attracted to the positive terminal of the battery, which has a deficiency of electrons and is positively charged. However, without a complete circuit, the electrons cannot flow from the negative terminal to the positive terminal.
Option B is incorrect because the electrons do not travel directly across the battery in the absence of a circuit.
Option C is incorrect because the negative terminal does have an electrical charge, as it has an excess of electrons.
Option D is also incorrect because the negative terminal is negatively charged, not positively charged.
Therefore, the negative charge is attracted to the opposite charge in the positive terminal but cannot get there, which is option A.
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help!! Sherri is drawing the free body diagram for an object. She says that the object has no net force acting upon it. Which of the following observations would support this statement? (Choose all that apply)
the object that is slowing down.
the object is sitting still
the object that is speeding up
the object is moving with constant velocity
the object that is changing direction.
Answer:
Constant velocity, sitting still
If a body does not have a net force acting upon it, then the object is sitting still or it is moving with constant velocity. Hence, options B and D are correct.
What is a force?A force is an action that modifies or maintains a body's or object's motion. A force is, to put it simply, a push or a pull. An object's speed, direction, and even shape can be altered by forces. Gravitational, electrostatic, and frictional forces are some examples of force.
Thus, when an object has no net force acting upon it, then the object is sitting still or is moving with constant velocity. Hence, options B and D are correct.
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you push a food tray 1.5m along a cafeteria table with a constant force of 18 N. how much work do you do ?
Answer:
27J
Explanation:
Work done =force×distance
Therefore
Work done =18×1.5
Work done =27J
Compute the ratio between the luminosity from part b to the mass from part a. How does that ratio compare with the sun's ratio of luminosity to mass?
L/M = 1000 L Sun/MSun Based on the spectral category and luminosity group of a star, a classification is made. Cepheids are an illustration of a variable star.
A)M≈1MSun
b)L≈1000LSun
c)1000
D) Wrong; every main-sequence star upon that HR diagram turns helium into hydrogen. T 10 7 years
SUPER HUGE AND RED GIANT:
The H-R diagram's upper right corner may be located there. It is incredibly cool but very bright.
THE SUN, FOR EXAMPLE, IS IN THE Major, AS ARE THE HEATEST AND LIGHTEST STARS IN The GALAXY.
Very hot and faint White Dwarfs with a radius that isn't significantly greater then Earth.
Stars on the lower left of both the H-R diagram have smaller radii and higher temperatures than low-luminosity main-sequence stars.
Main-sequence stars with a lengthy lifetime are much less brilliant, colder, smaller, and far less massive than main-sequence stars having short lifetimes.
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''Complete question"
What is the approximate mass of the most massive stars left on the main sequence of this star cluster?
a) M≈0.1M Sun
b) M≈1 M Sun
c) M≈10M Sun
d) M≈100M Sun
Part B
What is the luminosity of the most luminous stars in the cluster?
a) L≈ 1LSun
b) L≈ 10LSun
c) L≈ 100LSun
d) L≈ 1000LSun
Part C
Compute the ratio between the luminosity from part B to the mass from part A. How does that ratio compare with the Sun's ratio of luminosity to mass?
L / M = __ LSun /MSun
Part D
Estimate the maximum amount of time these very luminous stars can last as red giants from your answer to part C.
a) t≈ 10^5 years
b) t≈ 10^7 years
c) t≈ 10^9 years
d) t≈ 10^11 years
What is the mass of an object if it has 420 J of potential energy while suspended by a rope 48 m above the ground?
Answer:
0.89kg
Explanation:
PE=mgh
PE=420 m=? g=9.8m/s^2 h=48
Making m the subject of formula
[tex]m = \frac{pe}{gh} [/tex]
[tex] = \frac{420}{9.8 \times 48} [/tex]
[tex] = \frac{420}{470.4} [/tex]
m=0.89kg
A 23-in. Vertical rod cd is welded to the midpoint c of the 50-in. Rod ab. Determine the moment about ab of the 180-lb force q
The moment about ab of the 180-lb force q is 13,860 lb-in.
How to determine moment?To determine the moment about AB of the 180-lb force Q, we need to find the perpendicular distance between the line of action of the force and point A, and then multiply this distance by the magnitude of the force. This perpendicular distance is called the moment arm.
First, find the coordinates of point C. Since the vertical rod CD is welded to the midpoint C of the rod AB, use the midpoint formula:
x_C = (x_A + x_B)/2
y_C = (y_A + y_B)/2
where (x_A, y_A) and (x_B, y_B) are the coordinates of points A and B, respectively. Plugging in the values:
x_C = (0 + 50)/2 = 25 in.
y_C = (0 + 23)/2 = 11.5 in.
So point C has coordinates (25, 11.5).
Next, find the moment arm. To do this, draw a line through point C perpendicular to AB, and extend it until it intersects the line of action of the force Q. Call the point of intersection point D. Use similar triangles to find the distance from A to D.
The triangle ACD is similar to triangle ABC, since CD is perpendicular to AB and AC is the altitude to AB. Thus:
AC/AB = CD/BC
Solving for BC:
BC = (AB)(CD)/AC = (50 in.)(23 in.)/(11.5 in.) = 100 in.
Therefore, the distance from A to D is 100 - 23 = 77 in.
Finally, calculate the moment about AB by multiplying the magnitude of the force by the moment arm:
M_AB = Qd = (180 lb)(77 in.) = 13860 lb-in.
Therefore, the moment about AB of the 180-lb force Q is 13,860 lb-in.
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Shawna's hockey coach is planning for the upcoming game against their biggest rival.she thinks her players aren't quite as fast as most of the individuals on the other team and she knows they aren't as experienced the coach stresses fundamentals and proper passing techniques.one basic offensive strategy her coach ask her players to use is to make sure they pass the puck on
Answers:
1 a spot slightly ahead of their teammate
2 the teammate covered by two defenders
3 their teammate's back skate
4 their teammate's front skate
Shawna's hockey coach is committed to helping her players succeed in their upcoming game against their biggest rival.
What is mass?Mass is a fundamental physical property of every object that exists in the universe. It is the measure of an object's inertia and resistance to acceleration. Mass is measured in kilograms or pounds, and is commonly used to measure the weight of an object. Mass is an intrinsic property of an object that does not depend on its location or the gravitational field in which it is situated. Mass is related to the amount of matter, or material, an object contains, and it is not affected by gravity. Mass is an invariant quantity, meaning it is unaffected by any external forces or conditions.
To this end, she emphasizes the importance of fundamental hockey skills and proper passing techniques. She encourages her players to make quick, accurate passes to teammates in order to create more scoring opportunities; the goal is to always have an open man. To achieve this, the coach instructs the players to pass the puck to a spot slightly ahead of their teammate, the teammate covered by two defenders, their teammate's back skate, or their teammate's front skate. By focusing on the basics and utilizing these strategies, the coach hopes to give her team the best chance of coming out on top.
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find a magnitude and direction (the counterclockwise angle with the +x-axis) of a vector that is equal to a+b.
a: magnitude 27m direction 51°
b: magnitude 17m direction -6.5°
c: magnitude 19 m direction 0.0°
d: magnitude 27 m direction 39°
Magnitude and direction of a vector that is equal to a+b is 19m and 0.0° resp. Hence the correct option is C. magnitude 19 m direction 0.0°
What is Vector?`Vector is a mathematical quantity which has both magnitude and direction.
Vectors are denoted with usual notation with an arrow upon it. for example, Force, Displacement, Velocity and Acceleration etc. are the vectors which has both magnitude as well as direction.
When two same vectors are acting at a point in two dimension. The magnitude of resultant of this two vectors are given by,
R² = R₁² + R₁² +2R₁R₂cosθ......1
Where θ is the angle between them.
The direction of the resultant vector of two same vectors is given by the equation,
tanθ = (R₁ sinθ) ÷ (R₁ + R₂cosθ)......2.
In this picture, we have to find magnitude and direction of vector A+B, we have nothing to do with vector C.
vector A is at 37° from vertical, means 90-37 = 53° from positive x direction.
A = 12 m and 53°
B = 15m and 40°
angle between these two vectors are θ= 53+40 = 93°
magnitude of resultant of this two vectors are A+B which is given by the equation.
putting these values in equ. 1 we get,
R² = 12² + 15² +2(12×15)cos93°
R² = 350.15
R = 18.71 ≅ 19m ( magnitude)
From equation 2
tanα = (12 sin93°) ÷ (12+ 15cos93°)
tanα = 0.8337
α = 39.82° this angle is from vector B
so the angle of resultant from positive x axis is 40-39.82 = 0.17 ≅ 0.0°
Hence C is correct option is c: magnitude 19 m direction 0.0°
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A wheel rolls a distance of 24 meters and rotates through an angle of 12 radians. What is the radius of the wheel?
A circular wheel has a radius of 24 cm, a diameter of 48 cm, and a circumference of 3.14159 cm, or 150.8 cm, rounded to the nearest centimeter.
What exactly are circumference and diameter?Definition. The circumference of a circle is the length measured around its edge. The diameter of a circle is the distance from the center to the outside. The radius of a circle is the distance between any two points on its edge.
Does diameter include radius?A ring's diameter is equal to half of its diameter, or vice versa, meaning that the diameter of a circle is twice as long as the radius.
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An object starts out with a momentum of 5 kg·m/s. After a collision, it has a momentum of 25 kg·m/s in the same direction.
Which of the following parameters are consistent with the indicated change in momentum?
The parameter that is consistent with the indicated change in momentum is:
The velocity of the object increased from 1 m/s to 5 m/s.How to determine which of the following parameters are consistent with the indicated change in momentum ?First we can use the principle of conservation of momentum to determine which of the following parameters are consistent with the indicated change in momentum:
p = m * v
Where
p is the momentum m is the mass of the objectv is the velocityIf the momentum of the object increases from 5 kg·m/s to 25 kg·m/s in the same direction, then we can conclude that:
The mass of the object must have remained constant.The velocity of the object must have increased by a factor of 5.Therefore, the parameter that is consistent with the indicated change in momentum is:
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What is the problem with changing the force in the rubber band and the mass of the tub at the same time?
Changing the force in the rubber band and the mass of the tub at the same time can make it difficult to determine the effect of each variable on the motion of the tub.
What leads to changing forces?Changes in the mass of an object: If the mass of an object changes, the force required to move it will also change accordingly. This is due to the fact that force is directly proportional to mass.
Changes in the speed or velocity of an object: This is because the kinetic energy of the object increases with an increase in speed, which requires more force to be applied to maintain the same rate of acceleration.
This is because the change in one variable may mask the effect of the other variable. Therefore, it is best to change only one variable at a time and keep all other variables constant in order to accurately observe and measure the effect of each variable on the system.
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9. A bullet of mass 8g is stationary in the barrel of a gun of mass 4kg. The trigger is pulled and a force of 2.8kN is exerted on the bullet for 1.7ms. Calculate or find: a) Velocity of the bullet as it leaves the barrel of the gun. b) Recoil velocity of the gun. c) Show by calculation which type of collision is taking place.
After the trigger is pulled, the momentum of the system is:
p = mv
where p is the momentum, m is the mass, and v is the velocity.
Before the bullet is fired:
p = 0
After the bullet is fired:
p = (0.008 kg)(v) + (4 kg)(-u)
where u is the recoil velocity of the gun.
Since there are no external forces acting on the system, the initial momentum is equal to the final momentum:
0 = (0.008 kg)(v) + (4 kg)(-u)
Solving for u, we get:
u = -(0.008 kg)(v)/(4 kg) = -0.002 v
Substituting this into the equation for the momentum, we get:
p = (0.008 kg)(v) + (4 kg)(0.002 v) = 0.016 v
The force applied to the bullet is given by:
F = ma
where F is the force, m is the mass, and a is the acceleration.
Rearranging this equation to solve for acceleration, we get:
a = F/m = (2.8 kN)/(0.008 kg) = 350,000 m/s^2
Using the kinematic equation:
v = u + at
where u is the initial velocity (which is zero), t is the time, and a is the acceleration, we can solve for the final velocity:
v = at = (350,000 m/s^2)(1.7 × 10^-3 s) = 595 m/s
Therefore, the velocity of the bullet as it leaves the barrel of the gun is 595 m/s.
b) The recoil velocity of the gun is given by:
u = -(0.008 kg)(v)/(4 kg) = -0.002 v = -1.19 m/s
c) In an elastic collision, kinetic energy is conserved, while in an inelastic collision, kinetic energy is not conserved.
The initial kinetic energy of the system is zero, since both the bullet and the gun are stationary. After the collision, the kinetic energy of the system is:
K = (1/2)mv^2 + (1/2)Mu^2
where K is the kinetic energy, m is the mass of the bullet, v is its velocity, M is the mass of the gun, and u is its recoil velocity.
Substituting the values we found earlier, we get:
K = (1/2)(0.008 kg)(595 m/s)^2 + (1/2)(4 kg)(1.19 m/s)^2 = 1340 J
The work done on the bullet is:
W = Fs = (2.8 kN)(2 × 10^-3 m) = 5.6 J
Since the work done on the bullet is less than the change in kinetic energy of the system, the collision is inelastic.
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What is the wavelength of a sound wave that has a speed of 680 m/s and a frequency of 220 Hz? (With full explanation)
Answer:
3.0909 mExplanation:
Given,
Wave speed = 680 m/sfrequency = 220 HzWe need to find the wavelength of sound wave :
We know that ,
[tex]{ \underline{ \boxed{ \sf{F = \dfrac{v}{\lambda}}}}}[/tex]where,
F is frequency, v is wave speed,[tex]\sf\lambda[/tex] is wavelengthon substituting the values we get :
[tex]\dashrightarrow \sf \: 220 = \dfrac{680}{\lambda} \\ \\ \dashrightarrow \sf \: \lambda = \frac{680}{220} \\ \\ \dashrightarrow \sf \:\lambda = 3.0909 \: m\\ [/tex]
Hence,
Wavelength of sound is 3.0909 mThe cooling system of a laser system fails. As a result, 64 kcal of heat are absorbed each minute by the laser rod in the laser system. The laser rod has a mass of 5 kg. It has a specific heat of 0. 3 kcal/kg • Co.
Find: How much the temperature of the rod increases each minute, in 0C
The temperature of the laser rod increases by 21.33 degrees Celsius each minute due to the failure of the cooling system.
When heat is transferred to an object, its temperature increases. The amount of temperature increase depends on the amount of heat transferred, the mass of the object, and its specific heat.
To calculate the temperature increase of the laser rod, we can use the formula:
ΔT = Q / (m * c)
where ΔT is the change in temperature, Q is the heat absorbed, m is the mass of the laser rod, and c is the specific heat of the material.
In our case, the laser rod is a closed system, and the heat added is 64 kcal per minute.
Substituting the given values, we get:
ΔT = 64 kcal / (5 kg * 0.3 kcal/kg•Co)
ΔT = 21.33 Co
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A group of students investigated the relationship between the period of oscillation for a pendulum and the amplitude of the oscillation. Using a lightweight string that was 70.0 cm long and a mass of 1 kg, this group collected and calculated the data shown in the table below.
Amplitude (degrees) Period (s)
10 1.66
10 1.70
10 1.71
10 1.68
10 1.72
35 1.75
35 1.71
35 1.75
35 1.76
35 1.69
Using this information, answer the following questions.
What is the average period of the trials that were conducted with an amplitude of 10 degrees?Answer is units of seconds
What is the average period of the trials that were conducted with an amplitude of 35 degrees?Answer is units of seconds
What would you expect the period to be, based on the relationship given in equation L7.3 of the Experiment 7 handout? Answer is units of seconds
Using this information provided between the relationship between the period of oscillation for a pendulum and the amplitude of the oscillation, the solutions of the given problems are provided below.
What is a pendulum?A body hanging from a fixed point such that it may move back and forth while being pulled by gravity is called a pendulum.
The average period of the trials that were conducted with an amplitude of 10 degrees can be calculated by adding up the period values and dividing by the number of trials:
(1.66 + 1.70 + 1.71 + 1.68 + 1.72) / 5 = 1.69 s (rounded to two decimal places)
The average period of the trials that were conducted with an amplitude of 35 degrees can be calculated similarly:
(1.75 + 1.71 + 1.75 + 1.76 + 1.69) / 5 = 1.73 s (rounded to two decimal places)
Based on the data collected, the average period for an amplitude of 10 degrees is 1.69 s and the average period for an amplitude of 35 degrees is 1.73 s. This suggests that the period does increase with amplitude, consistent with the predicted relationship.
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A school classroom has six identical lamps. Each of the lamps is connected in parallel across a 220V mains supply. State the voltage across one of the lamps
The voltage across one of the lamps will be 220V. This is because when components are connected in parallel, the voltage across each component is the same as the voltage across the source.
What is voltage?Voltage is a measure of the potential difference in electrical energy between two points. It is measured in volts and is the electrical force that causes current to flow in an electrical circuit. Voltage is the energy per unit charge that causes a current to flow through a conductor. It can be compared to the pressure of water in a pipe, where the greater the pressure, the more water that can be pushed through the pipe. Voltage is the primary factor in determining the amount of electrical current that can be produced in an electrical circuit. Voltage is also related to the amount of power that can be produced in an electrical circuit. Voltage can be generated by a variety of sources, such as batteries, generators, and rectifiers.
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A person who weighs 50 N climbs 100 stairs up. Each stair is 0.2 m high. The work done is
Answer:
Explanation:
Given that ,
A man who weights is 50N climbs up 100 steps of a stair
each step is 0.2m high
mg=50N
Height at 100 steps , h=100×0.2=50 m
Change in potential energy , =mgh=50×50=2500 J
So, Work done by the man , W=2500 J
A bullet of mass 10g traveling at a speed of 100m/s embeds itself into a block of wood of mass 1900g. Suspended by a string.
A) Determine the velocity of the block and bullet immediately after the impact.
B) What is the height the pendulum rises to after impact?
The mass of kerosene needed to boil 5 liters of water at 10°C is (q = 4. 6. 10 J/ kg, % = 4200 J/ kg·grad, heat losses are neglected)
The mass of kerosene needed to boil 5 liters of water at 10°C is approximately 28070 kg.
To determine how much kerosene is needed to boil 5 liters of water at 10°C, we must first determine how much heat is needed to bring the water's temperature up to 100°C and then boil it at that degree.
Heating water from 10°C to 100°C:
4.186 J/g°C (or 4.186 kJ/kg°C) is the specific heat capacity of water. As a result, J is the quantity of heat needed to raise the temperature of 5 liters (or 5000 grams) of water from 10°C to 100°C is:
Q1 = m x c x ΔT
= 5000 g x 4.186 J/g°C x (100°C - 10°C)
= 1952200 J
Water vaporizes at a heat of 2260 kJ/kg (or 2.26 × 106 J/kg) at 100 °C when it is heated to boiling. To boil 5 liters (or 5000 grams) of water at 100°C, the following amount of heat is needed:
Q2 = m x L
= 5000 g x 2.26 x 10^6 J/kg
= 1.13 x 10^10 J
To heat and boil the water, the following amount of heat is needed:
Qtot = Q1 + Q2
= 1952200 J + 1.13 x 10^10 J
= 1.149522 x 10^10 J
Where m is kerosene's mass, c is kerosene's specific heat capacity (4.6 kJ/kg°C), and ΔT is the temperature change of the kerosene.
Assuming that the initial temperature of the kerosene is also 10°C, the temperature change of the kerosene is:
ΔT = 100°C - 10°C
= 90°C
Substituting the values into the equation, we get:
1.149522 x 10^10 J = m x 4.6 kJ/kg°C x 90°C
Solving for m, we get:
m = 28069.6 kg
Hence, 28070 kg of kerosene is required to boil 5 liters of water at 10°C.
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Why do ionizing smoke detectors contain an isotope that undergoes alpha decay rather than beta or gamma decay?
Ionizing smoke detectors contain an isotope that undergoes alpha decay (such as americium-241) because alpha particles are more ionizing than beta or gamma particles.
What is Isotopes?
Isotopes are variants of an element that have the same number of protons in their atomic nuclei but differ in the number of neutrons. This means that isotopes of the same element have the same atomic number (which determines the element's chemical properties) but different atomic masses.
In an ionizing smoke detector, the alpha particles emitted by the radioactive source ionize the air in the detector's chamber, creating a current that is detected by a circuit. When smoke particles enter the chamber, they attach to the ions and reduce the current, triggering the detector's alarm.
Alpha particles are heavier and have a higher charge than beta or gamma particles, which means they interact more strongly with matter and create more ionization as they travel through air. This makes them more effective at ionizing the air in the detector's chamber, and therefore more sensitive to the presence of smoke particles.
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Discuss how the government uses tax credits, direct payments, and deficiency payments to
subsidize renewable energy.
For eligible renewable energy technology and projects, a number of tax credits, grants, and loan programmes are offered by the federal government.
Why does the government promote the use of renewable energy sources?Fossil fuels are burned to produce energy, which produces a sizable amount of greenhouse gas emissions that contribute to global warming. Even when taking into account the entire life cycle of the technologies, the majority of renewable energy sources produce negligible to no emissions.
Why are subsidies for renewable energy good?Subsidies have helped reduce dependency on fossil fuels by expanding the use of renewable energy sources. This is crucial for lowering greenhouse gas emissions and preventing an increase in global temperatures.
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1 > Explain why scientists cannot watch the complete process of a star and planets forming. J
Scientists cannot watch the complete process of a star and planets forming due to dust
Basically, formation of a star takes place after the accumulation of gas and dust. which gets collapsed due to gravitation. This whole process takes millions of years until a star is formed and starts to shine like a sun. Moreover, the leftovers of from the formed star creates planets. In the whole process of formation of stars and planets the dust makes visible light difficult to see with help of our radio telescopes. Although it is possible for us observe formation of stars by radio waves.
Hence, due to dust and leftovers of stars scientists finds it difficult to see the formation of stars and planets.
Scientists use telescopes and simulations to study the formation of stars and planets because to their long time scales, distant locations, and dense dust and gas in molecular clouds.
Scientists cannot directly watch the full formation of a star and planet since these activities take place over extraordinarily long periods of time and often in faraway and opaque parts of space. In enormous molecular clouds, dense dust and gas block most electromagnetic radiation, including visible light, allowing stars and planets to form.
Time Scales: Scientists can't directly monitor every stage of star and planet formation because it takes millions of years.
Distance: Many of these creation events occur in faraway areas of our galaxy or other galaxies. With current technology, these processes are hard to see.
Obstructions: Thick clouds of dust and gas surround the regions where stars and planets develop, making it difficult for visible light and other electromagnetic waves to penetrate and provide clear observations.
Early Stages: These dense clouds hide the first collapse of material that forms protostars and protoplanetary discs.
Despite these constraints, scientists study these phenomena with infrared, radio, and X-ray telescopes. These approaches let astronomers to see infrared emissions from young stars and protoplanetary discs through dust clouds, indicating their origin. Scientists combine observations with theoretical knowledge to study star and planet formation using computer simulations and models.
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