Halp me this question

Yes, q = -5 is a solution to the inequality q < -7.

We have,

To determine if q = -5 is a solution to the inequality q < -7, we need to plug in -5 for q in the inequality and see if it is a true statement.

Substituting q = -5.

-5 < -7

Since -5 is less than -7,

The inequality q < -7 is true when q = -5.

Thus,

q = -5 is a solution to the inequality q < -7.

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To differentiate F(y) = 1/ y^2 − 9 /y^4 (y + 5y^3), we need to use the quotient rule of differentiation. Your answer: F'(y) = -2y^(-3) - (12y^(-5) + 60y^(-2))(y + 5y^3)

The quotient rule states that the derivative of a quotient of functions is equal to the numerator's derivative multiplied by the denominator minus the denominator's derivative multiplied by the numerator, all divided by the denominator squared.

Using this rule, we can find the derivative of F(y) as follows:

F'(y) = [(d/dy) (1/ y^2) * (y^4(y + 5y^3)) - (d/dy) (y^4(y + 5y^3)) * (1/ y^2)] / (y^4(y + 5y^3))^2

Simplifying this expression, we get:

F'(y) = [(-2y^3(y + 5y^3))/(y^4(y + 5y^3))^2 - (y^4(1 + 15y^2))/(y^2(y^4(y + 5y^3))^2)]

= [(-2y^3(y + 5y^3)) - (y^4(1 + 15y^2))] / (y^6(y + 5y^3))^2

= (-2y^4 - 10y^6 - y^4 - 15y^6) / (y^6(y + 5y^3))^2

= (-3y^4 - 25y^6) / (y^6(y + 5y^3))^2

Therefore, the derivative of F(y) is F'(y) = (-3y^4 - 25y^6) / (y^6(y + 5y^3))^2.
To differentiate the function F(y) = 1/y^2 - 9/y^4 (y + 5y^3), you can apply the power rule and the chain rule.

Your answer: F'(y) = -2y^(-3) - (12y^(-5) + 60y^(-2))(y + 5y^3)

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Rosie has 6 different lengths of craft ribbons.

In the graph provided for this question, we see that there are  2 of 1 [tex]\frac{3}{4}[/tex] yards, 3 of 2 [tex]\frac{2}{4}[/tex] yard, 2 of 3 yards, 1 of 3[tex]\frac{2}{4}[/tex] yards, 1 of 4 yards and 3 of 4 [tex]\frac{2}{4}[/tex] yards of ribbons.

If we list all this different lengths, it would look like

1. 1 [tex]\frac{3}{4}[/tex]  yards          2. 2 [tex]\frac{2}{4}[/tex] yards        3. 3 yards       4. 3[tex]\frac{2}{4}[/tex] yards       5. 4yards   and 6.  4 [tex]\frac{2}{4}[/tex] yards

Therefore there are only size different lengths. We were not asked for the sum total of the different lengths which would have amounted to 12.

The answer provided is in response to the question in the image attached below;

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The expression √75x³y in radical form is 5x√(3xy).

The given expression is √75x³y

Square root of seventy five times of x cube times of y

We have to write in radical form

We can simplify √75x³y as follows:

√75x³y

= √(25×3×x²×x×y)

= 5x√(3xy)

Therefore, the expression √75x³y in radical form is 5x√(3xy).

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The use of a "thumbs-up" gesture to symbolize the statement "good luck" is a common practice in many cultures. This gesture is typically used to express approval or agreement, but it can also be used to convey positive wishes, such as wishing someone good luck before an exam or a job interview.

It is believed that this gesture originated in ancient Rome, where it was used as a sign of approval in the gladiatorial arena. Today, the thumbs-up gesture has become a universal symbol of positivity and encouragement. So, if you want to wish someone good luck, a thumbs-up gesture is a great way to do it!

The use of a "thumbs-up" gesture to symbolize the statement "good luck" involves the following steps:

1. Extend your arm: To perform the thumbs-up gesture, first extend your arm in the direction of the person you want to wish good luck.
2. Make a fist: Close your fingers into a fist, with your thumb pointing upwards.
3. Show your thumb: Ensure that the thumb is clearly visible and pointing upwards. This represents the "thumbs-up" gesture.
4. Make eye contact: Look at the person you're wishing good luck to, so they know the gesture is directed at them.

By performing the thumbs-up gesture, you're using a universally recognized symbol to convey your positive sentiment and wish someone good luck in their endeavors.

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Dianelys should consider purchasing at least one ticket if she wants to have a chance of winning the grand-prize.

The word or phrase that describes the probability that Dianelys will win the raffle if she buys 0 tickets is "impossible." This means that there is no chance or likelihood of her winning the grand-prize if she does not buy any tickets. The probability of winning a raffle or any type of random drawing event is always dependent on the number of tickets or entries purchased.  

The more tickets you have, the higher your chances of winning. However, it's important to note that even if you purchase multiple tickets, winning is still not guaranteed as it ultimately depends on chance and luck.  

Therefore, Dianelys should consider purchasing at least one ticket if she wants to have a chance of winning the grand-prize, but she should also remember that there is no guarantee that she will win.

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The equation that represents the scenario is P + 1.2x + 0.25 = y. Euclid's weight is 10.625 pounds, and Riemann's weight is 21.25 pounds.

(a) Let us assume that the current weight of Euclid is x and the current weight of Pythagoras is P. Let us also assume that the weight of Pythagoras in January is y. The expression that represents the given scenario will be written as;

when Pythagoras lost 13 pounds in 5 months : P =  y - 13

when Pythagoras gains 1.2 times Euclid's weight: = P + 1.2x

when Pythagoras' weight is 1/4 pound less than their weight in January:

(b) Solving the given equation,

P + 1.2x + 0.25 = y

y- 13 + 1.2x + 0.25 = y

1.2x - 12.75 = 0

(c) Euclid's weight is calculated as follows;

1.2x = 12.75

x = 12.75/1.2

x = 10.625 pounds

(d) The weight of Riemann is calculated as follows;

2(Euclid's weight)

2(10.625)

21.25 pounds

weight of Pythagoras = 60.5-(21.25 + 10.62)

= 28.7

The weight of Pythagoras is 28.7 pounds.

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The complete question is "Jake has two dogs, Euclid and Pythagoras. Euclid is a smaller dog and Pythagoras is larger. Jake found that Pythagoras lost 13 pounds from January to June. If Pythagoras gains 1.2 times Euclid's weight, Pythagoras's weight would still be 1/4 pound less than he did in January. What is Euclid's weight? (a) Write an equation that represents the scenario. Begin by defining your variable (b) Solve the equation. Show your work. (c) What is Euclid's weight? (d) Jake adopts a third dog, Riemann. Riemann weighs exactly twice what Euclid weighs. The combined 60.5 pounds. What is Riemann's weight, and what is Pythagoras's weight? weight of the three dogs is Show your work.​"

the box with the largest volume has dimensions approximately 3.48 in. x 3.48 in. x 5.76 in.

Let x be the side length of the square cut from each corner of the tin sheet. Then the dimensions of the base of the box will be (10-2x) by (10-2x), and the height of the box will be x. Thus, the volume of the box is given by:

V = (10-2x)^2 * x = 4x^3 - 40x^2 + 100x

To maximize V, we take the derivative of this expression and set it equal to zero:

dV/dx = 12x^2 - 80x + 100 = 0

Solving for x using the quadratic formula, we get:

xx = (80 ± sqrt(80^2 - 4*12*100))/24 ≈ 1.74, 5.76

The solution x = 1.74 is extraneous, since it would result in negative dimensions for the box. Thus, the optimal size of the square to be cut from each corner is x = 5.76 inches.

The dimensions of the box with the largest volume are:

Length = Width = 10 - 2x = 10 - 2(5.76) ≈ 3.48 inches

Height = x = 5.76 inches

Therefore, the box with the largest volume has dimensions approximately 3.48 in. x 3.48 in. x 5.76 in.

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the tube diameter that will result in a flow rate of 500 m^3/hr is approximately 79.7 mm.

(a) To estimate the flow rate and determine whether the flow is laminar or turbulent, we can use the Hagen-Poiseuille equation for laminar flow in a circular pipe:

Q = (π/8) * d^4 * ΔP / μL

where:

Q = flow rate (m^3/s)

d = diameter of the tube (m)

ΔP = pressure difference between the tanks (Pa)

μ = dynamic viscosity of water (Pa·s)

L = length of the tube (m)

We can convert the units to be consistent with the given data:

ΔP = ρgh = (998 kg/m^3) * 9.81 m/s^2 * 0.3 m = 2927.8 Pa

d = 4 mm = 0.004 m

L = 3.5 m

μ = 0.001 kg/m·s

Substituting these values into the equation, we get:

Q = (π/8) * (0.004 m)^4 * 2927.8 Pa / (0.001 kg/m·s * 3.5 m) = 3.458 × 10^-8 m^3/s

To convert this to m/hr, we can multiply by the conversion factor:

Q = (3.458 × 10^-8 m^3/s) * (3600 s/hr) = 1.247 × 10^-4 m^3/hr

To determine whether the flow is laminar or turbulent, we can calculate the Reynolds number, which is a dimensionless value that describes the flow regime:

Re = ρvd / μ

where:

v = velocity of the fluid (m/s)

For laminar flow, Re < 2300, and for turbulent flow, Re > 4000. In the transitional range between 2300 and 4000, the flow regime can be either laminar or turbulent, depending on the specific conditions.

The velocity can be calculated as:

v = Q / (π/4 * d^2) = (1.247 × 10^-4 m^3/hr) / (π/4 * (0.004 m)^2) / (3600 s/hr) = 0.026 m/s

Substituting the values into the Reynolds number equation, we get:

Re = (998 kg/m^3) * (0.026 m/s) * (0.004 m) / (0.001 kg/m·s) = 103.7

Since the Reynolds number is less than 2300, the flow is laminar.

(b) To determine the tube diameter that will result in a flow rate of 500 m^3/hr, we can rearrange the Hagen-Poiseuille equation to solve for d:

d = (128 μL Q / πΔP)^1/4

Substituting the given values, we get:

d = (128 * 0.001 kg/m·s * 3.5 m * 500 m^3/hr / π * 2927.8 Pa)^1/4 = 0.0797 m

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The probability that three students, with different names, line up in alphabetical order from front-to-back can be expressed as a common fraction.

Explanation:

There are 3! = 6 ways in which the three students can line up in a single file. However, only one of these arrangements is in alphabetical order from front-to-back. Therefore, the probability of the three students lining up in alphabetical order is:

1/6

This can be expressed as a common fraction, indicating that there is only one favorable outcome out of six possible outcomes. Therefore, the probability of the three students lining up in alphabetical order is 1/6, or approximately 0.1667.

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The answer for the given Laplace Transform, f(s), is e^(-s)[(1/s^2) - (1/s)].

To find f(s), we can start by applying the Laplace transform to the given function:
ℒ{(t − 1)(t − 1)} = ℒ{t^2 - 2t + 1} = 1/s^3 - 2/s^2 + 1/s


Identify the function
We have the function (t - 1)u(t - 1), where u(t - 1) is the unit step function.

Apply the Laplace Transform property for the unit step function
The Laplace Transform of u(t - a)f(t - a) is given by e^(-as)F(s), where a = 1 in our case. So, we need to find the Laplace Transform of f(t - a) = f(t - 1).

Find the Laplace Transform of f(t - 1)
Our function f(t - 1) = t - 1. The Laplace Transform of t^n is given by n!/(s^(n+1)), so for n = 1, the Laplace Transform of t is 1!/(s^2) = 1/s^2. Since we have t - 1, we find the Laplace Transform of the constant 1 as well, which is 1/s.

So, the Laplace Transform of f(t - 1) = (1/s^2) - (1/s).

Apply the Laplace Transform property
Now, we apply the e^(-as)F(s) property with a = 1:
f(s) = e^(-s)[(1/s^2) - (1/s)]

So, the answer for the given Laplace Transform, f(s), is e^(-s)[(1/s^2) - (1/s)].

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Let thetaθ be an angle in the standard position. We can conclude that the angle theta lies in the first quadrant because both tangent theta and secant theta are positive.

If tangent theta is greater than 0 and secant theta is also greater than 0, then we know that the angle theta is located in either the first quadrant or the third quadrant.
To determine which quadrant the angle lies in, we need to consider the signs of sine and cosine as well. Since tangent is positive and secant is positive, we know that sine and cosine are either both positive or both negative.
In the first quadrant, all trigonometric functions are positive. So if sine and cosine are both positive, then the angle theta must lie in the first quadrant.
In the third quadrant, only tangent and cotangent are positive. So if sine and cosine are both negative, then the angle theta must lie in the third quadrant.

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The requried, after 9 days, Plant 2 is 10.09 inches taller than Plant 1.

We can use the equations given to find the heights of Plant 1 and Plant 2 after 9 days and then compare them.

For Plant 1, using the equation h = 2 + 1.06d, we have:

h₁ = 2 + 1.06(9) = 11.54 inches

So after 9 days, Plant 1 is 11.54 inches tall.

For Plant 2, we know that it increased by 2.07 inches every day after reaching a height of 3 inches. So after 9 days, it would have increased by:

2.07 x 9 = 18.63 inches

Starting from a height of 3 inches, the height of Plant 2 after 9 days would be:

h₂ = 3 + 18.63 = 21.63 inches

So after 9 days, Plant 2 is 21.63 inches tall.

Therefore, the difference in height between Plant 1 and Plant 2 after 9 days is:

h₂ - h₁ = 21.63 - 11.54 = 10.09 inches

So after 9 days, Plant 2 is 10.09 inches taller than Plant 1.

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Answer:

D. Quadrant IV

Step-by-step explanation:

Bc it IS!!!

The value of the slope between each pair of points are,

9) - 1/3

10) 1

11) 3/4

We have to given that;

Points are,

9. (4, 6) and (-2, 8)

10. (-1, 3) and (5,9)

11. (5, -1) and (-3,-7)

Now, We know that;

Slope of line passing through the points  (x₁ , y₁) and (x₂, y₂) is,

m = (y₂ - y₁) / (x₂ - x₁)

Hence, We get;

9) Points are,

(4, 6) and (-2, 8)

So, Slope is,

m = (8 - 6) / (- 2 - 4)

m = 2/ - 6

m = - 1/3

10) Points are,

(-1, 3) and (5,9)

So, Slope is,

m = (9 - 3) / (5 + 1)

m = 6/ 6

m = 1

11) Points are,

(5, -1) and (-3,-7)

So, Slope is,

m = (- 7 + 1) / (- 3 - 5)

m = - 6/- 8

m = 3/4

Thus, The value of the slope between each pair of points are,

9) - 1/3

10) 1

11) 3/4

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If you add a finite number of terms to a convergent series, the new series will still converge.

1. A convergent series is a series whose sum approaches a finite limit as the number of terms increases.

2. If you add a finite number of terms to a convergent series, you are essentially adding a fixed constant value to the original sum.

3. Since the original series converges to a finite limit, adding a fixed constant value to it will simply shift the limit by that constant value.

4. As a result, the new series will still approach a finite limit, and thus, it will also converge.

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The value of the expression 16 + 4 - (5 x 2) + 2 is 12.

To evaluate the expression 16 + 4 - (5 x 2) + 2, we follow the order of operations, which is commonly known as PEMDAS (Parentheses, Exponents, Multiplication and Division - from left to right, Addition and Subtraction - from left to right).

Let's simplify the expression step by step:

First, we perform the multiplication: 5 x 2 = 10.

Next, we evaluate the expression within parentheses: 16 + 4 - 10 + 2.

Now we perform the addition and subtraction from left to right: 16 + 4 = 20, 20 - 10 = 10, 10 + 2 = 12.

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Answer: very loud

Step-by-step explanation:

Actually ask a proper question

Answer:

Area:238 ft²

Perimeter: 62 ft

Step-by-step explanation:

You weren't clear on what you asked, so I can only assume that the question is asking for the area or perimeter.

To find the area, just multiply [tex]lw[/tex].

14·17

=238

To find the perimeter, add 14 and 17 then multiply by 2:

[tex]2(14+17)\\=62[/tex]

Hope this helps! :)

A critical value, z Subscript alphas is (c) z-score with an area of ?? to its left.

A critical value, denoted as z (Subscript α/2), is a point on the standard normal distribution curve, which is used in hypothesis testing. It helps to determine whether to accept or reject the null hypothesis. In this context, the critical value denotes the z-score with an area of ?? to its left, which represents the probability of observing a value more extreme than the critical value in the left tail of the distribution.

The critical value z Subscript α/2 signifies the z-score with an area of ?? to its left on the standard normal distribution curve, which is crucial for hypothesis testing.

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The solution to the system of inequalities is y ≤ -x and y > (3/2)x - 4 in the region bounded by the blue and red lines, but not including the blue line.

To graph the system of inequalities:

y ≤ -x

y > (3/2)x - 4

We can begin by graphing the boundary lines for each inequality, which are y = -x and y = (3/2)x - 4, respectively.

These boundary lines are shown in blue and red in the given graph

The solution to the system of inequalities is y ≤ -x and y > (3/2)x - 4 in the region bounded by the blue and red lines, but not including the blue line.

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Option C best describes the limiting values of T and a under the conditions given. In this case, T represents tension and a represents acceleration.

Without the specific conditions mentioned, it is impossible to determine the exact limiting values of T and a. However, certain options can be ruled out based on common sense and physical laws. For example, option C (T=mg and a=0) is not possible as the tension in a string cannot be equal to the weight of an object. Option E (T=0 and a=[infinity]) is also not possible as a mass cannot have zero tension and infinite acceleration.

Based on these eliminations, the most reasonable options are A (T=0 and a=0) and D (T=[infinity] and a=g). In the former case, the object is not moving and there is no tension in the string. In the latter case, the object is in free fall and the tension in the string is negligible compared to the weight of the object.

However, it is important to note that the exact limiting values of T and a will depend on the specific conditions of the scenario, such as the mass of the object and the angle of the string.

Option C best describes the limiting values of T and a under the conditions given. In this case, T represents tension and a represents acceleration. When T=mg and a=0, it means that the tension in the system is equal to the gravitational force acting on the mass (mg) and the system is in equilibrium with no acceleration. This is a common scenario when an object is hanging from a rope or cable and not moving. The other options do not represent stable or realistic conditions for a physical system.

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The solution to the initial value problem y''(t) = 18t - 84t⁵ with y(0) = 4 is:
y(t) = 3t³ - 2t⁷ + 4

To solve the initial value problem y''(t) = 18t - 84t⁵  with y(0) = 4, we need to integrate twice. First, we integrate both sides with respect to t to get y'(t):

y'(t) = ∫ (18t - 84t⁵ ) dt
y'(t) = 9t^2 - 14t⁶ + C1

where C1 is the constant of integration.

Next, we integrate y'(t) with respect to t to get y(t):

y(t) = ∫ (9t² - 14t⁶ + C1) dt
y(t) = 3t³ - 2t⁷ + C1t + C2

where C2 is the constant of integration.

To find the values of C1 and C2, we use the initial condition y(0) = 4:

y(0) = 3(0)³ - 2(0)⁷ + C1(0) + C2 = 4

Thus, C2 = 4.

To find C1, we take the derivative of y(t) and use the initial condition y'(0) = 0:

y'(t) = 9t² - 14t⁶ + C1
y'(0) = 0 + C1 = 0

Therefore, C1 = 0.

Thus, the solution is:
y(t) = 3t³ - 2t⁷ + 4

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The probability of rolling a 7 with two dice is 6/36, which simplifies to 1/6, or approximately 0.1667.

To calculate the probability of rolling a 7 with two dice, we first need to determine the total number of possible outcomes when rolling two dice. Each die has six sides, so there are 6 x 6 = 36 possible outcomes.

Next, we need to count the number of outcomes that result in rolling a 7. There are six possible ways to roll a 7: (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), and (6, 1).

Therefore, the probability of rolling a 7 with two dice is 6/36, which simplifies to 1/6, or approximately 0.1667.

To calculate the odds of rolling a 7, we need to compare the number of ways to roll a 7 to the number of ways to not roll a 7. There are 6 ways to roll a 7 and 30 ways to not roll a 7 (since there are 36 possible outcomes and 6 of them result in rolling a 7). So the odds of rolling a 7 are 6:30, or 1:5. This means that for every one time you roll a 7, you can expect to not roll a 7 five times.

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false. The vertical axis is the y-axis, which is where x=0. In this equation, when x=0, we have: y=4(0)-5
y=-5

Therefore, the line produced by the equation Y=4X−5 crosses the vertical axis at y=-5, not y=5.

To further understand this concept, we can visualize the equation on a graph. When we plot the points (0,-5) and (1,-1) (which is found by substituting x=1 into the equation), we can draw a line that passes through both points. This line is the graph of the equation Y=4X−5. We can see that the line crosses the vertical axis (y-axis) at y=-5, which confirms that the answer is false.

In summary, the equation Y=4X−5 crosses the vertical axis (y-axis) at y=-5, not y=5.

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The net displacement of the particle in motion from t=0 to t=4 given that the velocity function for the particle is v(t)=−3t 8 m/sec is 8 meters.

To determine the net displacement of a particle in motion from t=0 to t=4 with the velocity function v(t) = -3t + 8 m/sec, follow these steps:

1. Integrate the velocity function to find the displacement function. The displacement function, s(t), represents the particle's position at a given time t.
2. Calculate the displacement at t=4 and t=0 using the displacement function.
3. Subtract the displacement at t=0 from the displacement at t=4 to find the net displacement.

Integrate the velocity function
∫(-3t + 8) dt = -1.5t^2 + 8t + C, where C is the integration constant.

Calculate the displacement at t=4 and t=0
s(4) = -1.5(4)^2 + 8(4) = -1.5(16) + 32 = -24 + 32 = 8
s(0) = -1.5(0)^2 + 8(0) = 0

Find the net displacement
Net Displacement = s(4) - s(0) = 8 - 0 = 8

Therefore, the net displacement of the particle in motion from t=0 to t=4 is 8 meters.

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Answer:

Yes

Step-by-step explanation:

Answer:

To calculate the range, you need to find the largest observed value of a variable (the maximum) and subtract the smallest observed value (the minimum).

Set A:

50, 54, 56, 59, 60, 61, 61, 63

63 - 50 = 13

Set B:

78, 83, 88, 90, 92, 95, 98, 98

98 - 78 = 20

Range of Both Sets:

98 - 50 = 48

The range is a measure of dispersion, A measure of by how much the values in the data set are likely to differ from their mean. The range is easily calculated by subtracting the lowest from the highest value in the set.

The formula for the range is:

Range = maximum(xi) - minimum(xi)

where xi represents the set of values.

Range= 98-50= 48

Range= 48

First set:

63-50= 13

Second set:

98-78= 20

(Credits to the second answer)

The table is not provided in the question. However, we can use some general probability principles to solve this problem.

We are given two events:

A: The outcome is a divisor of 2.

B: The outcome is prime.

We want to find the conditional probability of A given B, denoted by P(A | B).

The formula for conditional probability is:

P(A | B) = P(A and B) / P(B)

We need to find the probability of the intersection of A and B, i.e., P(A and B), and the probability of event B, i.e., P(B).

Since 2 is the only even prime number, we know that A is equivalent to the event "the outcome is 2". Therefore, we have:

P(A) = P(the outcome is 2)

We also know that the outcome is either prime or composite, and that the prime numbers less than 10 are 2, 3, 5, and 7. Therefore, we have:

P(B) = P(the outcome is 2, 3, 5, or 7)

To find P(A and B), we note that A and B are mutually exclusive events. Therefore, if the outcome is prime, it cannot be a divisor of 2. Thus, we have:

P(A and B) = P(the outcome is 2 and the outcome is prime) = 0

Using the above equations and applying the formula for conditional probability, we get:

P(A | B) = P(A and B) / P(B) = 0 / P(B) = 0

Therefore, the conditional probability of A given B is 0. This means that if the outcome is prime, the probability that it is a divisor of 2 is 0.

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The surface area of the prism is 462.55 in².

We have,

Slant height = 20.7 in

The perimeter of the base.

= 11 + 11 + 11 + 11

= 44 in

And,

The lateral surface area of the prism.

= Area of all sides except the base area

So,

= 3 x ( 1/2 x 11 x 20.7)

There are same three triangles.

So we add up all the 3 triangles.

= 341.55 in²

And,

Area of the base.

= 11²

= 121 in²

And,

The surface area of the prism.

= Lateral surface area + base area

= 341.55 + 121

= 462.55 in²

Thus,

The surface area of the prism is 462.55 in².

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