Helium occupies a volume of 3.8 L at –45°C. What was its initial temperature when it occupied 8.3 L?

Answers

Answer 1

Answer:

98.3 gradius Celsius

Explanation:

This problem is solved using the Ideal Gas Equation

pV = nRT

...

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

Helium Occupies A Volume Of 3.8 L At 45C. What Was Its Initial Temperature When It Occupied 8.3 L?

Related Questions

A solution of KOH has a [OH-] concentration of 0.045 M. What is the pOH of the solution? *
1 point
-1.3
1.3
1.1
0.90​
what is the answer?

Answers

Answer:

[tex]pOH=1.3[/tex]

Explanation:

Hello,

In this case, since pH is computed by knowing the concentration of hydrogen ions, one could compute the pOH by knowing the concentration of the hydroxyl ions as in this case which is 0.045M as shown below:

[tex]pOH=-log([OH^-])=-log([0.045])\\\\pOH=1.3[/tex]

Best regards.

Answer:

The pOH of the 0.045 M solution is 1.3

The second option (1.3) is correct

Explanation:

Step 1: Data given

Concentration [OH-] of KOH is 0.045 M

Step 2: Calculate pOH

pOH = -log[OH-]

pOH = -log (0.045)

pOH = 1.3

The answer:

The pOH of the 0.045 M solution is 1.3

The second option (1.3) is correct

Which sulfur is a gas that reacts with liquid water to produce aqueous sulfuric acid, or acid rain. What is the equation for this reaction

Answers

Answer:

Sulfur Trioxide

Explanation:

Sulfur trioxide is a gas that reacts with liquid water to produce aqueous sulfuric acid,or acid rain.

HELP ASAP!!!! PLEASE AND THANK YOU!!!! Aluminum, which has a specific heat capacity of 0.902 J/g◦C and a mass of 20.9 g absorbs 348.0 J of energy. The final temperature (T2) is 100.0◦C. Calculate the initial temperature (T1).

Answers

Answer:

81.54 °C

Explanation:

Use the equation

q = mcΔT

348 = 20.9(0.902)(100-t)

t = 81.54 °C

*note, you don't have to convert these to kelvin since the difference will be the same

What is the molarity of a solution in
which 3.8 moles of sodium chloride
(NaCl) is dissolved in water to a final
volume of 2.5 L?

Answers

Answer:

1.52M in NaCl

Explanation:

Molarity = moles solute / volume solution in Liters

=> molarity (M) = 3.8 moles / 2.5 Liters solution = 1.52 molar solution in NaCl

Answer: 1.52

Explanation:

Porosities can have merits and demerits during manufacturing procedures of dental materials. Clarify this statement.

Answers

Answer:

The porosities in dental materials can be of merit and not merit since some dental materials need to be porous in order to reduce their weight and improve their properties and functions, whereas in those (which are the majority) porosities are not Merit, see the properties of the material, the function and can even influence dental rehabilitation.

An example of this is the use of vitreous ionomers, which is a dental material, where when it is spatulated it remains porous, it can give recurrence of infectious caries, since its permeability increases, the best cariogenic microorganisms are filtered and porosity works as a retentive site for these microorganisms that make up the dental biofilm.

In summary, the world of dental materials is very wide, some are resins, other cements, others have metallic claims, etc. To say that the presence of porosity is merit or demerit would be ideal because for some materials this is favorable and for others unfavorable since they are very versatile, with different qualities, different degrees of porosity, different molecules, different coefficients of thermal expansion, some do not set, others do not, some are light-cured, others do not, some withstand more mechanical forces and have more elastic modulus and less porosity, while others do not, and thus with many more variables.

Explanation:

In the manufacture of dental materials, much attention is always paid to what the manufacturer indicates in these indications that come on the reverse side of the material or on a paper inside the material container.

This is important to know, because the manufacturer is the one that indicates the mode of use and working time according to the trademark and the chemical composition of the dental material.

That a dental material in its manufacture is more or less porous, makes its density, weight and volume possibly be affected, there are materials that seek to increase porosity for a certain purpose, while others seek the opposite, depending on the function that is applied, will have more or less pores.

The example we gave above about the vitreous ionomer is an example that indicates that in the case of restorative dental materials where the function is to SEAL the porosity is almost nil, since otherwise it will not seal the cavity that was formed with caries and not the infectious problem would be solved.

On the other hand, in the surgical field of dentistry there are bone grafts or porous macroparticles that are for the purpose of bone replacement, which in order to be integrated need blood vessels that run over these pores, irrigating the area of ​​bone neoformation well, in this case the merit of porosity if necessary and it is essential that they be very porous.

Consider the following intermediate chemical equations.

2 equations. First: upper P subscript 4 (s) plus 6 upper C l subscript 2 (g) right arrow 4 upper P upper C l subscript 3 (g) delta H 1 equals negative 4,439 kilojoules. Second: 4 upper P upper C l subscript 3 (g) right arrow upper P subscript 4 (s) plus 10 upper C l subscript 2 (g) Delta H 2 equals 3,438 kilojoules.

What is the enthalpy of the overall chemical reaction Upper P upper C l subscript 5 (g) right arrow upper P upper C l subscript 3 (g) plus Uper C l subscript 2 (g).?
-999 kJ
-250. kJ
250. kJ
999 kJ

Answers

Answer:

PCl3 or option C

Explanation:

For everyone taking edge, trust me. Most of the answers are half-fasted, and offer no explanation. My explanation is that this is the right answer and you can trust me. Im taking the courses just like all of you, so i have no reason to misslead. Hope this helps! if you require more information, i cannot offer it. I gain knowledge by my failures.

Answer:

The correct answer is 250. kJ

Also referred to as C or Option 3

Explanation:

I got the answer correct because of the help from the other answer. Therefore, please mark the other person brainliest, they deserve it!

The radioactivity due to carbon-14 measured in a piece of a wooden casket from an ancient burial site was found to produce 20 counts per minute from a given sample, whereas the same amount of carbon from a piece of living wood produced 160 counts per minute. The half-life of carbon-14, a beta emitter, is 5730 years. Thus we would estimate the age of the artifact to be about?

Answers

Answer:

17202.6 years

Explanation:

Activity of the living sample (Ao) = 160 counts per minute

Activity of the wood sample (A) = 20 counts per minute

Half life of carbon-14 = 5730 years

t= age of the artifact

From;

0.693/t1/2= 2.303/t log Ao/A

Then;

0.693/ 5730= 2.303/t log Ao/A

Substituting values;

0.693/5730= 2.303/t log (160/20)

Then we obtain;

1.209×10^-4 = 2.0798/t

t= 2.0798/1.209×10^-4

Thus;

t= 17202.6 years

Therefore the artifact is 17202.6 years old.

H2O(g) + Cl2O(g) ↔ 2 HOCl(g) (a) Initially, 0.0555 mol H2O and 0.0230 mol Cl2O are mixed in a 1.00 L flask. At equilibrium, there is found to be 0.0200 mol of HOCl(g). Calculate the concentrations of H2O(g) and Cl2O(g) at equilibrium. (b) Using your results from part (a), calculate the equilibrium constant, Kc. (c) 1.0 mol pure HOCl is placed in a 2.0 L flask. Use your Kc from part (b) to calculate the equilibrium concentrations of H2O(g) and Cl2O(g).

Answers

Answer:

a)

[H₂O] = 0.0455M

[Cl₂O] = 0.0130M

[HOCl] = 0.0200M

b) Kc = 0.676

c) [H₂O] = [Cl₂O] = 0.177M

Explanation:

Based on the reaction:

H₂O(g) + Cl₂O(g) ⇄ 2HOCl(g)

Kc is defined as:

Kc = [HOCl]² / [H₂O][Cl₂O] For molar concentrations in equilibrium

As volume of the flask is 1.00L, the initial molar concentrations of H₂O and Cl₂O is 0.0555M and 0.0230M, respectively.

In equilibrium, the concentrations are:

[H₂O] = 0.0555M - X

[Cl₂O] = 0.0230M - X

[HOCl] = 2x = 0.0200M → X = 0.0100M

Where X is reaction coordinate

a) Concentrations in equilibrium are:

[H₂O] = 0.0455M

[Cl₂O] = 0.0130M

[HOCl] = 0.0200M

b) Replacing in Kc:

Kc = [0.0200]² / [0.0455][0.0130] = 0.676

c) Initial concentration of HOCl is 1.0mol / 2.0L = 0.50M. In equilibrium concentrations are:

[H₂O] = X

[Cl₂O] = X

[HOCl] = 0.50M - 2X

Replacing in Kc formula:

0.676 = [0.50-2X]² / [X][X]

0.676X² = 4X² - 2X + 0.25

0 = 3.324X² - 2X + 0.25

Solving for X:

X = 0.177M

X = 0.425M → False answer, produce negative concentrations.

As X = [H₂O] = [Cl₂O]; equilibrium concentrations of both compounds is 0.177M

ellus
What is the pH of a 3.5 x 10-11 M
H+ solution?
pH = [?]

Answers

Answer:

[tex]pH=10.5[/tex]

Explanation:

Hello,

In this case, since we define the pH as:

[tex]pH=-log([H^+])[/tex]

We can directly compute it by using the given concentration of H⁺:

[tex]pH=-log(3.5x10^{-11})\\\\pH=10.5[/tex]

For which we conclude it is a basic solution as the pH is greater than 7.

Best regards.

You have 0.00891 g of platinum. What is this in micrograms?

Answers

It would be 8910 micrograms.

The pressure of a gas is 100.0 kPa and its volume is 500.0 mL. If the volume increases to 1,000.0 mL, what is the new pressure of the gas?

Answers

Answer:

[tex]P_2=50kPa[/tex]

Explanation:

Hello,

In this case, we can apply the Boyle's law in order to understand the pressure-volume relationship as an inversely proportional relationship relating the initial and the final volume:

[tex]P_1V_1=P_2V_2[/tex]

Next, we compute the final pressure P2:

[tex]P_2=\frac{P_1V_1}{V_2}=\frac{100.00kPa*500.0mL}{1000.0mL} \\\\P_2=50kPa[/tex]

Thus we validate, the higher the volume the lower the pressure.

Best regards.

is the normal resting position of an object.

Answers

Answer:

being stationary relative to a particular frame of reference or another object; when the position of a body with respect to its surroundings does not change with time it is said to be at rest

Explanation:

Been stationary is the normal resting position of an object

When an object is at rest ( normal resting position ) it is stationary ( i.e. the position of the object does not change with time in relation to its environment or another object/reference  )

When an object is at rest it posses its' highest potential energy and its least kinetic energy. therefore been stationary is the normal resting position of an object.

Hence we can conclude that Been stationary is the normal resting position of an object.

Learn more : https://brainly.com/question/22533065

The tribute states of the ancient Aztec empire
were governed directly by the emperor.
made regular payments to the emperor.
acted as powerful independent city-states.
O surrounded the main Aztec city-state.

Answers

Answer:

made regular payments to the emperor.

Explanation:

The Aztec Empire was an alliance of three states: Mexico-Tenochtitlan, Texcoco, and Tlacopan. The area in and around the Valley of Mexico was ruled by these three city-states from 1428 to 1521. The state religion of the empire was polytheistic. The tribute states of the ancient Aztec empire made regular payments to the emperor.

Answer:

B

Explanation:

State whether the following is an example of a physical or chemical change:! 21. Burning a log: ________________________________! 22. Folding a piece of paper: _________________________! 23. Freezing water: _________________________! 24. Bending a copper wire. _________________________!

Answers

Answer:

Physical change

Explanation:

Because it doesn't require any chemical to change

Answer:

Physical change

Physical change

Physical change

Physical change

Explanation:

You weighed out 0.020 g of your crude aspirin product in order to determine the amount of salicylic acid impurity. Following the procedure outlined in the manual, you dissolved the solid and diluted the solution to a final volume of 10.0 mL. If the absorbance of your sample solution was 1.07, what was the percent salicylic acid in your product

Answers

Answer:

The correct answer is 7.8 percent.

Explanation:

As mentioned in the given question, the absorbance (A) of the sample solution is 1.07. To find the concentration of aspirin, Beer's law is used, that is, A = ebc

Here, e is the extinction coefficient, which is equal to 139.322 M^-1cm^-1 as per the standard value for salicylic acid, b is the pathlength, which is equivalent to 1 cm. Now putting the values we get,  

A = ebc

c = A / (eb)

c = 1.07 / (139.322 × 1)

c = 0.00768 M

Now to determine the percent salicylic acid in the sample, there is a need to compare the value of concentration determined with the concentration of aspirin given initially.  

0.02 grams is the initial concentration of aspirin mentioned in the question. The molar mass of aspirin is 240 g/mol.  

Therefore, the moles of aspirin will be,  

0.02 / 240 = 8.33 × 10^-5 moles  

The final volume of the diluted solution given is 10 ml or 0.01 liters.  

The molarity of aspirin in the diluted solution will be,  

c1 = 8.33 × 10^-5 / 0.01 = 8.33 × 10^-3 M or 0.00833 M

Now, the percent of salicylic acid in the product will be,  

c1 - c / c1 × 100

(0.00833 - 0.00768) / 0.00833 × 100 = 7.8 %

Absorbance is directly proportional to the concentration of the solution. The absorbance can be calculated if the molar absorptivity, path length, and concentration of the absorbing species are known.

The percent of salicylic acid in the solution is 7.8%

Given that:

Absorbance of the solution is = 1.07

Path length = 1 cm.

Applying Beer's Law,

A = ε b c

where,

c = concentration, A = absorbance, ε = constant, and b = path length

Now, putting the values in above equation

c = [tex]\dfrac{\text{A}}{\text {(e b)}}[/tex]

c = [tex]\dfrac{1.07}{139.32 \times 1}[/tex]        ( ε = 139.32)

c = 0.00768 M

Now, to calculate the percent of the salicylic acid in the solution, we will compare the given concentration of the aspirin.

As we know:

Given mass of aspirin = 0.02 g

Molar mass of aspririn = 240

Number of moles of aspirin = 0.02 / 240 = 8.33 x 10⁻⁵

Now, the molarity of aspirin is:

[tex]\text{Molarity}&= \dfrac{8.33 \times 10^{-5}}{0.01}\\\\\text{Molarity}&= 8.33 \times 10^{-5}[/tex]

Now, the percent of the salicylic acid is:

[tex]\dfrac{\text {C}_1 - \text C}{\text {C}_1 \times 100}[/tex]

[tex]\dfrac{(0.00833 - 0.00768)}{0.00833 \times 100}[/tex]

Percent of Salicyclic acid = 7.8%.

Thus, the percentage of the salicylic acid in the given solution is 7.8%.

To know more about Absorbance, refer to the following link:

https://brainly.com/question/17062521

A crystal of table salt (NaCl) is dissolved in water. Which of the following statements explains why the dissolved salt does not recrystallize as long as the temperature and the amount of water stay constant?

Answers

A crystal of table salt (NaCl) is dissolved in water. Which of the following statements explains why the dissolved salt does not recrystallize as long as the temperature and the amount of water stay constant?

Na+ and Cl- ions lose their charges in the water.

Water molecules surround the Na+ and Cl- ions.

Na+ and Cl- ions leave the water through vaporization.

Water molecules chemically react with the Na+ and Cl- ions.

Your answer: -

Answer: B - Water molecules surround the Na+ and Cl- ions.

Methanol (CH3OH) is the simplest of the alcohols. It is synthesized by the reaction of hydrogen and carbon monoxide
CO(g)+2H2(g)=CH3OH

If 500 mol of CO and 750 mol of H2 are present, which Is the limiting reactant?

Answers

Answer:

By reacting carbon monoxide and hydrogen the formation of methanol takes place, the reaction is,

CO(g)+2H₂(g)⇔CH₃OH (g)

Based on the given reaction, one mole of methanol is obtained by reacting one mole of carbon monoxide (CO) with the two moles of hydrogen (H₂). It is mentioned in the question that for the reaction 500 mol of carbon monoxide and 750 moles of hydrogen are present.

Therefore for 500 moles of carbon monoxide, there is a requirement of 2 × 500 moles of hydrogen, which is equivalent to 1000 moles of hydrogen (H₂). However, only 750 moles of hydrogen is present. Therefore, the limiting reactant in the given case is H₂. The present moles of H₂ will react with 0.5 × 750 moles of CO = 375 mole of CO

The additional or excess concentration of CO, which is the excess reactant will be, 500-375 = 125 moles.

A sample of gas occupies a volume of 120.0mL at a pressure of 0.75atm and a temperature of 295K. What will the volume be at a pressure of 1.25
atm and a temperature of 345K?

A)48mL

B)84mL

C)8mL

D)4mL

Answers

Answer:

A) 84 mL

Explanation:

use general gas equation P1×V1 / T1 = P2×V2/T2

rearrange the formula and solve for V2,it should give you V2= 84mL

Answer:

[tex]\large \boxed{\text{B) 84 mL}}[/tex]

Explanation:

We can use the Combined Gas Laws to solve this problem .

[tex]\dfrac{p_{1}V_{1} }{T_{1}} = \dfrac{p_{2}V_{2}}{T_{2}}[/tex]

Data

p₁ = 0.75 atm; V₁ = 120.0 mL; T₁ = 295 K  

p₂ = 1.25 atm; V₂ = ?;              T₂ = 345 K

Calculations

[tex]\begin{array}{rcl}\dfrac{p_{1}V_{1} }{T_{1}} & = & \dfrac{p_{2}V_{2}}{T_{2}}\\\\\dfrac{\text{0.75 atm $\times$ 120.0 mL}}{\text{295 K}} & = & \dfrac{\text{1.25 atm} \times V_{2}}{\text{345 K}}\\\\\text{0.305 mL} & = & \text{0.003 523V}_{2}\\V_{2}& =& \dfrac{\text{0.305 mL}}{0.003523}\\\\& = & \textbf{84 mL}\\\end{array}\\\text{The new volume of the gas is $\large \boxed{\textbf{84 mL}}$}[/tex]

Which of the following describes the change in atomic mass and atomic number during this reaction?

Answers

The mass number tells us the number (the sum of nucleons) of protons and neutrons in the nucleus of an atom. ... It is traditionally represented by the symbol Z. The atomic number uniquely identifies a chemical element. In an atom of neutral charge, atomic number is equal to the number of electrons.

An ethylene gas torch requires 300 L of gas at 0.8 atm. What will be the pressure of the gas if ethylene is supplied by a 200.0 L tank?

Answers

Answer:

1.2 atm

Explanation:

Given data

Volume of the gas in the tank (V₁): 200.0 LPressure of ethylene gas in the tank (P₁): ?Volume of the gas in the torch (V₂): 300 LPressure of the gas in the torch (P₂): 0.8 atm

If we consider ethylene gas to be an ideal gas, we can find the pressure of ethylene gas in the tank using Boyle's law.

[tex]P_1 \times V_1 = P_2 \times V_2\\P_1 = \frac{P_2 \times V_2}{V_1} = \frac{0.8atm \times 300L}{200.0L} = 1.2 atm[/tex]

If a solution has a pOH=12, what is its pH?

Answers

Answer:

2

Explanation:

pH+pOH=14

- Hope that helps! Please let me know if you need further explanation.

Answer:

2

Explanation:

Ph+PoH=14

An empty weighing dish has a mass of 1.0041 ± 0.0002 g. After you add dried sodium chloride to the dish, the mass is 3.2933 ± 0.0002 g. You quantitatively transfer the sodium chloride into a 500.00 ± 0.05 mL volumetric flask and dilute to the mark with deionized water. The molar mass of sodium chloride is 58.440 g/mol. What is the absolute error in the concentration of the resulting solution? Report your answer normally to the correct number of significant figures with the correct unit.

Answers

Answer:

The correct answer to the following question will be "0.0013%".

Explanation:

The given values are:

Weight of an empty dish = 1.0041 ± 0.0002 g

Weight of dish + sodium chloride (NaCl) = 3.2933 ± 0.0002 g

Weight of NaCl = 2.2892 ± 0.0002 g

Now,

Volume of the solution = 500.00 ± 0.05 ± 0.0002

                                      = 500.00 ± 0.0502 ml

So,

Molarity = [tex]\frac{W \ NaCl}{M \ NaCl} \times \frac{1000}{Volumes \ of \ solution}[/tex]

On putting the values in the above formula, we get

             = [tex]\frac{(2.2892\addeq +0.0002)}{58.440}\times \frac{1050}{(500.00+0.0502)}[/tex]

             = ([tex]3.917[/tex] ± [tex]0.0002[/tex]) × ([tex]2[/tex] ± [tex]0.0502[/tex])

             = ([tex]0.7834[/tex] ± [tex].00001004[/tex])

Now,

Absolute error = [tex]\frac{0.00001004}{0.7834}\times 100[/tex]

                         = [tex]0.0013[/tex]%

How many kilograms of solvent (water) must 0.71 moles of KI be dissolved in to produce a 1.93 m solution?

Answers

Answer: kg= 0.37

Explanation:

Use the molality formula.

M= m/kg

_______ occurs when a body’s molecular wavelength sends vibrations to another body, resulting in the production of another sound wave

Answers

Answer:

Natural frequency

Explanation:

Answer:

Resonance

Explanation:

The change in entropy, ΔS∘rxn , is related to the the change in the number of moles of gas molecules, Δngas . Determine the change in the moles of gas for each of the reactions and decide if the entropy increases, decreases, or has little or no change. A. 2H2(g)+O2(g) ⟶ 2H2O(l) Δngas= mol The entropy, ΔS∘rxn , increases. decreases. has little or no change.

Answers

Explanation:

Entropy of a reaction ΔS∘rxn is the degree of disoderliness in a system. Gases generally have a higher degree of disorder compared to liquids. Hence for the reaction 2H2(g)+O2(g) ⟶ 2H2O(l), the entropy decreases sice the reactants are in the gaseous state and the products is in the liquid state of matter

If 120.4 grams of reactant completely breaks down (decomposes) to produce 106.4 grams of chlorine. What mass of nitrogen gas could be expected? *

Answers

Answer:

[tex]m_{nitrogen}=14g[/tex]

Explanation:

Hello,

In this case, since we are talking about a chemical reaction in which a compound having nitrogen and chlorine is decomposed into chlorine and nitrogen, we must remember that the law of conservation of mass must be obeyed, for that reason, we notice that the mass of the whole reactants must equal the mass of the whole products, as shown below:

[tex]m_{reactants}=m_{products}[/tex]

Next, we know there is only one single reactant and products are constituted by both chlorine and nitrogen:

[tex]m_{reactant}=m_{chlorine}+m_{nitrogen}[/tex]

In such a way, we can compute the mass of nitrogen as shown below:

[tex]m_{nitrogen}=m_{reactant}-m_{chlorine}=120.4g-106.4g\\\\m_{nitrogen}=14g[/tex]

Best regards.

does the reaction Fe + CuNO3 occur

Answers

Answer:

yes

Explanation:

Sometimes in the lab we collect the O2gas formed by a chemical reaction over water (see sketch at right). This makes it easy to isolate and measure the amount of gas produced. Suppose the gas evolved by a certain chemical reaction taking place at 55.0C is collected over water, using an apparatus something like that in the sketch, and the final volume of gas in the collection tube is measured to be 117mL. Calculate the mass of that is in the collection tube. Round your answer to significant digits. You can make any normal and reasonable assumptions about the reaction conditions and the nature of the gases.

Answers

Answer:

mass CO = 0.12166 g

Explanation:

Mass of CO = 0.12 grams

Explanation

Volume of CO gas = 117 mL = 0.117 L

Temperature of CO = 55.0 oC = 328 K

Assumption : Pressure of CO = atmospheric pressure = 1.0 atm

According to ideal gas law,

moles of CO = [(Pressure of CO) * (Volume of CO gas)] / [(R) * (Temperature of CO)]

where R = gas constant = 0.0821 L-atm/mol-K

moles of CO = [(1.0 atm) * (0.117 L)] / [(0.0821 L-atm/mol-K) * (328 K)]

moles of CO = 0.004345 mol

mass CO = (moles of CO) * (molar mass CO)

mass CO = (0.004345 mol) * (28.0 g/mol)

mass CO = 0.12166 g

a hot liquid located under earth's surface?​

Answers

Answer:

Magma

Explanation:

Magma is the hot liquid under earths surface

Which of the following is not an indication of a chemical change?
A. Fracture Formation
B. Energy transfer
C. Precipitate formation.
D. Gas production

Answers

Answer:

C. precipitate formation.

Explanation:

options C is correct answer.

Answer:

C. precipitate formation.

Explanation:

Other Questions
I need help plzzzz Im nearly done THIS IS NOT A QUESTION! This is a list of Area and Perimeter on the coordinate plane answers from Khan Academy. approximate perimeter of STRIPE is 36.01area of rectangle TOUR is 80perimeter of of polygon CHOMP is 32.52area of parallelogram YORK is 122the area of trapezoid MASK is 34 The approximate perimeter of polygon CODIFY is 51.53 The area of triangle SOL is 52The approximate perimeter of polygon DINGO is 34.44the approximate perimeter of the isosceles triangle PAZ is 20.03the area of triangle CAW is 10The approximate perimeter of rectangle PEAR is 34.99The area of trapezoid COWL is 45The area of triangle TOP is 87/2 unitsThe approximate perimeter of triangle VEN is 29.80The area of parallelogram TOWN is 40 the approximate perimeter of quadrilateral BOAT is 30.34 Q9. A cylindrical specimen of a metal alloy 54.8 mm long and 10.8 mm in diameter is stressed in tension. A true stress of 365 MPa causes the specimen to plastically elongate to a length of 61.8 mm. If it is known that the strain-hardening exponent for this alloy is 0.2, calculate the true stress (in MPa) necessary to plastically elongate a specimen of this same material from a length of 54.8 mm to a length of 64.7 mm. (10 points) Which was not true about the first TV? Your drawer contains seven red socks and five green socks. It's too dark to see which are which. What is theprobability that the two socks that you pick are both red if you don't replace the first sock after you draw it?7/247/127/1514/35 which element in a story can better help a reader understand the theme Solve algebraically 8x + 4y = 4812x + 5y = 21 Based on the passage, which of the following sets of notes are ordered most appropriately?A. the releasing of high energyobserved on September 1, 1859solar flares stay near the Sun11-year period cyclesdamages space equipmentB. in the Sun's outermost atmospherenoticed on September 1, 1859observed by Carrington and Hodgsoncontains radio waves and gamma raysdisruption of radio communicationC. high-energy particles are heatedmore solar flares at cycle's heightdiscovered in 1859affects communications on Earthendangers astronautsD. bright, high-energy spots on the Sundiscovered by Carrington and Hodgsonoccurs generally in a 11-year periodimpacts the space around the Sunreleases radiation that affects people when it comes to the value of money, the perfect balance is when face value is in line with what?A. the market value of moneyB. the government value of moneyC. the money being printedD. the money being spent The solutions to a certain quadratic equation are x = 4 and x = -3. Write the equation in standard form below.x2 + x - 12 = 0x2 - x - 12 = 0x2 - 7x + 12 = 0 What is the measure of leg b?a. 16b. 23.3c. 32d. 34 mention elements of art 6. For the following waste treatment facility, chemical concentration (mg/gal) within the tank can be considered uniform. The initial chemical concentration inside the tank was 5 mg/gal, the concentration of effluent coming in is 20 mg/gal. The volume of the tank is 600 gallons. The fluid coming in rate is equal to fluid going out is equal to 60 gal/min. (a) Establish a dynamic model of how the concentration of chemical inside the tank increases over time. Specify the units for your variables. (Hint: establish a mass balance of the waste chemical. The concentration inside the tank = concentration going out) (b) Find the Laplace transformation of the concentration (transfer function) for this step input of 20 mg/gal. A snack company makes three batches of a nut mix using the recipe shown.Each batch contains a different total amount of mix.Drag numbers to show how much of each type of nut should be used in each batch.1 of the mix is pistachios.of the mix is almondsof the mix is cashews PLEASE HELP!!! What did Joan Miro believe the purpose of doodling was? Write the equation of the line in slope intercept form y=mx + b that would have the slope of two and crosses through the ordered pair (-3,5). 4. A plane was flying at an altitude of 55,000 feet when it began the descent toward the airport. The airplandescends at a rate of 825 feet per minute.A. What is the function rule that describes this situation?B. What is the altitude of the plane after it has descended for 13 minutes? Show your workC. Use the function in Part A to determine how long it takes for the plane to land if it descends at acontinuous rate. What is the volume of this rectangular prism? Porosities can have merits and demerits during manufacturing procedures of dental materials. Clarify this statement. fourteen less then the product of five and nine in numerical expressionpls help