Hello please help ASAP!

Hello Please Help ASAP!

Answers

Answer 1
Correct answer is B, Length is 32 while the width is 40

Related Questions

I have like no clue what this means, please help! :)

Answers

Answer:

1/9

You are being asked to "complete the square"

you need to find a value to make the quadratic a "perfect square:

the focus is -2/3 you need to "add" one half of -2/3 squared to the

equation (1/2 * -2/3)^2 .... (-2/6)^2 .... 4/36 .... 1/9

Step-by-step explanation:

WILL MARK AS BRAINLIEST. PLS HLP MEEE​

Answers

I’m confused what are u trying to am skmdi
Uhm I think it’s 21 because I don’t know the answer well

HELP WILL GIVE BRAINLIEST

Answers

Answer:

A.   hexagonal prism

Step-by-step explanation:

The box has 2 congruent hexagons as bases, and 6 congruent rectangles as sides.

Answer: hexagonal prism

0.54,0.45,0.405,0.054 in order smallest first

Answers

Answer:

0.054, 0.405, 0.45, 0.54

Answer:

0.054, 0.405, 0.45, 0.54

Step-by-step explanation:

1. The 0 after the decimal point makes it the smallest

2. 405/1000 < 45/100

3. 45/100 < 54/100

Find the area of a circle with radius, r = 5.72m.
Give your answer rounded to 2 DP.
r
The diagram is not drawn to scale.

Answers

Answer:

A≈102.79

Step-by-step explanation:

The formula for area of a circle is πr² so we need to substitute the r by 5.72.

π×5.7² = 102.79 m²

Answer:

Approximately 102.79 meters squared

Step-by-step explanation:

pi times 5.72 meters squared

Hope this helps!

Use the distributive property to write the next step in simplifying the numerical expression. Use the asterisk symbol (*) to represent multiplication. Do not multiply factors fully and do not use spaces. 4(x + 9)​

Answers

Answer:

This is the expression:

4*x+4*9

Someone please help, this is the last question on my assignment, and I really need to get it right! I'll mark brainliest for the best answer ^-^

Answers

Answer:

x + 2

Step-by-step explanation:

im sure its the right answe

Please help me with this question.

Answers

Answer:

Step-by-step explanation:

-1 ≤ x < 3    Solution set = {-1, 0 ,1 , 2}

-2 < x < 2   Solution set  = {-1 , 0 , 1}

Integer values that satisfies both inequalities are -1 , 0 , 1

        I \\\\\\\\\   I                                                                                                          

      [-1]          -3                                                                                                                  I   \\\\\\\\\\\   I                                                                                                            -2              2                                                                                                            [tex]\displaystyle\bf x\in[-1;2)\\-1;0;\underline1\\\\Answer: 1[/tex]                                                                                                                                                                                                                                    

Someone help me with these math problems please
Please

Answers

Answer:

a = 15

34.8 + b = 54.6

Step-by-step explanation:

First one:

5a - 10b = 45  (b = 3)

5a - 10(3) = 45

5a - 30 = 45

5a = 75

a = 15

Second one

b + a + 3a = 54.6

b + 4a = 54.6   ( a = 8.7)

b + 4(8.7) = 54.6

b + 34.8 = 54.6

34.8 + b = 54.6

Answer:

a=15 26.1 + b =54.6

Step-by-step explanation:

for the second question we first multiply 8.7 by 3 which gives us 26.1 and since there is only one answer with 26.1 it's it.

factories ((x+2)+3x+6. 2a(a-1)-a+1​

Answers

Answer:1. = 4x+8  

2. 2a²-a+1

Step-by-step explanation:

1. ((x+2)+3x+6.  2. 2a(a-1)-a+1​

((x+2)+3x+6

= x+2+3x+6

= 4x+8

2a(a-1)-a+1

2a²-2a-a+1

2a²-a+1

Rewrite the equation by completing the square.

Answers

Answer:

4(x - [tex]\frac{1}{2}[/tex] )² = 0

Step-by-step explanation:

Given

4x² - 4x + 1 = 0 ( factor out 4 from the first 2 terms )

4(x² - x) + 1 = 0

To complete the square

add/subtract ( half the coefficient of the x- term)² to x² - x

4(x² + 2(- [tex]\frac{1}{2}[/tex] )x + [tex]\frac{1}{4}[/tex] - [tex]\frac{1}{4}[/tex] ) + 1 = 0

4(x - [tex]\frac{1}{2}[/tex] )² - 1 + 1 = 0

4(x - [tex]\frac{1}{2}[/tex] )² = 0

In London today, four times the high temperature was more than twice the high temperature plus
sixty-six. In interval form, what are the possible temperatures

Answers

Answer:

Let's define the high temperature as T.

We know that:

"four times T, was more than 2*T plus 66°C"

(i assume that the temperature is in °C)

We can write this inequality as:

4*T > 2*T + 66°C

Now we just need to solve this for T.

subtracting 2*T in both sides, we get:

4*T - 2*T > 2*T + 66°C - 2*T

2*T > 66°C

Now we can divide both sides by 2:

2*T/2 > 66°C/2

T > 33°C

So T was larger than 33°C

Notice that T = 33°C is not a solution of the inequality, then we should use the symbol ( for the set notation.

Then the range of possible temperatures is:

(33°C, ...)

Where we do not have an upper limit, so we could write this as:

(33°C, ∞°C)

(ignoring the fact that ∞°C is something impossible because it means infinite energy, but for the given problem it works)

Tommy went to the shop where there was a 20% off sale taking place
The shirt he wanted to buy was originally £20
How much money does he save in the sale?

Answers

Answer:

4 pounds

Step-by-step explanation:

take 20% off the original price. 20(0.20)= 4

So that's a discount of 4 pounds and the sale price is 16 pounds.

The savings is 4 pounds on 1 shirt.

A claim is reviewed for MOHS surgery on the foot that was performed in 1 stage with 6 tissue blocks. The claim was reported with 17311, 17312-51, 17312-51. Is this correct

Answers

Answer:

17311, 17315  

Step-by-step explanation:

Explanation,

Mohs surgery, also known as chemosurgery, created by a general surgeon, Dr. Frederic E. Mohs, is performed to remove complex or ill-defined cutaneous malignancy.

List Of CPT Codes For Mohs Surgery

CPT Code 17311 and CPT Code 17313 are the base codes for the range of this surgery. CPT Code 17312, CPT Code 17314, and CPT Code 17315 are the add-on codes for this range.

Description Of CPT Code 17311

Moh’s micrographic technique, including removal of all gross tumor, surgical excision to tissue specimens, mapping, color coding of specimens, microscopic examination of specimens by the surgeon, and histopathologic preparation including routine stain(s) (eg. Hematoxylin and eosin, toluidine blue), head, neck, hands, feet genitalia, or any location with surgery directly involving muscle, cartilage, bone, tendon, major nerves, or vessels; first stage, up to 5 tissue blocks

Description Of CPT Code 17315 (addon)

CPT Code 17315 may be used to report each block after the first 5 blocks for any single-stage.

Moh’s micrographic technique, including removal of all gross tumor, surgical excision of tissue specimens, mapping color coding of specimens, microscopic examination of specimens by the surgeon, and histopathologic preparation including routine stains(s) (eg. Hematoxylin and eosin, toluidine blue), each additional block after the first 5 tissue blocks, any stage (List separately in addition to code for primary procedure)

Extras

Description Of CPT Code 17312 (addon)

Each additional stage after the first stage, up to 5 tissue blocks (List separately in addition to code for primary procedure)

Description of CPT Code 17313

Moh’s micrographic technique, including removal of all gross tumor, surgical excision of tissue specimens, mapping, color coding of specimens, microscopic examination of specimens by the surgeon, and histopathologic preparation including routine stains(s) (eg. Hematoxylin and eosin, toluidine blue), of the trunk, arms, or legs; first stage, up to 5 tissue blocks

Description Of CPT Code 17314 (addon)

Each additional stage after the first stage, up to 5 tissue blocks (List separately in addition to code for primary procedure).

Solve for x. Round to the nearest tenth of a degree, if necessary

Answers

Answer is x=50.1

Step 1

Tanx=opposite/adjacent

Step2

Tanx=6.1/5.1

x=arctan(6.1/5.1)

x=50.1

Answer in degrees as required

Find the lenght of x

Answers

Answer:

Answer in on Attached photo.

[tex]\color{red}{==========================}[/tex]

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✍︎ʀʀʏɴʟʀɴɪɴɢ

If < A and < B are vertical angles, and < A is 43 ° , then what is the measure of < B?

Select one:
a. 47 °
b. 137 °
c. 21 °
d. 43 °

Answers

Answer:

d

Step-by-step explanation:

vertical angles are congruent , so

∠ B = ∠ A  = 43°

Evaluate the function. f(x)=−x^2 −6x+12 Find f(4)

Answers

1. How to find f(4)?

I explained how to find f(5) in your previous question. It is exactly the same. We substitute x = 4 in the equation.

2. Substitution and Evaluate

[tex] \large{f(4) = - {(4)}^{2} - 6(4) + 12} [/tex]

Follow BODMAS/PEMDAS rules as well! Exponent first.

[tex] \large{ f(4) = - 16 - 24 + 12} \\ \large{f(4) = - 40 + 12} \\ \large{f(4) = -2 8}[/tex]

3. Final Answer

f(4) = -28.

Solve for x. Round to the nearest tenth of a degree, if necessary.

Answers

Answer:

[tex]x\approx 49.6^{\circ}[/tex]

Step-by-step explanation:

In any right triangle, the tangent of an angle is equal to its opposite side divided by its adjacent side.

For angle [tex]x[/tex]:

Opposite side is 40Adjacent side is 34

Therefore, we have:

[tex]\tan x^{\circ}=\frac{40}{34}[/tex]

Take the inverse tangent of both sides to solve for [tex]x[/tex]:

[tex]\tan^{-1}(\tan x)=\tan^{-1}(\frac{40}{34}),\\x=\tan^{-1}(\frac{40}{34}),\\x=49.63546343\approx \boxed{49.6^{\circ}}[/tex]

*Recall [tex]\tan^{-1}(\tan x)=x\text{ for } x\in (-90^{\circ}, 90^{\circ})[/tex]

FOR EASY BRAINLIEST ANSWER QUESTION BELOW!

1. Solve each word problem .twice a number added three times the sum of the number and 2 is more than 17. Find the numbers that satisfy condition

Answers

Answer:

x > 23/5

Step-by-step explanation:

2x+ 3(x+2)>17

2x + 3x + 6 >17

5x >23

x > 23/5

Find the integral of x(4x² + 1) from 0 to 2. a. 18 c. 22 b. 16 d. 20

Answers

Answer:

a. 18

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Distributive Property

Algebra I

Terms/Coefficients

Calculus

Integrals

Definite Integrals

Integration Rule [Reverse Power Rule]:                                                                      [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:                                        [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

Integration Property [Multiplied Constant]:                                                             [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Integration Property [Addition/Subtraction]:                                                           [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \int\limits^2_0 {x(4x^2 + 1)} \, dx[/tex]

Step 2: Integrate

[Integrand] Distribute x [Distributive Property]:                                              [tex]\displaystyle \int\limits^2_0 {(4x^3 + x)} \, dx[/tex]Rewrite Integral [Integration Property - Addition/Subtraction]:                     [tex]\displaystyle \int\limits^2_0 {4x^3} \, dx + \int\limits^2_0 {x} \, dx[/tex]Rewrite 1st Integral [Integration Property - Multiplied Constant]:                 [tex]\displaystyle 4\int\limits^2_0 {x^3} \, dx + \int\limits^2_0 {x} \, dx[/tex][Integrals] Reverse Power Rule:                                                                      [tex]\displaystyle 4(\frac{x^4}{4}) \bigg| \limits^2_0 + (\frac{x^2}{2}) \bigg| \limits^2_0[/tex]Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]:              [tex]\displaystyle 4(4) + 2[/tex]Evaluate:                                                                                                           [tex]\displaystyle 18[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

The nth term for the question

Answers

Answer:

Step-by-step explanation:

1) nth therm = dn + (a - d)

-10n + (11+10)

-10n + 21

t11 = -110 + 21 = -89

2) nth therm = 3n + (-66 - 3)

3n - 69

t16 = 48 - 69 = -21

Can someone help me with this math homework please!

Answers

Answfirst one

Step-by-step explanation:

hope it helps thank u

Answer:

first one

Step-by-step explanation:

2 students have the same age but different heights.

since age is the input and height is the output. in order to be a function one must have exact one output for one input.

since the heights of students in Tessa 's class are not a function of their ages (one input must have two outputs) two students of same age must have different heights.

what s the equation of the line through the origin and (-2, 3)

Answers

Answer:

y=[tex]\frac{-3x}{2}[/tex]

Step-by-step explanation:

Hi there!

We need to find the equation of the line that passes through the origin (the point (0,0)) and (-2,3)

There are 3 ways to write the equation of the line, although the most common way is slope-intercept form.

Slope-intercept form is given as y=mx+b, where m is the slope and b is the y intercept

So we need to find the slope of the line first

The formula for the slope (m) calculated from two points [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex] where ([tex]x_{1}[/tex],[tex]y_{1}[/tex]) and ([tex]x_{2}[/tex], [tex]y_{2}[/tex]) are points

We have the needed information to calculate the slope, but let's label the values of the points to avoid any confusion

[tex]x_{1}[/tex]=0

[tex]y_{1}[/tex]=0

[tex]x_{2}[/tex]=-2

[tex]y_{2}[/tex]=3

Now substitute their values into the equation and find m

m=[tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

m=[tex]\frac{3-0}{-2-0}[/tex]

subtract

m=[tex]\frac{3}{-2}[/tex]

so the slope of the line is [tex]\frac{3}{-2}[/tex]. It can also be rewritten as [tex]\frac{-3}{2}[/tex]

Here is the equation of the line so far:

y=[tex]\frac{-3x}{2}[/tex]+b

we need to find b

As the equation passes through both (0,0) and (-2,3), we can use either one of them to solve for b

Let's take (0,0) for this case

Substitute 0 as x and 0 as y

0=-[tex]\frac{3}{2}[/tex](0)+b

multiply

0=0+b

add 0 to both sides

0=b

So b is 0

The equation of the line therefore is y=[tex]\frac{-3x}{2}[/tex]

Hope this helps!

Find the measure of the indicated angle to the nearest degree using trig functions. (if you can also give me step by step on how to get the answer that would be great)


A) 21°
C) 20°
B) 70°
D) 9°

Answers

Answer:

A ; 21

Step-by-step explanation:

Here, the side facing the right angle is the hypotenuse and it has a measure of length 42

The side facing the missing angle is the opposite and it has a length of 15

The trigonometric ratio that connects the hypotenuse and the opposite is the sine

The sine of an angle is the ratio of the opposite to the hypotenuse

Thus;

sine ? = 15/42

sine ? = 0.357

? = arc•sim 0.357

? = 21 degrees

HELPPPPPP i will give brainliest!!!!!

Answers

Answer:

10-5=5 answer is 8^5

Step-by-step explanation:

Answer:

[tex]8^{5}[/tex]

Step-by-step explanation:

[tex]\frac{8^{10} }{8^{5} }[/tex]

Where are there more 8's ?

top

How many more?

5

Then they stay on top of fraction.

Another way :

[tex]x^{a}[/tex] ÷ [tex]x^{b}[/tex] = [tex]x^{a-b}[/tex]

[tex]8^{10}[/tex]  ÷ [tex]8^{5}[/tex] = [tex]8^{10-5}[/tex] = [tex]8^{5}[/tex]

685 gym members were asked if they use the elliptical machine or treadmill as their primary cardiovascular exercise. 257 said they use the treadmill, 157 said they use the elliptical, and 85 said they use both.

a.) Organize this using a venn diagram (2 marks)

b.) A gym member is chosen from this group. What is the probability that this member uses the treadmill only? (1 mark)

Answers

Given:

Total number of gym members = 685

257 said they use the treadmill, 157 said they use the elliptical, and 85 said they use both.

To find:

a. The venn diagram.

b. The probability that a member uses the treadmill only?

Solution:

(a)

We have,

Total number of gym members = 685

Treadmill user = 257

Elliptical user = 157

Who use both = 85

Only treadmill user is:

[tex]257-85=172[/tex]

Only Elliptical used

[tex]157-85=72[/tex]

Therefore, the venn diagram for the given situation is shown below.

(b)

The member who use treadmill only = 172

Total user = 685

The probability that a member uses the treadmill only is:

[tex]P(\text{Only treadmill})=\dfrac{\text{Only treadmill users}}{\text{Total users}}[/tex]

[tex]P(\text{Only treadmill})=\dfrac{172}{685}[/tex]

Therefore, the probability that a member uses the treadmill only is [tex]\dfrac{172}{685}[/tex].

I tried figuring it out but its kinda hard not knowing what to make as an equation?

Answers

Its 7 ft
11ft - 4ft = 7ft

If f(x) = -3 3 and g(x)= 4x2 + 2x - 4, find (f +g)(x).

Answers

Answer:

A. 4x² + 9x/4 - 7

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Terms/CoefficientsFunctionsFunction Notation

Step-by-step explanation:

Step 1: Define

Identify

f(x) = x/4 - 3

g(x) = 4x² + 2x - 4

(f + g)(x) is f(x) + g(x)

Step 2: Find

Substitute in functions:                                                                                     (f + g)(x) = x/4 - 3 + 4x² + 2x - 4Combine like terms:                                                                                         (f + g)(x) = 4x² + 9x/4 - 7

Question is in the photo*

Answers

Answer:

3x - y +5=0

Step-by-step explanation:

Slope:-

=> m = 2-8/-1-1 = -6/-2

=> m = 3

Using point slope form :-

=> y - 2 = 3 ( x - (-1))

=> y - 2 = 3x + 3

=> 3x - y +5 = 0

Answer:

y=3x+5

Step-by-step explanation:

first find the gradient

m=y2-y1/x2-x1

from the coordinates you are given x one is -1,x two is1,y one is 2,y two is 8

8-2/1-(-1)

=3

therefore the gradient is 3

after finding the gradient use the equation

y-y1=m(x-x1)

substitute x1,y1 and the gradient..y and x are constant

y-2=3(x-(-1))

y-2=3x+3

y=3x+3+2

y=3x+5

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