Hello so can someone help me with this problem. My teacher doesn't explain it very well </3​

it is an odd number containing 7 on unit place.

Answer:

its odd.

Step-by-step explanation:

if the unit place is divisible by two or it is zero then the number is even otherwise it is odd.

Answer:

1980

Step-by-step explanation:

Answer:

195

Step-by-step explanation:

65x3

Answer:

The area of the shaded region is the difference between the areas of the rectangle and the square.

Step-by-step explanation:

Answer:

using phythagoras formula of right angles we can calculate the hypotenuse

1^2=x^2+17^2

x^2=17^2-1^2(transpose)

×^2=288 (introduce a square root)

x=15.01(round of to the nearest tenth)

Step-by-step explanation:

x=10

The measure of the hypotenuse is 17.029

If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have Pythagoras theorem:

|AC|^2 = |AB|^2 + |BC|^2    

where |AB| = length of line segment AB. (AB and BC are rest of the two sides of that triangle ABC, AC being the hypotenuse).

Given;

The legs of a right triangle measures 1 cm

The other leg measures 17 cm

Now,

|AC|^2 = |AB|^2 + |BC|^2    

|AC|^2 = |1|^2 + |17|^2    

|AC|^2 = 1 + 289

AC=17.029

Therefore, by pythagoras theorem answer will be 17.029.

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We have that  The Total Number of People is

[tex]X\approx 137[/tex]

From the question we are told that

sample of 200

income is $48,000 per year

standard deviation of $9000

Generally the equation for the Ratio of people  is mathematically given as

[tex]Y=P(\frac{39000-48000}{9000}<z<\frac{57000-48000}{9000})\\\\\Y=P(z<1))-(1-p(z-1))\\\\Y=0.8413-0.1582\\\\\Y=0.6826[/tex]

Therefore

The Total Number of People is

[tex]X=0.6826*200\\\\X\approx 137[/tex]

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Answer:

24.464~20 pounds

Step-by-step explanation:

11.12*2.20

=24.464

24.46=20

Hope this helps :)

The best estimate of the weight of the box in pounds is 2,446.4 pounds.

Given that, a box filled with books weighs 1112 kilograms.

We need to find what is the best estimate of the weight of the box in pounds.

To convert kilograms to pounds, multiply your kilogram measurement by 2.2.

Given, 1 kilogram = 2.20 pounds

Now, 1112×2.2=2,446.4 pounds

≈2,446

Therefore, the best estimate of the weight of the box in pounds is 2,446  pounds.

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Answer:

To the thousandth place

9514 1404 393

Answer:

   [[. . 3 6 .][1 3 4 9 .][9 2 . 7 1][. 1 2 8 3][. 4 9 . . ]]

Step-by-step explanation:

It is helpful to remember that the first four digits {1, 2, 3, 4} total 10, and the last four digits {6, 7, 8, 9} total 30. It is also worthwhile to note that the smallest sum of two digits is 3 = 1+2, and the largest sum of 2 digits is 17 = 8+9. Some sums can only be made one way: 4 = 1+3, 16 = 7+9.

Here, we will refer to rows 1-5 from the top down, and columns 1-5 from the left to right.

__

Based on the above, column 5 can only be made one way: 1+3. Column 4 can only be made one way: 9+8+7+6. Then the choices for row 3B will be 1+7 or 5+3. We know it can't be 5+3 because 5 is not part of column 4. This makes our first fill-in (row, column) be (3,4)=7, (3,5)=1, (4,5)=3.

The sum of the remaining cells in row 4 must be 14-3 = 11, and cell (4,4) must be 6, 8, or 9. It cannot be 9, because that would require the remaining two cells to have a sum of 2, which they cannot. So, cell (4,4) is 6 or 8.

Cell (1,4) cannot be 9, either, because we cannot use 0 in cell (1,3). Then the only place for 9 in column 4 is in cell (2,4)=9.

With cell (1,4) being restricted to 6 or 8 (the two remaining numbers in column 4, cell (1,3) must be 3 or 1, and cell (2,3) must be 4 or 6. It cannot be 6 because that would require a sum of 2 in the first two cells of row 2, so (2,3)=4, (1,3)=3, and (1,4)=6. This makes (4,4)=8 and the remaining two cells of row 4 must be 1 and 2. 1 cannot go in (4,3), so we must have (4,3)=2 and (5,3)=9, (5,2)=4, (4,2)=1. That leaves 2 and 3 for rows 2 and 3 of column 2. The first two cells of row 2 must total 4, so must be 1 and 3. Cell (2,2) cannot be 1, so must be 3, leaving (2,1)=1, (3,1)=9, (3,2)=2 and that completes it.

The fill-ins are ...

   [. . 3 6 .]

  [1 3 4 9 .]

  [9 2 . 7 1]

  [. 1 2 8 3]

  [. 4 9 . . ]

Answer:

1 is your answer. I HOPE IT WILL HELP YOU A LOT.

Answer: 6

Step-by-step explanation:

3 (x-1) = x + 9

3x - 3 = X + 9

3x - x = 9 + 3

2x = 12

x = 12/2

x = 6

The correct answer will be "n = 6". A complete solution is provided below.

Let,

The number be "n".

According to the question, the expression will be:

→  [tex]3(n-1)=9+n[/tex]

→     [tex]3n-3=9+n[/tex]

By adding "3" both sides, we get

→  [tex]3n-3+3=9+n+3[/tex]

→              [tex]3n=12+n[/tex]

By subtracting "n" from both sides, we get

→        [tex]3n-n=12+n-n[/tex]

→               [tex]2n=12[/tex]

→                 [tex]n=\frac{12}{2}[/tex]

→                 [tex]n = 6[/tex]

Thus the above is the appropriate answer.

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Lets call the above set of points [tex]L[/tex].

The domain is between minimum and maximum of the x-coords points specified,

[tex]\mathrm{min}(L;x)=0[/tex]

[tex]\mathrm{max}(L;x)=7[/tex]

So domain is [tex]D_L=[\mathrm{min}(L;x),\mathrm{max}(L;x)]=[0,7][/tex].

The range is the same story but you look at y values,

[tex]\mathrm{min}(L;y)=-8[/tex]

[tex]\mathrm{max}(L;y)=8[/tex]

So range is [tex]R_L=[\mathrm{min}(L;y),\mathrm{max}(L;y)]=[-8,8][/tex].

Hope this helps :)

[tex]\displaystyle \huge \boxed{\mathfrak{Question} \downarrow}[/tex]

[tex] \displaystyle\large \bf( 2 \sqrt { 5 } + 3 \sqrt { 6 } ) ^ { 2 }[/tex]

[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]

[tex] \large \sf( 2 \sqrt { 5 } + 3 \sqrt { 6 } ) ^ { 2 }[/tex]

[tex] \large \sf \: 4\left(\sqrt{5}\right)^{2}+12\sqrt{5}\sqrt{6}+9\left(\sqrt{6}\right)^{2} [/tex]

[tex] \large \sf4\times 5+12\sqrt{5}\sqrt{6}+9\left(\sqrt{6}\right)^{2} [/tex]

[tex] \large \sf20+12\sqrt{5}\sqrt{6}+9\left(\sqrt{6}\right)^{2} [/tex]

[tex] \large \sf20+12\sqrt{30}+9\left(\sqrt{6}\right)^{2} [/tex]

[tex] \large \sf20+12\sqrt{30}+9\times 6 [/tex]

[tex] \large \sf20+12\sqrt{30}+54 [/tex]

[tex] \large \boxed{\bf12 \sqrt{30} + 74 = 139.72..}[/tex]

Answer:

D) no solution

Step-by-step explanation:

2x - 4y = 14

X + 2y = 7

2x - 4y + x + 2y = 14 + 7

2x - 4y + x + 2y = 21

3x - 2y = 21

no solution

Answer:

x=2y+7

step by step explanation:

2x-4y=14

2(x-2y)=14

x-2y=14/2

x-2y=7

x=2y+7

Answer:

18

Step-by-step explanation:

They want u to find MR, and I can do that by taking CR - CM

But first we need to know what is x

Now u know CM + MR =CR

Therefore

(3x - 2) + (x+8) = 46

3x - 2 + x + 8 = 46

4x + 6 = 46

4x = 40

x = 10

Now we know x is 10, let's just make it easier first

CM = 3x-2

= 3 (10) - 2

= 28

MR = x + 8

= 10 + 8

= 18

Now we got all our values

They want MR?

MR = x + 8

= 10 + 8

= 18

HERE U GO

Answer:

18

Step-by-step explanation:

cm=3x -2

mr=x +8

cr=46

cm+mr=cr

3x-2+x+8=46

4x+6=46

4x=46-6

x=40/4

x=10

hence, mr=x+8

=10+8

=18

Answer:

0

Step-by-step explanation:

The * means multiplication where the ^ means exponents, so you multiply in this case.

-6 * -6 = 36

Two negatives equals a positive.

PEMDAS shows that multiplication and division occurs first so...

7 * -6 = -42

36 + -42 + 8

-8 + 8

= 0

You can search it up to see what PEMDAS is.

Step-by-step explanation:

6m+7n+5m-3n

11m+7n-3n

11m+4n

Proof:

Let

We'll show that a contradiction happens if we tried to say A+B = C.

In other words, we'll show a contradiction happens for the form rational+irrational = rational.

Because A and C are rational, we can say

A = p/q

C = r/s

where p,q,r,s are integers. The q and s in the denominators cannot be zero.

So,

A+B = C

B = C - A

B = (r/s) - (p/q)

B = (qr/qs) - (ps/qs)

B = (qr-ps)/(qs)

B = (some integer)/(some other integer)

B = some rational number

But wait, we stated that B was irrational. The term "irrational" literally means "not rational". Irrational numbers cannot be written into fraction form of two integers. This is a contradiction and shows that A+B = C is never possible if A,C are rational while B is irrational.

This must lead to the conclusion that A+B must always be irrational if A is rational and B is irrational.

The template is this

rational + irrational = irrational

rational + rational = rational

Answer:

answer is 6

Step-by-step explanation:

m^2 - 4m + 2

-2(2) - 4(-2) + 2

-4 + 8 + 2

-4 + 10

6

Answer:

i dont know i just want points

Step-by-step explanation:

Answer:

no its not linear

Step-by-step explanation:

here is one example of a linear equation: y = 5x + 12

We have the graph of a function (say f(x)).

We have to determine which of the given statements are correct w.r.t this graph of f(x).

The domain of a function f(x) is the set of all values for which the function is defined, and the range of the function is the set of all values that f takes.

According to the question, we have the equation of this line as -

y = -5.

The value of y is constant for every value of x. Therefore, the range of the function is Set → {- 5}.

The function has same value → y= -5 for all values of x, ranging from →

- ∞ to + ∞, Therefore, its domain is the set of all Real numbers.

A function can have same value of y for different values of x.

Hence, Option B and D are correct.

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Answer: 28 per gallon

Answer:

u can do something like u have 8 pencils and 2 pens

Step-by-step explanation:

cause two divided by two is four and u only have to divide it once so that how u get that answer

Rewrite the root be,

[tex]\sqrt{39}=\sqrt{3\cdot13}=\sqrt{3}\sqrt{13}[/tex]

We know that [tex]\sqrt{3}\approx1.7,\sqrt{13}\approx3.6[/tex]

Write decimals as fractions and multiply them,

[tex]\frac{17}{10}\cdot\frac{36}{10}=\frac{612}{100}=6.12[/tex]

So it should be on somewhere around the next tick from 6.

Hope this helps :)

Answer:

6) F

7) B

Step-by-step explanation:

6)

[tex]\boxed{perimeter \: of \: rectangle = 2(length + breadth)}[/tex]

60= 2[½(n -6) +2n +5]

Expand:

60= 2(½)(n -6) +2(2n) +2(5)

60= n -6 +4n +10

Simplify:

60= 5n +4

Minus 4 on both sides:

5n= 60 -4

5n= 56

Divide both sides by 5:

n= 56 ÷5

n= 11.2

Thus, option F is correct.

7)

[tex]\boxed{area \: of \: rectangle = length \: \times breadth}[/tex]

13q +2= 9(q +6)

Expand:

13q +2= 9q +54

Bring q terms to one side, constant to the other:

13q -9q= 54 -2

Simplify:

4q= 52

Divide both sides by 4:

q= 52 ÷4

q= 13

Thus, option B is correct.

Answer:

what blanks

Step-by-step explanation: