Help 10 points please

Answer:

oh I thought you were talk about love well dang :(

Step-by-step explanation:

Step-by-step explanation:

For the 1st picture,

1 unit to the left and 3 units up.

Fir the 2nd picture,

We know the 90 degree counterclockwise rule is

[tex](x) \:(y) goes \: to \: ( - y)(x)[/tex]

So our new points will be

(-1,7)

(4,8)

(-2,2)

For the 3rd picture,

The new points will be

(-10,0)

(-6,2)

(-7,-1)

For the 4th picture,

A pentagon interior angles add up to 540.

We solve for x.

I cant really see the angles but just add up all the known angles and subtract them from 540 and that should get you your answer.

For 5th picture,

Exterior angles add up to 360 for every figure, a 13 sided polygon means it has 13 exterior angles. Since this is a regular polygon, the angles will all be equal.

[tex] \frac{360}{13} = 27 \frac{9}{13} [/tex]

Which equal

27.7

Answer:

Step-by-step explanation:

If a point (x, y) is reflected across y = -x, coordinates of the image point will be,

(x, y)→ (-y, -x)

Following this rule,

Vertices of the triangle will be,

(3, 1) → (-1, -3)

(3, -2) → (2, -3)

(6, -3) → (3, -6)

Therefore, image of the given triangle A will be,

(-1, -3), (2, -3) and (3, -6)

Answer:

Step-by-step explanation:

If a point (x, y) is translated by 4 units horizontally right and 1 unit upwards, coordinates of the image point will be,

(x, y) → (x + 4. y + 1)

Therefore, vertices of the image triangle ABC will be,

A(2, 2) → A'(2+4, 2+1)

           → A'(6, 3)

B(5, -1) → B'(5+4, -1+1)

           → B'(9, 0)

C(1, -2) → C'(1+4, -2+1)

           → C'(5, -1)

Then reflected across y-axis.

Rule for the reflection across y-axis will be,

(x, y) → (-x, y)

A'(6, 3) → A"(-6, 3)

B'(9, 0) → B"(-9, 0)

C'(5, -1) → C"(-5, -1)

Answer:

A"(-6, 3)

B"(-9, 0)

C"(-5, -1)

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

This is because the answer you picked means congruent to, however these two triangles are not the same size

Answer

Number of years 1               2            3

House 1 (value in dollars) 249,000 253,980 259,059.60

House 2 (value in dollars) 249,000 256,000 263,000

House 1: exponential function

House 2: linear function

House 1: f(x) = 249,000 * (1.02)^(x-1)

→ f(3) = 249,000 * (1.02)³⁻¹ = 249,000 * (1.02)² = 259,059.60

House 2: f(x) = 249,000 + 7,000(x-1)

→ f(3) = 249,000 + 7,000(3-1) = 249,000 + 7,000(2) = 249,000 + 14,000 = 263,000

House 1:

f(45) = 249,000 * (1.02)⁴⁵⁻¹ = 249,000 * (1.02)⁴⁴ = 249,000 * 2.39 = 595,110

House 2:

f(45) = 249,000 + 7,000(45-1) = 249,000 + 7,000(44) = 249,000 + 308,000 = 557,000

House 1 will have a greater value than House 2 after 45 years.

Step-by-step explanation:

Hope this helps, if not let me know and I will fix it.

Part A

The value for house 1 follows an exponential growth function since the value is increasing by 2% each year. This is because we multiply each value by 1.02 to get the next year's value.

In contrast, house 2's value increases by the same amount each year (7000 per year)

This fixed amount it increases directly leads to house 2 having linear growth.

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Part B

The equation for house 1's value is y = 249000(1.02)^x

This is in the form y = ab^x, where a = 249000 is the starting value and b = 1.02 is the growth rate factor.

We can think of 1.02 as 1+0.02 to represent the 2% growth.

In other words, 1.02 = 1+r solves to r = 0.02 = 2%

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The equation for the second home's value is y = 7000x+249000

The slope m = 7000 tells us how the value is going up per year.

The y intercept b = 249000 is the original home value (when x = 0).

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Part C

Let's plug x = 45 into each equation mentioned in part B

For home 1, we have

f(x) = 249000(1.02)^x

f(45) = 249000(1.02)^45

f(45) = 607,025.697

f(45) = 607,025.70

So that's the value of home 1 after 45 years of constant 2% growth per year

For the second home, we have,

f(x) = 7000x+249000

f(45) = 7000*45+249000

f(45) = 564,000

So there is a significant difference. This difference is 607,025.70 - 564,000 = 43,025.70 dollars.

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The coordinates that describe the point D are: Option C: (0, 4)

The graph shows that the vertical axis is labelled as the y-axis while the horizontal axis is labelled as the x -axis.

Normally, the coordinate system of writing the given points of the graph is (x, y)

Thus, the point D on the graph is seem to be 4 units on the positive y-axis and 0 units on the positive x-axis and as such, we can say that the coordinates of point D are:

D(0, 4)

Read more about Graph Coordinates at: https://brainly.com/question/11337174

Complete question is:

Which of the following describes point D?

(-4, 0)

(0, -4)

(0, 4)

(4, 0)

Answer: -5  < x < -2 or (-5, -2)

Step-by-step explanation:

Graph- (-5, -2)

Inequality- -5  < x < -2

Answer:

because when two negatives are together they can't add

Step-by-step explanation:

because when two negatives are together they can't add no matter if there's an addition sign

Answer:

f(g(x)) =

[tex] {x}^{6} + 6 {x}^{4} + 8x^{2} + 2[/tex]

Step-by-step explanation:

put g(x) instead of any x in f(x)

[tex] {(x ^{2} + 2) }^{3} - 4( {x}^{2} + 2) + 2[/tex]

Answer:

[tex]-\sqrt{2} \le m \le \sqrt{2}[/tex] would ensure that at least one real root exists for this equation when solving for [tex]x[/tex].

Step-by-step explanation:

Apply the Pythagorean identity [tex]1 - \sin^{2}(x) = \cos^{2}(x)[/tex] to replace the cosine this equation with sine:

[tex](1 - \sin^{2}(x)) - (m^2 - 3)\, \sin(x) + 2\, m^2 - 3 = 0[/tex].

Multiply both sides by [tex](-1)[/tex] to obtain:

[tex]-1 + \sin^{2}(x) + (m^2 - 3)\, \sin(x) - 2\, m^2 + 3 = 0[/tex].

[tex]\sin^{2}(x) + (m^2 - 3)\, \sin(x) - 2\, m^2 + 2 = 0[/tex].

If [tex]y = \sin(x)[/tex], then this equation would become a quadratic equation about [tex]y[/tex]:

[tex]y^{2} + (m^2 - 3)\, y + (- 2\, m^2 + 2) = 0[/tex].

However, [tex]-1 \le \sin(x) \le 1[/tex] for all real [tex]x[/tex].

Hence, the value of [tex]y[/tex] must be between [tex](-1)[/tex] and [tex]1[/tex] (inclusive) for the original equation to have a real root when solving for [tex]x[/tex].

Determinant of this quadratic equation about [tex]y[/tex]:

[tex]\begin{aligned} & b^{2} - 4\, a\, c \\ =\; & (m^{2} - 3)^{2} - 4 \cdot (-2\, m^{2} + 2) \\ =\; & m^{4} - 6\, m^{2} + 9 - (-8\, m^{2} + 8) \\ =\; & m^{4} - 6\, m^{2} + 9 + 8\, m^{2} - 8 \\ =\; & m^{4} + 2\, m^{2} + 1 \\ =\; &(m^2 + 1)^{2} \end{aligned}[/tex].

Hence, when solving for [tex]y[/tex], the roots of [tex]y^{2} + (m^2 - 3)\, y + (- 2\, m^2 + 2) = 0[/tex] in terms of [tex]m[/tex] would be:

[tex]\begin{aligned}y_1 &= \frac{-b + \sqrt{b^{2} - 4\, a\, c}}{2\, a} \\ &= \frac{-(m^{2} - 3) + \sqrt{(m^{2} + 1)^{2}}}{2} \\ &= \frac{-(m^{2} - 3) + (m^{2} + 1)}{2} = 2\end{aligned}[/tex].

[tex]\begin{aligned}y_2 &= \frac{-b - \sqrt{b^{2} - 4\, a\, c}}{2\, a} \\ &= \frac{-(m^{2} - 3) - \sqrt{(m^{2} + 1)^{2}}}{2} \\ &= \frac{-(m^{2} - 3) - (m^{2} + 1)}{2} \\ &= \frac{-2\, m^{2} + 2}{2} = -m^{2} + 1\end{aligned}[/tex].

Since [tex]y = \sin(x)[/tex], it is necessary that [tex]-1 \le y \le 1[/tex] for the original solution to have a real root when solved for [tex]x[/tex].

The first solution, [tex]y_1[/tex], does not meet the requirements. On the other hand, simplifying [tex]-1 \le y_2 \le 1[/tex], [tex]-1 \le -m^{2} + 1 \le 1[/tex] gives:

[tex]-2 \le -m^{2} \le 0[/tex].

[tex]0 \le m^{2} \le 2[/tex].

[tex]-\sqrt{2} \le m \le \sqrt{2}[/tex].

In other words,  solving [tex]y^{2} + (m^2 - 3)\, y + (- 2\, m^2 + 2) = 0[/tex] for [tex]y[/tex] would give a real root between [tex]-1 \le y \le 1[/tex] if and only if [tex]-\sqrt{2} \le m \le \sqrt{2}[/tex].

On the other hand, given that [tex]y = \sin(x)[/tex] for the [tex]x[/tex] in the original equation, solving that equation for [tex]x\![/tex] would give a real root if and only if [tex]-1 \le y \le 1[/tex].

Therefore, the original equation with [tex]x[/tex] as the unknown has a real root if and only if [tex]-\sqrt{2} \le m \le \sqrt{2}[/tex].

Given:

The gradient of the line passing through A(2,3), B(k,7) is [tex]\dfrac{2}{3}[/tex].

To find:

The value of k.

Solution:

The gradient or slope of a line is:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

The gradient of the line passing through A(2,3), B(k,7) is [tex]\dfrac{2}{3}[/tex]. So,

[tex]\dfrac{2}{3}=\dfrac{7-3}{k-2}[/tex]

[tex]\dfrac{2}{3}=\dfrac{4}{k-2}[/tex]

On cross multiplication, we get

[tex]2(k-2)=4(3)[/tex]

[tex]2k-4=12[/tex]

[tex]2k=12+4[/tex]

[tex]2k=16[/tex]

Divide both sides by 2.

[tex]k=\dfrac{16}{2}[/tex]

[tex]k=8[/tex]

Therefore, the value of k is 8.

Answer:

true

Step-by-step explanation:

idek

Answer:

True

Step-by-step explanation:

If we say x-1=0

x=1

F(1)=(1)^3-7(1)^2+15(1)-9

=1-7+15-9

=-6-9+15

=0

So this proves that it's a factor by factor theorem

A factor must give 0 if it's substituted to the equation

Answer:

x = 6

HI = 29

Step-by-step explanation:

✔️HI = ½(AB) => Triangle Mid-segment Theorem

HI = 5x - 1

AB = 58

Plug in the values and solve for x

5x - 1 = ½(58)

5x - 1 = 29

Add 1 to both sides

5x - 1 + 1 = 29 + 1

5x = 30

Divide both sides by 5

5x/5 = 30/5

x = 6

✔️HI = 5x - 1

Plug in the value of x

HI = 5(6) - 1

HI = 30 - 1

HI = 29

hope this helps you.

Answer:

Step-by-step explanation:

y = 2 - 4x

y = 2 - 4(-1)

y = 2 + 4

y = 6

hope this helps!

Answer:he's right

Step-by-step explanation:

Answer:

[tex]{ \tt{length = \sqrt{ {( - 2 - 5)}^{2} + {(3 - 7)}^{2} } }} \\ = \sqrt{65} \\ = 8.06 \: units[/tex]

what's the whole question??

Answer:

Scale model width = 12.5 yards

Step-by-step explanation:

Given:

Actual length of field = 120 yards

Actual width of field = 50 yards

Scale model length = 30 yards

FInd:

Scale model width

Computation:

Scale model width = [Scale model length / Actual length of field] Actual width of field

Scale model width = [30/120]50

Scale model width = [1/4]50

Scale model width = 0.25 x 50

Scale model width = 12.5 yards

(I) is true, since the plot shows f'(x) is negative on (0, 2)

(II) is false, since f'(x) is negative on (1, 2), so f(x) is decreasing over this interval

(III) is false. An inflection point can only occur at a point x if f''(x) is zero or doesn't exist. But at x = 0, the tangent line to f'(x) clearly has a negative, non-zero slope.

This makes A the correct choice.

Answer:

[tex]y = |x+2|+1[/tex]

Step-by-step explanation:

Answer:

Step-by-step explanation:

The area of a sector has the formula

[tex]A_s=\frac{\theta}{360}*\pi r^2[/tex] Hopefully, this looks somewhat familiar to you. Theta is the central angle given as 75, r is the radius given as 4. Filling in:

[tex]A_s=\frac{75}{360}*(3.14)(4)^2[/tex] and simplifying that a bit to look less threatening, but not by much:

[tex]A_s=\frac{5}{24}(3.14)(16)[/tex] and

[tex]A_s=\frac{251.2}{24}=\frac{157}{15}=10.466666666...[/tex] Not sure how you're supposed to express your answer so I gave both the fraction and its decimal equivalency.

Answer:

$843.67

Step-by-step explanation:

We can use a proportion to solve this problem:

12 : 100 = x : 896

x =(896 * 12)/100 = $107,52

896 - 107.52 = $788,48 (price of the computer after the discount)

7 : 100 = x : 788,48

x = (788,48 * 7)/100 = $55,1936

788.48 + 55,1936 = 843,6736 = $843.67 (final price)

Answer:

Hope it helps

Step-by-step explanation:

Hello,

All the numbers must begin with  6.

There are still 2,3,4,5 digits :  4 possibilities.

4!=4*3*2*1=24

The first is 62345 and the last 65432.

Answer:

Answer :

It's 3v - 9/2

Step-by-step explanation:

....

Answer:

a) 1.73

b)1.32

Step-by-step explanation:

y = f(x) = 3^x

f(1/2) = 3^1/2 = √(3) = 1.73

f(1/4) = 3^1/4 = 1/4√3 = 1.32

Answer: 7 hr

Step-by-step explanation:

Given

Distance between Emily and Kylie is [tex]140\ \text{miles}[/tex]

Speed of Emily [tex]v_e=12\ mph[/tex]

Speed of Kylie [tex]v_k=8\ mph[/tex]

Distance traveled by Emily [tex]\Rightarrow d_e=12t[/tex]

Distance traveled by Kylie [tex]\Rightarrow d_k=8t[/tex]

[tex]\Rightarrow 12t+8t=140\\\Rightarrow 20t=140\\\Rightarrow t=7\ hr[/tex]

They will meet after 7 hour.

Answer:

I'm sorry but no idea

Step-by-step explanation:

No idea