HELP
Write the products formed in the following acid-base reaction.

NaOH + HCl →

Then, describe the reaction using the terms strong acid, strong base, weak acid, weak base, salt, conjugate acid, conjugate base, and neutralization, as appropriate.
Answer in complete sentences.

The enthalpy (in kJ/mol) of the reaction, given that 0.026 moles of H₂O₂ at 25.0 °C is placed in a coffee cup calorimeter is 95.98 KJ/mol

First, we shall determine the heat energy of the reaction. Details below:

Q = MCΔT

Q = 30 × 4.18 × 19.9

Q = 2495.46 J

Finally, we shall determine the enthalpy of the reaction. Details below:

Q = n × ΔH

2.49546 = 0.026 × ΔH

Divide both sides by 0.026

ΔH = 2.49546 / 0.026

ΔH = 95.98 KJ/mol

Thus, the enthalpy of reaction is 95.98 KJ/mol

Learn more about enthalpy change:

https://brainly.com/question/24170335

#SPJ1

The correct rate law of the reaction from the experimental data is k[NO]^2 [O2]. Option D

The rate of reaction is usually expressed in terms of the amount of reactant consumed or product formed per unit time, and is typically measured in units of moles per liter per second (mol/L/s) or similar units.

We have that;

For NO;

3.4 * 10^-5/8.4 * 10^-6 = 2 * 10^-4/ 2 * 10^-4

4 = 2^n

n = 2

For O2;

8.4 * 10^-6/2.8 * 10^-6 = 3 * 10^-4/ 1 * 10^-4

3 = 3^n

n = 1

Thus the rate law of the reaction is;

Rate = k[NO]^2 [O2]

Learn more about rate of reaction:https://brainly.com/question/8592296

#SPJ1

Answer: An onion cell has a cell wall.

Explanation:

One of the main differences in cell structure between an onion cell and a human cheek cell is that an onion cell has a cell wall, while a human cheek cell does not. The cell wall of the onion cell provides it with additional support and protection, which is not required by animal cells, such as the human cheek cell.

The composition is three number of atoms in each sample.

The number of samples that was given include the following:

Water (H2O) : This sample is made up of three number of atoms but contains only two elements of oxygen and hydrogen in a ratio of 1:2 respectively.

Carbondioxide (CO2) : This sample is made up of three number of atoms but contains only two elements of carbon and oxygen in a ratio of 1:2.

Sugar (CHO) : This sample is made up of three number of atoms but contains three elements of carbon, oxygen and hydrogen in a ratio of 1:1:1.

Learn more about atoms here:

https://brainly.com/question/30459794

#SPJ1

The volume in which the weather ballon bursts is 640.21L.

The volume of a gas given the temperature and pressure can be calculated using the combined gas law as follows:

PaVa/Ta = PbVb/Tb

Where;

According to this question, a weather balloon is filled with 28.6 L helium at sea level where the pressure is 1.00 atm at 20.0 °C.

1 × 28.6/293 = 0.034 × Vb/223

0.0976109215 × 223 = 0.034Vb

Vb = 21.767 ÷ 0.034

Vb = 640.21L

Learn more about volume at: https://brainly.com/question/24189159

#SPJ1

Answer:

Problem 1:

The osmotic pressure, π, can be calculated using the formula:

π = iMRT

where i represents the van't Hoff factor (the number of particles into which a solute dissociates), M represents the molar concentration, R represents the gas constant (0.082 Latm/molK), and T is the temperature in Kelvin.

The osmotic pressure of pure water is 0. As a result, sea water's osmotic pressure must be equal to the pressure necessary to prevent osmosis.

Assuming that sea water is an ideal solution, the total dissolved ion concentration is 1.13 mol/L. Because each dissolved salt molecule dissociates into two ions, the effective particle concentration is 2.26 mol/L.

Filling in the blanks in the formula:

0.918 atm = (2)(2.26 mol/L)(0.082 Latm/molK)(298 K)

Therefore, a pressure of 0.918 atm must be applied to prevent osmotic flow of pure water into sea water.

Problem 2: Glucose has a molar mass of 180.16 g/mol. The solution contains the following number of moles of glucose:

n = 6.65 g / 180.16 g/mol = 0.0369 mol

The molarity of the solution is:

M = n / V = 0.0369 mol / 0.350 L = 0.105 M

Substituting the values into the formula:

π = iMRT = (1)(0.105 M)(0.082 L·atm/mol·K)(308 K) = 2.74 atm

As a result, the osmotic pressure of the solution is 2.74 atm.

Problem 3:

Following the same procedure as in Problem 2, the molarity of the solution is:

M = n / V = 0.02 mol / 0.450 L = 0.044 M

Substituting the values into the formula:

π = iMRT = (1)(0.044 M)(0.082 L·atm/mol·K)(308 K) = 1.14 atm

As a result, the osmotic pressure of the solution is 1.14 atm.

Problem 4:

The molar mass of propanol is 60.10 g/mol. The number of moles of propanol in the solution is:

n = 11.0 g / 60.10 g/mol = 0.183 mol

The molarity of the solution is:

M = n / V = 0.183 mol / 0.850 L = 0.215 M

Substituting the values into the formula:

π = iMRT = (1)(0.215 M)(0.082 L·atm/mol·K)(298 K) = 4.59 atm

Therefore, the osmotic pressure of the solution is 4.59 atm.

Problem 5:

Following the same procedure as in Problem 2, the molarity of the solution is:

M = n / V = 65 g / (180.16 g/mol × 35 L) = 0.104 M

Substituting the values into the formula:

π = iMRT = (1)(0.104 M)(0.082 L·atm/mol·K)(288 K) = 2.06 atm

Therefore, the osmotic pressure of the solution is 2.06 atm.

A Tutor is responsible for helping students to learn and understand the new concepts and complete assignments. They prepare lessons by studying lesson plans, reviewing textbooks in detail.

The role of a teacher is to teach a certain subject to the students according to the school syllabus whereas tutors respond to a child's individual needs by filling gaps. It is one who gives private instruction.

A Tutor for chemistry can be a person with good subject knowledge of chemistry. Generally the person who have taken MSC in chemistry or Mphil can be the apt tutor. They should got these degrees from a recognized university.

To know more about Tutor, visit;

https://brainly.com/question/13088995

#SPJ1

The process used 4.86 moles of hydrogen gas to generate 3.24 moles of ammonia gas.

According to the balanced chemical equation, the stoichiometry of the reaction shows that 3 moles of hydrogen gas (H₂) react with 1 mole of nitrogen gas (N₂) to produce 2 moles of ammonia gas (NH₃).

So, for every 2 moles of NH₃ produced, we need 3 moles of H₂ consumed. Therefore, to determine the moles of H₂ consumed, set up a proportion:

3 moles H₂ / 2 moles NH₃ = x moles H₂ / 3.24 moles NH₃

where x is the number of moles of H₂ consumed.

Solving for x:

x = (3 moles H₂ / 2 moles NH₃) x (3.24 moles NH₃) = 4.86 moles H₂

Therefore, 4.86 moles of hydrogen gas were consumed in the reaction to produce 3.24 moles of ammonia gas.

Find out more on hydrogen gas here: https://brainly.com/question/19813237

#SPJ1

There are several physical methods that can be used to monitor the rate of a chemical reaction are; Spectrophotometry, Conductometry, and Turbidity measurement

Spectrophotometry involves measuring the changes in the intensity of light absorbed or transmitted by a solution during a chemical reaction. Spectrophotometers are used to measure the amount of light absorbed or transmitted by a sample at different wavelengths.

Conductometry  involves measuring the changes in electrical conductivity of a solution during a chemical reaction. Conductivity meters are used to measure the electrical conductivity of a solution, which can change as the concentration of ions in the solution changes during a chemical reaction.

Turbidity measurement involves measuring the changes in the clarity or turbidity of a solution during a chemical reaction. Turbidimeters or nephelometers can be used to measure the amount of light scattered by a sample, which can change as particles form or dissolve during a reaction.

To know more about Spectrophotometry here

https://brainly.com/question/31440604

#SPJ1

--The given question is incomplete, the complete question is

"What are the physical methods of monitoring the rate of a chemical reaction?"--

The acid ionization steady of HCIO₂ (chlorous corrosive) can be spoken to by the taking after condition:

HCIO₂ + H₂O ⇌ H₃O⁺ + CIO₂⁻

The harmony steady expression for this response is:

Ka = [H₃O⁺][CIO₂⁻] / [HCIO₂]

The esteem of the acid ionization consistent (Ka) for HCIO₂ is roughly

1.1 x 10^-2 at 25°C.

It is critical to note that the esteem of Ka can change with temperature, and it is additionally subordinate on the dissolvable utilized.

Learn more about acid ionization constant

https://brainly.com/question/3075008

#SPJ1

0.01 mol/L is the molarity of given solution. 0.002 moles is added to 0.2 L solvent to make desired solution.

The amount of moles of solute found in a specific number of litres of the solution, or moles per litre of a solution, is known as molar concentration or molarity. Solutes are simply substances that can be found in solutions because a solution is defined as a homogenous mixture that comprises one or more solutes.

molar mass =342g /mol

number of moles=mass of solute / molar mass

0.45 /342 =0.002 moles

Volume solution =  50 mL / 1000 =0.2 L

M = n / V

M = 0.002 / 0.2

M = 0.01 mol/L

To know more about molarity, here:https://brainly.com/question/8732513

#SPJ1

Alkene is an unsaturated hydrocarbon which contain at least one carbon-carbon double bond. Here butene is an alkene with the chemical formula C₄H₈. The functional group present in alkenes is the double bond.

The structural isomers are those isomers in which the atoms are completely arranged in a different order but have the same molecular formulas. It is also called the constitutional isomers.

Geometric isomers are two or more compounds with the same number and types of atoms and bonds but have different geometries for the atoms.

To know more about Geometric isomers, visit;

https://brainly.com/question/28188244

#SPJ1

It would be easier to communicate information about mass to extraterrestrial civilizations.

Mass and weight are two different concepts that are often used interchangeably in everyday language.

Mass is a measure of the amount of matter in an object and is measured in kilograms (kg) or grams (g). Weight, on the other hand, is a measure of the force exerted on an object due to gravity and is measured in newtons (N).

If we were to communicate with an extraterrestrial civilization, it would be easier to communicate information about mass rather than weight because mass is an intrinsic property of an object that does not depend on gravity.

Therefore, mass would be more universal and easier to understand by extraterrestrial civilizations.

More on mass and weight can be found here: https://brainly.com/question/28122305

#SPJ1

The ranking of the elements by increasing ionization energy is; Cs < Sn < W < Xe.

Xenon (Xe) has the highest ionization energy among the given elements. It is a noble gas in Group 18 of the periodic table and has a full complement of valence electrons, making it very stable and difficult to remove an electron.

Tungsten (W) has higher ionization energy compared to tin. It is a transition metal in Group 6 of the periodic table and has even more valence electrons, which are held more tightly by the increased effective nuclear charge, resulting in higher ionization energy.

Tin (Sn) has higher ionization energy compared to cesium. It is a metal in Group 14 of the periodic table and has more valence electrons, which are closer to the nucleus, requiring more energy to remove.

Cesium (Cs) has the lowest ionization energy among the given elements. It is in the alkali metal group (Group 1) of the periodic table and has only one valence electron, which is relatively far from the nucleus, making it easier to remove.

To know more about ionization energy here

https://brainly.com/question/29203628

#SPJ1

To calculate the apparent bond energy of a carbon-sulfur bond in COS, we need to use the bond energies of the individual bonds that make up the molecule. The apparent bond energy of a carbon-sulfur bond in COS is approximately 1092 kJ/mol.

The apparent bond energy is the difference between the energy required to break the bonds in the reactants and the energy released when new bonds form in the products.

The enthalpy change of two (2) moles of COS is:

ΔH = –3.2 × 10⁻²⁴ × 2  × 6.02 × 10²³ = -3.85 kJ / mol

ΔH = ∑bond energy of reactants - ∑bond energy of products

2×C=O + 2 × C=S -[2 × C=O] + [2×C=S)

-3.85 = 2 × C=S -(2 × 552)

2 × C=S = 1104 - 3.85 = 1100.15

C=S =  1100.15 /2 = 550.08 kJ / mol

So apparent energy is 550.08 kJ / mol.

To know more about apparent energy, visit;

https://brainly.com/question/21670527

#SPJ1

10.0 g of ethanol would require more heat to raise the temperature by 10.0°C Because it has a higher boiling point.

The boiling point of a liquid is the temperature at which the vapour pressure of the liquid becomes equal to the atmospheric pressure of the liquid’s environment. At this temperature, the liquid is converted into a vapour.

The normal boiling point is high for liquids with strong intermolecular attractions and low for liquids with weak intermolecular attractions.

10.0 g of ethanol would require more heat to raise the temperature by 10.0°C because it has a higher boiling point.

Learn more about Boiling point, here:

https://brainly.com/question/2153588

#SPJ1

The balanced thermochemical equation for the reaction of pentane (C5H12) with oxygen gas (O2) to produce water (H2O) and carbon dioxide (CO2) is:

C5H12 (l) + 8 O2 (g) → 5 CO2 (g) + 6 H2O (l) ΔH = -3,510 kJ

The equation is balanced by making sure there are equal numbers of atoms of each element on both the reactant and product sides of the equation. The states of matter are included in the equation to show the physical state of each substance, with (l) indicating a liquid and (g) indicating a gas.

The negative value of enthalpy (ΔH) indicates that this reaction is exothermic, meaning that it releases heat to the surroundings. In other words, the products of the reaction have a lower enthalpy than the reactants. This can be explained by the fact that the bonds formed between carbon and oxygen in CO2 and between hydrogen and oxygen in H2O are stronger than the bonds broken between carbon and hydrogen in C5H12 and between oxygen atoms in O2. The excess energy is released in the form of heat, resulting in a negative value for ΔH.

There are 0.2107 moles of KBr are dissolved in 60.2 mL of a 3.50 M solution.

The molarity of a substance is defined as the number of moles of solute present in 1 litre of a solution.

According to the given data, the molarity of the solution tells us that there are 3.50 moles of KBr in 1000mL of solution. But we only have 60.2mL of solution, so with a mathematical rule of three we can calculate the amount of moles in 60.2mL:

1000 ml - 3.50 moles

60.2 ml -x = 60.2 ml× 3.50 moles/1000 ml

x= 60.2 ml -0.2107 moles

So, there are 0.2107 moles of KBr.

To know more about moles here

https://brainly.com/question/29293653

#SPJ1

The difference in lengths between the steel and copper bars at 41.0°C is 8.729 mm.

The difference in the lengths of the two bars can be calculated using the linear expansion equation;

ΔL = α × L × ΔT

where; ΔL = Difference in length

α = Coefficient of linear expansion

L = Initial length

ΔT = Change in temperature

Given; Initial length (L) = 1.500 m

Change in temperature (ΔT) = 41.0°C - (-12.0°C) = 53.0°C

The coefficient of linear expansion for steel is typically around 11 x 10⁻⁶ /°C, and for copper, it's around 16 x 10⁻⁶ /°C.

For the steel bar;

α (steel) = 11 x 10⁻⁶ /°C

For the copper bar;

α (copper) = 16 x 10⁻⁶ /°C

Now we can calculate the difference in lengths for both bars.

For the steel bar;

ΔL (steel) = α (steel) × L × ΔT

ΔL (steel) = 11 x 10⁻⁶ /°C × 1.500 m × 53.0°C

For the copper bar;

ΔL (copper) = α (copper) × L × ΔT

ΔL (copper) = 16 x 10⁻⁶ /°C × 1.500 m × 53.0°C

Converting the length difference from meters to millimeters (1 m = 1000 mm):

ΔL (steel) = 11 x 10⁻⁶ /°C × 1.500 m × 53.0°C × 1000 mm/m = 8.729 mm (rounded to three decimal places)

ΔL (copper) = 16 x 10⁻⁶ /°C × 1.500 m × 53.0°C × 1000 mm/m = 12.168 mm (rounded to three decimal places)

Therefore, the difference in the lengths of the two bars will be 8.729 mm.

To know more about copper bars here

https://brainly.com/question/21091191

#SPJ1

The ionization constant of propanoic acid is 0.7181

The ionization constant (Ka) of the monoprotic acid can be calculated using the equation:

Ka = ([H⁺][A⁻])/[HA]

where [H⁺] is the concentration of hydrogen ions, [A⁻] is the concentration of the conjugate base, and [HA] is the initial concentration of the acid.

We know that the acid is 0.815 percent ionized, which means that only 0.815 percent of the initial concentration of the acid has ionized into hydrogen ions and the conjugate base.

Therefore, the concentration of hydrogen ions and the conjugate base can be calculated using the following equations:

[H⁺] = 0.815 x 0.200 M = 0.163 M

[A⁻] = 0.815 x 0.200 M = 0.163 M

The initial concentration of the acid ([HA]) can be calculated by subtracting the concentration of hydrogen ions and the conjugate base from the initial concentration of the solution:

[HA] = 0.200 M - 0.163M= 0.037 M

Substituting these values into the equation for Ka, we get:

Ka = (0.163 M)² / 0.037M = 0.7181

Therefore, the ionization constant (Ka) of propanoic acid is 0.7181

To know more about ionization constant here :

brainly.com/question/28385102

#SPJ1

The heat change or enthalpy change, ΔH°rxn, for the slow reaction of zinc with water is +417.7 kJ/mol.

The heat change or enthalpy change, ΔH°rxn, for the reaction of zinc (Zn) with water (H₂O) can be calculated using the standard enthalpies of formation for each species involved in the reaction.

Balanced chemical equation for the reaction is;

Zn(s) + 2H₂O(l) → Zn²⁺(aq) + H₂(g)

The standard enthalpy change for the reaction, ΔH°rxn, can be calculated as the sum of the standard enthalpies of formation of the products minus the sum of the standard enthalpies of formation of the reactants, each multiplied by their respective stoichiometric coefficients;

ΔH°rxn = Σ(nΔH°f, products) - Σ(mΔH°f, reactants)

where n and m are the stoichiometric coefficients of the products and reactants, respectively, and ΔH°f is the standard enthalpy of formation.

Assuming standard conditions (25°C and 1 atm), the standard enthalpies of formation for Zn²⁺(aq) and H₂(g) are typically tabulated values. Let's assume their values to be ΔH°f(Zn²⁺(aq)) = -153.9 kJ/mol and ΔH°f(H₂(g)) = 0 kJ/mol, respectively.

The standard enthalpy of formation of water (H₂O) is -285.8 kJ/mol.

Put the values into the equation, we get;

ΔH°rxn = [ΔH°f(Zn²⁺(aq)) + ΔH°f(H₂(g)] - [ΔH°f(Zn(s)) + 2ΔH°f(H₂O(l))]

ΔH°rxn = [-153.9 + 0] - [0 + 2(-285.8)]

ΔH°rxn = -153.9 + 571.6

ΔH°rxn = 417.7 kJ/mol

To know more about heat change here

https://brainly.com/question/18912282

#SPJ1

The friend whose statement I agree with most about the cycling of carbon dioxide and oxygen in the ecosystem is Flynn.

I agree with Flynn's statement about the cycling of carbon dioxide and oxygen in the ecosystem.

Animals do indeed take in oxygen and release carbon dioxide during respiration, while plants take in carbon dioxide and release oxygen during photosynthesis. This process of exchanging gases between plants and animals is known as the carbon cycle, which is crucial for the survival of all living things.

The carbon cycle ensures that there is a balance between the amount of carbon dioxide in the atmosphere and the amount that is used up by living organisms. In addition, the cycling of other nutrients such as nitrogen and phosphorus is also important for the functioning of the ecosystem.

More on nutrient cycling in the ecosystem can be found here: https://brainly.com/question/16306728

#SPJ1

The electrolysis of water has the following balanced equation:

[tex]O_2(g) = 2H_2O(l) + 2H_2(g)[/tex]

According to the equation, it takes 2 moles of electrons to generate 1 mole O2.

The Faraday constant, F, which represents the charge carried by 1 mole of electrons, must be used to calculate the amount of charge needed to produce a specific amount of O2. The value of F is 96500 C/mol.

Using the Ideal Gas Law, we must first determine how many moles of O2 are formed from 1.50 L of O2 gas at 25.0 °C and 1.00 atm pressure:

PV = NRT

n = (PV)/(RT) = 1.00 atm/1.50 L/[(0.0821 lat/(molK)](298 K)]

= 0.0607 mol

Therefore, 0.0607 moles of O2 are formed.

We need 2 moles of electrons, or 2 x 0.0607, or 0.1214 moles, because 1 mole of oxygen requires 2 moles of electrons.

Finally, we can use the Faraday constant to determine the required charge:

Q = Nf = 0.1214 mol, 96500 C/mol, or 11700 C

Therefore, 11700 coulombs of charge are needed to produce 1.50 L of oxygen at 25.0 °C and 1.00 atm pressure.

Learn more about Faraday constant, here:

https://brainly.com/question/31604460

#SPJ1

At critical temperatures,  B. The substance changes its state if it continues gaining or losing thermal energy.

The critical temperature of a given substance or material refers to the temperature above which vapor cannot be liquefied, which is also known as the critical point of the material.

Therefore, with this data, we can see that the critical temperature of a given substance or material is a given temperature above the critical point of such material and it is related to its vapor state.

Learn more about the critical temperature here:

https://brainly.com/question/30217323

#SPJ1