HELP Heeeeeeelp!
Hey remember this for 100 points just reposting it please helpppppppp.

Explanation:

Physics is a discipline that its applications cut across all fields. Ranging from banking, cooking, transportation, lecturing, medicine, engineering etc. It is the bed rock of engineering because all aspect of engineering involves the application of Physics.

Some of the fields where Physics is applied are:

a) Lecturing: This field requires the continuous dissemination of Physics knowledge to students from one level to another level.

b) Medicine: The various applications of physics in medicine can not be over-emphasized. This is because medicine involves the use of ultrasound, ionizing and non-ionizing radiation, magnetic resonance etc.

c) Electrical Engineering: In this field, the basic knowledge of Physics is applied to circuits, boards and electrical components.

d) Civil Engineering: The knowledge of stress, strain, shear, force, torque, weight etc are used in a lot of deductions.

e) Broadcasting station: This field make use of a lot of Physics principles so as to increase awareness and pass information. Thus the frequency of a broadcasting station determines her area coverage.

f) Transportation: As all vehicles consists of electrical devices, then the knowledge of Physics can bot be avoided.

g) Communication: Ranging from GPS, GPRS, Data transmission, voice call, email etc requires the knowledge and application of Physics.

h) Archaeology: Though not a related to Physics, but it requires the application of it. Radio-dating and carbon-dating are required to determine the age of some ancestral objects or artifacts.

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She travelled in one third of time=160km

Total distance=160×3=480km

Time=6h

[tex]\\ \bull\tt\dashrightarrow Velocity=\dfrac{Displacement}{Time}[/tex]

[tex]\\ \bull\tt\dashrightarrow Velocity=\dfrac{480}{6}[/tex]

[tex]\\ \bull\tt\dashrightarrow Velocity=80km/h[/tex]

Answer: 160km

Explanation:

Answer:

I feel that people hurt the land and are destroying. I think they aren't using the land for the right reasons.

distance- 14 meters

displacement- 125 kilometers South

speed- 45 mph

velocity- 75 m/s upwards

acceleration due to gravity on the earth- 9.8 m/s^2

net force- 22 Newtons to the left

weight- 14 Newtons down

acceleration- 128 m/s^2 West

Velocity is the directional speed of a moving object as an indicator of its rate of change in location as perceived from a certain frame of reference and measured by a specific time standard.

Velocity is the directional speed of a moving object as an indicator of its rate of change in location as perceived from a certain frame of reference and measured by a specific time standard.

Velocity  →  75 m/s upwards

Velocity is the ratio of displacement and time, therefore, it has magnitude as well as direction.

Net force  →  22 Newtons to the left

Force is measured in Newton and can be in any direction

Acceleration due to gravity on Earth  →  9.8 m/s^2 or 9.81 m/s^2

It is the general value of Acceleration due to gravity on Earth.

Acceleration  →  128 m/s^2 West

Acceleration is measured in meters per second square.

Distance  →  14 meters

Distance is measured in meters, feet, cm, km, etc.

Speed  →  45 mph

Speed is the ratio of distance and time.

Displacement  →  125 kilometers South

Displacement has magnitude and direction both.

Weight  →  14 newtons down

Weight is also a force but it is in the downward direction.

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Answer:

14 m/s

Explanation:

a = v/t

subbing in:

2 = v/7

v = 14 m/s

Answer: The acceleration due to gravity increases the velocity of a falling object by 9.8 m/s per

second. Answer B is wrong because velocity increases. Answer C is wrong because the

distance increases every second. Ans. E is wrong because the derivative of distance with

respect to time gives the velocity, not the acceleration.

Explanation:

The absolute zero temperature is the smallest thermodynamic thermal limit, which is considered as a zero kelvin when the enthalpy, as well as the entropy of a cooled ideal gas, are of minimal value.

It is expressed by using the formula:

[tex]\mathbf{T_{abs} = T_N + k}[/tex]

where;

[tex]\mathbf{T_{abs } = absoulte \ temperature}[/tex]

[tex]\mathbf{T_N = temperature \ at \Neptune \ Scale}[/tex]

k = factor to convert temperature from absolute scale to Neptunian scale

N:B: An absolute temperature = zero (0) kelvin

From the information given, Using Ideal gas since it is used in Neptune:

PV = nRT

where;

From the question, provided that the gas is the same and no new mass is added;

Then, we can equate the moles of gas in the given conditions as;

[tex]\mathbf{\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}....\dfrac{P_nV_n}{T_n}}[/tex]

Using:

[tex]\mathbf{\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}}[/tex]

where the value of;

P₁V₁ = 28 dm³ atm

T₁ = 0⁰ N

P₂V₂ = 40dm³ atm

T₂ =  100⁰ N

∴

[tex]\mathbf{\dfrac{28}{(0+K)}=\dfrac{40}{(K+100)}}[/tex]

By cross multiply;

28(K+100) = 40(0+K)

28K + 2800  = 0 + 40K

40K - 28K = 2800

12 K = 2800

K = 2800/12

K = 233.33° N

Recall that:

[tex]\mathbf{T_{abs} = T_N + k}[/tex]

[tex]\mathbf{0= T_N+ 233.33 ^0 N}[/tex]

[tex]\mathbf{ T_N= - 233.33 ^0 N}[/tex]

Therefore, we can conclude that the value of the absolute zero of temperature on their temperature scale is -233.33° N

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The velocity of the object in free fall is 39.2 m/s.

Given the following data:

We know that acceleration due to gravity (a) for an object in free fall is equal to 9.8 meter per seconds square.

To find the final velocity (V) of the object, we would use the first equation of motion;

[tex]V = U + at\\\\V = 0 + 9.8(4)[/tex]

Final velocity, V = 39.2 m/s

Therefore, the velocity of the object in free fall is 39.2 m/s.

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Answer:

Remember 1 litre is equivalent to 1 cm³

[tex]density = \frac{mass}{volume} \\ \\ density = \frac{(2.08 \times 1000) \: g}{2 \: cm {}^{3} } \\ \\ { \boxed{ \boxed{density = 1040 \: g {cm}^{ - 3} }}}[/tex]

or: density is 1.04 kg/l

(amount of heat)Q = ? , (Mass) m= 4 g , ΔT = T f - T i = 180 c° - 20 °c = 160 °c ,

Ce = 0.093 cal/g. °c

Q = m C ΔT

Q = 4 g × 0.093 cal/g.c° × ( 180 °c- 20 °c )

Q= 4×0.093 × 160

Q = 59.52 cal

I hope I helped you^_^

No. A dog chasing its tail is just an animal running around in circles.

The dog's MOTION, however, IS accelerated motion, since the DIRECTION of its motion is constantly changing.

A a dog chasing its tail cannot be considered as acceleration.

Acceleration is the rate at which velocity changes over time, both in terms of speed and direction.

A point or object moving in a straight line is accelerated if it accelerates or decelerates. Even if the speed is constant, motion on a circle is accelerated because the direction is constantly changing.

For example, if a car accelerates as it turns a corner at constant speed, it is doing so because its direction is changing.

The faster you turn, the faster you accelerate. When velocity changes in magnitude (increase or decrease in speed), direction, or both, there is an acceleration.

Thus, as there is no change in either speed or direction in scenario in which a dog chases its tail, it is not considered as acceleration.

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Answer:

[tex] \boxed{d = 120\: meters} [/tex]

Explanation:

Given:

We can use this equation with the variables given to solve:

[tex] d \: = \frac{t \: (v + v_{0})}{2}[/tex] →

[tex] d \: = \frac{(10s) \: ((16.0 \: m/s) + (8.0 \: m/s))}{2} [/tex] →

[tex] d \: = \frac{(10s) \: (24 \: m/s)}{2} [/tex] →

[tex] d \: = \frac{(10 \: s \: • \: 24 \: m/s)}{2} [/tex] →

[tex] d \: = \frac{240 \: m}{2} [/tex] →

[tex] d \: = 120 \: m [/tex]

The distance traveled by the object in 10 seconds is 120 meters.

Given to us,

Final velocity of the object, [tex]v= 16\ meter/sec[/tex]

Initial velocity of the object, [tex]u= 8\ meter/sec[/tex]

Time for traveling, [tex]t= 10\ sec[/tex]

Using the first equation of motion,  we can find out acceleration of the object [tex]a[/tex],

[tex]v=u+at\\16=8+a\times 10\\a= 0.8\ meter/sec^2[/tex]

Now using the second equation of motion and putting the value of [tex]a[/tex],

The distance[tex](S)[/tex] traveled by the object ,

[tex]\begin{aligned}S&= ut+\frac{1}{2}at^2\\&= 8\times 10+ \frac{1}{2}\times 0.8\times 10^2\\&= 120\ meters \\\end{aligned}[/tex]

Hence,The distance traveled by the object in 10 seconds is 120 meters.

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Answer:

the shape of the glass change and the size of the glass also change

Explanation:

Answer:

The object will float better.

Explanation:

If you have basic knowledge on how it works, this question is relatively easy. Let's start by reviewing something. We already know that this object (let's assume it's a spaceship of sorts) is in orbit, meaning there is already a certain amount of gravity from Earth tugging on it. We also know that space has an effect on how this moves, so the two forces "balance" each other, allowing the object to stay at orbit rather than just drifting off. Now let's see the answers to see which makes more sense.

A. The object will stop moving.

The object can't stop moving. With gravity increasing, it would be impossible for that to happen.

B. The object will fly off into space.

This could only happen if the gravity were to decrease by a decent amount.

C. The object will smash into another object.

There is no other object mentioned in the question.

D. The object will float better.

This seems most likely as gravity would be pulling on the object a bit more, but probably not enough to bring it back to the ground. It might drop a bit lower into the exosphere.

I hope I was right and I hope this helps!

Answer:

0

Explanation:

acceleration = velocity÷time

20/5=4m/s square

substitute it v= u+at

u will get final answer as 0m/s

Answer:

You have no graph on the post.

[tex] \large \mathfrak{Solution : }[/tex]

Capicity of the septic tank is :

(i) capicity = 24 m³

(ii) capicity = 24 × 1000000 = 24000000 litres (cm³)

Answer:

True

Explanation:

It is true because scientists must use this method to get a correct and accurate solution.

Las dos líneas más largas del terreno de juego se denominarán líneas de banda. Las dos más cortas se llamarán líneas de meta. El terreno de juego será rectangular y la longitud de las líneas de banda deberá ser mayor que las de las líneas de meta. La longitud de la línea de banda debe tener como mínimo 90 metros y como máximo 120 metros. La anchura de la línea de meta debe de tener como mínimo 45 metros y como máximo de 90 metros. Todas las líneas del terreno de juego deberán se líneas continuas y tener la misma anchura, como máximo 12 cm., menos las líneas de meta que deben tener la misma anchura que los postes y larguero de la portería. Todas las líneas que delimitan al campo forma parte del terreno de juego. El terreno de juego puede ser de tierra, césped natural ó césped artificial de color verde según las normas del reglamento de la competición. El terreno de juego está dividido en dos partes iguales por una línea que unirá los puntos medios de las dos líneas de banda. El centro del campo estará marcado con un punto situado en la mitad de la línea media que divide las dos partes iguales del campo, tomando este punto como centro, haremos circulo de un radio de 9,15 metros. También se puede poner un banderín en cada extremo de la línea de media, a una distancia mínima de 1 m al exterior de la línea de banda.

Answer:

both of those numbers have 8 protons

Explanation:

Answer:

It take him 1 hour to travel 90 meters

Explanation:

Answer:

90 m

Explanation:

30 ÷ 20 = 1.5 m/min x 60 min = 90 m

Answer: A

Explanation: I looked it up on the internet

Answer:

the answer is A

Explanation:

protein helps build and repair tissues

Answer:

1.Energy is a quantity that is transferred from system to system. Energy is the ability of a system to do work. A system has done work if it has exerted a force on another system over some distance. When this happens, energy is transferred from one system to another.

2.physical quantity is a property of a material or system that can be quantified by measurement. A physical quantity can be expressed as a value, which is the algebraic multiplication of a numerical value and a unit. ... One is numerical magnitude and the other is the unit in which it is measured.

Answer:

The temperature is [tex]$80.6$[/tex] degrees Fahrenheit.

Explanation:

The weather is predicted to be 27 °C.

[tex]c=\frac{5}{9}(F-32)[/tex]

[tex]27=\frac{5}{9}(F-32)[/tex]

[tex]$5(F-32)=243$[/tex]

[tex]$F-32=\frac{243}{5}$[/tex]

[tex]$F-32+32=\frac{243}{5}+32$[/tex]

[tex]$F=\frac{403}{5}$[/tex]

[tex]F=80.6[/tex]

The temperature is [tex]$80.6$[/tex] degrees Fahrenheit.

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Answer:

Explanation:

Well mathematically it would look like this

E = k * I

k is the constant of proportionality.

As the voltage goes up, so does the current.

As the voltage goes down, so does the current.

In physics and engineering,, the formula is written somewhat differently.

E = I * R

The R is a device which limits the current. If R = 0 (like it is just a switch closing) then the first thing you will notice is that the lights go out and you better know where the circuit breakers are and have a flashlight to see which one you shorted out.

So R has a value > 0 in practice.

Answer:

Explanation:

B

A primary source is one that is written by the person who lived through an advenure or is one doing the action and recording it.

In this case, the answer is B.

Most frequently, for a historian, a primary source is something like a diary or a bunch of letter written by someone experiencing something.

It cannot be about someone else's work. Not C or D

A textbook is not the answer either. It is a bulky summary of scientific, or other kind of thought.