Help I will gib brain

Help I Will Gib Brain

Answers

Answer 1

Answer:

x-axis:  (18, 0)

y-axis:  (0, 12)

quadrant I:  (4.5, 10.6)

quadrant II:  (-15, 21)

quadrant III:  [tex](-\frac{3}{4}, -\frac{4}{9})[/tex]

quadrant IV:  (3, -7)

Step-by-step explanation: (view attached screenshot)

(18, 0) is 18 units left, 0 units up. This make the point line up exactly on the x-axis

(0, 12) is 0 units left, and 12 units up. This will cause it to be in the line of y-axis.

(4.5, 10.6) both x and y values in the point are positive, this means that it's in the first quadrant

(-15, 21) x value is negative, y value is positive. This means that the point is in the second quadrant

 [tex](-\frac{3}{4}, -\frac{4}{9})[/tex] both x and y values are negative. This means that the point is in the third quadrant.

(3, -7) x value is positive, y value is negative. This means that it's in the fourth quadrant.

Help I Will Gib Brain

Related Questions

10. Given: ABED, AD = EBProve: AABD AEDBLook at the proof. Name the postulate you would use to prove the two triangles are congruent.Given: AB ED, AD EBProve: AABD = AEDBAB EDGivenAD EBGivenBD BDReflexive Propertyof CongruenceAABD AEDB?BDE

Answers

In the problem, we are already given 2 pairs of sides that are congruent: AB and ED, and AD and BE.

Using the reflexive property of congruence, we also know that segment BD is congruent to itself.

We have therefore used three pairs of sides that are congruent to prove that △ABD ≅ △EDB.

This means that we used the SSS Postulate to prove the congruence of the two triangles.

Come onnnnSimplify fast help

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Answer:

i know that if i just answered the question quick then it would have been better for you but i also need help with something but i know something that will help you

Step-by-step explanation: go to cymath ans type it in it will help you and you can use it on school laptops so im kind of helping future you

help me please


thank you

Answers

Answer:

Domain: [-8, 2]

Range: [-4, 0]

Function: Yes

Step-by-step explanation:

The domain is the set of x-values and the range is the set of y-values.

A relation is a function if each x value corresponds to only one y-value.

The weight of 8 eggs is 496 grams. Identify the constant of proportionality of total weight to number of eggs.

Group of answer choices

60

56

62

58

Answers

The constant of proportionality of total weight to number of eggs having the weight of 8 eggs as  496 grams is 62.

How can the constant of proportionality of total weight to number of eggs be determined?

The  weight of 8 eggs is given as 496 grams

The equation can be written as :

w=n

where n= number of the eggs

we= weight of the eggs

then the equation can be written as

w∝n

Then we can introduce the proportionality constant sign as ;

then w=kn

where k is the proportionality constant

then we can substitute the given figures as ;

496=k *8

then k=496/8 = 62.

Therefore third option is correct.

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Hello, stuck on this practice problem. I also need to show all work.

Answers

Given the model for the height of a ball:

[tex]h(t)=-16t^2+5t+15[/tex]

To hit the ground, the height must be h(t) = 0. Then:

[tex]\begin{gathered} -16t^2+5t+15=0 \\ \Rightarrow16t^2-5t-15=0 \end{gathered}[/tex]

We use the general solution for a quadratic equation:

[tex]ax^2+bx+c=0\Rightarrow x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

From the problem, we identify:

[tex]\begin{gathered} a=16 \\ b=-5 \\ c=-15 \end{gathered}[/tex]

Using the formula:

[tex]\begin{gathered} t=\frac{5\pm\sqrt{25+4\cdot15\cdot16}}{2\cdot16}=\frac{5\pm\sqrt{985}}{32} \\ \\ \Rightarrow t_1=1.137 \\ \Rightarrow t_2=-0.825 \end{gathered}[/tex]

We only take the positive value (because the time is always positive!). Then, the answer is:

[tex]1.137\text{ seconds}[/tex]

Select the three equations that pass through the points (–4, –16) and (5, 2):

y + 4 = 2(x – 16)

y – 2 = 2(x – 5)

y = 2x – 8

y + 16 = 2(x + 4)

Answers

The equations of the line are:

y – 2 = 2(x – 5)

y + 16 = 2(x + 4)

y = 2x – 8

How to Find the Equation of a Line that Passes through two Points?

The equation of a line, in point-slope form, that passes through two points can be expressed as y - b = m(x - a).

To find the equation, first, we will need to find the slope of the line. Next, we will use a point and the slope to write the equation by simply substitute their values in y - b = m(x - a), where the slope is m and a point is (a, b).

Given the points:

(–4, –16) (5, 2)

Find the slope of the line (m):

Slope of the line (m) = change in y / change in x = (-16 - 2)/(-4 - 5)

Slope of the line (m) = -18/-9

Slope of the line (m) = 2

Substitute m = 2 and (a, b) = (5, 2) into y - b = m(x - a):

y - 2 = 2(x - 5)

Or, substitute m = 2 and (a, b) = (-4, -16) into y - b = m(x - a):

y + 16 = 2(x + 4)

Any of the above equations can be rewritten in slope-intercept form as:

y = 2x - 8.

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What is the product of the radical expression? (7- square root of 7) (-6+ square root of 7)

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The product of the given expression will be -49 + 13√7.

Product of two entities may be used to increase the amount of those entities. A radical expression may be defined as an expression which along with numbers and variables contain square root symbol. Instead of square root there can be cube root, fourth root or of root with any power. For example, 1 + √4, 1 + ∛4 etc. We have the expression (7 - √7) (-6 + √7). The product of this expression will be

Product = (7 - √7) (-6 + √7)

Product = -42 + 7√7 + 6√7 - 7

Product = -49 + 13√7 which is the required expression.

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Answer:

[tex]-49 + 13\sqrt{7}[/tex]

Step-by-step explanation:

[tex](7 - \sqrt{7} )(-6 + \sqrt{7})\[/tex] Distribute.

[tex]7 * -6 + 7 * \sqrt{7} - \sqrt{7} * -6 - \sqrt{7} * \sqrt{7}[/tex] Multiply. Keep in mind [tex]- \sqrt{7} * \sqrt{7} = (-\sqrt{7})^{2} = - 7[/tex].

[tex]-42 +13\sqrt{7} - 7[/tex] Combine like radicals/terms.

[tex]-49 +13\sqrt{7}[/tex]

Fill in the frequency distribution below

Answers

The frequency for the given distribution of the class interval 1.00 - 1.09 is 3, which are 1.07, 1.05 and 1.07.

What is frequency?

The frequency of a repeating event is its number of instances per unit of time. In some cases, it is also referred to as temporal frequency or ordinary frequency to emphasise differences with spatial and angular frequencies, respectively. One (event) per second is equal to one hertz (Hz), which is how frequency is expressed.

The period is the reciprocal of the frequency because it is the length of time for one cycle in a repeating event. For instance, the period, T—the space between beats—of a heart beating at a frequency of 120 beats per minute (2 hertz), is equal to 0.5 seconds (60 seconds divided by 120 beats).

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arc TQ =arc QR =arc TS =arc SQR =arc RQTBackNext

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[tex]\begin{gathered} For\text{ arc TQ} \\ UQ=RS=25\~ \\ TU=44\~ \\ \text{arc TQ=25+44} \\ \text{arc TQ=69\degree} \\ The\text{ value of arc TQ is 69\degree} \\ For\text{ arc QR} \\ \text{QR=QS-RS} \\ \text{QR=180-25} \\ \text{QR=155} \\ The\text{ value of arc QR is 155\degree} \\ For\text{ arc TS} \\ \text{TS=SQ-TQ-RS} \\ \text{TS=180-69-2}5 \\ \text{TS=86} \\ The\text{ value of arc TS is 86\degree} \\ For\text{ arc SQR} \\ \text{SQR=360-RS} \\ \text{SQR=360-25} \\ \text{SQR=335} \\ The\text{ value of arc SQR is 335\degree} \\ For\text{ }arc\text{ RQT} \\ RQT=360-TS \\ RQT=360-86 \\ RQT=274 \\ The\text{ value of arc RQT is 274\degree} \end{gathered}[/tex]

Sheila is making a model of a stadium using a scale where 3 centimeters equal 20 feet. If the model is 30.5 centimeters wide, what is the actual width of the stadium, in feet?

Answers

Answer:

answer is in the explanation

Step-by-step explanation:

first w have to get from 3cm to 30.5cm

to do that we can multiply by 10 1/6

3*10=30

1*3=3

30 3/6

the scale factor, like I said is 10 1/6.

20*10 1/6=20*10+20*1/6=200+20/6=203 2/6, or 203 1/3, or 203.3333333, or 610/3

Consider the expression. (-3)^-3 divided by 1/-6^2Which Three choices are equivalent to the expression givenA. 4/3B. 1/-(6)^2(-3)^3C. 36/-27D. -6^2/-27E. -36/(-3)^3

Answers

Solution

For this case we have the following:

[tex]3^{-3}=\frac{1}{3^3}=\frac{1}{27}[/tex][tex](\frac{1}{-6})^2=\frac{1}{36}[/tex]

When we apply the division we got:

[tex]\frac{\frac{1}{27}}{\frac{1}{36}}=\frac{36}{27}=\frac{4}{3}[/tex]

Option A is correct

Option D is correct

Option E is correct

Final answer: A, D, E

Answer the question in the picture below please someone help me

Answers

Answer:

here is the Answer The population will be 799,500 people

Step-by-step explanation:

Does the geometric sequence converge or diverge? Explain.
320,-40, 5, -0.625,...
O The sequence diverges because r = -8, which is less than one.
O The sequence diverges because |r | = 8, which is greater than one.
The sequence converges because || = 0.125, which is less than one.
O The sequence converges because r = 0.125, which is less than one.

Answers

The sequence converges because |r| = 0.125, which is less than one. The correct answer would be option (C).

What is geometric series?

The geometric series defined as a series represents the sum of the terms in a finite or infinite geometric sequence. The successive terms in this series share a common ratio.

The nth term of a geometric progression is expressed as

Tₙ = arⁿ⁻¹

Where a is the first term, r is the common ratio

We have been given that geometric sequence as:

320, -40, 5, -0.625,...

To determine whether the geometric sequence converges or diverges

We have to find the common ratio of the given sequence.

|r | = | -40/320 |

|r | = 0.125 < 1

Since the common ratio of the sequence is less than 1,

Therefore, the given sequence converges.

Hence, the correct answer would be an option (C).

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The laboratory technician can combine L of the pure acid solution with L of the 10% acid solution to get the desired concentration.A laboratory technician needs to make a 33-liter batch of a 40% acid solution. How can the laboratory technician combine a batch of an acid solution that is pure acid wi is 10% to get the desired concentration?

Answers

The laboratory technician has to combine 11 L  acid solution to get the desired concentration .

What is concentration in a solution?

The volume of solute that has been dissolved in a specific volume of solvent or solution is known as the concentration of a solution. A solution with a significant concentration of dissolved solute is one that is concentrated. When there is just a minimal amount of dissolved solute in a solution, it is said to be diluted. The amount of a solute, or dissolvable substance, combined with the solvent, or other substance, determines the concentration of a solution in chemistry. C = m/V, where m is the mass of the solute dissolved and V is the total volume of the solution, is the accepted formula. Among the quantitative units of concentration are molarity, molality, mass percentage, parts per thousand, parts per million, and parts per billion.

The33 L batch is 40% acid, so 33 x 0.4 = 13.2 L of pure acid in the batch.

Let P = the number of liters of pure acid required, D = the number of liters of the 10 % solution.

Then P + 0.10 x D = 13.2.  

Also, P + D = 33

This equation can be solved simultaneously by substitution.

P = 33 - D

33 - D + 0.10 x D = 16.8

-D (1 - 0.10) = 13.2 - 33

-D =  -19.2/ 0.9

D = -22

P = 33 - 22

= 11 L

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2. Invasive weed species can grow quickly. One variety grows up to 1.65 ft per day. How fast in inches per minute can this weed grow? Show your work using the correct conversion factors and make sure all conversion factors are labeled with appropriate units. You should have more than one conversion factor shown.

Show you work please :)

Answers

Answer:

0.825 inches per hour

Step-by-step explanation:

Invasive weed species can grow quickly. One variety grows up to 1.65 ft per day. How fast in inches per minute can this weed grow?

FACTS:

the weed grows up to 1.65 feet per day

there are 12 inches in 1 foot

there are 24 hours in 1 day

First, lets figure how many inches the weed can grow in one day:

= daily growth in feet per day * inches in 1 foot

= 1.65 feet * 12 inches

= 19.8 inches a day

If the weed can grown 19.8 inches a day, and there are 24 hours in a day:

= growth in inches per day/24 hours in 1 day

=19.8/24

= 0.825 inches per hour

Natalie walked 1.4 miles in one hour. How far did she walk in kilometers?

Answers

The distance covered by Natalie in kilometers will be 2.24 kilometers.

What is a unit conversion?

Multiplication or division by a numerical factor, selection of the correct number of significant figures, and unit conversion are all steps in a multi-step procedure.

Given that Natalie walked 1.4 miles in one hour. The distance covered by Natalie in kilometers will be calculated as:-

The value of 1 mile is equal to 1.4 kilometers.

1 miles = 1.6 kilometers

1.4 miles = 1.4 x 1.6 kilometers

1.4 miles = 2.24 kilometers

Therefore, the distance covered by Natalie in kilometers will be 2.24 kilometers.

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Evaluate: open parentheses 3 y minus 2 close parentheses plus open parentheses fraction numerator 2 x y over denominator 3 end fraction space minus 30 space close parentheses space w i t h space x equals 10 comma space y equals 6 ANS.____________________ __________.

Answers

In order to evalute this expression, replace the variable placeholders with the numerical values, that is,

[tex](3(6)-2)+(\frac{2(10)(6)}{3}-30)[/tex]

which gives

[tex]\begin{gathered} (18-2)+(\frac{120}{3}-30) \\ (16)+(40-30) \\ 16+10 \\ 26 \end{gathered}[/tex]

then, the answer is 26.

a. 2а + 4(7 + 5а) (simplify)

Answers

Answer

22a + 28

Explanation

The question asks us to simplify the given expression

2a + 4(7 + 5a)

The first step is to open the bracket

2a + 4(7 + 5a)

= 2a + 28 + 20a

= 2a + 20a + 28

= 22a + 28

Hope this Helps!!!

[tex] - 10 - (5 - 9) {}^{2} [/tex]How would you solve this problem?

Answers

You have the following expression:

-10 - (5 - 9)²

In order to simplify the previous expression you proceed as follow:

- 10 - (5 - 9)² simplify terms inside parenthesis

= -10 - (-4)² solve the parenthesis

= -10 - 16 simplify

= -26

Hence, the simplified expression is -26.

Triangles G H L and K H J are connected at point H. Angles Angles L G H and H K J are congruent. Sides G H and H K are congruent. Which congruency theorem can be used to prove that △GHL ≅ △KHJ?

Answers

[tex]ASA[/tex]

1) Considering that in these triangles, there is one pair of vertical angles

∠GHL and ∠JHK and two congruent angles ∠JKH and ∠HGL,

2) We can tell that these triangles fall within the following congruence case:

[tex]ASA[/tex]

Select that two values of x that are roots of thi equation

Answers

ANSWER:

B.

[tex]x=\frac{5+\sqrt{17}}{4}[/tex]

C.

[tex]x=\frac{5-\sqrt{17}}{4}[/tex]

EXPLANATION:

Given:

[tex]2x^2+1=5x[/tex]

To find:

The two values of x that are roots of the equation

Let's subtract 5x from both sides of the equation;

[tex]\begin{gathered} 2x^2+1-5x=5x-5x \\ 2x^2-5x+1=0 \end{gathered}[/tex]

Recall that a quadratic equation is generally given in the below form;

[tex]ax^2+bx+c=0[/tex]

Comparing both equations, we can see that;

[tex]\begin{gathered} a=2 \\ b=-5 \\ c=1 \end{gathered}[/tex]

Let's go ahead and use the below quadratic formula to solve for the values of x;

[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex][tex]\begin{gathered} x=\frac{-(-5)\pm\sqrt{(-5)^2-4*2*1}}{2*2} \\ \\ x=\frac{5\pm\sqrt{25-8}}{4} \\ \\ x=\frac{5\pm\sqrt{17}}{4} \\ \\ x=\frac{5+\sqrt{17}}{4},\frac{5-\sqrt{17}}{4} \end{gathered}[/tex]

Determine the slope and the y-intercept of the line.
12 = 3 y
Slope: 0; y-intercept: (0,4)
Slope: 0; y-intercept: (4, 0)
Slope: undefined; y-intercept: (4,0)
Slope: 1; y-intercept: (0,4)

Answers

Answer:

Slope = 0, y int = (0,4)

If there is no x variable, slope is 0. y = 4 so no matter what x is (which it will always be 0) the y intercept will always be 4

A carpenter spend his 40-hour workweek as follows: 1/4 of his ordering materials; 1/2 of his time doing the wooodwork; and 1/8 of his time talking to customers. The rest of his time devoted to cleanup. What is the approximately percentage of time the carpenter spend doing cleanup?

Answers

Explanation

The forty hours of the workweek of the carpenter are distributed as follows:

Then, the time that the carpenter spends cleaning up is (what remains from the 40 hours after subtracting the time he spends in the other activities):

[tex]40h-10h-20h-5h=5h\text{.}[/tex]

The question now is, what percentage does 5h represent in 40h? We need to use the percentage formula:

[tex]\begin{gathered} 5=\frac{\%}{100}\cdot40.\leftarrow\begin{cases}\%=\text{ Percentage that 5 represents in 40}\end{cases} \\ \\ \end{gathered}[/tex]

Solving this equation, we get

[tex]\begin{gathered} 5=\frac{\%}{100}\cdot40, \\ \\ 5=\frac{\%\cdot40}{100}, \\ \\ 100\cdot5=\%\cdot40, \\ \\ 500=\%\cdot40, \\ \\ \frac{500}{40}=\%, \\ \\ \%=\frac{500}{40}, \\ \\ \%=12.5. \end{gathered}[/tex]Answer

The percentage of time that the carpenter spends cleaning up is 12.5%.

Simplify.(5+squartrt3)225 + sqrtrt1010 + 28sqrtrt328 + 10sqrtrt3

Answers

The given expression is,

[tex](5+\sqrt[]{3})^2[/tex]

We have the algebraic expansion,

[tex](a+b)^2=a+2ab+b^2[/tex]

Therefore we have,

[tex]\begin{gathered} (5+\sqrt[]{3})^2=5^2+(2\times\sqrt[]{3}\times5)+(\sqrt[]{3})^2 \\ \text{ =25+10}\sqrt[]{3}+3=28+10\sqrt[]{3} \end{gathered}[/tex]

Thus, the correct option is 28 + 10sqrt3.

The x-intercept of 2x – y = 6 is -6.

True

False

Answers

Answer:

False

Step-by-step explanation:

The [tex]x[/tex] intercept is when [tex]y=0[/tex].

Substituting [tex]y=0[/tex], we get [tex]2x=6[/tex], meaning that [tex]x=3[/tex].

So, the [tex]x[/tex] intercept is 3, not -6.

How do i get the proportionality on this❓❓

Answers

Answer is k = 4

Step by step

Finding the constant of proportionality is the same as finding rate of change, or slope.

Here we have the given point of (1, 4)
y /x = 4 /1 or 4

We can see another possible point on the graph, (2, 8)
y /x = 8 /2 or 4

Which polynomials are prime? Check all of the boxes that apply.
x² +9
0²-9
Ox²+3x+9
O-2x² +8

Answers

x² +3x+9 and x² + 9 are prime polynomials.

Define prime numbers.

A whole number higher than 1 whose only elements are 1 and itself is referred to as a prime number. A whole number that may be split evenly into another number is referred to as a factor. 2, 3, 5, 7, 11, 13, 17, 19, 23 and 29 are the first few prime numbers. Composite numbers are those that have more than two components. A prime number is one that can only be divided without leaving a residue by itself and one.

Given Data

x² +9

x² + 9 cannot be divided into factors of rational numbers. It is a prime polynomial as a result.

x²+3x+9

It is impossible to factorize x² + 3x + 9 using rational values. It is a prime polynomial as a result.

x²-9

Factoring x² - 9 results in (x - 3)(x + 3). It is not a prime polynomial, therefore.

-2x² +8

The factorization of -2x² + 8 results in -2(x - 2)(x + 2). It is not a prime polynomial, therefore.

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NEED HELP NOW!!!!!!!!Find the number that should be added to the expression to create a perfect square trinomial. x^2-8x-161664-64

Answers

From a perfect square trinomial

[tex]a^2+2ab+b^2[/tex]

We know that:

[tex]2ab=2\cdot\sqrt[]{a^2}\cdot\sqrt[]{b^2}[/tex]

Now, let's use this for the trinomial given:

[tex]x^2-8x+b^2[/tex]

We know that:

[tex]-8x=2\cdot x\cdot b^2[/tex]

Solving for b,

[tex]\begin{gathered} -8x=2xb \\ \rightarrow b=-\frac{8x}{2x}\Rightarrow b=-4 \end{gathered}[/tex]

This way, the complete perfect square trinomial is:

[tex]x^2-8x-16[/tex]

Ans: Option A

Evaluate the expression 2x + 5 for x = 10

Answers

Answer:

[tex]2x + 5 \\ (2 \times 10) + 5 \\ 20 + 5 \\ = 25[/tex]

A moving company charges a one-time and a cost per mile for its service. The relationship between the mileage and the cost is displaying in the graph. Which equation best represents the relationship between the total cost, C, and miles traveled, m?*

Answers

This is a linear relation. For linear relations, we have the general form:

[tex]y=ax+b[/tex]

Where 'a' is the slope and 'b' is the intercept.

In this problem, we have that the intercept b is 200, because that's the point where the line crosses the y-axis. For now we have something like:

[tex]C=am+200[/tex]

(here y is C and x is m)

To find the slope we have to use the intercept point (0, 200) and another point on the line. We can see that one of those points is (200, 500).

For a line with points (x1, y1) and (x2, y2), the slope is find like:

[tex]a=\frac{y_2-y_1}{x_2-x_1}[/tex]

In this problem, the slope is:

[tex]a=\frac{500-200}{200-0}=\frac{300}{200}=\frac{3}{2}=1.5[/tex]

Then, we have the equation that represents the relationship between the mileage and the cost:

[tex]C=1.5m+200[/tex]

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