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Gold has a greater mass than silver,

5cm³ of gold has a mass of 5 × 19.3g/cm³ = 96.5g,

While 5cm³ of silver has a mass of 5 × 10.5g/cm³ = 52.5g.

To compare the masses of 5 cubic centimeters (cm³) of silver and gold, we need to multiply their densities by the volume.

For silver:

[tex]mass = density * volume[/tex]

= mass

=[tex]10.5 g/cm^3 * 5 cm^3[/tex]

= 52.5 g

For gold:

[tex]mass = density * volume[/tex]

= mass

= [tex]19.3 g/cm^3 * 5 cm^3[/tex]

= 96.5 g

Hence, 5 cm³ of gold has a greater mass than 5 cm³ of silver, 96.5 g > 52.5 g.

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The speed of the ball as it swings through this point is   a) 23.8 m/s

    b) 0

The most crucial scientific notion is measurement. A variety of measurable quantities are quantified using base or physical fundamental units.. One such quantifiable metric is speed, which calculates the ratio between the distance an item travels and the time needed to cover that distance. Let's explore speed in-depth in this session. Given that it just has a direction and no magnitude, speed is a scalar quantity.

a) The ball deviates from a straight line course due to the strain in the rope, which counteracts the effects of gravity. Last year's acceleration is

 a =[tex]\frac{ T -mg}{m}[/tex] = 2g = [tex]\frac{v^2}{r}[/tex]. . . . m is mass

 v = [tex]\sqrt(2gr)[/tex]= [tex]\sqrt{(2\times9.8 \times29 )} = \sqrt{(568.4 m^2/s^2)}[/tex]

 v ≈ 23.8 m/s a rough estimate of the ball's speed at the low point

b) The acceleration needed to cause the ball to veer from its horizontal course is determined using the same procedure.

 a =   a =[tex]\frac{ T -mg}{m}[/tex] = [tex]\frac{ mg -mg}{m}[/tex]= 0

and the velocity is  v = [tex]\sqrt{(ar)[/tex] = 0 . . . . . speed of the ball where the rope is vertical

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The α helix and β pleated sheet are examples of the secondary structure of protein. Hence, the correct option is (c).

The secondary structure of a protein refers to the local spatial arrangement of its amino acid residues, which are the building blocks of proteins. The α helix and β pleated sheet are two common types of secondary structure in proteins. The α helix is a right-handed helical structure that is stabilized by hydrogen bonds between the carbonyl group of one amino acid residue and the amide group of another, four residues down the polypeptide chain. The α helix structure resembles a spiral staircase, with the amino acid residues forming the steps and the hydrogen bonds forming the railings. The β pleated sheet, on the other hand, is a sheet-like structure that is stabilized by hydrogen bonds between neighboring amino acid residues in different parts of the polypeptide chain. The β pleated sheet is formed when the polypeptide chain folds back on itself, creating a sheet-like structure with the hydrogen bonds forming the edges of the sheet. The secondary structure of a protein is important because it helps to determine the overall shape of the protein, which in turn determines its function. The α helix and β pleated sheet are important secondary structures in many proteins, including enzymes, antibodies, and structural proteins.

In summary, the α helix and β pleated sheet are examples of the secondary structure of proteins, which refers to the local spatial arrangement of amino acid residues in a protein. The α helix is a right-handed helical structure, while the β pleated sheet is a sheet-like structure. The secondary structure of a protein is important for determining its overall shape and function.

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Electric charge is not possible on an oil droplet

How do charged oil drops form?

When radiation (such as X-rays) ionizes the area between the metal plates, electrons from the air attach to the falling oil droplets and give them a negative charge.

They could only gain or lose electrons, which are the only charged particles. The "elementary charge" of an electron is 1.60 • 10-19 C, and it is present on every electron. Therefore, any oil droplet's charge needs to be a multiple of this quantity. Due to their typically low conductivity, lubricants can act as insulators in transformers and switches. Oils can conduct electrical current, though. Their conductivity is influenced by a number of variables, including as the base oil, additives, and polarity.

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The painter can stand no closer than 9.19 times the length of the board from the end of the board without tipping it over.

The weight of the painter acts downward at a distance of x/2 from the center of the board, and the weight of the board itself acts downward at a distance of L/2 from the center of the board.

The torque due to the weight of the painter is given by:

Tpainter = (mg)(x/2)

The torque due to the weight of the board is given by:

Tboard = (Mg)(L/2)

For the board to be in rotational equilibrium, these two torques must balance each other, so we have:

Tpainter = Tboard

Substituting the expressions for the torques and solving for x, we get:

(mg)(x/2) = (Mg)(L/2)

x = (ML)/m

Substituting the given values, we get:

x = (25 kg) (L)/ (68 kg)

x = 9.19 L

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The cross-sectional area in 10⁻⁶ m of a cylindrical rod has a length of 36 cm and a diameter of 2.4 mm is 4.5216 x 10⁻⁶ m².

Cross Sectional Area of a Cylinder = π x R2 where π is a constant (3.14159265), which is the rate of the circumference to periphery of a circle, while R is the compass of the cylinder. So all you need to know, to be suitable to calculate the cross sectional area, is its compass. The forecourt of the compass, multiplied by π, shall give you the value of the cross sectional area. The unit of cross sectional area will depend on the length unit used for compass dimension. Since π is dimensionless, the unit for area could be meter2, cm2 or indeed ft2.

We're given a spherical rod whose cross-sectional area will be in the form of circle.

To calculate the area of circle, we use the equation:

Area = [tex]\pi r^2[/tex]

where,

r = radius of rod

r = 2.4 /2 = 1.2 x 10⁻³ m

 (Conversion factor: 1 m = 1000 mm)

Putting values in above equation, we get:

Area = [tex]\pi r^2[/tex]

= 3.14 x (1.2 x 10⁻³)²

= 4.5216 x 10⁻⁶ m²

Therefore, the cross sectional area of cylinder rod is 4.5216 x 10⁻⁶ m².

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It will take 5.0 s for the insulator to charge to 40 C with a current of 2 A.

The charge of an object is equal to the current times the time, i.e.

[tex]Q = I*t[/tex]

The equation can be written as [tex]Q = I*t[/tex],where Q, I, and t represent the charge (in Coulombs), current (in Amperes), and time (in seconds) .

Therefore, to calculate the time it will take to charge the insulator from 20 C to 40 C with a current of 2 A, you can use the equation:

[tex]t =\frac{ (40 - 20)}{2 }\\ \\ = \frac{10}{2} \\\\t = 5 s[/tex]

Therefore, it will take 5.0 s for the insulator to charge to 40 C with a current of 2 A.

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Using similar triangles, we can set up the following proportion:

height of tree / length of tree's shadow = height of flagpole / length of flagpole's shadow

Plugging in the values we know:

6 / 4 = x / 50

Solving for x:

x = 75

Therefore, the flag pole is 75 meters long.

To find the height of the flag pole, we can use similar triangles. The tree and its shadow form one triangle, while the flag pole and its shadow form another. Since the two triangles are similar, we can set up a proportion: the height of the tree over the length of its shadow is equal to the height of the flag pole over the length of its shadow. We can then cross-multiply and solve for the height of the flag pole. Specifically, we can write 6/4 = h/50, where h is the height of the flag pole, and solve for h. This gives us h = 75 meters, so the height of the flag pole is 75 meters.

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The period of motion when the mass-spring system is displaced from equilibrium by 15.0 cm is 6.0 seconds.

The period of a mass-spring system is given by:

[tex]T = 2pisqrt(m/k)[/tex]

where m is the mass and k is the spring constant.

The period of motion is not affected by the amplitude (displacement from equilibrium) of the oscillation for small amplitudes. However, for large amplitudes, the period does depend on the amplitude.

To find the period when the system is displaced from equilibrium by 15.0 cm, we need to find the new value of k, which depends on the displacement.

When the system is displaced by 5.0 cm, we have:

[tex]5.0 cm = A = x_max[/tex]

where A is the amplitude and [tex]x_max[/tex] is the maximum displacement from equilibrium.

When the system is displaced by 15.0 cm, we have:

[tex]15.0 cm = A = x_max[/tex]

The new spring constant k' can be found by:

[tex]k' = m*(2*pi/T')^2[/tex]

where T' is the period of motion when the system is displaced by 15.0 cm.

The energy of the system is conserved, so the potential energy at the maximum displacement is equal to the kinetic energy at the equilibrium position.

At the maximum displacement, all of the potential energy is converted into kinetic energy, so:

[tex]1/2 k' A^2 = 1/2 k x_max^2[/tex]

Solving for k' and substituting into the expression for the period, we get:

[tex]T' = 2pisqrt(m/k') = 2pisqrt(m/(k*(A/x_max)^2))[/tex]

Substituting the given values, we get:

[tex]T' = 2pisqrt(m/k*(15.0 cm/5.0 cm)^2) = 6.0 s[/tex]

Therefore, the period of motion when the mass-spring system is displaced from equilibrium by 15.0 cm is 6.0 seconds.

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The wavelength of the sound wave in the room is approximately 3.118 meters, given the frequency and assumed speed of sound.

The speed of sound in a gas relies upon the properties of the gas, and specifically on its temperature, pressure, and sub-atomic weight. Since the issue doesn't give data on these properties, we will accept that the speed of sound in helium is equivalent to in air at room temperature and tension, which is roughly 343 meters each second.

To find the frequency of the sound wave in the room, we can utilize the recipe:

frequency = speed of sound/recurrence

Connecting the qualities we know, we get:

frequency = 343 m/s/110 Hz = 3.118 m

At long last, we can utilize the recipe frequency = speed of sound/recurrence to track down the frequency of the sound wave in the room. The frequency is the distance between two sequential focuses on the wave that are in stage with one another, i.e., that have a similar plentifulness and bearing of movement. For this situation, the frequency ends up being around 3.118 meters.

Subsequently, the frequency of the sound wave in the room is roughly 3.118 meters.

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The expression for dividing distance by speed using floating point arithmetic is float(distance) / (speed).

Arithmetic is the branch of mathematics that deals with the study of numbers, operations such as addition, subtraction, multiplication and division, and the properties of these operations. It is a fundamental component of mathematics, and it is essential for solving problems in everyday life. Arithmetic is used to calculate the cost of goods, to figure out measurements, to estimate taxes, and to perform many other calculations. Arithmetic is an important part of higher-level mathematics, such as calculus, and is often used to solve complex problems.

This expression produces a fractional result by using the float() function, which calculates a floating point value from the given argument (in this case, the integer value of distance). To apply this expression to different variables, simply replace distance and speed with the other variables (e.g. float(children) / (families)).

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Ball A has been in motion for 2.77 seconds when the two balls collide.

For ball A, use the second law of motion equation to find its displacement after 4 seconds,

[tex]y_A = (30)4 + \dfrac{1}{2}(-g)(4)^2[/tex]

yA = 41.6 m

Find the time it takes for ball B to reach the same height,

41.6 m = (30 m/s)t + (1/2)(-g)t^2

Solving this quadratic equation for t,

[tex]t = \dfrac{30 \pm \sqrt{(30)^2\times - 4\times (-4.9)(-41.6)}} {2(-4.9)}[/tex]

t ≈ 3.33 s or t ≈ 6.77 s

Therefore, the time elapsed for ball A when the two balls collide is,

tA = t - 4 s

tA = 3.33 s - 4 s

tA = -0.67 s (disregarded, since it is negative)

or

tA = 6.77 s - 4 s

tA = 2.77 s

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The tension in the cord is T1 = m_2g and the radial force acting on the disk is F_radical = m_2g.

A), The speed of the disk is v=[tex]\sqrt{m_2Rg/m1}[/tex] , if mass block decreases tension & F_radial increase so radius decrease. If the mass of the block increases Tension & F_radial radius increase.

B). F_radical = T1

F_radical = m_2g

C). F_ Centripetal = m_1v²/ R

m_2g = m_1v²/ R

D). if the mass of the block decreases tension and F radical increase so radius decreases.  if the mass of the block decreases tension and F radical  increase

In physics, tension refers to the force that is transmitted through a string, rope, cable, or wire when it is pulled or stretched. The magnitude of the tension in a material is equal to the pulling force or stretching force that is being applied to it. Tension is a vector quantity, which means that it has both magnitude and direction.

The direction of tension is always along the length of the string or cable, away from the point where it is being applied. Tension plays an important role in various physical systems, including bridges, cranes, pulleys, and elevators. Engineers and designers must consider the tension in these structures to ensure their safety and functionality.

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Complete Question: -

A small disk of mass my is tied to a cord and allowed to move in a circle of radius R on a frictionless horizontal table. The cord passes through a small hole in the center of the table and a block of mass m, is suspended on the other end. The block remains stationary meanwhile the disk ok the table moves in a circle. a. What is the tension in the cord? b. What is the radial force acting on the disk? C. What is the speed of the disk? Describe what would happen to the disk if the mass of the hanging block is decreased (by removing part of the load), and what would happen to the disk if the mass of the hanging block is increased. ma

Answer:

[tex]F = \boxed{3.53002 \times 10^{22} \;N}[/tex]

Explanation:

The formula used to calculate the gravitational force between two objects
[tex]F = G \dfrac{m_1m_2}{r^2}[/tex]

where

m₁ and m₂ are the masses of the two objects

G  is the universal gravitational constant =6.6743 × 10⁻¹¹ m³/kg·s²

r is the average distance between the two objects

We are given
mass of earth = m₁  = 5.98 X 10²⁴ kg

mass of sun = m₂ = 1.99 x 10³⁰ kg

r = 1.5 x 10¹¹ m

Therefore

[tex]F\:=\:6.6743\:\times \:10^{-11}\times \dfrac{\left(5.98\:\times 10^{24}\times 1.99\:\times 10^{30}\right)}{\left(1.5\:\times \:10^{11}\right)^2}[/tex]

[tex]F = \boxed{3.53002 \times 10^{22} \;N}[/tex]

The term that best completes the given sentence is "competitive inhibition."

define competitive inhibition ?

Competitive inhibition is a type of enzyme inhibition where a molecule, called a competitive inhibitor, binds to the active site of an enzyme and blocks the binding of the substrate, preventing or reducing the enzyme's activity. The competitive inhibitor has a similar shape to the substrate, and thus competes with the substrate for binding to the active site. This type of inhibition can be reversed by adding more substrate, which outcompetes the inhibitor for binding to the active site.

Competitive inhibition is often used in drug design, as molecules that act as competitive inhibitors can be used to selectively target specific enzymes and prevent their activity.

The term that best completes the given sentence is "competitive inhibition."

Competitive inhibition refers to a situation in which one company or individual attempts to gain an advantage over another by developing or promoting a similar product or idea that reduces the demand for the other's product or idea. In this case, Nela believes that Logan's electric yacht idea is directly competing with Dunamis Motors, and is therefore a form of competitive inhibition.

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The force of friction of the ball is 870.8N.

Friction is the force that resists motion when the surface of one object comes in contact with the surface of another.

Frictional force is the force generated by two surfaces that contact and slide against each other.

Frictional force can be calculated by multiplying the normal force by coefficient of friction as follows:

f = F × µ

Where;

f = 58.4kg × 9.81m/s² × 1.52

f = 870.8N

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If you lose control of your vehicle and collide with a fixed object, such as a tree, at 60 m.p.h., the force of impact is the same as driving your vehicle off a cliff and falling 127 feet.

When a vehicle collides with a fixed object at high speed, the kinetic energy of the vehicle is transferred into other forms of energy such as deformation of the car, sound, heat, and kinetic energy of the object struck. This transfer of energy can cause a significant amount of damage to the vehicle and the passengers.

According to the National Highway Traffic Safety Administration (NHTSA), a 60 mph collision with a fixed object is equivalent to a fall from a height of 127 feet. This is because the force of impact is the same as that produced by a free fall from a height of 127 feet, which is about 39 meters. This emphasizes the importance of safe driving practices and adhering to traffic regulations to prevent such accidents from occurring.

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The complete question is-

If you lose control of your vehicle and collide with a fixed object, such as a tree, at 60 m.p.h., the force of impact is the same as driving your vehicle off a: _________.

(a) 1543.42 m far has the bicyclist traveled during the entire trip. (b) 1160.13 m/h is the average speed of the bicyclist for the trip.

a. To find the distance traveled by the bicyclist during the entire trip, we need to find the distance traveled in each part and add them up.

The distance traveled during the first part can be calculated using the formula:-

[tex]distance = speed * time[/tex]

= distance
= [tex]8.16 m/s * 27.5 minutes * (1 minute / 60 seconds)[/tex]

= 559.52 m

The distance traveled during the second part can be calculated using the formula:-

[tex]distance = speed * time[/tex]

= distance

= [tex]4.66 m/s * 38.7 minutes * (1 minute / 60 seconds)[/tex]

= 366.06 m

The distance traveled during the third part can be calculated using the formula:-

[tex]distance = speed * time[/tex]

= distance

= [tex]14.3 m/s * 13.6 minutes * (1 minute / 60 seconds)[/tex]

= 617.84 m

Adding up all the distances traveled in each part gives us the total distance traveled by the bicyclist during the entire trip:

=> total distance

= [tex]559.52 m + 366.06 m + 617.84 m[/tex]

= 1543.42 m

(b) To find the average speed of the bicyclist for the trip, we need to find the total time taken for the trip and the total distance traveled.

The total time taken for the trip can be found by adding up the time taken in each part:-

=> total time

= [tex]27.5 minutes + 38.7 minutes + 13.6 minutes[/tex]

= 79.8 minutes

=> total time

= [tex]79.8 minutes * (1 minute / 60 seconds)[/tex]

= 1.33 hours

The average speed of the bicyclist for the trip can be calculated using the formula:-

[tex]average speed = total distance / total time[/tex]

= average speed

= [tex]1543.42 m / 1.33 hours[/tex]

= 1160.13 m/h

The average speed of the bicyclist for the trip is 1160.13 m/h.

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Answer:

297.38 meters

Explanation:

The height of the hill can be calculated using the principle of conservation of energy. This principle states that the total energy of a system is conserved, and that the change in potential energy of an object is equal to the work done on it.


The height of the hill can be calculated using the formula:

h = (1/2) m v^2 / g

where m is the mass of the child and sled, v is the final speed of the sled, and g is the acceleration due to gravity (9.8 m/s^2).

Plugging in the values, we get:

h = (1/2) * 50.0 kg * (9.0 m/s)^2 / 9.8 m/s^2

h = (1/2) * 50.0 kg * 81.0 m^2/s^2 / 9.8 m/s^2

h = 40.5 kg * 81.0 m^2/s^2 / 9.8 m/s^2

h = 2911.76 kg m^2/s^2 / 9.8 m/s^2

h = 297.38 m

So the height of the hill is 297.38 meters.

Replacing PVC rod with semiconductor material, its behavior would depend on specific properties. To inject energy we can apply a voltage.

If we replaced the PVC rod with a semiconductor material, the behavior of the rod would depend on the specific properties of the semiconductor. Semiconductors have a unique property called the bandgap, which is the energy difference between the highest occupied energy level (valence band) and the lowest unoccupied energy level (conduction band). When an external energy source, such as heat or light, is applied to a semiconductor, it can promote electrons from the valence band to the conduction band, creating a flow of free electrons that can conduct electricity.

To inject energy into the bound charges in the semiconductor and force it to act more like a conductor, we could use several mechanisms. One common approach is to apply a voltage across the semiconductor, which creates an electric field that can promote electron movement. Another approach is to expose the semiconductor to light, which can excite electrons to higher energy levels and promote conduction. Additionally, thermal energy can cause the semiconductor to act more like a conductor by promoting electron movement. These mechanisms can be used to tailor the conductivity of semiconductors, which is the foundation of many modern technologies such as transistors, solar cells, and light-emitting diodes (LEDs).

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The statements "the potential at the center of the sphere is zero", "the potential at the surface of the sphere is the same as the potential at infinity", and "the potential is lowest at the center of the sphere" are all true.

The correct statements about the potential due to this conducting sphere are:The potential at the center of the sphere is zero, The potential at the surface of the sphere is the same as the potential at infinity,The potential is lowest at the center of the sphere.

When a charged particle moves in an electric field, the field exerts a force that can do work on the particle. The work can be expressed in terms of electric potential energy. Electric potential energy depends only on the position of the charged particle in the electric field.

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During the brief time interval when the elevator is descending with free-fall acceleration, the scale would show your weight to be zero.

Free-fall acceleration is the acceleration that an object experiences due to the force of gravity, assuming no other forces are acting on the object. In the absence of air resistance or any other resistance, all objects near the surface of the Earth, regardless of their mass or composition, will experience the same constant free-fall acceleration due to gravity, which is denoted by the symbol "g" and has a value of approximately 9.8 meters per second squared (m/s²) or 32.2 feet per second squared (ft/s²).

This means that if an object is dropped from rest near the surface of the Earth, it will fall with a constant acceleration of g, and will increase its velocity by 9.8 m/s or 32.2 ft/s every second. Similarly, if an object is thrown upwards, it will experience a deceleration of g due to gravity until it comes to rest at the highest point of its trajectory, after which it will begin to fall downwards with free-fall acceleration.

If the elevator is in free-fall acceleration, it means that the only force acting on you is the force due to gravity, and there is no normal force acting on you from the scale. In this case, according to Newton's second law of motion, your weight is equal to the force due to gravity acting on your mass.

So, during the brief time interval when the elevator is descending with free-fall acceleration, the scale would show your weight to be zero. This is because your body is in a state of weightlessness, as you and the scale are accelerating downwards at the same rate.

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Answer:

The formula for calculating the length change due to a temperature change is:

ΔL = α * L * ΔT

where α is the linear expansivity, L is the original length of the bar, and ΔT is the change in temperature.

So in this case, the length change of each bar would be:

ΔL = 1.0 x 10^-5 K^-1 * 3m * (40°C - 28°C)

Converting the temperatures to Kelvin (28°C = 28 + 273 = 301 K and 40°C = 40 + 273 = 313 K), we get:

ΔL = 1.0 x 10^-5 K^-1 * 3m * (313 K - 301 K)

ΔL = 1.0 x 10^-5 * 3 * 12

ΔL = 0.00036 m

So each bar will increase in length by approximately 0.00036 meters when the temperature changes from 28°C to 40°C. To allow for this increase in length, a safety gap of 0.00036 meters should be left between each bar.

The focal length of a converging lens is a measure of the distance between the lens and the point at which parallel light rays converge to form an image. The focal point is what we refer to as this.

At this point, the light rays are focused to a single point, resulting in the formation of an image. When an object is placed at a distance greater than the focal length, the light rays diverge, resulting in the formation of a virtual image. This virtual representation is taller and larger than the actual thing. Additionally, the virtual image is located behind the lens, making it an inverted image. The focal length of a converging lens is an important factor to consider when forming an image. The object must be placed at a distance greater than the focal length in order to form a virtual image. If the object is placed closer than the focal length, the light rays will not converge to form an image, but instead will diverge from the focal point.

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Every tube in the load must have a companion right across in the rotor holder in order for the centrifuge to be balanced.

In many laboratories, centrifuges are employed to separate fluids, gases, or liquids according to their densities. Centrifuges are often employed in clinical and research facilities for the purification of cells, organelles, viruses, proteins, and nucleic acids.

The separation of different components of whole blood using a centrifuge is an example of its usage in a clinical environment. Serum or plasma is required for several tests and can be obtained by centrifugation.

A full blood sample is allowed to clot at room temperature in order to get serum. The clot is subsequently removed from the sample by centrifugation, leaving a serum supernatant behind.

Plasma, in contrast to serum, is made from whole blood that has not been allowed to clot; it contains serum as well as clotting factors. A full blood sample is taken in tubes that have been anticoagulant-treated in order to get plasma.

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The statement is consistent with the Stefan- Boltzmann law

Stefan-Boltzmann law is a physical law that states that the total amount of radiation emitted by a blackbody per unit time and per unit surface area is proportional to the fourth power of its absolute temperature. Mathematically, the law can be expressed as:

E = σT^4

where E is the total radiant emittance, σ is the Stefan-Boltzmann constant (5.67 x 10^-8 W/m^2K^4), and T is the absolute temperature in Kelvin. The law is important in understanding the behavior of thermal radiation and plays a crucial role in many areas of science and engineering.

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The speed of the cart at a height of 0.17 m above the bottom of the incline would be 3.90 m/s.

Let's call the speed of the cart at a height of 0.17 m above the bottom of the incline "v". We can calculate v using the following equation:

v^2 = 2 * g * (h1 - h2)

where

g = 9.8 m/s^2 (acceleration due to gravity)

h1 = 0.94 m (initial height)

h2 = 0.17 m (final height)

Plugging in the values, we get:

v^2 = 2 * 9.8 * (0.94 - 0.17)

v^2 = 2 * 9.8 * 0.77

v^2 = 15.156

v = sqrt(15.156)

v = 3.90 m/s

So the speed of the cart at a height of 0.17 m above the bottom of the incline would be approximately 3.90 m/s.

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Answer:

Because of symmetry the gravitational field of the earth acts as though all of the mass of  the earth were centered at the center of the earth - so g = G M / R^2      and     W = m g        weight of an individual

If the mass (M) had 1/2 of its value the weight would also be halved.