Help me, I don’t understand

Answer:

Homozygous dominant

Explanation:

Answer:

yes

Explanation:gergrgregbfbwerbebw

Answer:

H2SO4

Explanation:

In 100 g of the compound we hgave

2.00 g H, 32.7 g S and 65.3 g O.

2g* 1 mol/g = 2.0 mol H

32.7 g S * 1 mol/32.1 g = 1.02 mol S

65.3 g 0 * 1 mol/16 g = 4.08 mol O

2.0 mol H : 1.02 mol S : 4.08 mol O = 2 mol H : 1 mol S : 4 mol O

H2SO4

Answer:

H2SO4

Explanation:

Answer:

no, not all objects emit electromagnet waves.

Explanation: because lets say the object is carpet it has no magnetic waves in it so not all objects do.

Answer:

Chemical properties can be tested without changing the substance

Explanation:

Answer:

I actually have no idea

Explanation:

Sorry my man

Answer:

Explanation:

generator

The balanced equation based on half-reactions is 2Cu + 8HNO3 + 6H+ -> 2Cu(NO3)2 + 2NO + 4H2O.

To complete the balanced equation for the given reaction Cu + HNO3 -> Cu(NO3)2 + NO + H2O using half-reactions, we need to break down the overall reaction into separate oxidation and reduction half-reactions.

1. Oxidation Half-Reaction:

Cu -> Cu2+ + 2e-

In this step, copper (Cu) is oxidized, losing two electrons to form copper(II) ions (Cu2+).

2. Reduction Half-Reaction:

HNO3 + 3H+ + 2e- -> NO + 2H2O

In this step, nitric acid (HNO3) is reduced, gaining two electrons to form nitric oxide (NO) and water (H2O).

Now, to balance the half-reactions, we need to make sure that the number of electrons gained in the reduction half-reaction is equal to the number of electrons lost in the oxidation half-reaction. In this case, we can achieve this by multiplying the oxidation half-reaction by two.

Balanced Half-Reactions:

Oxidation: 2Cu -> 2Cu2+ + 4e-

Reduction: HNO3 + 3H+ + 2e- -> NO + 2H2O

Finally, we can combine the balanced half-reactions to obtain the balanced equation for the overall reaction:

2Cu + 8HNO3 + 6H+ -> 2Cu(NO3)2 + 2NO + 4H2O

Therefore, the balanced equation based on half-reactions is 2Cu + 8HNO3 + 6H+ -> 2Cu(NO3)2 + 2NO + 4H2O.

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Answer:

sulfur dichloride

Explanation:

SCl2 is the chemical formula for sulfur dichloride. This compound is made of only two elements, so it is a binary compound.

Answer:

It reads as follows: 0.5 moles of solute per liter of solution.

Explanation:

Molarity is the most frequent way of expressing the concentration of solutions in chemistry, and it indicates the number of moles of solute dissolved per liter of solution; is represented by the letter M.

Answer:the parts of the body which is nearest to  the ground ie thier back will show discoloration

Explanation:

If the body remains at a position for long hours, the parts of the body which is nearest to  the ground can develop a skin discoloration as a result of pooling of blood in the tissues and this is called livor mortis, which tends to be permanent from 8Hours upwards.

Answer:

[tex]\large \boxed{\text{D.) 91 kPa}}[/tex]

Explanation:

We can use the Ideal Gas Law — pV = nRT

Data:

V = 15.0 L

n = 0.55 mol

T = 300 K

Calculation:

[tex]\begin{array}{rcl}pV & =& nRT\\p \times \text{15.0 L} & = & \text{0.55 mol} \times \text{8.31 kPa$\cdot$ L$\cdot$K$^{-1}$mol$^{-1}\times$ 300 K}\\15.0p & = & \text{1370 kPa}\\p & = & \textbf{91 kPa}\end{array}\\\text{The pressure in the container is $\large \boxed{\textbf{91 kPa}}$}[/tex]

Answer:

2, strong acid

Explanation:

Data obtained from the question. This includes:

[H+] = 0.01 M

pH =?

pH of a solution can be obtained by using the following formula:

pH = –Log [H+]

pH = –Log 0.01

pH = 2

The pH of a solution ranging between 0 and 6 is declared to be an acid solution. The smaller the pH value, the stronger the acid.

Since the pH of the above solution is 2, it means the solution is a strong acid.

Answer:

The options that apply to the description of grid-lines of the map are;

They are measured in degrees

They set up a reference system

They divide Earth into four equal parts

FIRST OPTION , SECOND OPTION and FIFTH OPTION are correct.

Explanation:

FIRST OPTION gave the describtion that the grid-lines of the map are measure in degrees,this option is applied to the gridlines on a map because the grid are lined as a result of angular measurement which makes it to makes the unit to be measured degrees and angles.

SECOND OPTION described it as been set up by a reference system which let us know that the area that are plotted were all grid as a result of the size

FIFTH OPTION also applied to the

description of the gridlines on a map because the Earth is divided into 4 equal parts through the Prime Meridian i.e the latitudinal line and longitudinal line .

.

Answer:

They are measured in degrees.

They set up a reference system.

They divide Earth into four equal parts.

Explanation:

i took the test

Answer:

9.7 atm.

Explanation:

The following data were obtained from the question:

Initial pressure (P1) = 1 atm

Initial volume (V1) = 0.725 L

Final volume (V2) = 0.075 L

Final pressure (P2) =?

The final pressure can be obtained by using the Boyle's law equation since the temperature is constant. This is illustrated below:

P1V1 = P2V2

1 x 0.725 = P2 x 0.075

Divide both side by 0.075

P2 = 0.725 / 0.075

P2 = 9.7 atm.

Therefore, the new pressure is 9.7 atm.

Answer:

63/16

Explanation:

tanE=  

adjacent

opposite

​  

=  

16

63

​

Answer:

63/16

Explanation:

this for delta math?

Answer:

A. 1.25M

B. 19.98g

Explanation:

A. Data obtained from the question include the following:

Mass of KMnO4 = 31.6 g

Volume = 160 mL

Molarity =..?

We'll begin by calculating the number of mole KMnO4 in the solution. This is can be obtained as follow:

Mass of KMnO4 = 31.6 g

Molar mass of KMnO4 = 39 + 55 + (16x4) = 158g/mol

Number of mole of KMnO4 =..?

Mole = mass /Molar mass

Number of mole of KMnO4 = 31.6/158 = 0.2 mole

Now, we can obtain the molarity of the solution as follow:

Volume = 160 mL = 160/1000 = 0.16L

Mole of KMnO4 = 0.2 mole

Molarity = mole /Volume

Molarity = 0.2/0.16 = 1.25M

B. Data obtained from the question include the following:

Volume = 300mL

Molarity = 0.74 M

Mass of H2C2O4 =..?

First, we shall determine the number of mole H2C2O4. This is illustrated below:

Volume = 300mL = 300/1000 = 0.3L

Molarity = 0.74 M

Mole of H2C2O4 =?

Mole = Molarity x Volume

Mole of H2C2O4 = 0.74 x 0.3

Mole of H2C2O4 = 0.222 mole

Now, we can easily find the mass of H2C2O4 by converting 0.222 mole to grams as shown below:

Number of mole of H2C2O4 = 0.222 mole

Molar mass of H2C2O4 = (2x1) + (12x2) + (16x4) = 2 + 24 + 64 = 90g/mol

Mass of H2C2O4 =..?

Mass = mole x molar mass

Mass of H2C2O4 = 0.222 x 90

Mass of H2C2O4 = 19.98g

Answer:

7.56 x 10^13 J/mol

Explanation:

Binding energy = (Mass defect) × (velocity of light)² = (84 × 10^-5) × (3 × 10^8)^2 = 756 × 10^11 J = 7.56 × 10^13 J/mol

Hope this helps -Paige

Answer:

[H⁺] = 1.0 x 10⁻¹² M.

Explanation:

∵ [H⁺][OH⁻] = 10⁻¹⁴.

[OH⁻] = 1 x 10⁻² mol/L.

∴ [H⁺] =  10⁻¹⁴/[OH⁻] = (10⁻¹⁴)/(1 x 10⁻² mol/L) = 1.0 x 10⁻¹² M.

∵ pH = - log[H⁺] = - log(1.0 x 10⁻¹² M) = 12.0.

∴ The solution is basic, since pH id higher than 7 and also the  [OH⁻] > [H⁺].

I think- IDK

Answer:

2MnO2 + H2O => Mn2O3 + 2OH is the correct balanced equation.

When manganese oxide reacts with water to form a different manganese oxide and hydroxide, the correct balanced equation for this is 2MnO₂ + H₂O ⇾ Mn₂O₃ + 2OH.

The term balance chemical equation is define as the equation which satisfy the law of conservation of mass, i.e., “Total mass of the products is equal to the total mass of all the reactants”.

If a chemical equation is not balanced, it will break the law of conservation of mass. It will indicate that either mass is created or destroyed, which is impossible.

Balanced chemical equations have the equal number and type of each atom on both sides of the equation.  

Thus, When manganese oxide reacts with water to produce a different manganese oxide and hydroxide, the correct balanced equation for this reaction is 2MnO₂ + H₂O ⇾ Mn₂O₃ + 2OH.

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Answer:

More energy

Explanation:

Wave amplitude is determined by the energy of the disturbance that causes the wave. A wave caused by a disturbance with more energy has greater amplitude.

Answer:

energy of the disturbance

Explanation:

........ btw bts paved the way I saw you was army and thought I would say that

Answer:

MRCORRECT has answered the question

Explanation:

13 electrons

So... for the element of ALUMINUM, you already know that the atomic number tells you the number of electrons. That means there are 13 electrons in a aluminum atom. you can see there are two electrons in shell one, eight in shell two, and three in shell three.

7 electrons

So... for the element of NITROGEN, you already know that the atomic number tells you the number of electrons. That means there are 7 electrons in a nitrogen atom. Looking at the picture, you can see there are two electrons in shell one and five in shell two.

Answer:

a → 3

b → 1

c → 6

d → 4

e → 2

f → 5

Hope this helps!

Answer:

a → 3

b → 1

c → 6

d → 4

e → 2

f → 5

Explanation: hope it helps!!

Answer:

An amplifying device that indicates the presence of ionizing particles  

GEIGER COUNTERS

A device that permits determination of alpha and beta radiation emitted from a substance  

BOTH

Film sensitive to radiation that is removed and developed to measure exposure  

NEITHER

A device used for monitoring individual cumulative exposure to ionizing radiation  

NEITHER

Explanation:

1. Geiger counters and scintillation counters can be described by statements 1 and 2.

2. Statement 3 refers to film-based radiation detectors, not Geiger counters or scintillation counters.

3. Statement 4 refers to dosimeters, not Geiger counters or scintillation counters.

1. An amplifying device that indicates the presence of ionizing particles: This statement describes both Geiger counters and scintillation counters. Both types of counters use amplifying devices to detect and indicate the presence of ionizing particles.

2. A device that permits determination of alpha and beta radiation emitted from a substance: This statement describes both Geiger counters and scintillation counters. Both types of counters are capable of detecting alpha and beta radiation.

3. Film sensitive to radiation that is removed and developed to measure exposure: This statement describes neither Geiger counters nor scintillation counters. Instead, it refers to film-based radiation detectors, such as photographic film or thermoluminescent dosimeters (TLDs), which are used to measure radiation exposure.

4. A device used for monitoring individual cumulative exposure to ionizing radiation: This statement describes neither Geiger counters nor scintillation counters.

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Answer:

b

Explanation:

i read this once and remember,trust me!

Answer:

20 is b and 21 is a.

Answer:

The amount of energy released from the combustion of 2 moles of methae is 1,605.08 kJ/mol

Explanation:

The chemical reaction of the combustion of methane is given as follows;

CH₄ (g) + 2O₂ (g) → CO₂ (g) + 2H₂O (g)

Hence, 1 mole of methane combines with 2 moles of oxygen gas to form 1 mole of carbon dioxide and 2 moles of water vapor

Where:

CH₄ (g): Hf = -74.6 kJ/mol

CO₂ (g): Hf = -393.5 kJ/mol

H₂O (g): Hf = -241.82 kJ/mol

Therefore, the combustion of 1 mole of methane releases;

-393.5 kJ/mol × 1 + 241.82 kJ/mol × 2 + 74.6 kJ/mol = -802.54 kJ/mol

Hence the combustion of 2 moles of methae will rellease;

2 × -802.54 kJ/mol or 1,605.08 kJ/mol.

Answer: answer is C

Explanation:

Just took the test

Answer:

They can use man made materials or they can also have designed areas that people can’t go into

Explanation:

Answer:

- From octane: [tex]m_{CO_2}=1.54x10^5gCO_2[/tex]

- From ethanol: [tex]m_{CO_2}=9.57x10^4gCO_2[/tex]

Explanation:

Hello,

At first, for the combustion of octane, the following chemical reaction is carried out:

[tex]C_8H_{18}+\frac{25}{2} O_2\rightarrow 8CO_2+9H_2O[/tex]

Thus, the produced mass of carbon dioxide is:

[tex]m_{CO_2}=5.00x10^4gC_8H_{18}*\frac{1molC_8H_{18}}{114gC_8H_{18}}*\frac{8molCO_2}{1molC_8H_{18}}*\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=1.54x10^5gCO_2[/tex]

Now, for ethanol:

[tex]C_2H_6O+3O_2\rightarrow 2CO_2+3H_2O[/tex]

[tex]m_{CO_2}=5.00x10^4gC_2H_6O*\frac{1molC_2H_6O}{46gC_2H_6O}*\frac{2molCO_2}{1molC_2H_6O}*\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=9.57x10^4gCO_2[/tex]

Best regards.