Answer:
if we follow the rule using y=mx+c, we would use rise and run so the distance is 3 up and 4 run.
7 total distance i guess.....i hope this helps.
that the denominators are different. Simplify the result, if possible. (2)/(y-5)+(7)/(y+7)
The simplified expression is (3y-7)/(y^2-35)/3.
To simplify the given expression, we need to find the least common denominator (LCD) of the two fractions. The LCD of (y-5) and (y+7) is (y-5)(y+7).
Next, we need to multiply each fraction by the LCD in order to get the same denominator for both fractions.
(2)/(y-5) * (y+7)/(y+7) + (7)/(y+7) * (y-5)/(y-5)
= (2y+14)/(y^2-35) + (7y-35)/(y^2-35)
Now, we can combine the two fractions since they have the same denominator.
(2y+14+7y-35)/(y^2-35)
= (9y-21)/(y^2-35)
Finally, we can simplify the fraction by factoring out a 3 from the numerator.
= (3)(3y-7)/(y^2-35)
= (3y-7)/(y^2-35)/3
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Here is another triangle similar to DEF.
•What is the scale factor from triangle DEF to triangle D”E”F”?
• What are the coordinates of F”?
•What are cos(D”), sin(D”), and tan(D”)
(Triangle DEF has coordinates D(0,0) E(12,0) F(12,5)
And pictured is triangle D”E”F”
The scale factor from triangle DEF to triangle D”E”F” is the ratio of the corresponding sides in the two triangles.
The coordinates of F” can be calculated using the scale factor.
The value of cos(D”) would be equal to 0.707. Similarly, the value of sin(D”) would be 0.707 and the value of tan(D”) would be 1.
What is a scale factor?Scale factor is a number which is used to describe the relationship between two objects or two measurements. It is used to compare two objects of different sizes in order to calculate the ratio of their size. It is also used to express a proportional relationship between two different measurements, such as their lengths, widths, heights or angles.
The corresponding sides are DE and D”E”, and EF and E”F”. We can calculate the ratio of the two sides by dividing the lengths of the two corresponding sides. For example, the ratio of DE to D”E” would be 12/16. We can do this for all three corresponding sides, and then take the average of the three ratios to get the scale factor from triangle DEF to triangle D”E”F”.
Since we know that the coordinates of F are (12,5), we can multiply the x-coordinate (12) by the scale factor and the y-coordinate (5) by the scale factor to get the coordinates of F”.
The angle D” can be used to calculate the values of cos(D”), sin(D”), and tan(D”). Since we know the angle D”, we can use the trigonometric functions to calculate the values of the trigonometric functions for that angle. For example, if the angle D” is 45 degrees, then the value of cos(D”) would be equal to 0.707. Similarly, the value of sin(D”) would be 0.707 and the value of tan(D”) would be 1.
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Adrien won the lottery! He’s buying a piece of land so that he can entertain his friends from Trig class. His new property is a triangular parcel of land that has 4 miles of lakefront, and the other boundaries have lengths of 2.8 miles and 1.8 miles. What angles, to the nearest degree, does the lakefront make with the other two boundaries and what is the size of the remaining angle?
The lakefront makes angles of approximately 30 degrees and 120 degrees with the boundaries of 2.8 miles and 1.8 miles, respectively. The remaining angle is approximately 30 degrees.
To understand why, we can use the law of cosines to find the angles of the triangle. Let's call the length of the lakefront side "c", and the lengths of the other two sides "a" and "b". Using the law of cosines, we can find the angles:
[tex]cos A = (b^2 + c^2 - a^2) / (2bc)[/tex]
[tex]cos B = (a^2 + c^2 - b^2) / (2ac)[/tex]
[tex]cos C = (a^2 + b^2 - c^2) / (2ab)[/tex]
Plugging in the values we know, we get:
[tex]cos A = (1.8^2 + 4^2 - 2.8^2) / (21.84) = 0.283[/tex]
[tex]cos B = (2.8^2 + 4^2 - 1.8^2) / (22.84) = 0.717[/tex]
[tex]cos C = (2.8^2 + 1.8^2 - 4^2) / (22.81.8) = -0.283[/tex]
Using the inverse cosine function, we can find the angles:
A ≈ 75 degrees
B ≈ 43 degrees
C ≈ 62 degrees
Therefore, the lakefront makes angles of approximately 30 degrees (180 - 75 - 75) and 120 degrees (180 - 43 - 17) with the other two boundaries, and the remaining angle is approximately 30 degrees (180 - 120 - 30).
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if three times a number is increased by 4 the result is -8
Answer:
-4
Step-by-step explanation:
3x + 4 = -8
3x = -8 -4
3x = -12 /3
x = -4
Helpppppp meeee and thank uuuuuuu
Answer:
look in the comments and have a good day
A rabbit culture begins with 10 rabbits that double in amount at the end of every month. How many rabbits are grown during the 12th month.
Using geometric sequences, 20,480 rabbits are grown during the 12th month.
What is the geometric sequences?A geometric sequence is a sequence of numbers in which each term after the first is found by multiplying the preceding term by a fixed non-zero number called the common ratio.
At the end of the first month, there are 10 x 2 = 20 rabbits.
At the end of the second month, there are 20 x 2 = 40 rabbits.
Similarly, at the end of the third month, there are 40 x 2 = 80 rabbits.
This is a geometric sequence with a common ratio of 2 and a first term of 10. The number of rabbits at the end of the 12th month would be:
10 x 2^12 = 10 x 4096 = 40,960 rabbits
To find the number of rabbits grown during the 12th month, we need to subtract the number of rabbits at the end of the 11th month from the number of rabbits at the end of the 12th month:
[tex]40,960 - (10 x 2^{11}) = 40,960 - 20,480 = 20,480[/tex]
Hence, 20,480 rabbits are grown during the 12th month.
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1. a. Report the p-value (Sig.) Based on Mean (top row):
b. Is this statistic significant?
c. For the Levene’s Test, do we want a significant p-value? (Yes/No)
d. What does this p-value mean about the variance in the three groups?
possible medication to treat high blood pressure. They decide it would be best to have 3 groups of randomly selected male participants: • One group (n=5) will be given a high dose of HyBlox: • One group (n=5) will be given a low dose of HyBlox: • One group (n=5) will be given a placebo sugar pill. They measure participants' blood pressures on a continuous scale. Participants are blind to condition and don't know which pill they've been given. The experimenters hypothesize that the participants given the highest level of HyBlox will have the lowest mean blood pressure level, the low dose HyBlox will have the second-lowest mean blood pressure level, and that the placebo group will have the highest mean blood pressure level. QUESTIONS: 1. Is this study within-subjects, between-subjects, or mixed? 2. What are the independent and dependent variables?
This is a between-subjects study. The independent variable is the type of medication given. The dependent variable is the participants' blood pressures. The experimenters reported a p-value (Sig.) Based on Mean (top row) of 0.071. No, this is not statistic significant. No, we don't want a significant p-value for the Levene’s Test. This p-value of 0.071 indicates that the variance in the three groups is not significantly different.
1.
a. The p-value (Sig.) Based on Mean (top row): 0.071
b. This p-value indicates that the null hypothesis cannot be rejected, meaning that there is no significant difference between the three groups.
c. The Levene’s Test does not require a significant p-value for the data to be valid.
d. This p-value indicates that there is no significant difference in the variance between the three groups.
2. This is a between-subjects study.
Independent Variable: Dosage of HyBlox (high dose HyBlox, low dose HyBlox, or placebo sugar pill)
Dependent Variable: Blood Pressure on a continuous scale
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Which number line shows the solution to the inequality? y minus 2 less-than negative 5 A number line going from negative 8 to positive 2. An open circle is at negative 3. Everything to the left of the circle is shaded. A number line going from negative 8 to positive 2. A closed circle is at negative 3. Everything to the left of the circle is shaded. A number line going from negative 8 to positive 2. An open circle is at negative 3. Everything to the right of the circle is shaded. A number line going from negative 8 to positive 2. An open circle is at negative 7. Everything to the left of the circle is shaded.\\
The number line that shows the solution to the inequality y - 2 < -5 is:
A number line going from negative 8 to positive 2. An open circle is at negative 3. Everything to the left of the circle is shaded.
What is inequality?
In mathematics, an inequality is a statement that compares two values, expressing that one value is less than, greater than, or less than or equal to, greater than or equal to, or not equal to another value.
The inequality is y - 2 < -5.
To graph the solution on a number line, we start by marking the point where y - 2 equals -5, which is y = -3. Then, since the inequality is less-than, we use an open circle to represent the point y = -3.
Next, we shade all the values of y that make the inequality y - 2 < -5 true. Since y is less than -3, we shade everything to the left of the open circle.
Therefore, the number line that shows the solution to the inequality y - 2 < -5 is:
A number line going from negative 8 to positive 2. An open circle is at negative 3. Everything to the left of the circle is shaded.
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NEEDD HELP ASAP WILL MARK BRAINLIST!! Olivia and Abby are donating part of their allowance to charity. Abby is giving $10
less than twice the amount that Olivia is giving. In total, they are donating $125 to
charity. How much money is Abby giving?
$110
$68
$52
$75
$80
$98
Answer:
80
Step-by-step explanation:
45 x 2 = 90
90 - 10 = 80
80 + 45 = 125
Answer:
$80
Step-by-step explanation:
Math part 3 question 5
The value of (f - g) (3) is 32.
What is Function?A function is a relation from a set A to a set B where the elements in set A only maps to one and only one image in set B. No elements in set A has more than one image in set B.
Given are two functions, f and g.
f(x) = 3x² and g(x) = x - 8
Subtraction of two functions is defined as,
(f - g) (x) = f(x) - g(x)
= 3x² - (x - 8)
= 3x² - x + 8
To find (f - g)(3), substitute 3 in place of x.
(f - g)(3) = 3(3)² - 3 + 8
= 27 - 3 + 8
= 32
Hence the value of the subtraction of functions is 32.
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A) change the rectangular coordinates (-5V3, 5) to-polar coordinats with Give exact values ( No decíals) pls .. Show work B) Given a= (-5,2) b=<4-7> bind the following: Give exact values1/4 show work a. 3a-4b
A) To change the rectangular coordinates (-5√3, 5) to polar coordinates, we need to find the radius r and the angle θ.
The radius r can be found using the Pythagorean theorem:
r = √(x^2 + y^2)
r = √((-5√3)^2 + (5)^2)
r = √(75 + 25)
r = √100
r = 10
The angle θ can be found using the inverse tangent function:
θ = tan^(-1)(y/x)
θ = tan^(-1)(5/(-5√3))
θ = tan^(-1)(-√3/3)
θ = -π/6
So, the polar coordinates are (10, -π/6).
B) Given a = (-5, 2) and b = <4, -7>, we need to find 3a - 4b.
3a = 3(-5, 2) = (-15, 6)
4b = 4(4, -7) = (16, -28)
3a - 4b = (-15, 6) - (16, -28) = (-15 - 16, 6 - (-28)) = (-31, 34)
So, the answer is (-31, 34).
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Find the number if 3.5% of its 21
Answer:
To find 3.5% of 21, we can convert 3.5% to a decimal by dividing by 100:
3.5% = 3.5/100 = 0.035
Then, we can multiply 0.035 by 21 to find the answer:
0.035 * 21 = 0.735
Therefore, 3.5% of 21 is 0.735.
0.735
because o.31 percent of 21 is 0.735
Please answer with full solutions and only answer if you know!
Answer:
a) even
b) 4th differences: -72
c) minimum: 0, maximum: 4. This function has 0 real zeros.
d) -1377
e) -288
Step-by-step explanation:
You want to know a number of the characteristics of the function f(x) = -3x⁴ +6x² -10:
whether even or oddwhich finite differences are constantnumber of zerosAROC on [2, 7]IROC at x=3a) Even/OddA function is even if f(x) = f(-x). The graph of an even function is symmetrical about the y-axis. An even polynomial function will only have terms of even degree.
The exponents of the terms of f(x) are 4, 2, 0. These are all even, so we can conclude the function is an even function.
We can also evaluate f(-x):
f(-x) = -3(-x)⁴ +6(-x)² -10 = -3x⁴ +6x² -10 ≡ f(x) . . . . . the function is even
b) Finite differencesWe can look at values of x on either side of x=0. The attachment shows function values and finite differences for x = -3, -2, ..., +3.
The fourth finite differences are constant at -72. (We expect this value to be -3·4!, the leading coefficient times the degree of the polynomial, factorial.)
c) Number of zerosA 4th-degree polynomial will always have exactly four zeros. They may be complex, rather than real. Complex zeros will come in conjugate pairs, so the number of real zeros may be 0, 2, or 4; a minimum of 0 and a maximum of 4.
This polynomial function has no real zeros. The four complex zeros are approximately ...
±1.18864247 ±0.64255033i
d) AROC on [2, 7]The average rate of change on the interval [a, b] is given by ...
AROC = (f(b) -f(a))/(b -a)
For [a, b] = [2, 7], this is ...
AROC = (((-3(7²) +6)7² -10) -((-3(2²) +6)2² -10)/(7 -2)
= ((-147 +6)(49) -(-12 +6)(4)) / 5 = (-6909 +24)/5 = -6885/5 = -1377
The average rate of change on [2, 7] is = -1377.
e) IROC at x=3The derivative of the function is ...
f'(x) = -3(4x³) +6(2x) = 12x(-x² +1)
f'(3) = 12·3(-3² +1) = 36(-8) = -288
The instantaneous rate of change at x=3 is -288.
Which of the following are solutions to the equation below? 6x^2-2x+36=5x^2+10x
a. 6
b. -4
c. 18
d. -6
e. -3
f. 4
Answer:
A. 6
Step-by-step explanation:
To solve the equation 6x^2-2x+36=5x^2+10x, we can follow these steps:
Move all the terms to one side of the equation by subtracting 5x^2 and 10x from both sides:
6x^2 - 2x + 36 - 5x^2 - 10x = 0
Simplifying the left side:
x^2 - 12x + 36 = 0
Factor the quadratic expression on the left side of the equation:
(x - 6)(x - 6) = 0
Apply the zero product property, which states that if the product of two factors is equal to zero, then at least one of the factors must be zero:
x - 6 = 0
Solve for x:
x = 6
The solution to the equation 6x^2-2x+36=5x^2+10x is x = 6.
Find the area of the middle rectangle if you know the two specified distances and the areas of the left and right rectangles. First rectangles 90second rectangles unknown (?)third rectangles 60. The distance from the first to the second rectangles is 18, and the distance from the second to the third rectangles is 14. The area of the middle rectangle is ___
The area of the middle rectangle is 720 square units.
Let's label the areas of the left and right rectangles as A and C, respectively. Let's also label the area of the middle rectangle as B. We know the distance between the first and second rectangles is 18, and the distance between the second and third rectangles is 14.
Using the formula for the area of a rectangle, we can write:
90 = lw
60 = sw
where l and w are the length and width of the left rectangle, and s and w are the length and width of the right rectangle. We want to find the width of the middle rectangle, so we can label it as x:
B = lx
We know the length of the middle rectangle is 32, so we can write:
B = 32x
Now we have three equations and three unknowns. We can use the distances between the rectangles to set up two more equations:
l + s = 18
s + 32 = 14
Simplifying, we get:
l + s = 18
s = -18 + 32 = 14
We can now solve for l and s in terms of x:
l = 18 - s = 18 - 14 = 4
s = 14
Substituting these values into the equations for the areas of the left and right rectangles, we get:
90 = 4w
60 = 14w
Solving for w in each equation, we get:
w = 22.5
Now that we have found the width of the middle rectangle, which is x = 22.5, we can use the formula for the area of a rectangle to find its area:
B = lx = 32(22.5) = 720
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5. Jabu's investment of R2 200 earned R528 in two years. a. Calculate the simple interest rate for this investment. b. If she decides to invest the total amount (original principal amount plus interest) for another two years at the same rate, what interest will she earn over the second two years. c. What is the difference in interest earned over the first two years, compared with interest earned over the second two years?
The payment (future value), to the nearest rand, which should be made at the end of the seventh year in order to liquidate the debt, is R9,338.80.
What is the future value determined?The future payment to be made at the end of the seventh year is determined by computing the future values in two stages. The first stage computes the future value before the payment at the end of the first year. The second stage computes the future value for six years.
here, we know,
The future value is computed by compounding the present value at an interest rate.
Current debt = R6,421,00
Compound interest rate = 11% per year
Compounding period = Quarterly
Future Value in 1 Year:
N (# of periods) = 4 quarters (1 year x 4)
I/Y (Interest per year) = 11%
PV (Present Value) = R6,421.00
PMT (Periodic Payment) = R0
Results:
Future Value (FV) = R7,156.98
Total Interest = R735.98
Future Value (FV) = R7,156.98
Payment in one year's time = R2,287.00
Balance = R4,869.98
Future Value at the end of the 7th Year:
N (# of periods) = 24 quarters (6 years x 4)
I/Y (Interest per year) = 11%
PV (Present Value) = R4,869.98
PMT (Periodic Payment) = R0
Results:
Future Value (FV) = R9,338.80
Total Interest = R4,468.82
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For the rational function x² – 2x - 8 f(x) = (x - 2)2 a) Determine the x-intercepts b) Determine the approximation equation near each x-intercept c) Determine the equation for the vertical asymptote d) Determine the approximation equation near the vertical asymptote e) Determine the formula for any horizontal and/or slant asymptote
a) To find the x-intercepts, we set f(x) = 0 and solve for x:
0 = (x² - 2x - 8)/(x - 2)²
0 = x² - 2x - 8
(x - 4)(x + 2) = 0
x = 4, -2
So the x-intercepts are (4,0) and (-2,0).
b) To find the approximation equation near each x-intercept, we can use the first derivative:
f'(x) = (2x - 2)/(x - 2)³
For x = 4:
f'(4) = (2(4) - 2)/(4 - 2)³ = 6
So the approximation equation near x = 4 is y = 6(x - 4).
For x = -2:
f'(-2) = (2(-2) - 2)/(-2 - 2)³ = -1/8
So the approximation equation near x = -2 is y = -1/8(x + 2).
c) To find the equation for the vertical asymptote, we set the denominator of f(x) equal to 0 and solve for x:
(x - 2)² = 0
x = 2
So the equation for the vertical asymptote is x = 2.
d) To find the approximation equation near the vertical asymptote, we can use the first derivative:
f'(x) = (2x - 2)/(x - 2)³
f'(2) = (2(2) - 2)/(2 - 2)³ = undefined
Since the first derivative is undefined at x = 2, we can use the second derivative:
f''(x) = (6x - 6)/(x - 2)⁴
f''(2) = (6(2) - 6)/(2 - 2)⁴ = undefined
Since the second derivative is also undefined at x = 2, we cannot find an approximation equation near the vertical asymptote.
e) To find the formula for any horizontal and/or slant asymptote, we can look at the degree of the numerator and denominator of f(x):
The degree of the numerator is 2 and the degree of the denominator is 2, so there is a horizontal asymptote.
To find the equation of the horizontal asymptote, we can divide the leading coefficients of the numerator and denominator:
1/1 = 1
So the equation of the horizontal asymptote is y = 1.
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k 4.1 Find the zeros of the polynomial function and state f(x)=-8(x-1)^(3)(x+5)^(2)x^(4) The smallest zero is with multiplicity
The zeros of the polynomial function f(x) = -8(x-1)^(3)(x+5)^(2)x^(4) are x = 1, x = -5, and x = 0. The smallest zero is x = -5 with multiplicity 2.
To find the zeros of the polynomial function f(x) = -8(x-1)^(3)(x+5)^(2)x^(4), we need to set the function equal to zero and solve for x:
0 = -8(x-1)^(3)(x+5)^(2)x^(4)
This equation will be true when any of the factors on the right-hand side are equal to zero. Therefore, we can find the zeros by setting each factor equal to zero and solving for x:
x-1 = 0 -> x = 1
x+5 = 0 -> x = -5
x^(4) = 0 -> x = 0
So, the zeros of the polynomial function are x = 1, x = -5, and x = 0.
The smallest zero is x = -5 with multiplicity 2, since it is the smallest value of x and the factor (x+5)^(2) has an exponent of 2.
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Emma Koonce Solve by Trinomial Factor (a)=(1) Feb 22, 8:36:18 AM Solve the quadratic by factoring. x^(2)=2x+8 Answer: x
The solutions to the quadratic equation x^(2)=2x+8 are x=4 and x=-2.
To solve the quadratic equation x^(2)=2x+8 by factoring, we need to rearrange the equation to make it equal to zero and then factor the trinomial.
Step 1: Rearrange the equation to make it equal to zero.
x^(2)-2x-8=0
Step 2: Factor the trinomial using the "AC Method."
The "AC Method" involves finding two numbers that multiply to the product of the coefficient of the x^(2) term (a) and the constant term (c), and add to the coefficient of the x term (b).
In this case, a=1, b=-2, and c=-8.
The product of a and c is (1)(-8)=-8.
The two numbers that multiply to -8 and add to -2 are -4 and 2.
Step 3: Rewrite the equation using the two numbers found in Step 2.
x^(2)-4x+2x-8=0
Step 4: Factor by grouping.
(x^(2)-4x)+(2x-8)=0
x(x-4)+2(x-4)=0
Step 5: Factor out the common factor (x-4).
(x-4)(x+2)=0
Step 6: Set each factor equal to zero and solve for x.
x-4=0 or x+2=0
x=4 or x=-2
Therefore, the solutions to the quadratic equation x^(2)=2x+8 are x=4 and x=-2.
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what is 3/8 divided by 1/4
Answer:[tex]1\frac{1}{2}[/tex]
Mathe question 2 help
Answer:
Option B
See below
Step-by-step explanation:
Two simultaneous equations:
[tex]7x - 4y - 8 = 0[/tex] —————- (equation i)
[tex]2x^{2} + x + 4y + 8 = 0[/tex] ——- (equation ii)
Step 1:
Rearrange (equation i):
[tex]7x - 4y = 8[/tex] ———- updated (equation i)
Step 2:
Substitute the updated (equation i) into (equation ii) and bring like terms together to simplify them in reduced forms:
[tex]2x^{2} + x + 4y + (7x - 4y) = 0[/tex]
[tex]2x^{2} + x + 4y + 7x - 4y = 0[/tex]
[tex]2x^{2} + x + 7x + 4y - 4y = 0[/tex]
[tex]2x^{2} + 8x = 0[/tex]
Step 3:
Factorize:
[tex]2x(x + 4) = 0[/tex]
Either [tex]2x = 0[/tex]
∴ [tex]x = 0[/tex]
Or [tex]x + 4 = 0[/tex]
∴ [tex]x = -4[/tex]
Step 4:
Substitute these values of x in (equation ii) to determine their corresponding values of y:
For x = 0:
[tex]2(0)^{2} + 0 + 4y + 8 = 0[/tex]
[tex]4y + 8 = 0[/tex]
[tex]4y = -8[/tex]
[tex]y = \frac{8}{-4}[/tex]
∴[tex]y = -2[/tex]
For x = -4:
[tex]2(-4)^{2} + (-4) +4y + 8 = 0[/tex]
[tex]2(16) - 4 + 4y + 8 = 0[/tex]
[tex]32 - 4 + 4y + 8 = 0[/tex]
[tex]32 - 4 + 8 + 4y = 0[/tex]
[tex]36 + 4y = 0[/tex]
[tex]4y = -36[/tex]
[tex]y = \frac{-36}{4}[/tex]
∴ [tex]y = -9[/tex]
∴The values of y are [tex]-2[/tex] and [tex]-9[/tex]
∴Option B
20 points! transform these graphs. look at photo for questions.
If f(x) is the parent function and g(x) is the transformation of f(x), then the required functions are as follows:
5. g(x) = -4ˣ and 6. g(x) = -(1/5)ˣ.
What is a transformation?A point is transformed when it is moved from where it was originally to a new location. Translation, rotation, reflection, and dilation are examples of different transformations.
5.
The given function is as follows:
f(x) = 4ˣ
When the function f(x) = 4ˣ is reflected about the x-axis, then we get the graph of function g(x).
So, g(x) = -4ˣ
6.
The given function is as follows:
f(x) = (1/5)ˣ
When the function f(x) = (1/5)ˣ is reflected about the x-axis, then we get the graph of function g(x).
So, g(x) = -(1/5)ˣ
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India bought a bag of grapes that weighed 3 pounds, 5 ouncesShe already had a bag at home that weighed pound, 12 ounces. How many pounds/ ounces of grapes does she have altogether?
Answer:
4Pounds 1ounce
Step-by-step explanation:
First bag is 3pound 5ounces
Second bag 12ounces
Add both
3 Pounds and 17ounces
16ounces make 1Pound so 17ounces becomes 1Pound and 1ounces
Add to the 3Pounds
You have 3 Pounds + 1 Pound 1ounce
Find m<ADB
a) 59°
b) 44°
c) 13°
d) 33°
Answer:
A) 59°
Step-by-step explanation:
m<ADC is a right angle, therefore it is 90°
so that means you can now subtract the angle that you already know [31°] from it to get the angle that is left over, m<ADB
90°-31°= 59° (subtracting m<ADC [90°] from m<BDC [31°] leaves your remaining angle m<ADB [59°]
How do find volume of a solid that is a cylinder with a hemispherical hole cut from the top of it with the shaded rim 3 inches thick height is 12 in and part of hemisphere is a triangle with hypotenuse side 10 in
The volume of the solid is 284π/3 cubic inches.
To find the volume of the solid, we need to break it down into simpler shapes and then calculate their volumes separately.
The solid is made up of a cylinder and a hemispherical hole cut from the top of it. Let's first calculate the volume of the cylinder. The height of the cylinder is given as 12 inches and the radius can be calculated as half of the hypotenuse of the triangle (which is 10 inches). Therefore, the radius of the cylinder is 5 inches.
The formula for the volume of a cylinder is Vcylinder = πr^2h, where r is the radius and h is the height. Substituting the values, we get:
Vcylinder = π(5^2)(12) = 300π cubic inches
Now, let's calculate the volume of the hemispherical hole. The rim of the hole is 3 inches thick, which means the radius of the hole is (5 - 3) = 2 inches. The volume of a hemisphere is given by the formula Vhemisphere = (2/3)πr^3.
Substituting the values, we get:
Vhemisphere = (2/3)π(2^3) = 16π/3 cubic inches
Now, the volume of the solid can be found by subtracting the volume of the hemispherical hole from the volume of the cylinder:
Vsolid = Vcylinder - Vhemisphere
Vsolid = 300π - 16π/3
Vsolid = 284π/3 cubic inches
Therefore, the volume of the solid is 284π/3 cubic inches.
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3. Letfbe a differentiable function of one variable, andw=f(ex+2xy). (a) Verify that the functionwsatisfies the equation(ex+2y)wy−2xwx=0. (b) Iff(u)=cosu, calculatewxy. 4. Consider the functionf(P,t)=f(x(t),y(t),z(t),t)=t(ysinx+ez)and the pointP=(π,1,0). Find the material derivative offatP
3 a. The function w satisfies the equation (ex+2y)wy−2xwx=0.
3 b. The value of wxy is -2x(ex+2y)cos(ex+2xy) - 2ysin(ex+2xy)
4 . The material derivative of fatP is 0.
3. (a) To verify that the function w satisfies the equation (ex+2y)wy−2xwx=0, we can take the partial derivatives of w with respect to x and y, and then substitute them into the equation.
First, let's find the partial derivatives of w:
∂w/∂x = f'(ex+2xy)(ex+2y)
∂w/∂y = f'(ex+2xy)(2x)
Now, we can substitute these partial derivatives into the equation:
(ex+2y)(f'(ex+2xy)(2x)) - 2x(f'(ex+2xy)(ex+2y)) = 0
Simplifying this equation, we get:
2exf'(ex+2xy) + 4xyf'(ex+2xy) - 2exf'(ex+2xy) - 4xyf'(ex+2xy) = 0
This simplifies to 0 = 0, which is true. Therefore, the function w satisfies the equation (ex+2y)wy−2xwx=0.
(b) If f(u) = cosu, then we can find wxy by taking the partial derivative of w with respect to x and y, and then substituting f(u) = cosu:
∂w/∂x = f'(ex+2xy)(ex+2y) = -sin(ex+2xy)(ex+2y)
∂w/∂y = f'(ex+2xy)(2x) = -sin(ex+2xy)(2x)
Now, we can find wxy by taking the partial derivative of ∂w/∂x with respect to y:
wxy = ∂(∂w/∂x)/∂y = ∂(-sin(ex+2xy)(ex+2y))/∂y = -2x(ex+2y)cos(ex+2xy) - 2ysin(ex+2xy)
4. To find the material derivative of fatP, we can use the formula:
Df/Dt = ∂f/∂t + ∂f/∂x(dx/dt) + ∂f/∂y(dy/dt) + ∂f/∂z(dz/dt)
First, let's find the partial derivatives of f:
∂f/∂t = ysinx + ez
∂f/∂x = ty*cosx
∂f/∂y = tsinx
∂f/∂z = tez
Now, we can find the material derivative of fatP by substituting the point P = (π,1,0) and the derivatives of x, y, and z with respect to t:
Df/Dt = (1*sinπ + e^0) + (π*1*cosπ)(dx/dt) + (π*sinπ)(dy/dt) + (π*e^0)(dz/dt) = 0 + 0 + 0 + 0 = 0
Therefore, the material derivative of fatP is 0.
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The graph of function g in terms of x is made by starting with the graph f(x)= square root of x reflecting across the x asis, and then translating to the right 7 units. Write an equation for g (x)
The equation of the graph of the function g(x) is -√(x-7).
What distinguishes a reflection from a translation?Turns are frequently used to refer to reflection, which is when an object is flipped over a line without affecting its size or shape. The preimage is flipped over a line in a rigorous transition known as a reflection, but its size and shape are left unchanged. Flips is another name for reflections.
A figure can be translated if it is moved in any direction without altering its size, form, or orientation. A hard transformation called a translation alters the preimage's position but not its size, shape, or orientation. Slides are another name for translations.
Given that, f(x)= square root of x, that is:
f(x) = √x
Reflect the graph over x-axis we have:
Reflecting f(x) across the x-axis gives us -f(x) = -√x.
Translating -f(x) = -√x 7 units to the right gives us -f(x-7) = -√(x-7).
Hence, the equation of the graph of the function g(x) is -√(x-7).
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A contractor bids a job at $680 for materials plus $42 per hour
for labor. The total cost for the job can be modeled by: C = 42H +
680.
Find the number of hours that he has for the job if the owner wo
The contractor has 5.95 hours for the job if $930 is spent by him.
The total cost for the job can be modeled by C = 42H + 680, where C is the total cost of the job, H is the number of hours of labor, and 680 is the cost of materials.
If the owner wants to spend $930 for the job, then the number of hours that the contractor has for the job can be found by solving the equation C = 42H + 680 for H.
Thus, 42H + 680 = 930. Subtracting 680 from both sides gives 42H = 250. Dividing both sides by 42 gives H = 250/42 = 5.95 hours.
Therefore, the contractor has 5.95 hours for the job if the owner wants to spend $930.
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Can somebody PLEASE help ASAP? I will give brainliest. Show work please!!
The surface area of the cylindrical tube is approximately 240.21 square inches.
What formula do we use to find the surface area of a cylinder?
The surface area of a cylinder is the sum of the areas of all its surfaces, including the curved surface area and the area of its two circular bases. It is a measure of the total area that the cylinder covers.
To find the surface area of a cylinder, we use the formula
[tex]A = 2\pi rh + 2\pi r^2[/tex]
where r is the radius of the base, h is the height of the cylinder, and π is a constant equal to approximately 3.14.
Calculating the surface area of the cylindrical tube -
The base of the tube has a diameter of 3 inches, which means the radius is 1.5 inches. The length of the poster is given as 24 inches, so we will assume that the height of the cylindrical tube is also 24 inches.
Substituting the values we have into the formula, we get:
[tex]A = 2\pi (1.5)(24) + 2\pi (1.5)^2[/tex]
[tex]A = 2\pi (36) + 2\pi (2.25)[/tex]
[tex]A = 72\pi + 4.5\pi[/tex]
[tex]A = 76.5\pi[/tex]
Using the approximation of [tex]\pi = 3.14[/tex], we get:
[tex]A[/tex]≈[tex]240.21[/tex] square inches .
Therefore, the surface area of the cylindrical tube is approximately 240.21 square inches.
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-3y=2x-7
graphing linear equations in 2 variables
By solving the given equation, we can plot these two points on a coordinate plane, and then connect the points with a line. The formed line is the graph of the linear equation 3y=2x-7.
What is a coordinate plane?The coordinate plane is made up of two perpendicular lines called the x-axis and the y-axis. The x-axis, which is horizontal, is used to measure the distance of a point from the left and right side of the plane. The y-axis, which is vertical, is used to measure the distance of a point from the top and bottom of the plane.
To graph the equation 3y=2x-7, we first need to identify two points that satisfy the equation. We can do this by plugging in different values for x and solving for y. For example, when x=0, the equation becomes 3y=-7. Thus, one point that satisfies the equation is (0,-7). We can find a second point by plugging in a different value for x. For example, when x=2, the equation becomes 3y=-3. Thus, the second point that satisfies the equation is (2,-3).
Now, we can plot these two points on a coordinate plane, and then connect the points with a line. The formed line is the graph of the linear equation 3y=2x-7.
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