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Answer:

67.5%

Explanation:

Step 1: Write the balanced equation for the electrolysis of water

2 H₂O ⇒ 2 H₂ + O₂

Step 2: Calculate the theoretical yield of O₂ from 17.0 g of H₂O

According to the balanced equation, the mass ratio of H₂O to O₂ is 36.04:32.00.

17.0 g H₂O × 32.00 g O₂/36.04 g H₂O = 15.1 g O₂

Step 3: Calculate the percent yield of O₂

Given the experimental yield of O₂ is 10.2 g, we can calculate its percent yield using the following expression.

%yield = (exp yield / theoret yield) × 100%

%yield = (10.2 g / 15.1 g) × 100% = 67.5%

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Answer: oxnzle

Explanation:

Answer:

NO. 10.

performed experiments

NO. 11.

Inference

Explanation:

No 10.

in order to prove that Mary Mellon was in fact infected by typhoid proper experiments needs to be carried out.

No. 11

inference means an assumption due to the situation.

Answer:

When gases in containers are heated, their molecules increase in average speed. This means that they exert a greater force when they collide with the container walls, and also collide with the walls more frequently. The gas is therefore under greater pressure when its temperature is higher.

Answer:

Option B.

C₆H₁₀O₅ + 6O₂ —> 6CO₂ + 5H₂O

Explanation:

To know which option is correct, we shall write the balanced equation for the combustion of cellulose. This is illustrated below:

C₆H₁₀O₅ + O₂ —> CO₂ + H₂O

There are 6 atoms of C on the left side and 1 atom on the right side. It can be balance by writing 6 before CO₂ as shown below:

C₆H₁₀O₅ + O₂ —> 6CO₂ + H₂O

There are 10 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 5 before H₂O as shown below:

C₆H₁₀O₅ + O₂ —> 6CO₂ + 5H₂O

There are a total of 7 atoms of O on the left side and a total of 17 atoms on the right side. It can be balance by writing 6 before O₂ as shown below:

C₆H₁₀O₅ + 6O₂ —> 6CO₂ + 5H₂O

Now, the equation is balanced.

Thus, option B gives the correct answer to the question.

Answer:

This is because peroxy oxygen bonded to hydrogen can easily undergo nucleophilic protonation with the carbonyl carbon to form an alcohol

Explanation:

A ketone is a functional group that contains a carbonyl group (carbon-oxygen double bond ( R1R2-C=O).

The carbonyl carbon doubly bonded to the oxygen is electron deficient as a result of difference in electronegativity between carbon and oxygen, hence is susceptible to nucleophilic attacks

R1R2 - C = O

where R1 and R2 are organic substituents.

The peroxy oxygen that is bonded to hydrogen (H -O-O-R) is the electron-rich centre and easily attacks electron-deficient centres like the carbonyl carbon in ketones to form an alcohol.

The bond between the hydrogen attached to the peroxy oxygen is broken and the resultant hydrogen ion undergoes protonation with the oxygen of the carbonyl group to form an alcohol

R1R2 - C = O + H - O-O - R =>

R1R2- CH - OH + R - O-O-R1

Answer:

[tex]V=795.26L[/tex]

Explanation:

From the question we are told that:

Volume [tex]V=1dm^3=>1L[/tex]

Density [tex]\rho=70.8g/L[/tex]

Generally the equation for Density is mathematically given by

[tex]\rho =\frac{Mass}{Volume}[/tex]

Therefore

[tex]M=\rho*V[/tex]

[tex]M=70.8*1[/tex]

[tex]M=70.8g[/tex]

Since at STP

[tex]T=273K[/tex]

[tex]P=1atm[/tex]

[tex]Mass =70.8g[/tex]

Therefore

[tex]Moles\ of\ Hydrogen=\frac{Mass}{2g}[/tex]

[tex]Moles\ of\ Hydrogen=\frac{70.8}{2g}[/tex]

[tex]Moles\ of\ Hydrogen=35.4moles[/tex]

Generally the equation for Ideal gas is mathematically given by

[tex]PV=nRT[/tex]

Therefore

[tex]V=\frac{nRT}{P}[/tex]

[tex]V=\frac{35.4*0.0826*273}{1}[/tex]

[tex]V=795.3L[/tex]

Answer:

3.0 mol H₂O

Explanation:

Step 1: Write the balanced combustion equation

C₂H₆ + 3.5 O₂ ⇒ 2 CO₂ + 3 H₂O

Step 2: Establish the appropriate molar ratio

The molar ratio of C₂H₆ to H₂O is 1:3.

Step 3: Calculate the moles of H₂O formed from 1.0 mole of C₂H₆

1.0 mol C₂H₆ × 3 mol H₂O/1 mol C₂H₆ = 3.0 mol H₂O

When the hematite particles rearrange to form a new substance", this statement describes chemical change.

A chemical change is a change of materials into another, new materials with different properties and one or more than one new substances are formed.

As a chemical changes is usually a change where a substance undergoes a chemical change and forms a new substance; which cannot be easily reversed into reactants by any simple physical methods.

In this example the hematite ore forms a new substance by an irreversible chemical change.

Hence, "The hematite particles rearrange to form a new substance", this statement describes chemical change.

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Answer:

1. Isotope 2 occurs most commonly

2. 39.02amu

Explanation:

1. Isotope 2 has a relative abundance of 78.68% i.e. 78.68 out of 100, hence, it is the isotope that occurs most commonly.

2. Isotope 1 = 9.67%, mass no: 38

Isotope 2 = 78.68%, mass no: 39

Isotope 3 = 11.34%, mass no: 40

Isotope 4 = 0.31%, mass no: 41

To find the average atomic mass of element X, we multiply each isotopes' relative abundance by its mass no and find the sum as follows:

We convert each percentage to decimal abundance:

Isotope 1 = 9.67% = 0.0967

Isotope 2 = 78.68% = 0.7868

Isotope 3 = 11.34% = 0.1134

Isotope 4 = 0.31% = 0.0031

(0.0967 × 38) + (0.7868 × 39) + (0.1134 × 40) + (0.0031 × 41)

3.6746 + 30.6852 + 4.536 + 0.1271

Average atomic mass = 39.02amu

Answer:

Explanation:

Volume of one mole of a gas = 22.4 litre.

No of molecules in one mole of gas = 6.02 x 10²³ .

Volume of one molecule = 4/3 π R³

= 4/3 x 3.14 x ( 167 x 10⁻¹² m )³

= 19.5 x 10⁶ x 10⁻³⁶ m³

=19.5 x 10⁻³⁰ m³

= 19.5 x 10⁻³⁰ x 10³ litre .

=  19.5 x 10⁻²⁷ litre .

So volume occupied by molecules in one mole of gas

= 19.5 x 10⁻²⁷ x 6.02 x 10²³  litre

117.4 x 10⁻⁴ litre

= .01174 litre.

Excluded volume

= ( 22.4 -  .01174  ) litre .

= 22.388 litre.

Answer:

[tex] moles = \frac{ number \: of \: particles}{6.02 \times {10}^{23} } [/tex]

=1.806×10^22/6.02×10^23

=0.03 moles

hope this helps :)

Answer:

Neutralization reactions occur when two reactants, an acid and a base, combine to form the products salt and water.

The organ that is used to detect the product of a neutralization reaction is the sense of taste.

When a neutralization reaction occurs between an acid and a base, it results in the formation of a salt and water. The salt produced in the reaction may have a distinct taste, depending on its chemical properties. For example, when hydrochloric acid reacts with sodium hydroxide, the products are sodium chloride and water. Sodium chloride, commonly known as table salt, has a characteristic salty taste.

Similarly, other salts formed from neutralization reactions may have different tastes. For instance, magnesium hydroxide reacting with acetic acid produces magnesium acetate, which has a slightly sweet taste. By using our taste buds, particularly on the tongue, we can detect and identify the taste of the salt formed during a neutralization reaction.

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Answer:

C

Explanation:

like charges repel each others so if they have the same charge they will move away from each other

Answer: A volume of 1.16 L hydrogen is produced at a pressure of 2 atm and a temperature of 298 K.

Explanation:

Given: Mass of Mg = 2.3 g

Pressure = 2 atm

Temperature = 298 K

The reaction equation is as follows.

[tex]Mg + 2HCl \rightarrow MgCl_{2} + H_{2}[/tex]

This shows that 1 mole of Mg gives 1 mole of [tex]H_{2}[/tex].

Hence, moles of Mg for the given mass is calculated as follows.

[tex]Moles = \frac{mass}{molar mass}\\= \frac{2.3 g}{24.30 g/mol}\\= 0.095 mol[/tex]

Hence, 0.095 moles of Mg will give 0.095 moles of [tex]H_{2}[/tex].

Formula used to calculate volume is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into the above formula as follows.

[tex]PV = nRT\\2 atm \times V = 0.095 mol \times 0.0821 L atm/mol K \times 298 K\\V = \frac{0.095 mol \times 0.0821 L atm/mol K \times 298 K}{2 atm}\\= 1.16 L[/tex]

Thus, we can conclude that a volume of 1.16 L hydrogen is produced at a pressure of 2 atm and a temperature of 298 K.

Answer:

For the first question, to determine the total number of molecules of nitrogen dioxide, first make use of the molar mass of the nonpolar compound and then use that to find the total number of moles and then subsequently after make use of the ratio for the Avogadro's number to determine the total number of molecules of this compound.

For the final question, do the inverse, where we make use of the molecules of the compound and then use Avogadro's number to determine the moles of the compound and then use the same molar mass of the compound to determine the grams of the Nitrogen Dioxide.

Answer:

I hope that's what u were lookong for :))

Explanation:

Answer:

6.40 is the answer to your question

The number of moles of oxygen in 1.60 moles of sodium hydrogen phosphate is 6.4 moles

Let's represent the chemical formula of the compound. The chemical formula of sodium hydrogen phosphate is as follows:

The chemical formula of a compound is a symbolic expression use to signify the number of atoms present in a molecular substance. Therefore,

sodium hydrogen phosphate  = Na₃PO₄

Therefore,

1 mole of Na₃PO₄ = 4 moles of oxygen

1.60 moles of Na₃PO₄  = ? moles of oxygen

cross multiply

number of moles of oxygen = 1.60 × 4

number of moles of oxygen = 6.4 moles

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Answer:

b

Explanation:

Molecular formula of Decanoic Acid is  C₁₀H₂₀O₂ therefore Option A is the right answer.

Decanoic Acid is a C10 , straight chain , saturated fatty acid . Its general formula is C₁₀H₂₀O₂ .

In the first option we can see a straight chain , saturated fatty acid and the molecular formula is also same as decanoic acid .

In second option the molecular formula is C₉H₁₈O₂ which is not same as Decanoic Acid.

Hence option A is the right answer.

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[tex]\huge\boxed{\fcolorbox{red}{blue}{ QUESTION }}[/tex]

The maximum number of electrons that can be present in an shell is

[tex] \orange{\underline{\huge{\bold{\textit{\green{\bf{OPTIONS}}}}}}} [/tex]

a) [tex]2 {n}^{2} [/tex]

b) [tex]2 {n}^{2} + 1[/tex]

c) 2n

d) none of these.

[tex] \huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}[/tex]

OPTION (a)

[tex]2 {n}^{2} [/tex]

[tex] \bold { \red{ \star{ \blue{EXAMPLES}}}}[/tex]

In First shell only 2 electron can be placed .

[tex]2 {n}^{2} \\ n = 1 \: (bez \: \: no \: \: shell \: = 1) \\ so \\ 2 { n}^{2} = 2 \times {1}^{2} = 2 \: electrons[/tex]

In second shell 8 electrons can be placed

[tex]2 {n}^{2} \\ n = 1(bez \: \: no\: \: shell \: = 2) \\ 2 {n}^{2} = 2 \times {2}^{2} = 2 \times 4 = 8 \: electrons[/tex]

Answer:

a. "-ic"

Explanation:

The correct answer is a. "-ic".

For example:

Following the same logic, the name for HBr is Hydrobromic acid; and the name for HI is Hydroiodic acid.

Answer:

Rr

Explanation:

Answer:

Diatomic molecules contain two atoms that are chemically bonded. If the two atoms are identical, as in, for example, the oxygen molecule (O2), they compose a homonuclear diatomic molecule, while if the atoms are different, as in the carbon monoxide molecule (CO), they make up…

Explanation:

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Answer:

A structure that obeys the octet rule for each molecule or ion is [tex]XeO_4[/tex]  

Explanation:

Here in [tex]XeO_4[/tex]   , Xenon  has  8 valence electrons and each oxygen atom has 6 valence electrons  

Lewis structure for [tex]XeO_4[/tex] is shown below :

Here , all atoms are having their complete octet .

All the atoms in this Lewis structure is having their complete octet .

Resonance structure is not required as all atoms are same that is oxygen .