HELP ME PLEASE WILL GIVE BRAINLIEST!!!!

Answer:y=1/2x+8

Step-by-step explanation: You find the slope using the equation

m= y2-y1/x2-x1= 1/2

and then you use point-slope form y-y1=m(x-x1)

Total area

A = semi circle + triangle.

1. Area of the semi circle:

2. Area of the triangle:

h = 6; to find base we use the Pythagoras theorem, as follows:

Then,

Total area = 14 + 24 = 38 m²

Perimeter =

6 (π + 2) + 10 + 8 = 49 m

Any number of angles that add up to 180 are supplementary. Since a 180 degree angle is a straight line, these two angles, which lie on a straight line are supplementary.

An arithmetic succession, is defined by constant sums or substractions. A geometric succession, is defined by constant products. In this case, we can define this succession as a product

It means this succession is geometric.

When one grain of sand weighs 7×10⁻⁵ g, then there are 9.0 × 10¹⁰ grains of sand in 6300 kg of sand.

Given, one grain of sand approximately weighs 7×10⁻⁵ g.

Then how many grains of sand are there in 6300 kg of sand = ?

we know that one grain of sand weighs =  7×10⁻⁵ g.

therefore, 6300 kg = 6300 × 10³ g sand contains

= 6300 × 10³/7×10⁻⁵

= 900×10³/10⁻⁵

= 900 × 10³ × 10⁵

= 9.00 × 10² × 10³ ×10⁵

= 9.0 × 10²⁺³⁺⁵

= 9.0 × 10¹⁰

Hence there are 9.0 × 10¹⁰ grains of sand in 6300 kg of sand.

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Based on the figure shown the lines that are parallel are

Using the given figure

From the alternate internal angle postulate it can be shown that angle in both line t and line s are equal. This angle is 65 degrees.

The alternate angle postulate hold true for parallel lines hence it shows that line s is parallel to line t while line m is the transversal line required to complete the postulate.

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assuming is simple interest

[tex]~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$4000\\ r=rate\to 3.75\%\to \frac{3.75}{100}\dotfill &0.0375\\ t=years\dotfill &5 \end{cases} \\\\\\ A=4000[1+(0.0375)(5)] \implies A=4000(1.1875)\implies A = 4750[/tex]

x + x +2x + 2x = 64 is the right equation

How to check perimeter of rectangle ?

The formula for perimeter of rectangle is P = 2*(l+w)

we have perimeter , 64 = 2* (2x + x)

                                64  = x + x + 2x +2x

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The answer is number UNO

The answer can be  window and 11

Answer:

answer is fish

Step-by-step explanation:

_______________________________

Answer:

In a parallelogram:

Opposite sides are parallel.

Opposite sides and opposite angles are congruent.

Consecutive angles are supplementary.

Answer:

[tex](3p, 3p+4)[/tex]

Step-by-step explanation:

[tex]f(3p)=3p+4 \\ \\ \therefore (3p, 3p+4)[/tex]

Answer:

Slope is -12.5

x-intercept is 75

y-intercept is 6

Step-by-step explanation:

See attached image

Answer:

b

Step-by-step explanation:

Answer: x = 2.5

The change in P in percentage terms is 51% decrease.

Since the two variables are connected by the relation, this will be illustrated as:

P=k/Q^2

where k is the proportionality constant.

Now, If Q is increased by 40%, i.e. the update Q' = Q + 0.4Q.

Now, we have

P1 = k/Q^2 and P2 = k/(Q+0.4Q)^2

P2/P1 = {k/(Q+0.4Q)^2}/{k/Q^2}

P2/P1 = 1/(1.4)^2

P2=0.51*P1

P2 = 0.5P1

Hence P reduces by 51%.

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By solving a quadratic equation we will find two solutions, one is good and that is x = 0.62, and the other is extraneous and is x = -1.62

Here we have the following equation:

ln(x + 2) + ln(2x - 1) = 0

To solve this we need to know two things, first:

ln(a)+ ln(b) = ln(a*b)

ln(1) = 0

Using the first property, we can rewrite:

ln(x + 2) + ln(2x - 1) = ln( (x + 2)*(2x - 1)) = 0

And that can only be equal to zero if:

(x + 2)*(2x - 1) = 1

So we have a quadratic equation:

(x + 2)*(2x - 1) = 1

2x² - x + 4x - 2 = 1

2x² + 3x - 3 = 0

The solutions are:

[tex]x = \frac{-3 \pm \sqrt{3^2 - 4*3*(-3)} }{2*3} \\\\x = \frac{-3 \pm 6.7 }{6}[/tex]

So we have:

x = (-3 + 6.7)/6 = 0.62

x = (-3 - 6.7)/6 = -1.62

The second solution when evaluated in the second term of the equation gives:

ln(2*(-1.62) - 1) = ln(-4.24)

And this is not defined, so x = -1.62 is an extraneous solution.

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1)Use the following rule to rewrite with only a positive exponent: [tex]x^{-n}[/tex] = 1 ÷ [tex]x^{n}[/tex] and apply the exponent to both the numerator and the denominator of the fractional base using the rule: [tex](\frac{a}{b} )^{n} = \frac{a^{n} }{b^{n} }[/tex].

2) Simply add or subtract the numerators of two arithmetic operations with the same denominator and write the result to the common factor.

3) Yes, reasonable expressions have limitations at times. Check for zero just on the denominator side to identify those constraints.

1) To evaluate an expression with a rational and negative exponent, follow these steps:

2) To simplify rational variable expressions,

Simply add or subtract the numerators of two arithmetic operations with the same denominator and write the result to the common factor. If the denominators do not match, they must be changed until they are equal. That is, we need to find a common denominator.

3) The denominator can be any number, even zero. However, there are constraints based on not reducing by zero inside the case of a denominator. There is a limit to the value that may be used to replace our variable and get a denominator of 0.

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The relationship between ∠7 and ∠8 are linear pair angles.

Line m and n intersect at point E.

When line intersects angle relationships are formed such as vertically opposite angles, linear angles etc.

Therefore, angles relationships are formed when the line m and line n intersect at point E.

Hence,

∠7 and ∠8 are linear pair angles.

Linear pair of angles are formed when two lines intersect each other at a single point.

Linear pair angles are supplementary.

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The parent function is the most basic example of the function type specified.

Solve the equation y=(2)x for y.

Lessen the steps you tap...

Take the parentheses out.

y=2x

Take the parentheses out.

Rmove parenthesis from y=(2)x.

y=2x

Assume that f(x)=2x for y=(2)x and g(x)=2x for y=2x8 respectively.

f(x)=2x\sg(x)=2x−8

Find a, h, and k for each equation to determine the transformation from the first equation to the second.

y=abx−h+k

For f(x)=2x a=1, find a, h, and k.

h=0\sk=0

Find a, h, and k for g(x)=2x8 with a=1, h=8, and k=0.

The value of h determines the horizontal shift.

The graph is moved to the left by h units, which is expressed as g(x)=f(x+h).

The graph is moved to the right by h units when g(x)=f(xh).

Right 8 Units Horizontal Shift

The value of k determines the vertical shift.

The graph is shifted up k units and is denoted by the expression: g(x)=f(x)+k).

g(x)=f(x)k shifts the graph down k units.

No vertical shift

The reflection that spans the x-axis is indicated by the symbol of a.

A signifies that the x-axis of the graph is reflected.

No reflection on the x-axis

The graph's vertical stretch or compression is indicated by the value of a.

A vertical stretch is a>1 (makes it narrower)

A vertical compression (which results in 0a1)

The graph's vertical stretch or compression is indicated by the value of a.

A vertical stretch is a>1 (makes it narrower)

A vertical compression is 0a1 (makes it wider)

Vertical Stretch or Compression: None

Compare the two functions and look for a horizontal or vertical shift, a reflection about the x-axis, and a vertical stretch to identify the transformation.

f(x)=2x is the parent function.

Right 8 Units Horizontal Shift

No vertical shift

No reflection on the x-axis

Vertical Stretch or Compression: None

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Answer:

432. Zola will have 432 4-inch pieces of rope.

The inequality that can be used with the squeeze theorem to calculate the limit of f(x) is [tex]-x^{2} \leq x^{2} cos\frac{1}{x^{2} } \leq x^{2} or -x^{2} \leq f(x)\leq x^{2}[/tex]

Squeeze Theorem,

If f(x)g(x)h(x) for all numbers and at some point x=k we get f(k)=h(k), then g(k) must also be equal to them, according to the squeeze (or sandwich) theorem. Theorem: By "squeezing" sin(x)/x between two better functions and using them to discover the limit at x=0, we can utilize them to obtain tricky limits like sin(x)/x at x=0.

The given function is [tex]f(x) = x^{2} cos(\frac{1}{x} )[/tex]

The range of the cos function is from -1 and 1.

We have,

[tex]-1\leq cos\frac{1}{x^{2} } \leq 1\\[/tex]

Multiplying the above inequality by x^2, we get :

[tex]-x^{2} \leq x^{2} cos\frac{1}{x^{2} } \leq x^{2}[/tex]

The above equation can be rewritten as,

[tex]-x^{2} \leq f(x)\leq x^{2}[/tex]

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The linear equation that passes through the anchor points (-3, -38) and (8, 61) is:

y = 9*x - 11

The general linear equation is written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

We know that for a line that passes through two points (x₁, y₁) and (x₂, y₂) can be written as:

a = (y₂ - y₁)/(x₂ - x₁)

Now, in this case we know that our line passes through the points (-3, -38) and (8, 61), then the slope will be:

a = (61 + 38)/(8 + 3) = 9

Replacing that we get:

y = 9*x + b

Now, using one of the points we can find the y-intercept, I will use (8, 61), replacing the values we get:

61 = 9*8 + b

61 = 72 + b

61 - 72 = b

-11 = b

The linear equation is:

y = 9*x - 11

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Answer:

C = $60

Step-by-step explanation:

To calculate monthly charges, a cellphone provider uses the equation: C = 0.25m + 60, with C being dollars and m representing minutes used beyond the ones provided by the plan. Assuming the plan allowed for 60 minutes, what would the charge be for a client that used 55 minutes? Put your answer in terms of dollars.

The customer used 55 minutes and did not max out the phone plan, and therefore does not pay any over charges of m.

C = 0.25m + 60 when m = 0

C = 0.25m + 60

C = 0.25(0) + 60

C = 0 + 60

C = $60

Answer:

C = $60

Step-by-step explanation:

The image of the point after the dilation is (3, 6)

Dilation involves changing the side length of a shape or a function

The given parameters are:

Point =  (6, 12)

The scale factor of dilation is given as

Scale factor = 1/2

Mathematically, this transformation can be represented as

(x, y) = 1/2(x, y)

So, we have

(x, y) = (1/2x, 1/2y)

When represented as a function, we have

Image = 1/2 * Point

Substitute the equation Point =  (6, 12) in the equation Image = 1/2 * Point

So, we have the following equation

Image = 1/2 * (6, 12)

Evaluate the product

Image = (3, 6)

Hence, the image is (3, 6)

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According to the information, it can be concluded that there is no significant difference in the braking distances of the two models.

To check if there is a wide difference between the braking distances of the two models we can use several alternatives. One of them is to add all the braking distance results of each car and take the average as shown below:

According to the above, it can be concluded that the braking distance of both models only varies by 2 feet, so it is considered that there is not a great difference in braking distances.

Note: This question is incomplete because there is some information missing. Here is the complete information:

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Answer:

[tex]3.2129 \times {10}^{5} [/tex]

Step-by-step explanation:

[tex](7.22 \times {10}^{1} )(4.45 \times {10}^{3} )[/tex]

[tex](7.22 \times 4.45) \times ( {10}^{1} \times {10}^{3} )[/tex]

[tex]32.129 \times {10}^{4} [/tex]

[tex]3.2129 \times {10}^{5} [/tex]

Hello!

The angle of 30º is one of the remarkable angles (the others are 45º and 60º).

These angles are the most used in trigonometry, so it's good to memorize it.

Below, I'll explain to you one way to memorize it as a table:

For the sine and cosine, let's fill these spaces with 1 2 3 on the first line, and 3 2 1 on the second line. Then we're going to divide all of that by 2.

When the numerator is 2 or 3 we will put a square root in it.

For the tangent, it will be a little different:

• Tangent of ,30º ,is √3/3

• Tangent of ,45º ,is 1

• Tangent of ,60º ,is √3

Sin 30º: 1/2 or 0.5

Cos 30º: √3/2

Tan 30º: √3/3

If a milk truck delivers 486 dozen gallons of milk to stores in 1 day, then equation to calculate "g",  the number of gallons of milk the milk truck delivers in 1 day, can be written as [g = (486 * 12)]

As per the question statement, a milk truck delivers 486 dozen gallons of milk to stores in 1 day.

We are required to determine the equation that can best express "g", the number of gallons of milk the milk truck delivers in 1 day.

To solve this question, first we need to know what an equation is.

Here, We know that (1 dozen = a set of 12),

Then, [486 Dozen Gallons = (486 * 12)] gallons, which is the total number of gallons of milk the milk truck delivers in 1 day.

On the other hand, the variable "g" can also be used to determine the number of gallons of milk the milk truck delivers in 1 day.

Therefore, our required equation is [g = (486 * 12)].

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Answer:

3 and 4

Step-by-step explanation:

square root 12 lies between (square root 9 and 16) so it is between 3 and 4

Answer: 3 and 4 is what your teacher is probably looking for, but there are technically infinite solutions to the first question.

3 is a better estimate for the square root of 12 since 3 times 3 = 9 which is 3 integers away from 12, where as 4 times 4 = 16, which is 4 integers away from 12.  

Step-by-step explanation:

Calculate the square root of 12 which is roughly 3.464

Whole numbers are non-fractional.  They can be any positive integer, as well as zero.

3.464 is between 3 and 4.

3 is less than 3.464 which is less than 4.  

3 < 3.464 < 4

Technically there are infinite solutions to this problem, since 3.464 is also between 3 and 4, 3 and 5, 3 and 6, 2 and 4, 2 and 5, and infinitely more.  

Question 2:

3*3 = 9.  

4*4 = 16.  

12-9 = 3.

16-12 = 4.

3 < 4.

12 is closer to 9 than it is to 16.  

Answer:

There are 20 long tables and 5 round tables y.

Step-by-step explanation:

Given:

long tables x + round tables y = total of 25 tables

8seats ·x +6seats ·y = 190 seats

Find x and y:

x+y= 25 so x= 25-y

8x+6y = 190, we substitute x for 25-y to find y

8(25-y) +6y = 190, we distribute 8 in parenthesis

200 -8y+6y = 190, combine like terms

200 -2y = 190, subtract 200 from both sides

-2y = 190-200, combine like terms

-2y = -10, divide both sides by -2

y = 5

x+y = 25, substitute y for 5

x+5 = 25, subtract 5 from both sides

x= 20

Conclusion:

There are 20 long tables and 5 round tables y.

Check :

20·8+5·6 = 160+30 = 190 seats