Answer:
Domain: A, [tex][1, \infty)[/tex]
Range: A, [tex][-4, \infty)[/tex]
Step-by-step explanation:
The domain is the set of x-values and the range is the set of y-values.
Ethan says that the value of 40.7 is 10 times the value of 4.07
The assumption Ethan made was correct
What is Fraction?
Any number of equal parts is represented by a fraction, which also represents a portion of a whole. A fraction, such as one-half, eight-fifths, or three-quarters, indicates how many components of a particular size there are when stated in ordinary English.
Ethan said that the result of 10 and 4.07 is 40.7, thus we must verify that his computation is accurate.
In order to do such, we must multiply 10 by 4.07 as illustrated below:
= 10 x 4.07
= 10 x 407/100
= 4070/100
= 40.70
Since the outcome matches Ethan's hypothesis,
The conclusion is valid.
Hence, The result of Ethan is correct
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Which number is the additive inverse of -10 1/4 ?
10 1/4
-4 1/10
0
4/41
The additive inverse is 10(1/4)
What is additive inverse?By merely switching the integer's sign, you can add the original number and the additive inverse to produce a result equal to 0. The attributes of additive inverse are outlined below based on the negation of the original number. For instance, if the beginning integer is x, the additive inverse of x is -x.
The additive inverse of a number is the one that, when added to, yields zero. Other names for this exact number include sign change, negation, and the opposite (number).
Given -10(1/4)
-10(1/4) + 10(1/4) = 0
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I need help with this problem
Answer:
f(1) + g(2) = 7
Step-by-step explanation:
Given functions:
[tex]\begin{cases}f(x)=-x^2+2x-3\\g(x)=10-\dfrac{1}{2}x \end{cases}[/tex]
To find f(1), substitute x = 1 into function f(x):
[tex]\begin{aligned}x=1 \implies f(1)& =-(1)^2+2(1)-3\\& = -1+2-3\\&=1-3\\&=-2\end{aligned}[/tex]
To find g(2), substitute x = 2 into function g(x):
[tex]\begin{aligned}x=2 \implies g(2)& =10-\dfrac{1}{2}(2)\\& =10-1\\&=9\end{aligned}[/tex]
Therefore, to evaluate f(1) + g(2), sum the two values found for f(1) and g(2):
[tex]\begin{aligned}\implies f(1)+g(2)&=-2+9\\&=7\end{aligned}[/tex]
As one calculation:
[tex]\begin{aligned}\implies f(1)+g(2)&=-(1)^2+2(1)-3+10-\dfrac{1}{2}(2)\\&=-1+2-3+10-1\\&=1-3+10-1\\&=-2+10-1\\&=8-1\\&=7\end{aligned}[/tex]
In an athletics team there are 60 members. 24 of them are girls. What percentage are girls?
To determine the percentage of girls on the team, you have to divide the number of girls by the total members of the team and multiply the result by 100:
[tex]\frac{nº\text{girls}}{nº\text{members}}\cdot100=\frac{24}{60}\cdot100=0.4\cdot100=40\%[/tex]The percentage of girls on the team is 40%
The question is in the photo please answer with each one
Answer:
Solution(s) below.
Step-by-step explanation:
This question involves the concept of reading values from graph.
The first 3 questions are basically asking you to find the value of y when x is a certain value.
a) g(7) is asking to find the value of y when x = 7.
So we can see from the graph, when x = 7, y = 4.
b) g(0) is asking to find the value of y when x = 0.
So we can see from the graph, when x = 0, y = 7.
c) g(-5) is asking to find the value of y when x = -5.
So we can see from the graph, when x = -5, y = 6 (Read from the value of 5 on the left side of the graph since x is negative.)
d) This question is asking us to do the opposite compared to the other 3 questions, its asking us to find the value of x when y = 3.
So, we can see from the graph, when y = 3, x = 9.
How much more will his shirt cost in Fresno than Bakersfield (in dollars)? (Round each to the nearest cent and write your answer as a decimal).
The amount of money more that his shirt cost in Fresno than Bakersfield is $0.145.
How to calculate the value?Given that the amount of shirt is $20. The value of the shirt in Fresno will be:
= Cost + Tax
= $20 + (8.225% × $20)
= $20 + $1.645
= $21.645
The value in Bakersfield will be:
= Cost + Tax
= $20 + (7.5% × $20)
= $20 + $1.5
= $21.5
The difference will be:
= $21.645 - $21.5
= $0.145
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help meeeeeeeeeeeeeeeeeeeeeee
thank you
Answer:
v-x=&56
Step-by-step explanation:
i catrostiphically BELIVE THT IT IS THE FLYRIDE ANDREW TATE INN ADOPT ME
An elementary school wants to purchase a new swing set. The table shows the selling price of the swing sets they are interested in buying Swing Set Wholesale Price ($) Adventurers 3,056 Thunder Ridge 4,125 The markup for both swing sets is 20%. The school decides to buy the Adventurers swing set. What is the selling price of the swing set they are buying? Round to the nearest cent if necessary,
The selling price of Adventurers swing set is $3,667
What are mathematics operations?
• An operation is a function in mathematics that converts zero or more input values (also known as "operands" or "arguments") to a well-defined output value.
• The operation's arity is determined by the number of operands.
• Binary operations (i.e., operations of arity 2), such as addition and multiplication, and unary operations (i.e., operations of arity 1), such as additive inverse and multiplicative inverse, are the most commonly studied operations.
• A zero-arity operation, also known as a nullary operation, is a constant.
• The mixed product is an example of an arity 3 operation, also known as a ternary operation.
We have,
Adventurers swing set wholesale selling price = $3056
Markup means the amount increased.
20% Mark up on the price:
= 20% of 3056
= 20/100 x 3056
= $611.2
The selling price of Adventurers swing set:
= $3056 + $611.2
= $3,667.2
Rounding to the nearest cent:
= $3,667
Thus the selling price of Adventurers swing set is $3,667
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-A fisherman illegally introduces some fish into a lake, and they quickly propagate. The growth of thepopulation of this new species (within a period of a few years) is modeled P(x) = 5b>, where x is thetime in weeks following the introduction and b is a positive unknown base.a. Exactly how many fish did the fisherman release into the lake?
Equation:
P(x)= 5b^x
Where:
x = time in weeks
b= unknown base
When t= 0
P(0)= 5 b^0
P(0)= 5
a. The fisherman released 5 fish into the lake.
Please help struggling in math & this is for practice
The given functions are
[tex]\begin{gathered} f(t)=\frac{11}{t-2} \\ g(t)=\frac{22t}{t^2-4} \end{gathered}[/tex]The first part consists in adding the functions f(t) + g(t)
[tex]f(t)+g(t)=\frac{11}{t-2}+\frac{22t}{t^2-4}=\frac{11(t^2-4)+22t(t-2)}{(t-2)(t^2-4)}[/tex]Let's factor the square difference
[tex]\frac{11(t+2)(t-2)+22t(t-2)}{(t-2)(t^2-4)}=\frac{11(t+2)+22t}{t^2-4}[/tex]Now, we simplify
[tex]\frac{11t+22+22t}{t^2-4}=\frac{33t+22}{t^2-4}[/tex]Hence, the addition of the given functions is
[tex]f(t)+g(t)=\frac{33t+22}{t^2-4}[/tex]On other hand, let's solve the difference
[tex]\begin{gathered} f(t)-g(t)=\frac{11}{t-2}-\frac{22t}{t^2-4}=\frac{11(t^2-4)-22t(t-2)}{(t-2)(t^2-4)} \\ f(t)-g(t)=\frac{11(t+2)(t-2)-22t(t-2)}{(t-2)(t^2-4)} \\ f(t)-g(t)=\frac{11(t+2)-22t}{t^2-4}=\frac{11t+2-22t}{t^2-4} \end{gathered}[/tex]Hence, the difference is
[tex]f(t)-g(t)=\frac{-11t+2}{t^2-4}[/tex]Find the values for x given the equation7. (x - 5) (x + 1) = 0
Solution:
Given the equation;
[tex](x-5)(x+1)=0[/tex]Thus, the solution of the quadratic equation is;
[tex]\begin{gathered} x-5=0,x+1=0 \\ \\ x=5,x=-1 \end{gathered}[/tex]Connor went to New York for vacation. He spent threenights at a hotel and rented a car for four days. Jillian stayed at the samehotel but spent four nights and rented a car for five days from the samecompany. If Connor paid $675 and Jillian paid $875, how much did onenight at the hotel cost?
Solution:
Let x the cost for a night and y the cost to rent a car for a day.
Connor = 3 nights and 4 days = 3x + 4y = 675
Jillian = 4 nights and 5 days = 4x + 5y = 875
3x + 4y = 675 Multiply by 5
4x + 5y = 875 Multiply by 4
we get:
15x + 20y = 3375
16x + 20y = 3500
now, subtracting the two previous equations we obtain:
15x + 20y = 3375
-
16x + 20y = 3500
________________
-x + 0 = -125
x = 125
then, we can conclude that the correct answer is:
$125
Dont judge me on my answers Im not that good at maths I need to know the corrections . Also there’s another part . c) on a graph show the axis of symmetry of the function . Write down the equation of symmetry below.
Part a:
Let's factor f(x)=2x² - x -6
= (x-2)*(2x+3)
Part b: Solve for f(x) = 0
(x-2)*(2x+3) = 0
x-2 = 0
x = 2
OR
2x+3 = 0
2x = -3
x= -3/2
Part C: In a quadratic equation, such as the one given, the line of symmetry is given by:
x = -b/2a
x= -1/2*2
x= - 1/4
Bellow, you can see the graph:
what’s the correct answer answer asap for brainlist please.
Answer:
nitrogen is most abundant in atmosphere and soil
Which is true about the domain and range of a function in the form f(x) = m√x, where m is a real number greater
than 0?
O The only value that must be in both the domain and range is 0.
O The only values that must be in both the domain and range are 0 and 1.
O There are no values that are in the domain and the range.
O There is an infinite number of values that are in both the domain and range.
Mark this and return
Save and Cult
There is an infinite number of values that are in both the domain and range.
Define domain and range.The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x). A function's range is the collection of values it can take as input. After we enter an x value, the function outputs this sequence of values. The collection of all potential inputs for a function is its domain.
Given Data
Range of a function in the form f(x) = m√x, where m is a real number greater than 0
There is an infinite number of values that are in both the domain and range.
The range of a function always has an unlimited number of values when the domain of the function does. The claim is untrue because more than one input and output might have been matched.
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I need helpp this is geometry
Answer:
x = 8
AB = 1
BC = 1
Step-by-step explanation:
AB = BC when
[tex]\dfrac{3}{4}x - 5 = \dfrac{9}{4}x - 17[/tex]
In the above equation bring all the x terms to the left and the constants to the right as follows
Add 5 on both sides:Since x = 8 we can solve for the lengths of both segments by plugging in the value in the two expressions
[tex]AB = \dfrac{3}{4} \times 8 - 5\\\\AB = 6 - 5 = 1\\\\BC = \dfrac{9}{4} \times 8 - 17\\\\BC = 18 - 17 = 1\\\\[/tex]
So AB = BC = 1
Answer:
x = 8 , AB = BC = 1
Step-by-step explanation:
we require
AB = BC , that is
[tex]\frac{3}{4}[/tex] x - 5 = [tex]\frac{9}{4}[/tex] x - 17
multiply through by 4 to clear the fractions
3x - 20 = 9x - 68 ( subtract 9x from both sides )
- 6x - 20 = - 68 ( add 20 to both sides )
- 6x = - 48 ( divide both sides by - 6 )
x = 8
Then
AB = [tex]\frac{3}{4}[/tex] × 8 - 5 = 6 - 5 = 1
BC = [tex]\frac{9}{4}[/tex] × 8 - 17 = 18 - 17 = 1
so AB = BC
What is the measure of the unknown angle in the base of this pyramid? A) 25° OB) 40° OC) 55° OD) 70°
Notice that the base of the pyramid is a triangle, and recall that the interior angles of a triangle add up 180 degrees, therefore:
[tex]\text{?}+55^{\circ}+70^{\circ}=180^{\circ}[/tex]solving for ?, we get:
[tex]\begin{gathered} \text{?}=180^{\circ}-70^{\circ}-55^{\circ} \\ \text{? = 55}^{\circ} \end{gathered}[/tex]Answer:
its C. 70 degrees
because 180 - 50 - 60 = 70
180= whole shape,
so u want to subtract ur known degrees to get the unknown degree
Find the quadratic model in standard form for the set of values (3, -6), (1,-2), (6,3)
We are asked to determine a quadratic equation given a set of points. To do that, let's remember that a quadratic function is of the following form:
[tex]y=ax^{2^{}}+bx+c[/tex]Now we replace the given points:
Replacing (3, -6)
[tex]\begin{gathered} -6=a(3)^2+3b+c \\ -6=9a+3b+c,(1) \end{gathered}[/tex]Replacing (1, -2)
[tex]\begin{gathered} -2=a(1)^2+b(1)+c \\ -2=a+b+c,(2) \end{gathered}[/tex]Replacing (6, 3)
[tex]\begin{gathered} 3=a(6)^2+b(6)+c \\ 3=36a+6b+c,(3) \end{gathered}[/tex]We get a system of three equations and three variables, these are:
[tex]\begin{gathered} 9a+3b+c=-6,(1) \\ a+b+c=-2,(2) \\ 36a+6b+c=3,(3) \end{gathered}[/tex]Solving for "c" in equation (1):
[tex]c=-6-3b-9a,(4)[/tex]Solving for "c" in equation (2):
[tex]c=-2-b-a,(5)[/tex]Solving for "c" in equation (3)
[tex]c=3-6b-36a,(6)[/tex]equating equations (4) and (5):
[tex]-6-3b-9a=-2-b-a[/tex]Rewritting:
[tex]\begin{gathered} -3b+b-9a+a=-2+6 \\ -8a-2b=4,(7) \end{gathered}[/tex]equating equation (5) and (6):
[tex]-2-b-a=3-6b-36a[/tex]Rewritting:
[tex]\begin{gathered} -b-a+6b+36a=3+2 \\ 35a+5b=5,(8) \end{gathered}[/tex]Now we solve for "a" in equation (7):
[tex]\begin{gathered} -8a=4+2b \\ a=-\frac{1}{2}-\frac{1}{4}b \end{gathered}[/tex]Replacing the value of 2a" in equation (8)
[tex]35(-\frac{1}{2}-\frac{1}{4}b)+5b=5[/tex]Solving the operations:
[tex]-\frac{35}{2}-\frac{35}{4}b+5b=5[/tex]Solving for "b":
[tex]\begin{gathered} -\frac{7}{2}-\frac{7}{4}b+b=1 \\ -\frac{7}{2}-\frac{3}{4}b=1 \end{gathered}[/tex]Adding 7/2 to both sides:
[tex]\begin{gathered} -\frac{3}{4}b=1+\frac{7}{2} \\ -\frac{3}{4}b=\frac{9}{2} \\ b=-6 \end{gathered}[/tex]Therefore, b = 9.
Replacing this value in equation (7)
[tex]\begin{gathered} a=-\frac{1}{2}-\frac{1}{4}(-6) \\ a=1 \end{gathered}[/tex]Replacing in equation (2)
[tex]\begin{gathered} 1-6+c=-2 \\ \end{gathered}[/tex]Adding like terms:
[tex]-5+c=-2[/tex]Adding 5 to both sides:
[tex]\begin{gathered} c=-2+5 \\ c=3 \end{gathered}[/tex]Therefore, the quadratic equation is:
[tex]y=x^2-6x+3[/tex]stephen needs to place several cubic packages in a shipping box that measures 12 inches by 18 inches by 24 inches.
648cubes
Explanations
The formula for calculating the volume of a box is expressed as
[tex]V=lwh[/tex]where;
l is the length
w is the width
h is the height
Find the volume of the shipping box
[tex]\begin{gathered} V=12in\times18in\times24in \\ V=5184in^3 \end{gathered}[/tex]Determine the dimension of the cubic package
[tex]\begin{gathered} V_c=2in\times2in\times2in \\ V_c=8in^3 \end{gathered}[/tex]Determine the number of cubes that can fit in the shipping box.
[tex]\begin{gathered} number\text{ of cubes}=\frac{5184in^3}{8in^3} \\ number\text{ of cubes}=648cubes \end{gathered}[/tex]Therefore the maximum number of cubes that can fit into the box is 648cubes
explain how I get 1.2 from multiplying 4×0.3
To multiply 4x0.3 you need to multiply as if there is no decimal, 4x3=12
Then you count the number of digits after the decimal and put the same number of digits behind the decimal in the product.
Because 0.3 has just one number behind the decimal and there is only 1 number after the decimal it would be 1.2
Yesterday, Reuben had 143 baseball cards. Today, he gave b away. Using b, write an expression for the number of cards Reuben has left. II +0 O-O ローロ Х 5 ? Continue Save For La 2022 McGraw Hill LLC. All Rights Reserved. Terms of U hp
ANSWER:
143 - b
STEP-BY-STEP EXPLANATION:
Given:
Original quantity: 143
Amount given away: b
The amount of cards Ruben has today will be equal to the difference between the original amount and the given amount, it will be written as the following expression:
[tex]143-b[/tex]Plato please help!!
Which statement correctly describes the graph of g(x)=f(-x)+8
Answer:
D
Step-by-step explanation:
hopes this helps please mark brainliest
What is 4 x 1/7
Give your answer in simplify fully
Answer: 4/7 or 0.571428
Step-by-step explanation:
convert the expression
4/1 x 1/7
multiply the fractions
4x1 / 1x7
calculate the products
4/7 or 0.571428
Answer:
4 * 1/7 simplified is 4/7
Step-by-step explanation:
let me know if you want a thorough explanation!
The product of -13 and the difference of c and d
The text mentions a product of two terms and a subtraction. The first term is the number - 13 times the difference of c and d. As a mathematical expression, this would be
[tex](-13)\times(c-d)[/tex]Expanding this expression using the distributive rule, we have
[tex]\begin{gathered} (-13)\times(c-d) \\ =-13c+13d \end{gathered}[/tex]A Chick-o-stick is the inside of a Butterfingermade into a cylinder. A Chick-o-stick has adiameter of 1.8 cm and a height of 9.6 cm, ifwe were to cover it in chocolate, how mucharea needs to be covered?
It is given that the diameter is 1.8 cm so the radius is 0.9 cm
It is also given that the height is 9.6 cm.
It needs to be covered in chocolate so the surface area of the cylinder needs to be calculated.
The surface area of the cylinder is given by:
[tex]A=2\pi\times r(r+h)[/tex]Substitute the values to get:
[tex]\begin{gathered} A=2\times\pi\times0.9(0.9+9.6) \\ A=59.3761cm^2 \end{gathered}[/tex]Hence the area of chocolate required is 59.3761 square centimeters.
Joe bought 2 pairs of jeans and 1 shirt for 120 Sam bought 1 pair of jeans and 3 shirts for 135 How much does one shirt cost
Answer:
One shirt costs $80 and a pair of jeans equals $`15.
Step-by-step explanation:
If the shirt would cost $80 and you get 1, the jeans would equal 15. 2 pairs of jeans is 30, leaving $80 for the 1 shirt. You buy 1 pair of jeans, 15, and get 3 shirts for 135, 3 shirts would be 120. 120 + 15= 135. 80 + 15 + 15= 120.
Answer:
One shirt costs 30
Step-by-step explanation:
So, we don't know the prices for 1 shirt & 1 jeans, and we're to find the value of 1 shirt. Let's take it that:
1 shirt costs: x
1 jeans costs: y
Given that two persons in the names of Joe and Sam bought 2 pairs of jeans and 1 shirt for 120 and 1 pair of jeans and 3 shirts for 135 respectively, we can actually see that both persons bought jeans and shirts for different values. With the information, we convert to simultaneous equation.
The first info states that:
[tex]2y + x = 120→equ(i)[/tex]
The second info states that:
[tex]y + 3x = 135→equ(ii)[/tex]
Now, since we are to find the cost of 1 shirt (x), we make y the subject of formula in equation (ii) to solve for x.
[tex]y = 135 - 3x→equ(iii)[/tex]
Replace for the value of y in equation (i)
[tex]2(135 - 3x) + x = 120[/tex]
[tex]270 - 6x + x = 120[/tex]
Take like terms
[tex]-5x = 120 - 270[/tex]
[tex]-5x = -150[/tex]
Divide both sides by -5 to find the value of x
x = -150/ -5
Therefore: x = 30
Replace for the value of x in any of the equations
y = 45
Rewrite the expression by factoring out 3u-5. [tex]4u(3u-5)+(3u-5)[/tex]
Answer:
[tex]4u(3u-5)+(3u-5)=3u-5(4u +1)[/tex]
Step-by-step explanation:
[tex]4u(3u-5)+(3u-5)=3u-5(4u +1)[/tex]
Given the equation 6x-y=98, find x if y=-2
x=16
Explanationgiven the function
[tex]6x-y=98[/tex]Step 1
as we need x is terms of y, let's solve for x
[tex]6x-y=98[/tex]a) add y in both sides
[tex]\begin{gathered} 6x-y+y=98+y \\ 6x=98+y \end{gathered}[/tex]b) divide both sides by 6
[tex]\begin{gathered} 6x=98+y \\ \frac{6x}{6}=\frac{98+y}{6} \\ x=\frac{98}{6}+\frac{y}{6}\Rightarrow equation \\ \end{gathered}[/tex]Step 2
now, evaluate for y=-2
[tex]\begin{gathered} x=\frac{98}{6}+\frac{y}{6}\operatorname{\Rightarrow}equat\imaginaryI on \\ replace \\ x=\frac{98}{6}-\frac{2}{6} \\ x=\frac{96}{6}=16 \\ x=16 \end{gathered}[/tex]therefore, the answer is
x=16
I hope this helps you
a ferris wheel has a radius of 16 feet. how far will you travel if you go around 5 times ? pi= 22/7
Answer
Total distance travelled = 502.86 feet
Explanation
To know how far one would go, we need to first find the circumference of the ferris wheel. Since it is circular in shape,
Circumference = 2πr
where
π = pi = (22/7)
r = radius of the ferris wheel = 16 feet
Circumference = 2πr
Circumference = 2 × (22/7) × 16
Circumference = 100.57 feet
So, if one now goes round this exactly 5 times,
Total distance travelled = 5 (Circumfernce of the ferris wheel)
Total distance travelled = 5 (100.57)
Total distance travelled = 502.86 feet
Hope this Helps!!!
Select the correct answer, What is the least common multiple of the numbers 5, 25, and 157 A 25 B, 50 C. 75 D 100 E, 125