help me plis ............

a. To find the possible coordinates of point A, we know that the x-coordinate of point A is 5 and the distance between point A and point B is 15 units. Since the x-coordinate of point B is -4, we can calculate the difference between the x-coordinates of point A and point B:

x-coordinate of point A - x-coordinate of point B = 5 - (-4) = 9

So, the possible x-coordinate of point A is 9.

Now, we can use the distance formula to find the possible y-coordinate of point A. The distance between point A (5, y) and point B (-4, -2) is given as 15 units:

√[(x2 - x1)^2 + (y2 - y1)^2] = 15

Plugging in the coordinates of the points:

√[(5 - (-4))^2 + (y - (-2))^2] = 15

Simplifying:

√[9^2 + (y + 2)^2] = 15

Squaring both sides:

81 + (y + 2)^2 = 225

Solving for (y + 2)^2:

(y + 2)^2 = 225 - 81

(y + 2)^2 = 144

Taking the square root:

y + 2 = ±12

Solving for y:

y = -2 ± 12

This gives us two possible y-coordinates:

y = -2 + 12 = 10

y = -2 - 12 = -14

Therefore, the possible coordinates of point A are (9, 10) and (9, -14).

b. If point B were moved to (-7, -2), we follow the same process as above.

The x-coordinate of point A is 5, and the x-coordinate of point B is -7. The difference in x-coordinates is:

x-coordinate of point A - x-coordinate of point B = 5 - (-7) = 12

So, the possible x-coordinate of point A is 12.

Using the distance formula, we have:

√[(12 - (-7))^2 + (y - (-2))^2] = 15

Simplifying:

√[19^2 + (y + 2)^2] = 15

Squaring both sides:

361 + (y + 2)^2 = 225

Solving for (y + 2)^2:

(y + 2)^2 = 225 - 361

(y + 2)^2 = -136

Since the square of a real number cannot be negative, there are no real solutions for (y + 2)^2. Therefore, there are no possible coordinates for point A if point B is moved to (-7, -2).

HOPE THIS HELP :)

The answer is:

In point slope:

[tex]\rm{y-5=-3(x+1)}[/tex]

In slope intercept:

[tex]\rm{y=-3x+2}[/tex]

Work/explanation:

Given:

To find the equation of the line, I'm going to use point slope:

[tex]\sf{y-y_1=m(x-x_1)}[/tex]

Where the slope is m and the point is (x₁, y₁).

So our point-slope is:

[tex]\rm{y-5=-3(x-(-1)}[/tex]

Let's simplify.

[tex]\rm{y-5=-3(x+1)}[/tex]

That's our equation in point slope.

__________________________

We might want to write the equation in slope intercept (y = mx + b).

We can do that, too, but let's simplify first.

We take our point slope equation.

We simplify the right side.

[tex]\rm{y-5=-3x-3}[/tex]

Add 5 on both sides

[tex]\rm{y=-3x+2}[/tex]

The probability that the three randomly selected students will have blood types A, B and AB is given as follows:

0.00164 = 0.164%.

The parameters that are needed to calculate a probability are listed as follows:

Then the probability is calculated as the division of the number of desired outcomes by the number of total outcomes.

Hence the probability for this problem is calculated as follows:

41/100 x 1/10 x 1/25 = 0.00164 = 0.164%.

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Answer:

7. a. 16 units         b. 96 square units.

8. 30 units

Step-by-step explanation:

7.

a. The perimeter of a rhombus is 40, and PR is 12.

This means that all four sides are equal, and each side is 10.

Since diagonal bisect each other creating right angle.

so

In ΔPMS

PS=10

PM=1/2 of PR= 1/2*12=6

Now by using Pythagoras theorem:

PS²=MS²+PM²

10²=MS²+6²

MS²=100-36

MS²=64

MS=[tex]\sqrt{64}=8[/tex]

Therefore, diagonal QS=2*MS=2*8=16 units

b.

Since the area of a rhombus is half the product of its diagonals. The diagonals of this rhombus are QS=16 and PR=12,

So, Area=1/2*PR*QS

=1/2*12*16

=96 square units.

8.

The perimeter of a rhombus is the total length of all four sides.

Since the diagonals of a rhombus bisect each other at right angles, we can use the Pythagorean Theorem to find the length of one side of the rhombus.

let d1=9 and d2=12

[tex]s = \sqrt{(d1/2)^2 + (d2/2)^2}[/tex]

[tex]s = \sqrt{(9/2)^2 + (12/2)^2}[/tex]

s=7.5

we have

P = 4s where p is perimeter

P=4*7.5

Therefore, the perimeter of the rhombus is 30 units.

Answer:

7a)  QS = 16 units

7b)  96 square units

8)  30 units

Step-by-step explanation:

The sides lengths of a rhombus are equal.

Therefore, if the rhombus has a perimeter of 40, each side length is 10, since 40 ÷ 4 = 10.

PQ = QR = RS = SP = 10

The diagonals of a rhombus are perpendicular bisectors of each other.

Therefore, if PR is 12, then PM = 6.

Also, if QM + MS = QS, and QM = MS, then QS = 2·QM.

As the diagonals bisect each other at right angles, triangle PMQ is a right triangle, where:

Using Pythagoras Theorem to find the length of QM:

[tex]PM^2+QM^2=PQ^2[/tex]

   [tex]6^2+QM^2=10^2[/tex]

   [tex]36+QM^2=100[/tex]

           [tex]QM^2=64[/tex]

             [tex]QM=8[/tex]

As QS = 2·QM, then:

[tex]QS = 2 \cdot 8[/tex]

[tex]QS = 16[/tex]

[tex]\hrulefill[/tex]

The formula for the area of a rhombus is half the product of its diagonals.

[tex]\boxed{\begin{minipage}{5 cm}\underline{Area of a rhombus} \\\\$A=\dfrac{1}{2}pq$\\\\where:\\ \phantom{ww}$\bullet$ $p$ and $q$ are the diagonals.\\\end{minipage}}[/tex]

Therefore, given the diagonals of the rhombus are PR = 12 and QS = 16, the area of the rhombus is:

[tex]\begin{aligned}\textsf{Area}&=\dfrac{1}{2} \cdot 12 \cdot 16\\\\&=6 \cdot 16\\\\&=96\; \sf square\;units\end{aligned}[/tex]

[tex]\hrulefill[/tex]

The formula for the perimeter of a rhombus given its diagonals is:

[tex]\boxed{\begin{minipage}{5 cm}\underline{Perimeter of a rhombus} \\\\$P=2\sqrt{p^2+q^2}$\\\\where:\\ \phantom{ww}$\bullet$ $p$ and $q$ are the diagonals.\\\end{minipage}}[/tex]

If the diagonals are 9 and 12, the perimeter is:

[tex]\begin{aligned}\textsf{Perimeter}&=2\sqrt{9^2+12^2}\\&=2\sqrt{81+144}\\&=2\sqrt{225}\\&=2 \cdot 15\\&=30\end{aligned}[/tex]

Therefore, the perimeter of the rhombus is 30 units.

Step-by-step explanation:

11.16 days ok hope it helps

The y-intercept of [tex]f(x) = (1/2)^x[/tex] is option d D. (0, 1)

To find the y-intercept of a function, we need to evaluate the function when x = 0. In the given function f(x) = (1/2)^x, we substitute x = 0 and calculate the corresponding y-value.

f(0) = [tex](1/2)^0[/tex] = 1

Therefore, the y-intercept of the function is the point (0, 1). This means that when x is 0, the function has a y-value of 1.

The y-intercept represents the point where the function intersects the y-axis, which corresponds to the value of the function when x is 0. In this case, as x approaches 0, the value of [tex](1/2)^x[/tex] approaches 1. This is because any number raised to the power of 0 is equal to 1.

Option D. (0, 1) correctly represents the y-intercept of the function f(x) = [tex](1/2)^x[/tex]. The point (0, 1) indicates that when no units of the base (1/2) are multiplied together, the result is 1.

The other options (A. (0, 0), B. (1, 1/2), and C. (1, 0)) do not correctly represent the y-intercept because they either have incorrect y-values or are not on the y-axis (x ≠ 0). The y-intercept specifically refers to the point where the function crosses the y-axis, which occurs when x = 0.

The complete question is:

What is the y-intercept of[tex]f(x) = (1/2)^x[/tex]?​

A. (0, 0)

B. (1, 1/2)

C. (1, 0)

D. (0, 1)

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Answer:

8 units

Step-by-step explanation:

Area of square:

length * width

2 * 3

= 6  units

Area of triangle:

1/2 * base * height

1/2 * 2 * 2

= 2 units

Area of entire shape:

6 + 2

= 8 units

So, the area of the shape is 8 units.

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The equivalent exponential function for this problem is given as follows:

[tex]m_b = 2000(1.05)^t(1.05)^4[/tex]

An exponential function has the definition presented according to the equation as follows:

[tex]y = ab^x[/tex]

In which the parameters are given as follows:

The function for this problem is given as follows:

[tex]m_b = 2000(1.05)^{t + 4}[/tex]

Applying the addition of exponents rule, the equivalent expression is given as follows:

[tex]m_b = 2000(1.05)^t(1.05)^4[/tex]

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There are 200 consumers who do not buy any brand of tea and there are 400 consumers who like only one brand of tea.

To find the number of consumers who do not buy any brand of tea, we need to subtract the number of consumers who buy either the own nation's tea or the international tea or both from the total number of consumers.

a) Number of consumers who do not buy any brand of tea = Total number of consumers - (Number of consumers buying own nation's tea + Number of consumers buying international tea - Number of consumers buying both brands)

= 600 - (300 + 250 - 150)

= 600 - 400

= 200

Therefore, there are 200 consumers who do not buy any brand of tea.

b) To find the number of consumers who like only one brand of tea, we need to subtract the number of consumers buying both brands of tea from the sum of the number of consumers buying each brand individually.

Number of consumers who like only one brand of tea = Number of consumers buying own nation's tea + Number of consumers buying international tea - Number of consumers buying both brands

= 300 + 250 - 150

= 400

Therefore, there are 400 consumers who like only one brand of tea.

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The side b is approximately 80.02 feet in length. In a right triangle ABC with angle C equal to 90°, if angle B is 37.56° and side a is 49.94 feet, we can solve for side b using the trigonometric function sine.

First, we can label the triangle as follows:

Side a is opposite angle A,

Side b is opposite angle B,

Side c is the hypotenuse.

Let's label the triangle with the given and asked for information. Angle C is the right angle, angle B is 37.56°, side a is 49.94 feet, and side b is the side we are trying to find.

Using the sine function, we have:

sin(B) = opposite/hypotenuse

sin(37.56°) = a/b

Now we can substitute the known values:

sin(37.56°) = 49.94/b

To solve for b, we rearrange the equation:

b = 49.94 / sin(37.56°)

Using a calculator, we find:

b ≈ 80.02 feet.

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Answer:

7y+31.5

Step-by-step explanation:

your distributing the 7 to the y and the 4.5

Answer:

7y + 31.5

Step-by-step explanation:

7(y+4.5)

7y + 31.5

So, the answer is 7y + 31.5

The solutions to the equation |2x - 11| = 7 are x = 2 and x = 9. Option D

To find the numbers that satisfy the given condition, we can set up an equation based on the information provided.

Let's assume the number we're looking for is x. According to the problem, twice the number is 7 units from 11. Mathematically, we can represent this as:

|2x - 11| = 7

To find the possible values of x, we need to solve this equation. We can split it into two cases:

Case 1: 2x - 11 = 7

In this case, we have:

2x = 7 + 11

2x = 18

x = 18/2

x = 9

Case 2: -(2x - 11) = 7

In this case, we have:

-2x + 11 = 7

-2x = 7 - 11

-2x = -4

x = -4/-2

x = 2

Therefore, the solutions to the equation |2x - 11| = 7 are x = 2 and x = 9. These are the numbers that satisfy the condition where twice the number is 7 units from 11.

The correct answer is:

x = 2, 9 Option D

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The factored form of the polynomial x^3 - 12x^2 - 2x + 24 by grouping is (x - 12)(x^2 - 2).

To determine the factors of the polynomial x^3 - 12x^2 - 2x + 24 by grouping, we can follow these steps:

Step 1: Group the terms in pairs. In this case, we can pair the first two terms and the last two terms:

(x^3 - 12x^2) + (-2x + 24)

Step 2: Factor out the greatest common factor from each pair. From the first pair, we can factor out x^2, and from the second pair, we can factor out -2:

x^2(x - 12) - 2(x - 12)

Step 3: Notice that we now have a common binomial factor of (x - 12) in both terms. Factor out this common binomial factor:

(x - 12)(x^2 - 2)

Therefore, the factored form of the polynomial x^3 - 12x^2 - 2x + 24 by grouping is (x - 12)(x^2 - 2).

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Answer:

Step-by-step explanation:

The measure of the unknown angle is 143 degrees.

To find the measure of the unknown angle, we need to use the properties of straight angles. A straight angle is a line, and it measures 180 degrees.

In this case, we have a straight angle divided into a 37-degree angle and an unknown angle. So, we can set up the equation:

37° + unknown angle = 180°

To solve for the unknown angle, we need to isolate it on one side of the equation.

Subtracting 37° from both sides of the equation:

unknown angle = 180° - 37°

Simplifying:

unknown angle = 143°

As a result, the unknown angle is 143 degrees in length.

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Using the least common multiple of 19 and 18, the smallest number that could be in the group is 342

To find the smallest number of people that could be in the group, we need to find the least common multiple (LCM) of 19 and 18. The LCM is the smallest positive integer that is divisible by both 19 and 18.

The prime factorization of 19 is 19 (since 19 is a prime number), and the prime factorization of 18 is 2 * 3^2.

To find the LCM, we take the highest power of each prime factor that appears in either number:

LCM = 2 * 3² * 19

LCM = 2 * 9 * 19

LCM = 342

Therefore, the smallest number of people that could be in the group is 342.

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The product of 7/8 and 2/7, reduced to the Lowest terms, is 1/4.

To find the product of the fractions 7/8 and 2/7, we multiply the numerators together and the denominators together:

(7/8) * (2/7) = (7 * 2) / (8 * 7) = 14/56

To reduce this fraction to its lowest terms, we need to find the greatest common divisor (GCD) of the numerator and denominator. In this case, the GCD of 14 and 56 is 14. We can divide both the numerator and denominator by 14:

14/56 = (14/14) / (56/14) = 1/4

Therefore, the product of 7/8 and 2/7, reduced to the lowest terms, is 1/4.

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Total Liabilities and Stockholders' Equity: $71,750

To complete the income statement and balance sheet based on the provided data, let's use the given figures:

Income Statement:

Total revenues: $308,000

Total expenses (excluding income taxes): $185,000

Income tax expense: $33,800

To calculate the net income, we subtract the total expenses and income tax expense from the total revenues:

Net income = Total revenues - Total expenses - Income tax expense

Net income = $308,000 - $185,000 - $33,800

Net income = $89,200

The completed income statement is as follows:

Income Statement:

Total Revenues: $308,000

Total Expenses: $185,000

Income Tax Expense: $33,800

Net Income: $89,200

Balance Sheet:

Cash balance, January 31: $66,250

Receivables from customers (all considered collectible): $33,800

Merchandise inventory (by inventory count at cost): $94,100

Payables to suppliers for merchandise purchased from them (will be paid during February): $26,550

Common stock: $45,200

The balance sheet provides a snapshot of the company's financial position at a specific date, in this case, January 31. Therefore, the completed balance sheet is as follows:

Balance Sheet:

Assets:

Cash: $66,250

Accounts Receivable: $33,800

Merchandise Inventory: $94,100

Total Assets: $194,150

Liabilities and Stockholders' Equity:

Accounts Payable: $26,550

Common Stock: $45,200

Total Liabilities and Stockholders' Equity: $71,750

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a. The premium for this coverage will depend on the  individual's age, location, driving record, and the insurance company's rates.

b.   It will cost higher because the insurance company provides more coverage in the event of an accident.

c.  The difference in cost between the two coverage amounts depends on factors such as the insurance provider's rates and the person's specific circumstances.

a. Insurance coverage of 50/100/10:

The coverage limits 50/100/10 is a representation of  the minimum liability coverage required by state laws.

$50,000 = coverage for bodily injury liability per person.

$100,000  = coverage for bodily injury liability per accident.

$10,000 = coverage for property damage liability per accident.

b. Insurance coverage of 100/300/25:

The coverage limits 100/300/25 represent higher liability coverage limits:

$100,000  = coverage for bodily injury liability per person.

$300,000  = coverage for bodily injury liability per accident.

$25,000  = coverage for property damage liability per accident.

c. Difference in cost:

The difference in cost between the two coverage levels is influenced by a number of variables, including the insurance company's rates and the individual's unique situation.

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The measure of the length of segment AB in the triangle is 20 units.

The figure in the image is of two similar triangles:

From the image,

For the smaller triangle:

Leg 1 AP = 12

Leg 2 AQ = 8

For the larger triangle:

Leg 1 AC = 12 + 18 = 30

Leg 2 AB = 8 + QB

First, we determine length QB, we take the ratio of the sides of the two triangle since they similar:

Hence:

Leg 1 AP : Leg 2 AQ = Leg 1 AC : Leg 2 AB

12 : 8 = 30 : ( 8 + QB )

12/8 = 30/( 8 + QB )

Solve for QB:

12( 8 + QB ) = 8 × 30

96 + 12QB = 240

12QB = 240 - 96

12QB = 144

QB = 144/12

QB = 12

Now,

Leg 2 AB = 8 + QB

Plug in QB = 12:

Leg 2 AB = 8 + 12

Leg 2 AB = 20

Therefore, AB measure 20 units.

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Khoi invested $220 in the account that earns 5% interest and $380 in the account that earns 10% interest.

Khoi has a total of $600 invested in two accounts. The accounts earn 5% and 10% simple interest. The interest due to Khoi after one year is $49.Let x be the amount of money invested in the account that earns 5% interest and y be the amount of money invested in the account that earns 10% interest.

As per the problem statement, the sum of the two investments equals $600.

Therefore,x + y = 600orx = 600 - y

Also, the interest earned on the first account is given by,0.05xAnd, the interest earned on the second account is given by,0.10yThe total interest earned is $49.

Thus, we can write,0.05x + 0.10y = 49

Substituting the value of x from the first equation, we get,

0.05(600 - y) + 0.10y = 49

Simplifying this equation, we get,30 - 0.05y + 0.10y = 49Or,0.05y = 19

Therefore,y = 380

Plugging this value of y back into the first equation, we get,x + 380 = 600orx = 220.

Therefore, Khoi invested $220 in the account that earns 5% interest and $380 in the account that earns 10% interest.

Hence, the solution is as follows:Khoi invested $220 in the account that earns 5% interest and $380 in the account that earns 10% interest.

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The amount due from creditors is ₹17,000.

Opening Entry:The opening entry is a term used to describe the initial journal entry of a company's financial transactions in its general ledger. To begin the accounting process, an opening entry is made that records the beginning account balances for all accounts in the ledger.

The opening entry is an important component of the accounting cycle, as it establishes the starting point of all transactions and provides a basis for future analysis and reporting.

The opening entry for the above transactions is:   

Particulars                        Amount         Particulars                  Amount  Cash in hand               25,000     Capital                    86,000Cash at bank                15,000     Furniture                    20,000Machinery                    50,000     Debtors                       10,000Bills payable                  10,000     Bills payable                    13,000Bank loan                      15,000     Salary Outstanding            8,000Total                            1,50,000    Total                            1,50,000

Amount due from creditors:

Creditors refer to an individual or organization that a company owes money to for goods or services that it has received. The amount owed to creditors by the company can be calculated by subtracting the amount of bills payable from the total of all accounts payable. Creditors' amount is ₹14,000. Transactions:1. Paid 2,000 in cash as wages on installation of a machine.                                Particulars             Amount                     Particulars                Amount Wages                        2,000                        Cash                            2,0002. Sold goods to Mr. Chopra at a list price of ₹4,000. Sales subject to 10% Trade Discount and 5% Cash discount if payment is made immediately, Mr. Chopra availed of a cash discount.                                Particulars             Amount                     Particulars                AmountSales                        3,600                        Mr. Chopra                  3,600Trade discount             400                                                                                                                                       Cash                        3,420Bank charges                   1803. Supplied goods costing ₹600 to Gopi& Sons. Issued invoice at 10% above cost less 5% trade discount.                                Particulars             Amount                     Particulars                AmountGopi& Sons                     660                                Sales                            660Trade discount                    30                                                                                                                                    Cost of goods sold              6004. Paid Custom Duty 10,000 in cash on import of a new machine.                                Particulars             Amount                     Particulars                AmountCustom Duty                10,000                        Cash                           10,0005. Goods sold costing 10,000 to M/s Abbas & Sons at an invoice price 10% above cost less 10% Trade Discount.                                Particulars             Amount                     Particulars                AmountSales                         9,000                         M/s Abbas & Sons            9,000Trade discount                 1,000Cost of goods sold              10,0006. Purchased goods on credit ₹5,000.                                             Particulars                   Amount                     Particulars                AmountPurchase                      5,000                        Creditors                   5,0007. Sold goods on credit 1,000.                                                 Particulars                 Amount                     Particulars                   AmountDebtors                                                                    1,000Sales                                                                      1,0008. Started business with Cash 1,50,000 and goods worth 10,000.                                Particulars                                              Amount              Particulars                                               AmountCash                                                          1,50,000                                 Goods                                                      10,0009. Goods purchased from M/S Garg& Sons 4,000 and from Peterson 1,000.                                Particulars                                         Amount                        Particulars                                      AmountPurchase                                               5,000                               M/S Garg& Sons                                    4,000Purchase                                                     1,000                               Peterson                                                     1,00010. Goods worth 300 used by the proprietor for personal use.                                Particulars                        Amount                     Particulars                              AmountDrawings                                        300                             Goods                                                  30011. Goods uninsured worth 2,000 were destroyed by fire.                                Particulars                                               Amount                                                Particulars                                          AmountLoss by fire                                                    2,000                                              Goods                                                              2,00012. Supplied goods costing 1,000 to Gavaskar issued at 10% above cost less 5% Trade discount.                                Particulars                                            Amount                    Particulars                                              AmountGavaskar                                                        1,050                                            Sales                                                                 1,050Trade discount                                                      50Cost of goods sold                                                  1,00013. Issued a cheque in favour of M/s Garg& Sons on account of purchase of goods worth 4,000.                                Particulars                        Amount                     Particulars                              AmountM/s Garg& Sons                                                  4,000                                          Bank                                                                              4,00014. Outstanding salary at the end of the year ₹650.                                Particulars                        Amount                      Particulars                              AmountSalary                                                            650                                 Salary Outstanding                            65015. Interest charged on drawings 5% p.a.                                Particulars                                      Amount                     Particulars                                            AmountDrawings                                                               Interest on Drawings                         Total Drawings*5%/12                         Total Drawings/12                                                       0.00                                                                           0.00*5% = 3,25016. Paid to Peterson ₹990 in full settlement of 1,000.                                Particulars                                 Amount                        Particulars                                         AmountPeterson                                               990                               Discount                                                     10                                Cash                                                                1,000Total                                                1,000                                Total                                                        1,000.

Therefore, the solution is:The opening entry for the given transaction is:                        Particulars                         Amount                     Particulars                              AmountCash in hand                      25,000                       Capital                             86,000Cash at bank                      15,000                       Furniture                          20,000Machinery                        50,000                       Debtors                            10,000Bills payable                      10,000                       Bills payable                    13,000Bank loan                          15,000                       Salary Outstanding               8,000Total                                    1,50,000                  Total                                    1,50,000

Calculation of Amount due from creditors:

Creditors = Total of all accounts payable - Bills payable

Creditors = ₹30,000 - ₹13,000Creditors = ₹17,000.

Therefore, the amount due from creditors is ₹17,000.

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The y-intercept can be calculated using the formula: b = (Σy - m(Σx))/n.

Based on the given data points, we can create a scatterplot and draw a line of best fit to analyze the relationship between the input and output variables.

To create the scatterplot, we plot the input values (2, 3, 4, 5, 7, 9) on the x-axis and the corresponding output values (3, 3, 5, 4, 7, 9) on the y-axis. Each point represents a data pair.

Next, we draw a line of best fit that represents the general trend of the data. The line should pass through the middle of the data points, minimizing the distance between the line and the points. We can determine the equation of the line using linear regression.

After drawing the line of best fit, we can determine the equation by finding the slope and y-intercept. The equation of a line is typically represented as y = mx + b, where m is the slope and b is the y-intercept.

To calculate the slope, we can use the formula: m = (Σ(xy) - (Σx)(Σy)/n) / (Σ(x^2) - (Σx)^2/n), where Σ denotes summation and n is the number of data points.

The y-intercept can be calculated using the formula: b = (Σy - m(Σx))/n.

Substituting the values from the given data into the formulas, we can determine the equation of the line of best fit.

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Answer:

  x ≈ 21.8

Step-by-step explanation:

You want the side length opposite the 98° angle in a triangle with side length 10 between that angle and one marked 55°.

The law of sines can be used when angles are known and at least one side is known. The unknown angle is found by using the fact that the sum of angles is 180°.

  angle opposite 10 = 180° -98° -55° = 27°

The law of sines tells you ...

  a/sin(A) = b/sin(B)

  x/sin(98°) = 10/sin(27°)

  x = 10(sin(98°)/sin(27°)) ≈ 21.8

The value of x is about 21.8 units.

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Answer:

a

Step-by-step explanation:

the data is represented in the dot plot

Answer:

answer is 77.67

Step-by-step explanation:

explain by the x axis is 68 to y axis is 84 so the median is 77.67

Irene has 49 Books, and Alejandro has 24 books.

Let's assume that Irene has x books, and Alejandro has y books. According to the given information, we can form the following equations:

1. Irene has twice as many books as Alejandro plus 1:

  x = 2y + 1

2. The total number of books between Irene and Alejandro is 73:

  x + y = 73

We can now solve this system of equations to find the values of x and y.

Substituting the value of x from equation (1) into equation (2), we have:

(2y + 1) + y = 73

3y + 1 = 73

3y = 72

y = 24

Now, we can substitute the value of y into equation (1) to find x:

x = 2(24) + 1

x = 49

Therefore, Irene has 49 books, and Alejandro has 24 books.

To verify our solution, we can check if the sum of their books equals 73:

49 + 24 = 7

So, our solution is correct.

In conclusion, Irene has 49 books, and Alejandro has 24 books.

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Speed and distance are not independent variables.3. Height and weight: Height and weight are interrelated variables, with taller people tending to weigh more than shorter individuals.

Independence is a basic statistical concept that refers to the absence of a relationship between two variables. Two variables can be considered independent of each other if the occurrence of one does not affect the probability of the other occurring.

In contrast, dependent variables are those that have a cause-and-effect relationship. Changes in the independent variable cause changes in the dependent variable.

The following are some examples of situations with independent and not independent variables:

Independent variables1. Tossing a coin: The probability of obtaining a head or tail is 50% and is not affected by previous flips or any other factor. Therefore, this is an example of an independent event.2.

Rolling a dice: When rolling a dice, the chances of rolling any particular number are all equal, and the outcome of each roll is not influenced by the previous roll.

As a result, rolling a dice is an example of an independent event.3. Selecting a card from a deck: When selecting a card from a deck, the odds of picking a particular card are equal.

After selecting the card, it is not replaced in the deck, so the probability of selecting another card changes.Non-Independent variables1.

Studying for a test: The amount of time spent studying for a test is a dependent variable, as the more time spent studying, the higher the chances of obtaining a better grade on the test.2. Speed and distance: In general, the faster one drives, the farther one travels.

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Answer:

angle ced is a right ange

so the m angels debate =135 m angle aeb =35

so the answer is 135+35 =170

180 is a all side sim

=180-170=10 answer

Answer:

∠CED is a right angle.

∠CEA is a right angle.

m∠CEB = m∠BEA

m∠DEB = 135°