Help me pls........................

Help Me Pls........................

Answers

Answer 1

All the possible angle measures are given as follows:

25º and 35º.

What are the trigonometric ratios?

The three trigonometric ratios are the sine, the cosine and the tangent, and they are defined as follows:

Sine of angle = length of opposite side to the angle divided by the length of the hypotenuse.Cosine of angle = length of adjacent side to the angle divided by the length of the hypotenuse.Tangent of angle = length of opposite side to the angle divided by the length of the adjacent side to the angle.

On the first quadrant, we have that:

The cosine is greater than the sine for angles that are less than 45º.The cosine is equals to the sine for an angle of 45º.The cosine is less than the sine for angles that are greater than 45º.

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Related Questions

the product of three distinct positive integers is 144. if the sum of the three integers is 26, what is the sum of their squares?

Answers

We can then check the sum of each set of three integers and see which one adds up to 26. We find that the set 2, 8, 16 has a sum of 26, so these are the three distinct integers that multiply to 144.Therefore, the sum of the squares of the three integers is 324.

To solve this problem, we can start by listing all the factors of 144 and looking for three distinct integers that multiply to 144. The factors of 144 are 1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 36, 48, 72, and 144. We can eliminate any factor that is not a positive integer or is repeated, leaving us with the following possibilities:
- 1, 2, 72
- 1, 3, 48
- 1, 4, 36
- 1, 6, 24
- 2, 3, 24
- 2, 4, 18
- 2, 8, 9
- 3, 4, 12
- 3, 6, 8


To find the sum of their squares, we simply square each integer and add them together:
2² + 8² + 16² = 4 + 64 + 256 = 324

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The sum of the squares of the three distinct positive integers is 589.

Let's denote the three distinct positive integers as a, b, and c. We know the following:
1. a * b * c = 144
2. a + b + c = 26
Our goal is to find the sum of their squares, i.e.,[tex]a^2 + b^2 + c^2.[/tex]
Find the prime factorization of 144. It is [tex]2^4 * 3^2[/tex]
We need to find three distinct factors of 144 that add up to 26.

By analyzing the factors, we find that the integers are 2, 3, and 24.
Calculate the sum of their squares:
[tex]a^2 + b^2 + c^2 = 2^2 + 3^2 + 24^2 = 4 + 9 + 576 = 589[/tex].

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14. An airplane flew 2,800 miles from Los Angeles to New York. The airplane flies at approximately 500
mi/hr. How many hours did it take the plane to reach New York?

Answers

Answer:

Speed= 500ml/hr

total distance= 2800 m

total time = d/t

2800/500= 5.6hrs

Step-by-step explanation:

tarting in the 1970s, medical technology allowed babies with very low birth weight (vlbw, less than 1500 grams, or about 3.3 pounds) to survive without major handicaps. it was noticed that these children nonetheless had difficulties in school and as adults. a long study has followed 242 randomly selected vlbw babies to age 20 years, along with a control group of 233 randomly selected babies from the same population who had normal birth weight.49 (a) is this an experiment or an observational study? why? (b) at age 20, 179 of the vlbw group and 193 of the control group had graduated from high school. is the graduation rate among the vlbw group significantly lower than for the normal-birth-weight controls? give appropriate statistical evidence to justify your answer. ap3.33 a nuclear power plant

Answers

(a) This is an observational study.

The reason is that the researchers did not manipulate any variables or conditions; they simply observed and collected data on the two groups of babies (VLBW and normal birth weight) as they grew up.
(b) The p-value (0.0013) is less than the significance level (typically 0.05), we reject the null hypothesis.  

There is sufficient evidence to suggest that the graduation rate among the VLBW group is significantly lower than the normal-birth-weight controls.

To determine if the graduation rate among the VLBW group is significantly lower than the normal-birth-weight controls, we can perform a hypothesis test using the proportion of high school graduates in each group.
State the null and alternative hypotheses.
Null hypothesis (H0):

There is no significant difference in graduation rates between the VLBW group and the control group ([tex]p_VLBW = p_control).[/tex]
Alternative hypothesis (Ha):

The graduation rate among the VLBW group is significantly lower than the control group [tex](p_VLBW < p_control).[/tex].

Calculate the sample proportions and the pooled proportion.
[tex]p_VLBW[/tex] = 179/242 = 0.7397
[tex]p_control = 193/233 = 0.8283.[/tex]
[tex]p_pooled = (179 + 193) / (242 + 233) = 0.7842[/tex]
Calculate the test statistic.
[tex]z = (p_VLBW - p_control) / sqrt(p_pooled * (1 - p_pooled) * (1/242 + 1/233)) = -3.0074[/tex]
Determine the p-value.
Using a z-table or calculator, the p-value for z = -3.0074 is approximately 0.0013.

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Ten seventh graders and 15 eighth graders were selected for the elite choir ensemble.
a. Write the ratio of seventh graders to eighth graders who were selected for the
elite choir.
b. Write the ratio of seventh graders to total students who were selected for the
elite choir.
c. Write the ratio of eighth graders to total students who were selected for the elite
choir.

Answers

Answer:

Your answer should be A

Circle I and circle L are shown. Sector HIJ and sector KLM have the same area.
BLANK 1: Which formula should be used to solve this problem?
BLANK 2: What is the area of sector HIJ? Use 3.14 for pi.
BLANK 3: What is the measure of angle KLM?

Answers

1. Formula for the area of a sector of a circle, which is  A = (θ/360)π[tex]r^2[/tex] 2. The area of sector HIJ is 2.51 square units. 3. The measure of angle KLM is approximately 0.29 degrees

What is circle?

A circle is a geometric shape consisting of all the points in a plane that are a fixed distance (called the radius) away from a given point (called the center).

According to given information:

BLANK 1: To solve this problem, we can use the formula for the area of a sector of a circle, which is A = (θ/360)π[tex]r^2[/tex], where θ is the central angle of the sector, r is the radius of the circle, and π is pi (approximately 3.14).

BLANK 2: To find the area of sector HIJ, we need to know the radius of circle I and the measure of angle HIJ. From the given information, we know that circle I has a radius of 8, and angle HIJ is 45 degrees. Therefore, the area of sector HIJ is:

A = (45/360) x 3.14 x [tex]8^2[/tex]

A = 3.14 x 8 x (45/360)

A = 3.14 x 8 x 0.125

A = 2.51 square units (rounded to two decimal places)

Therefore, the area of sector HIJ is 2.51 square units.

BLANK 3: We know that sector KLM has the same area as sector HIJ, and circle L has a radius of 10. Therefore, we can use the formula for the area of a sector of a circle again to find the measure of angle KLM. Let x be the measure of angle KLM in degrees. Then:

A = (x/360) x 3.14 x [tex]10^2[/tex] = 2.51

Simplifying this equation gives:

(x/360) = 2.51/(3.14 x [tex]10^2[/tex])

(x/360) = 0.0008

x = 360 x 0.0008

x = 0.288

Therefore, the measure of angle KLM is approximately 0.29 degrees (rounded to two decimal places).

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The radius of a semicircle is 8.4 millimeters. What is the semicircle's diameter?

Answers

Answer:

Step-by-step explanation:

8.4 x 2 = 16.8

25 Points Please Help!!!

Denae is designing bouquets for the tables at her restaurant. She wants at least twice as many daisies as daffodils in each bouquet. Daisies are $0. 50 each and daffodils are $0. 75 each. Denae has a total of $50 to spend. Denae needs both daisies and daffodils in each bouquet.


Let x represent the number of daisies. Let y represent the number of daffodils.


Which inequalities are among the constraints for this situation?


Select each correct answer.

y > 0


y≤2xy≤2x


x≤2yx≤2y


0. 5x+0. 75y≤500. 5x+0. 75y≤50


x≥0. 5

Answers

The correct answer from the following given to find the details regarding the bouquet is:

y > 0

x ≥ 2y

0.5x + 0.75y ≤ 50

From the problem, we know that Denae wants at least twice as many daisies as daffodils in each bouquet, and she has a total of $50 to spend. This means that the number of daisies (x) and daffodils (y) must satisfy certain constraints.

The correct inequality among the constraints for this situation are:

y > 0, since there must be at least one daffodil in each bouquet.

x ≥ 2y, since Denae wants at least twice as many daisies as daffodils in each bouquet.

0.5x + 0.75y ≤ 50, since Denae has a total of $50 to spend and daisies cost $0.50 each and daffodils cost $0.75 each.

Therefore, the correct answers are:

y > 0

x ≥ 2y

0.5x + 0.75y ≤ 50

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Eight of 10 students in the library completed the reading assignment.
a. Write the ratio of students who completed the reading assignment to total students.
b. Write the ratio of students who did not complete the reading assignment to total students.
c. Write the ratio of students in the library who completed the reading assignment to those who did
not complete the reading assignment.

Answers

a. 8:10
b. 2:10
c. 8:2

In a multiple regression analysis involving 15 independent variables and 200 observations, SST = 800 and SSE = 240. The coefficient of determination is equal to what value?

Answers

the coefficient of determination is 0.7, indicating that the independent variables explain 70% of the variation in the dependent variable.

The coefficient of determination, also known as R-squared, is a measure of how well the independent variables explain the variation in the dependent variable. It is calculated as the ratio of the explained variation to the total variation.

In this case, SST (total sum of squares) is 800 and SSE (error sum of squares) is 240. Therefore, the explained sum of squares (SSE) is 800 - 240 = 560.

The coefficient of determination is then calculated as:

R-squared = explained variation / total variation

R-squared = 560 / 800

R-squared = 0.7

Therefore, the coefficient of determination is 0.7, indicating that the independent variables explain 70% of the variation in the dependent variable.

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The coefficient of determination (R²) in this multiple regression analysis involving 15 independent variables and 200 observations is equal to 0.7.

To find the coefficient of determination, we'll use the following terms:

SST (total sum of squares), SSE (sum of squared errors), and

the formula R² = 1 - (SSE / SST).

the values for SST (800) and SSE (240).

Using the formula, we can calculate the coefficient of determination (R²) as follows:

R² = 1 - (SSE / SST)

R² = 1 - (240 / 800)

R² = 1 - 0.3

R² = 0.7

The coefficient of determination (R²) in this multiple regression analysis involving 15 independent variables and 200 observations is equal to 0.7.

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If x and y are supplementary angles, then y is acute
tell whether the statement is always, sometimes, or never true

Answers

The statement is sometimes true.

Supplementary angles are two angles whose measures add up to 180 degrees. So if x and y are supplementary angles, then:

x + y = 180

If x is an acute angle (less than 90 degrees), then y must be an obtuse angle (greater than 90 degrees) in order for their sum to be 180 degrees. In this case, y is not acute.

However, if x is a right angle (exactly 90 degrees) or an obtuse angle (greater than 90 degrees), then y must be an acute angle (less than 90 degrees) in order for their sum to be 180 degrees. In this case, y is indeed acute.

Therefore, the statement "if x and y are supplementary angles, then y is acute" is sometimes true, depending on the measure of angle x.

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Need the answer to question 15

Answers

An equation in slope-intercept form for the perpendicular bisector of the segment with endpoints H (-3, 2) and K (7, -5) is y = -0.7x - 0.1.

How to determine an equation of this line?

In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical equation (formula):

y - y₁ = m(x - x₁)

Where:

m represent the slope.x and y represent the points.

First of all, we would determine the slope of this line;

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

Slope (m) = (-5 - 2)/(7 + 3)

Slope (m) = -7/10

Slope (m) = -0.7.

At data point (-3, 2) and a slope of -7/10, a linear equation in slope-intercept form for this line can be calculated by using the point-slope form as follows:

y - y₁ = m(x - x₁)

y - 2 = -7/10(x + 3)

y - 2 = -7x/10 - 21/10

y = -7x/10 - 21/10 + 2

y = -0.7x - 0.1

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SOMEONE HELP!!!!!!!!!!!!

Answers

the answer your looking for is
150

Answer: It's none of these because the answer is 30.

the life of light bulbs is distributed normally. the variance of the lifetime is 625 and the mean lifetime of a bulb is 530 hours. find the probability of a bulb lasting for between 547 and 580 hours. round your answer to four decimal places.

Answers

The probability of a bulb lasting between 547 and 580 hours is approximately 0.0392

To solve this problem, we first need to standardize the values using the formula

z = (x - μ) / σ

where

x is the value we want to find the probability for,

μ is the mean, and

σ is the standard deviation.

In this case, we want to find the probability that a bulb will last between 547 and 580 hours, so we need to find the z-scores for these values.

z1 = (547 - 530) / sqrt(625) = 1.72

z2 = (580 - 530) / sqrt(625) = 2.8

Next, we use a standard normal distribution table or calculator to find the probabilities for each z-score. For example, using a calculator, we can find that

P(z1 < Z < z2) = P(1.72 < Z < 2.8) ≈ 0.0392

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Find the LCM of 24b³ & 12ab²
i need answer asap ​

Answers

The answer of this question is above in the picture

LCM of 12 and 24 is 24
And of b3 Amd b2 it US b3
Answer is 24ab3

The scale factor of the larger of two similar triangular prisms is 6. The surface area of the smaller prism is 36 ft2. Identify the surface area, rounded to the nearest tenth, of the larger prism

Answers

The surface area, rounded to the nearest tenth, of the larger prism is 1296 square feet.

If the scale factor of the larger prism to the smaller prism is 6, then the corresponding ratio of their surface areas is 6² or 36:1.

Scale factor is the ratio of the lengths of corresponding sides of two similar figures. It is used to determine how much larger or smaller one figure is compared to another, and it is often expressed as a fraction or a decimal.

We know that the surface area of the smaller prism is 36 ft², so we can set up the equation

x = 36 × 36

where x is the surface area of the larger prism.

Simplifying the equation

x = 1296 square feet

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Steven has a bag of 20 pieces of candy. Five are bubble gum, 8 are chocolates, 5 are fruit chews, and the rest are peppermints. If he randomly draws one piece of candy what is the probability that it will be chocolate?
A. 0. 4
B. 0. 45
C. 0. 2
D. 0. 8

Answers

The opportunity of drawing a chocolate from the bag is 0.4, therefore, the answer is A. 0.4.

Steven has a bag of 20 pieces of candy, out of which 8 are chocolates. If he draws one piece of sweet at random, the opportunity of it being a chocolate may be calculated through dividing the wide variety of chocolates in the bag with the aid of the full quantity of chocolates inside the bag. In this situation, there are 8 chocolates out of 20 total candies.

The formulation to calculate the opportunity is:

P(chocolate) = number of candies / total range of candies

Substituting the given values, we get:

P(chocolate) = 8 / 20

Simplifying this fraction, we get:

P(chocolate) = 0.4

Consequently, the opportunity of drawing a chocolate from the bag is 0.4  

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If you watch from ground level, a child riding on a merry-go-round will seem to be undergoing simple harmonic motion from side to side. Assume the merry-go-round is 10.6 feet across and the child completes 8 rotations in 120 seconds. Write a sine function that describes d, the child's apparent distance from the center of the merry-go-round, as a function of time t.

Answers

The sine function that describes the child's apparent distance from the center of the merry-go-round is d(t) = 5.3 sin(2π/15 * t)

How to write a sine function that describes the child's apparent distance?

To write a sine function that describes the child's apparent distance from the center of the merry-go-round as a function of time t, we can start by finding the amplitude, period, and phase shift of the motion.

Amplitude:

The amplitude of the motion is half the diameter of the merry-go-round, which is 10.6/2 = 5.3 feet. This is because the child moves back and forth across the diameter of the merry-go-round.

Period:

The period of the motion is the time it takes for the child to complete one full cycle of back-and-forth motion, which is equal to the time it takes for the merry-go-round to complete one full rotation.

From the given information, the child completes 8 rotations in 120 seconds, so the period is T = 120/8 = 15 seconds.

Phase shift:

The phase shift of the motion is the amount of time by which the sine function is shifted horizontally (to the right or left).

In this case, the child starts at one end of the diameter and moves to the other end, so the sine function starts at its maximum value when t = 0. Thus, the phase shift is 0.

With these values, we can write the sine function that describes the child's apparent distance from the center of the merry-go-round as:

d(t) = 5.3 sin(2π/15 * t)

where d is the child's distance from the center of the merry-go-round in feet, and t is the time in seconds. The factor 2π/15 is the angular frequency of the motion, which is equal to 2π/T.

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Keiko paid $15. 84 for a 7. 48 - kg bag of dog food. A few weeks later, she paid $16. 58 for a 7. 94 - kg bag at a different store. Find the unit price for each bag

Answers

The unit price for the first bag is $2.12 per kilogram and the unit price for the second bag is $2.09 per kilogram.

To find the unit price, we need to divide the total cost by the weight of the bag.

For the first bag

Unit price = Total cost / Weight

Unit price = $15.84 / 7.48 kg

Unit price = $2.12/kg

Therefore, the unit price for the first bag is $2.12 per kilogram.

For the second bag

Unit price = Total cost / Weight

Substitute the values in the equation

Unit price = $16.58 / 7.94 kg

Unit price = $2.09/kg

Therefore, the unit price for the second bag is $2.09 per kilogram.

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Helppp
Please
I need help

Answers

According to the information, the surface area of the first prism is 795 cm², sencond prism is 843 in², and the cylinder is 3775.87 mm²

How to find the surface area of two triangular prims?

To find the surface area of two triangular prisms, we need to add the surface area of each prism. We can use the formula we found in the previous question to calculate the surface area of each triangular prism:

Surface area of first triangular prism = 2(0.5 x base x height) + perimeter x height

where base is the width of the triangular face, height is the height of the triangular face, and perimeter is the sum of the lengths of the three sides of the triangular face.

In this case, the first triangular face has a base of 9 cm, a height of 16 cm, and a perimeter of (9+15+12)=36 cm. Therefore, the area of each triangular face is:

0.5 x 9 cm x 16 cm = 72 cm²

The rectangular faces have dimensions of 9 cm x 15 cm, 15 cm x 16 cm, and 9 cm x 16 cm. Therefore, the area of each rectangular face is:

9 cm x 15 cm = 135 cm²

15 cm x 16 cm = 240 cm²

9 cm x 16 cm = 144 cm²

The total surface area of the first triangular prism is:

2(72 cm²) + (135 cm² + 240 cm² + 144 cm²) = 795 cm²

Similarly, for the second triangular prism, we have:

Surface area of second triangular prism = 2(0.5 x base x height) + perimeter x height

where base is the width of the triangular face, height is the height of the triangular face, and perimeter is the sum of the lengths of the three sides of the triangular face.

In this case, the second triangular face has a base of 8 in, a height of 15 in, and a perimeter of (8+15+20)=43 in. Therefore, the area of each triangular face is:

0.5 x 8 in x 15 in = 60 in²

The rectangular faces have dimensions of 8 in x 21 in, 15 in x 21 in, and 8 in x 15 in. Therefore, the area of each rectangular face is:

8 in x 21 in = 168 in²

15 in x 21 in = 315 in²

8 in x 15 in = 120 in²

The total surface area of the second triangular prism is:

2(60 in²) + (168 in² + 315 in² + 120 in²) = 843 in²

Therefore, the surface area of two triangular prisms is:

795 cm² + 843 in² = 795 cm² + (843 in² x 6.452 cm²/in²) ≈ 5508 cm²

For the cylinder, we can use the formula we found in the previous question to calculate the surface area:

Surface area of cylinder = 2πr² + 2πrh

where r is the radius of the circular face, h is the height of the cylinder.

In this case, the radius is 14 mm and the height is 29 mm. Therefore, the surface area of the cylinder is:

2π(14 mm)² + 2π(14 mm)(29 mm) = 2π(14 mm)(43 mm) ≈ 3775.87 mm²

Therefore, the surface area of two triangular prisms and a cylinder is approximately:

5508 cm² + 3775.87 mm² = 5508 cm² + (3775.87 mm² x 0.01 m²/mm²) ≈ 5885.47 cm²

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The circumference of a circle is 176 mm. Find the diameter, radius and area. Show your working.

Answers

Step-by-step explanation:

Given :

Circumstance = 176 mm

We know that,

C = 2πr

r = C / 2π

r = 176 × 7/ 22 × 2

r = 1232/44

r = 28 mm

Now,

d = 2r = 2(28) = 56 mm

Now,

A = π r²

A = 22/7 × (28)²

A = 22/7 × 784

A = 17248/7

A = 2464 mm²

Answer:

Step-by-step explanation:

Circumference, C = 2πr

given: c=176mm, π=[tex]\frac{22}{7}[/tex]

c = 2 x [tex]\frac{22}{7}[/tex] x r

176 = [tex]\frac{44}{7}[/tex]r

r = [tex]\frac{7 *176}{44}[/tex]

r = 28

Area, A = π[tex]r^{2}[/tex]

A = [tex]\frac{22}{7}[/tex] x [tex]28^{2}[/tex]

A = 2464[tex]mm^{2}[/tex]

The function f(x) = -4(3)-4+3 represents the value of a savings account in dollars, x months after the individual opened
the account.
In how many months will be account have a balance of $0?
O 0.26 months
O 2.46 months
O 3.74 months
O 4.26 months
NEED HELP ASP

Answers

Answer: A

Explanation:

in the previous simulation, when we were building a sampling distribution, what does each dot represent in the graph?

Answers

The central limit theorem tells us that under certain conditions.

The sampling distribution of the means will approximate a normal distribution.

Regardless of the shape of the population distribution.

Building a sampling distribution through simulation, each dot in the graph represents a simulated sample.

Calculated from a sample of a fixed size (usually denoted as "n") drawn randomly from a population.

To create a sampling distribution.

Multiple simulated samples of the same size are drawn randomly from the population.

The mean of each sample is calculated.

Each dot on the graph represents the mean of one of these simulated samples.

By plotting the distribution of these sample means on a graph.

Visualize the behavior of the sample means and infer about the population mean.

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evaluate the expression when x=2 and y= 2/3 3(x^2+2)-3y

Answers

Answer:

53/3

Step-by-step explanation:

3(x^2+2)-3y                   Evaluate when x = 2 & y = 2/3

3(2² + 2) - 3(2/3)

3(4 + 2) - 3(2/3)

3(6) - 3(2/3)

18 - 3(2/3)

18 - 6/18

18 - 1/3

54/3 - 1/3

53/3

So, the answer is 53/3

A brick has a mass of 2,022.75 grams and a volume of 1,064.5 cubic centimeters.
What is the density of the brick, in grams per cubic centimeter (³) ²¹
g
cm
3
Round your answer to the nearest tenth.

Answers

Answer:

To find the density of the brick, we need to divide its mass by its volume:

density = mass / volume

Plugging in the values given in the problem, we get:

density = 2,022.75 g / 1,064.5 cm³

Simplifying the division, we get:

density = 1.8996 g/cm³

Rounding to the nearest tenth, we get:

density ≈ 1.9 g/cm³

Therefore, the density of the brick is approximately 1.9 grams per cubic centimeter (g/cm³).

a card is selected from a deck of 52 cards. what is the probability that it is a queen? what are the odds in favor

Answers

Step-by-step explanation:

There are FOUR queens in a deck of 52 cards

4/52 chance of selecting a queen =  1/13  chance  = .07692 chance

PLEASE HELP ME ASAP! IT'S DUE TODAY

Answers

The constant ratio in each representation include the following: r = 3.

How to calculate the nth term of a geometric sequence?

In Mathematics, the nth term of a geometric sequence can be calculated by using this mathematical expression:

aₙ = a₁rⁿ⁻¹

Where:

aₙ represents the nth term of a geometric sequence.r represents the common ratio.a₁ represents the first term of a geometric sequence.

Next, we would determine the common ratio in each representation as follows;

Common ratio, r = a₂/a₁

Common ratio, r = -6/-2

Common ratio, r = 3.

Based on comparison with the exponential equation, the common ratio is given by;

Common ratio, r = 3.

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a random sample of 104 marketing vice presidents from large fortune 500 corporations was questioned on future developments in the business environment. of those sample members, 50 indicated some measurement of agreement with this statement: firms will concentrate their efforts more on cash flow than on profits. what is the lowest level of significance at which the null hypothesis, which states that the true proportion of all such executives who would agree with this statement is one-half, can be rejected against a two-sided alternative?

Answers

|z| = 0.669 < 1.96, we fail to reject the null hypothesis at any significance level up to α = 0.05.

In other words, we do not have enough evidence to conclude that the true proportion of executives who would agree with the statement is different from one-half.

The null hypothesis that the true proportion of all such executives.

Agree with this statement is one-half, we can use a two-sample z-test for proportions.

Let p be the true proportion of executives who would agree with the statement and let. [tex]\^p[/tex] be the sample proportion.

Under the null hypothesis, the test statistic z is given by:

[tex]z = (\^p - 0.5) / \sqrt(0.5 \times 0.5 / n),[/tex]

n is the sample size (104 in this case).

This test statistic follows a standard normal distribution under the null hypothesis.

To reject the null hypothesis at a significance level α, we need to find the critical values.[tex]z\alpha/2[/tex] and [tex]-z\alpha/2[/tex] such that [tex]P(Z > z\alpha/2) = \alpha/2[/tex] and[tex]P(Z < -z\alpha/2) = \alpha/2[/tex], where Z is a standard normal random variable.

The lowest level of significance at which the null hypothesis can be rejected against a two-sided alternative.

The smallest α such that [tex]|z| > z\alpha/2.[/tex]

The two-sided alternative implies that we are interested in deviations from the null value of 0.5 in either direction.

Using the given information, we have:

[tex]\^p = 50/104 = 0.4808,[/tex]

n = 104.

Substituting these values into the formula for z, we get:

[tex]z = (0.4808 - 0.5) / \sqrt(0.5 \times 0.5 / 104) = -0.669.[/tex]

The critical value [tex]z\alpha/2[/tex], we look up the corresponding value in the standard normal distribution table.

[tex]z\alpha/2[/tex] such that [tex]P(Z > z\alpha/2) = \alpha/2[/tex], or equivalently, [tex]P(Z < -z\alpha/2) = \alpha/2[/tex]. Since the standard normal distribution is symmetric, we can look up the value of zα/2 that satisfies. [tex]P(Z > z\alpha/2) = \alpha/2[/tex], and then take its absolute value to find. [tex]-z\alpha/2.[/tex]

Using a standard normal distribution table, we find that z0.025 = 1.96 (rounded to two decimal places).

The critical values for rejecting the null hypothesis at a significance level α are:

[tex]z\alpha/2[/tex] = ±1.96.

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You ask 60 randomly chosen students whether they support a later starting time for school. The table shows the results. Estimate the probability that at least two out of four randomly chosen students do not support a later starting time. Round your answer to the nearest hundredth.

Yes No
42 18

Answers

Answer: The estimated probability is 0.76.

Step-by-step explanation:

Five times a number x minus one is greater than or equal to negative eleven.

Answers

The solution to the inequality is x ≥ -2. This means that any number greater than or equal to -2 will make the inequality true.

What is inequality?

In mathematics, inequality is a relationship or a statement that compares two numbers or expressions that are not equal. It is expressed by symbols such as, >,,, or, which indicate which value is lower, greater, or simply different.

The given inequality can be written as:

5x - 1 ≥ -11

To solve for x, we can isolate the variable by adding 1 to both sides of the inequality:

5x ≥ -11 + 1

5x ≥ -10

Finally, we can solve for x by dividing both sides of the inequality by 5:

x ≥ -10/5

x ≥ -2

Therefore, the solution to the inequality is x ≥ -2. This means that any number greater than or equal to -2 will make the inequality true.

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write an equation of the parabola that passes through the point (-5,2) and has vertex (7,-2)

Answers

[tex]~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{a~is~negative}{op ens~\cap}\qquad \stackrel{a~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\begin{cases} h=7\\ k=-2\\ \end{cases}\implies y=a(~~x-7~~)^2 + (-2)\hspace{4em}\textit{we also know that} \begin{cases} x=-5\\ y=2 \end{cases} \\\\\\ 2=a(-5-7)^2-2\implies 4=a(-12)^2\implies 4=144a\implies \cfrac{4}{144}=a \\\\\\ \cfrac{1}{36}=a\hspace{9em} {\Large \begin{array}{llll} y=\cfrac{1}{36}(x-7)^2-2 \end{array}}[/tex]

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