help mee please!!


thank you

Help Mee Please!!thank You

Answers

Answer 1
answer: 10 ; 10 ; 2658

Related Questions

If the size of an object is 5.0 cm, and the size of the image formed by a lens is 15.0 cm, what is the magnification of the system?

Answers

The magnification of the system with an object distance of 5 cm and an image distance of 15 cm is 0.33.

A lens is a transmissive optical tool that employs refraction to focus or disperse a light beam.

In optics, magnification refers to the image's size in relation to the item that produced it. The ratio of the image length to the object length, as measured in planes perpendicular to the optical axis, is referred to as linear magnification, also known as lateral or transverse magnification.

The size of an object is u = 5 cm

The size of the image formed by the lens is v = 15 cm

Then the magnification M will be:

Magnification = Image distance/ Object distance

M = v/u

M = 5/15

M = 1/3

M = 0.33

Hence, the magnification of the system is 0.33.

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picture to the problem sented

Answers

Answer:

Explanation:

For the matrix equation

[tex]2X+A=B[/tex]

We first subtract A from both sides to get

[tex]2X=B-A_{}[/tex]

Now,

[tex]B-A=\begin{bmatrix}{-7} & {-8} & {} \\ {-2} & {6} & {} \\ {4} & {4} & {}\end{bmatrix}-\begin{bmatrix}{-3} & {0} & {} \\ {0} & {3} & {} \\ {-6} & {6} & {}\end{bmatrix}[/tex][tex]B-A=\begin{bmatrix}{-7--3} & {-8-0} & {\square} \\ {-2-0} & {6-3} & {\square} \\ {4--6} & {4-6} & {\square}\end{bmatrix}[/tex][tex]B-A=\begin{bmatrix}{-10} & {-8} & {} \\ {-2} & {-3} & {} \\ {10} & {-2} & {}\end{bmatrix}[/tex]

Hence, we have

[tex]2X=\begin{bmatrix}{-10} & {-8} & {} \\ {-2} & {-3} & {} \\ {10} & {-2} & {}\end{bmatrix}[/tex]

Dividing both sides by 2 gives

[tex]\begin{gathered} X=\frac{1}{2}\cdot\begin{bmatrix}{-10} & {-8} & {} \\ {-2} & {-3} & {} \\ {10} & {-2} & {}\end{bmatrix} \\ \end{gathered}[/tex][tex]X=\begin{bmatrix}{-5} & {-4} & {} \\ {-1} & {-\frac{3}{2}} & {} \\ {5} & {-1} & {}\end{bmatrix}[/tex]

which is our answer!

Question 6 of 10Which choice is equivalent to the fraction below when x is an appropriatevalue? Hint: Rationalize the denominator and simplify.Please help

Answers

[tex]undefined[/tex]

Which expression does not belong? 2^3 8 3^2 2^2*2^1

Answers

[tex]\begin{gathered} 2^3=8 \\ 2^2\cdot2^1=4\cdot2=8 \\ All\text{ the expressions are equal to 8, but} \\ 3^2=9\ne8 \\ thus \\ 3^2\text{ does not belong } \end{gathered}[/tex]

George is putting trim around his rectangular deck, including the gate. He will need 50 feet of trim to do the entire deck. If the deck is 15 feet long, how wide is the deck?OA. 8 feetOB. 25 feetOC. 10 feetOD. 20 feet

Answers

George is putting trim around the rectangular deck, this means that he is surrounding the deck's perimeter with trim.

You know that he needs 50ft of trim to do the entire deck, this value represents the perimeter of the rectangular deck, and the length of the deck is 15ft.

Knowing the perimeter (P) and the length (l) of the rectangular deck, you can calculate the width (w) of the deck.

The formula for the perimeter of the rectangle is:

[tex]P=2l+2w[/tex]

Write the formula for w:

[tex]\begin{gathered} P=2l+2w \\ P-2l=2l-2l+2w \\ P-2l=2w \\ \frac{P-2l}{2}=\frac{2w}{2} \\ w=\frac{P-2l}{2} \end{gathered}[/tex]

Use P=50ft and l=15ft to calculate the width:

[tex]\begin{gathered} w=\frac{50-(2*15)}{2} \\ w=\frac{50-30}{2} \\ w=\frac{20}{2} \\ w=10ft \end{gathered}[/tex]

The width of the deck is 10ft (option C)

What is the function g(x) that What is the results when translating the function f(x)=x to the left 12 units and reflecting it over the x-axis?

g(x) =

Answers

The function g(x) that results when translating the function f(x)=x to the left 12 units and reflecting it over the x-axis is g(x) = -|x + 12|

Translating to left ≡ f(x + 12)

Translation up 12 units means g(x)=f(x)+5g(x)=f(x)+5. Reflecting this across the x-axis means g(x)=-(f(x)+12)g(x)=−(f(x)+12)

-(x+12)=-x-12

f(x + 12) = |x + 12|

Reflection of a function f(x) about the x - axis is keeping the x value same but negating the y values

Reflected f'(x) = -y = -f(x)

Taken together

g(x) = -(|x + 12|)

The function g(x) that results when translating the function f(x)=x to the left 12 units and reflecting it over the x-axis is g(x) = -|x + 12|

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Drag the red and blue dots along the x-axis and y-axis to graph 3x-5y=20

Answers

Answer:

what red and blue dots?

Step-by-step explanation:

x +3 +7 = 2x -10 -x how many solutions does it have

Answers

Answer:

no solution

Step-by-step explanation:

x + 3 + 7 = 2x + 10 - x ( simplify both sides )

x + 10 = x - 10 ( subtract 10 from both sides )

x = x - 20 ( subtract x from both sides )

0 = - 20 ← not possible

this indicates the equation has no solution

help me please


thank you

Answers

The domain is (2,4,6,8,10,12,14) and range is (8,6,4,2,0,2,4).

What is domain and range?

The domain of a function refers to the set of values that we are allowed to enter into our function.

The set of values that a function can accept as input is known as its range. Once we enter an x value, the function returns this list of values , the y values are these.

The range and domain must be understood to be all the values that the variable y can represent, respectively, and the x values.

Since the ordered pairs have the form (x,y), we can determine the values of x and y.

The x and y values of function are:

F(x,y) = (2,8), (4,6), (6,4), (8,2), (10,0), (12,2), (14,4)

Domain (x) = (2,4,6,8,10,12,14)

Range (y) = (8,6,4,2,0,2,4)

.

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Solve the system using the elimination.

Answers

On solving the system of equation using elimination method , the value of x is 1 and value of y is 3 .

in the question ,

the two equations are given as

3x+y=6   ...(i)

and

-8x+2y= -2     ...(ii)

In elimination method, the equation is multiplied by some constant and then add/subtract the equations to eliminate any variable x or y.

multiplying equation(i) by 2 we get

6x+2y=12      ....(iii)

subtracting , the equation (ii) from equation (iii) , we get

(6x+2y) - (-8x+2y) = 12-(-2)

6x+2y+8x-2y = 12+2

14x = 14

x = 1

We eliminate 'x' from equation (ii) by replacing the value of 'x' with 1 ,

we get

-8x+2y= -2  

-8(1)+2y= -2

-8 + 2y = -2

2y = -2 + 8

2y = 6

y = 3

Therefore , On solving the system of equation using elimination method , the value of x is 1 and value of y is 3 .

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Nixon will pay for his new car in 36 monthly payments. if his car loan is for 19,061, THEN HOW MUCH will pay each month

Answers

19061 divide it with 36 months to get how much Nixon must pay for each month.
Just divide 19,061 with the amount of months which is 36
Answer is 529.4 every month

In the circle below, G is the center, LM Is a diameter, HF intersects the circle at M, and JN intersects the circle at K and L. Useblanks.

Answers

HF, JN

1) Examining this question, we can state that a tangent line is the one that "touches" the circle in one single point.

So, in this diagram we can state that the tangent line is HF

2) On the other hand, a secant line crosses the circle in two points at least. So the one that fits in this definition is the line defined by points JN

3) In Euclidian Geometry, a chord is a line segment that connects two points in a circle or curve. Examning the diagram again, we can state that KM is a chord.

write an expression
1. Richie makes $40 per hour doing web design and $20 per hour doing logo design.

Answers

Answer:

Step-by-step explanation:

40x+20y x is for the amount of hours he spends on web design and y for 20 obviously

Find the area of the triangle I’ll send a picture of the triangle

Answers

Ok, so

We want to find the area of the following triangle:

Remember that the area of a trangle is given by the following equation:

[tex]A=\frac{bh}{2}[/tex]

Where b is the base of the triangle and h is its height.

If we replace our values:

[tex]A=\frac{(11)(2)}{2}=11[/tex]

Therefore, the area is equal to 11 square units.

which expression is equivalent to 3(x-y)

Answers

MULTIPLY EVERY TERM IN THE BRACKETS BY 3

[tex] = 3(x) + 3( - y) \\ = 3x - 3y[/tex]

ATTACHED IS THE SOLUTION

in a class of students the following data table summarizes how many students pass a test and completed the homework due the day of the test what is the possibility that a student chosen randomly from the class failed the test

Answers

From the table,

Total number of students that failed the test = 2 + 7 = 9

The total number of students that participated = 10 + 3 + 2 + 7 = 22

The possibility that a student chosen randomly from the class failed the test = ​Total number of students that failed the test divided by the total number of students that participated

= 9/22

Hence, the possibility that a student chosen randomly from the class failed the test is 9/22

numbe

The resting heart rates for a sample of 15 students are recorded in the following stemplot.

A stemplot titled heart rates has values 55, 63, 65, 69, 69, 69, 69, 70, 71, 73, 73, 74, 75, 76, 77.

What is the mean resting heart rate for this sample?

66.0 beats per minute
69.0 beats per minute
69.9 beats per minute
70.0 beats per minute

Answers

Answer:

C) 69.9 beats per minute

Step-by-step explanation:

Mean is the average.

It is calculated as:

mean = sum of samples/ number of samples

Find it using the equation above:

(55 + 63 + 65 + 69*4 + 70 + 71 + 73*2 + 74 + 75 + 76 + 77)/15 = 1048/15 = 69.866 ≈ 69.9

Correct choice is C

Answer:

c

Step-by-step explanation:

Which type of wave does the illustration depict?

Answers

Where is the picture?

Find the coordinates of the vertices of each figure after the given transformation REFLECTION ACROSS y=-x

Answers

The coordinates of the vertices after the reflection are V'(-3,2), U'(0,-2), W'(-1,3) and T'(1,2) .

A reflection in mathematics is a mapping from a Cartesian coordinates to itself which is an isometry with such a set of fixed points known as the hyperplane, also known as the axis or plane of reflection.

The mirror image of a figure in the axis or plane of reflections is the image produced by a reflection. For instance, the minuscule Latin letter p would appear like the letter q when reflected with regard to a vertical axis. It would appear like b when reflected on a horizontal axis. Every object goes back to its original place and every geometric object is returned to its initial condition when a reflection is applied twice consecutively.

We know that when a figure is reflected along the line y = -x then the coordinates change their places and they are negated.

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what is the answer use the slope intercept form to graph the equation y=7/4x-1

Answers

The equation y = 7/4x - 1​ is in slope-intercept form, with a slope of 7/4 and a y-intercept of -1.

To graph it, you need to locate the point (0, -1) - the y-intercept -, and then use the slope to find another point. From (0, -1) you have to move 4 units to the right, and 7 units up, reaching the point (4, 6). Then, you have to draw the line that passes through theses points, as follows:

Help mee pleasee!!




thank you <3

Answers

Answer:

never to leave the unknown shackspeare

Step-by-step explanation:

it never leaves

or never stays

and never comes back

line g has an equation of y=-10x-2. Line h, which is perpendicular to line g, includes the point (4,1). what is the equation of line h?

Answers

The Slope-Intercept form of the equation of a line is:

[tex]y=mx+b[/tex]

Where "m" is the slope of the line and "b" is the y-intercept.

Given the equation of the line "g":

[tex]y=-10x-2[/tex]

You can identify that:

[tex]\begin{gathered} m_g=-10 \\ b_g=-2 \end{gathered}[/tex]

By definition the slopes of perpendicular lines are opposite reciprocals. Then, the slope of the line "h" is:

[tex]m_h=\frac{1}{10}[/tex]

Knowing a point on the line "h" and its slope, you can substitute them into the equation

[tex]y=m_hx+b_h[/tex]

And solve for the y-intercept:

[tex]\begin{gathered} 1=\frac{1}{10}(4)+b_h \\ \\ 1=\frac{2}{5}+b_h \\ \\ b_h=\frac{3}{5} \end{gathered}[/tex]

Then, the equation of the line "h" is:

[tex]y=\frac{1}{10}x+\frac{3}{5}[/tex]

What is the word for added and subtracted parts of an expression

Answers

The word for added and subtracted parts of an expression is known as the term.

What is an expression?

An expression in math is an arithmetic set of numbers and variables with signs and calculations. For example, 4x - 2x = 2x is an expression. The parts that are connected with addition or subtraction or other signs are called terms.

Terms that have the same base exponent can be joined with addition and subtraction. These are called like terms. For example, 3 x 3 and 5 x 3 are like terms.

Therefore, the term is the term for the added and removed components of an equation.

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Instructions: Select all of the methods that will find both real andimaginary solutions.Select one or more:Quadratic FormulaCompleting the SquareFactoringSquare RootsCheck

Answers

Let's begin by identifying key information given to us:

Imaginary solutions

I need help on 8 please it says find the value of x round each answer to the nearest tenth

Answers

Step 1

Redraw the diagram and use the Pythagoras theorem to find the value of c\x.

Step 2:

Find the value of y from the right-angle triangle of sides: 10, 25 and y using the Pythagoras theorem

Opposite = y

Adjacent = 10

Hypotenuse = 25

[tex]\begin{gathered} \text{Pythagoras theorem} \\ \text{Opposite}^2+adjacent^2=hypotenuse^2 \\ y^2+10^2=25^2 \\ y^2\text{ + 100 = 625} \\ y^2\text{ = 625 - 100} \\ y^2\text{ = 525} \\ y\text{ = }\sqrt[]{525} \\ y\text{ = 5}\sqrt[]{21} \end{gathered}[/tex]

Step 3

Next, use the Pythagoras theorem to find x from the triangle with sides

28, x and y

Hypotenuse = 28

Opposite = x

Adjacent = y

[tex]\begin{gathered} x^2+y^2=28^2 \\ x^2\text{ + (5}\sqrt[]{21})^2=28^2 \\ x^2\text{ + 525 = 784} \\ x^2\text{ = 784 - 525} \\ x^2\text{ = 259} \\ \text{ x = }\sqrt[]{259} \\ x\text{ = 16.1} \end{gathered}[/tex]

Final answer

x = 16.1

Simplify square root of 540 Radical way

Answers

[tex]\sqrt{540}=\sqrt[]{2^2\cdot3^3\cdot5}=6\cdot\sqrt[]{15}[/tex]

which fact below has the same difference as 18-6= ?8-1614-814-716-8

Answers

18-6=12

8-16=-8 not equal 18-6

14-8=6 not equal 18-6

14-7=7 not equal 18-6

16-8=8 not equal 18-6

Hence none of the options has the same difference as 18-6

2 subtracted from the product of 5 and a number

Answers

Answer:

5x-2

Step-by-step explanation:

the 'x' is "a number"

1. Given that U = {1, 2, 3, ..., 10}, S = {3, 5, 7, 9} and T = {4, 5, 6, 7}, find S-T​

Answers

The set of, S - T = {3, 9}

Define Set Operation.

To obtain a combination of components according to the operation done on them, the set operations are conducted on two or more sets.

In a set theory, there are three major types of operations performed on sets, such as:

1) Union of sets (∪)

2) Intersection of sets (∩)

3) Difference of sets ( – )

We know, S -T = S ∩ T'

Given, universal set is U = {1, 2, 3, ..., 10}

S = {3, 5, 7, 9} and T = {4, 5, 6, 7}

Now, find T' (T's compliment),

The complement of set T is defined as a set that contains the elements present in the universal set but not in set T.

T'  = {1, 2, 3, 8, 9, 10}

given, S = {3, 5, 7, 9}

Find, S ∩ T'

S ∩ T' = {3, 5, 7, 9} ∩ {1, 2, 3, 8, 9, 10}

The intersection of two sets S and T is a subset of the universal set U and contains elements that are present in both sets S and T. It is represented by the symbol "".

so, S ∩ T'  = {3, 9}

Hence, S - T = S ∩ T'  = {3, 9}

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Pls explain I have a test on this number 2

Answers

Hello there. To solve this question, we have to remember some properties about equations of circles.

Given the following equation:

[tex](x-x_0)^2+(y-y_0)^2=R^2[/tex]

It is called the equation of a circle with center at

[tex](x_0,\,y_0)[/tex]

And radius R.

In the question, it gives us two equations that we might describe the shape of the equation, considering its key features (center, foci, asymptotes, semi-major and semi-minor axes, if applicable).

We have that

[tex](x+4)^2+(y-2)^2=16[/tex]

Is the equation of a circle with center at (-4, 2) and radius equal to

[tex]R=\sqrt{16}=4[/tex]

For the other equation

[tex](x-2)^2+(y-5)^2=64[/tex]

Is also the equation of a circle, with center at (2, 5) and radius equal to

[tex]R=\sqrt{64}=8[/tex]

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