Using the exponential function given y = 7.1(1.03)ˣ, the amount produced in 2006 was 7.8 billion pounds and the estimated amount in 2014 is 9.8 billion pounds
Exponential FunctionAn exponential function is a function of form f (x) = ax, where “x” is a variable and “a” is a constant which is called the base of the function and it should be greater than 0.
In the function given;
y = 7.1(1.03)ˣ
x = number of years after 2003a) What is the estimated number in 2006
We can find the value of x in 2006 as
2006 - 2003 = 3
x = 3
Let's substitute the values into the formula above;
y = 7.1(1.03)³
y = 7.76 ≅ 7.8 billion pounds
b)
The cheese produced in 2014
x = 2014 - 2003 = 11
Plug in the value
y = 7.1(1.03)¹¹
y = 9.83 ≅ 9.8 billion pounds
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The estimate of the total cheese production in 2006 is 7.8 billions of pounds.
The estimate of the total cheese production in 2014 is 9.8 billions of pounds.
How to solve exponential equation?[tex]y =7 .1( {1.03})^{x} [/tex]
Where,
The amount of cheese produced in billions of pounds = yThe number of years after 2003 = xCheese production is between 2003 and 2009The total cheese production in 2006;
x = 3 years
[tex]y =7 .1( {1.03})^{x} [/tex]
[tex]y =7 .1( {1.03})^{3} [/tex]
[tex]y =7 .1(1.092727)[/tex]
y = 7.7583617 billions of pounds
Approximately,
y = 7.8 billions of pounds
The total amount of cheese produced in 2014;
x = 11
[tex]y =7 .1( {1.03})^{x} [/tex]
[tex]y =7 .1( {1.03})^{11} [/tex]
[tex]y =7 .1(1.3842338707244)[/tex]
y = 9.8280604821435
y = 9.8 billions of pounds
In conclusion, the estimated production of cheese in 2006 and 2014 are 7.8 and 9.8 billions of pounds respectively.
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Alex competes in 100 m wheelchair races. He calculates the information
below using his last 4 race times.
His minimum race time was 18.9 s.
The range of his race times was 5.2 s.
The median of his race times was 22.3 s.
The mode of his race times was 24.1 s.
If Alex includes a new race time of 24.9 s in his calculations, how much will
the mean change by?
Give your answer in seconds (s).
With including a new race time of 24.9s the mean will change from 21.9s to 22.5s by 0.6s
What is mean?
The mean is the average or the most common value in a collection of numbers.
In statistics, it is a measure of central tendency of a probability distribution along median and mode.
It is also referred to as an expected value.
According to the given question:
His initial mean would be calculated by:
His minimum race time = 18.9s
The maximum race time = 18.9 + 5.2 = 24.1s
Since the mode is also 24.1, there are two 24.1s races.
Since the median is 22.3s and the number of race times is even, the final race time can be calculated by:
24.1 - 22.3s = 1.8s
22.3 - 1.8 = 20.5s
So the race times are 18.9s, 20.5s, 24.1s and 24.1s.
This means that his initial mean was ( 18.9 + 20.5s + 24.1 + 24.1)/4 = (87.6)/4 = 21.9s
With the new race time, the equation will change to (87.6 + 24.9)/(4+1)= 112.5/5= 22.5s
So the mean change would be 22.5 - 21.9 = 0.6 s
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gladstorm enterprises sells a product for $50 per unit. the variable cost is $32 per unit, while fixed costs are $11,664.a. determine the break-even point in sales units. round answer to the nearest whole number.
When Gladstorm enterprises sells a product for $50 per unit. the variable cost is $32 per unit, while fixed costs are $11,664. The break-even point in sales units is 775 units
The break-even point in sales units can be calculate as follows:
Contribution margin per unit:
= selling price - variable cost
= $50 - $31
= $19
Break-even point in sales:
= fixed cost ÷ contribution margin per unit
= $14,725 ÷ $19
= 775 units
Therefore, The break-even point in sales units is 775 units when Gladstorm enterprises sells a product for $50 per unit. the variable cost is $32 per unit, while fixed costs are $11,664.
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quadrilateral $abcd$ is a square. let $a,$ $b,$ $c$ be parallel lines passing through $a$, $b$, $c$, respectively. the distance between lines $a$ and $b$ is $12,$ and the distance between lines $b$ and $c$ is $17$. find the area of square $abcd$.
The area of square abcd is be parallel lines passing through $a$, $b$, $c$, respectively is the 433.
Squares are quadrilaterals with four congruent aspects and four proper angles, and additionally they have units of parallel aspects. Parallelograms are quadrilaterals with units of parallel aspects. Since squares have to be quadrilaterals with units of parallel aspects, then all squares are parallelograms.
Here we have the values the distance between lines a and b is 12, and the distance between lines b and c is 17.
The distance is 12 and 17
x^2 = 12^2 + 17^2 = 144 +289 = 433
433 is the total that is the area of square of abcd.
Thus the area = 433.
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Students in a classroom have eaten 80% of jellybeans from a jar. There are now only 100 jellybeans left! how many jellybeans were in the jar to begin with?.
500 jellybeans were originally present in the jar when 80 percent of the jellybeans in a jar were consumed by students in a classroom. Only 100 jelly beans are still available.
Given that,
80 percent of the jellybeans in a jar were consumed by students in a classroom. Only 100 jelly beans are still available.
We have to find how many jellybeans were originally present in the jar.
We know that,
80 percent of the jellybeans in a jar were consumed by students in a classroom.
Only 100 jelly beans are still available.
100/(1-80%)
100/0.2
100/1/5
100×5
500
Therefore, 500 jellybeans were originally present in the jar when 80 percent of the jellybeans in a jar were consumed by students in a classroom. Only 100 jelly beans are still available.
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the 5x5 grid shown contains a collection of squares with sizes from 1x1 to 5x5. how many of these squares contain the black center square?
Using Counting principle,
The black center square contains total 330 small squares.
We start with lowest one i.e 1 × 1
Let’s consider any one face out of six faces of cube ,
1×1 squares = 25as one face of grid or cube is made up of 25 small squares.
2× 2 squares = 16If we are facing difficulty in visualising then
simply we draw a 5× 5 board on paper, just as seen in above picture :
and now check 2× 2 squares.
By using R1, R2 and all columns we shall be able to draw 4 such blocks.
Again, R2,R3 and R3, R4 and R4,R5 we can easily draw 4 squares each cash .
Thus, total square count of 2× 2 squares will be
= 16
similarly, we do it for 3× 3 and 4×4 and we will get 9 & 4 respectively.
For final one 5× 5 there is one big square
So, total squares for one face will be
= 25+16+9+4+1=55
Since, there are 6 such faces for a cube then
=>55× 6= 330
Hence, total squares contain the black center square is 330.
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Mike pent $11. 19 on a bag containing red and blue candie. The bag weighed 11 pound. The red candy cot $1. 29 a pound and the blue candy cot $0. 79 a pound. How much red and blue candy did Mike have?
Mike bought 5 pounds of red candy and 6 pounds of blue candy.
What is word problem?
Our comprehensive list of math problems focuses on addition, subtraction, multiplication, division and more specific operations. A math problem is a math question written in one or more sentences that asks a child to apply math knowledge to the "real world." life scenario. This means that children need to be familiar with the vocabulary related to the mathematical symbols they used to understand the meaning of word problems.
Here Mike spent $11.19 on a bag of red and blue candies and both candies weigh 11 lbs
=>Red candies weigh x lbs
=>Blue candies weigh (11-x) lbs
Here cost of x red candy is
=>$1.29/lb* x lbs of red candy
=> 1.29x
Now ,(11-x) lbs of blue candy costs $0.79 (11-x) = $8.69-0 .79 x
Due to the problem, $8.69 - 0.79 x + 1.29 x = $11.19
or $0.50 x = $11.19 - $8.69 = 2.50 $
or $50 x / 100 = $250 / $100
or $50 x = 250 $
or x = 250/50 = 5, red The candy weighs 5 pounds
The blue candy weighs =11-x=11–5=6 pounds
Therefore mike bought 5 pounds of red candy and 6 pounds of blue candy.
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Fermium-253 has a half-life of three days. a sample contains 400 g. how long will it take for the sample to decay to 100 g? number of half-lives: number of days:
Answer: 2 half-life periods
and 6 days
Answer:
2, and 6.12.5.B: [tex]f(d)=400(0.794)^d[/tex]D: 1.986Step-by-step explanation:
if both variables in a correlational study are non-numerical, the data can be organized in a matrix and then analyzed using a .
If both variable in a correlational study are non-numerical, the data can be organized in a matrix and then analyzed using a Chi-square hypothesis test.
A correlational study design investigates relationships between two variables (or more) without the researcher controlling or manipulating any of them.
Chi-square test for hypothesis tests about whether your data is as expected. The basic idea behind the test is to compare the observed values in your data to the expected values that you would see if the null hypothesis is true.
The Chi-square statistic compares the size of any discrepancies between the expected results and the actual results, given the size of the sample and the number of variables in the relationship.
Hence if both variables in a correlational study are non-numerical, the data can be organized in a matrix and then analyzed using a Chi-square hypothesis test.
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How is Animal Farm an allegory to the Soviet Union?.
Orwell wanted to portray the Russian (or Bolshevik) Revolution of 1917 as one that produced a government more oppressive, totalitarian, and lethal than the one it toppled in Animal Farm.
What does Animal Farm say about the USSR?
Despite overtly attacking the Soviet Union, Animal Farm opposes all forms of authoritarianism. Despite his support for socialism's objectives, Orwell was vehemently opposed to the Soviet Union's slide toward dictatorship under Stalin in the years leading up to and during World War II.What kind of allegory does Animal Farm depict?
In order to make his point about corrupt government, Orwell utilizes an allegory. Orwell argues that governments can be corrupt in his allegory Animal Farm, which is primarily understood through the symbolism of the dogs, hens, and Boxer. The canines serve as a metaphor for how governments frighten society by using military force, according to Orwell.Learn more about Animal Farm
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Match the definitions on the left with the terms on the right.
Just want to make sure. Am I right??? Pls help Thxs!
Mr. X invet $1,000 at a 10 percent nominal rate for one year. If the inflation rate i 4 percent, what i the real value of the invetment at the end of one year?
Using the Real rate of return,
the real value of the invetment at the end of one year is $1058.
Real rate of return:
The real rate of return is the present value of the return on investment after taxes and inflation.
By considering the expected inflation rate and the effective interest rate in the compounding interval, we can derive the real interest rate.
Real Rate Of Return Formula,
Real rate of return = [( 1+ Nominal rate )/(1+ inflation rate) ] - 1
The principal amount of investment by Mr.X ( A)
= $1,000
The nominal or current rate of interest (i)= 10%
The rate of inflation ( π )= 4%
pulging all the values in above formula we get,
rate of return (R) =[ ( 1 + i ) /(1+π)] - 1
=> R =[ (1+0.1 )/(1+0.04) ] - 1 = (1.1 / 1.04 ) - 1
=> R = 0.05769(approx.)
=5.8%(approx.)
so, real rate of return = 5.8%
Real value of investment after a year = principle amount (A) + { real rate return × principle amount}
Real value of investment =$1,000+{5.8%×$1,000}
=$1,000+$58
=$1,058
Hence, real value of investment at the end of year is $1,058.
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A 5. 5% 20-year municipal bond is currently priced to yield 7. 2%. For a taxpayer in the 33% marginal tax bracket, this bond would offer an equivalent taxable yield of:.
Using the Equivalent Taxable yield formula ,
the equivalent Taxable yield for a taxpayer is 10.75%.
Equivalent Taxable yield :
Tax-equivalent yield is determined by taking the yield of a tax-exempt bond and dividing it by one minus an investor's federal income tax bracket.
Tax-equivalent yield is a way to measure the return on a taxable bond or other investment to make it equal to the return associated with a tax-exempt bond or investment.
Formula:
Tax-equivalent yield = interest rate ÷ (1 – tax rate)
We have given that
Marginal tax bracket or tax rate = 33%
currently priced yield = 7.2 %
Equivalent taxable yield = Yield / ( 1 - Tax% )
= 7.2% / ( 1 - 33% )
= 0.072 /(1-0.33)
= 0.072/0.67
= 0.10746
= 10.75%
Hence, total equivalent Taxable yield for taxpayer is 10.75%.
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a box of snacks, contain 20 individual packages. The newly designed box contains 28 individual packages by what percentage did the number of individual packages increase.
The percentage that the number of individual packages increased by in the newly designed box is 40%
How to find the percentage increase?To find the percentage increase, you first need to find the increase in the number of individual packages in the newly designed box.
This increase is:
= Newly designed box quantity - old box of snacks
= 28 - 20
= 8 individual packages
The percentage increase would then be:
= Increase in packages / Number of packages in old box of snacks
= 8 / 20
= 40%
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What are the factors of x3 5x2 8x 4?.
A factor is just a number that completely divides another number, x=1,2,2 are factors.
What are polynomials?Using mathematical operations like addition, subtraction, multiplication, and division, a polynomial is an equation made up of variables, constants, and exponents.
Here x³ - 5x² + 8x - 4 is the cubic polynomial
Let's take x = 1 ,
=> 0=x - 1
So, one of the factor = (x - 1)
Now,
By Division method, we get
=> (x³ - 5x² + 8x - 4) is Dividend
=> (x - 1) is Divisor
=> (x² - 4x + 4) is Quotient
Now we will solve for,
(x)² - (4x) + 4
(x)² - (2x)- (2x) + 4
(x-2)X(x-2)
x=2,2
x=1,2,2 are factors.
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chubbyville purchases a delivery van for $24,000, chubbyville estimates a four-year service life and a residual life of $1600
The answer is tabulated as below :
Given that,
Chubby Ville purchases a delivery van for $24,000, chubbyville estimates a four-year service life and a residual life of $1600
A Single straight line method Depreciation each year is 5,600 (24,000 - 1,600) divided by four years.
Method 2 of Double Declining Balance
Depreciable Year Amount
Depreciation Rate, Exp. Acc., and Dep Book Value
1 $24,000 50.00%
$12,000 $12,000 $12,000\s 2 $12,000 50.00%
$6,000 $18,000 $6,000\s 3 $6,000 50.00%
$3,000 $21,000 $3,000
4 $3,000 46.67%
$1,400 $22,400 $1,600
Three Units of Production
Year miles
Depreciation Amount/Unit Depreciation Expense Accounting Dep Book Value
1 19,000 $0.21 $3,990 $3,990 $20,010
2 30,000 $0.21 $6,300 $10,290 $13,710\s 3 23,000 $0.21 $4,830 $15,120 $8,880
4 24,000 $0.21 $5,040 $20,160 $3,840
Mileage depreciation $0.21 (24,000 - 1,600)/109,000
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you want to buy some noodles. an 8-oz package costs 3.40. a 12-oz bag costs 4.80 a 26 oz package costs 10.40. which package is better
Answer:
The cost per unit is the same for the 12 ounce bag and the 26 ounce bag. Since the cost is the same, it would come down to would you rather have 12 ounces or 26 ounces? The 8 ounce bag cost the most.
Step-by-step explanation:
Find the unit costs
[tex]\frac{3.40}{8}[/tex] = .425
[tex]\frac{4.80}{12}[/tex] = .4
[tex]\frac{10.40}{26}[/tex] = .4
Dylan buys 2 sodas and 3 teas for £2.
Caroline buys 5 sodas and 3 teas for £2.75.
Work out the cost of one soda and one tea.
Answer:
.4
=soda,
0.5=tea
Step-by-step explanation:
Answer:
one soda costs 0.25 euros
One tea costs 0.5 euros
Step-by-step explanation:
we make a system of equations
S- soda
t- tea
2s+3t=2
5s+3t=2.75
we have to isolate a variable because I like to use substitution method best
2s+3t=2
-3t. -3t
2s=2-3t
/2. /2. /2
s=1-1.5t
5(1-1.5t)+3t=2.75
5-7.5t+3t=2.75
5-4.5t=2.75
-5. -5
-4.5t=-2.25
/-4.5. /-4.5
t=0.5
One tea is 0.5 euros
Now to find one soda we just fill it in
2s+3(0.5)=2
2s+1.5=2
-1.5. -1.5
2s=0.5
/2. /2
s=0.25
One side cost 0.25 euros
Hopes this helps please mark brainliest
An important factor in selling a residential property is the number of people who look through the home. A sample of 21 homes recently sold in the Buffalo, New York, area revealed the mean number looking through each home was 25 and the standard deviation of the sample was 7 people.
Develop a 99% confidence interval for the population mean. (Use t Distribution Table.) (Round your answers to 2 decimal places.)
The 99% confidence interval for the population mean is (20.6568, 29.3432)
In statistics, a confidence interval describes the likelihood that a population parameter would fall between a set of values for a given percentage of the time. Confidence ranges that include 95% or 99% of anticipated observations are frequently used by analysts. Therefore, it can be concluded that there is a 95% probability that the true value falls within that range if a point estimate of 10.00 is produced from a statistical model with a 95% confidence interval of 9.50 - 10.50.
Given:
Sample size = 21
Mean = 25
Standard deviation = 7
Confidence interval = 99%
α=1−0.99=0.01
α/2 = 0.005
Degrees of freedom(df)=n−1=21−1=20
Critical value(tc)=tα/2,df = t0.005,20 = 2.8433
Confidence Interval = mean +- tc * s/[tex]\sqrt{n}[/tex]
C.I = 25 ± 2.8433×7/[tex]\sqrt{21}[/tex]
C.I = (25 ± 4.3432)
C.I = (25−4.3432, 25+4.3432)
C.I = (20.6568, 29.3432)
99% confidence interval for the population average of the times homes are shown is (20.6568, 29.3432)
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One difficulty in measuring the nesting success of birds is that the researchers must count the number of eggs in the nest, which is disturbing to the parents. Even though the researcher does not harm the birds, the flight of the bird might alert predators to the presence of a nest. To see if researcher activity might degrade nesting success, the nest survival of 102 nests that had their eggs counted, was recorded. Sixty-four of the nests failed (i.e. the parent abandoned the nest.) Assuming that it is reasonable to regard the 102 nests in the sample as representative of the population of nests for which the eggs have been counted, construct and interpret a 95% confidence interval for the proportion of nests that have eggs counted that are then abandoned. (0.5336, 0.7213) (0.5136, 0.7113) (0.5436, 0.7313) None of these
A 95% confidence interval for population proportion p is (0.5336, 0.7213).
Given,
One difficulty in measuring the nesting success of birds is that the researchers must count the number of eggs in the nest, which is disturbing to the parents. Even though the researcher does not harm the birds, the flight of the bird might alert predators to the presence of a nest. To see if researcher activity might degrade nesting success, the nest survival of 102 nests that had their eggs counted, was recorded. Sixty-four of the nests failed (i.e. the parent abandoned the nest.)
To find,
Assuming that it is reasonable to regard the 102 nests in the sample as representative of the population of nests for which the eggs have been counted, construct and interpret a 95% confidence interval for the proportion of nests that have eggs counted that are then abandoned;
n = 102
x = 64
Point estimate = sample proportion = [tex]\hat p[/tex] = x / n = 64/102 =0.627
1 - [tex]\hat p[/tex] = 1 - 0.627 = 0.373
[tex]Z\alpha/2[/tex] = 1.96
The margin of error = E
[tex]= Z\alpha / 2 * \sqrt((\hat p * (1 - \hat p)) / n) = 1.96 * (\sqrt(0.627*(0.373) /102 ) = 0.0934[/tex]
A 95% confidence interval for population proportion p is;
[tex]\hat p[/tex] - E < p < [tex]\hat p[/tex] + E
0.627 - 0.0934 < p < 0.627 + 0.0934
0.5336 < p < 0.7213
(0.5336, 0.7213)
Hence, a 95% confidence interval for population proportion p is (0.5336, 0.7213).
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How many prime numbers are multiples 3?.
Answer:
the only positive multiple of 3, which is a prime number is 1×3=3 itself.
hope this helps! :)
Step-by-step explanation:
SOMEONE PLEASE HELP ☹️
Answer: A is the answerrrrrr
Step-by-step explanation:
Calculate the length of AB in each of the following right-angled triangles:
Answer:
AB= 12 AB=18
Step-by-step explanation:
sin(30)=AB/AC
=> AB=Sin(30)*AC
sin(30)=0.5
=>AB=0.5*24=15
sin(30)=AB/AC
=> AB=Sin(30)*AC
sin(30)=0.5
=>AB=0.5*36=18
Answer:
part a: AB = 12cm
part b: AB = 18cm
Step-by-step explanation:
sin(angle)=OPP/HYP
sine of an angle is a ratio of two sides of a right triangle. For sine, the ratio is the opposite side over the hypotenuse. In part a the marked angle is 30° and AB is the opposite side. The hypotenuse is given, 24cm.
So the sin 30°
= opp/hyp
= AB / 24
also given is the fact that sin30°=.5
Substitute that into our equation also.
sin30° = AB/24
.5 = AB/24
multiply both sides by 24.
.5×24 = AB
12 = AB
AB is 12 cm.
Part b is an identical calculation except the hypotenuse is 36cm.
sin30° = AB/36
.5 = AB/36
.5×36 = AB
18 = AB
AB is 18cm.
They may be trying to lead you to discover some shortcut patterns in a 30°-60°-90° triangle. That is that the short leg is HALF the hypotenuse OR the hypotenuse is double the short leg.
Which set of data has a mean of 15 a range of 22 a median of 14 and a mode of 14?.
3,14,19,25,14 is set of data has a mean of 15 a range of 22 a median of 14 and a mode of 14.
What is Statistics?Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.
First, arrange the given set in ascending order.
3,14,19,25,14
Ascending order = 3, 14, 14, 19, 25
Mean = sum of observations/total observations
(3+14+14+19+25)/5
75/5
15
Median is the middle number of the data.
3, 14, 14, 19, 25
14 is the median
The Mode is the number that occurs most number of times.
3, 14, 14, 19, 25
In the given data, 14 occurs two times. so, 14 is the mode.
Range:
Range is highest value - lowest value
3, 14, 14, 19, 25
=> 25 - 3 =22
so, range is 22.
Hence, the required set of data is 3,14,19,25,14
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the proportion of dental procedures that are extractions is 0.16. which of the following exemplifies a type i error in this situation? a. we reject the claim that the proportion of dental procedures that are extractions is 0.16 when the proportion is actually different from 0.16. b. we reject the claim that the proportion of dental procedures that are extractions is 0.16 when the proportion is actually 0.16. c. we fail to reject the claim that the proportion of dental procedures that are extractions is 0.16 when the proportion is actually different from 0.16. d. we fail to reject the claim that the proportion of dental procedures that are extractions is 0.16 when the proportion is actually 0.16.
The following exemplifies a type of error in this situation, we fail to reject the claim that the proportion of dental procedures that are extractions is 0.16 when the proportion is actually different from 0.16.
What is dental extraction?
An extraction is a process used to remove a tooth from its socket in the gum. A regular dentist, an oral surgeon, or a periodontist typically performs it. Normal teeth might look different, especially the molars.
Here, we have
The proportion of dental procedures that are extractions is 0.16.
We have to find errors in this situation,
we concluded that we fail to reject the claim that the proportion of dental procedures that are extractions is 0.16 when the proportion is actually different from 0.16.
Hence, the following exemplifies a type of error in this situation, we fail to reject the claim that the proportion of dental procedures that are extractions is 0.16 when the proportion is actually different from 0.16.
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BBQ Corp. had a 3:1 stock split ratio. Pre-split the company had 1.35 Million outstanding shares at a price of $72.45 per share.
What is the post-split market capitalization of BBQ corp.?
The pre-split market capitalization of BBQ corp. is $24,451,875.
Given that, BBQ Corp. had a 3:1 stock split ratio. Pre-split the company had 1.35 Million outstanding shares at a price of $72.45 per share.
What is the ratio?
The ratio is defined as the comparison of two quantities of the same units that indicates how much of one quantity is present in the other quantity.
Here, 3+1=4
Now, 1/4 × 1350000
= 337500 shares
So, capitalization is 337500×72.45
= $24,451,875
Therefore, the pre-split market capitalization of BBQ corp. is $24,451,875.
Any help on this question please?
Answer:
C. 20
Step-by-step explanation:
Since 11 times 4 = 44, you can multiply your 5 by 4 to get 20.
Members of a softball team raised $2089. 50 to go to a tournament. They rented a bus for $1087. 50 and budgeted $41. 75 per player for meals. Write and solve an equation which can be used to determine xx, the number of players the team can bring to the tournament.
The number of players the team can bring to the tournament is 24.
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
Let x represnets the number of players the team can bring to the tournament.
Then the equation which can be used to determine x, the number of players the team can bring to the tournament can be written as;
Thus Total money raised = Rent of bus + (Cost per player) (Number of players)
2089.50 = 1087.50 + 41. 75x
2089.50- 1087.50 = 41. 75x
1002 = 41. 75x
x = 24
Hence, the number of players the team can bring to the tournament is 24.
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On a scale 1 3/4 inches represent 50 miles. How many miles are represented by 7 inches?
Answer:
200 miles
Step-by-step explanation:
1 3/4 can be turned into a decimal as 1.75
Now let’s create fractions to prepare for cross multiplication
1.75/50=7/x
1.75x=7(50)
1.75x=350
/1.75. /1.75
x=200
200 miles
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α and β are the roots of the equation 2x² - 3x + 4 = 0. Find α+β
Answer:
Step-by-step explanation:
ans is in the attachment.
suppose a jar contains 11 red marbles and 40 blue marbles. if you reach in the jar and pull out 2 marbles at random, find the probability that both are red. write your answer as a reduced fraction.
The required probability that both are red out of total marbles is 0.0431 or 4.31%.
What is probability?A probability is a number that mirrors the opportunity or probability that a specific occasion will happen. Probabilities can be communicated as extents that reach from 0 to 1, and they can likewise be communicated as rates going from 0% to 100 percent.
According to question:Total number of marbles in a jar = 40 + 11 = 51
Number of red marbles = 11, blue marbles = 40
At our first pull, there is an 11/51 chance that a red will be pulled and in second pull the probability is 10/50 , as one red marbles taken out.
Net probability = 11/51×10/50 = 0.0431
percentage probability = 4.31%
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