Help please 100 points

Answer:

61.9 g C3H8

Explanation:

First write and balance equation

C3H8 + 5O2 -> 3CO2 + 4H2O

Next find the limiting reactant

25.0g propane/ 44.097 g propane = 0.567 mol propane

(75.0gO2)(1mol C3H8)/ (32g)(5mol O2)= 0.468 mol propane

Since O2 is the limiting reactant now we can find the mass of CO2

(75.0g O2)(1 mol O2)( 3 mol CO2)(44.01 g CO2)/(32g O2)(5 mol O2)( 1 mol CO2) =61.9g CO2

Answer:

(a) Rate of formation of NO2 is also 0.066M/s

(b) Rate of reaction of O2 gas is 0.033M/s

Explanation:

(a) in one second, according to the equation,

2 moles of NO combines with 2moles of NO2.

Therefore 0.066M NO will still consume 0.066mole NO2.

(b) According to the equation,

2 moles NO consumes 1 mole O2, 0.0666M will consume 0.0333 mole O2

To prepare a 0.12 M solution of FeCl₃, the amount of solid FeCl₃ to be dissolved in a given volume of solvent will be 9.72 grams.

Given,

Molarity of FeCl₃ (M)= 0.12 M

The molecular weight (m) of FeCl₃ is  = 162 gm

The volume of the solution (V) to be prepared is =500 ml

The amount of FeCl₃ to be dissolved to make a 0.12 M solution is= x

So,

MV= x ÷ m × 1000

0.12× 500 = x ÷ 162 × 1000

x = 60 × 162 ÷ 1000

x= 9.72 gm

So 9.72 grams of FeCl₃ is dissolved to make 500 ml of 0.12 M solution.

For preparing 0.4 M HCl from 4M HCL:

If we need to make 500 ml of solution with 0.4M of HCL, then we use the formula:

M₁V₁= M₂V₂

0.4 × 500= 4 × x

x= 50 ml

So 50 ml of 4M HCL is taken to make 0.4 M HCL.

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The expression "104" is not equal to the option:

O $408

The other options all represent the value 104 in different notations or formats:

1.0 100,000 is equal to 104.

2.00.1 x 105 is equal to 104.

3.10 x 10 x 10 x 10 is equal to 104.

5.0 10² x 10² is equal to 104.

Therefore, the correct answer is option 4. O $408, as it does not represent the value 104.

Answer:

The molecule with two carbon atoms double-bonded to each other and single-bonded to four hydrogen atoms (C2H4). This molecule represents an organic compound because it contains carbon atoms covalently bonded to hydrogen atoms. Organic compounds are characterized by their ability to form covalent bonds with hydrogen atoms and other organic functional groups (such as carbon-carbon double bonds in this case). The other molecules mentioned in the question either have inorganic elements (O, S, N) or do not have any carbon-hydrogen bonds, making them inorganic in nature.

The compound represented by two Carbon atoms double-bonded and single-bonded to Hydrogen is an organic compound. Organic compounds are commonly formed of Carbon bonded to Hydrogen and possibly other elements.

The structure that represents an organic compound is the one with two Carbon (C) atoms double-bonded together, and single bonded above left, above right, below left, and below right to Hydrogen (H). This is because organic compounds are typically composed of Carbon atoms covalently bonded to Hydrogen, and possibly other elements. The other examples described include Oxygen (O) bonded to Hydrogen, which is a compound (water) but not an organic one; Sulfur (S) double bonded to Oxygen and single bonded to two other Oxygen atoms and a Hydrogen atom, likely forming a sulfate ion (not an organic compound); and Nitrogen triple-bonded to Nitrogen which forms N2 (a molecule but not an organic compound).

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The identity of X in the nuclear equation is  10 Ne.

The nuclear equation for the alpha decay of 242 Cm is given by:242 Cm → 245 Cf + X + α + γIn the above nuclear equation, 242 Cm undergoes alpha decay to produce 245 Cf and release an alpha particle (α) and gamma rays (γ). Thus, the identity of X in the nuclear equation is unknown and needs to be determined. To solve for X, the mass and atomic numbers must be conserved on both sides of the equation.Mass Conservation: The sum of the mass numbers of the reactants should be equal to the sum of the mass numbers of the products.242 + m(X) = 245 + 4m Atomic Number Conservation: The sum of the atomic numbers of the reactants should be equal to the sum of the atomic numbers of the products.96 + z(X) = 98 + 2zBy solving for the unknowns m and z, we can determine the identity of X.  Mass Conservation Equation: 242 + m(X) = 245 + 4m⇒ m(X) - 4m = 245 - 242⇒ m(X) - 4m = 3⇒ m(X) = 4m + 3Atomic Number Conservation Equation: 96 + z(X) = 98 + 2z⇒ z(X) - 2z = 98 - 96⇒ z(X) - 2z = 2⇒ z(X) = 2z + 2From the above equations, we can substitute m and z values to determine X. Substitute m = 1, 5, 9, ... to find X.Substitute z = 96, 98, 100, ... to find X.However, there is no integer value of m that satisfies the mass conservation equation, so we need to try fractional values of m to solve for X.Using the fractional value of m = 1.75, we can solve for X.  m(X) = 4m + 3⇒ m(X) = 4(1.75) + 3⇒ m(X) = 10⇒ X has 10 as its mass number. z(X) = 2z + 2⇒ z(X) = 2(96) + 2⇒ z(X) = 194⇒ X has 194 as its atomic number.

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Answer:

  B. pressure

  C. temperature

Explanation:

You want to know the variable(s) that are changing when studying Amonton's Law.

Guillaume Amonton discovered in the late 1600s that pressure and absolute temperature are proportional for a given quantity and volume of gas.

The variables of concern are pressure and temperature.

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The names of the compounds are;

1) Sodium carbonate

2) potassium hydroxide

3) Copper II nitrate

4) Iron II sulfate

5) Silver acetate

6) Lead II chromate

7) Manganese II chlorate

8) Iron II sulfite

9) Nickel III phosphate

10) Chromium III bicarbonate

An example of a polyatomic ionic molecule is one that has several atoms covalently bound together, carrying a net charge as a group, and acting as a single unit during chemical reactions.

These compounds contain polyatomic ions, charged entities made up of two or more atoms joined by covalent bonds but carrying an overall charge as a result of electron gain or loss.

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There are 1.4 grams of acetic acid in 28 grams of vinegar.

If the vinegar has a concentration of 5.0% acetic acid, it means that 5.0 g of acetic acid is present in 100 g of vinegar.

To calculate how many grams of acetic acid are in 28 g of vinegar, we can set up a proportion:

(5.0 g acetic acid / 100 g vinegar) = (x g acetic acid / 28 g vinegar)

Cross-multiplying and solving for x, we get:

x = (5.0 g acetic acid / 100 g vinegar) * 28 g vinegar

x = 1.4 g acetic acid

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White vinegar typically consists of 93%–96% water and 4–7% acetic acid. It can be used to cooking, bake, cleaning, and get rid of weeds. It can also help you lose weight and lower your blood sugar and cholesterol. Consumption is safe in moderation, but excessive consumption or when combined with certain medications could be harmful.

Apple cider vinegar is widely used in cooking and as a salad dressing because it contains acetic acid and nutrients like vitamins C and B vitamins. But at the same time, it's been utilized customarily as medication. It helps in losing weight.

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Rounded to the appropriate number of significant figures, the mass of 8.51 moles of K₂CO₃ is 1176.6 g. To calculate the mass of 8.51 moles of K₂CO₃you need to use the molar mass of K₂CO₃ and multiply it by the number of moles.

The molar mass of K₂CO₃ can be determined by adding up the atomic masses of its constituent elements. Potassium (K) has a molar mass of 39.10 g/mol, carbon (C) has a molar mass of 12.01 g/mol, and oxygen (O) has a molar mass of 16.00 g/mol.

Molar mass of K₂CO₃ = (2 × molar mass of K) + molar mass of C + (3 × molar mass of O)

                     = (2 × 39.10 g/mol) + 12.01 g/mol + (3 × 16.00 g/mol)

                     = 78.20 g/mol + 12.01 g/mol + 48.00 g/mol

                     = 138.21 g/mol

Now, to calculate the mass of 8.51 moles of K₂CO₃, you can use the formula:

Mass = number of moles × molar mass

Mass = 8.51 mol × 138.21 g/mol

Mass = 1176.5771 g

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It would take approximately 15,000 minutes (rounded to the nearest whole number) for the dripping faucet to fill a 1.00-gallon bucket. we can use the given information about the rate of water dripping from the faucet.

Given:

- Rate of water dripping = 41 drops/minute

- Number of drops in a gallon = 15,000 drops

We need to convert the number of drops into gallons and then determine the time required.

1 gallon = 15,000 drops

Let's set up the conversion:

(1.00 gallon / 15,000 drops) × (41 drops / 1 minute) = (1.00 gallon × 1 minute) / (15,000 drops)

Simplifying the equation:

(1.00 gallon × 1 minute) / (15,000 drops) = 0.0000666667 gallon/minute

Now, we can calculate the time required to fill a 1.00-gallon bucket:

Time = Volume / Rate

Time = 1.00 gallon / (0.0000666667 gallon/minute)

Calculating the result:

Time = 1.00 gallon / (0.0000666667 gallon/minute) = 15,000 minutes

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At a temperature of 375 K, 0.45 moles of oxygen gas will occupy 7.5 liters at a pressure of approximately 3.333 atm.we can use the ideal gas law equation:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles . R is the ideal gas constant, and T is the temperature in Kelvin.

R is a constant value of 0.0821 L·atm/(mol·K).

First, we need to convert the given temperature to Kelvin by adding 273.15:

[tex]375 K = 375 + 273.15 = 648.15 K[/tex]

Now we can substitute the known values into the equation:

[tex]P * 7.5 = 0.45 * 0.0821 * 648.15[/tex]

[tex]P * 7.5 = 24.997[/tex]

Dividing both sides of the equation by 7.5, we get:

P = 24.997 / 7.5

P ≈ 3.333 atm

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