Answers
1) Aluminum and indium are in the same group
2) Barium is in group 2 and period 6
What is the periodic table?The names of the compounds are;
Triphosphorous tetrachloride
Calcium bromide
Nitrogen hexasulfur
The molecules that balance the charges are;
K3P, Al2O3, CaS
The elements in group 17 are chlorine and fluorine
The elements in period 3 are sodium and magnesium.
The balanced equations are from the data given;
SnO2 + 2H2 → Sn + 2H2O
4Al + 3O2 → 2Al2O3
Au2S3 + 3H2 → 2Au + 3H2S
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Related Questions
What happens to a buffered solution
when a small amount of base is
added?
Answers
Answer: When you add small quantities of an acid or alkali (base) to it, its pH does not change significantly. In other words, the buffer solution stops the acid and base from neutralizing each other.
Answer:
the result is a decrease in the amount of conjugate base present and an increase in the amount of the weak acid.
Explanation:
)A mixture of 0.220 molesCO, 0.350 molesF2and 0.640 molesHehas a total pressure of 2.95 atm.What is the partial pressure ofCO?
Answers
The partial pressure of a component gas in a mixture is the pressure that gas would exert if present alone in the vessel at the same temperature as that of the mixture. Here the partial pressure of CO is
The pressure exerted by a mixture of two or more non-reacting gases enclosed in a definite volume is equal to the sum of the partial pressures of the component gases. This is sated by Dalton.
Here partial pressure is:
partial pressure = Mole fraction × Total pressure
Mole fraction of CO = Number of moles of CO / Total moles
n(CO) = 0.220 / 1.21 = 0.181 moles
partial pressure = 2.95 × 0.181 = 0.533 atm
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How many years passed between the first man on the Moon and the first US woman in space?
Answers
It took 14 years between the first man on the Moon and the first US woman in space.
What is space exploration?The use of astronomy and space technology to explore outer space is known as space exploration. While astronomers use telescopes to explore space, physical exploration is carried out by both uncrewed robotic space probes and human spaceflight.
Understanding gravity, the magnetosphere, the atmosphere, fluid dynamics, and the geological evolution of other planets, for example, has come from studying the solar system.
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2 Pretest Unit 5 Question 22 of 30 Why are there so many carbon-based compounds? O A. Carbon can form compounds with any other element in the periodic table except noble gases. OB. Carbon can form up to six bonds with other carbon atoms and atoms of other elements. OC. Carbon can form single, double, or triple bonds and can bond with itself and other elements. D. Carbon can form ionic, covalent, and metallic compounds under the right conditions. ZA
Answers
The why there are so many carbon-based compounds is that B. Carbon can form up to six bonds with other carbon atoms and atoms of other elements.
What is the uniqueness of carbon?Carbon can be described as the element that posses 4 electrons in its outermost shell, and it has the asbility to gain or loss 4 electrons to so it can have nobel gas configuration.
It should be noted that Catenation is one of the unique ability of carbon which help it to form bonds with other atoms of carbon and due to this reason, it have the ability to record a long chains of different types of compounds.
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Given the reaction:
If there are initially 14.2 moles of iron (III) nitrate nonahydrate, how many moles of steam (water vapor) will be produced?
Answer in mol.
Answers
Total, 127.8 moles of the steam (water vapor) will be produced.
Iron(III) nitrate nonahydrate, or Fe(NO₃)₃·9H₂O, is a compound that contains iron (III) cations (Fe³⁺) and nitrate anions (NO₃⁻) combined with nine water molecules (H₂O) per formula unit. The nine water molecules are referred to as "nonahydrate," which indicates that there are nine water molecules associated with each formula unit of Fe(NO₃)₃. This compound is also commonly known as ferric nitrate nonahydrate.
Balanced equation for the given reaction is;
Fe(NO₃)₃·9H₂O(s) → Fe(NO₃)₃(s) + 9H₂O(g)
According to the equation, one mole of Fe(NO₃)₃·9H₂O produces 9 moles of water vapor (H₂O) when it undergoes the reaction. Therefore, if there are initially 14.2 moles of Fe(NO₃)₃·9H₂O, the number of moles of water vapor (H₂O) produced will be;
14.2 moles of Fe(NO₃)₃·9H₂O × 9 moles of H₂O per 1 mole of Fe(NO₃)₃·9H₂O = 127.8 moles of H₂O
Therefore, 127.8 moles of water vapor will be produced.
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If 4.53g Ar are added to 1.12 atm He in a 2.00 L cylinder at 27.0 Celsius degree
What is the total of gaseous mixture?
Answers
The total gaseous mixture is 4.48 g.
The total gaseous mixture can be calculated using the ideal gas law: PV = nRT.
First, we need to convert the temperature to Kelvin: 27.0°C + 273.15 = 300.15 K.
Next, we can use the ideal gas law to calculate the number of moles of each gas:
For He: n = (1.12 atm) (2.00 L) / (0.08206 L·atm/mol·K) (300.15 K) = 0.0906 mol
For Ar: n = (4.53 g) / (39.95 g/mol) = 0.113 mol
The total number of moles of gas in the mixture is then:
n(total) = n(He) + n(Ar) = 0.0906 mol + 0.113 mol = 0.204 mol
Finally, we can calculate the total mass of the mixture:
m(total) = n(total) × M(avg)
where M(avg) is the average molar mass of the mixture, which can be calculated as:
M(avg) = (M(He) + M(Ar)) / 2 = (4.003 g/mol + 39.95 g/mol) / 2 = 21.98 g/mol
Thus,
m(total) = 0.204 mol × 21.98 g/mol = 4.48 g
Therefore, The total weight of the gaseous mixture is 4.48 g.
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Why does intermolecular force exists between particles
Answers
HELP ME PLEASE!! I NEED HELP ANSWERING THESE!!
Answers
1) Indium and aluminum belong to the same group.
2) Barium belongs to groups 2 and 6
The periodic table is what?The compounds' names are;
Tetrachloro phosphorus chloride
Calcium bromide
Hexasulfur nitrogen
The following molecules balance the charges:
K3P, CaS, Al2O3
Chlorine and fluorine are elements of group 17
Magnesium and salt are the components that make up period 3.
The data are used to create the balanced equations;
Sn + 2H2O = SnO2 + H2
3O2 + 4Al = 2Al2O3
2Au + 3H2S = Au2S3 + 3H2
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a 40 ml solution containing .30 M Ti+3 was titrated with 0.75 M Sn+2. what potential at the equivalence point if the resulting solution is
measured against a reference electrode
Answers
Ti+3 + Sn+2 → Ti+4 + Sn+4
The balanced equation shows that one mole of Ti+3 reacts with one mole of Sn+2. We can use this to calculate the number of moles of Sn+2 required to react completely with the Ti+3 in the solution:
n(Sn+2) = (0.30 mol/L) x (0.040 L) = 0.012 mol
The volume of Sn+2 required to react with the Ti+3 can be calculated using the molarity and the number of moles:
V(Sn+2) = n(Sn+2) / [Sn+2] = 0.012 mol / 0.75 mol/L = 0.016 L = 16 mL
At the equivalence point, all of the Ti+3 has reacted with the Sn+2, so the resulting solution contains only Ti+4 and Sn+4. The potential at the equivalence point can be calculated using the Nernst equation:
E = E° - (RT/nF) x ln(Q)
where E° is the standard cell potential, R is the gas constant, T is the temperature in Kelvin, n is the number of electrons transferred in the reaction, F is the Faraday constant, and Q is the reaction quotient.
The standard cell potential can be calculated using the reduction potentials for the half-reactions:
Ti+4 + 2 e- → Ti+3 E° = -0.15 V
Sn+4 + 2 e- → Sn+2 E° = 0.15 V
The overall cell potential is the sum of the reduction potentials:
E°cell = E°reduction (cathode) - E°reduction (anode) = 0.15 V + 0.15 V = 0.30 V
At the equivalence point, the reaction quotient Q is equal to the equilibrium constant K:
K = [Ti+4] / [Sn+4]
The concentrations of Ti+4 and Sn+4 can be calculated from the number of moles and the total volume of the solution:
n(Ti+4) = n(Sn+2) = 0.012 mol
V(total) = 0.040 L + 0.016 L = 0.056
What mass in grams of oxygen gas are produced when 2.43 x 10-4 g of KCIO,
are completely reacted according to the following chemical equation:
2 KCIO₂ (s) → 2 KCI (s) + 3 0₂(g)
Answers
The balanced chemical equation shows that 2 moles of KCIO4 produce 3 moles of O2. Therefore, we can write a ratio of the moles of KCIO4 to moles of O2 as:
2 moles KCIO4 / 3 moles O2
We can use the molar mass of KCIO4 to convert the given mass of KCIO4 to moles:
2.43 x 10^-4 g KCIO4 x (1 mol KCIO4/ 391.28 g KCIO4) = 6.20 x 10^-7 mol KCIO4
Using the mole ratio, we can calculate the number of moles of O2 produced:
6.20 x 10^-7 mol KCIO4 x (3 moles O2 / 2 moles KCIO4) = 9.30 x 10^-7 mol O2
Finally, we can use the molar mass of O2 to convert the number of moles to mass in grams:
9.30 x 10^-7 mol O2 x (32.00 g O2 / 1 mol O2) = 2.98 x 10^-5 g O2
Therefore, the mass of O2 produced is 2.98 x 10^-5 g.
2.5 mL of a 0.150 M solution is diluted with 2.5 mL of water. What is the concentration of the new solution?
Answers
The new concentration of the solution can be gotten as 0.075 M.
Dilution formula for solutionsThe formula that we should use is;
C1V1 = C2V2
where:
C1 = initial concentration of the solution (in units of mass/volume, moles/liter, or other concentration units)
V1 = initial volume of the solution
C2 = final concentration of the solution after dilution
V2 = final volume of the solution after dilution
We have to note that;
C1V1= C2V2
Thus we have that;
2.5 * 0.150 = 5 * V
V = 0.075 M
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in general, which of the following statements about electron-pair geometries is true? question 14 options: a) they maximize the space between valence electrons to minimize the repulsion between them. b) they maximize the polarity of valence electrons to minimize the attraction between them. c) they maximize the space between
Answers
They maximise the distance between valence electrons to reduce the repulsion between them, which is option an in the correct response. This is so because the idea behind electron-pair geometries is to reduce valence electron repulsion.
By increasing the distance between them, which decreases the repelling power of the interactions between electrons, this is accomplished.
Because they reduce electron repulsion and enable molecules to adopt their most stable form, electron-pair geometries are used to anticipate the structure of molecules.
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Please name this compound.
Answers
Answer:
3 methyl hexene
Explanation:
Name the property shown.
9. 2 x= x 2
td
11. 7(z+ y) = 7z+ 7y
10. 231= 23
12. a + (2b + 3c) = (a + 2b) + 3c
The numerical value of the equilibrium constant, Kc, for the following reaction is 1.7×102. If the equilibrium mixture contains 0.21 M H2 and 0.015 M N2, what is the molar concentration of NH3?
3H2(g)+N2(g)⇌2NH3(g)
Answers
The molar concentration of NH₃ is 0.17 M.
The equilibrium constant expression for the given reaction is:
Kc = [NH₃]² / ([H₂]³[N₂])We are given Kc = 1.7 × 10² and the molar concentrations of H₂ and N₂ in the equilibrium mixture as 0.21 M and 0.015 M, respectively. Let x be the molar concentration of NH₃ at equilibrium. Then, we can write:
Kc = (x)² / (0.21)³(0.015)1.7 × 10² = x² / 1.84 × 10⁻⁶x² = 3.128 × 10⁻⁴x = 0.017 M or 0.17 M (since there are two NH₃ molecules produced for every three H₂ molecules consumed, we take the square root of the calculated value to get the molar concentration of NH₃)
Therefore, the molar concentration of NH₃ in the equilibrium mixture is 0.17 M.
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Determine the number of moles in 100,0 g S
Answers
The number of moles in 100g of Sulphur is 3.13 moles.
How to calculate number of moles?The number of moles in a substance can be calculated by dividing the mass of the substance by its molar mass as follows:
moles = mass ÷ molar mass
According to this question, there are 100g of Sulphur. Sulphur has an atomic mass of 32g/mol. The moles of this element can be calculated as follows;
moles = 100g ÷ 32g/mol
moles = 3.13moles
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Assuming that ground water flow does follow the contours of the land, is it possible that there are two sources of contamination? What would you expect to find if all three companies had leaking storage tanks and were actual sources of contamination?o
Answers
If ground water flow follows the contours of the land, it is possible that there are two sources of contamination.
This can occur if there are multiple locations of contamination that are not connected through the flow of groundwater. For example, if two companies had leaking storage tanks on opposite sides of a hill, the contaminants from each site could flow in different directions and not mix with each other.
If all three companies had leaking storage tanks and were actual sources of contamination, we would expect to find that the groundwater near each company contained contaminants associated with that company's stored chemicals. The contaminants may be different for each company, depending on the type of chemicals stored.
However, if the contamination has been ongoing for a long time, the chemicals may have mixed together in the groundwater, making it difficult to identify the specific source of contamination for each chemical. In this case, further investigation would be needed to determine the specific sources and extent of contamination from each company.
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Numbers placed in front of formulas in an aquation are called
Answers
If you added 50.0 grams of MgSO4 7H₂O to 1.60 liters
of water, what would be the concentration of the
resulting solution? Assume the addition of the 50.0
grams has no significant impact on the volume. (Solutions problem)
Answers
The concentration of the resulting solution, given that 50.0 grams of MgSO₄.7H₂O were added to 1.60 liters of water is 0.127 M
How do i determine the concentration of the solution?First, we shall obtain the mole of 50 grams of MgSO₄.7H₂O. This is given below:
Mass of MgSO₄.7H₂O = 50 gramsMolar mass of MgSO₄.7H₂O = 246 g/molMole of MgSO₄.7H₂O =?Mole = mass / molar mass
Mole of MgSO₄.7H₂O = 50 / 246
Mole of MgSO₄.7H₂O = 0.203 mole
Finally, we shall determine the concentration of the solution. Details below:
Mole of MgSO₄.7H₂O = 0.203 mole Volume = 1.60 LitersConcentration of solution = ?Concentration = mole / volume
Concentration of solution = 0.203 / 1.60
Concentration of solution = 0.127 M
Thus, the concentration of the solution is 0.127 M
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What is the numerical value of Kc
for the following reaction if the equilibrium mixture contains 0.032 M
N2O4 and 0.24 M NO2?
N2O4(g)⇌2NO2(g)
Answers
Kc = [NO2]^2 / [N2O4]
Where [NO2] and [N2O4] are the molar concentrations of NO2 and N2O4, respectively, at equilibrium.
Substituting the given equilibrium concentrations into the expression for Kc, we get:
Kc = (0.24 M)^2 / (0.032 M) = 1.8 M
Therefore, the numerical value of Kc for the given reaction, when the equilibrium mixture contains 0.032 M N2O4 and 0.24 M NO2, is 1.8 M.
shapes of simple polyatomic molecules
Answers
Answer:
Polyatomic molecules that are linear in shape are known as linear polyatomic molecules. The atoms in these linear molecules are arranged in a straight line (at an angle of 180 degrees). At the central atom of linear geometry polyatomic molecules, the electron pair has sp hybridization.
Calculate the molar solubility, S , of CuS if it has a Ksp value of 6×10−37.
Answers
The molar solubility of CuS is 7.8 x 10⁻¹⁹ M.
The solubility product expression for CuS is:
Ksp = [Cu²⁺][S²⁻]Since CuS dissociates to form one Cu²⁺ ion and one S²⁻ ion, the molar solubility of CuS can be represented as x. Therefore, at equilibrium:
[Cu²⁺] = x[S²⁻] = xSubstituting these values in the Ksp expression:
Ksp = x²Solving for x, we get:
x = √(Ksp) = √(6 x 10⁻³⁷) = 7.8 x 10⁻¹⁹ MTherefore, the molar solubility of CuS is 7.8 x 10⁻¹⁹ M.
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The complete question is:
Calculate the molar solubility, S , of CuS if it has a Ksp value of 6×10⁻³⁷.
A soft drink contains 33g of sugar in 349g of H2O. What is the concentration of sugar in the soft drink in mass precent?
Answers
The concentration of the sugar in the soft drink in mass percent is 8.64%
How do i determine the concentration in mass percent?First, we shall determine the mass of the solution. Details below:
Mass of sugar = 33 gramsMass of water = 349 gramsMass of solution =?Mass of solution = Mass of sugar + mass of water
Mass of solution = 33 + 349
Mass of solution = 382 grams
Finally, we shall determine the mass percent of the sugar in the solution. Details below:
Mass of sugar = 33 gramsMass of solution = 382 gramsPercentage of sugar =?Percentage = (mass of sugar / mass of solution) × 100
Percentage of sugar = (33 / 382) × 100
Percentage of sugar = 8.64%
Thus, we can conclude that the mass percent of the sugar is 8.64%
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The nitrogen pressure at the Venusian surface is 2050 torr and the atmosphere of Venus is 3.0 mole% N2. What is the surface pressure on Venus in atm?
Answers
P = nRT/V
where P is the pressure, n is the number of moles, R is the gas constant, T is the temperature, and V is the volume.
First, we'll find the number of moles of nitrogen in the atmosphere:
n(N2) = 3.0/100 x n(total)
where n(total) is the total number of moles in the atmosphere.
Next, we'll rearrange the ideal gas law to solve for P:
P = nRT/V
We can assume that the volume is 1 mole of gas at STP, which is 22.4 L. The temperature on Venus is around 735 K. The gas constant is 0.08206 L atm/mol K.
Plugging in the values, we get:
P = (0.03)(0.08206)(735)/22.4
P = 0.679 atm
Therefore, the surface pressure on Venus is approximately 0.679 atm.
how many grams of MgCl2 are contained in 0.50 L kc a 1.5 m solution?
Answers
0.50 L of a 1.5 m solution contains 71.4 grams of MgCl2.
To solve this problemThe equation moles of solute = molarity x volume (in liters) can be used.
When converting to grams, we may use the molar mass of the MgCl2 to determine how many moles there are in the solution.
MgCl2 has a molar mass of roughly 95.21 g/mol.
The volume must first be changed from liters to milliliters:
0.50 L = 500 mL
Next, we may determine how many moles of MgCl2 are present in the solution:
moles of MgCl2 = molarity x volume (in liters)
moles of MgCl2 = 1.5 mol/L x 0.50 L
moles of MgCl2 = 0.75 moles
Finally, we can figure out how much MgCl2 is present in the solution:
mass of MgCl2 = moles of MgCl2 x molar mass
mass of MgCl2 = 0.75 moles x 95.21 g/mol
mass of MgCl2 = 71.4 grams
Therefore, 0.50 L of a 1.5 m solution contains 71.4 grams of MgCl2.
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Why are some Hydro flow rolling pins HFO refrigerants classified as a a2l
Answers
Hydro flow rolling pins HFO refrigerants classified as a A2L because they contain a fluorine.
Some Hydro Fluoro Olefin (HFO) refrigerants are classified as A2L according to the ASHRAE (American Society of Heating, Refrigerating, and Air-Conditioning Engineers) classification system for refrigerants. The "A" in A2L stands for "lower toxicity," and the "2" indicates "lower flammability."
The classification of refrigerants is based on their potential toxicity and flammability. A2L refrigerants are considered to have lower toxicity and lower flammability compared to other types of refrigerants. They have specific thermodynamic properties that make them suitable for use in refrigeration and air conditioning systems.
Fluorine makes HFO refrigerants less flammable than hydrochlorofluorocarbons (HCFCs) and hydrofluorocarbons (HFCs). which are highly flammable. A2L refrigerants have lower global warming potential (GWP) and ozone depletion potential (ODP), which makes them a more sustainable choice for certain applications.
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Hydro flow rolling pins HFO refrigerants are a type of refrigerant used in air conditioning systems. The 'a2L' is a safety classification from ASHRAE that indicates these refrigerants are mildly flammable but have lower flammability. Such classifications are used for safety considerations.
Explanation:The Hydro flow rolling pins HFO refrigerants are designed for use in refrigeration and air conditioning systems. An HFO refrigerant is a hydrofluorolefin refrigerant; they are a new class of refrigerants that have a very low planet-warming potential.
The designation a2L is actually a safety classification set by ASHRAE (American Society of Heating, Refrigerating and Air-Conditioning Engineers) and it means that these refrigerants are mildly flammable but exhibit lower flammability. The '2' indicates that the refrigerant has low flammability and the 'L' means it has a lower burning velocity. These classifications inform technicians and engineers about the safety considerations they need to be aware of when handling and working with these substances.
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A sample of gas occupies 50.0L at 15.0 Cand 640.0 mmHg pressure. What is the volume at STP?
Answers
Answer:
2.00 L of a gas is collected at 25.0°C and 745.0 mmHg
Explanation:
concept of hybridization in chemistry
Answers
Answer:
Hybridization is the process in which two complementary single-stranded DNA and/or RNA molecules bond together to form a double-stranded molecule.
Explanation: Hope it helps you:)))))
Have a good day.
A soft drink contains 33g of sugar in 349g of H2O. What is the concentration of sugar in the soft drink in mass percent?
.
Answers
A soft drink contains 33g of sugar in 349g of H[tex]_2[/tex]O. 14.3% is the concentration of sugar in the soft drink in mass percent.
One approach to indicate the concentration of any dissolved component in a solution is by mass percentage. Mass percentage is the ratio of the total weight of a compound in a solution to the overall mass of the solution, expressed in percentages.
In order to express the mass percent of a solution, the grammes of solute are divided by the grammes of solution, and the result is multiplied by 100. As long as you use a comparable number for both the component and solute mass.
Mass percent = (mass of solute/mass of solute+ mass of solvent)×100
= ( 33/ 33+ 349)×100
=14.3%
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A solution of KNO3 is prepared by dissolving 80 g KNO3 in 100 g water at 60oC. The solution is
Group of answer choices
dilute
saturated
unsaturated
supersaturated
Answers
The solubility of KNO3 in water at 60°C is 110 g per 100 g of water. Since only 80 g of KNO3 was dissolved in 100 g of water, the solution is unsaturated.
Therefore, the answer is unsaturated.
How many moles do 235.5 liters of carbon dioxide
Answers
Gas legislation
PV = nRT
where P is atmospheric pressure
Volume (measured in litres)
The number of moles is n.
R = gas constant (0.0821 L atm/(mol K))
Temperature (in Kelvin) equals T.
We need to rearrange the ideal gas law to solve for n:
n = PV / RT
To use this equation, we need to know the pressure, temperature, and volume of the carbon dioxide.
0.002355 moles of carbon dioxide are equal to 235.5 litres of the petrol. As a result, 0.002355 moles of carbon dioxide are equivalent to 0.053 litres.
This is because 1 mole of carbon dioxide is equal to 22.4 litres. This indicates that there are 0.002355 moles of carbon dioxide for every 0.053 litres of carbon dioxide.
Therefore, there are 0.002355 moles of carbon dioxide in 235.5 litres of carbon dioxide.
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