Help please I’m so lost on this. I really need help. I can’t get any of the questions ):

Answer:

15 hour(s) and 30 minute(s).

Step-by-step explanation:

Answer:

krkrkrl4k3?8999kekek

Step-by-step explanation:

the UK. I have been a while. I have been a while. I have been a while. I have been a while 6e5 the UK. I have been a while. I have been a while. I have

. How do we have a look at the moment. The comments for the first time in the UK. I

Answer:

The final result is 7/10

the "divisions" (divisor) is 1/10

thus the answer is 7/10 ÷ 1/10

the actual operation ....

"to divide fractions we INVERT and Multiply"

7/10 * 10/1 = 70/10 = 7

there are 7 arrows going to the right

Step-by-step explanation:

Answer: b and c

a) 5x + 5 = -4x - 5

9x = - 10

x = -10/9

-

b) - 4x + 5 = -4x - 4

0x = -9 (no solution)

-

c) -4x + 5 = -4x - 5

0x = -10 (no solution)

-

d) 4x + 5 = -4x + 5

8x = 0

x = 0

-

hope it helps.

Also, I think that Brainly is an awesome app, but there's an app which is doing great work for me in maths, named Gauthmath. I will suggest it. Video concepts and answers from real tutors.

Answer:

6x+y=30

-9x+3y=-18

Solving by substitution means that you have to express one of the variables (from one the equations) through the other one and substitute in the second equation.

In this example it is easier to express y through x in the first equation: y=30-6x. Put the expression for y in the second equation and solve for x.

-9x+3(30-6x)=-18 (divide by -3)

3x-30+6x=6

9x=36

x=4,  

y=30-6x=30-24=6

Step-by-step explanation:

Answer:

c: y=(x-1)(x-3)

Step-by-step explanation:

Given:

In quadrilateral EFGH, [tex]FG\parallel EH,\angleE\cong \angle H,EF=4n-4,FG=3n+3, GH=2n+6[/tex]

To find:

The length of segment GH.

Solution:

Draw a figure according to the given information as shown below.

In quadrilateral EFGH, [tex]FG\parallel EH,\angleE\cong \angle H[/tex], it means the quadrilateral EFGH is an isosceles quadrilateral because base angles are equal.

Now, quadrilateral EFGH is an isosceles quadrilateral, so the sides EF and GH are equal.

[tex]EF=GH[/tex]

[tex]4n-4=2n+6[/tex]

[tex]4n-2n=4+6[/tex]

[tex]2n=10[/tex]

Divide both sides by 2.

[tex]n=\dfrac{10}{2}[/tex]

[tex]n=5[/tex]

Now,

[tex]GH=2n+6[/tex]

[tex]GH=2(5)+6[/tex]

[tex]GH=10+6[/tex]

[tex]GH=16[/tex]

Therefore, the correct option is C.

Answer:

the answer is C

Step-by-step explanation:

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Answer:

A. 2(I + w)

Step-by-step explanation:

The space bounded by a rectangle is its perimeter. So, I would use 2(l + w) where l = length of rectangle and w = width of rectangle.

As an example, suppose we have a rectangle of length, l = 40 meters and width, w = 20 meters and seek to find its perimeter that is, the space bounded by the rectangle, we substitute the values of l and w into the equation for the perimeter.

So, P = 2(l + w)

substituting the values of l and w into the equation, we have

P = 2(l + w)

P = 2(40 m + 20 m)

P = 2(60 m)

P = 120 m

So the space bounded by the rectangle is 120 m.

So, to find the space bounded by a rectangle, we use 2(l + w).

So, the answer is A.

Answer:

?=83 degrees

Step-by-step explanation:

74+120=194

360-194=166

166÷2=83

You divide by two because it is an inscribed angle, so it will always be half the measure of the arc it is inscribing or enclosing.

Answer:

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Step-by-step explanation:

Smith overtakes the bus at (2/3)×60=40 minutes

A body is said to have speed v if he travels v distance in unit time.

Suppose that Smith overtakes the bus at a time 't'. Then the distance traveled by bus is 48×t m and that by Smith is 64×(t-1/6).

Smith needs t-1/6 hours to reach the same position that the bus is in.

Since Smith leaves ten minutes later hence it takes t-1/6 hours for him to overtake the bus.

Because 10 minutes is equal to 10/60=1/6 hour.

So,

48×t=64×(t-1/6)

⇒t=2/3

Hence, Smith overtakes the bus at (2/3)×60=40 minutes

Learn more about speed and distance here-

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Answer:

Um

Step-by-step explanation:

Its half of diameter

Are you thinking of circumference and area?

Given equation of the Circle is ,

[tex]\sf\implies x^2 + y^2 = 25 [/tex]

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

[tex]\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2[/tex]

Here we can say that ,

• Radius = 5 units

• Centre = (0,0)

Finding distance between the two points :-

[tex]\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }[/tex]

Here we can see that the distance of point from centre is less than the radius.

Hence the point lies within the circle .

Answer:

21.45 oz

Step-by-step explanation:

(16.5*0.3)+16.5=x

(4.95)+16.5=x

21.45

Answer:

top x-16.5

bottom 16.5

Step-by-step explanation:

im right

Answer:

the picture I've given is an answer

Answer:

2,-12

Step-by-step explanation:

The given equation is ,

[tex]\implies |x + 5 | = -7 [/tex]

We know that modulus only gives positive value , Therefore on squaring both sides we have ,

[tex]\implies (x + 5 )^2=( -7)^2 \\\\\implies (x+5)^2=7^2\\\\\implies x + 5 =\pm 7 \\\\\implies x = 7-5,-7-5 \\\\\implies \boxed{ x = 2, -12} [/tex]

They have a total time of 3 hours and they equally spend at each exhibit which means that they spent 18 minutes on each exhibit.

The four fundamental operations of arithmetic are addition, subtracting, multiplying, and dividing two or more numbers. Included is the study of integers, especially the order of operations, which is essential for all other aspects of mathematics, notably algebra, information management, and geometry.

As per the given information in the question,

Total time = 3 hours

Time in minutes = 3 × 60 = 180 minutes

They have 10 exhibits to visit.

The time spent on each exhibit is,

180/10 = 18 minutes on each exhibit.

To know more about arithmetic operations:

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Answer:

Multiply to -63

and add to -2

Step-by-step explanation:

I'm a genius.

Answer:

(x - 9)(x + 7)

Step-by-step explanation:

Given

x² - 2x - 63

Consider the factors of the constant term (- 63) which sum to give the coefficient of the x- term, that is

numbers that multiply to give - 63 and add to give - 2

The factors are - 9 and + 7 , since

- 9 × 7 = - 63 and - 9 + 7 = - 2 , then

x² - 2x - 63 = (x - 9)(x + 7) ← in factored form

Answer:

domain=1

range= -2

hope it helps

Answer:

In picture

Step-by-step explanation:

Brianliest please~

Answer:

1.0246

Step-by-step explanation:

100*1.09 = 109

109*0.94 = 102.46

102.46% = 1.0246

Answer:

the area is 279 mm squared

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

[tex] \large{ \tt{❃ \: TAKING \: \angle \: \: A \: AS \: A \: ANGLE \: OF \: REFERENCE : }}[/tex]

[tex] \large{ \tt{❁ \: sin \: 60 \degree = \frac{perpendicular}{hypotenuse} }}[/tex]

[tex] \large{ \tt{➝ \: \frac{ \sqrt{3} }{2} = \frac{6}{y} }}[/tex]

[tex] \large{ \tt{➝ \sqrt{3}y = 6 \times 2 }}[/tex]

[tex] \large{ \tt{➝ \: \sqrt{3} \: y = 12 }}[/tex]

[tex] \large{ \tt{➝ \: y= \frac{12}{ \sqrt{ 3} } }}[/tex]

[tex] \boxed{ \large{ \tt{➝ y = \: 4 \sqrt{3} }}}[/tex]

[tex] \large{ \tt{❇ \: TAKING \: \angle \: B \: AS \: THE \: ANGLE \: OF \: REFERENCE}} : [/tex]

[tex] \large{ \tt{❊ \: sin \: 30 \degree = \frac{perpendicular}{hypotenuse} }}[/tex]

[tex] \large{ \tt{⟶ \: \frac{1}{2} = \frac{x}{4 \sqrt{3} } }}[/tex]

[tex] \large{ \tt{⟶ \: 2x = 4 \sqrt{3} }}[/tex]

[tex] \large{ \tt{⟶ \: x = \frac{4 \sqrt{3} }{2} }}[/tex]

[tex] \boxed{\large{ \tt{⟶ \: x = 2 \sqrt{3} }}}[/tex]

[tex] \boxed{ \large{ \tt{❈ \: OUR \: FINAL \: ANSWER : \boxed{ \tt \: x = 2 \sqrt{3} \: \: y = 4 \sqrt{3} }✓}}}[/tex]

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Answer:

x=-3 and y=-2

Step-by-step explanation:

let the numbers be x and y

x+y=-5

x-y=-1

therefore x=-5-y

-5-y-y=-1

-2y=-1+5

-2y=4

y=-2

×=-5-(-2)

x=-5+2

x=-3

Answer: -2 and -3

Step-by-step explanation:

x + y = -5

x - y = -1 -> x = y - 1

(y - 1) + y = -5

y - 1 + y = -5

2y = 1 - 5

2y = -4

y = -2

x = y - 1 = -2 - 1 = -3

Answer:

[tex]g(-2)=20[/tex]

Step-by-step explanation:

Given [tex]g(x)=2x^2-2x+8[/tex], substitute what is in the parentheses for [tex]x[/tex] to find an output.

For [tex]g(-2)[/tex], the term [tex]-2[/tex] is in the parentheses. Thus, substitute [tex]x=-2[/tex] into [tex]2x^2-2x+8[/tex] to find [tex]g(-2)[/tex]:

[tex]g(-2)=2(-2)^2-2(-2)+8,\\g(-2)=2\cdot 4+4+8,\\g(-2)=8+4+8,\\g(-2)=\boxed{20}[/tex]

Answer:

a) 8

b) 20

c) 20

Step-by-step explanation:

a) Insert X=0 from g(0) to the equation: 2(0) power of 2 - 2x0 +8.

b) Insert X=(-2) from g(-2) to the equation: 2(-2) power of 2 - 2x(-2) +8.

c) Insert X=3 from g(3) to the question 2(3) power of 2 - 2x3 +8.

Answer:

810

Step-by-step explanation:

(-5)×(-6) = 30

9*3 = 27

27*30 = 810

Step-by-step explanation:

V = πr²h

V = 3 × 14² × 28

v = 16464cm³

Answer:

12

Step-by-step explanation:

Multiply to get the number of girls they've given you.

3 x 6 = 18 girls.

2 x 6 = 12 boys.

Answer:

Number of boys = 12

Step-by-step explanation:

Let the total number of children in the class be x

Number of girls = 18

Number of boys = x - 18

Ratio of girls and boys = 3 : 2

Sum of the ratio = 5

Find the value of x

[tex]\frac{3}{5 } \times x = 18\\\\3 \times x = 18 \times 5\\\\x = \frac{90}{3} = 30[/tex]

Therefore, total number of children in the class = 30

Hence number of boys  = x - 18 = 30 - 18 = 12