HELP PLEASE ITS DUE TOMORROW I NEED A PARAGRAPH
Objects in our solar system, including planets and their moons, stay in orbit because
of gravity and inertia. Draw a model to show how each factor contributes to the
orbits of a planet and a moon orbiting that planet. Include the following in your
model:
Labeled arrows to represent gravity and inertia
• The paths the planet and the moon take during their orbits
. A brief summary of your model
.

The roots of given equations can be solved by calculus and the intersection of the 3 equations are at the origin i.e (0,0)

The roots of x=tan(x) :

The solution is the x-value of the point of intersection.

x = 69.05396782n, 4.49340945+69.05396782n,7.72525183+69.05396782n,14.06619391+

69.05396782n,20.37130295+69.05396782n,26.66605425 +69.05396782n,42.38791356 +69.05396782n

, for any integer n

Graph the line using the slope and y-intercept, or two points.

Slope:

1

y-intercept: (0,0)

x          y

0         0

1           1

Graph the trigonometric function using the amplitude, period, phase shift, and vertical shift.

Vertical Asymptotes: x = pi/2 + pi.n ,for any integer n

Amplitude: None

Period: π

Therefore, the intersection is origin here.

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The average speed of the car is 50 km/h and in miles per hour it is 31.0686 miles.

Average speed can be defined as the total distance travelled by an object in a particular time period. This is a scalar quantity. The SI unit of average speed is meter per second.

A. Distance travelled in half an hour = 25km

Therefore, the distance covered in an hour = 25 × 2 = 50km

The speed of the car will be 50km/hr

B. The in average speed miler per hour will be:

1km = 0.621371miles

50km = 31.0686 miles

The speed will be 31068 miles per hour.

C. Speed of cheetah = 25m/s

If, the time is 5 seconds then the distance covered by the cheetah with this speed will be:

Speed = Distance/ Time
25 = D/ 5

Distance = 25 × 5

Distance = 125 meters

D. Distance travelled in 1 minute = 60 seconds will be:

Speed = Distance/ Time

25 = D/ 60

Distance = 25 × 60

Distance = 1500 meters

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The center of gravity of a three-dimensional rigid object is an important concept in physics and engineering for several reasons like stability, Dynamics, Design, Lifting and handling, etc.

Stability: The CoG of an object determines its stability. An object is considered stable if its CoG is located above its support base. If the CoG is not located above the support base, the object is considered unstable.

Dynamics: The CoG is used in the study of the dynamics of objects in motion. The CoG of an object is used to determine the forces and their reactions to those forces.

Design: in the design of objects, especially in engineering the location of the CoG can affect the stability, balance, and efficiency of an object, and it is often optimized during the design process.

Lifting and Handling: The CoG is used to determine the best way to lift and handle an object. If the CoG is known, it is easier to determine the most efficient and safe way to lift and move the object, reducing the risk of injury or damage.

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The basketball player must be moving at approximately 10.5 m/s to jump 1.9 m.

To calculate the speed the player must be moving at to jump 1.9 m, we need to use the equation of motion for vertical motion under acceleration due to gravity. This equation is:

v^2 = u^2 + 2as

where:

v = final velocity (speed)

u = initial velocity (speed)

a = acceleration due to gravity (9.8 m/s^2)

s = vertical distance (1.9 m)

Since the player is jumping vertically from rest (u = 0), the equation becomes:

v^2 = 2as

Substituting in the values for a and s:

v^2 = 2 * 9.8 * 1.9

v^2 = 37.24

Taking the square root of both sides:

v = sqrt(37.24)

v = approximately 6.1 m/s

So, the player must be moving at approximately 6.1 m/s the instant her foot leaves the ground to jump 1.9 m.

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The correct answer is 4 numbers of angles to measure to map out the position of a sky object at any particular time.

What is Degrees (°) are the units used by astronomers?

Degrees (°) are the units used by astronomers to measure the "angular distance" between celestial objects. There are 90 degrees between any point on the horizon and the highest top of the sky because a circle has 360 degrees.

So we can conclude there are 4 number of angles as 90 arc minute in sky object.

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The distance between Priya's home and office is 70 km. This can be found by using the time-distance-speed formula and equating the distances she traveled when she traveled at 40 km/hr and 60 km/hr.

We can use the time-distance-speed formula to solve for the distance between Priya's home and office. The formula is given by:

distance = speed * time

Let's call the distance between Priya's home and office "d".

When she travels at 40 km/hr, she reaches her office 20 minutes late, so the time she took to travel is given by:

time = (60 minutes/hour) + 20 minutes = 80 minutes

time = 80 minutes / 60 minutes/hour = 1 hour and 20 minutes

So the distance she traveled is given by:

d = 40 km/hr * (1 hour + 20 minutes / 60 minutes/hour)

d = 40 km/hr * 1.3333 hours

Similarly, when she travels at 60 km/hr, she reaches her office 10 minutes early, so the time she took to travel is given by:

time = (60 minutes/hour) - 10 minutes = 50 minutes

time = 50 minutes / 60 minutes/hour = 0.83 hours

So the distance she traveled is given by:

d = 60 km/hr * 0.83 hours

Equating the two distances we have:

40 km/hr * 1.3333 hours = 60 km/hr * 0.83 hours

Solving for d we find that:

d = 70 km

So the answer is D) 70 km.

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Answer:

Explanation:The question is about the diffusion of humans, traveling at a speed of

v

=

1

km/year

, attempting to migrate to China over a distance of

d

=

10000

km

. The time taken is obtained as:

t

=

d

v

=

10000

km

1

km/year

=

10000

years

.

We are asked to provide the answer in centuries. Noting that 1 century is equivalent to 100 years, we write the time required as:

10000

years

100

years/century

=

100

centuries

Answer:

the force F2 has a magnitude of 45.5 N and a direction of 128.7° counterclockwise from the x-axis

Explanation:

To determine the second force (F2), we can use vector addition.

Starting from F1=25 N west, we add F2 in the opposite direction of the resultant (40 N south) until the vectors sum to the desired resultant:

F1 + F2 = 40 N south

25 N west + F2 = 40 N south

To find F2, subtract F1 from both sides:

F2 = 40 N south - 25 N west

Using the Pythagorean theorem, the magnitude of F2 can be found as follows:

F2 = √(F2x^2 + F2y^2) = √((-25)^2 + 40^2) = √(625 + 1600) = √2125 = 45.5 N

The direction of F2 can be found using inverse tangent:

Θ = atan2(F2y, F2x) = atan2(40, -25) = 128.7° (measured counterclockwise from the x-axis)

Over 118 elements have been identified and placed on the periodic table, including unstable elements made artificially in accelerators. Since 1993, a number of new elements have been discovered or synthesized in the laboratory, but the exact number may have changed.

There are more than 118 components in the occasional table, including some that were made falsely in labs. This number has expanded since the time the DOE handbook was written in 1993. The disclosure of new components is a continuous interaction, and researchers are continually attempting to find and recognize new components. Nonetheless, it's difficult to give a precise number of the number of new components that have been found starting around 1993, as the field of science is continuously developing and new disclosures are being made. In this way, any reasonable person would agree that the occasional table has extended starting around 1993, and more components might be included what's in store.

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The peak current in a 5.6 k resistor connected to a 120 v rms ac source   Is 0.03 Amp.

The peak current is the maximum amount of current which output is capable of sourcing for brief periods of time. When a power supply or an electrical device is first turned on, high initial current flows into the load, starting at zero and rising until it reaches a peak value, known as the peak current.

Vrms = 120v , R = 5600 ohm

Peak current = Ip

                      = peak voltage /resistance = Vp/R

Also Vp = Vrma × √2

=) Ip = Vrms ×√2 /R

       = 120√2/5600 = 0.0303 A

=) Ip = 0.03A

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The minimum coefficient of static friction that keeps the people from slipping down is 0.162.

Radius of the room, or radius of the rotation, R = 5.1 m

Rotation frequency, ω = 0.55 revolution/sec

ω = 2π×0.55 = 3.46 rad/sec

Then linear speed, v = rω = 5.1 × 3.46

v = 17.6 m/s

Let the mass of the person, = m

Let the minimum coefficient of static friction, = μ

Wall reaction will provide the normal reaction, N = mv²/r

Weight of the person will be balanced by the friction force, mg = μN

μmv²/r = mg

μ = rg/v²

μ = 5.1×9.81/17.6²

μ = 0.162

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Answer:

A1 = π R^2        original area

A2 = π (R + ΔR)^2        area of hole increased in radius by ΔR

A2 - A1 = π (2 R ΔR + ΔR^2) change in area due to heating

Δ A = π 2 R ΔR           ΔR^2 is small and will be omitted

ΔR = R c ΔT        where ΔT is the temperature change

Thus the coefficient of area expansion is twice that of the coefficient of linear expansion

Answer:

45 km per hour due east

Explanation:

it has bot magnitude and direction

The equation for angular magnification and telescope length is used even if a diverging lens is used as an eyepiece.

A telescope is a tool that astronomers use to see far-away objects by using a curved mirror. The work of the mirror is to gather, collect and focus the light from the night sky and enable us to see the objects far away in the sky. In the early stages of the development of telescopes,  the focusing of light from the sky used to take place by the use of a piece of curved, clear glass called lenses. But now mirrors are used in place of lenses, as mirrors are lighter and easier to make perfectly smooth. These types of telescopes are called reflecting lens telescope. While others are called refracting lens telescopes.

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The distance traveled is not equal to the magnitude of displacement in the following examples: Rabbit returns home after going to eat dandelions 5 m away.

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The drop in pressure was greater in Fairbanks than compared to Key West.

Troposphere: The troposphere is Earth's lowest atmosphere layer. The troposphere contains approximately 75-80% of the atmosphere's mass. The troposphere is home to the majority of cloud types and virtually all weather.

In the troposphere, 2 km above the surface of Fairbanks is higher than 2 km above the surface of Key West. As a result, the density of the air in Fairbanks is significantly lower than that of Key West. When the air is less dense in cold temperatures, the pressure falls more quickly in Fairbanks compared to the pressure drop in Key West.

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The steady-state current in the inductor has a maximum amplitude of 10 A.

Calculate the inductance of the inductor by using the formula L = V/(ωI), where V is the voltage (100 V), ω is the angular frequency (2πf, where f is the frequency (370 Hz)), and I is the current (10 A):

L = 100 V/(2π(370 Hz) (10 A)) = 6.82 mH

Calculate the reactance of the inductor by using the formula X = 2πfL, where f is the frequency (370 Hz) and L is the inductance (6.82 mH):

X = 2π(370 Hz) (6.82 mH) = 1010 Ω

Calculate the peak current of the steady-state current by using the equation I_p = V/X, where V is the voltage (100 V) and X is the reactance (1010 Ω):

I_p = 100 V/1010 Ω = 0.099 A

Calculate the maximum amplitude of the steady-state current by multiplying the peak current (0.099 A) by √2:

I_max = 0.099 A × √2 = 0.14 A = 10 A

Hence, The maximum amplitude of the steady-state current in the inductor is 10 A.

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The conductivity of the substance containing free electrons is calculated to be 7.59 × 10⁹ siemens/m or mho.

Number of free electrons is given as 9 × 10³⁰

Collision time is given as 3 × 10⁻¹⁴ s

Mass of electron is known to be = 9.1 × 10⁻³¹ kg

Charge on electron = 1.6 × 10⁻¹⁹ C

Conductivity of the substance is given by the formula,

σ = (n e² τ)/m

where,

σ is conductivity

n is number of electrons

m is mass of electron

e is charge of electron

τ is time

Putting in the values in the above equation, we have,

σ = [(9 × 10³⁰)(1.6 × 10⁻¹⁹)² (3 × 10⁻¹⁴)]/(9.1 × 10⁻³¹) = (69.12× 10⁻²²)/(9.1 × 10⁻³¹) = 7.59 × 10⁹ siemens/m.

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The spectral type of a star is the characteristic that most directly influences its color.

A star's spectral type determines its color uniquely. A star's color is intimately correlated with its spectral class. also The hue of light emitted by a star depends on its surface temperature. Yellow stars are hotter than red stars, and yellow stars are hotter yet than blue stars. A red dwarf is the most common type of star. Spectral classes are divided into seven categories. These seven spectral classes are denoted by the letters O, B, A, F, G, K, and M, ranging from hottest to coolest. Recently, three other classes—L, T, and Y—have been introduced by astronomers for even cooler objects.

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The value of escape velocity will be 2.38 Km/s

The minimal speed necessary for an object to liberate itself from the gravitational attraction imposed by a big object is defined as escape speed, also known as escape velocity.

Escape velocity is the minimal velocity necessary to overcome a big body's gravitational potential and escape to infinity.

The velocity at which an item circles around a huge body is referred to as orbital velocity.

The escape speed from the moon can be calculated using the formula:

[tex]v_{escape = \sqrt{(2GM/r)[/tex]

Where G is the gravitational constant (6.67x10^-11 N.m^2/kg^2),

M is the mass of the moon (7.36x10^22 kg), and

r is the radius of the moon (1740 km or 1.74x10^6 m).

Plugging in the values, we get:

[tex]v_{escape = \sqrt{(2 \times 6.67 \times 10^{-11} \times 7.36 \times 10^22 / 1.74 \times 10^6)[/tex]

= 2.38 km/s

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The correct answer is A)greater than your normal weight at rest.

When an elevator moves upward, the passengers inside experience a change in their gravitational potential energy. According to the law of conservation of energy, the change in potential energy must be compensated by an equal and opposite change in some other form of energy, such as kinetic energy or thermal energy.

In the case of an elevator, the change in potential energy is compensated by the work done by the elevator's motor, which converts electrical energy into mechanical energy to lift the elevator. The passengers inside the elevator do not experience any change in their weight, as they are still subject to the same gravitational force. However, they do experience a change in their relative position with respect to the Earth's surface, which can result in changes in their apparent weight.

In addition to the change in potential energy, the passengers inside the elevator may also experience changes in their kinetic energy and thermal energy due to the motion of the elevator.

Therefore, The correct answer is A)greater than your normal weight at rest.

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Answer:

The speed of a free electron that has justify barerly enough kinetic energy collisionally ionize a sodium atom in it's ground state is about 5.4eV.

the speed of a free proton with just enough kinetic energy to collisionally ionize this atom is about 6.8eV.

1. The speed of a free electron that has just barely enough kinetic energy to collisionally ionize a sodium atom in its ground state is 2.2 x 10^6 m/s.

2. The speed of a free proton with just enough kinetic energy to collisionally ionize this atom 1.2 x 10^7 m/s.

The ionization potential of a neutral sodium atom is 5.1 eV. This is the minimum amount of energy required to remove an electron from the atom and make it a positive ion.

To calculate the speed of an electron with just enough kinetic energy to ionize the atom, we can use the equation:

E_k = 1/2 * m * v^2

where E_k is the kinetic energy, m is the mass of the electron, and v is its speed. We know that E_k = 5.1 eV, so we can rearrange the equation to solve for v:

v = sqrt(2 * E_k / m)

where m is the mass of the electron, which is approximately 9.11 x 10^-31 kg.

Plugging in the values, we get:

v = sqrt(2 * 5.1 eV / 9.11 x 10^-31 kg)

which is approximately 2.2 x 10^6 m/s.

To calculate the speed of a proton with just enough kinetic energy to ionize the sodium atom, we use the same equation as above, but substitute the mass of the proton (approximately 1.67 x 10^-27 kg) for the mass of the electron:

v = sqrt(2 * 5.1 eV / 1.67 x 10^-27 kg)

which is approximately 1.2 x 10^7 m/s.

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A region has a uniform electric field of 200,000 N/C directed to the Southwest. The electric force on this electron would point southwest (opposite to the direction of the electric field.)

Imagine yourself in an electric field. This field would exert an electric force on a positive point charge placed there. By definition, the field's direction at that location corresponds to the force that it applies to the positive point charge there in terms of electric field.

It should be obvious that the electric field in this area in this query points northeast. A positive point charge would therefore experience an electric force in the same direction—to the northeast—if it were placed in this area.

Negative charge characterizes electrons. An electron would experience electric force in the opposite direction from a positive point charge positioned in the same location. The positive point charge in this area has an electric force that points northeast (same as the direction of the electric field). Southwest is the polar opposite of northeast. Therefore, the direction of the electric field acting on an electron in this location would be southwest

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We only need to multiply 5V by the amount of current the device is drawing from the port because power is equal to current times voltage.

Although the USB port is only designed to handle electricity up to 5 A, certain manufacturers may offer a higher maximum current.

The potential difference in charge between two sites in an electrical field is quantified as voltage, also known as electromotive force.

The amount of charge carriers that pass a fixed point in a unit of time via a conducting or semiconducting medium for a certain flow resistance increases with voltage, i.e., the number of charge carriers that pass a fixed point in a unit of time.

Therefore, We only need to multiply 5V by the amount of current the device is drawing from the port because power is equal to current times voltage.

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The height h of mercury in the right side of the U-tube is 4.37 cm.

The Bernoulli's principle of fluid dynamic states that as a fluid's static pressure or potential energy falls, so too does its speed.

Given,

Rate if volume flow Q = 1200 cm³/s

The broader end diameter D1 = 2.0 cm

The narrower end diameter D2 = 0.4 cm

By using bernoulli's theorem,

1/2pv1² + P1 = 1/2pv2² + P2

P1 - P2 = 1/2pv1² - 1/2pv2²

By using continuity equation,

Q = π(D1²/2)²v1 = π(D2²/2)²v2 = 1200 cm³/s

v2 = 4 × 1200 cm³/s / π × (0.4)² = 9550 cm/s = 95.5 m/s

v1 = 4 × 1200 cm³/s / π × (2)² = 382 cm/s = 3.82 m/s

P1 - P2 = 1/2 p(v2² - v1²)

P1 - P2 = 1/2 × 1.28 kg/m³ × ( (95.5m/s)² - (3.82m/s)² )

P1 - P2 = 5827.6 N/m²

then,

pgh = 5827.6 N/m²

h = 5827.6 N/m² / pg

h = 5827.6 N/m² / 13600 kg/m³ × 9.8 m/s² = 0.0437 m

h = 4.37 cm.

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Q. Air flows through the tube shown in figure below at a rate of 1200 cm³/s. Assume that air is an ideal fluid. What is the height h of mercury in the right side of the U-tube?

The acceleration due to gravity on that planet is 6.13 m/s², if the height of drop of wrench is 1.52 m and time is 0.705 seconds.

Initial velocity of the wrench, u = 0   [initially at rest]

Height travelled by the wrench, h = 1.52 m

Time taken to travel through 1.52 m height, t = 0.705 sec

Let the acceleration due to gravity at that planet is g.

By the second equation of motion,

h = ut + 0.5gt²

1.52 = 0 × t + 0.5 × g × 0.705²

1.52 = 0.248g

g = 1.52/0.248

g = 6.13 m/s²

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Answer:

208333 J (approx)

Explanation:

Work required to stop = Kinetic energy of car

So,

Kinetic Energy = 1/2 * m * v^2

Convert 60 kmh-1 to ms-1

= 1/2 * 1500 * (50/3)^2

= 208333.33 J

If the temperature rises to 28°c, the submerged volume fraction of the cube will increase by 0.2%.

Due to a temperature increase is defined by the following expression:

at 20∘c and then its temperature is increased by 100∘c

When the iron cube if partly immersed in mercury, the buoyant force that is acting on it will be

FB=ρVg where V is the volume of the iron cube immersed in the liquid.

Since we have a constant mass of the iron cube, from the relation of density with mass and volume for the iron cube

ρi=miVi

since the density of the iron block will decrease, to produce the same amount of buoyant force (FB=ρVg), the volume of the iron block immersed in the liquid will have to increase for the cube to not sink in the mercury.

Part (a)

If the temperature rises to 28°c, then the cube will float lower since the submerged fraction is higher (0.580), and before it was 0.578.

Part (b)

If the temperature rises to 28°c, the submerged volume fraction of the cube will increase by 0.2%. In effect, when the temperature was 0°c the submerged fraction was 57.8%, then the temperature increases to 28°c and the submerged fraction is now 58.0%.

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A week after full moon, the moon's phase is third quarter.

In its spherical form, the moon completes one orbit of the Earth every 29.5 days. It's being lit up by the sun from all sides as it rotates. When the moon is in its "new moon" position between the Earth and the Sun, the side of the moon that is facing us is completely in the dark, and is only dimly illuminated by sunlight reflected from the Earth. The side of the Moon that we can see from Earth grows increasingly bright as it orbits the planet. The "third quarter phase" of the moon occurs exactly one week (or 21 days) after the "new moon" phase begins or seven days after full moon. The sun's light is now shining on the opposite half of the moon's visible face.

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The answer to the multiple questions asked on friction, Humidity,  triboelectric effect and static electricity is given below.

14. A-tape (or B-tape) is attracted to a neutral object because the tape acquires a static charge through friction, and like charges repel each other while opposite charges attract. When the charged tape comes near a neutral object, the neutral object acquires an electric charge of the opposite sign, causing an attraction between the charged tape and the neutral object.

15. Humid air makes it difficult to perform experiments with static electricity because the humidity in the air provides a path for the static charge to flow to the ground, thus reducing the charge on the object. This is because water is a good conductor of electricity, allowing the static charge to dissipate more quickly than in dry air.

16. When you rub your fingers on the non-sticky side of A-tape, you transfer some electrons from your fingers to the tape, effectively neutralizing its charge. The triboelectric effect, which is the transfer of electrons from one material to another through friction, can result in a buildup of static charge on the tape. By rubbing your fingers on the tape, you equalize the distribution of electrons between the tape and your fingers, neutralizing the charge on the tape.

17. Clothes taken out of the dryer tend to have a lot of static electricity because of the triboelectric effect. As the clothes rub against each other and the dryer drum during the tumbling and spinning action, they transfer electrons, resulting in a buildup of static charge. Dryer sheets work to eliminate this static charge by releasing positively charged ions into the dryer that neutralize the static charge on the clothes. The positively charged ions are attracted to the negatively charged clothes, effectively reducing the static charge and making the clothes less likely to cling to each other.

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