Answer:
16b > 94
Step-by-step explanation:
16b > 94
b > 5.875
Crystal needs 6 boxes to fit all 94 discs.
Find the producer surplus at the equilibrium point. 3) s(x) = x 3, 0 k x k 3; x = 3
The producer surplus at the equilibrium point is 1.0146
An equilibrium (or equilibrium point) of a dynamical machine-generated via an autonomous machine of everyday differential equations (ODEs) is a solution that doesn't change with time.
Equilibrium is the country in which the marketplace delivers and calls for stability each different, and as a result, expenses turn out to be solid. usually, an over-deliver of products or services reasons charges to head down, which leads to higher demand—at the same time as a below-supply or scarcity reasons costs to head up resulting in fewer calls.
The equilibrium equations (balance of linear momentum) are given in index form as(1.4)σji,j+bi=ρu¨i, I,j=1,2,3where σij are additives of (Cauchy) stress, ρ is mass density, and bi is body force additives.
Producer Surplus = area of shadestportion
Area of shaded portion = free of rect minus area of OneD
Aves of OABO=Now serving from
"[3√74-3/5]
= √(x+3)" de
=2 (2√6-√5)
(Jon= √46 = Fure=456-255
(x+3)+1
Area of rectangle OA BC =316
= 3√6
producer surplus = 3√6 - (ure -2√5)
= 2√3-66
= 1.0146
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Michelle is purchasing fabric for two new sewing projects: a hat and a tote bag. The two projects each need red and black fabric. The hat requires 2 yards of red fabric and 1 yard of black fabric. The tote bag requires 2 yards of red fabric and 4 yards of black fabric. Michelle paid $14 for the hat’s fabric and $26 for the tote bag’s fabric. How much does one yard of each fabric cost?
The cost of one yard of black fabric is $4.
The cost of one yard of red fabric is $5.
What are the linear functions that represent the question?2r + b = 14 equation 1
2r + 4b = 26 equation 2
Where:
r = cost of one yard of red fabric
b = cost of one yard of black fabric
What is the cost of each type of fabric?
Subtract equation 1 from equation 2
3b = 12
b = 12 / 3
b = 4
Substitute for b in equation 1
2r + 4 = 14
2r = 14 - 4
2r = 10
r = 10 / 2
r = $5
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JUST NEED A BIT OF HELP PLS
Step-by-step explanation:
1st : Vector translation.
a vector -8j ( 0 , -8 ) helped translate (x , y) => (x , y - 8)
2nd : rotation.
The only rotation that results in (-x , -y) is pi rotation.
formula : (x , y -8) => ( xcos(pi) - ysin(pi) , xsin(pi) + ycos(pi) )
substitute x & y-8 into x & y respectively of the formula above.
What is the equation of the line that passes through (4, -1) and (-2, 3)?
a.) 2 x + 3 y - 5 = 0
b.) -2 x + 3 y - 5 = 0
c.) 2 x - 3 y - 5 = 0
Answer:
a
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
calculate m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (4, - 1 ) and (x₂, y₂ ) = (- 2, 3 )
m = [tex]\frac{3-(-1)}{-2-4}[/tex] = [tex]\frac{3+1}{-6}[/tex] = [tex]\frac{4}{-6}[/tex] = - [tex]\frac{2}{3}[/tex] , then
y = - [tex]\frac{2}{3}[/tex] x + c ← is the partial equation
to find c substitute either of the 2 points into the partial equation
using (- 2, 3 ) , then
3 = [tex]\frac{4}{3}[/tex] + c ⇒ c = 3 - [tex]\frac{4}{3}[/tex] = [tex]\frac{5}{3}[/tex]
y = - [tex]\frac{2}{3}[/tex] x + [tex]\frac{5}{3}[/tex] ← in slope- intercept form
multiply through by 3 to clear the fractions
3y = - 2x + 5 ( subtract - 2x + 5 from both sides )
2x + 3y - 5 = 0 ← in general form
in how many ways can 20 identical balls be distributed among 5 distinct bins?
Answer:
put four balls in each been
Step-by-step explanation:
ramiro has filled 1/3 or 50 gallons of his fish tank. find the total capacity of the fish tank
Answer:
150
Step-by-step explanation:
because full capacity is 3/3, therefore you time 50 by 3, which will be 150 gallons
Please help with this question asap!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
no solution
Step-by-step explanation:
We can think of an absolute value as the magnitude of the number. We can also define it as how far the number is from 0 on the number line. Thus, absolute value must always be positive (or 0).
Solve
Start by adding 1 to both sides:
[tex]\frac{|m|}{2}=-2[/tex]
Multiply both sides by 2:
[tex]|m|=-4[/tex]
The absolute value of a number is always positive (with the exception of 0), therefore there is no solution.
Additional CommentsNotice we can only add/multiply (or subtract/divide) an equation because of the Addition/Subtraction/Multiplication/Division Property of Equality which state that if you add/subtract/multiply/divide one side of the equation by a certain value, you must do the same to the other side of the equation.
The two lines y = 2x + 8 and y = 2x - 12 intersect the x-axis at the P and Q.
Work out the distance PQ.
Answer:
PQ = 10 units
Step-by-step explanation:
to find where the lines cross the x- axis let y = 0 and solve for x , that is
2x + 8 = 0 ( subtract 8 from both sides )
2x = - 8 ( divide both sides by 2 )
x = - 4 ← point P
and
2x - 12 = 0 ( add 12 to both sides )
2x = 12 ( divide both sides by 2 )
x = 6 ← point Q
the lines cross the x- axis at x = - 4 and x = 6
using the absolute value of the difference , then
PQ = | - 4 - 6 | = | - 10 | = 10 units
or
PQ = | 6 - (- 4) | = | 6 + 4 | = | 10 | = 10 units
Answer: [tex]\Huge\boxed{Distance=10~units}[/tex]
Step-by-step explanation:
Find the point PGiven expression
y = 2x + 8
Substitute 0 for the y value to find the x value
This is the definition of x-intercepts
(0) = 2x + 8
Subtract 8 on both sides
0 - 8 = 2x + 8 - 8
-8 = 2x
Divide 2 on both sides
-8 / 2 = 2x / 2
x = -4
[tex]\large\boxed{P~(-4,0)}[/tex]
Find the point QGiven expression
y = 2x - 12
Substitute 0 for the y value to find the x value
(0) = 2x - 12
Add 12 on both sides
0 + 12 = 2x - 12 + 12
12 = 2x
Divide 2 on both sides
12 / 2 = 2x / 2
x = 6
[tex]\large\boxed{Q~(6,0)}[/tex]
Find the distance between PQGiven information
[tex](x_1,~y_1)=(-4,~0)[/tex]
[tex](x_2,~y_2)=(6,~0)[/tex]
Substitute values into the distance formula
[tex]Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]Distance=\sqrt{(6-(-4))^2+(0-0)^2}[/tex]
Simplify values in the parenthesis
[tex]Distance=\sqrt{(10)^2+(0)^2}[/tex]
Simplify values in the radical sign
[tex]Distance=\sqrt{100}[/tex]
[tex]\Huge\boxed{Distance=10~units}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
pls pls help meee i dont understand the fundamental theorem of algebra
Answer:
Hey! I'm gonna go ahead and give ya the "meaning" of the fundamental theorem of algebra but not the answer to the A. B. and C.
Step-by-step explanation:
fundamental theorem of algebra, theorem of equations proved by Carl Friedrich Gauss in 1799. It states that every polynomial equation of degree n with complex number coefficients has n roots, or solutions, in the complex numbers. The roots can have a multiplicity greater than zero.
PLS HELP ME WITH THIS
Answer:
The first option
Kindly award branliest
what is the sum of (6x^2-x+8) - (x^2+2)
Answer:
5x^2-x+6
Step-by-step explanation:
That should work
Identify the elevation and the percentage of oxygen available at each elevation. 8,850 m 57% 33% 4,500 m 100%
1. Sea level (0 m) - 100%
2. Mid-level elevation (4,500 m) - 57%
3. Peak (8,850 m) - 33%
What does oxygen mean?Oxygen is a colorless, odorless, and tasteless gas necessary for all living things. Animals take it up and then change it into carbon dioxide, which plants then use as a carbon source to release oxygen back into the atmosphere.The energy-producing process that powers the metabolisms of most living organisms, respiration, depends heavily on oxygen. All living things, including humans, depend on oxygen in the air we breathe to survive. The process of photosynthesis is where plants and certain bacteria produce oxygen.Identify the elevation and the percentage of oxygen available at each elevation.
Elevation has a significant impact on the amount of oxygen in the atmosphere. The oxygen level increases with decreasing height and decreases with increasing elevation. Thus, we have a situation where the oxygen concentration is highest at sea level or 0 elevations. The oxygen level drops dramatically when we ascend to greater elevations, say 4,500 m, making breathing difficult. Even at higher altitudes, such as 8,850 m, the oxygen level will drop significantly, making it necessary for a person to undergo extensive training and carry oxygen to survive.
1. Sea level (0 m) - 100%
2. Mid-level elevation (4,500 m) - 57%
3. Peak (8,850 m) - 33%
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What is this expression in simplified form?
4/14 - 11/14
Answer:
baiBsiasbisvdxhsbhssj
Answer:
-1/7
is the answer of your question
Let f (x) = x4 – 2x3 – 3x2 + 4x + 4, g of x is equal to the square root of the quantity x squared minus x minus 2 end quantity and h of x is equal to the quantity negative x squared plus 1 end quantity over the quantity x squared minus x minus 2 end quantity Part A: Use complete sentences to compare the domain and range of the polynomial function f (x) to that of the radical function g(x). (5 points) Part B: How do the breaks in the domain of h (x) relate to the zeros of f (x)? (5 points)
The domain of f(x) is all set of real values while, the domain of g(x) is x ≤ -1 or x ≥ 2 and both functions have the same range
Part A: Compare the domain and range of the function f(x) to g(x)The functions are given as:
f(x) = x^4 - 2x^3 - 3x^2 + 4x + 4
g(x) = √(x^2 - x - 2)
Domain
The polynomial function f(x) has no restriction on its input.
So, the domain of f(x) is all set of real values
Set the radical of g(x) = √(x^2 - x - 2) greater than 0
x^2 - x - 2 ≥ 0
Factorize
(x + 1)(x - 2) ≥ 0
Solve for x
x ≥ -1 and x ≥ 2
Combine both inequalities
x ≤ -1 and x ≥ 2
So, the domain of g(x) is x ≤ -1 or x ≥ 2
Range
Using a graphical calculator, we have:
Range of f(x) = x^4 - 2x^3 - 3x^2 + 4x + 4 ⇒ f(x) ≥ 0Range of g(x) = √(x^2 - x - 2) ⇒ g(x) ≥ 0Hence, both functions have the same range
How do the breaks in the domain of h(x) relate to the zeros of f(x)?We have:
h(x) = (-x^2 + x)/(x^2 - x - 2)
Set the denominator to 0
x^2 - x - 2 = 0
The above represents the radical of the function f(x)
This means that the breaks in the domain of h(x) and the zeros of f(x) are the same
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Complete question
Let f(x) = x^4 - 2x^3 - 3x^2 + 4x + 4, g(x) = √(x^2 - x - 2) and h(x) = (-x^2 + x)/(x^2 - x - 2)
Part A: Use complete sentences to compare the domain and range of the polynomial function f (x) to that of the radical function g(x). (5 points)
Part B: How do the breaks in the domain of h (x) relate to the zeros of f (x)? (5 points)
Does anybody know this? Evaluate the following expression using the correct order of operations.
Answer:
-4
Step-by-step explanation:
Wehn dealing with order of operations, we can remember the expression PEMDAS, which stands for parentheses, exponents, multiplication, division, addition, and subtraction.
So, our first step in the above problem is the parentheses:
[tex]2(3-5)^3+4(-4+7)\\2(-2)^3+4(3)[/tex]
The second step is exponents:
[tex]2(-2)^3+4(3)\\2(-8)+4(3)[/tex]
The third step is multiplication:
[tex]2(-8)+4(3)\\-16+12[/tex]
The fourth and final step is addition:
[tex]-16+12\\-4[/tex]
HELP ME ASAP!!! I WILL GIVE MANY POINTS and
The 8 cm circle radius and the location of the circle X gives the following values;
(a) tan(<XAB) = -(r - 8)/(2•r + 4) = (8 - r)/8
Which gives;
r = (8 - 4)÷2 = 2(b) <XAB is approximately 0.644 radians
(c) The area of the shaded region is approximately 3.107 cm²
Which method can be used to analyze the figure?8 × (8 - r) = 0.5 × 16 × (8 + r) × sin(A)
(8 - r) = (8 + r) × sin(A)
sin(A) = (8 - r)÷(8 + r)
(8 - r)² = 8² + (8 + r)² - 2×8×(8 + r)×cos(A)
16×(8 + r)×cos(A) = (8² + (8 + r)²) - (8 - r)²
Which gives;
cos(A) = ((8² + (8 + r)²) - (8 - r)²) ÷ (16×(8 + r))
cos(A) = (2•r + 4)/(r + 8)
tan(A) = ((8 - r)÷(8 + r))/( (2•r + 4)/(r + 8))
tan(A) = -(r - 8)/(2•r + 4) = (8 - r)/8
(8 - r)/(2•r + 4) = (8 - r)/8
8 = 2•r + 4
2•r + 4 = 8
Therefore;
r = (8 - 4)÷2 = 2(b) sin(A) = (8 - r)÷(8 + r)
sin(A) = (8 - 2)÷(8 + 2) = 0.6
Therefore;
<XAB = <A = arcsin(0.6) ≈ 0.644 rad
<XAB in degrees ≈ 36.87°
Angle at sector PXQ = 180° - 2 × (36.87°) ≈ 106.26°
Area of sector PXQ ≈ (106.26°/(360°)) × π × 2²
(106.26°/(360°)) × π × 2² ≈ 3.71
Area of sector APO ≈ (36.87°/(360°)) × π × 8² ≈ 20.59
Area of triangle AXB = 8 × (8-2) = 48
The shaded area is therefore;
48 - (2×20.59 + 3.71) ≈ 3.107
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a) The radius of the small circle is 2 centimeters.
b) The measure of the angle XAB is approximately equal to 51.340°.
c) The area of the shaded region is approximately equal to 2.423 square centimeters.
How to analyze a system formed by three semicircles and a circle
In this question we must analyze a geometrical system formed by three semicircles and a circle. The small circle touches the two side semicircles tangentially at points P and Q and the uppermost section of it also tangent to the central semicircle (point R).
(a) Therefore, we have to solve the following system of equations:
8² + h² = (8 + r)² (1)
h + r = 8 (2)
By (2) in (1):
8² + (8 - r)² = (8 + r)²
32 · r = 64
r = 2
The radius of the small circle is 2 centimeters.
(b) The measure of the angle XAB is found by trigonometric functions:
tan m ∠ XAB = OX / AO
tan m ∠ XAB = 10 / 8
m ∠ XAB ≈ 51.340°
The measure of the angle XAB is approximately equal to 51.340°.
(c) The area of the shaded region if the area of the triangle AXB minus the areas of the three circular sections, that is:
A = 0.5 · (16 cm) · (10 cm) · sin 51.340° - (51.340° / 180°) · π · (8 cm)² - 0.5 · (77.320° / 180°) · π · (2 cm)²
A ≈ 2.423 cm²
The area of the shaded region is approximately equal to 2.423 square centimeters.
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the value of digit 7 in 906.7
The answer is tenths
Step-by-step explanation:
According to the place value chart of decimals,the first number after the decimal point starts from tenths and continues.so the answer is tenths
Hi :)
Remember Place value in decimal numbers
———————————[tex]\large\boldsymbol{\hfill\stackrel{hundreds}{9}~\hfill\stackrel{tenths}0~\hfill\stackrel{ones}6.\hfill\stackrel{tenths}{7}}[/tex]
Then
The place-value of [tex]\boldsymbol{7}[/tex] is [tex]\boldsymbol{tenths}[/tex].
[tex]\tt{Learn~More;Work~Harder}[/tex]
:)
Quick algebra 1 question for 10 points!
Only answer if you know the answer, quick shout-out to tariqareesha2 and MrBrainly, tysm for the help!
Answer:
B {3/2, -5/3}
Step-by-step explanation:
6x² + x - 15 = 0
6x² + 10x - 9x - 15 = 0
2x(3x + 5) - 3(3x + 5) = 0
(3x + 5)(2x - 3) = 0
3x + 5 = 0 or 2x - 3 = 0
3x = -5 or 2x = 3
x = -5/3 or x = 3/2
Answer: B {3/2, -5/3}
Answer:
[tex]\left\{\dfrac{3}{2},\ -\dfrac{5}{3}\right\}[/tex]
Step-by-step explanation:
Given quadratic equation: [tex]6x^2+x-15=0[/tex]
[tex]\implies a=\textsf{6},b=\textsf{1},c=\textsf{-15}[/tex]
..................................................................................................................................................
[tex]{\large \textsf{ Quadratic Formula: }}x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\ \Bigg{\|}\ \textsf{when }ax^2+bx+c=0[/tex]
..................................................................................................................................................
Step 1: Substitute the given values into the formula and simplify.
[tex]\implies x=\dfrac{-{(\textsf1})\pm \sqrt{\textsf{(1)}^2-4(\textsf{6}){(\textsf{-15})}}}{2{(\textsf{6})}}[/tex]
[tex]\implies x=\dfrac{-1\pm \sqrt{1-4(-90)}}{12}[/tex]
[tex]\implies x=\dfrac{-1\pm \sqrt{1+360}}{12}[/tex]
[tex]\implies x=\dfrac{-1\pm \sqrt{361}}{12}[/tex]
[tex]\implies x=\dfrac{-1\pm 19}{12}[/tex]
Step 2: Separate into two cases.
[tex]x_1=\dfrac{-1+19}{2}[/tex]
[tex]x_2=\dfrac{-1-19}{2}[/tex]
Step 3: Solve both cases.
[tex]\implies x_1=\dfrac{-1+19}{12}=\dfrac{18}{12}=\dfrac{6\times3}{6\times2}=\boxed{\dfrac{3}{2}}[/tex]
[tex]\implies x_2=\dfrac{-1-19}{12}=\dfrac{-20}{12}=\dfrac{-4\times5}{4\times3}=\boxed{-\dfrac{5}{3}}[/tex]
The solutions to this quadratic are: [tex]x_1=\dfrac{3}{2},\ x_2=-\dfrac{5}{3}[/tex]
..................................................................................................................................................
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The volume of a cone is 1,782 cubic centimeters. a cylinder has the same radius and height as the cone. what is the volume of the cylinder?
The volume of the cylinder that has same height and radius with the given cone is 5,346 cm³
What are the 3-D figure?Pyramids and prisms are examples of three-dimensional shapes, as are shapes with curved surfaces. The three-dimensional prism shape has two bases that are parallel and congruent. Any polygon is acceptable for the bases, which are two of the faces. Rectangles make up the remaining faces.
What is the Volume of a Cylinder?Given that the cylinder and the cone have the same radius and height, the volume of a cylinder equals 3 times the volume of a cone.
According to the given figure:
Given, a cone that has a volume of 1,782 cubic cm, has the same radius and height with a cylinder,
therefore,
Volume of the cylinder = 3 x (1,782)
Volume of the cylinder = 5,346 cubic centimeters
Hence, the volume of the cylinder is 5,346 cubic centimeter.
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Write a polynomial of least degree with rational coefficients and with the root
–15+10[tex]\sqrt{6\\}[/tex]
Answer:
p(x) = x² +30x -375
Step-by-step explanation:
When a quadratic has real rational coefficients, any irrational or complex roots come in conjugate pairs.
Factored formA root of p means (x -p) is a factor of the polynomial. Here, we have roots of -15+10√6 and -15-10√6, so the factored form can be written ...
p(x) = (x -(-15 +10√6))(x -(-15 -10√6))
Using the factoring of the difference of squares, we can write this as ...
p(x) = (x +15)² -(10√6)²
Standard formExpanding the factored form, we can write the polynomial as ...
p(x) = x² +30x +225 -600
p(x) = x² +30x -375
With tax included, a couch costs $315. What does the couch cost before tax?
The $315 cost of the couch after tax, gives the cost before tax, C, as the following equation;
[tex]Cost \: before \: tax, \: \: \mathbf {C} = \frac{315}{1 + t} [/tex]
How can the cost before tax be expressed?The cost of the couch with tax = $315
Let, t, represent the tax rate, and let C, represent the cost before tax, we have;
315 = C + C × t
315 = C × (1 + t)Which gives;
The cost of the couch before tax, C = 315/(1 + t)Mathematically, we have the following equation;
[tex]Cost \: before \: tax, \: \: \mathbf {C} = \frac{315}{1 + t} [/tex]
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Miss a turn
Go forward
3 squares
Go back
2 squares
Go back
1 square
Go forward
2 squares
Go forward
3 squares
In a game, a fair spinner has six equal sections
as shown.
a) Noel spins the spinner.
Write down the probability he gets 'Miss a turn'.
Give your answer as a fraction.
(1)
b) The spinner lands on 'Go back 1 square'
four times in a row.
Steve is next to spin.
Write down the probability that he gets
'Go back 1 square'.
Give your answer as a fraction.
c) In one game there are 96 spins.
How many of these spins are expected
to be 'Go forward 3 squares'?
(1)
(2)
Total marks: 4
See below for the values of the probabilities
How to determine the probabilityThe complete question is added as an attachment
Write down the probability he gets 'Miss a turn'.
From the spinner, we have
Sections = 6
Miss a turn = 1
So, the probability that he gets 'Miss a turn is
P = 1/6
Write down the probability that he gets 'Go back 1 square'.
Here, we have:
Number of rows = 4
'Go back 1 square' = 4
The probability that he gets 'Go back 1 square' is
P = 'Go back 1 square'/Number of rows
This gives
P = 4/4
Evaluate
P = 1
How many of these spins are expected to be 'Go forward 3 squares'?
Here, we have
Spins = 96
From the spinner, the probability of 'Go forward 3 squares' is
P =1/6
So, the expected number is
E(x) = np
This gives
E(x) = 96 * 1/6
Evaluate
E(x) = 16
Hence, 16 spins are expected to be 'Go forward 3 squares'
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Darlene is building a rectangular fence. the length is 8 feet longer than the width. the perimeter of the rectangle is 76 feet. what is the length of the rectangle?
Answer:8 feet
Step-by-step explanation:
What are the domain and range of g of x equals negative 3 times the square root of the quantity x minus 1? d: (1, [infinity]) and r: (0, [infinity]) d: [–3, [infinity]) and r: [0, [infinity]) d: (–3, [infinity]) and r: (–[infinity], 0) d: [1, [infinity]) and r: (–[infinity], 0]
Answer:
d: d [1, infinity) and r (-infinity, 0)
Step-by-step explanation:
right on the test :3 good luck dear!!
Mrs. Gurung allowed 10% discount on her fancy items to make 25% profit and sold a lady bag for Rs 5,085 with 13% VAT. Due to the excessive demands of her items, she decreased the discount percent by 2%. By how much was her profit percent increased?
Her profit % was increased by 2.77%
Answer:
Solution Given:
discount =10%
profit =25%
S.P with 13% vat = Rs 5,085
S.P+Vat% of S.P= Rs 5,085
S.P(1+13%)=Rs 5,085
S.P=Rs 5,085/1.13
S.P =Rs 4,500
Again
M.P = S.P+discount% of M.P
M.P- discount% of M.P= Rs 4,500
M.P(1-10%)=Rs 4,500
M.P=Rs 4,500/0.9
M.P = Rs 5,000
Now
C.P= (S.P*100)/(1+profit%)
C.P=(4,500*100)/(100+25%)
C.P= Rs 3,600
Again
profit =S.P- C.P= Rs 4,500-Rs 3,600=Rs 900
Again
Due to the excessive demands of her items, she decreased the discount percent by 2%.
So,
New discount = 10%-2%=8%
New S.P= M.P -discount% of M.P
=M.P(1-discount%)
=Rs 5,000(1-8%)
=Rs 4,600
Again
Profit=S.P- C.P
New profit =Rs 4,600 - Rs 3,600=Rs 1,000
Profit% =profit/C.P*100%= 1000/3600*100=27.77%
Profit % increased =New profit%- profit%
=27.77-25
=2.77%
Select true or false to tell whether the following conditional p q is true or false. Use the truth table if needed.
If 3 + 2 = 5, Then 5 + 5 = 10
The given condition on the basis of truth table is true.
According to the statement
we have given that the some condition p and q. and we have to find that the given condition is true or false on the basis of the truth table.
So, The given conditions are:
If 3 + 2 = 5, Then 5 + 5 = 10
Now,
The Truth table is a tabular representation of all the combinations of values for inputs and their corresponding outputs. It is a mathematical table that shows all possible outcomes that would occur from all possible scenarios that are considered.
So, the given conditions are properly verified with the truth table. So, it is true.
So, The given condition on the basis of truth table is true.
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How would I describe this?
Answer:
That's a reflection in the x axis.
Step-by-step explanation:
Triangle C is the mirror image of B with the x axis acting as a mirror.
solve this if u can pls!
using the numbers 5, 7, and 8 only once each, fill in the boxes to make the statement true.
Answer:
its log 5 7/8
Step-by-step explanation:
Consider this function. f(x)=6log2x-3 over which interval is function f increasing at the greatest rate?
The function increased at the highest rate in the interval [1/8, 1/2], as can be seen from the function value and its interval values.
What is maxima and minima?A function's maxima and minima are its highest and lowest values, respectively, either on the entire domain or inside a certain range. They are referred to as the function's extrema collectively. The plural forms of maximum and minimum for a function are respectively known as maxima and minima.
Why do we use maxima and minima?The extreme values of a function—their maximum and minimum values—are referred to by the words maxima and minima. Maximum refers to the maximum value or amount that is feasible. A function's biggest value within its range is known as its absolute maximum.
According to the given information we have:f(x)=6log2x-3
For the interval x ∈[2, 6]
f(x) ∈ [-0.678, 3]
For the interval x ∈ [1/8, 1/2]
f(x) ∈ [ -9.96, -5.32]
For the interval x ∈ [1, 2]
f(x) ∈ [-3, -0.67]
For the interval x∈ [1/2, 1]
f(x) ∈ [-5.32, -3]
The function increased at the highest rate in the interval [1/8, 1/2], as can be seen from the function value and its interval values.
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(x^2-6x+9)^2-15(x^2-6x+10)=1
Answer:
x = -1, 7, 3 + i, 3 - i.
Step-by-step explanation:
(x^2-6x+9)^2-15(x^2-6x+10)=1
(x^2 - 6x + 9)^2 - 15(x^2 - 6x + 9) - 15*1 = 1
(x^2 - 6x + 9)^2 - 15(x^2 - 6x + 9) - 16 = 0
Let Z = x^2 - 6x + 9, then we have:
Z^2 - 15Z - 16 = 0
(Z - 16)(Z + 1) = 0
Z = 16 or Z = -1
so x^2 - 6x + 9 = -1 or x^2 - 6x + 9 = 16
x^2 - 6x + 9 = -1
---> x^2 - 6x + 10 = 0
Using the Quadratic Formula:
---> x = [6 +/- √((-6)^2 - 4* 1* 10) / 2
---> x = 6/2 +/- √-4/2
---> x = 3 + i , 3 - i.
x^2 - 6x + 9 = 16
---> x^2 - 6x - 7 = 0
---> (x - 7)(x + 1) = 0
---> x = 7, -1.
