Help please!
Zach drives his car with an average velocity of 24 m/s toward the east. How long will it take him to drive 560 km on a perfectly straight highway?

Answers

Answer 1
d=560 km = 560000 m
V=24 m/s
t-?
d=V*t
t = d/V= 560000/24= 23333.3 s = 388.9 min = 6.5 hours

Related Questions

which of these is a risk of speeding? a. Tire Damage b.Greater likelihood of being distracted c.longer barking distance d.mechanical failure

Answers

All of the above are risks of speeding.

Speeding is a type of aggressive driving behavior. Speeding is more than just breaking the law. The consequences are far-ranging:

Greater potential for loss of vehicle control;Reduced effectiveness of occupant protection equipment;Increased stopping distance after the driver perceives a danger;Increased degree of crash severity leading to more severe injuries;Economic implications of a speed-related crash; andIncreased fuel consumption/cost.

Speed also affects your safety even when you are driving at the speed limit but too fast for road conditions, such as during bad weather, when a road is under repair, or in an area at night that isn’t well lit.

Speeding endangers not only the life of the speeder, but all of the people on the road around them, including law enforcement officers. It is a problem we all need to help solve.

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gfcis operate by comparing the amount of current flowing in the ___ circuit conductors of a 240-volt circuit. when these are not the same, the gfci device trips.

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gfcis operate by comparing the amount of current flowing in the outlet circuit conductors of a 240-volt circuit. when these are not the same, the gfci device trips.

What is gfcis ?

This refers to an electrical safety device that immediately breaks an electrical circuit with leakage current to the ground. It protects equipment and reduces the risk of serious harm from an ongoing electric shock. It is also known as a residual-current device/ residual-current circuit breaker or ground fault circuit interrupter.

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FILL IN THE BLANK. The wind is moving from a rough to a smooth surface; at the same height wind over the smooth surface gets with fetch. a) faster b) slower c) None of the above

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Option A, The wind is moving from a rough to a smooth surface; at the same height wind over the smooth surface gets faster with fetch.

The wind can move more quickly over a smooth surface as compared to a rough one at the same height. This is known as fetch. The exchange of momentum between the atmosphere and the ocean is facilitated by surface winds, which generate ocean waves and drive ocean circulation.

This circulation transports heat and carbon around the globe. As the roughness of the surface increases, the wind speed at the surface decreases. However, when the roughness length is shorter, there is less exchange between the surface and the atmosphere but the winds near the surface become stronger.

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A man runs 300 m west in 60 seconds. He then runs 100m north-west in 20 seconds. What is his average velocity in meter per second?

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Man moves at an average velocity of 5 meters per second.

What is his average velocity?A man runs 300 m west in 60 seconds. He then runs 100m north-west in 20 seconds. Average velocity is determined by dividing your displacement (a vector pointing from your initial location to your end position) by the total time, whereas average speed is determined by dividing the whole distance you went by the total time.We divide the total distance traveled by the total time taken by an object to determine its average speed.

Man has traveled a total of 400 meters (300 + 100).

Total time required by man: 60 + 20 = 80 seconds.

average velocity is  400/80 = 5

Therefore, the average velocity of a man is 5 meters per second.

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the radius of mars is approximately one half the radius of earth, and the mass of mars is approxamitely one-tenth that of Earth

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The radius of mars is approximately the mean distance between the number of sick days taken and the mean number of sick days taken by all employees

What is radius of mars?

Only Mercury is smaller than Mars, which is the fourth planet from the Sun and the second-smallest planet in the Solar System. Mars is the name of the Roman god of war that appears in the English language.

On average, Mars has a temperature of -81 degrees Fahrenheit. The polar regions have winters with temperatures around -220 degrees Fahrenheit, while summers at lower latitudes average 70 degrees Fahrenheit.

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An inventive child named Nick wants to reach an apple in a tree without climbing the tree. Sitting in a chair connected to a rope that passes over a frictionless pulley (see figure below), Nick pulls on the loose end of the rope with such a force that the spring scale reads 310 N. Nick's true weight is 290 N, and the chair weighs 160 N. Nick's feet are not touching the ground.
(b) Show that the acceleration of the system is upward. (Do this on paper. Your instructor may ask you to turn in this work.)
Find its magnitude.
m/s2
(c) Find the force Nick exerts on the chair.
N

Answers

b) The magnitude of the acceleration of system is [tex]3.7m/s^2[/tex].

c)The force exerted by nick on the chair is 89.483 N.

Given,

weight of nick = 290 N

Weight of chair = 160 N

Spring scale force ,T = 310 N

then,

Total weight = 290+160= 450 N

b)

then the total mass be

Mass ,[tex]m = \frac{weight}{force}= \frac{450}{9.8} = 45.918 Kg[/tex]

By adding the forces of both ropes, the upward force can be calculated.

Net upward force = 310 + 310 = 620 N

The downward force can be calculated by adding the forces generated by Nick and its chair.

Net downward force = 290 + 160 = 450 N

Then, the resultant force be,

F = Net upward force - Net downward force = 620 - 450 = 170 N                    

To determine acceleration use formula,

[tex]F=ma\\\\45.918*a = 170\\\\a = \frac{170}{45.918} = 3.7 m/s^2[/tex]

Because net upward force exceeds net downward force, the resultant force is directed upwards thus the acceleration is  also upward.

c)

The force exerted by nick on the chair can be calculated by

F = n + T - 290\\\\

ma=n+T-290

Here, consider only nick's weight then mass will be

[tex]m=\frac{290}{9.8}=59.591 kg[/tex]

[tex]59.591*3.7=n+310-290\\\n=89.483 N[/tex]

Thus, the force exerted by nick on the chair is 89.483 N

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You put on sunglasses and looks at the outside view. The sky is a little dark, but the reflection from a pond is much darker. Why?

A. Pond reflection is polarized
B. The light outside has changed.
C. Sunglasses are not polarized.
D. Skylight is polarized.

Answers

When you put on sunglasses and looks at the outside view, the sky is a little dark, but the reflection from a pond is much darker because Pond reflection is polarized. Option (A) is correct.

What is polarization?

In the field of physics, polarization is referred to as a phenomena brought on by the fact that electromagnetic radiation is a wave.

Moving across space, electric and magnetic fields interact to form light. Light waves vibrate electrically and magnetically in perpendicular to one another. The magnetic field and electric field both move perpendicular to one another in different directions.

As a result, the direction of motion is perpendicular to both the plane occupied by the electric field and the plane of the magnetic field that is perpendicular to it.

These magnetic and electric vibrations can take place on a variety of planes. Unpolarized light is a type of light wave that vibrates in more than one plane. The sun, a lamp, and a tube light are all examples of unpolarized light sources.

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vexplain the differences between refraction diffraction, and interference. are there any situations where more than one of those are happening at the same time? in which of these situations does the speed of a wave change? what about the wavelength? and the frequency? provide as detailed a description as possible to show that you have mastered the differences between these three processes

Answers

Refraction is when light travels from one medium to another

This is studied by considering the light as ray.

Here as the ray travels from one medium to another, its speed changes.

However, the frequency of the waves which depend on the source will not change in the other medium as well. So frequency does not change in refraction. But wavelength changes when light undergoes refraction.

Interference and Diffraction are studied treating light as wave. And both of these are basically superposition of waves

In interference, light from two coherent sources interfere with each other and the resulting wave pattern is the subject of interference.

While in diffraction, secondary wavelets emerging from the original wave's different parts is considered. The supersposition of these secondary wavelets is basically diffraction.

In both of these interference and diffraction, speed, wavelength and frequency all remains same as the speed and therefore wavelength depends only on the medium

Reflection involves the change in direction of a wave as it bounces off a barrier. Wave refraction involves the change in direction of a wave as it passes from one medium to another. Diffraction involves the change of direction of a wave as it passes around an opening or barrier in its path.

Reflection is the process of reflecting light when it hits an in-plane medium. Refraction is the process of changing the path and bending light as it passes through a material. Hence, this is the main difference between reflection and refraction.

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Two electric model trains are sitting on a long stretch of track. One train has a mass of 5.50 kg and rolls into the second train which is at rest. The second train is much smaller, with a mass of 550.0 g. After the bump, the large and small trains have velocities of 3.2727 cm/s and 7.2727cm/s , respectively. What is the original velocity of the large train before the bump?

Answers

The original velocity of the large train before the bump will be 3.999 cm/s.

Velocity can be defined as the rate of change distance with respect to time.

Its SI unit is m/s.

According to the law of conservation of momentum,

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

m₁ = mass of the first model electric train = 5.50 kg = 5500 g

u₁ = initial velocity of the first model train

m₂ = mass of the second model electric train = 550.0 g

u₂ = 0 m/s as it is at rest

v₁ = final velocity of the first model train after collision = 3.2727 cm/s

v₂ = final velocity of the second model train after collision = 7.2727 cm/s

By putting the values in the main equation, u₁ can be calculated,

5500*u₁ + 550*0 = 5500*3.2727 + 550*7.2727

5500*u₁ = 17999.85 + 3999.985

5500*u₁ = 21999.835

u₁ = 21999.835/5500

u₁ = 3.999 cm/s

The original velocity of the large train before the bump will be 3.999 cm/s.

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if the magnitude of the net force acting on the particle is f , how long does it take the particle to acquire its final velocity, 2v in the positive y direction? express your answer in terms of m , f , and v . if you use a numerical coefficient, use three significant figures.

Answers

The final velocity, 2v in the positive y direction, is 2.24mv/F. The final velocity is in terms of mass, velocity, and force.

Given:

Initial velocity, Vi

Final velocity, Vf = 2v

Mass, m

Acceleration, a

The force is given by:

F=ma

The direction of force is in y direction and the acceleration is given by:

a=Fcosθ/m

From th first equation of motion:

Vf=Vi + at

The initial velocity is zero. Therefore, the final velocity is:

2v=0+ (Fcosθ/m)(t)

2mv / (Fcosθ) = t

If theta is equal to 26.6 degrees.

The final velocity is:
v = 2.24mv/F

Hence. the final velocity, 2v in the positive y direction, is 2.24mv/F. The final velocity is in terms of mass, velocity, and force.

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time quantum is defined in: group of answer choices shortest job scheduling algorithm priority scheduling algorithm round robin scheduling algorithm multilevel queue scheduling algorithm

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In the round robin scheduling algorithm, time quantum is specified. As part of a theory that contends that time is not continuous, a chronon is a discrete and indivisible "unit" of time that is proposed.

A preemptive scheduler permits a certain process to operate for a brief period of time known as a quantum (or time slice). The process is put back in the ready queue after this amount of time and another one is put into the run state (i.e., the scheduler ensures that the processes take turns to run). Round Robin Scheduling fixes the time quantum before scheduling the processes such that no one process receives more CPU time than one time quantum at a time. The response time of the processes is too long if time quantum is too large, which could not be acceptable in an interactive environment.

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a fixed amount of a monatomic ideal gas is taken through the following cyclic process. originally (a) it is near atmospheric pressure (100 kpa) with a volume of 0.50 m3 and a temperature of 375 k. then it is isothermally compressed to half its volume (b). then its volume triples (c) during an isobaric expansion.

Answers

The qualitative sketch of the process on the PV plane is attached below:

What is  ideal gas equation?

The ideal gas law (also called the perfect gas law), the relationship between pressure P, volume V, and temperature T of a gas in the boundary region between low pressure and high temperature. Gas molecules move almost independently. each other. In such cases, all gases obey an equation of state known as the ideal gas law.

PV = nRT, where n is the number of moles of gas and R is the universal (or complete) gas constant, 8.31446261815324 joules/kelvin/mol (the universal gas constant is defined as Avogadro's number NA multiplied by Boltzmann's constant k) . ) In the International System of Units, energy is measured in joules, volume in cubic meters (m3), force in newtons (N), and pressure in pascals (Pa). where 1 Pa = 1 N/m2. A force of 1 Newton moving a distance of 1 meter does 1 Joule of work. Therefore, the dimension of both products PV and nRT is work (energy).

The qualitative sketch of the process is drawn on the PV plane.

At A,

P₁ = 100 kPa

V₁ = 0.50 m³
T₁ = 375 K

At B,

T₂ = 375 K

V₂ = 0.25 m³
P₁V₁ = P₂V₂

So, P₂ = (100× 10³ ×0.50)/ 0.25

= 200 kPa

At C,

P₃ = 200 kPa

V₃ = 0.75 m³

We know, V₂/ T₂ = V₃/ T₃

So,

T₃ = V₃T₂/ V₂

= (0.75 × 375)/ 0.25

= 1125 K

At D,

P₄ = 100 kPa

T₄ = 1125 K

V₄ = P₃V₃/ P₄

= (200 × 0.75)/ 100

= 1.5 m³

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The complete question is:

An audio speaker producing a steady sound at an outdoor concert is 42 ft away from you. If you move to a position where the speaker is 77 ft distant, by what factor will the amplitude of the sound change?

Answers

One of the phenomena whose strength changes with the square root of the inverse of the distance from the source is sound.

define amplitude ?

A periodic variable's amplitude measures its change over a single period (such as time or spatial period). A non-periodic signal's magnitude in relation to a standard value is its amplitude. There are several definitions of amplitude (see below), all of which depend on how much the extreme values of the variable deviate from one another. The phase of a periodic function is frequently referred to as the amplitude in older publications.

=(42/77)^2

=(0.545)^2

=0.297025

Thus, the sound increases in volume by around 8% from its initial level.

(The noise level has been lowered by 10.98 dB.)

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given below is stream flow data due to a storm of two hour duration. the area of the drainage basin is 2000 acre. determine the total volume of direct runoff (in inch). use the constant discharge method to separate the base flow. plot the hydrograph (5 points).

Answers

The minimum streamflow immediately prior to the rising limb is used as the constant value.

Here the constant value is taken as 25cfs which is at 2nd hour just before the rise of hydrograph.

The direct runoff discharge starts from 2nd hour and ends at 36th hour.

from the trapezoidal formula, The runoff discharge = (0+72+173+295+419+510+559+495+397+266+167+110+7 2+47+27+19+12+(8/2)) * 2 * 3600 = 26236800 cubic feet. The area of the catchment = 2000 acres. = 2000* 43560 =87120000 ft^2

The depth of runoff (discharge / area) = 0.266 feet = 0.266* 12 inches 3.2 inches.

Stream flow or channel outflow is the flow of water in streams and other channels and is a major component of the hydrological cycle. This is one component of water movement from land to water, and another component is surface runoff. The water flowing through the channel comes from surface runoff from adjacent hillsides, groundwater flowing from the ground, and water drained from pipes. The flow rate of water flowing through a canal can be measured with a hydrometer or estimated using Manning's equation. A record of flow over time is called a hydrograph. Flooding occurs when the volume of water exceeds the capacity of the canal.

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In which graph is acceleration the slope?
A. Distance versus time

B. Acceleration versus time

C. Velocity versus time

D. Position Versus time

Answers

The graph of the slope's acceleration depicts velocity vs time.

reveals the solution.

The distance an object has travelled over time is displayed on a distance-time graph.

A straight-line graph of the time versus distance results is shown. The Y-axis displays the distance. The X-axis displays a time plot. Velocity changes occur more quickly on the graph with the sharpest slope.

It picks up speed the fastest. The acceleration of an item is shown by the slope of a velocity graph. As a result, the value of the slope at a particular time determines the item's acceleration at that specific instant.

A moving item is shown by a sloped line on a distance-time graph. The object's speed is equal to the gradient or slope of the line on a distance-time graph.

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g an object is placed in a fluid and then released. assume that the object either floats to the surface (settling so that the object is partly above and partly below the fluid surface) or sinks to the bottom. (note that for parts a through d, you should assume that the object has settled in equilibrium.)
Part A Consider the following statement The magnitude of the buoyant force is equal to the weight of fluid displaced by the object Under what circumstances is this statement true? Hints O for every object submerged partially or completely in a fluid O only for an object that is floating O only for an object that is fully submerged and is sinking O for no object submerged in a fluid Submit My Answers Give Up Part B Consider the following statement The magnitude of the buoyant force is equal to the weight of the amount of fluid that has the same al volume as the object. Under what circumstances is this statement true? Hints O for an object that is partially submerged in a fluid O only for an object is floating O for an object completely submerged in a fluid O for no object partially or completely submerged in a fluid Submit My Answers Give Up Part C Consider the following statement The magnitude of the buoyant force equals the weight of the object. Under what circumstances is this statement true?

Answers

Part A: The statement "The magnitude of the buoyant force is equal to the weight of the fluid displaced by the object" is true only for an object that is floating.

This is because, when an object is floating, it is in equilibrium with the fluid; the buoyant force acting on the object is equal to the weight of the fluid it displaces, which is also equal to the weight of the object. This means that the buoyant force is equal to the weight of the object.

Part B: The statement "The magnitude of the buoyant force is equal to the weight of the amount of fluid that has the same volume as the object" is true for an object that is partially submerged in a fluid.

This is because, when an object is partially submerged, the buoyant force acting on it is equal to the weight of the amount of fluid that has the same volume as the object. Since the buoyant force is equal to the weight of the object, this statement is true.

Part C: The statement “The magnitude of the buoyant force equals the weight of the object" is false for any object partially or completely submerged in a fluid.

This is because the buoyant force acting on the object is not equal to its weight; rather, the buoyant force acting on the object is equal to the weight of the fluid it displaces, which is less than the weight of the object. Therefore, this statement is false.

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Complete question:

G an object is placed in a fluid and then released. assume that the object either floats to the surface (settling so that the object is partly above and partly below the fluid surface) or sinks to the bottom. (note that for parts a through d, you should assume that the object has settled in equilibrium.)

Part A Consider the following statement The magnitude of the buoyant force is equal to the weight of fluid displaced by the object Under what circumstances is this statement true? Hints O for every object submerged partially or completely in a fluid

O only for an object that is floating

O only for an object that is fully submerged and is sinking

O for no object submerged in a fluid

Part B Consider the following statement The magnitude of the buoyant force is equal to the weight of the amount of fluid that has the same al volume as the object. Under what circumstances is this statement true? Hints

O for an object that is partially submerged in a fluid

O only for an object is floating

O for an object completely submerged in a fluid

O for no object partially or completely submerged in a fluid

Submit My Answers Give Up

Part C Consider the following statement The magnitude of the buoyant force equals the weight of the object. Under what circumstances is this statement true?

O for an object that is partially submerged in a fluid

O only for an object is floating

O for an object completely submerged in a fluid

O for no object partially or completely submerged in a fluid

Problem 12.15 Determine the electrical conductivity of a Cu-Ni alloy that has a yield strength of 100 MPa. Refer to Eigures 12.9 an 8.16. (1-m) the tolerance is +/-5% Click if you would like to Show Work for this question: Open Show Work Electrical resistivity (10-8 82 m) Composition (wt% Ni) Figure 12.9 Room-temperature electrical resistivity versus composition for copper-nickel alloys. 400 Tensile strength (MPa) Tensile strength (ksi) Yield strength (MPa) Yield strength (ksi) do o 10 40 50 10 40 50 20 30 Nickel content (wt%) (a) 20 30 Nickel content (wt%) (b) Elongation (% in 2 in.) 0 10 40 20 30 Nickel content (wt%) (e) Figure 8.16 Variation with nickel content of (a) tensile strength, (b) yield strength, and (e) ductility (EL) for copper- nickel alloys, showing strengthening

Answers

The electrical conductivity of a Cu-Ni alloy that has yield strength of 100MPa is  47 ohm-meter.

Electrical conductivity is indicated by the image σ and has SI units of siemens per meter (S/m). In electrical designing, the Greek letter κ is utilized. Now and again the Greek letter γ addresses conductivity. In water, conductivity is in many cases detailed as unambiguous conductance, which is an action contrasted with that of unadulterated water at 25°C.

We know very well that electrical conductivity is just converse of resistivity multiplied by the yield strength.

From the given diagram, we can understand that maximum value of electrical resistivity is 47×10⁻⁸ (ohm-meter)⁻¹.

So, electrical conductivity =electrical resistivity ×yield-strength

=>electrical conductivity =(47×10⁻⁸ ×100×10⁶)

=>electrical conductivity =47 ohm-meter.

Hence, value of electrical conductivity is 47 ohm-meter.

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(Complete question) is:

Problem 12.15 Determine the electrical conductivity of a Cu-Ni alloy that has a yield strength of 100 MPa. Refer to Figures 12.9 an 8.16. (1-m) the tolerance is +/-5% Click if you would like to Show Work for this question:

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