Help Pleasss I will give brainlyest!!!! :D

Answer:

f is not a function

Step-by-step explanation:

Given

Domain: Whole numbers

Range: Real numbers

Required

Is f a function

Base on the given parameters, f is not a function because:

There are more real numbers than whole numbers

And this implies that at least one element in the domain will have more than one corresponding elements in the range. i.e. one-to-many or many-to-many relationship

For a relation to be regarded as a function, the relationship has to be one-to-one or many-to-one

i.e. 1 or many domain elements to 1 element in the range.

An example is:

[tex]\begin{array}{ccccc}x & {1} & {9} & {9} & {0} \ \\ f(x) & {1.5} & {3.2} & {-3.5} & {0.1} \ \end{array}[/tex]

In the above function

The domain (i.e. x values) are whole numbers

The range (i.e. y values) are real numbers

However,

9 points to 3.2 and -3.5

So, the relation is not a function.

Answer:

0.5759

Step-by-step explanation:

Answer:

283 flowers

Step-by-step explanation:

c=2pi*r

c = 1130.973 =1131

1131/4

282.75 = 283

Answer with Step-by-step explanation:

Complete question:

The coordinates  of the vertices of the triangle are (-8,8),(-8,-4), and. Consider QR the base of the triangle. The measure of the base is b = 18 units, and the measure of the height is h = units. The area of triangle PQR is square units.

Let

P=(-8,8)

Q=(-8,-4)

QR=b=18 units

Height of triangle, h=Length of PQ

Distance formula

[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Using the formula

Height of triangle, h=[tex]\sqrt{(-8+8)^2+(-4-8)^2}=12units[/tex]

Area of triangle PQR=[tex]\frac{1}{2}\times base\times height[/tex]

Area of triangle PQR=[tex]\frac{1}{2}\times 18\times 12[/tex]

Area of triangle PQR=108 square units

Length of QR=18units

Let the coordinates of R(x,y)

[tex]\sqrt{(x+8)^2+(y+4)^2}=18[/tex]

[tex](x+8)^2+(y+4)^2=324[/tex]

[tex]x^2+64+16x+y^2+8y+16=324[/tex]

[tex]x^2+y^2+16x+8y=324-64-16[/tex]

[tex]x^2+y^2+16x+8y=244[/tex]   ......(1)

Using Pythagoras theorem

[tex]H=\sqrt{P^2+B^2}[/tex]

[tex]H=\sqrt{(18)^2+(12)^2}[/tex]

[tex]H=6\sqrt{13}[/tex]units

[tex](6\sqrt{13})^2=(x+8)^2+(y-8)^2[/tex]

[tex]x^2+64+16x+y^2+64-16y=468[/tex]

[tex]x^2+y^2+16x-16y=468-64-64=340[/tex]

[tex]x^2+y^2+16x-16y=340[/tex] .....(2)

Subtract equation (2) from (1) we get

[tex]24y=-96[/tex]

[tex]y=-96/24=-4[/tex]

Using the value of y in equation (1)

[tex]x^2+16x+16-32=244[/tex]

[tex]x^2+16x=244-16+32[/tex]

[tex]x^2+16x=260[/tex]

[tex]x^2+16x-260=0[/tex]

[tex]x^2+26x-10x-260=0[/tex]

[tex]x(x+26)-10(x+26)=0[/tex]

[tex](x+26)(x-10)=0[/tex]

[tex]x=-26, x=10[/tex]

Hence, the coordinate of R (10,-4) or (-26,-4).

Answer:

y=4√3 units

Step-by-step explanation:

Hi there!

We are given ΔABC, which is a right triangle (m<C=90°), m<A=60°, AB=8, and BC=y

We need to find the value of y (BC)

The side AB is the hypotenuse of the  (the side opposite from the right angle).

BC is a leg, which is a side that makes up the right angle.

Now, if we have a right triangle that has one of the acute angles as 60°, the side OPPOSITE from that 60° angle (in this case, BC) is equal to [tex]\frac{a\sqrt{3}}{2}[/tex], where a is the length of the hypotenuse

Since we have the hypotenuse given as 8, the length of BC (y) is [tex]\frac{8\sqrt{3}}{2}[/tex], or 4√3

so y=4√3 units

Hope this helps!

Answer:

9262

Step-by-step explanation:

just plug in 22 for n and calculate

Answer:

ghthtf

Step-by-step explanation:

tygtgg

Answer:

absolute value of the determinant, adjacent to, equal to

Step-by-step explanation:

The absolute value of a determinant  of the [tex]\text{matrix whose}[/tex] columns are the vectors and they define the [tex]\text{sides}[/tex] of a [tex]\text{parallelogram}[/tex] which is adjacent to  one another and is equal to the [tex]\text{area}[/tex] of the [tex]\text{parallelogram}[/tex].

The determinant is a real number. They are like matrices, but we use absolute value bars to show determinants whereas to represent a matric, we use square brackets.

Answer:

AAS

Step-by-step explanation:

It will be angle angle side because you are given a side and two angles, and when you put them in the correct order, you will get AAS, or SAA (not the correct way to say it)

Answer:

Step-by-step explanation:

By applying cosine rule in the given triangle,

c² = a² + b²-2abcosC

c² = (5.6)² + (10.7)² - 2(5.6)(10.7)cos(109.3°)

c² = 185.46

c = 13.6 km

By applying sine rule in the given triangle ABC,

[tex]\frac{\text{sin}A}{a}= \frac{\text{sin}B}{b}= \frac{\text{sin}C}{c}[/tex]

[tex]\frac{\text{sin}A}{5.6}=\frac{\text{sin}B}{10.7}=\frac{\text{sin}109.3}{13.6}[/tex]

[tex]\frac{\text{sin}B}{10.7}=\frac{\text{sin}109.3}{13.6}[/tex]

sin(B) = [tex]\frac{10.7\times \text{sin}(109.30)}{13.6}[/tex]

         = 0.7425

B = [tex]\text{sin}^{-1}(0.7425)[/tex]

B = 48.0°

[tex]\frac{\text{sin}A}{5.6}=\frac{\text{sin}109.3}{13.6}[/tex]

sin(A) = [tex]\frac{[\text{sin}(109.3)]\times (5.6)}{13.6}[/tex]

         = 0.3886

A = [tex]\text{sin}^{-1}(0.3886)[/tex]

A = 22.9°

Answer:

60 miles

Step-by-step explanation:

Create an equation where y is the total cost and x is the number of miles traveled.

0.8x will represent the cost from the miles traveled. 8.5 will be added to this to represent the taxi cost and additional charge from tolls:

y = 0.8x + 8.5

Plug in 56.50 as y and solve for x, the number of miles:

y = 0.8x + 8.5

56.5 = 0.8x + 8.5

48 = 0.8x

60 = x

So, you can travel 60 miles

Answer:

270 plates

Step-by-step explanation:

First, you need to find how much one plate costs.

6x = 54

----    ----

6       6

x = 9

Now, multiply 30 plates with x, which is 9.

30(9) = 270

The answer is 270.

Answer:

270

Step-by-step explanation:

54($)÷6= 9 then 9×30=270

Answer:

Cuboid = width*height*length

Cuboid = 24 cm^2

step by step explanation:

[tex]\mathfrak{x}^{2}+{y}^{2}+16=0[/tex]

=[x2+16=0x26]

=[2x{y}^2{16}~0]

=[4×{y}^0{16}]

=[32x{y}^x]

Answer:

the second option : ST and WX

Step-by-step explanation:

congruent means they would completely cover each other when oriented in the same direction and positioned at the same location.

after dying the two mirroring actions we get

VS correlates to ZW

ST correlates to WX

TU correlates to XY

UV correlates to ZY

Perimeter = namely the length of outside bordering,

well, this is a PENTAgon, or PENTA=5 or namely 5 sides, is regular so each side is the same length, so we have a polygon with 5 sides each measuring 40cm, well, its perimeter is just 40+40+40+40+40 = 200.

Answer:

Yeah the answer is n o .

Answer:

yes i do have but i dont use it

Answer:

[tex]\boxed {\boxed {\sf \$15.06 \ billion }}[/tex]

Step-by-step explanation:

We are given the function f(x). This is the value of diamond production for the year in billions.

[tex]f(x)= 0.21x+13.8[/tex]

We want to find the value of the diamond production in 2006.

We know that x is the number of years after 2000. The year 2006 was 6 years after 2000 because 2006 - 2000 = 6. Therefore, x (years after 2000) is equal to 6. We can substitute 6 in for x.

[tex]f(6)= 0.21(6)+ 13.8[/tex]

Solve according to PEMDAS (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction).

Multiply 0.21 and 6.

[tex]f(6)= 1.26+13.8[/tex]

Add 1.26 and 13.8

[tex]f(6)=15.06[/tex]

Remember the answer is in billions of dollars.

[tex]f(6)= \$ 15.06 \ billion[/tex]

Diamond production in 2006 is expected to be worth 15.06 billion dollars.

Answer:

15=2p+3

Step-by-step explanation:

Answer:

The responses to these question can be defined as follows:

Step-by-step explanation:

For point a:

[tex]\to P(1) = 0.73[/tex]

For point b:

[tex]\to P(2\ or\ 3) = P(2) + P(3)[/tex]

                    [tex]= 0.27 \times 0.73 + 0.27\times 0.27\times0.73\\\\=0.1971+0.1971\times 0.27\\\\=0.1971+0.053217\\\\=0.250317[/tex]

Answer:

[tex]T =56.3[/tex]

Step-by-step explanation:

Given

The attached triangle

Required

Measure of T

This is calculated as:

[tex]\cos T = \frac{Adjacent}{Hypotenuse}[/tex]

[tex]\cos T = \frac{5}{9}[/tex]

Take arccos

[tex]T = \cos^{-1}{(5/9)}[/tex]

[tex]T =56.3[/tex]

Answer:

The difference is that Marla's exam in her statistics class was graded by percent of correct answers, in her case 70%, while the SAT is graded into a curve, taking other students' grades also into account, and since she scored in the 70th percentile, Marla scored better than 70% of the students.

Step-by-step explanation:

Marla scored 70% on her last unit exam in her statistics class.

This means that in her statistics class, Marla got 70% of her test correct.

When Marla took the SAT exam, she scored at the 70th percentile in mathematics.

This means that on the SAT exam, graded on a curve, Marla scored better than 70% of the students.

Explain the difference in these two scores.

The difference is that Marla's exam in her statistics class was graded by percent of correct answers, in her case 70%, while the SAT is graded into a curve, taking other students' grades also into account, and since she scored in the 70th percentile, Marla scored better than 70% of the students.

Answer:

DGF = 106

Step-by-step explanation:

Bisects means to divide in half, with two equal parts

DGF = DGE + EGF

DGE = EGF

DGF = DGE + DGE

DGF = 53+53

DGF = 106

GE bisects ∠DGF, so it divides ∠DGF into 2 equal parts.

So, m∠EGF = m∠DGE

=> m∠EGF = 53°

m∠DGF = m∠EGF + m∠DGE

=> m∠DGF = 53° + 53°

=> m∠DGF = 106°

Answer:

5555 Lakh rupoes maybe hope it helps

The amount Frans took as loan = R12000

"It is the interest that is only calculated on the initial amount of the loan."

[tex]SI=\frac{P\times R\times T}{100}[/tex]

where, P: principal amount

T : period

R: rate of interest

For given question,

SI = 9600

T = 5 years

R = 16%

We need to find the principal amount.

Using simple interest formula,

[tex]\Rightarrow SI=\frac{P\times R\times T}{100}\\\\\Rightarrow P=\frac{SI\times 100}{R\times T}\\\\\Rightarrow P=\frac{9600\times 100}{5\times 16}\\\\\Rightarrow P=12000[/tex]

Therefore, the amount Frans took as loan = R12000

Learn more about the simple interest here:

https://brainly.com/question/22621039

#SPJ3

Answer

a) chart

Step-by-step explanation:

a) chart best represents the following information about student results from a class assignment

Answer:

a) f(x,y) = - 1    minimum  at   P ( 0 ; -1 )

b) f (x,y) = 10  maximum at   P ( 3 , 1 ) and   f (x,y) = - 10 minimum at       Q ( - 3 , - 1 )

c)  Max  f ( x , y ) = 2   for points    P ( 1, 2 )  and T ( -1 , -2 )

Min  f ( x , y ) =  -2   for points   Q ( 1 , - 2 )  and R  ( -1 , 2 )

Step-by-step explanation:

A)  f(x,y) = x² - y²         subject to   x² + y² = 1      g(x,y) = x² + y²- 1

δf(x,y)/ δx  = 2*x                                                 δg(x,y)/ δx  =    2*x                      

δf(x,y)/ δy  = - 2*y                                                 δg(x,y)/ δy  =    2*y

δf(x,y)/ δx  = λ* δg(x,y)/ δx

2*x = λ*2*x

δf(x,y)/ δy  = λ* δg(x,y)/ δy

- 2*y = λ*2*y

Then, solving

2*x = λ*2*x           x = λ*x      λ = 1

- 2*y = λ*2*y         y = - 1

x² + y²- 1 = 0         x²  + ( -1)² - 1 = 0      x = 0    

Point  P ( 0 ; -1 )  ; then at that point

f(x,y) = x² - y²             f(x,y) = 0 - ( -1)²     f(x,y) = - 1    minimum

b)  f( x, y ) =  3*x  + y            g ( x , y )  = x² +  y²  = 10

  δf(x,y)/ δx  = 3                   δg(x,y)/ δx  =  2*x

 δf(x,y)/ δy   = 1                   δg(x,y)/ δy  =   2*y

δf(x,y)/ δx  =   λ * δg(x,y)/ δx      ⇒   3 = 2* λ *x    (1)

δf(x,y)/ δy   =  λ *  δg(x,y)/ δy     ⇒    1 = 2*λ * y    (2)

                                                           x² +  y²  - 10 = 0  (3)

Solving that system

From ec (1)     λ  =  3/2*x      From ec (2)     λ  = 1/2*y

Then    (3/2*x )  = 1/2*y          3*y  =  x

x²  +  y²  = 10     ⇒   9y²  + y²  = 10      10*y² = 10

y² = 1       y  ± 1       and    

y  =  1      x  = 3       P  ( 3 , 1  )       y  = - 1    x = -3    Q  ( - 3 , - 1 )

Value of  f( x , y )  at   P   f (x,y) = 3*x + y      f (x,y) =    3*(3) +1  

f (x,y) = 10  maximum at  P ( 3 , 1 )

Value of  f( x , y )  at  Q     f (x,y) = 3*x + y    f (x,y) =  3*(- 3) + ( - 1 )

f (x,y) = - 10 minimum at Q ( - 3 , - 1 )

c)  f( x, y ) =  xy                       g ( x , y )  =  4*x² + y² - 8

δf(x,y)/ δx  = y                         δg(x,y)/ δx  = 8*x

δf(x,y)/ δy = x                          δg(x,y)/ δy  =  2*y

δf(x,y)/ δx  =  λ * δg(x,y)/ δx   ⇒   y  =  λ *8*x    (1)

δf(x,y)/ δy =   λ * δg(x,y)/ δy   ⇒   x  =  λ *2*y    (2)

                                                      4*x² + y² - 8 = 0   (3)

Solving the system

From ec (1)  λ = y/8*x    and From ec (2)      λ = x/2*y        Then    y/8*x  =  x/2*y

2*y² = 8*x²       y² = 4*x²    

Plugging that value in ec (3)

4*x²  +  4*x² - 8 = 0

8*x² = 8     x² = 1        x ± 1      And y² = 4*x²

Then:

for x  = 1      y² =  4     y = ± 2

for x  = -1     y² =  4     y = ± 2

Then we get     P (  1 ; 2 )   Q  ( 1 ; - 2)

                          R ( - 1 ; 2 )  T  ( -1 ; -2)

Plugging that values in f( x , y ) = xy

P (  1 ; 2 )  f( x , y ) = 2            R ( - 1 ; 2 )  f( x , y ) = - 2

Q ( 1 ; - 2)  f( x , y ) = -2           T ( -1 ; -2 )  f( x , y ) = 2

Max  f ( x , y ) = 2   for points    P and T

Min  f ( x , y ) =  -2   for points   Q and R

a hour,.....................

Answer:

This problem has not solution

Step-by-step explanation:

lets the  integers be:

x

x+1

x+2

x+3

so:

x+(x+1)+(x+2)+(x+3)=2021

x+x+x+x+1+2+3=2021

4x+6=2021

4x=2021-6=2015

x=2015/4=503.75

x is not a integer

Answer and explanation:

A linear problem is an equation based on known and unknown variables that follow a linear path, usually without exponents and look like this:

y=mx+b. To formulate the linear constraints of the problem above, we look at the unknown variables and known variables and define and equation using this.

From the problem, assume x and y are the prices of the different boat brands:

50x+50y=420000

Assume a and b are number of x brand boats and y brand boats supplied thus:

a+b>=200