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Milk is an example of solid emulsion. Hence, option D is correct.

An emulsion is defined as a colloid consisting of two or more non-homogenous type of liquids in which one of the liquid contains the dispersion of the different form of liquids.

Emulsion consist of a dispersion of two liquids that are immiscible with each other.

One of the liquids act as the dispersion medium and the other will act as the dispersed phase.

Emulsions are colloids in which both the dispersed phase and dispersion medium are liquids.

Types of Emulsion:

    2. Water in oil (W/O)

Milk is an example of solid emulsion. Hence, option D is correct.

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The process which involves the addition of a hydrogen molecule to compounds containing multiple bonds will be known as hydrogenation reaction.

Unsaturated hydrocarbons are transformed into saturated hydrocarbons by the addition process when they interact with hydrogen gas and nickel. The term "hydrogenation reaction" is also employed to describe this process.

In the production of fats and oils, hydrogenation seems to be crucial for two reasons. It increases the oil's oxidative stability and turns liquid oils become semisolid or plastic fats for use in shortenings as well as margarine, among other things.

Therefore, the process which involves the addition of a hydrogen molecule to compounds containing multiple bonds will be known as hydrogenation reaction.

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Aside from the high-energy molecules like ATP and NaDH . The net reaction for the complete oxidation of acetyl-COA in the TCA cycle is given as ,

Pyruvate → 3[tex]CO_{2}[/tex]

The reaction of the cycle are carried out by eight enzymes that completely oxidize acetate ( a two carbon molecule ) , in the form of acetyl-COA , into two molecules each of carbon dioxide and water . The net yield of one turn of the TCA cycle in terms of energy - containing compounds is one GTP , one FADH2 , and three NADH molecules . The NADH molecules are used in oxidative

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The relative velocity is described as the velocity of an object with respect to another viewer. It is the time rate of shift of relative position of one object with respect to another object.

a) Velocity of car A (Va) = 20m/s

Velocity of car B (Vb) = -6m/s

To find the Relative Velocity, we should apply the formula as,

Relative Velocity of car A and car B = Vab

Vab = Va - Vb

Vab = 20 - (-6)

Vab = 20+6

Vab = 26m/s

b). if Velocity of car A = Velocity of car B

Va = Vb

In this case,

Relative Velocity = Vab

Vab = Va - Vb

(since Va = Vb)

Vab = 0m/s

Hence, the Relative Velocity in a). is 26m/s and in b). is 0m/s.

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The  empirical formula refers to the simplest formula of a compound.

The term empirical formula refers to the simplest formula of a compound. The empirical formula shows us the ratio of the atoms that are involved in the compound. It does not show the actual number of the atoms in the molecule as this is shown by the molecular formula. However, the arrangement of atoms in the compound is shown by the structural formula.

Now, let us write the compounds that can be formed rom each ion;

1) Fe^3+

-FeCl3

-FeBr3

-FeI3

-FeF3

2) C2H3O2^-

-NaC2H3O2

-KC2H3O2

-Ca(C2H3O2)2

-Mg(C2H3O2)2

3)

CN^-

-Fe(CN)3

-CsCN

-NaCN

-KCN

4) Pb^4+

-PbCl4

-PbI4

-PbBr4

-PbF4

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Ksp of PbBr₂ is 6.60 × 10⁻⁶. The molar solubility of PbBr₂ in pure water is 0.0118M.

Ksp or Solubility Product Constant is an equilibrium constant for the dissociation in an aqueous solution.

Molar solubility (S) is the concentration of the dissolved substance in a solution that is saturated.

Let the molar solubility be S upon dissociation.

PbBr₂ or Lead Bromide dissociates in pure water as follows:

                          PbBr₂ ----------> Pb⁺² + Br⁻

                                                     S      2S

Ksp = [Pb⁺²] [ Br⁻]

Ksp = (S) (2S)²

Ksp = 4S³

6.60 × 10⁻⁶ = 4S³

S = 0.0118M

Hence, the Molar solubility S is 0.0118M.

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From the question we know that 12 - 11.70 = 0.3  so 0.3 / 12 = 0.025 therefore Simon's percent error is 2.5%.

Percent error compares an estimate to an accurate value and expresses the difference among them as a percent. This statistic lets analysts recognize the scale of the mistake relative to the true cost. it's also referred to as percentage error as well as % mistakes.

Percentage errors Calculation Steps :

Percentage error tells you the way huge your mistakes are when you degree something in an experiment. Smaller values suggest that you are close to the accepted or actual value. for instance, a 1% blunder means that you obtain very near the accepted value, whilst 45% means that you were pretty a long way off from the real value.

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BrCH2CH2CH2Br exhibits only two signals in its 1h NMR spectrum, a triplet and a quintet (splitting of 5)

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The alpha- ketoglutarate is the  5-carbon intermediate of the citric acid cycle which converted to a 4-carbon molecule with the release of carbon dioxide

The first decarboxylation reaction in Krebs cycle ( known as  citric acid cycle ) is catalyzed by isocitrate dehydrogenase in which one six carbon atoms compound isocitrate is decarboxylated to yield five carbon atom containing alpha ketoglutaric acid.

The alpha- ketoglutarate is the  5-carbon intermediate of the citric acid cycle which is salt of alpha ketoglutaric acid. The last reaction in the citric acid cycle produces a product that is a substrate for the first reaction of the citric acid cycle.

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The equation of the reaction is; B2O3 + CoO -----> Co(BO2)2.

The term chemical reaction has to do with the interaction  between reactants in order to yield products.  We know that when a chemical reaction occurs, the reactants are rearranged to form the products.

Now the first step in this reaction is that the Borax  is heated to form boric anhydride (B2O3). Thus compound now reacts with cobalt II oxide as follows; B2O3 + CoO -----> Co(BO2)2.

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a) Mg is oxidized and O2 is reduced

b) Zn is oxidized while Pb(NO3)2 is reduced.

Oxidation is defined as:

Reduction is defined as:

Looking at the first reaction, the Mg atom gains oxygen to become MgO. This means that Mg is oxidized. The oxidizing agent is O2. At the same time, O2 is being reduced and the reducing agent is Mg.

For the second reaction, the oxidation number of Pb is reduced from +2 to 0. Thus, Pb has been reduced by Zn while Zn itself has been oxidized. The reducing agent here is Zn while the oxidizing agent is Pb(NO3)2.

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400 BTU of wasted heat energy is present in the form of electricity.

So, when efficiency is 60%, energy is used 60% of the time and lost 40% of the time. Thus, according to question, the energy that is wasted is:

1000 BTUx (40/100) = 400 BTU

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The correct value is 1417.7 grams.

The mass of a sample of Nacl that needs 732.6 kj of heat to melt completely is 1417.7 grams.

Enthalpy of fusion is the quantity of heat energy needed to turn a unit mass of the a solid now at melting point into such a liquids without raising the temperature.

Some key point for enthalpy of fusion of melting ice are-

Calculation for the heat required-

Nacl has a delta.hfus = 30.2 kj/mol => [tex]\Delta H_{\text {fusion }}=30.2 \mathrm{~kJ} / \mathrm{mol}[/tex]

As a result, the enthalpy of fusion for 1 mole of sample NaCl is 30.2 kJ.

Additionally, the mass of 1 mole for NaCl is 58.44 grams.

For a quantity of 58.44 grams of NaCl, 30.2 kJ of heat are required.

Consequently, 732.6 kJ heat will be required for;

[tex]\frac{58.44 g}{30.2 k J} \times 732.6 k J=1417.65 \approx 1417.7[/tex] grams of NaCl.

Therefore, the mass of a sample of Nacl that needs 732.6 kj of heat to melt completely is 1417.7 grams of NaCl.

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An aqueous solution of a strong base has a pH of 10. 220 at 25°C then concentration of the base if the base is

(a)  LiOH =  1.66×[tex]10^{-4}[/tex]  M

(b)  [tex]Ba(OH)_{2[/tex] =  3.32×[tex]10^{-4}[/tex]M

Calculation ,

For calculation of concentration of the   LiOH and  [tex]Ba(OH)_{2[/tex] first we have to calculate pOH of the solution.

pH + pOH = 14

pOH = 14 - pOH = 14 - 10.22  = 3.78

pOH = -㏒ [ [tex]OH^{-}[/tex] ]

[ [tex]OH^{-}[/tex] ] = [tex]10^{-pH}[/tex] =  [tex]10^{-3.78}[/tex] = 1.66×[tex]10^{-4}[/tex]

So ,  concentration of the base LiOH =  1.66×[tex]10^{-4}[/tex]

So ,  concentration of the base [tex]Ba(OH)_{2[/tex] =  1.66×[tex]10^{-4}[/tex] ×2 = 3.32×[tex]10^{-4}[/tex]

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It is important to know if a substance is a molecular compound or an ionic compound because the boiling and freezing points of a solvent are colligative properties, and they depend on the solute particles.

Molecular compounds are pure things called that are created when atoms are joined by the sharing of electrons. Ionic compounds are formed by transferring electrons between the elements.

It is important to know the type of compounds before predicting because the more the solute particles the more the freezing point and lower the boiling points. And it tells how much amount f solute will be fine in the solvent.

Thus, knowing if a material is a molecular or ionic compound is crucial since a solvent's boiling and freezing temperatures are collaborative features that are dependent on the solute particles.

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The potential of a standard hydrogen electrode (s. h. e. ) be under the given conditions is - 0.029 V

Calculation ,

Formula used :

[tex]E_{cell}[/tex] = [tex]E_{cell}[/tex] ° - 0.059/n ㏒[tex]H_{2}[/tex]/ [tex][H^{+}]^{2}[/tex]

As we know that ,

[[tex]H^{+}[/tex]] = 0. 84 M

[tex]P_{H_{2}[/tex] = 2. 2 atm

Temperature ( T ) = 298  K

From reaction at electrode number of electrons involve ( n ) = 1

Standard electrode potential of  standard hydrogen electrode [tex]E_{cell}[/tex] ° = 0

Putting the value of all data in equation ( i ) , we get

[tex]E_{cell}[/tex] = 0  - 0.059/1 ㏒2. 2 / [tex](0. 84)^{2}[/tex] =  - 0.059 ㏒3.14 =  - 0.059×0.497

[tex]E_{cell}[/tex] = - 0.029 V

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The properties of all metals are "good conductors of heat and electricity".

Metals are excellent heat or electricity conductors and were malleable, ductile materials that may be pulled into wire and pounded into sheets. Apart from mercury, which appears a liquid at ambient temperature, most metals have solids with a distinctive silvery shine.

Due to the metals' atoms' ability to create a matrix across which outside electrons could easily travel, metals make good electrical and thermal conductors. The positive nuclei of the connecting metal ions are surrounded by a sea of electrons rather than orbiting their individual atoms.

Therefore, the properties of all metals are "good conductors of heat and electricity".

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To convert oxygen gas to solid, we need to continuous withdrawal of heat from the gas by cooling.

Matter is composed of particles and these particles that compose matter are always in constant motion. This is the main thrust of the so called Kinetic Theory of Matter.

Now we know that the particles that compose a solid are held in a fixed position thus they spread out or expand when heated. The particles of a liquid tend not to be held in fixed positions thus they can be poured.

Given that oxygen has a boiling point of -219°C and a freezing point of -183°C, it follows that at 0°C is a gas and at -200°C, oxygen is a liquid.

To convert oxygen gas to solid, we need to continuous withdrawal of heat from the gas by cooling.

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The two common by-products of sugar fermentation are acid ( like lactic acid) or hydrogen and gas(carbon dioxide). During fermentation , any gas that is produced by the microbes get trapped in the inverted Durham tube and bubbles will appear.

The acid production is indicated by the color change of medium from normal red to yellow and remains red for no acid production.

The respiration process can be aerobic or anaerobic. In both process glycolysis, which occur in absence of oxygen is common. In this process one molecule of glucose is converted into two molecules of pyruvic acid . Gycolysis occur in cell cytoplasm. In anaerobic respiration is a cytosolic process, which results in production of lactic acid ( lactic acid fermentation)   or ethanol and carbon dioxide (alcoholic fermentation)

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Answer is plug-in hybrid cars also offer advantages and disadvantages. The primary benefit is range. Plug-in hybrid vehicles include a gasoline engine in addition to an electric motor, whereas an electric car can only go as far as its batteries will allow. Plug-in drivers benefit from having the best of both worlds as a consequence.

what is a electric vehicle?

An electric car is fully electric. Instead of a petrol tank, it has a battery, and an electric motor rather than an internal combustion one. If your batteries run out, there isn't a backup motor like in a hybrid electric vehicle. Many versions, nevertheless, offer space for an extra battery. The Nissan Leaf, Tesla Model S, and Ford Focus Electric are a few examples.

what is a plug in hybrid electric vehicle?

A plug-in hybrid electric car combines (or, if you prefer, is a hybrid of) an electric and gasoline-powered vehicle. They have a gas tank, an internal combustion engine, an electric motor, and a battery. You could say they have everything. Gasoline and electricity are both used as fuel in plug-in hybrid electric vehicles. The Chevrolet Volt, Toyota Prius Plug-in, and Cadillac ELR are a few examples.

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Alkali metals nitrates on heating give the corresponding nitrogen dioxide and oxygen.

These are the metals which forms alkali when dissolved in water. They are any of the soft, light, reactive metals of Group 1 of the periodic table.

Some examples of alkali metals are as follows:

A periodic table is a tabular chart of the chemical elements according to their atomic numbers so that elements with similar properties are in the same column.

So therefore, alkali metals nitrates on heating give the corresponding nitrogen dioxide and oxygen.

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Benzene is produced as a side product when water react with phenyl magnesium bromide during Grignard reactions.

The Grignard reaction  involves an R-Mg-X, a carbon chain bound to a magnesium halide, used to form alcohols  by attacking carbonyls such as in aldehydes or ketones.

Here R act as a nucleophile and Mg-X act as a electrophile. Instead of attacking carbonyl, which is  present in the reaction, the benzene ring will attack  water molecules present around, grabbing a H⁺ and pushing away MgBr .    

The required reaction is :

PhMgBr + H₂O → Ph-H + MgBrOH

Thus from the above conclusion we can say that it is always advised to use dry Grignard to avoid this reaction.

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The pH of a buffer solution containing acid of pKa 7.5 will be 8.1.

The pH of a solution indicates its acidity or basicity. A pH below 7 is acidic, while pH above 7 is basic. 7 is considered as the neutral value.

A buffer is a solution that has the ability to resist the change in pH when an acid or a base is added to it. The natural example of buffer is blood.

According to the question, pKa of acid = 7.5

If concentration of base is x then, concentration of acid will be x/4.

According to the Henderson–Hasselbalch equation,

pH = pKa + log [A⁻] / [HA]

pH = 7.5 + log [[tex]\frac{x}{x/4}[/tex]]

pH = 7.5 + log 4 ⇒ 7.5 + 0.602

pH = 8.1

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Answer:

2.34 molality

Explanation:

Mole weight of KOH ( using periodic table ...rounded to 3 s.f.) =

              56.1 gm/mole

Number of moles in 43.2 g

  43.2 g  /  56.1 gm / mole =.770 mole

molality = .770 mole / .329 kg = 2.34 m

1-H NMR spectroscopy tool will be used for distinguishing a sample of 1,2,2-tribromopropane from 1,1,2-tribromopropane.

The preferred method for determining or validating the structure of organic molecules or those containing protons is H NMR. When compared to other nuclei, a solution-state proton spectrum may be obtained relatively quickly, and it contains a wealth of knowledge regarding a compound's structure.

It can be calculated by simply counting the number of unique hydrogens on one side of the symmetry plane will give you the count of signals individual molecules emit in a 1H NMR spectrum.

Therefore, 1-H NMR spectroscopy tool will be used for distinguishing a sample of 1,2,2-tribromopropane from 1,1,2-tribromopropane.

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option (c) 1 × 10-9 m is the right answer.

The [oh−] of the solution  having a [h3o ] of 1 × 10−5 m is 1 × 10-9 m.

The concentration of OH- ions will be,

OH- = Kw {H3O+}

{H3O+} = 1 × 10−5 M.

Kw = 14

On substituting the value in the equation,

OH = 14 { 1 × 10−5 M.}

OH = 1 × 10−9 M

Consequently, the [H3O+] of the solution is 1 × 10-5 M.

Option (C) is the right choice because the [OH-] of the solution will be 1 × 10-9 M.

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Answer:

decreased by a factor of 10

Explanation:

pH is defined in such a way that;

pH= −log10(H)

Where H represents the concentration of Hydronium or Hydrogen ions

Given that pH is changed from 1 to 2,

By rearranging the above formula , we get 10−pH = H

Therefore,  0.1/0.01 = 10 and 0.1 > 0.01

Hence, the concentration of hydronium ions in the solution is decreased by a factor of 10.

If the dehydration reaction of an alcohol is successful. The changes would be seen in the IR spectrum for the product compared to the starting material are as,

In dehydration reaction of alcohol (  O-H and  C-O bond ) contain , the water molecule ( [tex]H_{2}O[/tex] ) is release from the reactant and C-C double bond is form which is known as alkene in the product .

The reactant and product have different structure. To determine the structure of the compound IR spectroscopy is used. In IR spectrum the peak corresponds to 3400-3600 cm is missing in the product of  dehydration reaction of an alcohol. It means  O-H band is disappear from stating material.

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The boiling point of a solution consisting of cyclohexane (c6h12) dissolved in benzene if the freezing point of this solution is 0. 0°c is 80.9°C.

When a solute and a solvent are combined to form a liquid homogeneous mixture or solution, the properties that result are different from those of the pure substances. As a result, we can find a freezing point depression, boiling point elevation, and a few other cooperative properties, but these two are the focus of this article.

Taking into account that the freezing point depression constant solely depends on the solvent (cyclohexane), we can begin by utilizing the freezing point depression to determine the molality of the solution:

[tex]T_{fsolution} - T_{fsolvent} = -m * {K_{fsolvent}[/tex]

0. 0°c - 5.5°c = -m * 20.0 °c

[tex]m = \frac{-5.5}{- 20.0 }[/tex]

m = 0.275 m

The boiling point elevation formula is then used to get the solution's boiling point, which is once more dependent on the solvent's boiling point elevation constant:

[tex]T_{b, solution} - T_{b, solute} = m * Kb_{solvent} \\\\T_{b, solution} - 80.1 = 0.275m + 2.79\\\\T_{b, solution} = 80.9[/tex]

Therefore, The boiling point of a solution is 80.9°C.

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The option that is most likely to be true regarding L76, L77, and L79  is that option B: The assembly would incur an entropic penalty if they occupied a solvent-exposed site.

The entropic penalty in regards to ordered water is known to be one that tells or account  for any form of  weaker binding of the antibiotic novobiocin to what we call resistant mutant of DNA gyrase.

Note that in regards to the scenario above, the Entropic penalty is seen as the thermodynamically disfavored needs that is required in forming a cage of polar solvent molecules that is known to be seen around surface that has exposed hydrophobic potion of a molecule.

Hence, The option that is most likely to be true regarding L76, L77, and L79  is that option B: The assembly would incur an entropic penalty if they occupied a solvent-exposed site.

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See full question below

When Bs1A is assembled as an octamer, what is most likely to be true regarding L76, L77, and L79?

A. They are oriented toward the solvent-exposed exterior of the protein assembly.

B. The assembly would incur an entropic penalty if they occupied a solvent-exposed site.

C. Unlike in a monomer, they are not situated within the hydrophobic cap.

D. Their physiochemical properties are not substantially dependent on their hydrophobicity