Help pls !!!!!!!!!!!!!!!!!!!!!!

a) y = 1/2 √ −3(x + 1) + 4
- The function is multiplied by 1/2, indicating a vertical compression by a factor of 1/2.
- The function is multiplied by -3 inside the square root, indicating a horizontal compression by a factor of 1/3 and a reflection across the y-axis.
- The function is shifted 1 unit to the left, indicated by the (x + 1) inside the square root.
- The function is shifted 4 units up, indicated by the + 4 outside the square root.

a) y = (2(x − 1))^3 − 5
- The function is multiplied by 2 inside the cube, indicating a horizontal compression by a factor of 1/2.
- The function is shifted 1 unit to the right, indicated by the (x - 1) inside the cube.
- The function is shifted 5 units down, indicated by the - 5 outside the cube.

The transformations to f(x) = √x are as follows:
a) y = 1/2 √ −3(x + 1) + 4
- The function is multiplied by 1/2, indicating a vertical compression by a factor of 1/2.
- The function is multiplied by -3 inside the square root, indicating a horizontal compression by a factor of 1/3 and a reflection across the y-axis.
- The function is shifted 1 unit to the left, indicated by the (x + 1) inside the square root.
- The function is shifted 4 units up, indicated by the + 4 outside the square root.

The transformations to f(x) = x^3 are as follows:
a) y = (2(x − 1))^3 − 5
- The function is multiplied by 2 inside the cube, indicating a horizontal compression by a factor of 1/2.
- The function is shifted 1 unit to the right, indicated by the (x - 1) inside the cube.
- The function is shifted 5 units down, indicated by the - 5 outside the cube.

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The required equation of the line perpendicular to y=4 that passes through (-5,-2) is: x = -5

The equation of the line y=4 is a horizontal line that passes through the point (0,4).

A line perpendicular to this line would be a vertical line passing through the point (-5,-2).

The equation of a vertical line passing through the point (-5,-2) can be written in the form x = -5,

which means that the x-coordinate of any point on this line must be -5.

Therefore, the equation of the line perpendicular to y=4 that passes through (-5,-2) is: x = -5

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Answer:

q - 8

Step-by-step explanation:

q - 8

Answer:

q=0

Step-by-step explanation:

Answer:

35.13

Rounded: 35.1

Step-by-step explanation:

The figure will look like the attached image.

(My guess, based on hint)

We will first find the area of the circle.

Area of circle is radius squared times Pi

3x3x3.14=28.26

It is half circle so 28.26/2=14.13

The question didn't state the height, but the base is 6 and we'll assume it is 7 because the question has 7 in the third to last row. 7x6/2=21

14.13+21=35.13

Answer:

The three sectors of our economy -- private, public and non-profit -- are inextricably intertwined.

The 3 sectors of economy are:

There are three sectors of the economy, each consisting of the following:

Each of these sectors plays a crucial role in the overall economy and contributes to the production and distribution of goods and services.

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The line's y-intercept is equal to -3.

An inequality to express the possible distances Jim and Lee can travel in the taxi is 1.75x + 3.00 < 45.

In Mathematics, the y-intercept is sometimes referred to as an initial value or vertical intercept and the y-intercept of any graph such as a linear function, generally occur at the point where the value of "x" is equal to zero (x = 0).

Based on the information provided about the line on the graph, we have the following:

y-intercept of function P = (0, -3).

Next, we would determine the possible distances Jim and Lee can travel in the taxi:

1.75x + 3.00 < 45.

1.75x < 45 - 3

1.75x < 42

x < 42/1.75

x < 24.

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The statement about cosecant, secant, and cotangent values that is correct is Kayla's: The cosecant and secant of an acute angle are always greater than 1, but the cotangent can be greater than 1, less than 1 or equal to 1.

In Trigonometry, the sine of an acute angle is a ratio of the length of an opposite side of a right-angled triangle to the length of its hypotenuse. Also, the sine of an angle generally lies between -1 and 1.

In Trigonometry, the cosecant (cosec) of an acute angle is a ratio of the length of its hypotenuse to the length of an opposite side of a right-angled triangle. Thus, the cosecant of an angle is the reciprocal of the sine function and as such lies outside -1 and 1.

The cotangent of an acute angle is a ratio of the length of its adjacent side to the length of an opposite side of a right-angled triangle.

In conclusion, Kayla's statement about the values of cosecant, secant, and cotangent is correct.

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The solutions in radian units are:
Ω = 0.928, 2.213, 4.070, 5.355
The solutions should be entered as a comma-separated list:
Ω = 0.928, 2.213, 4.070, 5.355

The equation cos(Ω) = -cos(2Ω) can be solved by using the double angle formula for cosine. The double angle formula for cosine is cos(2Ω) = 1 - 2sin^2(Ω).

Substituting the double angle formula into the original equation gives:
cos(Ω) = - (1 - 2sin^2(Ω))

Rearranging the equation gives:
2sin^2(Ω) = 1 + cos(Ω)

Squaring both sides of the equation gives:
4sin^4(Ω) - 4sin^2(Ω) - cos^2(Ω) = 0

Using the identity cos^2(Ω) = 1 - sin^2(Ω) gives:
4sin^4(Ω) - 4sin^2(Ω) - (1 - sin^2(Ω)) = 0

Simplifying the equation gives:
4sin^4(Ω) - 3sin^2(Ω) - 1 = 0

Using the quadratic formula gives:
sin^2(Ω) = (3 ± √(9 + 16))/8

Solving for sin(Ω) gives:
sin(Ω) = ±√(7/8)

Taking the inverse sine of both sides gives:
Ω = sin^-1(±√(7/8))

The solutions in radian units are:
Ω = 0.928, 2.213, 4.070, 5.355

The solutions should be entered as a comma-separated list:
Ω = 0.928, 2.213, 4.070, 5.355

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rank(A) = 1

Given that A = $\left[\begin{array}{cc}a & b \\ a & b\end{array}\right]$, where $a \neq 0$.Let's find the rank of A:Rank(A) = number of leading 1's in the row echelon form of A.= $\left[\begin{array}{cc}a & b \\ a & b\end{array}\right]$=> $\left[\begin{array}{cc}a & b \\ 0 & 0\end{array}\right]$There are two leading 1's in row 1. Hence, rank(A) = 1.Now, let's find the basis of the null space of A:Null space of A is the set of all solutions to the equation $Ax=0$.So, $Ax$ = $\left[\begin{array}{cc}a & b \\ a & b\end{array}\right]$ $\left[\begin{array}{c}x \\ y\end{array}\right]$= $\left[\begin{array}{c}ax+by \\ ax+by\end{array}\right]$= $\left[\begin{array}{c}(a+b)x \\ (a+b)y\end{array}\right]$= $\left[\begin{array}{c}0 \\ 0\end{array}\right]$=> (a + b) x = 0 and (a + b) y = 0=> $x = \frac{-b}{a}y$=> $\left[\begin{array}{c}x \\ y\end{array}\right]$= $\left[\begin{array}{c}\frac{-b}{a}y \\ y\end{array}\right]$= $y \left[\begin{array}{c}\frac{-b}{a} \\ 1\end{array}\right]$=> Null space of A = $\{y \left[\begin{array}{c}\frac{-b}{a} \\ 1\end{array}\right] | y \in R \}$Let's take a = 1, b = 2. So, the null space of A = $\{y \left[\begin{array}{c}-2 \\ 1\end{array}\right] | y \in R \}$Therefore, the basis of the null space of A = $\left[\begin{array}{c}-2 \\ 1\end{array}\right]$Now, let's find the basis of the row space of A:Row space of A is the span of the rows of A.=> Row space of A = span $\left\{\left[\begin{array}{cc}a & b\end{array}\right]\right\}$Since rank(A) = 1, there is only 1 non-zero row. Therefore, a basis of the row space of A is $\left\{\left[\begin{array}{cc}a & b\end{array}\right]\right\}$.

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The points are not on the same side. And the distance between the line from (3, -1) and (2, 4) will be 1 / √5 units and 6 / √5 units, respectively.

Let (x₁, y₁) be the point and ax + by + c = 0 be the line. Then the distance between a point and a line will be given as,

[tex]\rm d = \dfrac{|ax_1 + by_1 + c|}{\sqrt{a^2 + b^2}}[/tex]

The diagram is given below.

The points are not on the same side of the line y = 2x - 6. Then the distance from a line to (3, -1) is given as,

d = |2 × 3 - (-1) - 6| / [√(2² + (-1)²)]

d = |7 - 6| / √5

d = 1 / √5

And the distance from a line to (2, 4) is given as,

d = |2 × 2 - 4 - 6| / [√(2² + (-1)²)]

d = |-6| / √5

d = 6 / √5

The points are not on the same side. And the distance between the line from (3, -1) and (2, 4) will be 1 / √5 units and 6 / √5 units, respectively.

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The equation that represents the amount of money Gilberto has after buying T-shirts for n sponsors at a cost of $4.75 per shirt can be written as nx - 4.75n = n² - 4.75n.

Assume count that Gilberto has n sponsors, and he plans to buy a t-shirt for each sponsor at a fee of $4.75 in step with a t-shirt. Assume also count on that every sponsor contributes x greenbacks to Gilberto's fundraising marketing campaign.

The overall amount of money Gilberto raises from all n sponsors is n instances x or nx. If Gilberto makes use of some of this cash to buy t-shirts, he may have nx - 4. 75n bucks left over.

Therefore, the equation that represents the quantity of cash Gilberto has after shopping for t-shirts is:

nx - 4. 75n = (n - 4. 75)n

simplifying this equation, we get:

nx - 4. 75n = n² - 4. 75n

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We have shown that ∫_((a,b])▒〖G(x)dF(x)=F(b)G(b)-F(a)G(a)-∫_((a,b])▒〖F(x)dG(x)〗〗 as required.

The given statement is that F and G are two cumulative distribution functions on the real line, and they have no common points of discontinuity in the interval (a, b). We need to show that ∫_((a,b])▒〖G(x)dF(x)=F(b)G(b)-F(a)G(a)-∫_((a,b])▒〖F(x)dG(x)〗〗

First, we can use the fact that F and G are cumulative distribution functions to write the integral of G(x)dF(x) as the difference of the product of F and G at the endpoints of the interval:

∫_((a,b])▒〖G(x)dF(x)=F(b)G(b)-F(a)G(a)〗

Similarly, we can write the integral of F(x)dG(x) as the difference of the product of F and G at the endpoints of the interval:

∫_((a,b])▒〖F(x)dG(x)=F(b)G(b)-F(a)G(a)〗

Subtracting the second equation from the first gives us:

∫_((a,b])▒〖G(x)dF(x)-∫_((a,b])▒〖F(x)dG(x)=F(b)G(b)-F(a)G(a)-F(b)G(b)+F(a)G(a)〗

Simplifying the right-hand side of the equation gives us:

∫_((a,b])▒〖G(x)dF(x)-∫_((a,b])▒〖F(x)dG(x)=0〗

Therefore, we have shown that ∫_((a,b])▒〖G(x)dF(x)=F(b)G(b)-F(a)G(a)-∫_((a,b])▒〖F(x)dG(x)〗〗 as required.

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4.61 x 10¹⁷ atoms of radon means that is the total number of atoms in the  element and is dependent on the number of mole.

This is referred to as the proportionality factor that relates the number of constituent particles in a sample with the amount of substance in that sample.

One mole of a substance is equal to 6.022 × 10²³ units of that substance (such as atoms, molecules, or ions). The number 6.022 × 10²³ is known as Avogadro's number or Avogadro's constant. The concept of the mole can be used to convert between mass and number of particles.

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A. My sister is a graduate of Polytechnic University and a border services officer who lives in North Delta.
B. Yesterday, Jasmine left to visit her friend in Alberta.
A. They listened to relaxing music while they did their homework, which helped them concentrate.
B. To help them focus on their homework, they listened to relaxing music.

Combining sentences is a useful writing technique that helps make sentences concise and easy to read. Combining two or more sentences into one sentence can also help to create smoother transitions between ideas. When combining sentences, it is important to make sure the sentence remains grammatically correct, and to retain important information from the original sentences.

Another way to combine sentences is to delete certain words or phrases. For example, in the sentence “Yesterday, Jasmine left to visit her friend in Alberta”, the phrase “yesterday” can be removed without changing the meaning of the sentence.

You can also combine sentences by changing the order of the words. For example, in the sentence “They listened to relaxing music while they did their homework, which helped them concentrate”, the order of the words can be changed to “They did their homework while they listened to relaxing music, which helped them concentrate”.

Finally, it is important to make sure that the sentence remains grammatically correct. When combining sentences, it is important to make sure that the sentence still has a subject and verb, and that the verb is still in the correct tense.

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J is a maximal ideal.

1. To prove that A/J is a commutative ring with unity, note that the operations of addition and multiplication on A/J are well-defined and are commutative since they are inherited from the commutative ring A. Furthermore, the additive identity of A is the same as the additive identity of A/J, and therefore A/J has a unity.
2. Suppose first that J is a prime ideal of A. Then, if A/J is not an integral domain, there exist two nonzero elements x,y of A/J such that xy=0. This means that x and y are in the same coset of J in A. Thus, x-y is an element of J. Since J is prime, either x or y must be in J, which is a contradiction. Therefore, A/J is an integral domain. Conversely, if A/J is an integral domain, then the same argument can be reversed to show that J is a prime ideal.
3. If J is a maximal ideal of A, then A/J is a field by the fact proved in this chapter. Since a field is an integral domain, J is a prime ideal.
4. Suppose that A/J is a field. Then, for any ideal I of A, either I is contained in J or J is contained in I. This implies that J is a maximal ideal.

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Kim should use 8/3 (or 2.67) ounces of oil in the recipe.

what is a linear equation?

A linear equation is an algebraic equation in which each term is either a constant or the product of a constant and a variable raised to the first power (i.e., the exponent of the variable is 1).

Based on the table, we can see that the recipe calls for a total of 24 ounces of dressing, with a ratio of 3 parts oil to 1 part vinegar.

To calculate how much oil Kim should use, we can set up a proportion:

3 parts oil : 1 part vinegar = x ounces of oil : 8 ounces of vinegar

Cross-multiplying, we get:

3x = 8

Dividing both sides by 3, we get:

x = 8/3

To complete the table, we can fill in the remaining values based on the given ratio:

Total Ounces of Dressing Ounces of Oil       Ounces of Vinegar

               12                                    9                         3

               16                                   12                      4

               20                                 15                         5

               24                                 18                         6

Therefore, Kim should use 8/3 (or 2.67) ounces of oil in the recipe.

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If the velocity of the fisherman is 4.00 m/s when he jumps into the boat, then the final velocity of the fisherman and the boat is 1.78 m/s.

Momentum is a vector quantity, which means that it has both magnitude and direction.

We can solve this problem using the law of conservation of momentum, which states that the total momentum of a system is conserved if there are no external forces acting on it.

The system's starting momentum is determined by:

p1 = m1v1

where p1 is the initial momentum of the fisherman, m1 is his mass, and v1 is his initial velocity. Since the boat is initially at rest, its momentum is zero. As a result, the system's overall initial momentum is:

p1tot = p1 + p2 = m1v1

where p2 is the initial momentum of the boat and is equal to zero.

When the fisherman jumps into the boat, the system becomes a closed system with no external forces acting on it. As a result, the system's overall momentum must be conserved.

p1tot = p2tot

where p2tot is the final momentum of the system. The system's final momentum is determined by:

p2tot = (m1 + m2)vf

where m2 is the mass of the boat, and vf is the final velocity of the boat and the fisherman.

We can rearrange these equations to solve for the final velocity vf:

p1tot = p2tot

m1v1 = (m1 + m2)vf

vf = (m1v1)/(m1 + m2)

Substituting the given values, we get:

vf = (80.0 kg)(4.00 m/s)/(80.0 kg + 100.0 kg)

vf = 1.78 m/s

Therefore, the final velocity of the fisherman and the boat is 1.78 m/s.

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Therefore, f(x) = [[x − 2]] is discontinuous at x = k - 2 and x = k + 2. The discontinuities at these points are removable.

The function f(x) = [[x − 2]] is discontinuous at any value of x that is two units away from an integer. That means it is discontinuous at x = k - 2 and x = k + 2, where k is any arbitrary integer.

The discontinuities at x = k - 2 and x = k + 2 are both removable. That is because the discontinuities occur when the left- and right-hand limits of the function are not equal, and the limits can be made equal by redefining the value of the function at the point of discontinuity.

To solve the problem, set the left- and right-hand limits equal to each other and solve for x.

Left-hand limit: lim x→k-2  f(x) = lim x→k-2 [[x − 2]] = [[k - 2 - 2]] = [[k - 4]]
Right-hand limit: lim x→k+2  f(x) = lim x→k+2 [[x − 2]] = [[k + 2 - 2]] = [[k]]

Equating the two limits, we have [[k - 4]] = [[k]]. Solving for x, we get x = k - 2 and x = k + 2.

Therefore, f(x) = [[x − 2]] is discontinuous at x = k - 2 and x = k + 2. The discontinuities at these points are removable.
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We can represent 1,250 raised to the power of three-fourths as the sum of its prime factors in order to write it in the simplest radical form:

1,250 = 2 × 5 × 5 × 5 × 5

Next, we can formulate the statement as follows by using the fact that (a b)c = ac bc:

[tex](2\times5^3)^3/4 = 2^{(3/4)} \times(5^3)^{(3/4)[/tex]

Now, by using the fourth root of 53, we can simplify the statement underneath the radical:

[tex](2\times5^3)^3/4 = 2^{(3/4)} \times5^{(9/4)[/tex]

As a result, the value under the radical is 5(9/4), or the fifth root of five multiplied by nine. 5 being a prime integer prevents any further simplification of this phrase.

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Answer:

5

Step-by-step explanation:

The answer above is correct.

The daily percent οf decrease is 12.94%.

Sο the cοrrect οptiοn is: 12.94%.

Percentage decrease is the percentage by which a quantity οr value has decreased cοmpared tο its οriginal οr previοus value. It is calculated by taking the difference between the οriginal value and the new value, dividing that difference by the οriginal value, and then multiplying by 100 tο cοnvert the result intο a percentage. The fοrmula fοr percentage decrease is:

Percentage decrease = [(Original value - New value) / Original value] x 100%

The fοrmula fοr the amοunt οf radiοactive element remaining, r, in a 100-mg sample after d days is given as:

[tex]r = 100(1/2)^{(d/5)[/tex]

Tο find the daily percent οf decrease, we need tο find the difference between the amοunt οf the element at the start οf a day and the amοunt at the end οf that day, and then express this as a percentage οf the starting amοunt.

Let's assume that we start with 100 mg οf the radiοactive element. After οne day, the amοunt remaining is:

[tex]r = 100(1/2)^{(1/5)[/tex] ≈ 87.06 mg

The difference between the starting amοunt and the amοunt at the end οf the day is:

100 - 87.06 = 12.94

Tο express this as a percentage οf the starting amοunt, we divide this difference by the starting amοunt and multiply by 100:

12.94/100 * 100% = 12.94%

Therefοre, the daily percent οf decrease is 12.94%.

Sο the cοrrect οptiοn is: 12.94%.

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Therefore, 13.509 is roughly the standard deviation of the number of attendees who would favour chicken.

The degree of variation or dispersion in a set of data is measured by standard deviation. It calculates how far the data points, on average, deviate from the mean (average) of the data collection. Finding the square root of the data's variation yields the standard deviation. In statistics, the standard deviation is frequently used to characterise the distribution of data and is significant in areas like science, finance, and economics. It can be used to assess the validity of statistical data and to contrast different groups of data.

given

The following formula must be used to determine the standard deviation of attendees who would favour chicken as the main course:

σ = √(np(1-p))

When we change the numbers, we obtain:

σ = √(780 x 0.38 x 0.62) (780 x 0.38 x 0.62)

σ = √(182.616) (182.616)

σ = 13.509

Therefore, 13.509 is roughly the standard deviation of the number of attendees who would favour chicken.

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By answering the supplied question, we may infer that the response is slope As a result, the equation's y-intercept is equal to -8.

A line's slope determines how steep it is. The gradient is mathematically expressed as gradient overflow. By dividing the vertical change (run) between two spots by the height change (rise) between the same two locations, the slope is determined. The equation for a straight line, y = mx + b, is written as a curve form of an expression. When the slope is m, b is b, and the line's y-intercept is located (0, b). For instance, the y-intercept and slope of the equation y = 3x - 7 (0, 7). The location of the y-intercept is where the slope of the path is m, b is b, and (0, b).

The slope of the line is represented by the coefficient of x in the equation Y = -6x - 8.

As a result, the equation's slope is -6.

-8, the line's y-intercept, serves as the equation's constant term.

As a result, the equation's y-intercept is equal to -8.

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The angle LZW, given that angles Izw and Wzo are supplementary, would be an Obtuse angle.

If the angles Izw and Wzo are supplementary, then their sum is equal to 180 degrees.

Since Wzo is an acute angle (meaning it measures less than 90 degrees), we know that Izw must be an obtuse angle, so that their sum is 180 degrees. An obtuse angle is an angle that measures greater than 90 degrees and less than 180 degrees. It is "obtuse" because it is more than a right angle (90 degrees), which is considered "sharp" or "acute".

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The value of x in the sequence notation is 27/4

From the question, we have the following sequence that can be used in our computation:

[tex]\sum\limits^4_{j=-2} {2x(-\frac{3}{2})^j = \frac{1389}{32}[/tex]

When the above expression is expanded, we have the following equation

2x[(-3/2)⁻² + (-3/2)⁻¹ + (-3/2)⁰ + (-3/2)¹ + (-3/2)² + (-3/2)³ + (-3/2)⁴] = 1389/32

Evaluate the exponents the expressions

So, we have

2x[4/9 - 2/3 + 1 - 3/2 + 9/4 - 27/8 + 81/16] = 1389/32

Evaluate the fractions

2x * 463/144 = 1389/32

Evaluate the products

x * 463/72 = 1389/32

Solve for x

x = 72/463 * 1389/32

Evaluate

x = 27/4

Hence, the value of x is 27/4

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The distance between the two groups after the hikes is approximately 12.04 miles.

A right triangle's connection between its sides is described by the Pythagorean Theorem, a foundational idea in mathematics. It claims that the hypotenuse's square length, which is the side that faces the right angle, equals the sum of the squares of the lengths of the other two sides of any right triangle. The Pythagorean Theorem is frequently used to solve issues involving distance, velocity, and acceleration and has various applications in the disciplines of geometry, trigonometry, and physics.

The distance between the two groups serves as the hypotenuse of a right triangle, which is formed by the two pathways. The following formula can be used to determine the hypotenuse's length:

Distance = √((2+7)² + (5+3)²)

= √(9² + 8²)

= √(81 + 64)

= √(145)

≈ 12.04 miles

Therefore, the distance between the two groups after the hikes is approximately 12.04 miles.

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The simplified form of the expression log( 14/3 ) + log( 11/5 ) - log( 22/15 ) is log( 7 ).

Given the expression in the question;

log( 14/3 ) + log( 11/5 ) - log( 22/15 ) = ?

To simplify the expression, we use the property of logarithm.

log(a) + log(b) = log(ab)

log(a) - log(b) = log(a/b)

log( 14/3 ) + log( 11/5 ) - log( 22/15 )

log[ ( 14/3 ) × ( 11/5 ) ] - log( 22/15 )

Simplify

log[ 154/15 ] - log( 22/15 )

log[ 154/15 ] - log( 22/15 )

Now, using the quotient property of logarithm

log[ 154/15 ÷ 22/15 ]

log[ 154/15 × 15/22 ]

log[ 2310/330 ]

log( 7 )

Therefore, the simplified form is log( 7 ).

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Given the slope of the line and the intercept it forms with the y-axis, one of the mathematical forms used to derive the equation of a straight line is called the slope intercept form. Y = mx + b, where m is the slope of the straight line and b is the y-intercept, is the slope intercept form.

The equation of the line, as determined by the slope-intercept formula, is: y = mx + b, where m is the line's slope and b is its y-intercept. As x and y represent each point on the line, they must be maintained as variables when using the formula above.

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Answer:

50%.

Step-by-step explanation:

If 25 students picked vanilla, then it is 50%. This is because 25 is half of 50.

Yes, the two points (-2,-3) and (2,-1) belong to the same linear function.

To determine the function, we can use the slope-intercept form of an linear equation, which is y = mx + b, where m is the slope and b is the y-intercept.

First, we need to find the slope of the line using the formula m = (y2 - y1) / (x2 - x1). Plugging in the values of the given points, we get:

m = (-1 - (-3)) / (2 - (-2)) = 2 / 4 = 1/2

Now, we can use one of the given points and the slope to find the y-intercept. Let's use the point (2,-1) and plug in the values into the equation y = mx + b:

-1 = (1/2)(2) + b

Solving for b, we get:

b = -1 - 1 = -2

Therefore, the equation of the linear function is y = (1/2)x - 2.

So, the two points (-2,-3) and (2,-1) belong to the same function, which is y = (1/2)x - 2.

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To find the number of coins the statement made by Elena is correct.

The exponent of a number indicates how many times a number has been multiplied by itself. For instance, 34 indicates that we have multiplied 3 four times. Its full form is 3 3 3 3. Exponent is another name for a number's power. It might be an integer, a fraction, a negative integer, or a decimal.

Elena is on point. The formula 228 = 28 x 2 = 56 doesn't make sense in this situation since it suggests that they only counted for 28 days and received 228 coins, when the problem states that they counted for 28 days and received 228 coins. The fact that they counted for 28 days and came up with a total of 28 times 28 coins, or 784, makes the equation 228 = 28 x 28 make sense. Elena is accurate as a result.

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