Help!!!, will give brainly, thx, question is in the picture!!

The area of the figure is 13 cm².

We have,

From the figure,

We can make two rectangles.

Now,

Length = 5 cm

Width =  1 cm

Area of one rectangle.

= 5 x 1

= 5 cm²

Length = 4 cm

Width = 2 cm

Area of another rectangle.

= 4 x 2

= 8 cm²

Now,

Area of the figure,

= 5 + 8

=  13 cm²

Thus,

The area of the figure is 13 cm².

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Answer:

f(x) = 3x + 5

Step-by-step explanation:

You can use trial and error by putting each set of points into the equations and seeing which one works.

All four points work for the third function, f(x) = 3x + 5.

The sequence is arithmetic and the common difference is -8.

The term number 24 is:

A(24) = -206

To check if a sequence is arithmetic, take the difference between the consecutive terms, you should get the same value for all the cases.

Here we have:

-22, -30, -38, -46, ...

The differences give:

-30 + 22 = -8

-38 + 30 = -8

-48 + 38 = -8

We get the same thing in all, so the sequence is arithmetic, and the common difference is -8.

The n-th term of this sequence will be:

A(n) = -22 + (-8)*(n - 1)

Then the 24th term is:

A(24) = -22 + (-8)*(24 - 1)= -206

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The value of operated function is -3x²-13x+4.

Given are two functions f(x) = -x²+10x+3 and g(x) = -4x²-3x+7, we need find g(x) - f(x),

So,

g(x) - f(x) = -4x²-3x+7 - (-x²+10x+3)

= -4x²-3x+7 + x²-10x-3

Combining the like terms,

= -4x²+x²-3x-10x+7-3

= -3x²-13x+4

Hence the value of operated function is -3x²-13x+4.

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Answer:

11.40=7.50+0.65x. There are 6 toppings

Step-by-step explanation:

Answer: Equation: 7.50+(0.65 x 6)

6 toppings on the pizza

Dana will need 8 gallons of fuel for her trip and it will cost her $35.60 in total.

To calculate the total cost of fuel for Dana's trip, we need to determine how many gallons of fuel she will need.

For the trip from New York to Boston, which is a distance of 200 miles, Dana will need 200/50 = 4 gallons of fuel.

For the return trip from Boston to New York, which is another 200 miles, Dana will also need 4 gallons of fuel.

Therefore, the total amount of fuel Dana will need for the round trip is 4 + 4 = 8 gallons.

Since biodiesel fuel costs $4.45 per gallon, the total cost of fuel for Dana's trip will be 8 x $4.45 = $35.60.

So Dana will need 8 gallons of fuel for her trip and it will cost her $35.60 in total.

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Theorem 4.4.4 is the divisibility by a prime theorem, which states that any integer n greater than 1 is divisible by at least one prime number. This theorem is a fundamental result in number theory and has many important applications.

To prove this theorem, we can use proof by contradiction. Suppose that there exists an integer n greater than 1 that is not divisible by any prime number. Then n must be a composite number, since it is not prime and has factors other than 1 and itself. Let p be the smallest prime divisor of n, which exists by the well-ordering principle.

Since p is the smallest prime divisor of n, it follows that p ≤ √n. If p > √n, then p cannot divide n, which contradicts the assumption that p is a divisor of n. Therefore, p ≤ √n, and we have p ≤ n/p, which implies that [tex]p^2 ≤ n[/tex].

Since n is composite, we can write n = ab, where a and b are positive integers greater than 1. Since p is a prime divisor of n, it must divide either a or b, say a without loss of generality. But then p divides a and hence p is a divisor of the composite number a, which contradicts the choice of p as the smallest prime divisor of n.

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Answer:

1. For the 4th period:

Mean = (10+11+12+13+16+17+18)/7 = 13

Mean Absolute Deviation (MAD) = [(|10-13| + |11-13| + |12-13| + |13-13| + |16-13| + |17-13| + |18-13|)/7] = 2

For the 6th period:

Mean = (19+20+19+20)/4 = 19.5

Mean Absolute Deviation (MAD) = [(|19-19.5| + |20-19.5| + |19-19.5| + |20-19.5|)/4] = 0.5

2. The 6th period, on average, scored better on the quiz by 6.5 points (19.5-13=6.5). The difference between the mean scores is larger than the mean absolute deviation, which indicates that the data is spread out and not clustered around the mean. There is no overlap in the data between the two classes, which indicates that the 6th period did better than the 4th period on the quiz.

We can use the fact that the sum of angles in a triangle is 180 degrees, and the sum of angles in a quadrilateral is 360 degrees, to solve for the variables.

For the first three angles:

M = 180 - 54 - 46 = 80

W = 180 - 46 - 130 = 4

K = 360 - 54 - 130 - 46 = 130

For the last two angles:

The sum of angles in a triangle is 180 degrees, so:

3aº + 110° + 180° = 180°

3aº = -110°

This doesn't make sense, since an angle cannot be negative. Therefore, there is no solution for a that satisfies the given conditions.

Answer:

M = 80

W = 4

K = 130

There is no solution for a that satisfies the given conditions.

first off, let's notice something, hmm the volume is in ft³, however the height is 6 meters, so hmmm and we need the radius is meters as well, so we'd need to convert the ft³ to m³, keeping in mind 1m³ has 35 ft³.

[tex]\begin{array}{ccll} m^3&ft^3\\ \cline{1-2} 1 & 35\\ x& 8\pi \end{array} \implies \cfrac{1}{x}~~=~~\cfrac{35}{8\pi }\implies \cfrac{8\pi }{35}=x[/tex]

now, let's check its volume then

[tex]\textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ V=\frac{8\pi}{35} ~m^3\\ h=6~m \end{cases}\implies \cfrac{8\pi }{35}=\cfrac{\pi r^2(6)}{3}\implies \cfrac{8\pi }{35}=2\pi r^2 \\\\\\ \cfrac{8\pi }{35\cdot 2\pi }=r^2\implies \cfrac{4}{35}=r^2\implies \sqrt{\cfrac{4}{35}}=r\implies \stackrel{ meter }{0.72}\approx r[/tex]

To solve the equation [tex]tan 25^{o} + tan 110^{o} = \frac{-1}{1-tan25^{0}tan110^{o} }[/tex], we first need to simplify the expression on the right-hand side. Using the identity for the tangent of the sum of two angles.

[tex]tan(25^{o} + 110^{o} ) =[/tex] [tex]\frac{(tan 25^{0} + tan 110^{0} )}{(1 - tan 25^{0} tan 110^{0} )}[/tex]
Multiplying both sides by the denominator on the right-hand side of the original equation. We can substitute the expression on the left-hand side with the tangent of the sum of two angles:

[tex]\frac{(tan 25^{o} + tan 110^{o} )}{(1 - tan 25^{o} tan 110^{o} )} =-1[/tex]

[tex]tan(25^{o} + 110^{o} ) = tan 135^{0} = -1[/tex]
Therefore, the equation simplifies to:

-1=-1
This is a true statement, so the original equation is satisfied. Therefore, the solution to the equation is:

[tex]tan 25^{o} + tan 110^{o} =\frac{-1}{1-tan 25^{o} tan 110^{o}}[/tex] is true for any values of tan 25∘ and tan 110∘.
To solve the given equation using the given terms, you can use the tangent addition formula:

[tex]tan(A + B) = \frac{ (tanA + tanB)}{ (1 - tanAtanB)}[/tex]
Here, A = 25° and B = 110°. Plugging in these values, we have:

[tex]tan(25^{o} + 110^{o} ) = (tan(25^{o} ) + tan(110^{o})) / (1 - tan(25^{o}) tan(110^{o} ))[/tex]
Now, we need to find if [tex]tan(25^{o} + 110^{o} )[/tex] equals -1:

[tex]tan(135^{o} ) = \frac{ (tan(25^{o} ) + tan(110^{o} ))}{ (1 - tan(25^{o} )tan(110^{o} ))}[/tex]
As tan(135°) is indeed equal to -1, the given equation is true.

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The value of the integral is approximately 16.416.

We can use the change of variables s = xy, t = xy^2 to transform the integral ∫R xy^2 dA into an integral over the region R' in the st-plane:

∫R xy^2 dA = ∫R' t ds dt

where R' is the region bounded by s = 2, s = 5, t = 2, and t = 5.

To find the limits of integration for s and t, we solve for x and y in terms of s and t:

s = xy --> y = s/x

t = xy^2 --> y = (t/x)^{1/2}

Equating these expressions for y, we get:

s/x = (t/x)^{1/2} --> x = (s^2/t)^{1/3}

Substituting this into s = xy, we get:

y = s/x = s^{1/3}t^{-1/3}

Now we can express the integral over R' in terms of s and t:

∫R' t ds dt = ∫2^5 ∫2^5 t (∂s/∂t) ds dt

where (∂s/∂t) is the Jacobian determinant of the transformation:

(∂s/∂t) = | ∂s/∂t ∂t/∂t |

| ∂s/∂s ∂t/∂s |

= | y   2xy^2 |

         | x   3xy^2 |

       = | s^{1/3}t^{-2/3}   2s^{2/3}t^{1/3} |

         | (s^2/t)^{1/3}   3(s^2/t)^{2/3} |

       = s^{1/3}t^{-2/3} (3s - 2t)

Substituting this and the expression for y into the integral, we get:

∫R xy^2 dA = ∫2^5 ∫2^5 t s^{1/3}t^{-2/3} (3s - 2t) ds dt

Simplifying and evaluating the integral, we get:

∫R xy^2 dA = 3/4 (5^{4/3} - 2^{4/3}) - 1/2 (5^{5/3} - 2^{5/3})

Therefore, the value of the integral is approximately 16.416.

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Answer:

16 quarts left.

Step-by-step explanation:

just subtract.

Answer:

(x+2)^2 - 6

Step-by-step explanation:

Answer:

The asymptotic behavior of f(x), where the leading term is 3x, is a straight line that grows without bound as x approaches infinity or negative infinity. The function has a slope of 3 and becomes increasingly steep in the positive and negative directions. This means that the function will either constantly increase or constantly decrease without limit as x approaches infinity or negative infinity.

The probability that it runs on electrical power and has an alarm is 0.54.

In the collection of clocks at Dr. Zadok's Museum, 28% run on electrical power, 45% have alarms, and 54% either run on electrical power or have alarms.

The number of clocks that do not meet both requirements (i.e., those that do not operate on electrical power or do not have alarms) can be subtracted from the total number of clocks in order to get the number of clocks that do so:

The probability that it runs on electrical power and has an alarm is calculated as,

P = 54 / 100

P = 0.54

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The solution is,  the changes in her account is a debit of $11 i.e. -$11

Here, we have,

Given

Polly bought a cracker for $7 and then bought a parrot for $4.

Required

Determine the changes in the account

First, we need to determine the total amount spent;

we have,

Polly bought a cracker for $7

then, bought a parrot for $4.

so, total changes is:

$7 +  $4

=$11

Hence, the changes in her account is a debit of $11 i.e. -$11.

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The requried function that has the greater rate of change and y-intercept is function L.

The slope of the line is a tangent angle made by line with horizontal. i.e. m =tanx where x in degrees.

From the table of function B,
Slope is given as = -1 +7/-1+3 = 3

The linear equation of B is given as,
y + 1 = 3(x + 1)
y = 3x + 2

The linear equation of L is given as,
y = 6x + 4

Comparing both the expression,
6 > 3

Rate of change of L > Rate of change of B

Similarly,
The intercept of L > Intercept of B

Thus, the requried function that has the greater rate of change and y-intercept is function L.

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Based on the given scatterplot the best prediction of weight of the 28 week old dog will be approximately 75 lb pounds.

In the given scatterplot in the x-axis we find the age of the dog in weeks and on the y-axis there is the weight of the dog per each week.

From the given scatterplot after observing closely, we can see that at 28 weeks which is in between 26 and 30, the weight of the dog will be approximately present at 75 lb which is in between 70 lb and 80 lb pounds on the y-axis.

From the above explanation, we can conclude that the weight of the 28 week old dog is 75 lb pounds.

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Given question is not having enough information, so I am attaching the complete question below:

When matched with examples, the words would be:

The goal of visiting all fifty states during one's lifespan is clearly a great undertaking. Furthermore, the amusement park ride that attempts to realistically reproduce each person's experience of skydiving is an astonishing feat.

Moreover, it is readily apparent the school buses remain stationary and without activity in their parking lot throughout the weekend-- displaying their ordinary idleness. Likewise, electric cars are known to require fewer repairs than those powered by gas engines, offering a tremendous advantage above traditional cars.

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Answer:

this is same question

Step-by-step explanation:

Whenever you have this type of question (a question of "how many coins") along with a dollar amount, this will signal that you will have two equations. One equation will total the value of the coins. The second equation will total the number of each coin the person has.

The total value of the coins is $3.10. Let x = number of nickels and y = number of dimes. Since the coins have two different values, you must use two different variables. Assign the appropriate decimal value to each variable: 5 cents for a nickel, 10 cents for a dime.

Equation 1: .05x + .10y = 3.10

The second equation is a quantity equation: how many coins of each does Carter have?

Equation 2: x + y = 37.

.05x + .10y = 3.10

x + y = 37

Now, you need to cancel out one of the variables (either x or y) in order to solve for one.

Let's cancel out the x value first. Do this by multiplying each term in the second equation by -.05

The first equation stays the same.

.05x + .10y = 3.10

-.05x - .05y = -1.85

--------------------------

Now combine the x terms, y terms and the decimals. You'll notice that .05x and -.05x cancel out, so you are left with

.05y = 1.25

Divide both sides by .05

y = 25

Remember that y is the number of dimes. Carter has 25 dimes.

pls mark brainliest

(5)The measure of the angle, m∠H  is 62⁰.

(6) The measure of arc XY is 120⁰.

(7) The measure of the angle, m∠GEF is 32⁰ and arc EG is 116⁰.

(8) The measure of the variable x is 10 and c is 62.

The measure of the angles is calculated as follows;

question 5.

m∠H + m∠A = 180 (opposite angles of a cyclic quadrilateral)

4x - 6 +  7x - 1 = 180

11x = 187

x = 187/11

x = 17

m∠H = 4(17) - 6 = 62⁰

Question 6.

arc ZY = 2 x ∠X (intersecting chord theorem)

arc ZY = 2 x 55 = 110⁰

arc XY = 360 - (arc ZY + arc XZ) (sum of angles in a circle)

arc XY = 360 - (110 + 130)

arc XY = 120⁰

question 7.

m∠GEF = ¹/₂ arc GF (intersecting chord theorem)

m∠GEF = ¹/₂ x 64

m∠GEF = 32⁰

arc EG = 180 - arc GF (sum of angles of a semicircle)

arc EG = 180 - 64

arc EG = 116⁰

Question 8.

8x + 10x = 180 (opposite angles of a cyclic quadrilateral)

18x = 180

x = 180/18

x = 10

c + 2c - 6 = 180 (opposite angles of a cyclic quadrilateral)

3c - 6 = 180

3c = 186

c = 186/3

c = 62

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There are 1040 citizens in the community. x is the total number of citizens in the community.

Let's use x to represent the total number of citizens in the community. We know that 400 citizens did not agree with the analysis, which means that the remaining (1 - 5/13) = 8/13 of citizens did agree with the analysis. Therefore, we can set up the following equation:

(8/13)x = number of citizens who agreed with the analysis

We can solve for x by adding the number of citizens who did not agree with the analysis to the number who did agree:

x = (8/13)x + 400

Multiplying both sides by 13, we get:

13x = 8x + 5200

Simplifying, we get:

5x = 5200

Dividing both sides by 5, we get:

x = 1040

Therefore, there are 1040 citizens in the community.

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If 5/13 of citizens believe that difficulty with procrastination led to not agreeing with an analysis, and 400 citizens did not agree with this analysis, how many citizens live in the community?

The correct answer is B. P{z ≥ 1.88}.

To find the p-value for a hypothesis test, you need to determine the probability of observing a test statistic as extreme or more extreme than the one you obtained, assuming that the null hypothesis is true.

In this case, the test statistic is Z = 1.88, which represents the number of standard deviations that the sample mean is away from the hypothesized population mean of 20, under the assumption that the null hypothesis is true.

Since this is a one-tailed test in the positive direction (Ha: μ > 20), we want to find the probability of observing a Z value that is greater than or equal to the observed test statistic of 1.88.

We can use a standard normal distribution table or a calculator to find this probability, which is the p-value.

Using a standard normal distribution table or a calculator, we find that the area to the right of Z = 1.88 is 0.0307, or approximately 0.031.

Therefore, the p-value is P{z ≥ 1.88} ≈ 0.031.

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The triangle inequality states that for any two real numbers x and y, the sum of their absolute values is greater than or equal to the absolute value of their difference:

| x + y | ≥ | x | - | y |

or

| x + y | ≥ | y | - | x |

This means that the length of any side of a triangle must be less than or equal to the sum of the lengths of the other two sides. In other words, the shortest distance between two points is a straight line, and the direct path between two points is always shorter than the path that includes additional points.

This inequality is essential in geometry and helps in determining the feasibility of a triangle, especially in the calculation of the perimeter and area of the triangle. It also has applications in physics, engineering, and computer science, where it is used to analyze vector quantities and to establish the stability of various systems.

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Miami, FL is higher in altitude than New Orleans, LA.

On the number line, the zero point represents sea level.

Miami, FL has an altitude of about [tex]6\frac{3}{5}[/tex] feet,

so it is represented by a point [tex]6\frac{3}{5}[/tex] units above sea level.

New Orleans, LA has an altitude of about [tex]-6\frac{1}{2}[/tex] feet

so it is represented by a point 6 1/2 units below sea level.

Thus, we can see that Miami, FL is higher in altitude than New Orleans, LA.

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The Pythagorean theorem was used long before Pythagoras by the ancient Babylonians and Egyptians. The Pythagorean Theorem is a fundamental principle in mathematics that relates to the sides of a right triangle.

While Pythagoras is often credited with discovering this theorem, evidence suggests that the concept existed long before he did. The ancient Egyptians, for example, used the principle to construct right angles in their architectural designs. Similarly, the Babylonians and Indians also developed their own versions of the Pythagorean Theorem.

However, it is Pythagoras who is most commonly associated with this theorem as he developed a proof for it and gave it a more formal mathematical foundation. Nonetheless, it is clear that the Pythagorean Theorem was in use well before Pythagoras came along, and that it has played a crucial role in shaping our understanding of mathematics and geometry.

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The evaluation of the points on the graph of the function indicates;

(a) The intercepts are;

x-intercepts; (-π, 0), (0, 0), (π, 0)

y-intercept; (0, 0)

(b) Domain; [-π, π]

Range [-8, 8]

(c) The interval the function is increasing is; [-π/2, π/2]

The interval the function is decreasing are; [-π, -π/2], [π/2, π]

(d) The function is an odd function

A function is a definition or rule that maps the set of input variables unto the set of output variables, such that each input maps unto exactly one output.

The parameters in the graph of the function f indicates that we get;

(a) The intercepts of the graph are the point where the graph intersects the x and y-axis, therefore;

The intercepts are; (-π, 0), (0, 0), and (π, 0)

Therefore;

The x-intercepts are; (-π, 0), (0, 0), and (π, 0)

The y-intercept is; (0, 0)

(b) The domain is the set of possible x-values, the domain is therefore; -π ≤ x ≤ π

The range is the set of the possible y-values. The graph indicates that the range is; -8 ≤ y ≤ 8

(c) The interval on which the y-values of the graph is increasing is; [-π/2, π/2]

The interval on which it is decreasing are; [-π, π/2], and [π/2, π]

(d) A function is even if f(x) = f(-x)

f(π/2) = 8

f(-π/2) = -8

f(x) ≠ f(-x)

The function is odd if -f(x) = f(-x)

The points on the graph indicates

f(π/2) = 8, -f(π/2) = -8 = f(-π/2)

The function is an odd function

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