Here are the meanings of some of the symbols that appear in the statements below. means "is a subset of." • C means "is a proper subset of." • means "is not a subset of." Øis the empty set. For each statement, decide if it is true or false. Statement True False X {c, f, h, j, n} = {c, f, h, j, n} {2,4} C {1, 2, 3, 4, ...} {11, 13, 14, 16} CƠ {p, q, r, s, t, u} {p, r, u} O O ?

Answer:

Step-by-step explanation:

If the books length (L) is three times as long as the width (W), the equation for area is this:

L · W = 20 inches,

3W · W = 20 inches -  substituting L for 3W

So then the books perimeter is

The probability that at least one of the stocks will rise in price is 0.92. Rounded to 2 decimal places, the answer is 0.92.

To calculate the probability that at least one of the stocks will rise in

, we can use the complement rule of probability. The complement rule of probability states that the probability of an event occurring is equal to one minus the probability of the event not occurring. Therefore, the probability of at least one stock rising in price can be found by subtracting the probability that none of the stocks will rise in price from one.

Let P(A) be the probability that a stock will rise in price and P(A') be the probability that a stock will not rise in price.

The probability that none of the stocks will rise in price is:

P(A') * P(A') * P(A') = (0.2) * (0.5) * (0.8) = 0.08

The probability that at least one of the stocks will rise in price is:

1 - 0.08 = 0.92

Therefore, the probability that at least one of the stocks will rise in price is 0.92. Rounded to 2 decimal places, the answer is 0.92.

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Answer:

t = 2

Step-by-step explanation:

5t - 4 = 6

make t the subject

move -4 to the other side of the equal sign

5t = 6 + 4

5t = 10

t = 10/5

t = 2

Answer:

t=2

Step-by-step explanation:

5t=6+4

5t=10

t=2

Answer:

Step-by-step explanation:

The slope of a line given two points can be found by using the formula

[tex]m = \frac{ y_2 - y _ 1}{x_ 2 - x_ 1} \\ [/tex]

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(5,-11) and (-9, 17)

We have

[tex]m = \frac{17 - - 11}{ - 9 - 5} = \frac{28}{ - 14} = - \frac{28}{14} = - 2 \\ [/tex]

We have the final answer as

[tex] - 2 \\ [/tex]

Hope this helps you

There are 49.78 grams of fat in the meal consisting of a cheeseburger, large fries, and a chocolate shake.

A meal that comprises of a cheeseburger, large fries, and a chocolate shake contains a total of 1120 kcal. If 40% of total calories in this meal are from fat, how many grams of fat are in this meal?To calculate the grams of fat in the meal, we have to find out the total calories that come from fat, as 40% of the total calories in the meal come from fat.To find out how many calories come from fat, we have to convert the percentage of calories from fat into actual calories. Therefore, we can use the following formula:Fat percentage = (Calories from fat/Total calories) × 100%Let C be the total number of calories in the meal, then the number of calories from fat is given by:Calories from fat = 40% of CUsing this information, we can rewrite the formula as:Fat percentage = (40% of C/C) × 100%We know that the total number of calories in the meal is 1120 kcal, so we can substitute this value in the formula:Fat percentage = (40% of 1120/1120) × 100%Fat percentage = (448/1120) × 100%Fat percentage = 0.4 × 100%Fat percentage = 40%So 40% of 1120 kcal come from fat. To find out how many calories from fat this is, we can use the formula:Calories from fat = 40% of 1120Calories from fat = 0.4 × 1120Calories from fat = 448 kcalTo calculate the number of grams of fat in the meal, we need to convert the number of calories from fat into grams of fat. We can use the following formula:1 g of fat = 9 kcalUsing this information, we can rewrite the formula as:Calories from fat = grams of fat × 9 kcalDividing both sides of the equation by 9 kcal gives:Grams of fat = Calories from fat/9 kcalSubstituting the value of Calories from fat we calculated earlier gives:Grams of fat = 448 kcal/9 kcalGrams of fat = 49.78 g

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Answer: Projectile motion involves objects that are dropped, thrown straight up, ... pjm1. bracketleft. y = height t = time in seconds a = acceleration due to gravity ... Notice that this formula is a quadratic function, which means its graph will be a parabola.

Step-by-step explanation:

Answer:

32/3 is the answer and please write it easy

Step-by-step explanation:

Answer:

[tex] \frac{6 + r}{18 + r} = \frac{3}{5} [/tex]

[tex]5(6 + r) = 3(18 + r)[/tex]

[tex]30 + 5r = 54 + 3r[/tex]

[tex]2r = 24[/tex]

[tex]r = 12[/tex]

12 additional red marbles should be added to the 18 marbles already in the bag.

Answer: -4

Step-by-step explanation:

g(2)=2²-4(2)

g(2)=4-8

g(2)=-4

20 skittles double the number of red

the red skittles have 10 skittles the orange skittles have 20 so its additon

20

+

10

------

30

Answer: there isnt that much math into it but mk

20+10

---------

30

The estimated total time for all five pools is approximately 13.85 hours.

To estimate the time required to install the fifth pool using the learning curve, we can use the formula:

Time for nth unit = Time for first unit * (n^b)

Where:

Time for nth unit is the estimated time to install the nth pool

Time for first unit is the estimated time to build the first pool (30 hours)

n is the number of units (in this case, n = 5 for the fifth pool)

b is the learning curve exponent (85% learning rate corresponds to b = log(0.85) / log(2))

Let's calculate the estimated time for the fifth pool:

b = log(0.85) / log(2) ≈ -0.157

Time for fifth pool = Time for first pool * (5^b)

Time for fifth pool = 30 * (5^(-0.157))

Calculating this, we find:

Time for fifth pool ≈ 30 * 0.6764 ≈ 20.29 hours

Therefore, the estimated time required to install the fifth pool is approximately 20.29 hours.

To calculate the total time for all five pools, we need to sum the time required for each pool from the first to the fifth. Since the learning curve assumes decreasing time with increasing units, we can use a summation formula:

Total time for all units = Time for first unit * ((1 - (n^b)) / (1 - b))

Using this formula, let's calculate the total time for all five pools:

Total time for all five pools = Time for first pool * ((1 - (5^b)) / (1 - b))

Total time for all five pools = 30 * ((1 - (5^(-0.157))) / (1 - (-0.157)))

Calculating this, we find:

Total time for all five pools ≈ 30 * 0.4615 ≈ 13.85 hours

Therefore, the estimated total time for all five pools is approximately 13.85 hours.

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Answer:

Step-by-step explanation:

[tex]V = \frac{1}{3} bh \\ [/tex]

To solve for h multiply through by 3 to eliminate the fraction

That's

[tex]3V = 3 \times \frac{1}{3} bh \\ 3V = bh[/tex]

Divide both sides by b to make h stand alone

[tex] \frac{bh}{b} = \frac{3V}{b} \\ [/tex]

We have the final answer as

[tex]h = \frac{3V}{b} \\ [/tex]

Hope this helps you

Answer:

$5000

Step-by-step explanation:

800/16=50

50*100=5000

Answer:

z = -10

Step-by-step explanation:

5/10 = 1/2

1/2 of 10 = 5

a. To calculate the Euclidean distances between the three pairs of facilities, we use the formula: d = sqrt((x2 - x1)^2 + (y2 - y1)^2) where (x1, y1) and (x2, y2) are the coordinates of the two points.

Calculating the Euclidean distances:

dAB = sqrt((51 - 27)^2 + (59 - 17)^2) ≈ 45.28 miles

dBC = sqrt((61 - 51)^2 + (66 - 59)^2) ≈ 10.82 miles

dAC = sqrt((61 - 27)^2 + (66 - 17)^2) ≈ 51.23 miles

b. To calculate the rectilinear distances, we use the formula:

d = |x2 - x1| + |y2 - y1|

Calculating the rectilinear distances:

dAB = |51 - 27| + |59 - 17| = 27 + 42 = 69 miles

dBC = |61 - 51| + |66 - 59| = 10 + 7 = 17 miles

dAC = |61 - 27| + |66 - 17| = 34 + 49 = 83 miles

Therefore, the Euclidean distances are approximately dAB = 45.28 miles, dBC = 10.82 miles, and dAC = 51.23 miles. The rectilinear distances are dAB = 69 miles, dBC = 17 miles, and dAC = 83 miles.

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Answer:WFG=116

Step-by-step explanation:

Answer: -19.35

Step-by-step explanation:

Answer:

±sqrt( H *f•c)= L

Step-by-step explanation:

H=L^2/f•c

Multiply each side by fc

H *fc=L^2/f•c  * fc

H *f•c=L^2

Take the square root of each side

±sqrt( H *f•c)= sqrt(L^2)

±sqrt( H *f•c)= L

Answer:

  z^2 +7z -8 = 0

Step-by-step explanation:

Let z = 3x+2. Then we can substitute z wherever we see 3x+2.

  z^2 +7z -8 = 0 . . . . equivalent quadratic

__

This is easily factored to ...

  (z -1)(z +8) = 0

So, the original quadratic has solutions ...

  (3x +2) -1 = 0

  x = -1/3

and

  (3x +2) +8 = 0

  x = -10/3

Answer: 1/y^4

Step-by-step explanation:

Answer:

[tex]\frac{13}{99}[/tex]

Step-by-step explanation:

We require to create 2 equations with the repeating numbers after the decimal point.

let x = 0.1313.... → (1) ( multiply both sides by 100 )

100x = 13.1313.... → (2)

Subtract (1) from (2) thus eliminating the repeating numbers

99x = 13 ( divide both sides by 99 )

x = [tex]\frac{13}{99}[/tex]

That is 0.1313.... = [tex]\frac{13}{99}[/tex]

0.5983 falls within the range of -1.9719 to 1.9719, it does not surpass the critical value. Therefore, we fail to reject the null hypothesis.

To determine if there is a significant difference in the readiness for college between basketball and football players, we can perform an independent samples t-test.

Sample size for basketball (n1) = 102

Mean for basketball (Xbar1) = 460

Standard deviation for basketball (S1) = 92

Sample size for football (n2) = 117

Mean for football (Xbar2) = 442

Standard deviation for football (S2) = 57

We can set up the hypotheses as follows:

Null hypothesis (H0): There is no significant difference in the means of readiness for college between basketball and football players.

Alternative hypothesis (H1): There is a significant difference in the means of readiness for college between basketball and football players.

Assuming equal variances, we can calculate the pooled standard deviation (Sp) using the formula:

Sp = sqrt(((n1-1) * S1^2 + (n2-1) * S2^2)/(n1 + n2 - 2))

Plugging in the values:

Sp = sqrt(((101 * 92^2) + (116 * 57^2))/(101 + 116 - 2))

≈ sqrt((850048 + 190278)/(215))

≈ sqrt(1049026/215)

≈ sqrt(4875.182)

≈ 69.81

Next, we calculate the t-statistic using the formula:

t = (Xbar1 - Xbar2)/sqrt((Sp^2/n1) + (Sp^2/n2))

Plugging in the values:

t = (460 - 442)/sqrt((69.81^2/102) + (69.81^2/117))

≈ 18/sqrt(483.5271 + 421.9679)

≈ 18/sqrt(905.4950)

≈ 18/30.09

≈ 0.5983

Finally, we compare the calculated t-statistic with the critical t-value at the desired significance level and degrees of freedom (df = n1 + n2 - 2) to determine if the difference is significant.

At a .05 alpha level with (102 + 117 - 2) = 217 degrees of freedom, the critical t-value is approximately ±1.9719.

Since 0.5983 falls within the range of -1.9719 to 1.9719, it does not surpass the critical value. Therefore, we fail to reject the null hypothesis.

Conclusion: Based on the given data, there is insufficient evidence to conclude that there is a significant difference in the means of readiness for college between basketball and football players at a .05 alpha level.

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Answer:

55.94 mph

Step-by-step explanation:

The speedometer is measuring the speed of the vehicle according to the initial configuration.

The number of the revolution, n, that the wheels made in 1 hour is

[tex]n=\frac {\text{Speed}}{\text{Perimeter of the wheel}}[/tex]

Let p and p' be the perimeter of the old and the new wheels respectively.

[tex]P=\pi\times 94.4086[/tex] inches,

[tex]P'=\pi\times 96.0165[/tex] inches.

Since the speedometer is not calibrated according to the new configuration, so, the perimeter of old wheel has been used for the calculation of indicated speed.

[tex]\Rightarrow n=\frac{\text{Speed}}{P}[/tex]

Actually, this number of revolutions in 1 hour is made with the new tires having perimeter P'.

So, the actual speed with new tires is

[tex]=n\times P'[/tex]

[tex]= \frac{\text{Speed}}{P}\times P'[/tex]

[tex]=\frac {55}{\pi\times 94.4086}\pi\times 96.0165[/tex]

[tex]=\frac {55} {94.4086}\times 96.0165[/tex]

[tex]=55.94[/tex] mph

So, the actual speed of traveling is 55.94 mph.

By solving we gets for 6 hours of service, both Derrick's Dog Sitting and Darlene's Dog Sitting will cost the same.

Given the rates for Derrick's Dog Sitting and Darlene's Dog Sitting as shown in the given image. We need to write and solve an equation to find the number of hours for which Derrick's Dog Sitting $12 plus $5 per hour the total cost will be the same for the two services. We are also required to analyze which dog sitting service is more economical to use if we need 5 hours of service.The cost of Derrick's Dog Sitting can be represented as:

C = 12 + 5h

where C is the total cost for h hours.

The cost of Darlene's Dog Sitting can be represented as:

C = 7h where C is the total cost for h hours.To find the number of hours for which both services cost the same, we can equate both equations.

12 + 5h = 7h

Subtracting 7h from both sides, we get:

12 = 2h

Dividing both sides by 2, we get:h = 6

Therefore, for 6 hours of service, both services will cost the same

Therefore, Derrick's Dog Sitting and Darlene's Dog Sitting will cost the same for 6 hours of service.

From the given information, we know that the cost of Derrick's Dog Sitting is $12 plus $5 per hour and the cost of Darlene's Dog Sitting is $7 per hour. To find the number of hours for which the total cost will be the same for both services, we wrote and solved an equation. The equation was 12 + 5h = 7h. On solving it, we found that the number of hours for which the cost will be the same is 6 hours. Therefore, both services will cost the same for 6 hours of service.Now, we need to analyze which dog sitting service is more economical to use if we need 5 hours of service. We can calculate the cost for 5 hours of service for both services using their respective rates. For Derrick's Dog Sitting, the cost for 5 hours of service will be:

12 + (5 x 5) = $37

For Darlene's Dog Sitting, the cost for 5 hours of service will be:7 x 5 = $35

Therefore, if we need 5 hours of service, Darlene's Dog Sitting will be more economical to use as it will cost $2 less than Derrick's Dog Sitting.

Therefore, we can conclude that for 6 hours of service, both Derrick's Dog Sitting and Darlene's Dog Sitting will cost the same. However, if we need 5 hours of service, Darlene's Dog Sitting will be more economical to use as it will cost $2 less than Derrick's Dog Sitting.

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Without knowing any pricing information for Darlene's Dog Sitting, we can't fully answer the question. However, for Derrick's Dog Sitting the equation representing the cost is C = 12 + 5*H, where C is the total cost, and H is the number of hours.

In order to find the number of hours for which the total cost for both Derrick's and Darlene's dog sitting services is the same, we need to write and solve an equation. Let's denote the total cost using the symbol C, and the number of hours using H.

For Derrick's Dog Sitting, we know the cost is $12 for the initial fee, plus $5 per hour, which results in the following equation: C = 12 + 5*H.

However, we haven't been given the cost structure for Darlene's service, so we can't complete this part of the question without more information.

Regarding your second question, without knowing the cost for Darlene's Dog Sitting, we cannot say which one is more economical for 5 hours of service.

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The cost of the apples is 2.9 dollars.

The cost of the bananas is 5.7 dollars.

The total cost is 6 dollars, each apple cost $1.50 each banana cost $.30 and there’s two more bananas then apples.

Therefore,

let

x = number of apples

y = 2x

where

Therefore, using equations,

1.5(x) + y(0.30) = 6

Hence,

where

y = 2x

1.5(x) + 2x(0.30) = 6

1.5x + 0.6x = 6

2.1x = 6

divide both sides by 2.1

x = 6 / 2.1

x = 2.9 dollars

y = 2(2.9) = 5.7 dollars

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Answer: 6.75 cuz u caculate idk

Step-by-step explanation: why dont

you ask  your parent or teacher.

Answer:

Add that

Step-by-step explanation: