Hey so basically I'm having trouble understanding this problem so if someone can help me with the answer that'd be great thx <3

Two poles of heights 9 m and 14 m stand on a plane ground. If the distance between their feet is 12 m,
then what will be the distance between their tops?

Answer:

$1.70 per share

Step-by-step explanation:

37.90-36.20=1.70

By taking the product between the combinations of possible groups fo men and women we will see that the number of different committees is:

392

For a set of N elements, the number of different sets of K elements that can be formed is:

C(N, K) = N!/(K!*(N - K)!)

Here we have 8 men and 7 women, and we want to make a committee of 5 men and 6 women

Then the total number of different committees is given by the product between the different sets of 5 men and the different sets of 6 women, these are:

for men:

C(8, 5) = 8!/( 5!*(8 - 5)!) = (8*7*6)/(3*2*1) = 56

for women:

C(7, 6) = 7!/(6!*(7 - 6)!) = 7

Then the total number of different committees is:

C = 56*7 = 392

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If On December 12, Lowell Corporation accepted a $160,000, 120-day, non-interest-bearing note from Able.com. the maturity value of the note is:  $213,333.

Using this formula to find the maturity value of the note

Maturity value of the note =  Principal + interest

Let plug in the formula

Maturity value of the note = $160,000 + ($160,000 × 120 /360)

Maturity value of the note = $160,000 + $53,333

Maturity value of the note = $213,333

Therefore the maturity value of the note is $213,333.

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The required equation of inequality is 4 ≤ b ≤ 6

Given ; Cups of iced tea = 120 cups

and the cups of iced coffee should not be less than 180 cups

Thus this is a question of inequality

Each batch of iced tea makes = 30 cups

thus the required equation is

[tex]\frac{120}{30}[/tex] and this is less than the number of batches which is represented by b

thus the equation would be [tex]\frac{120}{30}[/tex]  ≤ b

And it should be less than 180 cups of iced tea

thus the equation would be

b ≤ [tex]\frac{180}{30}[/tex]

Thus the required equation is :

[tex]\frac{120}{30}[/tex] ≤ b ≤ [tex]\frac{180}{30}[/tex]

On simplifying this we will get ;

4 ≤ b ≤ 6

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Answer:

Step-by-step explanation:

Solution

Solve with the quadratic formula 

3k2+k−3=0    :    k=(−1+√376)/6 , k=(−1−√376 )/6   (Decimal:    k=0.84712…, k=−1.18046…)- Answer

Steps

3k2+k−3=0

Solve with the quadratic formula

For a quadratic equation of the form ax^2+bx+c=0,

the solutions are x1, 2=(−b±√b^2−4ac)/2a  where    a=3, b=1, c=−3 

Substituting we have

k1, 2= [(−1±√1^2−4· 3(−3)]/2· 3 

Apply rule 1^a=1 , therefore 1^2=1

=√1+4· 3· 3=√1+36

√1^2−4· 3(−3)=√37

Therefore,

k1, 2=(−1±√37)/2· 3 

k1, 2=(−1±√37)/6 

Separate the solutions

k1=(−1+√37)/6 

k2=(−1−√37)/6 

The solutions to the quadratic equation are:

k=(−1+√37)/6 , k=(−1−√37)/6 

k1=0.84712        k2=−1.18046

Equation of the parabola that passes through the points (-4, 7), (-3, 9), and (4,-5) is y = -1/2[tex]x^{2}[/tex] - 3/2 x + 9.

Given points:

(-4, 7), (-3, 9), and (4,-5).

Let parabola equation be y = a[tex]x^{2} +bx+c[/tex].

substitute (-4,7)

7 = a(16)+b(-4)+c

16a-4b+c-7 = 0.

substitute (-3,9)

9 = a(9)+b(-3)+c

9a-3b+c-9 = 0

substitute (4,-5)

-5 = 16a+4b+c

16a+4b+c+5=0.

solving three equations we get,

a = -1/2 , b = -3/2 and c = 9

substitute a,b and c values we get,

y = (-1/2)[tex]x^{2}[/tex] + (-3/2)x + 9

y = -1/2[tex]x^{2}[/tex] - 3/2 x + 9.

Therefore the equation of the parabola that passes through the points (-4, 7), (-3, 9), and (4,-5) is y = -1/2[tex]x^{2}[/tex] - 3/2 x + 9.

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It will take 7 days for Claire to sell as many candy bars as Ayden

Claire has sold 8 candy bars and sells 5 more each day

The first term = 8

Common difference = 5

nth term is = a+(n-1)d

= 8 +(n-1)5

= 8 + 5n - 5

= 3 +5n

Ayden has sold 20 candy bars and sells 3 more each day

The first term = 20

Common difference = 3

nth term = a+(n-1) d

= 20 +(n-1)3

= 20 + 3n -3

= 17 + 3n

Then,

3 + 5n = 17 + 3n

5n - 3n = 17 - 3

2n = 14

n = 14/2

n = 7

Hence, it will take 7 days for Claire to sell as many candy bars as Ayden

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The farmer should use 1200 pounds of type 1 mixture and 800 pounds of type 2 mixture to satisfy the given conditions

From given information,

Type 1: 45 percent of protein in the supplement is x pounds

Type 2: 20 percent of the protein in the supplement is (2000 - x) pounds

Also Mixture A 35% of the protein in the supplement is 2000 pounds

According to the equation after removing the percentage sign we have

45x + 20(2000-x)= 35*2000

45x + 40000 - 20x = 70000

25x = 30000

x = 1200

Now for type 2 mixture we have

2000 - 1200 = 800 pounds

Therefore, the farmer should use 1200 pounds of type 1 mixture and 800 pounds of type 2 mixture to satisfy the given conditions

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The equation of the vertical asymptote for the graph of the rational number g(x) = 6/x-1 is x - 1 = 0 or x = 1.

Given function:

g(x) = 6/x-1

vertical asymptote for any function is denominator is equal to zero.

x - 1 = 0

x = 1.

Therefore the equation of the vertical asymptote for the graph of the rational number g(x) = 6/x-1 is x - 1 = 0 or x = 1.

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The differentiation of the given function is [tex]9x^2tan(x^4)[/tex] + [tex]12x^{6}sec^2(x^4)+8x^3sec^2(x^4)[/tex].

In the given question we have to differentiate the given function with respect to x.

The given function is f(x)= [tex]tan(x^4)\cdot(3x^3+2)[/tex].

We have to differentiate the given function so we differentiate using the Product Rule.

The Product Rule of Differentiation is

d/dx[h(x)g(x)]=h(x) d/dx g(x)+g(x) d/dx h(x)

In the given function the value of

h(x) = [tex]tan(x^4)[/tex] and g(x) = [tex](3x^3+2)[/tex]

So;

f'(x)= [tex]tan(x^4)[/tex]d/dx [tex](3x^3+2)[/tex] + [tex](3x^3+2)[/tex] d/dx [tex]tan(x^4)[/tex]............(1)

We firstly find the value of d/dx [tex](3x^3+2)[/tex] and d/dx [tex]tan(x^4)[/tex].

We firstly find the value of d/dx [tex](3x^3+2)[/tex]

As we know that d/dx of x^n =nx^(n-1) and d/dx a=0

So;

d/dx [tex](3x^3+2)[/tex]= 3 d/dx [tex]x^3[/tex]+d/dx 2

d/dx [tex](3x^3+2)[/tex]=3(3[tex]x^2[/tex])+0

d/dx [tex](3x^3+2)[/tex]=9[tex]x^2[/tex]

Now finding the value of d/dx tan([tex]x^4[/tex])

d/dx [tex]tan(x^4)[/tex] = d/dx [tex]tan(x^4)[/tex] d/dx [tex]x^4[/tex]

d/dx [tex]tan(x^4)[/tex]= [tex]sec^2(x^4)\cdot(4x^3)[/tex]

d/dx [tex]tan(x^4)[/tex]= [tex]4x^3sec^2(x^4)[/tex]

Now putting the values of differentiation in equation 1

f'(x)= [tex]tan(x^4)\cdot9x^2[/tex] + [tex](3x^3+2)\cdot4x^3sec^2(x^4)[/tex]

f'(x)= [tex]9x^2tan(x^4)[/tex] + [tex]3x^3\cdot4x^3sec^2(x^4)+2\cdot4x^3sec^2(x^4)[/tex]

Simplifying

f'(x)= [tex]9x^2tan(x^4)[/tex] + [tex]12x^{3+3}sec^2(x^4)+8x^3sec^2(x^4)[/tex]

f'(x)= [tex]9x^2tan(x^4)[/tex] + [tex]12x^{6}sec^2(x^4)+8x^3sec^2(x^4)[/tex]

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The function is positive and increasing from 0 to 2.5, at negative and decreasing  from 0 to -2.5,  respectively.

How to find returns to scale?

Returns to scale involves an increase in an output more than when all the inputs increase proportionately.

Using the graph, there is a line segment from the origin to a point. at the middle of the third block making 2.5.

This shows an increase which is positive and on the other hand, there is a line segment from the origin towards left hand side on the number line showing a decrease and a negative from 0 to -2.5.

In conclusion, the line pointing upwards towards right hand side shows both positive and increase while the line pointing leftward shows decrease and negative.

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The value of the number 9.15 x 10° written in standard form is equal to 9.15.

As given in the question,

Given number is equal to :

9.15 x 10°

Given number 9.15 x 10°  is written in standard form.

The value of the given number 9.15 x 10°  written in standard form is given by:

9.15 x 10°

Here 10° = 1

Using property of number: Any number raise to zero is always equal to 1.

9.15 x 1

Using Multiplicative identity , number multiply to 1 remain number itself.

= 9.15

Therefore, the value of the number 9.15 x 10° written in standard form is equal to 9.15.

The complete question is:

What is the value of 9.15 x 10° written in standard form?​

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Answer:

40

Step-by-step explanation:

2 x 10⁷/5 x 10⁵ = 2/5 x 10^5-7 = 2/5 x 10² = 2 x 100/5

There were 40 times more white-tailed deer in 2000 than in 1905

Max gain 10.3 pounds of weight between the time he was a puppy and his 1-year check-up.

Two or more expressions with an Equal sign is called as Equation.

Given,

When Max was a puppy, he weighted [tex]5\frac{1}{2}[/tex] pounds

At his 1-year check-up with the vet, Max weighted 15.8 pounds

We need to find the weight did Max gain between the time he was a puppy and his 1-year check-up.

To find this we need to find the difference when Max was a puppy and after one year check up.

Difference is nothing but subtracting one value from another value.

Let us convert mixed fraction  [tex]5\frac{1}{2}[/tex] pounds to improper.

[tex]5\frac{1}{2}[/tex] =11/2=5.5

Now subtract 15.8-5.5

10.3 pounds.

Hence, max gain 10.3 pounds of weight between the time he was a puppy and his 1-year check-up.

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The total cost to be in the team will be $1192. He must earn an average of $119.2 per week for 10 weeks. If Ralph is paid at a flat rate of exactly q dollars each week, so the standard deviation will $0.

Total cost is the sum of all expenditures made to produce a certain level of output; when this total cost is divided by the quantity produced, average or unit cost is discovered. The sum of the fixed and variable costs is the total cost. For instance, if a company has a fixed cost per unit of $30 and a variable cost per unit of $5 that increases as output increases, the total cost will be $35. Total cost is equal to the sum of all fixed and variable costs. Total Cost = (Average Fixed Cost + Average Variable Cost) x Number of Units is another way to express it. All of this had to do with the total cost formula, which is a crucial idea for figuring out the total cost of production.

Here,

The expenses of team is,

Uniform=$67.00

Registration=$50.00

Tournaments=$775.00

Travel =$300.00

Total cost=sum of all expense

=67+50+775+300

=$1192

Average cost=Total cost/number of weeks he worked

=1192/10

=$119.2

Deviation of distribution cost,

If Ralph is paid at a flat rate of exactly q dollars each week then there will be $0 deviation.

It will cost $1192 in total to join the team. For ten weeks, he must make an average of $119.2 per week. If Ralph receives a fixed weekly salary of exactly q dollars, the standard deviation will be zero.

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Answer:

US$1.00=EC$2.70 TT$1.00=EC$0.40 calculate the value of : 1.EC$1in TT$ 2.US$80inEC$ 3.TT$648 in US$

Step-by-step explanation:

that what i've got is that I hope that helps you

The comparison done by Mr Jones means that Test A of standard deviation 7 is closer to the mean scores and Test B of standard deviation 12 is further apart from the mean score

The standard deviation is a statistic measure that expresses how much variance or dispersion there is in a group of numbers.

A high standard deviation suggests that the values are dispersed throughout a wider range,

A low standard deviation suggests that the values tend to be close to the established mean.

A positive value means the standard deviation is above the mean while a negative value means the standard deviation is below the mean

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The correct way to replace equation 1 into equation 2 using the substitution method is 2x+(-5x+10) = 7.

According to the question,

We have the following two equations:

Equation 1: y = -5x+10

Equation 2: 2x+y = 7

Now, we will substitute the value of y from equation 1 in equation 2.

So, we have the following expression:

2x+(-5x+10) = 7

(More to know: we can also solve this equation to find the value of x and then the obtained value of x can be put in equation 1 to find the value of y.)

Hence, the correct option is B.

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The relationship between the number of years that Simon's money is invested and the account balance can be described as 4:The relationship is linear. His account increases each year by a constant value of $28.

The simple interest due to Simon's account every year is:
= Simple interest rate x Amount invested

= 0.4% x 7, 000

= $28

This means that every year, Simon's account would increase by a value of $28.

This represents a linear relationship because in linear relationships, the value of the variables increases by a constant amount each year or period.

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a) The confidence interval is given as follows: (71.43, 77.17).

b) The manufacturer's claim is not correct, as 78 is not a part of the interval.

c) A sample of 55 employees is needed to achieve the desired margin of error.

The bounds of the t-distribution confidence interval, used when only the standard deviation for the sample is known, are given by the equation presented as follows:

[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]

The variables of the equation are presented as follows:

The critical value, considering the 95% confidence level and 12 - 1 = 11 df, is of:

t = 2.201.

The remaining parameters, namely sample mean, sample standard deviation and sample size are given as follows:

[tex]\overline{x} = 74.3, s = 4.52, n = 12[/tex]

(obtained using a calculator from the sample given in this problem).

The bounds of the interval are given as follows:

The interval does not contain the number 78, hence it is not a good estimate for the mean amount.

For item c, the z-distribution is used, as the population standard deviation is used, hence the minimum sample size is obtained as follows:

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]1.04 = 1.96\frac{3.91}{\sqrt{n}}[/tex]

[tex]1.04\sqrt{n} = 1.96 \times 3.91[/tex]

[tex]\sqrt{n} = \frac{1.96 \times 3.91}{1.04}[/tex]

[tex](\sqrt{n})^2 = \left(\frac{1.96 \times 3.91}{1.04}\right)^2[/tex]

n = 55. (rounded up, as a sample size of 54 would mean that the margin of error would be slightly above 1.04).

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Answer: 2/17 or 2 over 17

Step-by-step explanation:

The slope of a line KH if H(-4, 2) and K(2, -2) is -2/3.

A mathematical word used to define a line's direction and steepness is its slope or gradient.

If a line is rising from left to right, it is growing. The slope is positive, or m>0

If a line decreases from left to right, it is said to be diminishing. The slope is negative, indicating that m < 0

A line has zero slopes if it is horizontal. This function is constant.

The slope of a line is y - y₁ = m(x - x₁)

Slope m = (y₂ - y₁)/(x₂ - x₁)

m = (- 2 - 2)/(2 + 4)

m = - 4/6

m = - 2/3

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Answer:

x = 11

Step-by-step explanation:

using the rule of logarithms

[tex]log_{b}[/tex] x = n ⇒ x = [tex]b^{n}[/tex]

given

[tex]log_{3}[/tex] (2x + 5) = 3 , then

2x + 5 = 3³ = 27 ( subtract 5 from both sides )

2x = 22 ( divide both sides by 2 )

x = 11

The contribution margin rate is 40%.

What is contribution margin rate?

A company's contribution margin rate is the total revenue minus variable costs divided by the revenue.

First we need to determine the contribution margin in order to calculate the contribution margin rate. There are two approaches to determine the contribution margin.

Contribution Margin = $15 - $9 = $6

The contribution margin is $6.

Now we will calculate the contribution margin rate using this formula,

Contribution Margin Rate = Contribution Margin [tex]/[/tex] Sales Revenue

Contribution Margin Rate = $6 / $15

                                             = 0.4 * 100

                                             = 40%.

Hence the contribution margin rate is 40%.

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Answer:

1024

Step-by-step explanation:

using the rule of exponents

[tex]a^{m}[/tex] × [tex]a^{n}[/tex] = [tex]a^{(m+n)}[/tex]

, then

8 × [tex]2^{7}[/tex]

= 2³ × [tex]2^{7}[/tex]

= [tex]2^{(3+7)}[/tex]

= [tex]2^{10}[/tex]

= 1024

The area of two lawns will be 4000 square meters.

According to the question,

We have the following information:

Craig mows two lawns. The first lawn is 40 meters long and 20 meters wide. The second lawn has the same length, and a width that is 4 times as much as the first one.

So, the width of the second lawn = 4*20

Width of second lawn = 80 m

Now, formula to find area of rectangle:

Length*width

Area of first lawn:

40*20

800 square meters

Area of second lawn:

40*80

3200 square meters

Now, the area of two lawns = area of first lawn+ area of second lawn

Area = 800+3200

Area = 4000 square meters

Hence, the total area of two lawns is 4000 square meters.

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Answer: There is no solution

Step-by-step explanation:

The formatting of the question isn't clear, but I'll still explore both possibilities. If the square root is only applied to x, we can solve for the variable by adding 4 to both sides and then squaring both sides, which would give us 4. Since that is not an answer choice, it means the square root applies to x-4. With this problem, we square both sides right away. That gives us x=0, but plug 0 back into the original equation. Doing so gives us the square root of -4, which is not possible with real numbers, only with imaginary numbers.