Hi I need help with these questions, if you can only answer 1 that’s okay. Thank you!
Answers
Each square in the block represents each block of size = 0.1*0.4 = 0.04.
1.
The factor 1.5 is divided into two number because in the figure it is shown that the 1 is up to orange line and 0.5 is up to black line and we want to find only area of divided parts.
That is
1*0.4 + 0.5 * 0.4
= 0.4+0.20
= 0.6
2.
Each square in the block represents each block of size = 0.1*0.4
= 1*4/10*10
= 4/100
= 0.04
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Related Questions
Question 41: Find the product and express it in rectangular form.
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ANSWER:
[tex]-18-18\sqrt[]{3}i[/tex]SOLUTION:
12) Alyssa draws a rectangle that is 2/3 of ameter long and 3/5 of a meter wide. What isthe area of this rectangle?
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A=LW
L=2/3
W=3/5
A= (2/3)(3/5)
A=2/5 or 0.4
need help with a question
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Let's go over each of the expressions and see if they are equal to 1/8
[tex]2^{-3}=\frac{1}{2^3}=\frac{1}{8}[/tex]So A is equivalent
[tex](-8)^1=-8[/tex]So B is not equivalent
[tex](\frac{32}{4})^{-1}=\frac{1}{\frac{32}{4}}=\frac{4}{32}=\frac{1}{8}[/tex]So C is equivalent
[tex]8^8-8^9=-117440512[/tex]So D is not equivalent
[tex]\frac{8^8}{8^9}=8^{8-9}=8^{-1}=\frac{1}{8}[/tex]So E is equivalent
[tex]undefined[/tex]For f(x) = 2x and g(x) = x,find f (g(2))
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2. Calculate the distance MI for the length of the zipline cable. 3. Calculate the angle at which our zipliners will be descending toward the island . Safety regulations state that the angle at which a zipline cable meets the launching point cannot be smaller than 68 degrees . Please determine if we are in compliance with these regulations
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right
[tex]\begin{gathered} AI)\text{ 400 ft} \\ MI)412.31\text{ f} \\ \text{angle = 76} \end{gathered}[/tex]Explanation
Step 1
AI?
we have a rigth triangle
then
let
[tex]\begin{gathered} AB=side1 \\ AI=side\text{ 2} \\ IB=\text{ hypotenuse} \end{gathered}[/tex]we can use the pythagorean Thoerem to find the missing vale
so
[tex]\begin{gathered} (AB)^2+(AI)^2=(BI)^2 \\ \text{replace} \\ 300^2+(AI)^2=500^2 \\ so \\ (AI)^2=500^2-300^2 \\ AI=\sqrt[]{500^2-300^2}=\sqrt[]{160000}=400 \\ AI=400 \end{gathered}[/tex]Step 2
MI?
let
[tex]\begin{gathered} \text{angle}=x \\ \text{opposite side=100 m} \\ \text{adjacent side=400 m} \end{gathered}[/tex]so, we need a function that relates those 3 values
[tex]\tan \theta=\frac{opposite\text{ side}}{\text{adjacent side}}[/tex]replace
[tex]\begin{gathered} \tan \theta=\frac{opposite\text{ side}}{\text{adjacent side}} \\ \tan x=\frac{400}{100} \\ \tan x=4 \\ \text{hence} \\ x=\tan ^{-1}(4) \\ x=75.96 \\ \text{rounded} \\ x=76\text{ \degree} \end{gathered}[/tex]As 76 is greater than 68, the zipline cable compliance with these regulations.
Also, the hypotenuse (zipline ) is
[tex]\begin{gathered} (MI)^2=(AI)^2+(AM)^2 \\ \text{replace} \\ (MI)^2=(400)^2+(100)^2 \\ (MI)^2=170000 \\ MI=\sqrt[]{17000} \\ MI=412.31\text{ ft} \end{gathered}[/tex]I hope this helps you
Write an inequality for the problem and answer the question about the inequality. The square of x is greater than or equal to 10. Is 3 a solution.
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"The square of x..." translates to x²
"...is greater than or equal to 10." translates to ≥ 10.
To determine if 3 is a solution, substitute 3 to the inequality.
[tex]\begin{gathered} x^2\ge10 \\ \text{If }x=3 \\ (3)^2\ge10 \\ 9\ge10 \\ 9\ngeq10 \end{gathered}[/tex]The resulting number, 9 is not greater than 10. Therefore, 3 is not a solution.
A laboratory tested 82 chicken eggs and found that the mean amount of cholesterol was 228 milligrams with sigma equals 19.0 milligrams. Construct a 95% confidence interval for the true mean cholesterol content u of all such eggs.
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ANSWER
[tex]223.88,232.11[/tex]EXPLANATION
Given;
[tex]\begin{gathered} n=82 \\ \bar{x}=228 \\ \sigma=19.0 \\ \end{gathered}[/tex]At 95% confidence level;
[tex]\begin{gathered} \propto=1-95\% \\ =1-0.95 \\ =0.05 \\ \frac{\propto}{2}=0.025 \\ Z_{\frac{\operatorname{\propto}}{2}}=Z_{0.025}=1.96 \\ \end{gathered}[/tex]At 95% confidence interval for true mean;
[tex]\begin{gathered} \bar{x}\pm Z_{\frac{\operatorname{\propto}}{2}}\frac{\sigma}{\sqrt{n}} \\ =228\operatorname{\pm}1.96\times\frac{19}{\sqrt{82}} \\ =228+1.96\times\frac{19}{\sqrt{82}}<228-1.96\times\frac{19}{\sqrt{82}} \\ =228-4.1124<228+4.1124 \\ =223.88<\mu<232.11 \end{gathered}[/tex]Therefore, 95% confidence interval for the true mean cholesterol content
(223.88,232.11)
can someone please help?just in case if the picture seems blurry, the question says the take off ramp is parallel to the waiting ramp, and the interest ramps are parallel. Given that the measure of angle a is 88 find the measure of each remaining angles
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hi, need help how the graph looks like for this [tex]y \ \textless \ \frac{1}{2} x - 2[/tex][tex]y \leqslant - 2x + 4[/tex]
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Solution:
Given:
[tex]\begin{gathered} y<\frac{1}{2}x-2 \\ y\leq-2x+4 \end{gathered}[/tex]Using a graph plotter, the graph of the two inequalities is shown;
use the function g=f+4 to find the value of g when f=1use the function u=10c to find the value of u when c=5how about this one use the function u=n-5 to find the value of u when n=7this one use the function h=g+13 to find the value of h when g =1use the function w=14f to find the value of w when f =4
Answers
Given function g=f+4
To find the value of g at f=1
substitute f=1 in the given equation
[tex]\begin{gathered} g=f+4 \\ g=1+4 \\ g=5 \end{gathered}[/tex]So, at f=1, the value of g will be 5.
(b).
At u=10c
to find the value of u at c=5
substitute the value c=5 in the given equation
[tex]\begin{gathered} u=10c \\ u=10\times5 \\ u=50 \end{gathered}[/tex]The value of u at c=5 is 50
(c).
Given function u=n-5
to find the value of u at n=7
substitute the value of n=7 in the given equation
[tex]\begin{gathered} u=n-5 \\ u=7-5 \\ u=2 \end{gathered}[/tex]So the value of u at n=7 is 2
(d).
Given function h=g+13
to find the value of h at g=1
substitute the value g=1 in the given equation
[tex]\begin{gathered} h=g+13 \\ h=1+13 \\ h=14 \end{gathered}[/tex]The value of h at g=1 is 14
(e).
Given function w=14f
to find the value of w at f=4
substitute the value f=4 in the given equation
[tex]\begin{gathered} w=14f \\ w=14\times4 \\ w=56 \end{gathered}[/tex]The value of w at f=4 is 56
Round to the nearest hundredth.1.9541
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In order to round to the neares hundreth 1.9541, consider that hundreths are the second number after the decimal point, moreover, take into account that the value of such a number depends of the value of the next number (that is, third number after decimal point).
If next number is lower than 5, then, the second number remains the same, if next number is 5 or greater, second number is increased 1 unit.
In this case, the next number is 4, then, second number or hundreths remain the same.
Hence, you have:
[tex]1.9541\approx1.95[/tex]The amount of metal needed to be installed spring the workbench is
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To answer this question we will use the following formula to compute the perimeter of a rectangle:
[tex]Perimeter=2(length+width)[/tex]Therefore the perimeter of the workbench is:
[tex]Perimeter=2(5ft+3ft).[/tex]Simplfying the above result we get:
[tex]Perimeter=2(8ft)=16ft.[/tex]Therefore we will need 16ft of metal stripping.
Answer: 16ft.
Which of the following functions shows the quadratic parent function,
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Given the function f(x);
[tex]f(x)=x[/tex]When the function is flipped across the x-axis, we'll have the sign reversed.
So, the new function formed is;
[tex]undefined[/tex]Determine algebraically if f(x)=x^2-8 is a function even, odd, or neither.
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For a function to be even, it has to meet the following condition:
[tex]f(x)=f(-x)[/tex]To check if the given is an even function, evaluate the function at x and -x:
[tex]\begin{gathered} f(x)=x^2-8 \\ f(-x)=(-x)^2-8=x^2-8 \\ f(x)=f(-x) \end{gathered}[/tex]It means that the function is even.
For a function to be odd, it has to meet this condition:
[tex]f(-x)=-f(x)[/tex]We already know the values of f(-x) and f(x) and from this we can state that the function is not odd.
this graphic organizer is being used to classify triangles based on their angle measures or sideways which list shows all of the ways that strangle could be classified
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D
1) Examining the sides of that triangle, we can state that this is an equilateral triangle (at least 2 sides have the same measure). But Since isosceles is a triangle that has 2 sides with the same measure.
Then we can state that about their sides this is an equilateral and isosceles triangle.
2) Examining their angles. An equilateral triangle has 3 angles with 60º measure. A 60º angle is lesser than 90º, then we can classify this triangle as an acute triangle
3) Hence, the answer is D
You ordered from an online company. The original price of the item is $65. Theitem is on sale for 10%, and you have a coupon for an additional 15%. Applying onediscount at a time, what is the final price?$46.96$49.73$49.47$45.45
Answers
Given:
The original price, CP=$65.
The initial discount on sale, D1=10%.
The additional discount, D2=15%.
If the cost price(CP) of an item is given, then the selling price after the first discount is applied is,
[tex]SP=CP\times(\frac{1-First\text{ }Discount\text{ Percentage}}{100})[/tex]The additional discount is applied to the price after the first discount is applied. So, the final price after applying the second discount is,
[tex]SP^{\prime}=SP\times(\frac{1-Second\text{ }Discount\text{ Percentage}}{100})[/tex]Applying the first discount on the original price, the selling price is,
[tex]\begin{gathered} SP=CP\times\frac{(100-D1)}{100} \\ =65\times\frac{(100-10)}{100} \\ =58.5 \end{gathered}[/tex]Applying the second discount on the selling price, the final selling price is,
[tex]\begin{gathered} SP^{\prime}=SP_{}\times\frac{(100-D2_{})}{100} \\ =58.5_{}\times\frac{(100-15_{})}{100} \\ \cong49.73 \end{gathered}[/tex]Therefore, the final price is $49.73.
Note:
The direct formula for the final price if two successive discounts D1 and D2 are applied to a cost price CP is,
[tex]SP=CP\times(\frac{100-D1}{100})(\frac{100-D2}{100})[/tex]the chance of you having the same DNA as another person (other than an identical twin) is approximately 1 in 10 trillion (one trillion is a 1 by 12 zeros). Given the fraction,express this very small number using a negative power of 101/10,000,000,000,000
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We are asked to write the quotient : 1/10,000,000,000,000 in a notation with powers of ten. This is called "scientific notation".
when we perform the division of 1 by that enormous number, we get:
0.0000000000001
This can be represented by a 10 to a negative exponent. Notice that we have 13 zeros in the denominator (which implies that we have to divide 13 times by ten)
so we can write the answer as: 1 * 10^(-13)
which with the appropriate equation editor becomes:
[tex]1\cdot10^{-13}[/tex]the base 10 with exponent -13 (negative 13)
Solve the system of equations by any method. -2x + 8y = 14 x – 4y= -7
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-2x+8y = 14 (a)
x-4y = -7 (b)
Multiply (b) by 2 and add both equations:
-2x + 8y = 14
2x -8y = -14
___________
0 = 0
Since both variables were eliminated there is an infinite number of solutions.
Given: GEFH is a parallelogram with two 35° angles as shown.EF35359GHWhich is the most specific descriptor for GEFH?ParallelogramRhombusRectangleSquare
Answers
SOLUTION
The diagram above satifies all the properties of a parallologram
Which are
[tex]\begin{gathered} \text{opposite angle are equal} \\ \text{Opposite sides are equal and parallel} \\ \text{adjacent angle are supplementary} \end{gathered}[/tex]But if from the rule of isoseleses triagle we can conclude that all the side of the figure above are equal
Hence the most specific description for GEFH is
[tex]\text{Rhombus}[/tex]Let's say you have a bag with 12 cherries, 4 of the cherries are sweet and 8 are sour. If you pick a cherry atrandom, what is the probability that it will be sweet? Write your answer as a reduced fraction.Pot)
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1) A rolled die has just 6 outcomes; from 1 to 6
[tex]\text{Probability = }\frac{number\text{ of required events}}{nu\text{mber of total events}}[/tex]Number of total events for a die = 6
[tex]\begin{gathered} a)\text{ p(6) } \\ \text{for this the number of required events = 1 because there can and there is only one six showing at a time} \\ p(6)\text{ =}\frac{1}{6} \end{gathered}[/tex][tex]\begin{gathered} b)\text{ p(even)} \\ Here\text{ number of total events are 1,2,3,4,5 and 6} \\ \text{The number of even numbers = 3} \\ \\ p(\text{even) =}\frac{3}{6}=\frac{1}{2} \end{gathered}[/tex][tex]\begin{gathered} c)p(\text{greater than 1)} \\ \text{Here total number of outcomes are 1,2,3,4,5 and 6} \\ \text{numbers greater than 1 are 2,3,4,5 and 6}\ldots..\text{ Th}ere\text{ are 5 of them} \\ \text{Hence} \\ p(\text{greater than 1) =}\frac{5}{6} \end{gathered}[/tex][tex]\begin{gathered} 2)\text{ Total number of cherries = 12} \\ p(\text{sweet) =}\frac{number\text{ of sw}eet\text{ cherries}}{Total\text{number of cherries}} \\ \text{number of swe}et\text{ cherries= 4} \\ p(\text{sweet) =}\frac{4}{12}=\frac{1}{3} \end{gathered}[/tex]A. 12in ^2B. 30 in ^2C. 24 in ^2 D. 27 in 2pls help with guided practice
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The given figure is a parallelogram. The formula for determining the area of a parallelogram is expressed as
Area = base * height
From the diagram,
base = 9 inches
height = 3 inches
Area = 9 * 3 = 27 in^2
The correct option is D
K
There are 48 runners in a race. How many ways can the runners finish first, second, and third?
There are different ways that the runners can finish first through third.
(Type a whole number.)
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The number of different ways that the runners can finish first through third. is 103776
There are 48 runners in a race
The number of options for the first place is 48, as only one can be in 1st postion and there are a total of 48 persons
The number of options for the second place is 47, as the person who became first cannot be in the second position
The number of options for the third place is 46, as the person who became first and second cannot be in the third position
There are different ways that the runners can finish first through third. is
48 x 47 x 46 = 103776
Therefore, the number of different ways that the runners can finish first through third. is 103776
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10. What is 7/4 as a mixed number?
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Solution:
Given;
What is 7/4 as a mixed number?
7/4 as a mixed number can be expressed as
[tex]1\frac{3}{4}[/tex]Hence, the answer is 1 3/4
Write the expression that can be used tofind the height of the Eiffel Tower.
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First, let's picture the problem:
I have represented the height of the Effiel tower as H
Using the trigonometric ratios:
[tex]\begin{gathered} \tan 53^0\text{ = }\frac{H}{225} \\ H=225\times\tan 53^0^{} \end{gathered}[/tex]Hence the required expression is :
[tex]\begin{gathered} \text{Height of tower = d }\times\text{ tan}\phi \\ \text{if d is the distance of the base} \end{gathered}[/tex]Given that tan A= 5/12 and tan B= -4/3 such that A is an acute angle and B is an obtuse angle find the value of,a) tan (A-45°)b) tan (B+360°)
Answers
Solve for tan(A-45°).
Recall that tan(45°) = 1
[tex]\begin{gathered} \tan (A-45\degree)=\frac{\tan A-\tan B}{1+\tan A\tan B} \\ \tan (A-45\degree)=\frac{\frac{5}{12}-1}{1+(\frac{5}{12})(1)} \\ \tan (A-45\degree)=\frac{-\frac{7}{12}}{1+\frac{5}{12}} \\ \tan (A-45\degree)=\frac{-\frac{7}{12}}{\frac{17}{12}} \\ \tan (A-45\degree)=-\frac{7}{17} \end{gathered}[/tex]Therefore, tan(A-45°) = -7/17.
Solve for tan(B+360°)
Recall that tan(360°) = 0
[tex]\begin{gathered} \tan (B+360\degree)=\frac{\tan A+\tan B}{1-\tan A\tan B} \\ \tan (B+360\degree)=\frac{\frac{5}{12}+0}{1-(\frac{5}{12})(0)} \\ \tan (B+360\degree)=\frac{\frac{5}{12}}{1-\frac{5}{12}} \\ \tan (B+360\degree)=\frac{\frac{5}{12}}{\frac{7}{12}} \\ \tan (B+360\degree)=\frac{5}{7} \end{gathered}[/tex]Therefore, tan(B+360°) = 5/7.
what is the area of a semicircle with a diameter of 2 ?
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we have that
the area of semicircle is equal to
[tex]A=\frac{1}{2}\cdot\pi\cdot r^2[/tex]we have
r=2/2=1
substitute
[tex]\begin{gathered} A=\frac{1}{2}\cdot\pi\cdot1^2 \\ A=\frac{\pi}{2} \end{gathered}[/tex]area is equal to pi/2 square unitsA math teacher said that 18 out of 25 students passed the test. What percent of the students did NOT pass the test?can you please show me the work for this?
Answers
Given:
A math teacher said that 18 out of 25 students passed the test.
So,
Total number of students = 25 student
Number of students who passed the test = 18
Number of students who did not pass the test = 25 - 18 = 7
So, the percent of the students who did NOT pass the test =
[tex]\frac{7}{25}\times100=28\%[/tex]So, the answer will be 28%
How do I find the minimum and maximum in a factored quadratic equation
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Supposed you have a quadratic equation
x^
Can you help me find the answer to my homework questions thankyouuuu
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In this problem, we have an exponential decay function of the form
[tex]y=a(1-r)^x[/tex]where
y is the area in km2
x is the number of years
a=3,800 km2 (initial value)
r=6.25%=6.25/100=0.0625
substitute given values
[tex]\begin{gathered} y=3,800(1-0.0625)^x \\ y=3,800(0.9375)^x \end{gathered}[/tex]For x=12 years
substitute
[tex]\begin{gathered} y=3,800(0.9375)^{12} \\ y=1,752\text{ km}^2 \end{gathered}[/tex]therefore
The answer is 1,752 square kilometersFind the next term of the geometric sequence 3/2, 3/4, 3/8 , ...
Answers
Given:
Geometric sequence:
[tex]\frac{3}{2},\frac{3}{4},\frac{3}{8},.....[/tex]Find-: Next term of the geometric.
Sol:
Common ratio of a geometric sequence.
[tex]r=\frac{a_n}{a_{n-1}}[/tex]A common ratio is:
[tex]\begin{gathered} r=\frac{\frac{3}{4}}{\frac{3}{2}} \\ r=\frac{3}{4}\times\frac{2}{3} \\ r=\frac{1}{2} \end{gathered}[/tex]The next term is:
[tex]a_n=ra_{n-1}[/tex][tex]\begin{gathered} =\frac{1}{2}\times\frac{3}{8} \\ =\frac{3}{16} \end{gathered}[/tex]